Answer:
x/4 = x-6
Step-by-step explanation:
x/4 = x-6 makes x = 8
Hope this helps!!!
1. Which of the following results in the difference of two squares?
O (3r-5y) (3x - 5y)
O (5x+3y) (5x-3y)
O 4r²(3r-9)
O (2r-3y)2
The difference of two squares is (5x+3y) (5x-3y)
How to determine the difference of two squares?The difference of two squares of variables a and b is represented as:
(a + b)(a - b) = a^2 - b^2
By comparing the list of options, we have:
(5x+3y) (5x-3y)
This means that
a = 5x and b = 3y
Hence, the difference of two squares is (5x+3y) (5x-3y)
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Find the remainder when f(x)=2x^3-x^2+x+1 is divided by 2x+1
Answer:
0
Step-by-step explanation:
By the remainder theorem, this is the same as finding f(-1/2), which is equal to 0.
A rectangular vegetable patch is 5 meters long and 4 meters wide. what is the area?
Answer:
20
Step-by-step explanation:
Area of a rectangle = l*w
5*4 = 20
is {{-12,8),(-15,8),(-5,8),(-12.8}} a function
Answer:
Yes. {(-12, 8), (-15, 8), (-5, 8)} is function because there is no overlap in the x values.
50 points will give brainliest
The x-coordinates of the vertices of the hyperbola are 11 and -11
How to determine the x-coordinates?The hyperbola is given as:
[tex]\frac{x^2}{121} - \frac{y^2}{49} = 1[/tex]
A hyperbola is represented as:
[tex]\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1[/tex]
Where the coordinate of the vertex is:
Vertex = (±a, 0)
By comparing the above equations, we have:
[tex]a^2= 121[/tex]
Take the square of both sides
a = 11
Substitute 11 for a in Vertex = (±a, 0)
Vertex = (±11, 0)
Hence, the x-coordinates of the vertices of the hyperbola are 11 and -11
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Question for 60 Points
Using the Factor Theorem to find the equation of the parabola, we have that:
[tex]a + b + c = -\frac{48}{7}[/tex]
What is the Factor Theorem?The Factor Theorem states that a polynomial function with roots [tex]x_1, x_2, \codts, x_n[/tex] is given by:
[tex]f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)[/tex]
In which a is the leading coefficient.
In this problem, we have a horizontal parabola, defined as follows:
[tex]f(y) = a(y - y_1)(y - y_2)[/tex].
The roots are [tex]y_1 = -1, y_2 = -7[/tex], hence:
f(y) = a(y + 1)(y + 7)
f(y) = a(y² + 8y + 7).
The x-intercept is of x = -3, hence f(0) = -3, so:
[tex]-3 = 7a[/tex]
[tex]a = -\frac{3}{7}[/tex]
Then the equation is:
[tex]x = -\frac{3}{7}y^2 - \frac{24}{7}x - 3[/tex]
Then the sum of the coefficients is:
[tex]a + b + c = -\frac{3}{7} - \frac{24}{7} - \frac{21}{7} = -\frac{48}{7}[/tex]
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Answer:
Hello!
Step-by-step explanation:
Assume a firm reports net income of 84,000 prior to making adjusting entries for expired rent $6400, depreciation 7600 and supplies used 3,000
Assume that the entries have not been made What effect do these errors have on the reported net income
Assume that the entries have not been made. The effect that these errors have on the reported net income is: Net income will be overstated by $17,000.
Net incomeUsing this formula
Net income=Expired rent+Depreciation+Supplies
Let plug in the formula
Net income=$6400+$7600+$3000
Net income=$17,000 (Overstated)
Therefore the net income will be overstated by $17,000.
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whats the correct answer
Answer:
C
Step-by-step explanation:
The first part of this is to represent the center.
It sits at (1,-1), so the left hand part of the equation is
(x - 1)^2 + (y + 1) = r^2
That means the answer has to be either B or C. D gets knocked out of the running because of the minus sign in the middle. D does not give a circle.
B is wrong because the y value should be plus. So the answer is C. Notice because the question is multiple choice you don't need to solve for r since all answers give r^2 = 36
19. For which of the following values of x is the function
f(x)=√4-x2 NOT defined as a real number?
