Answer:
E = 108
Step-by-step explanation:
E = 3 * [tex]6^{2}[/tex]
= 108
Answer:
e=mc^2 if m=3 and c=6
e=3([tex]6^2[/tex])
e=3[tex](36)[/tex]
e=108
Step-by-step explanation:
hope this helps have a good rest of your day/afternoon :) ❤
2 The length of Rectangle A is 7x +11. The
length of Rectangle B is 15x - 9. Given the
two Rectangles are congruent, what is the
value of x?
Answer:
Step-by-step explanation:
If congruent the sides are equal
15x-9=7x+11
8x=20
x=20/8=2.5
Rachel jogged along the trail that was 1/4 of a mile long she jogged along the trail eight times how many miles did Richel jog
Answer:
Step-by-step explanation:
8 laps × (¼ mile)/lap = 2 miles
need help plz help me
Answer:
080777056656:5 c
Suppose a math class contains 40 students. There are 18 females (two of whom speak Spanish) and 22 males (two of whom speak Spanish). Give all answers as decimals to at least two decimal places.
What percent of Spanish speaking students are male? Give answer as a decimal.
Answer:
50%.
Step-by-step explanation:
Given that a math class contains 40 students, and there are 18 females (two of whom speak Spanish) and 22 males (two of whom speak Spanish), in order to know the percent of Spanish speaking students that are male with respect to the total Spanish-speaking students, the following calculation has to be made:
2 + 2 = 4
2 / 4 = 0.5
Therefore, the percentage of Spanish speaking students that are male is 50%.
Find the area of the figure. Use 3.14 for it.
2 ft.
8 ft
3 ft
4 ft
3 ft
8 ft
Answer:
I dont know if you still need it but the area of the figure is 51.5 ft2.
The area of the given figure is equivalent to 39.5 square feet.
What is Area?Area is a collection of two - dimensional points enclosed by a single dimensional line. Mathematically, we can write -
V = ∫∫F(x, y) dx dy
Given is to find the area of the given figure as shown in the image.
We can write the area of the given figure as -
A{total} = A{Rectangle} + A{Δ1} + A{Δ2}
A{total} = (8 x 4) + (1/2 x 3 x 3) + (1/2 x 3 x 2)
A{total} = 32 + 4.5 + 3
A{total} = 39.5 square feet
Therefore, the area of the given figure is equivalent to 39.5 square feet.
To solve more questions on areas, visit the link-
https://brainly.com/question/29213222
#SPJ2
Which expressions are equivalent to 5 +(-3)(6x - 5)?
Choose all answers that apply:
A
18r - 20
B
3.x - 3
None of the above
Answer:
B i think
Step-by-step explanation:
If Sara can only work 5% of one hour now many minutes of one hour can Sara work?
5% or 5percent can be thought of 5 per 100.
5 per 100 or 5 out of 100 can be written as 5/100 or 1/20.
An hour have 60 minutes and 1/20 of an hour is 60*1/20=3 minutes.
Therefore Sara can work 3 minutes every hour.
Write an inequality that represents the graph? Please. Please.
Answer:
y[tex]\leq[/tex][tex]\frac{1}{2}[/tex]x-2
it is less than because it is shaded down, its less than or equal to because the line is solid.
Answer:
2y < - x - 4
Step-by-step explanation:
First find the equation of the line in the form y=mx+c (straight line)
The y-intercept is at -2 so c=-2.
For each 2 along the x-axis it goes 1 down the y-axis, so the gradient is -1/2, so m = -1/2
We now have y = -(1/2) x - 2
Try a coordinate, e.g. (0,0) one side of that line:
-(1/2) 0 - 2 = -2
-2 is less than 0, but we don't want (0,0) in the region, so we say
y < -(1/2)x - 2 or
2y < - x - 4
1. Only 60% of the students passed a drawing class. 2,000 students took the class. Find out how many students were failures.
