Draw The Lewis Structure Of COF2. Include Lone Pairs.

The Part of Nicotinamide Adenine Dinucleotide NADH that is a vitamin is niacin, a type of B vitamin.

This cofactor acts as a hydrogen acceptor in oxidation-reduction reactions.

NADH  is the reduced form of the NAD+, which means that it gains the electron lost by NAD+. NADH is a very important coenzyme central to metabolism.

   NADH is a dinucloetide because it consists of two nucleotides joined through their phosphate groups.

 One nucleotide contains an adenine nucleobase and the other nicotinamide.

A cofactor is a non-protein chemical compound or metallic ion that is required for an enzyme's role as a catalyst in a chemical reaction. A cofactor binds to an enzyme to bring about its  catalytic reaction.

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From the calculations, the pH of the buffer is 3.1.

The  Henderson-Hasselbach equation comes in handy when we deal with the pH of a buffer solution. From that equation;

pH = pKa + log[(salt/acid]

Amount of the salt = 25/1000 *  0.50 M = 0.0125 moles

Amount of the acid = 75/1000 *  1.00 M = 0.075 moles

Total volume = ( 25 + 75)/1000 = 0.1 L

Molarity of salt = 0.0125 moles/0.1 L = 0.125 M

Molarity of the acid = 0.075 moles/0.1 L = 0.75 M

Given that the pKa of lactic acid is 3.86

pH = 3.86 + log( 0.125/0.75)

pH = 3.1

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The molar solubility of AgCl:

The molar solubility of AgCl in a 0.050 M NaCl solution is 8 x [tex]10^{-8}[/tex] M [tex]Ag^{+}[/tex]

What is solubility?

The solubility is the quantity of reagent required to saturate the solution or bring about the dissociation reaction's equilibrium.

Reaction:

The dissociation reaction of AgCl in water is:

[tex]AgCl[/tex]  ⇄ [tex]Ag^{+} + Cl^{-}[/tex]

Each mole of AgCl that dissolves in this reaction yields 1 mole of both [tex]Ag^{+}[/tex] and  [tex]Cl^{-}[/tex]. The concentration of either the Ag or Cl ions would then be equal to the solubility.

Solubility= [[tex]Ag^{+}[/tex]] = [[tex]Cl^{-}[/tex]]

Calculation:

in 0.050 M NaCl, the [[tex]Cl^{-}[/tex]] = 1 x [tex]10^{-2}[/tex]

ksp = [[tex]Ag^{+}[/tex]] x [[tex]Cl^{-}[/tex]]

1.6 x [tex]10^{-10}[/tex] = [[tex]Ag{+}[/tex]] x ( 5 x [tex]10^{-2}[/tex])

[[tex]Ag^{+}[/tex]] = 5 x [tex]10^{+2}[/tex] x 1.6 x [tex]10^{-10}[/tex]

[[tex]Ag^{+}[/tex]] = 5 x 1.6 x [tex]10^{-10+2}[/tex]

[[tex]Ag^{+}[/tex]] = 8 x [tex]10^{-8}[/tex] M

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We use a solution, such as a cabbage ph indicator, to measure the ph of household items :

Anthocyanin, a water-soluble pigment found in red cabbage, can change color when combined with an acid or a basic. The color changes to red in situations with a pH under 7, and to bluish-green in alkaline (basic) environments with a pH above 7. Cabbage isn't known to cause acid reflux, but plenty of other common foods are.

Anthocyanin turns pink when it interacts with the hydronium ions in an acid, and blue or green when it interacts with the hydroxide ions in a base. Because it may inform us if a substance is acidic or basic by changing color, cabbage juice is referred to as a pH indicator.

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H - C ≡ C - CH₂ - CH₃ this is an alkyne molecule.

Hence, Option C is correct answer.

The saturated hydrocarbon which have only single bonds between the carbon atoms is called Alkanes.

The unsaturated hydrocarbon which have at least one carbon carbon double bond is called Alkene.