[square root]
A. -2
B. 0
C. 2
D. 4
Answer:
D. 4
Step-by-step explanation:
[tex]\sqrt{2-\left( 4\right)^{2} } =\sqrt{2-16} =\sqrt{-12}[/tex]
since ,√(-12) is not a real number
Then
The function f is not defined for x = 4
Answer:
D. 4
Step-by-step explanation:
thank you for your help 4 was the correct answer took the test and got it right
What is DC to the nearest tenth? I need help, thank you:)
The measure of the length DC to nearest tenth is 24.1 units
Pythagoras theoremIn order to determine the measure of DC from the figure shown, we will use the pythagoras theorem
Determine the measure of BC
BC² = 22² - 15²
BC² = 259
BC = 16.09
Determine the measure of DC
DC² = 259 + 28²
DC = √583
DC = 24.1 units
Hence the measure of the length DC to nearest tenth is 24.1 units
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The correct answer is a right?
We can see that a and b are parallel, and c and e are parallel, so the correct option is E.
Which line must be parallel?
On the diagram, we can see that the angles in the third quadrant of the intersections between a and c, and the intersections between b and c, are the same angle.
Then, lines a and b must be parallel.
For the intersections with line d, we can see that this time the angle is on the fourth quadrant, so c and d are not parallel.
Finally, for line e, we can see that the known angle is on the first quadrant.
Notice that the angle on the first quadrant will be equal to the angle on the third quadrant.
So for the intersections of a and e, and b and e, on the third quadrant we have the known angle (the same one as in the intersections of a and c, and a and b).
Then c and e are parallel.
Then A and C are true.
Thus, the correct option is E.
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The length of a rectangle is two more than double the width. If the perimeter is 100 inches, find the
dimensions.
Answer:
width = 34 inches
length = 16 inches
Step-by-step explanation:
Given:
1.)The length of a rectangle is two more than double the width
2.)The perimeter is 100 inches
Let's analyze the first part,
The length is 2 more than double the width so if we let x represent the length the width would be 2x + 2
Now the second part,
the perimeter is calculated by the following formula:
2*(w+l)
(w: width, l: length)
2*(x+2x+2) first do inside the parenthesis by adding like terms
x+2x+2 = 3x + 2 now multiply both terms with 2
2*(3x+2) = 6x + 4 this is the perimeter of the rectangle, now write another equation using this
6x + 4 = 100 subtract 4 from both sides
6x = 96 divide both sides by 6
x = 16 this the length and the width would be
2x + 2 = 2*16 + 2 = 34
- Save & Exit Practice Lesson: 8.5 Applications: Interest and Mixt...
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Question 6 of 8. Step 1 of 1
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Lydia has money in two savings accounts. One rate is 6% and the other is 12 %. If she has $500 more in the 12 % account and the total interest is $375, how much is
invested in each savings account?
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at 6%
at 12%
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CLARISSA HANEY
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Answer:
16y1yg1gyyq717177171716161yggqg1g2y2gqgq62g2gtqy2g
1jwjqhwhwjmnbhokmbhiknb
Compare the monthly payments and total loan costs for the following pairs of loan options. Assume that both loans are fixed rate and have the same closing costs. You need a $200,000 loan Option 1 a 30-year loan at an APR of 10% Option 2 a 15-year loan at an APR of 9.5%. Find the monthly payment for each option. The monthly payment for option 1 is S The monthly payment for option 2 is S (Do not round until the final answer Then round to the nearest cent as needed) Find the total amount paid for each option The total payment for option 1 is S The total payment for option 2 is S (Use the answers from the previous step to find this answer Round to the nearest cent as needed) Compare the two options Which appears to be the better option? OA Option 2 will always be the better option B. Option 1 is the better option, but only if the borrower plans to stay in the same home for the entire term of the loan OC. Option 1 will always be the better option OD. Option 2 is the better option, but only if the borrower can afford the higher monthly payments over the entire term of the loan 0
The monthly payment for option 1 is $1755.144 and option 2 is $2088.97, total amount for option 1 is $631851.84 and option 2 is $376014.6, and on comparing option 2 will be better option.
Given that for $200,000 loan Option 1 is a 30-year loan at an APR of 10% Option 2 is a 15-year loan at an APR of 9.5%.
A concept that implies that the future value of money will be lower than its present value due to several factors such as inflation is known as TVM(time of value money).