Answer:
800 students failed
Step-by-step explanation:
Since 60% passed the class, 40% failed
This means that 40% of the 2,000 students are failures
[tex]\frac{40}{100} (2,000)= 800[/tex]
The Acculturation Rating Scale for Mexican Americans (ARSMA) is a psychological test that measures the degree to which Mexican Americans are adapted to Mexican/Spanish versus Anglo/English culture. The range of possible scores is 1.0 to 5.0, with higher scores showing more Anglo/English acculturation. The distribution of ARSMA scores in a population used to develop the test is approximately Normal with mean 3.0 and standard deviation 0.8. A researcher believes that Mexicans will have an average score near 1.7 and that first-generation Mexican Americans will average about 2.1 on the ARSMA scale.
What proportion of the population used to develop the test has scores below 1.7? Between 1.7 and 2.1?
Answer:
The proportion of the population used to develop the test that has scores below 1.7 is 0.063.
The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The distribution of ARSMA scores in a population used to develop the test is approximately Normal with mean 3.0 and standard deviation 0.8.
This means that [tex]\mu = 3, \sigma = 0.8[/tex]
What proportion of the population used to develop the test has scores below 1.7?
This is the pvalue of Z when X = 1.7. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{1.7 - 3}{0.8}[/tex]
[tex]Z = -1.63[/tex]
[tex]Z = -1.63[/tex] has a pvalue of 0.063
The proportion of the population used to develop the test that has scores below 1.7 is 0.063.
Between 1.7 and 2.1?
This is the pvalue of Z when X = 2.1 subtracted by the pvalue of Z when X = 1.7.
X = 2.1
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{2.1 - 3}{0.8}[/tex]
[tex]Z = -1.13[/tex]
[tex]Z = -1.13[/tex] has a pvalue of 0.1292
X = 1.7
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{1.7 - 3}{0.8}[/tex]
[tex]Z = -1.63[/tex]
[tex]Z = -1.63[/tex] has a pvalue of 0.063
0.1292 - 0.063 = 0.0662
The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.
I If x > 0 and x^2-2x-35 = 0, then the value of x^2 is 3
Answer:
x^2 = 49
Step-by-step explanation:
Notice that the polynomial on the left of the equation can be factored out as:
x^2 - 2 x - 35 = (x - 7) (x + 5)
Then the equation: x^2 - 2 x - 35 = = 0
gives two solutions as follows:
(x - 7) (x + 5) = 0 Then either binomial factor must be zero, and therefore, x = 7 or x = -5
Since we are told that x is POSITIVE, the x = 7, and its square is 7^2 = 49.
• Work out the percentage change to 2 decimal places when £78.98 is increased to £100
Answer:
The total change is £21.02 from the original amount of £78.98. Therefore, the percentage change is directly related to the original amount.
Divide the total change by the original amount to determine the percentage change the new amount represents.
21.02÷78.98=0.15219 which rounds up to two decimal places as 15.22%.
Given the following formula, solve for t. V = ut at OA. ย + 1 t 1 B. いま O C. t a(v – u) OD. t = a(v + a) Re
Answer:
[tex]\frac{v - u}{a} = t[/tex]
Step-by-step explanation:
Given
[tex]v = u + at[/tex]
Required
Solve for t
[tex]v = u + at[/tex]
Subtract u from both sides
[tex]v - u = u - u + at[/tex]
[tex]v - u = at[/tex]
Divide both sides by 1
[tex]\frac{v - u}{a} = \frac{at}{a}[/tex]
[tex]\frac{v - u}{a} = t[/tex]
[tex]t = \frac{v - u}{a}[/tex]
Gabriel finds some dimes and quarters in his change purse. How many coins
does he have if he has 11 dimes and 8 quarters? How many coins does he have
if he has d dimes and a quarters?
8 quarters equal 2 dollars 11 dimes is a dollar and 10 cents so 3 dollars and 10 cents
Two points A and C are on the same level ground as the foot of pole B . The distance between A and C is 40m and A and C are on the same sides of the vertical pole . The distances from the top of the pole D to A and C are 53 and 85 respectively. Find correct to 1 do the distance between the foot of the pole B and the point A.
Answer:
The distance between the pole and point A is 35.2m
Step-by-step explanation:
First, we have to illustrate the problem. I can't draw as of the moment but I'll try my best to describe the drawing as best as I can. You can draw this in a scratch paper to have a better understanding.
