Draw the products for the following Sn2 reactions, if no reaction takes place say that. Br NaCN, Acetone K, Acetonitrile NaOE, Dimethylsulfoxide iodomethane Lithium Chloride, Dimethylfonamide

Answers

Answer 1

1) Br + NaCN → no reaction (NaCN is a weak nucleophile and cannot displace Br in an Sn2 reaction)


2) K + Acetone → no reaction (K is a strong base and not a nucleophile)


3) NaOE + Acetonitrile → OEt- + NaCN (NaOE is a strong base and a good nucleophile, Acetonitrile is a polar aprotic solvent that stabilizes the negative charge on the nucleophile. The leaving group is CN-)


4) Iodomethane + LiCl → no reaction (LiCl is an ionizing solvent and not a nucleophile)


5) Iodomethane + Dimethylformamide → CH₃CONHCH₃+ HI (DMF is a polar aprotic solvent that stabilizes the negative charge on the nucleophile. The leaving group is I-)

To know more about Sn2 reaction click on below link:

https://brainly.com/question/30310995#

#SPJ11


Related Questions

How many molecules of sucrose (c12h11o22) are there in 15.6 g?

Answers

To determine the number of sucrose molecules in 15.6 g, we need to use the following steps: Calculate the molar mass of sucrose, Calculate the number of moles of sucrose, Convert the number of moles to the number of molecules. There are   2.74 x [tex]10^{22}[/tex]  molecules of sucrose in 15.6 g.

The molar mass of sucrose can be calculated by adding the atomic masses of each element in the formula. The atomic masses can be found in the periodic table. Molar mass of sucrose = (12 x 12.01 g/mol) + (22 x 1.01 g/mol) + (11 x 16.00 g/mol) = 342.3 g/mol

Calculate the number of moles of sucrose: The number of moles of sucrose can be calculated by dividing the given mass of sucrose by its molar mass. Number of moles = 15.6 g / 342.3 g/mol = 0.0455 mol

Convert the number of moles to the number of molecules: The Avogadro's number is used to convert the number of moles to the number of molecules. 1 mol of any substance contains 6.022 x 10^23 particles (Avogadro's number). Therefore,

Number of sucrose molecules = 0.0455 mol x 6.022 x 10^23 molecules/mol = [tex]2.74 x 10^{22}molecules[/tex], Therefore, there are approximately 2.74 x [tex]10^{22}[/tex] molecules of sucrose in 15.6 g.

Know more about molar mass here:

https://brainly.com/question/22997914

#SPJ11

calculate [oh−oh−] for a solution where [h3o ]=0.00667 m[h3o ]=0.00667 m.[OH-]=

Answers

The [OH-] concentration was found to be 1.5 x 10^-12 M.

To calculate [OH-] for a solution where [H3O+] is 0.00667 M, we can use the equation for the ion product of water (Kw= [H3O+][OH-] = 1.0 x 10^-14) and solve for [OH-].

First, we can find [OH-] by dividing Kw by [H3O+]:
Kw = [H3O+][OH-]
1.0 x 10^-14 = (0.00667 M) [OH-]
[OH-] = 1.5 x 10^-12 M

Therefore, the [OH-] concentration for this solution is 1.5 x 10^-12 M. It is important to note that the solution is basic, as [OH-] > [H3O+].

In conclusion, to calculate the [OH-] concentration in a solution with [H3O+] = 0.00667 M, we can use the ion product of water equation to solve for [OH-]. The [OH-] concentration was found to be 1.5 x 10^-12 M.

To know more about  [OH-] concentration visit:

https://brainly.com/question/3045247

#SPJ11

Chemistry Give the IUPAC names for the following compounds. Use the abbreviations o, m, or p (no italics) for ortho, meta, or para if you choose to use these in your name. For positively charged species, name them as aryl cations. Example: ethyl cation. Be sure to specity stereochemistry when relevant. NO2 OH Ph ČI Name: Name: 1-choloro-4nitrobenzene

Answers

Using the given abbreviations, the name of NO2 OH Ph ČI is 1-chloro-4-nitrobenzene.

The International Union of Pure and Applied Chemistry (IUPAC) has established specific rules and guidelines that must be followed when naming a chemical compound with an IUPAC name. It is used to convey a chemical compound's molecular structure and composition as well as its distinctive identification.

The substance in the cited example is 1-chloro-4-nitrobenzene. The name adheres to the IUPAC guidelines for naming aromatic compounds, which include allocating the lowest numbers to the substituents for the carbons on the benzene ring. In this instance the benzene ring has two substituents a chlorine atom (Cl) and a nitro group (NO2).

The name 1-chloro-4-nitrobenzene comes from the fact that the chlorine atom is bonded to carbon 1 and the nitro group is bonded to carbon 4 respectively.

Learn more about IUPAC name at:

brainly.com/question/16631447

#SPJ4

What is the pH of a 0.65 M solution of the weak acid HClO, with a Ka of 2.90×10−8? The equilibrium expression is:
HClO(aq)+H2O(l)⇋H3O+(aq)+ClO−(aq)
Round your answer to two decimal places.

Answers

The pH of a 0.65 M solution of the weak acid HClO, with a Ka of 2.90×10⁻⁸ is 4.27.

Given information:

The acid dissociation constant (Ka) = 2.90×10⁻⁸

The concentration of HClO = 0.65 M

The given balanced reaction:

HClO + H₂O ⇋ H₃O+ + ClO⁻

The Ka expression for this reaction is:

Ka = [H₃O⁺][ClO⁻]/[HClO]

At equilibrium, let x be the concentration of H₃O⁺ and ClO⁻.

Then, the equilibrium concentration of HClO will be (0.65 - x) M. Substituting these values into the Ka expression and solving for x,

Ka = [H₃O+][ClO-]/[HClO]

2.90×10⁻⁸ = x²/(0.65-x)

Solving for x using the quadratic formula, we get:

x = 5.38×10^-5 M

Therefore, the concentration of H₃O⁺  of the solution is 5.38×10⁻⁵ M.

pH = -log[H₃O⁺]

pH = -log(5.38×10⁻⁵)

= 4.27

Therefore, the pH of the 0.65 M solution of HClO is 4.27.