Monthly Payments
Option 1
Loan Amount = $200,000
Number of payments = 30×12 = 360
Monthly interest rate = 10%/12 = 0.008333333
Monthly payment = Loan amount (1+ monthly interest rate)ⁿ×monthly interest rate/[(1+monthly interest rate)ⁿ- 1]
Monthly payment=200,000×(1+0.008333333)³⁶⁰×(0.008333333)/[(1+0.008333333)³⁶⁰-1]
Monthly payment=33062.328/18.83739
Monthly payment=$1755.144
Option 2
Loan Amount = $200,000
Number of payments = 15 x 12=180
Monthly interest rate = 9.5%/12=0.00792
Monthly payment = 200,000(1+0.00792)¹⁸⁰(0.00792)/[(1+0.00792)¹⁸⁰-1]
Monthly payment=6553.096/3.137
Monthly payment=$2088.97
Total Payments
Option 1
As we've found out the monthly payments, we now need to multiply it by the number of months.
$1755.144×360 = $631851.84
Option 2
$2088.97×180 = $376014.6
Conclusion
Option 2 will always be the better option economically as it saves $255837.24 ($631851.84 - $376014.6) in total payments.
Hence, For $200,000 loan Option 1 a 30-year loan at an APR of 10% Option 2 a 15-year loan at an APR of 9.5% is the monthly payment for option 1 is $1755.144 and option 2 is $2088.97, total amount for option 1 is $631851.84 and option 2 is $376014.6, and on comparing option 2 will be the better option.
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A line has the equation 32 - 2y = 1 What is the equation of
parallel line going through the point (-6,
- 10)?
The equation is given by Ar + By = C where
Answer:
A = 3; B = -2; C = 2
Step-by-step explanation:
Original line:
3x - 2y = 1
Slope of original line:
-2y = -3x + 1
y = 3/2 x - 1/2
slope = m = 3/2
Parallel lines have equal slopes, so we need the equation of the line with slope 3/2 that passes through the point (-6, -10)
y = mx + b
y = (3/2)x + b
Substitute -6 for x and -10 for y and solve for b.
-10 = (3/2)(-6) + b
-10 + 9 = b
b = -1
Equation: y = (3/2)x - 1
2y = 3x - 2
3x - 2y = 2
f r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)?
The equivalent expression to [tex]\mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}[/tex]
What are the equivalent expressions?Equivalent expressions are similar expressions that may have different forms but when a value is replaced with the variables in the same form provides the same answer.
From the information given, If:
r(x) = 3x - 1s(x) = 2x + 1Then the fractional form can be an expression as:
[tex]\mathbf{(\dfrac{r}{s})(x)= \dfrac{3x-1}{2x+1}}[/tex]
where;
x = 6[tex]\mathbf{(\dfrac{r}{s})(6)= \dfrac{3(6)-1}{2(6)+1}}[/tex]
[tex]\mathbf{(\dfrac{r}{s})(6)= \dfrac{18-1}{12+1}}[/tex]
[tex]\mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}[/tex]
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Question 19 (5 points)
14
8
M
49
28 T
Determine if the two triangles shown are similar. If so, write the similarity
statement.
OA) AVML-AUMT
B) The triangles are not similar.
C) Impossible to determine.
D) AVML-AUTM
Question 20 (5 points)
Saved
Answer:
In question 20
B) the triangles are not similar
Step-by-step explanation:
u can see that 1 triangle length is 14 and other 49 and one triangle breath is 8 and other 28 so how they are same
Answer:
IN question 19
what is your question I can't understand
Solve: ( − )( + ) = �
Answer:
+ and - is always equals to -
Hope it helps!
If you vertically compress the exponential function f(x)=2^x by a factor of 5, what is the equation of the new function?
The equation of the new function is:
[tex]g(x) = \frac{2^x}{5}[/tex]
What is the equation of the compressed function?Here we have the function:
[tex]f(x) = 2^x[/tex]
A vertical compression by a factor of 5 is written as:
[tex]g(x) = f(x)/5[/tex]
Replacing the function f(x) we get:
[tex]g(x) = \frac{2^x}{5}[/tex]
That is the equation of the new function.
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Mal works at a photo gallery. He charges $50 for a large photo and $40 for a large frame. Sales tax is 5%. How much total tax will a customer pay on both?Answer the questions to show how to write and simplify expressions that represent the problem
1. One way to calculate the total tax is 0.05(50 + 40). Use the order of operations to evaluate this expression. Show your work. (2 points)
Answer:
$4.50
Step-by-step explanation:
Okay so, first add both.