The unsaturated hydrocarbon which have one or more than one carbon carbon triple bonds is called Alkynes.

H - C ≡ C - CH₂ - CH₃ in this molecule one triple bond is present so it is alkyne.

Thus from the above conclusion we can say that H - C ≡ C - CH₂ - CH₃ this is an alkyne molecule.

Hence, Option C is correct answer.

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The concentration of the final solution will be 0.2886 M.

50.6 g of NaCl is dissolved in 600 mL of water.

Mole of 50.6 g NaCl = 50.6/58.44 = 0.8658 mol

Molar concentration of the oiriginal solution = 0.8658/06 = 1.4431 M

25 mL of 1.4431 M of the solution is diluted up to the 125 mL mark.

m1 = 1.4431, v1 = 25 ml, v2 = 125 mL

m2 = m1v1/v2 = 1.4431 x 25/125 = 0.2886 M

The concentration of the final solution will be 0.2886 M

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If 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.

The concentration of a solution can be calculated by using the following formula;

Molarity = no of moles ÷ volume

According to this question, 5.0 grams of KCl is dissolved in 500 ml of water. The concentration is calculated as follows:

no of moles of KCl = 5g ÷ 74.5g/mol = 0.067mol

Molarity = 0.067mol ÷ 0.5L = 0.134M

Therefore, if 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.

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n = m/M = 2/18 = 1/9 ~0,1 mol

Answer:

.111 mole    (using 3 significant digits)

Explanation:

Mole weight of H2O  = 2 x 1.008  + 15.999 = 18.015 gm/mole

2 gm / 18.015 gm/mole = .111 mole

Dissolving sugar in water results in an increase in the entropy.

Hence, Option (D) is correct answer.

Measurement of randomness of a system is called entropy. It is an extensive property. It is a state function. Unit of entropy is JK⁻¹ mol⁻¹.

Now lets check all options one by one

Option (A): Freezing water

Freezing water decreases the entropy because here second law of thermodynamics does not violate.

So it is incorrect option

Option (B): Cooling water

Cooling water does not increases entropy because entropy increases when solid melts to give liquid.

So it is incorrect option

Option (C): Condensing water vapour

In Condensing water vapour the temperature of liquid phase decreases and thus kinetic energy decreases. The randomness will decrease and hence entropy will also decrease.

So it is incorrect option.

Option (D): Dissolving sugar in solute

In dissolving sugar in solute the solid dissociates to ions and  the randomness will increase and hence entropy will also increase.

So it is correct option

Thus from the above conclusion we can say that Dissolving sugar in water results in an increase in the entropy.

Hence, Option (D) is correct answer.

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Answer:

D.) A symbol of magnesium Mg has two dots representing two free electrons.

Explanation:

Magnesium is located in the second group (column) of the periodic table. Elements located here have 2 valence electrons in their outermost shell. Thus, the electron dot diagram of magnesium has 2 dots symbolizing the 2 valence electrons.

Answer:

6.4 g BaSO₄

Explanation:

You have been given the molarity and the volume of the solution. To find the mass of the solution, you need to (1) find the moles BaSO₄ (via the molarity ratio) and then (2) convert moles BaSO₄ to grams BaSO₄ (via the molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to reflect the sig figs of the given values.

Molarity (mol/L) = moles / volume (L)

(Step 1)

55 mL / 1,000 = 0.055 L

Molarity = moles / volume                             <----- Molarity ratio

0.5 (mol/L) = moles / 0.055 L                        <----- Insert values

0.0275 = moles                                             <----- Multiply both sides by 0.055

(Step 2)

Molar Mass (BaSO₄): 137.33 g/mol + 32.065 g/mol + 4(15.998 g/mol)

Molar Mass (BaSO₄): 233.387 g/mol

0.0275 moles BaSO₄          233.387 g
---------------------------------  x  -------------------  =  6.4 g BaSO₄
                                                1 mole

The surface area of the statute covered with the gold is 9,627.32 m².

Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.