To learn more about the pH, follow the link:

https://brainly.com/question/15289741

#SPJ1

A particular solution of a weak base with a concentration of 0.200M is measured to have a pH of 8.80 at equilibrium.
A. What is the Kb of the weak base?
B. What is the % ionization of the weak base?

Answers

The percent ionization of the weak base is approximately 0.032%.

The relationship between the concentration of the weak base, its ionization constant (Kb), and the pH of the solution. We can use the following equation:

Kb = Kw / Ka

where Kb is the ionization constant of the weak base, Kw is the ion product constant of water (1.0 x 10^-14 at 25°C), and Ka is the ionization constant of the conjugate acid of the weak base.

Step 1: Determine the concentration of hydroxide ions in the solution.

Since the pH of the solution is 8.80, we can use the following equation to determine the concentration of hydroxide ions:

pH = 14.00 - pOH

pOH = 14.00 - pH

pOH = 14.00 - 8.80

pOH = 5.20

[OH-] = 10^(-pOH)

[OH-] = 10^(-5.20)

[OH-] = 6.31 x 10^-6 M

Step 2: Determine the concentration of the weak base that has ionized.

We know that the weak base has a concentration of 0.200 M, and that it has partially ionized. Let x be the concentration of the weak base that has ionized. Then the concentration of the weak base remaining is (0.200 - x).

Step 3: Write the chemical equation for the ionization of the weak base and the expression for Kb.

The chemical equation for the ionization of the weak base, B, is:

B + H2O ↔ BH+ + OH-

The expression for Kb is:

Kb = [BH+][OH-] / [B]

Step 4: Calculate the value of Kb.

We know that [OH-] = 6.31 x 10^-6 M, and we can assume that [BH+] is negligible compared to [B] since the weak base is weakly ionized. Therefore, we can simplify the expression for Kb to:

Kb = [OH-]^2 / [B]

Kb = (6.31 x 10^-6)^2 / (0.200 - x)

Kb = 2.00 x 10^-5 / (0.200 - x)

Step 5: Calculate the value of x.

We can use the approximation that x is much smaller than 0.200 to simplify the expression for Kb. Then:

Kb ≈ 2.00 x 10^-5 / 0.200

Kb ≈ 1.00 x 10^-4

Now we can use the Kb value to calculate the percent ionization of the weak base.

Step 6: Calculate the percent ionization of the weak base.

The percent ionization of the weak base is defined as the ratio of the concentration of the weak base that has ionized to the initial concentration of the weak base, multiplied by 100%.

% ionization = (x / 0.200) x 100%

% ionization = (Kb x [B]) / 0.200 x 100%

% ionization = (1.00 x 10^-4) x (x / 0.200) x 100%

% ionization = (1.00 x 10^-4) x (6.31 x 10^-5) / 0.200 x 100%

% ionization ≈ 0.032%

Therefore, the percent ionization of the weak base is approximately 0.032%.

For more such questions on ionization , Visit:

https://brainly.com/question/30403192

#SPJ11

A. To find the Kb of the weak base, we first need to find the pOH of the solution since Kb = Kw/Ka.

B. To find the % ionization of the weak base, we first need to calculate the concentration of the weak base that did not ionize.

A. At equilibrium, the pH of the solution is 8.80, which means the pOH is 14 - 8.80 = 5.20. Since the solution is a weak base, we can assume that it is not completely ionized and that [OH-] is equal to the concentration of the weak base that did ionize. Using the concentration of the weak base given in the problem (0.200M) and the measured pOH, we can calculate [OH-]:

pOH = -log[OH-]
5.20 = -log[OH-]
[OH-] = 6.31 x 10^-6 M

Now, we can use the equilibrium expression for Kb to solve for Kb:

Kb = [BH+][OH-]/[B]
Assuming that the weak base completely dissociates into BH+ and OH-:
Kb = [OH-]^2/[B]
Kb = (6.31 x 10^-6)^2/0.200
Kb = 1.99 x 10^-10

Therefore, the Kb of the weak base is 1.99 x 10^-10.

B. We can assume that the initial concentration of the weak base is the same as the concentration at equilibrium (0.200M). Since the weak base is a base, we can assume that the reaction that occurs is:

B + H2O ⇌ BH+ + OH-

At equilibrium, we can assume that x mol/L of B has ionized. Therefore, the concentration of BH+ is also x mol/L and the concentration of OH- is also x mol/L. The concentration of the weak base that did not ionize is then 0.200 - x mol/L.

To calculate x, we can use the Kb value we found in part A:

Kb = [BH+][OH-]/[B]
1.99 x 10^-10 = x^2/(0.200 - x)
Solving for x, we get:
x = 2.82 x 10^-4 M

Now, we can calculate the % ionization of the weak base:

% ionization = (amount of weak base that ionized/initial amount of weak base) x 100%
% ionization = (2.82 x 10^-4 M/0.200 M) x 100%
% ionization = 0.14%

Therefore, the % ionization of the weak base is 0.14%.

Learn more about % ionization  click here:

https://brainly.com/question/13949664

#SPJ11

How many grams of Cl are in 41. 8 g of each sample of chlorofluorocarbons (CFCs)?



CF2Cl2

Answers

Mass of Cl = Number of moles of CF2Cl2 × Molar mass of Cl= 0.346 mol × 35.45 g/mol= 12.26 g Therefore, the mass of chlorine in 41.8 g of CF2Cl2 is 12.26 g.

The given sample of chlorofluorocarbons (CFCs) is CF2Cl2. We are to determine the mass of Cl (chlorine) in 41.8 g of the sample CF2Cl2. Here is the solution: First of all, we have to find the molar mass of CF2Cl2:Molar mass of CF2Cl2 = Molar mass of C + 2(Molar mass of F) + Molar mass of Cl= 12.01 g/mol + 2(18.99 g/mol) + 35.45 g/mol= 120.91 g/molNow we can calculate the number of moles of CF2Cl2 present in the given sample: Number of moles of CF2Cl2 = mass of CF2Cl2 / molar mass= 41.8 g / 120.91 g/mol= 0.346 moles Now we can find the mass of chlorine in the given sample by multiplying the number of moles by the molar mass of chlorine: Mass of Cl = Number of moles of CF2Cl2 × Molar mass of Cl= 0.346 mol × 35.45 g/mol= 12.26 gTherefore, the mass of chlorine in 41.8 g of CF2Cl2 is 12.26 g.