In a horizontal line, there is a point A, B, and C.From left going to right, the arrangement of points will be C-A-B.The distance between A and C is 40m.The pole is standing at point B with height h.The tip of the pole or the top most part of the pole is point D.From point D to A, the measurement is 53m.From point D to C, the measurement is 85m.Let's name the distance between A and B as x.Now that you have drawn this. There should be two triangles formed now namely triangle DCB and DAB.
TRIANGLE DCB
By Pythagorean Theorem, we can write an equation for the height of the pole.
[tex]h^{2} = {53}^{2} - {x}^{2} [/tex]
TRIANGLE DAB
By Pythagorean Theorem, we can write an equation for the height of the pole.
[tex] {h}^{2} = {85}^{2} - {(40 + x)}^{2} [/tex]
Since we only have one pole, this means that we can equate the two equations.
[tex] {53}^{2} - {x}^{2} = {85}^{2} - {(40 + x)}^{2} \\ {53}^{2} - {85}^{2} = {x}^{2} - ( {x}^{2} + 80x + 1600) \\ - 4416 = - 80x - 1600 \\ 80x = 4416 - 1600 \\ 80x = 2816 \\ x = \frac{2816}{80} \\ x = 35.2[/tex]
BROOOOOOOOOOOOOOO HELPPPPPPPPP
What is the answer to this?
9514 1404 393
Answer:
cot(θ) = 24/7
Step-by-step explanation:
A suitable calculator can answer this nicely.
__
Perhaps you're expected to remember relevant trig identities.
tan(θ)^2 = sec(θ)^2 -1
cot(θ) = 1/tan(θ)
__
cot(θ) = 1/√(sec(θ)^2 -1)
cot(θ) = 1/√((25/24)^2 -1) = 24/√(25^2 -24^2) = 24/√49
cot(θ) = 24/7
Please do all of the attachments, quick. It is due please
First one with the right answer gets brainlest, and I will give extra points please.
Find and simplify the expression
F(3x)=(3x)^2-3
____________________________
1.) Expand [tex]\bold{(3x)^2}[/tex]:[tex]3^2x^2-3[/tex]- We do this to make the problem easier to simplify. When expanded you can easily figure out what you need to find to make it a simplified equation.
2.) Calculate [tex]\bold{3^2}[/tex]:[tex]3^2=9[/tex]- We do this because it's the only thing we can find, that would make this a simplified problem.
So your answer is [tex]\bold{9x^2-3}[/tex].
____________________________
3. (07.02 MC) What is the value of y in the equation 3(3y - 12) = 0? (5 points) 4 5 6 9
3(3y-12)=0 divide both sides by 3
3y-12=0 add 12 to both sides
3y=12 divide both sides by 3
y=4
divide 72 into the ratio of 4:5
divide 72 in the ratio of 4: 5
= 16
Given: y = 12 when x = 7, find: “y” when x = 5.
Answer:
y = 84/5 or 16 4/5
Step-by-step explanation:
12/5 = y/7
cross-multiply to get 5y = 84
y = 84/5
Running out of time, Could i please get help
Answer:
D
Step-by-step explanation:
For an expansion (ax+b)^c the row that will help you is the c'th one
He is using the c'th row so look for something in the form (ax+b)^15
Only one that fits is D
Find the missing value in the picture?
Answer:
AC=13.6
Step-by-step explanation:
let the triangle is ABC
radius =6 , diameter =6*2=12
therefore AB=12
since BC is a tangent
therefore angle B =90 degrees
BC=6.4
[tex]\sqrt (AB)^2+(BC)^2 =AC[/tex]
AC=13.6
The function f(x)=3x+K and f(4)=7. Find the value of K and f(2)
Step-by-step explanation:
step 1. f(4) = 3(4) + K = 7 (plug in values)
step 2. K = -5 (subtract 12 from each side)
step 3. therefore f(x) = 3x - 5
step 4. f(2) = 3(2) - 5 = 1 (plug in x= 2)
The ratio of the measures of the three angles in a tangle 3107. Find the measures of the angles and write them in size order,
largest:
middle
Answer:
27, 90 and 63
Step-by-step explanation:
Given
Ratio of triangle sides
[tex]Ratio = 3 : 10 : 7[/tex]
Required:
The length of each side
Triangles in a triangle add up to 180.