The volume of the statute covered with gold is calculated as follows;

Volume = mass/density

Volume = (279 kg) / (19,320 kg/m³)

Volume = 0.0144 m³

The surface area of a solid object is a measure of the total area that the surface of the object occupies.

V = S.A x h

where;

S.A = V/h

S.A = (0.0144) / (0.0015 x 10⁻³)

S.A = 9,627.32 m²

Thus, the surface area of the statute covered with the gold is 9,627.32 m².

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With a good mask-to-face seal and an oxygen flow rate of 15 L/min, the nonrebreathing mask is capable of delivering up to  90% inspired oxygen.

FiO2 is the fraction of inspired oxygen which is explained as the concentration of oxygen inhaled by a person.

It delivers a high concentration of oxygen. Hence the liter flow will be 8-15L/min with the percentage of oxygen between 60-90%.

The liter flow of nonbreathing mask must not be less than 8L/min.

From the above information we can conclude that the fraction of inspired oxygen for a nonbreathing mask is 90%

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Organic molecules (amino acids) needed to be concentrated to stimulate reactions to form protein concentration mechanisms that do not include Boiling.

Amino acids are natural compounds composed particularly of nitrogen, carbon, hydrogen, and oxygen. Your body desires 20 awesome amino acids to grow and function. amino acid, any of a group of organic molecules that consist of a basic amino group (―NH2), an acidic carboxyl group (―COOH).

fruits have an excessive content of amino acid that allows modify insulin degrees. fruits like bananas, apples, berries, and so forth., are rich resources of amino acids.

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The molality of a solution is 0.304g

Calculation,

Given data,

Density of bromine = 3.105 g/ml  = mass / volume = mass / 2 ml

Mass of bromine = 3.105 g/ml ×  2 ml = 6.206 g

Density of acetic acid = 1.05 g/ml = mass / volume = mass / 125 ml

Mass of bromine = 1.05 g/ml ×  125 ml = 127.5 g

Molality = mass of solute in gram/molar mass of solute × 1000/mass of solvent in gram

Molality = 6.206 g/159.88 g/mol × 1000/127.5 g = 0.304 g

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The hydrolysis of sucrose to glucose and fructose is exergonic. However, if sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose because the activation energy of the reaction is high.

Hence, Option (B) is correct answer.

The minimum amount of energy that must be provided by a reacting molecules to get converted into the product is called Activation energy.

It is expressed as:

[tex]k = Ae^{\frac{-E_a}{RT}}[/tex]

where,

k = rate constant

A = pre-exponential factor

Eₐ = activation energy

R = universal gas constant

T = absolute temperature in K

Thus from the above conclusion we can say that The hydrolysis of sucrose to glucose and fructose is exergonic. However, if sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose because the activation energy of the reaction is high.

Hence, Option (B) is correct answer.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: The hydrolysis of sucrose to glucose and fructose is exergonic. However, if sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose. Why?

A. The change in free energy of the reaction is positive.

B. The activation energy of the reaction is high.

C. The change in free energy of the reaction is negative.

D. This is a hydrolysis reaction, so it requires an input of energy.

E. The free energy of the products is higher than the free energy of the reactants.

The two lines show that these are the only two lines  that do not cause energy transition in the sodium atom. Option D

The spectrum of the sodium atom appears as a doublet. This implies that there are two lines in the spectrum and they appear as bright yellow lines that are not spaced apart in the spectrum.

The  two bright yellow vertical lines in the spectrum shows that these are the only two lines  that do not cause energy transition in the sodium atom.

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The total percent yield:

After the combustion reaction with methane, the percent yield was 66.7%.  

Combustion of Methane:

The other reactant, air's excess oxygen, is always present, making methane the limiting reactant. As a result, the amount of CH₄ burned will determine how much CO₂ and H₂O are produced.