Learn more about chlorine here:

https://brainly.com/question/19460448

#SPJ11




What is the speed of a wave with a frequency of 1,000,000 Hz and a wavelength of 299. 79?

Answers

Given that the frequency of wave is 1,000,000 Hz and the wavelength is 299.79, we can substitute these values into the equation is Speed = 1,000,000 Hz × 299.79

To calculate the speed of a wave, we can use the formula: Speed = Frequency × Wavelength. Speed = 299,790,000 meters per second (m/s)

Therefore, the speed of the wave is approximately 299,790,000 m/s.

It's important to note that the speed of a wave is a fundamental property that represents how fast the wave propagates through a medium. In this case, the calculated speed is exceptionally high, as it represents the speed of light in a vacuum, which is approximately 299,792,458 m/s.

The period is equal to the frequency times the length of a cycle in a recurrent event. Therefore, the strongest, highest frequency, and shortest wavelength rays are gamma rays. The final response is gamma rays.

Learn more about frequency of wave here

https://brainly.com/question/30333783

#SPJ11

calculate the ph of an aqueous solution, which has an [h3o ] = 1.0x10-11 m.

Answers

The pH of the aqueous solution with an [H3O+] concentration of 1.0x10-11 M is 11.

The pH scale is a logarithmic scale that measures the concentration of hydrogen ions in a solution. A pH of 7 is neutral, while a pH below 7 is acidic and a pH above 7 is basic. The pH can be calculated using the formula pH = -log[H3O+].

In this case, the [H3O+] concentration is 1.0x10-11 M.

To calculate the pH of an aqueous solution with an [H3O+] concentration of 1.0 x 10^-11 M:

The pH is calculated using the formula pH = -log10[H3O+]. In this case, the [H3O+] concentration is 1.0 x 10^-11 M.

By substituting the given concentration into the formula, we get pH = -log10(1.0 x 10^-11). Calculating the logarithm, we find that the pH of the aqueous solution is 11, which is basic.

To learn more about pH of solution visit:

brainly.com/question/491373

#SPJ11

What is the molarity of an hcl solution if 16. 0 mL of a 0. 5 M naoh are required to neutralize 25. 0 mL hcl

Answers

The molarity of the HCl solution is 0.32 M. The molarity of an HCl solution can be calculated if 16.0 mL of a 0.5 M NaOH is required to neutralize 25.0 mL HCl.

Here's how you can calculate it:

First, you need to balance the equation for the reaction between HCl and NaOH. It is given as:

HCl + NaOH → NaCl + H2O

From the balanced equation, you can see that 1 mole of HCl reacts with 1 mole of NaOH. Therefore, the number of moles of NaOH used to neutralize HCl can be calculated as follows:

0.5 M NaOH = 0.5 moles NaOH in 1 liter of solution

= 0.5 x (16.0/1000)

= 0.008 moles NaOH used

Similarly, the number of moles of HCl can be calculated as follows:

Moles of NaOH = Moles of HCl

=> 0.008 moles NaOH = Moles of HCl

=> Moles of HCl = 0.008 moles

Volume of HCl solution used = 25.0/1000

= 0.025 L

V = n/M

=> M = n/V

=> M = 0.008/0.025

=> M = 0.32 M

To leran more about molarity refer to:-

https://brainly.com/question/30909953

#SPJ11

why is it important to add an acid/base to water, instead of adding water to an acid/base

Answers

It is important to add an acid/base to water instead of adding water to an acid/base because of the potential for a dangerous reaction.

When water is added to an acid, there is a risk of splashing and spattering due to the heat generated by the exothermic reaction. This can cause burns and damage to surrounding materials. In contrast, adding an acid or base to water allows for a more controlled and gradual reaction, reducing the risk of splashing and overheating. Additionally, adding water to an acid or base can result in a more concentrated solution, which can be dangerous and difficult to handle. Adding the acid or base to water helps to dilute the solution and prevent potentially dangerous concentrations. Overall, the order in which substances are added can greatly affect the safety and efficacy of the reaction, making it important to add acids and bases to water in a controlled and safe manner.

To know more about acid visit:

brainly.com/question/30693072

#SPJ11

What is the electron-pair geometry for N in NOCl? There are _____ lone pair(s) around the central atom, so the geometry of NOCl is _____.

Answers

Answer:What is the electron-pair geometry for N in NOCl? There are _____ lone pair(s) around the central atom, so the geometry of NOCl is _____.

learn more about electron-pair geometry

https://brainly.com/question/29470595?referrer=searchResults

#SPJ11

Choose the relationship that is INCORRECT a. Na+ = 1 Atrial Natriuretic Hormone (ANH) b. Na+ = 1 Atrial Natriuretic Hormone (ANH) c. Na+ = 1 Anti-diuretic hormone (ADH) d. Na+ = | Aldosterone (ALDO)

Answers

The relationship that is INCORRECT is Na+ = | Aldosterone (ALDO). So the correct answer is option d.

The relationship is incorrect because aldosterone promotes the reabsorption of sodium ions, not excretion, so it would not be expected to have a 1:1 relationship with Na+.

The correct relationship is Na+ = 1 Atrial Natriuretic Hormone (ANH), which promotes the excretion of sodium ions, and is therefore inversely related to Na+ levels. Na+ = 1 Anti-diuretic hormone (ADH) is also a correct relationship, as ADH regulates water balance in the body and can indirectly affect Na+ levels.

So option d is the correct answer.

To learn more about Atrial Natriuretic Hormone: https://brainly.com/question/9360479

#SPJ11

Calculate the hydrogen ion concentration for an aqueous solution that has a ph of 3.45. 1. 0.54 m.

Answers

The hydrogen ion concentration ([H+]) is a measure of the acidity of an aqueous solution. It represents the concentration of hydrogen ions, which are positively charged ions formed when water molecules (H2O) dissociate into their component parts: hydrogen ions (H+) and hydroxide ions (OH-). In pure water, the concentration of [H+] is equal to the concentration of [OH-], and both are very small, approximately 1 x [tex]10^{-7 }[/tex]M, at 25°C.

The pH scale is a logarithmic scale that expresses the acidity or basicity of a solution. It ranges from 0 to 14, where a pH of 7 is considered neutral, a pH below 7 is acidic, and a pH above 7 is basic.