50+40 is 90, then multiply 90 by the tax percent which is
90x5%=4.5
If expression then,
x=money that they have to pay.
5%(50+40)=x (the original)
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You want to place stone pavers around the edge of your concrete patio. The patio is 12 ft wide by 14 ft long and each stone paver is 14 inches long . How many stone pavers will you need to go around the patio (not counting the side against the house which is 14 ft long)? (round to the nearest whole number )
The number of stone pavers needed to go round the patio is 3.
What is the number of stone pavers needed to go round the patio?The first step is to determine the perimeter of the concrete patio.
Perimeter : 12 + 12 + 14 = 38 feet
Number of stone pavers needed to go round the patio : perimeter of the patio / length of each stone paver
38 / 14 = 3
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In △ OPQ, OP ≅ QO and m∠O=65∘. Find m∠Q
Answer:
65°
Step-by-step explanation:
Angles opposite congruent sides in a triangle are congruent, so both angle Q and angle P are congruent.
Since angles in a triangle add to 180°, angle Q measures (180-50)/2 = 65°
What is the total length of all meteors that are 1 6/8 inches?
A line plot with the title, length of meteors. The data is measurement in inches. The line plot goes from two eighths to one and seven eighths, with fourteen tick marks in all. The first tick mark is two eighths and has one data point. The second tick mark is three eighths and has three data points. The third tick mark is four eighths and has two data points. The fourth tick mark is five eighths and has no data points. The fifth tick mark is six eighths and has two data points. The sixth tick mark is seven eighths and has no data points. The seventh tick mark is one and has no data points. The eighth tick mark is one and one eighth and has no data points. The ninth tick mark is one and two eighths and has one data point. The tenth tick mark is one and three eighths and has two data points. The eleventh tick mark is one and four eighths and has no data points. The twelfth tick mark is one and five eighths and has no data points. The thirteenth tick mark is one and six eighths and has two data points. The fourteenth tick mark is one and seven eighths and has one data point.
The total length of all meteors that are 1 6/8 inches is three and four-eighths inches.
What is the total length of all meteors?Given :
Tick 1 exists 2/8 (1 data point)
Tick 2 exists 3/8 (3 data points)
Tick 3 exists 4/8 (2 data points)
Tick 4 exists 5/8 (no points)
Tick 5 exists 6/8 (2 data points)
Tick 6 exists 7/8 (no data points)
Tick 2 exists 3/8 (3 data points)
....
Tick 13 exists [tex]$1\frac{6}{8}[/tex] (2 data points)
Therefore, total length of all meteors that exist [tex]$1\frac{6}{8}[/tex] inches :
Length of meteor = [tex]$1\frac{6}{8}[/tex]
Number of meteors = 2
[tex]$(2 * 1\frac{6}{8}) = 2 * 1\frac{4}{8} = \frac{28}{8} = 3 \frac{3}{8} = 3 \frac{1}{2}[/tex]
Therefore, the correct answer is option A. three and four-eighths inches
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The complete question is :
What is the total length of all meteors that are 1 6/8 inches? A line plot with the title, length of meteors. The data is a measurement in inches. The line plot goes from two eighths to one and seven eighths, with fourteen tick marks in all. The first tick mark is two eighths and has one data point. The second tick mark is three eighths and has three data points. The third tick mark is four eighths and has two data points. The fourth tick mark is five eighths and has no data points. The fifth tick mark is six eighths and has two data points. The sixth tick mark is seven eighths and has no data points. The seventh tick mark is one and has no data points. The eighth tick mark is one and one eighth and has no data points. The ninth tick mark is one and two eighths and has one data point. The tenth tick mark is one and three-eighths and has two data points. The eleventh tick mark is one and four eighths and has no data points. The twelfth tick mark is one and five-eighths and has no data points. The thirteenth tick mark is one and six eighths and has two data points. The fourteenth tick mark is one and seven eighths and has one data point.
A) three and four-eighths inches
B) three and five-eighths inches
C) four and seven-eighths inches
D) three and seven-eighths inches
In order to solve the following system of equations by addition, which of the
following could you do before adding the equations so that one variable will
be eliminated when you add them?