The following chemical process produces carbon dioxide from methane:

CH₄ + 2O₂ ⇒ CO₂ + 2H₂O

Calculations:

1. Theoretical quantity of carbon dioxide:

All calculations will be based on the amount of methane because the problem specifies that it is the limiting reagent:

12.0g of CH₄ × (1 mol of CH₄/16g CH₄) × (1 mole of CO₂/1 mole of CH₄) × (44g CO₂/1 mole of CO₂)

= 33g of CO₂

2. Percent yield:

= Actual yield/Theoretical yield × 100

= 22.0g/33g × 100

= 66.7%

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The answer is 9.94 ml.

Given,

        The density of ethanol, C2H5OH = 0.789 g/mL

[tex]n (CO_{2} ) = \frac{m}{M} = \frac{15G}{44 g/mol} } = 0.341 mol;[/tex]

[tex]n ( C_{2} H_{2} OH) = \frac{n (CO_{2}) }{2} = \frac{0.341}{2} = 0.1705 mol;[/tex]

[tex]m (C_{2} H_{2} OH) = 0.1705 mol * 46 g/ mol[/tex] = 7.843 g

[tex]V (C_{2} H_{2} OH ) = \frac{7.843}{0.789} = 9.94 ml.[/tex]

Therefore, the answer is 9.94 ml

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The complete question is -

If the density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 according to the following chemical equation?

C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l)

The reaction is completed by the equation below: [tex]3H_2 + N_2 --- > 2NH_3[/tex]

They are chemical reactions in which two or more molecules react to produce a single product.

In this case, the synthesis reaction is that of ammonia. Molecules of hydrogen gas and nitrogen gas combine to produce ammonia.

The equation of the reaction is as follows: [tex]3H_2 + N_2 --- > 2NH_3[/tex]

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A wavy pattern of dark and light bands on the bottom of a pond is caused by refraction of light waves through a rough surface; option D.

Destructive interference occur when two waves come in contact with each other and cancel each other out.

Reflection and refraction of light waves can result in destructive interference. An example of destructive interference due to refraction of light is a wavy pattern of dark and light bands on the bottom of a pond.

In conclusion, destructive interference occurs when waves cancel each other out.

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The answer to the question is D.

A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively.  27.1 torr is the partial pressure of the carbon dioxide in the mixture.

Dalton's Law of partial pressure states that the total pressure exerted by non reacting gaseous mixture at a constant temperature and given volume is equal to the sum of partial pressure of all gases.

It is expressed as:

[tex]P_{A} = X_{A} P_{T}[/tex]

where,

[tex]P_{A}[/tex] = Partial pressure of gas A

[tex]X_{A}[/tex] = Mole fraction of gas A

[tex]P_{T}[/tex] = Total pressure

Mole Fraction of Nitrogen

= [tex]\frac{930}{930 + 850}[/tex]

= 0.52

Mole Fraction of Oxygen

= [tex]\frac{850}{850 + 930}[/tex]

= 0.47

Now,

Mole fraction of nitrogen + Mole fraction of oxygen + Mole fraction of carbon dioxide = 1

⇒ 0.52 + 0.47 + Mole fraction of carbon dioxide = 1

⇒ 0.99 + Mole fraction of carbon dioxide = 1

⇒ Mole fraction of carbon dioxide = 1 - 0.99

⇒ Mole fraction of carbon dioxide = 0.01

Now put the value in above expression we get

[tex]P_{A} = X_{A} P_{T}[/tex]

     = 0.01 × 2710

     = 27.1 torr

Thus from the above conclusion we can say that A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively.  27.1 torr is the partial pressure of the carbon dioxide in the mixture.

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Answer:

The answer to your question is True

Explanation:

CH2O is a polar molecule. It has three polar bonds that are arranged asymmetrically, thus allowing their dipole moments to add up and give the molecule an overall dipole moment. CH2O has a central carbon atom that forms two single bonds with the two hydrogen atoms and a double bond with the oxygen atom.

I hope this helps and have a good day!

Answer:

renewable energy sources such as solar and wind DONT emit carbon dioxide and other greenhouse gases that contribute to global warming

Explanation:

Answer:

3.25 x 10²⁴ molecules H₂O

Explanation:

To find the number of H₂O molecules, you need to (1) convert grams to moles (via molar mass) and then (2) convert moles to molecules (via Avogadro's Number). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the amount of sig figs in the given value.