The pH of a solution can be calculated from the [H+] using the equation pH = -log[H+].

In the case of the given solution with a pH of 3.45, the [H+] is 3.55 x [tex]10^{-4 }[/tex]M, indicating that the solution is acidic. This means that there are more hydrogen ions than hydroxide ions in the solution, and the pH is lower than 7.

The concentration of a solution is typically expressed in units of molarity (M), which is defined as the number of moles of solute per liter of solution.

The molarity of a solution is directly proportional to the number of particles present, and can be used to calculate other properties of the solution, such as its density or osmotic pressure.

In summary, the hydrogen ion concentration is a fundamental property of aqueous solutions that influences their acidity and pH.

It is related to the molarity of the solution, which is a measure of the number of solute particles present per unit volume.

To know more about hydrogen ion refer here

https://brainly.com/question/12845664#

#SPJ11

Which solid would you expect to have the largest band gap? a. As(s), b. Sb(s),c. Bi(s).

Answers

Band gap refers to the energy difference between the valence band and the conduction band in a solid material. The larger the band gap, the greater the energy required to move an electron from the valence band to the conduction band. The size of the band gap depends on the electronic structure of the solid and the types of atoms that make up the material.

In general, elements with larger atomic numbers tend to have larger band gaps. This is because the valence electrons in these materials are more tightly bound to the nucleus and require more energy to move to the conduction band. Among the options given, bismuth (Bi) has the largest atomic number and therefore would be expected to have the largest band gap.
Another factor that can affect the band gap is the crystal structure of the material. Different crystal structures can lead to different electronic properties, including the size of the band gap. However, all three options (As, Sb, Bi) have the same crystal structure (rhombohedral) so this factor does not differentiate between them.
In summary, based on atomic number alone, we would expect bismuth (Bi) to have the largest band gap among the options given.

For more such question on energy

https://brainly.com/question/24496809

#SPJ11

2. draw lewis structures and predict molecular geometries for dimethyl sulfide, (ch3)2s, and dimethyl sulfoxide, (ch3)2so. how will the csc bond angles differ?

Answers

Dimethyl sulfide posses tetrahedral geometry with ~109.5° bond angles; Dimethyl sulfoxide makes trigonal pyramidal geometry with ~107° bond angles.

Dimethyl sulfide  and dimethyl sulfoxide are considered natural mixtures that comprises sulfur. In order to make their Lewis structures, we have to measure the valence electrons for every particle and orchestrate them likewise.

In case of  dimethyl sulfide, every methyl bunch contributes one valence electron, and sulfur contributes six. Thusly, the all out number of valence electrons is 14. We can organize them as follows:

Duplicate code in the figure 1

This design has a tetrahedral math, with bond points of roughly 109.5 degrees. The atom is polar because of the electronegativity contrast among sulfur and carbon.

For dimethyl sulfoxide, every methyl bunch contributes one valence electron, sulfur contributes six, and oxygen contributes six. Accordingly, the complete number of valence electrons is 22. We can orchestrate them as follows:

Duplicate code in the figure 2

This design has a three-sided pyramidal math, with bond points of roughly 107 degrees. The atom is polar because of the electronegativity contrast between sulfur, oxygen, and carbon.

The CS-C bond points in dimethyl sulfide will be bigger than those in dimethyl sulfoxide because of the presence of an oxygen particle, which will apply a more grounded horrendous power on the neighboring iotas. This distinction in bond points can influence the physical and substance properties of these mixtures.
To learn more about Lewis structures,
brainly.com/question/9227593
#SPJ1

the conversion of 3-hydroxybutyrate to two molecules of acetyl-coa produces 1 nadh and consumes 1 equivalent of atp. what is the net atp yield from the complete oxidation of 3-hydroxybutyrate?

Answers

Therefore, the net ATP yield from the complete oxidation of 3-hydroxybutyrate is 24 - 1 = 23 ATP.

The complete oxidation of 3-hydroxybutyrate involves several steps in which the molecule is converted to acetyl-CoA. Each molecule of 3-hydroxybutyrate yields 2 molecules of acetyl-CoA. The conversion of one molecule of 3-hydroxybutyrate to 2 molecules of acetyl-CoA produces 1 NADH and consumes 1 ATP equivalent. The NADH can be used to produce ATP through oxidative phosphorylation, which generates about 2.5 ATP per NADH.

Therefore, the net ATP yield from the complete oxidation of 3-hydroxybutyrate is calculated as follows:
- One molecule of 3-hydroxybutyrate yields 2 molecules of acetyl-CoA.
- Each molecule of acetyl-CoA produces 12 ATP through the Krebs cycle (2 ATP for each turn of the cycle).
- The total ATP produced from the 2 acetyl-CoA molecules is 24 ATP.
- One equivalent of ATP is consumed during the conversion of 3-hydroxybutyrate to acetyl-CoA.
- Therefore, the net ATP yield from the complete oxidation of 3-hydroxybutyrate is 24 - 1 = 23 ATP.

To know more about complete oxidation visit:-

https://brainly.com/question/13154005

#SPJ11

seaborgium (sg, element 106) is prepared by the bombardment of curium-248 with neon-22, which produces two isotopes, 265sg and 266sg.

Answers

The statement is true. Seaborgium, with the symbol Sg and atomic number 106, is a synthetic element that was first synthesized in 1974 by a team of scientists at the Lawrence Berkeley National Laboratory in California.

The production of seaborgium involves the bombardment of a heavy target nucleus with a lighter projectile nucleus to induce a nuclear fusion reaction.

In the case of seaborgium, the element is prepared by bombarding a curium-248 target with neon-22 projectiles, which produces two isotopes: 265Sg and 266Sg. The reaction can be represented by the following equation:

248Cm + 22Ne → 265,266Sg + n

The neutrons produced in the reaction are necessary to maintain the stability of the newly formed isotopes. Seaborgium is a highly unstable element, with a half-life of only a few minutes, and its properties are difficult to study due to its short-lived nature.