The side with ratio 3 is:
[tex]S_1 = \frac{3}{3 + 10 + 7} *180[/tex]
[tex]S_1 = \frac{3 *180}{20}[/tex]
[tex]S_1 = \frac{540}{20}[/tex]
[tex]S_1 = 27[/tex]
The side with ratio 10 is:
[tex]S_2 = \frac{10}{3 + 10 + 7} *180[/tex]
[tex]S_2 = \frac{10 *180}{20}[/tex]
[tex]S_2 = \frac{1800}{20}[/tex]
[tex]S_2 = 90[/tex]
Lastly:
The side with 7 as its ratio
[tex]S_3 = \frac{7}{3 + 10 + 7} *180[/tex]
[tex]S_3 = \frac{7 *180}{20}[/tex]
[tex]S_3 = \frac{1260}{20}[/tex]
[tex]S_3 = 63[/tex]
Hence, the angles are: 27, 90 and 63
select all the correct answers which expressions are equal to 6^3.2^6/2^3 A. 2^3.3^3 B. 12^6 C. 2^6.3^3 D.6^3 E. 12^3
Answer:
C and EStep-by-step explanation:
Given expression:
6³×2⁶/2³Simplify:
6³×2⁶/2³ = 6³×2⁶⁻³ =6³2³ =(6×2)³ =12³The answer choices:
A. 2³×3³ = 6³ ⇒ IncorrectB. 12⁶ ⇒ IncorrectC. 2⁶×3³ = 4³×3³ = 12³ ⇒ CorrectD.6³ ⇒ IncorrectE. 12³ ⇒ Correct
Oliver sets out 5 one-gallon buckets to collect rainwater. After a storm, of each bucket
is filled with water. Oliver wants to know how many total gallons of water he collects.
Which addition expression can you use to find how many
total gallons of water Oliver collects?
1. He collected 5 gallons of water.
2. We find this out by knowing 5 = 5.
Hope it helps! Good luck! :D
The point (x, y) is proportional to the point (2, 5). Select all the true statements.
(x, y) is a solution to y = 5/2X
(x, y) is a solution to y=x+3.
The ratio of Y/X is equivalent to 5/2
Point (x, y) is the same point as (5, 2).
A straight line through points (2, 5) and (x, y) will pass through the origin.
Step-by-step explanation:
(x, y) is a solution to y = 5/2X
(x, y) is a solution to y=x+3.
The ratio of Y/X is equivalent to 5/2
Point (x, y) is the same point as (5, 2).
A straight line through points (2, 5) and (x, y) will pass through the origin.
Use the information given to find a convenient dass width. Then list the class boundaries that can be used to create a relative frequency histogram. (Round your class with up to the nearest multiple of 5. Use the minimum value as the smallest class boundary. Enter your class boundaries as a comma separated list.)
8 classes for 75 measurements; minimum value-20; maximum value = 175
class width
class boundaries
Answer:
a)
Class width = 19.375
b)
Class Boundaries are;
19.5 - 39.5, 39.5 - 59.5, 59.5 - 79.5, 79.5 - 99.5, 99.5 - 119.5, 119.5 - 139.5, 139.5 - 159.5, 159.5 - 179.5.
Step-by-step explanation:
Given the data in the question;
Class width = Range / Number of classes
Range = maximum - minimum = 175 - 20 = 155
Number of classes = 8
so,
Class width = 155 / 8 = 19.375
∴ the class limits will be
20 - 39
40 - 59
60 - 79
80 - 99
100 - 119
120 - 139
140 - 159
160 - 179
Low class boundary = Lower class limit - 0.5
Upper class boundary = upper class limit + 0.5
so
Class Boundaries are;
19.5 - 39.5, 39.5 - 59.5, 59.5 - 79.5, 79.5 - 99.5, 99.5 - 119.5, 119.5 - 139.5, 139.5 - 159.5, 159.5 - 179.5.