Atomic Mass (H): 1.008 g/mol

Atomic Mass (O): 16.00 g/mol

Molar Mass (H₂O): 2(1.008 g/mol) + 16.00 g/mol

Molar Mass (H₂O): 18.016 g/mol

Avogadro's Number:

6.02 x 10²³ molecules = 1 mole

97.2 g H₂O            1 mole              6.02 x 10²³ molecules
------------------  x  -------------------  x  ------------------------------------  =
                              18.016 g                      1 mole

=  3.25 x 10²⁴ molecules H₂O

Since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.

The term concentration has to do with the amount of substance in solution. The concentration can be measured in several units. Generally, concentration is expressed in molarity, molality, mass concentration units or percentage.

Now we are asked to find the amount concentration of calcium ions and acetate ions in a 0.80 mol/L solution of calcium acetate. The formula of calcium acetate is Ca(CH3COO)2.

Thus;

Ca(CH3COO)2(aq)  ----> Ca^2+(aq) + 2CH3COO^-(aq)

It then follows that since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.

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molar mass of sucrose is 342 g/mol.

Concept:

It is the substance's molecular mass. M is the abbreviation for it, and g/mol is the standard unit for measuring molar mass.

Given:

Sucrose (C12H22O11)

Find:

Calculate the molar mass of the powdered fruit drink mix, made from sucrose (C12H22O11).

Solution:

The molar mass of carbon = 12 g/mol

The molar mass of hydrogen = 1 g/mol

The molar mass of oxygen = 16 g/mol

Thus, the molar mass of sucrose can be calculated as:

C12H22O11 12 C + 22 H + 11 O

= 12 12 g/mol + 22 * 1 g/mol + 11 * 16 g/mol

= 144 g/mol + 22 g/mol + 176 g/mol = 342 g/mol

Therefore, the molar mass of sucrose is 342 g/mol.

Hence, the molar mass of the powdered fruit drink mix, made from sucrose

Hence, the molar mass of the powdered fruit drink mix, made from sucrose(C12H22O11) is 342 g/mol.

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A plant cell has a solute potential of -2.0 bars and pressure potential of 0.0. Its water potential is -2 bar. The cell will gain water or swell.

Water Potential is the potential energy of water in a system per unit volume relative to pure water , when both pressure and temperature are kept same. Water potential is never positive. It is expressed in kPa (Kilopascals). The symbol of water potential is ψ.

To find the water potential use this formula

[tex]\Psi = \Psi_{s} + \Psi_{p}[/tex]

where,

ψ = Water Potential

[tex]\Psi_{s}[/tex] = Solute Potential

[tex]\Psi_{p}[/tex] = Pressure potential

Now put the value in above expression we get

[tex]\Psi = \Psi_{s} + \Psi_{p}[/tex]

   = -2.0 + 0.0

   = - 2 bar

Thus from the above conclusion we can say that A plant cell has a solute potential of -2.0 bars and pressure potential of 0.0. Its water potential is -2 bar. The cell will gain water or swell.

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Molecules undergo London dispersion forces:

[tex]C_{4}H_{10}[/tex] is the molecule will undergo only London dispersion forces when interacting with other molecules of the same kind.

What are London dispersion forces?

Reason for incorrect options:

b: the compound is ionic because Na is a metal and the other part is covalent,

c: two compounds are possible: one is nonpolar and exhibits London dispersion force; the other is polar and exhibits dipole-dipole force; and

d: both compounds exhibit hydrogen bonds (H bonded to O, and H bonded to F).

NOTE: Your question is incomplete, but most probably your full question was, which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind? Which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind?

A. [tex]C_{4}H_{10}[/tex]

B. [tex]NaC_{2}H_{3}O_{2}[/tex]

C. [tex]CH_{2}C_{12}[/tex]

D. [tex]C_{2}H_{5}OH HF[/tex]

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