The synthesis of seaborgium and other heavy elements has important implications for our understanding of nuclear physics and the structure of matter. It also has potential applications in areas such as nuclear energy and medicine. However, the production of these elements is challenging and requires sophisticated technology and highly skilled scientists.

learn more about seaborgium here:

https://brainly.com/question/29238159

#SPJ11

Use the Nernst equation to calculate the theoretical value of E of th copper-concentration cell and compare this value with th cell potential you measured.
E = E* - 0.0592 / n * logQ
**So I believe this is the equation that I would use. However, i'm don't know what E* is suppose to be...**
The my electrochemistry experiment the cell potential that i measured were: 0.130V, 0.115V, and 0.110V (average cell potential = 0.118V)
The concentration of the copper concentration cells used for this lab were: 0.05M CuSO4 and 1.0M CuSO4
standard reduction potential (in text) = Cu2+ + 2e- --> Cu(s) E* = +0.34V **I believe I use the 2 here for n in the Nernst equation. **
am i doing this right? ---> E= 0.118v - 0.0592V / 2e- * log (1.0M/0.05M) =0.0795V ???

Answers

The theoretical value of E using the Nernst equation is approximately 0.108 V.

How to use the Nernst equation to calculate cell potential?

The Nernst equation can be used to calculate the theoretical value of the cell potential (E) for the copper-concentration cell.

First, let's clarify the values:

Measured cell potential: 0.118 V

Standard reduction potential: E* = +0.34 V

Number of electrons transferred in the reaction (n): 2

Ratio of copper concentrations: 1.0 M / 0.05 M = 20

Now, let's calculate the theoretical value of E using the Nernst equation:

E = E* - (0.0592 V / (n * log(Q)))

where:

E is the cell potential

E* is the standard reduction potential

n is the number of electrons transferred in the reaction

Q is the reaction quotient (ratio of product concentrations to reactant concentrations)

Plugging in the values:

E = 0.118 V - (0.0592 V / (2 * log(20)))

Calculating this equation:

E ≈ 0.118 V - (0.0592 V / (2 * 2.9957))

E ≈ 0.118 V - (0.0592 V / 5.9914)

E ≈ 0.118 V - 0.00986 V

E ≈ 0.108 V

So the theoretical value of E using the Nernst equation is approximately 0.108 V.

Comparing this value to the measured average cell potential of 0.118 V, you can see that the theoretical value is slightly lower than the measured value.

Please note that the concentrations used in the Nernst equation should be in mol/L or M, so the concentrations of 0.05 M and 1.0 M CuSO4 are correct. Also, make sure to use natural logarithm (log base e) in the equation.

Learn more about cell potential

brainly.com/question/31044904

#SPJ11

how many atoms of hydrogen are in 110 g of hydrogen peroxide ( h2o2 )?

Answers

There are approximately 6.47 x Avogadro's number (6.022 x 10²³) or 3.89 x 10²⁴ atoms of hydrogen in 110 g of hydrogen peroxide.

The molar mass of hydrogen peroxide (H2O2) is 34.0147 g/mol.

First, we need to find the number of moles of H2O2 in 110 g:

number of moles = mass/molar mass

number of moles = 110 g / 34.0147 g/mol

number of moles = 3.235 mol

Next, we use the chemical formula of H2O2 to find the number of atoms of hydrogen present:

1 molecule of H2O2 has 2 atoms of hydrogen.

So, the total number of atoms of hydrogen in 3.235 mol of H2O2 can be calculated as:

number of atoms of hydrogen = 2 x number of moles of H2O2

number of atoms of hydrogen = 2 x 3.235 mol

number of atoms of hydrogen = 6.47 mol

To know more about hydrogen peroxide refer here :-

https://brainly.com/question/29102186#

#SPJ11

Given the balanced chemical reaction:


2Na+ s → Na2s


What is the total number of moles of sodium required to completely react with 0. 50 moles of sulfur?



A) 2. 0 mol


B) 1. 0 mol


C) 0. 5 mol


C) 4. 0 mol

Answers

To completely react with 0.50 moles of sulfur, 1.0 mole of sodium is required.

According to the balanced chemical reaction, 2 moles of sodium react with 1 mole of sulfur to produce 1 mole of sodium sulfide. This means that, to react with 0.50 moles of sulfur, we need half of the amount of sodium, which is 0.50 x 2 = 1.0 mole of sodium.

Therefore, the answer is option B) 1.0 mol. It is important to note that the coefficients in the balanced chemical reaction indicate the mole ratio between the reactants and products, which can be used to determine the required amounts of reactants or products in a given reaction.

Learn more about mole here.

https://brainly.com/questions/31545539

#SPJ11

Addition of small amounts of which solids to 4 M HCl will result in gas evolution? I. Zn II. Na2SO3 (A) I only (B) II only (C) Both I and II (D) Neither I nor II

Answers

Both zinc and sodium sulfite can react with 4 M HCl to produce gas evolution. Zinc produces hydrogen gas, while sodium sulfite produces sulfur dioxide gas. Therefore, the correct answer is (C) Both I and II.

Zinc (Zn) is a common metal that reacts with hydrochloric acid (HCl) to produce hydrogen gas (H2) and zinc chloride (ZnCl2) according to the following chemical equation:

[tex]Zn + 2HCl → ZnCl2 + H2[/tex]

Therefore, the addition of zinc to 4 M HCl will result in the evolution of hydrogen gas.

Sodium sulfite (Na2SO3) is a salt that can act as a reducing agent in acidic solutions. When it is added to hydrochloric acid, it undergoes a redox reaction, where it reduces the H+ ions to H2 gas while being oxidized to sodium sulfate (Na2SO4):

[tex]Na2SO3 + 2HCl → 2NaCl + H2O + SO2 + H2[/tex]

The gas produced in this reaction is sulfur dioxide (SO2), which is a colorless, pungent gas that can be easily recognized by its characteristic odor. Therefore, the correct answer is (C) Both I and II.

For more such questions on hydrogen gas

https://brainly.com/question/31235702

#SPJ11

Both I (Zn) and II (Na_{2}SO_{3}) will produce a gas when added to 4 M HCl. The correct answer is (C) Both I and II.

The addition of small amounts of certain solids to 4 M HCl can result in gas evolution, which is the formation and release of gas as a product of the reaction. In this case, we have two solids: I. Zn (zinc) and II. Na_{2}SO_{3} (sodium sulfite).
I. Zn: When zinc is added to hydrochloric acid (HCl), it reacts to produce hydrogen gas (H2) and zinc chloride (ZnCl2). The reaction is as follows:
Zn(s) + 2HCl(aq) → ZnCl_{2}(aq) + H_{2}(g)
II. Na2SO3: When sodium sulfite is added to hydrochloric acid, it reacts to produce sodium chloride (NaCl), water (H2O), and sulfur dioxide gas (SO_{2}). The reaction is as follows:
Na_{2}SO_{3}(s) + 2HCl(aq) → 2NaCl(aq) + H_{2}O(l) + SO_{2}(g)
Both I (Zn) and II (Na_{2}SO_{3}) will produce a gas when added to 4 M HCl. Therefore, the correct answer is (C) Both I and II.

learn more about gas evolution Refer: https://brainly.com/question/14809313

#SPJ11

Can solid FeBrą react with Cl, gas to produce solid FeCl, and Br2 gas? Why or why not? A. Yes, because Cl2 has lower activity than Br2 B. No, because Cl, has lower activity than Bra C. No, because Cl, and Br, have the same activity D. Yes, because Cl2 has higher activity than Br2

Answers

Answer:The reaction can occur since Cl2 gas has a higher activity than Br2 gas. Therefore, solid FeBr2 can react with Cl2 gas to produce solid FeCl2 and Br2 gas. The reaction can be represented as follows:

FeBr2 (s) + Cl2 (g) -> FeCl2 (s) + Br2 (g)

Thus, the correct answer is D: Yes, because Cl2 has higher activity than Br2.

Explanation:

given 12.01 gram of carbon (c) = 1 mole of c. how many grams are in 3 moles of carbon (c)?

Answers

A mole is the mass of a substance made up of the same number of fundamental components. Atoms in a 12 gram example are identical to 12C. Depending on the substance, the fundamental units may be molecules, atoms, or formula units.

A mole of any substance has an agadro number value of 6.023 x 10²³. It can be used to quantify the chemical reaction's byproducts. The symbol for the unit is mol.

The formula for the number of moles formula is expressed as

Number of Moles = Mass  / Molar Mass

Molar mass of 'C' = 12.01 g / mol

Mass = n × Molar Mass = 3 × 12.01 = 36.03 g

To know more about mole, visit;

https://brainly.com/question/30307377

#SPJ1

Calculate G° for each reaction at 298K using G°f values. (a) MnO2(s) + 2 CO(g) Mn(s) + 2 CO2(g) kJ (b) NH4Cl(s) NH3(g) + HCl(g) kJ (c) H2(g) + I2(s) 2 HI(g) kJ

Answers

(a) -408.2 kJ/mol (b) 176.2 kJ/mol (c) -52.1 kJ/mol  Using the G°f values, the calculation results in a G° of -52.1 kJ/mol.

(a) The reaction involves the formation of two moles of CO2 and one mole of Mn from one mole of MnO2 and two moles of CO. Using the G°f values, the calculation results in a G° of -408.2 kJ/mol.

(b) The reaction involves the decomposition of one mole of NH4Cl to form one mole of NH3 and one mole of HCl. Using the G°f values, the calculation results in a G° of 176.2 kJ/mol.

(c) The reaction involves the formation of two moles of HI from one mole of H2 and one mole of I2. Using the G°f values, the calculation results in a G° of -52.1 kJ/mol.

learn more about values here:

https://brainly.com/question/10416781

#SPJ11

the nuclear mass of cl37 is 36.9566 amu. calculate the binding energy per nucleon for cl37 .

Answers

The binding energy per nucleon for a nucleus can be calculated using the formula: BE/A = (Zmp + (A-Z)mn - M)/A. so binding energy is BE/A = -0.026.

For Cl37, Z = 17 and A = 37, so the number of neutrons, N, is 20. The mass of a proton is approximately equal to 1 amu, and the mass of a neutron is approximately equal to 1.0087 amu. The nuclear mass of Cl37 is given as 36.9566 amu.

BE/A = [(17 × 1) + (20 × 1.0087) - 36.9566]/37

BE/A = (27.1709 - 36.9566)/37

BE/A = -0.026

The binding energy per nucleon for Cl37 is approximately -0.026 amu. This negative value indicates that the nucleus is not stable and may undergo radioactive decay to become more stable.

The binding energy per nucleon is a measure of the stability of an atomic nucleus. The higher the binding energy per nucleon, the more stable the nucleus. In the case of Cl37, the binding energy per nucleon can be calculated using the formula: Binding energy per nucleon = (total binding energy of nucleus) / (total number of nucleons)

The total binding energy of a nucleus can be calculated using the formula: Total binding energy = (atomic mass defect) x (c^2)

where c is the speed of light.The atomic mass defect is the difference between the mass of an atomic nucleus and the sum of the masses of its constituent protons and neutrons.

Using the given nuclear mass of Cl37, the atomic mass defect can be calculated. From there, the total binding energy and binding energy per nucleon can be determined.

Once calculated, the binding energy per nucleon of Cl37 can be compared to the average binding energy per nucleon for stable nuclei, which is around 8.5 MeV. If the binding energy per nucleon for a given nucleus is lower than this average, it is less stable than average, while a higher value indicates greater stability

learn more about protons here:

https://brainly.com/question/12535409

#SPJ11

What is the mass of 12. 5 moles of Ca3(PO40)2?

Answers

The mass of 12.5 moles of Ca3(PO4)2 is approximately 1,780.65 grams. To calculate the mass of 12.5 moles of [tex]Ca_{3}(PO)^{4}_{2}[/tex], we need to use the molar mass of Ca_{3}(PO)^{4}_{2} and multiply it by the number of moles.

The molar mass of Ca_{3}(PO)^{4}_{2} can be calculated by adding up the atomic masses of each element in the compound. Calcium (Ca) has a molar mass of 40.08 g/mol, phosphorus (P) has a molar mass of 30.97 g/mol, and oxygen (O) has a molar mass of 16.00 g/mol.

The molar mass of Ca_{3}(PO)^{4}_{2} is then:

(3 * 40.08 g/mol) + (2 * (30.97 g/mol + 4 * 16.00 g/mol)) = 310.18 g/mol

To find the mass of 12.5 moles of Ca_{3}(PO)^{4}_{2} we multiply the molar mass by the number of moles:

12.5 moles * 310.18 g/mol = 3,877.25 g

Therefore, the mass of 12.5 moles ofCa_{3}(PO)^{4}_{2} is approximately 1,780.65 grams.

Learn more about moles here: https://brainly.com/question/29367909

#SPJ11

The neutralization reaction of HNO2 and a strong base is based on: HNO3(aq) + OH-(aq) H2O(1) + NO2 (aq) K= 4.5x1010 What is the standard change in Gibbs free energy at 25 °C? O 1) -2.21 kJ 2) -5.10 kJ 3) -26.4 kJ O4) -60.8 kJ

Answers

The standard change in Gibbs free energy at 25°C for the given reaction is -60.8 kJ/mol.

The standard change in Gibbs free energy (ΔG°) for a reaction is a measure of the spontaneity of the reaction.

It can be calculated using the equation ΔG° = -RTlnK, where R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant for the reaction.

In this case, the equilibrium constant (K) is given as 4.5x10^10. Plugging in the values, we get ΔG° = -8.314 J/mol*K * (298.15 K) * ln(4.5x10^10) = -60.8 kJ/mol.

The negative sign indicates that the reaction is spontaneous in the forward direction.

Therefore, the answer is option 4) -60.8 kJ.

For more such questions on Gibbs, click on:

https://brainly.com/question/13765848

#SPJ11

The standard change in Gibbs free energy for the neutralization reaction of HNO2 and a strong base is -60.8 kJ at 25 °C, according to the given equilibrium constant (K = 4.5 x [tex]10^10[/tex]).

The standard change in Gibbs free energy (ΔG°) for a reaction can be determined using the equation: ΔG° = -RT ln(K), where R is the gas constant, T is the temperature in kelvin, and K is the equilibrium constant. In this case, the given reaction has a K value of 4.5x10^10. The temperature is 25 °C, which is 298 K. Using the equation and plugging in the values, ΔG° can be calculated as follows: ΔG° = - (8.314 J/K/mol) x (298 K) x ln([tex]4.5x10^10[/tex]) = -60.8 kJ/mol. Therefore, the correct answer is option (4) -60.8 kJ. This indicates that the reaction is highly spontaneous under standard conditions.

Learn more about neutralization here:

https://brainly.com/question/27891712

#SPJ11

You set your music player to shuffle mode. It plays each of the n songs before repeating any. Write a program to estimate the likelihood that you will not hear any sequential pair of songs (that is, song 3 does not follow song 2, song 10 does not follow song 9, and so on)

Answers

The formula for the number of derangements is D(n) = n! * (1 - 1/1! + 1/2! - 1/3! + ... + (-1)^n/n!).

Let's assume we have n songs in the playlist. The total number of possible permutations is n!, which represents all the ways the songs can be arranged. Now, we want to count the number of derangements, which are the permutations where no song appears in its original position.

To calculate the number of derangements, we can use the formula D(n) = n! * (1 - 1/1! + 1/2! - 1/3! + ... + (-1)^n/n!). This formula considers the principle of inclusion-exclusion. The term (-1)^n/n! accounts for the alternating signs, and the sum in the parentheses represents the inclusion-exclusion principle.

To estimate the likelihood, we divide the number of derangements by the total number of permutations: D(n) / n!. The result is an approximation of the probability that no sequential pair of songs will be played in the shuffled playlist.

Note that as the number of songs increases, the probability approaches a specific value known as the derangement constant, which is approximately 1/e (where e is Euler's number, approximately 2.71828).

To learn more about permutations click here, brainly.com/question/29990226

#SPJ11

what is the maximum mass of solid barium sulfate (233 g·mol-1) that can be dissolved in 1.00 l of 0.100 m nazs04 solution? ksp (bas04) = 1.5 x 1 o-9

Answers

The maximum mass of BaSO₄ that can be dissolved in 1.00 L of 0.100 M Na2SO4 solution is 23.3 g.

What is the mass of a solid that can dissolve?

The solubility product constant, Ksp, for BaSO₄ is given as 1.5 x 10⁻⁹. The balanced chemical equation for the dissolution of BaSO4 is:

BaSO₄ (s) ⇄ Ba²⁺ (aq) + SO₄⁻ (aq)

The molar solubility of BaSO₄ is x mol/L.

So, Ksp = [Ba2+][SO42-] = x * x = x²

Therefore, x = √(Ksp)

x = √(1.5 x 10^-9)

x = 1.22 x 10^-4 mol/L

The maximum mass of BaSO₄ that can be dissolved in 1.00 L of 0.100 M Na2SO4 solution will be:

Moles of Na₂SO₄ in 1.00 L of 0.100 M solution:

Molarity = moles of solute / volume of solution

moles of Na₂SO = Molarity * volume of solution

moles of Na₂SO₄ = 0.100 mol/L * 1.00 L

moles of Na₂SO₄ = 0.100 mol

The mass of BaSO4 that can dissolve:

mass = moles of BaSO4 * molar mass of BaSO4

mass = 0.100 mol * 233 g/mol

mass = 23.3 g

Learn more about solubility at: https://brainly.com/question/24057916

#SPJ1

How many grams of ammonia are consumed in the reaction of 103.0 g of lead(ii) oxide?

Answers

Approximately 15.7 grams of ammonia are consumed in the reaction of 103.0 g of lead(II) oxide.

To answer this question, we need to first write the balanced chemical equation for the reaction of lead(II) oxide with ammonia:

PbO + 2NH3 → Pb(NH3)2O

From this equation, we can see that 1 mole of lead(II) oxide reacts with 2 moles of ammonia. We can use the molar mass of lead(II) oxide to convert the given mass of 103.0 g into moles:

103.0 g PbO × (1 mole PbO/223.2 g PbO) = 0.462 moles PbO

Since 1 mole of PbO reacts with 2 moles of NH3, we can use stoichiometry to calculate the amount of NH3 consumed in the reaction:

0.462 moles PbO × (2 moles NH3/1 mole PbO) = 0.924 moles NH3

Finally, we can convert moles of NH3 to grams using its molar mass:

0.924 moles NH3 × (17.03 g NH3/1 mole NH3) = 15.62 g NH3

Therefore, 15.62 grams of ammonia are consumed in the reaction of 103.0 grams of lead(II) oxide.
To determine how many grams of ammonia are consumed in the reaction of 103.0 g of lead(II) oxide, we need to use stoichiometry. First, we need a balanced chemical equation for the reaction:

PbO (lead(II) oxide) + 2 NH3 (ammonia) → Pb(NH2)2 (lead(II) amide) + H2O (water)

Now, follow these steps:

1. Calculate the molar mass of lead(II) oxide (PbO): 207.2 g/mol (Pb) + 16.0 g/mol (O) = 223.2 g/mol.
2. Determine the moles of PbO: 103.0 g / 223.2 g/mol ≈ 0.461 mol PbO.
3. Use the stoichiometry from the balanced equation to find the moles of NH3: 0.461 mol PbO × (2 mol NH3 / 1 mol PbO) = 0.922 mol NH3.
4. Calculate the grams of NH3: 0.922 mol NH3 × 17.0 g/mol (NH3) ≈ 15.7 g.

To know more about chemical equation visit:-

https://brainly.com/question/30087623

#SPJ11

Other Questions
the average age of death in the us is (=77.6, =12.5). what proportion of americans die before the age of 85? The matrix A is given below, followed by a sequence {x_k} produced by the power method. Use these data to estimate the largest eigenvalue of A, and given a corresponding eigenvector. A = [6 3 1 2]; [1 0], [1 0.2051], [1 0.2132, [1.0.2148] Choose the best estimate for the dominant eigenvalue below. Solve the differential equation xy' = y + xe^8y/x by making the change of variable v = y/x. monetary policy end of chapter problems why does the fed pay such close attention to gdp, if its mandate is to promote maximum employment while keeping prices stable? An incorporation is considering these two alternatives to finance its construction of a new $1.05 million plant: 1. Issuance of 105,000 shares of common stock at the market price of $10 per share. Issuance of $1.05 million, 5% bonds at face value. The Binding Of CAMP-CRP To DNA Affects The Binding Of A Repressor. True False Government securities dealers frequently engage in repos to a. manage liquidity b. take advantage of anticipated changes InInterest rates c. lend or borrow lor a day or two with what is essentially collateralized d. do all of the above.e. do only A and B of the above. An 11-m beam is subjected to a load, and the shear force follows the equation V(x) = 5 + 0.25x where V is the shear force and x is length in distance along the beam. We know that V = dM/dx, and M is the bending moment. Integration yields the relationship M = M, + V dx If M, is zero and x = 11, calculate M using (a) analytical integration, (b) multiple-application trapezoidal rule, and (c) multiple-application Simpson's rules. For (b) and (c) use 1-m increments. The complex ion NiCl4 ^2- has two unpaired electrons, whereas Ni(CN)4^2- is diamagnetic. propose structures for these two complex ions. For each graph below, write an equation of a line that is parallel to the line and passes through the square point. Then, write an equation of a line that is perpendicular to the line and passes through the square point. plane polarized light of intensity i 0 is passed through a polarizer oriented at 45 to the original plane of polarization. what is the intensity transmitted?A. 0.70 IoB. 0.50 IoC. 0.35 IoD. 0.25 IoE. 0.00 Io In this lesson, you learned about the changes that occurred in and because of France from 1789 to 1815. Three different eras were discussed: The French Revolutionary Era (17891799), The Napoleonic Era (17991815), and the Bourbon Restoration (after 1815).Consider this: in many ways, a historian's work is like that of a detective. Historians carefully try to put together the pieces of history by looking at primary and secondary sources. This is similar to the way detectives look at evidence when trying to solve a case. In this assessment, you will have an opportunity to work like a true historian. You will study evidence and develop a logical conclusion based on the sources presented to you.In this assessment, you will analyze the sources based on the era, and you will also use information you have learned in this lesson to support your responses.You will be analyzing sources during and after the French Revolutionary Era. You will use the documents to evaluate how the different eras during the late 18th and early 19th centuries shaped the identity and character of the people of France. You will need to answer each analysis question in a short paragraph of complete sentences. Select the template to review the documents. You will first analyze each of them with two separate questions and then you will consider the big picture of the 26 extraordinary years of the French Revolution and Napoleonic Era with a reflection question.If you would like a fuller treatment of analyzing sources, you can review these three stages of source analysis. Ozonolysis of alkenes yields carbon dioxide as a product. a. True b. False Which of following is true about normal changes to the GI system that occur as individuals age?a. decreased motility and increased liver blood flow and liver enzyme activityb. decreased motility and decreased liver blood flow and liver enzyme activityc. increased motility and decreased liver blood flowd. increased motility and increased liver enzyme activity how many 5-permutations are there of 11 distinct objects? Singleton Inc. reported the following information for the current year:I.Net Sales $650,000Cost of goods sold $495,000Gross Profit $155,000II.Inventory, 1/1 $21,250Inventory, 12/31 $24,850Compute Singleton's(a) gross profit ratio,(b) inventory turnover ratio, and(c) average days to sell inventory.(Note: Round all answers to two decimal places.) Label the cranial nerves (VII. VIII, IX X XI,XII) attached to the base of the human brain by clicking and dragging the labels to the correct location ANTERIOR Facial nerve (VI) Glossopharyngeal nerve (IX) Hypoglossal nerve (XII) Vestibulocochlear nerve (VI) Cerebellum Spinal cord Accessory nerve (XI) Pons Vagusix) given the same information as in the previous problem, what is the i/o rate for the 50 reads? give your answer in mb/sec. 1. Functional writing (20marks) Just after a few days of being in a secondary school, you have visited a national park, you have played a friendly matched against another school, and done your first exams. Write a letter to your parent/guardian briefing them about these developments. Part A: Using the Class Methods 1. Examine the Python statements in the file named "lab10a. Py", then extend that program to do the following tasks: a. Display each players hand after the first card has been played from each hand. B. Display the second card dealt to each player and compare them. C. Display each players hand after the second card has been played from each hand. D. Display the last card dealt to each player and compare them. Here is the additional output after those modifcations: Second card dealt to player #1: Q Player #1 hand: [7, 10, 7] Second card dealt to player #2: Q Player #2 hand: [K, 2, 8] Last card in hand of player #1: 7 Last card in hand of player #2: 8 8 of higher rank than 7 Note on Mimir testing: you will notice that the symbols for the suits are not printed in the Mimir tests instead the letters hcds are used. That is because Mimir cannot handle the symbols. You do not need to do anything about thatit is built into the cards. Py that we use for testing