4x - 2y = 7
3.x - 3y = 15
Answer:
Multiply the top equation by -3 and the bottom equation by 2
Step-by-step explanation:
Given system of equations:
[tex]\begin{cases}4x-2y=7\\3x-3y=15 \end{cases}[/tex]
To solve the given system of equations by addition, make one of the variables in both equations sum to zero. To do this, the chosen variable must have the same coefficient, but it should be negative in one equation and positive in the other, so that when the two equations are added together, the variable is eliminated.
To eliminate the variable y:
Multiply the top equation by -3 to make the coefficient of the y variable 6:
[tex]\implies -3(4x-2y=7) \implies -12x+6y=-21[/tex]
Multiply the bottom equation by 2 to make the coefficient of the y variable -6:
[tex]\implies 2(3x-3y=15) \implies 6x-6y=30[/tex]
Add the two equations together to eliminate y:
[tex]\begin{array}{l r r}& -12x+6y= &-21\\+ & 6x-6y= & 30\\\cline{1-3}& -6x\phantom{))))))} = & 9\end{array}[/tex]
Solve for x:
[tex]\implies -6x=9[/tex]
[tex]\implies x=-\dfrac{9}{6}=-\dfrac{3}{2}[/tex]
Substitute the found value of x into one of the equations and solve for y:
[tex]\implies 3\left(-\dfrac{3}{2}\right)-3y=15[/tex]
[tex]\implies -\dfrac{9}{2}-3y=15[/tex]
[tex]\implies -3y=\dfrac{39}{2}[/tex]
[tex]\implies y=-\dfrac{39}{2 \cdot 3}[/tex]
[tex]\implies y=-\dfrac{13}{2}[/tex]
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Solve the system of equations by substitution.
2x + y = 3z
x + y = 6z
What is the value for y from the first equation, that could be substituted into the second equation?
A. -2x +3z
B. 3z + 2x
C. -2x - 3z
D. 2x + 3z
Identify the compositions performed on ΔXYZ to map onto ΔX″Y″Z″.
Triangle XYZ was translated 2 units left and 1 unit up to form triangle X'Y'Z'. It was then rotated 180° about the origin to form triangle X''Y''Z''
What is transformation?Transformation is the movement of a point from its initial location to a new location. Types of transformations are reflection, rotation, translation and dilation.
Translation is the movement of a point either up, left, right or down in the coordinate plane.
Triangle XYZ was translated 2 units left and 1 unit up to form triangle X'Y'Z'. It was then rotated 180° about the origin to form triangle X''Y''Z''
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Perform the indicated operation 7 1/8×5 2/3
Answer:
40 3/8
Step-by-step explanation:
You can just multiple it on calculator, which 1/8 is 0.125 so convert 40.375 to 40 3/8
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Which equation is equivalent to StartRoot x EndRoot + 11 = 15?
x + 11 = 225
x + 121 = 225
StartRoot x EndRoot = 15 + 11
The equivalent expression of [tex]\sqrt x + 11 = 15[/tex] is [tex]\sqrt x = 15 - 11[/tex]
How to determine the equivalent expression?The complete question is in the attached image
The expression is given as:
[tex]\sqrt x + 11 = 15[/tex]
Subtract 11 from both sides of the equation
[tex]\sqrt x + 11 - 11= 15 - 11[/tex]
This gives
[tex]\sqrt x = 15 - 11[/tex]
Hence, the equivalent expression of [tex]\sqrt x + 11 = 15[/tex] is [tex]\sqrt x = 15 - 11[/tex]
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Suppose we want to choose objects, without replacement, from the objects pencil, eraser, desk, and chair.
(a) How many ways can this be done, if the order of the choices is relevant?
(b) How many ways can this be done, if the order of the choices is not relevant?
The number of ways when the choice is not relevant is 10
How to determine the number of ways?The number of objects are:
Object, n = 5
The object to choose are:
r = 3
Relevant choice
When the choice is relevant, we have:
[tex]Ways = ^nP_r[/tex]
This gives
[tex]Ways = ^{5}P_3[/tex]
Evaluate
Ways = 60
Hence, the number of ways when the choice is relevant is 60
Not relevant choice
When the choice is not relevant, we have:
[tex]Ways = ^nC_r[/tex]
This gives
[tex]Ways = ^{5}C_3[/tex]
Evaluate
Ways = 10
Hence, the number of ways when the choice is not relevant is 10
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the chairs in a hall are about to be arranged in a row. if i put 6 chairs in a row there will be 4 left if i put 7 chairs in a row there will be 3 short how many chairs are there
Step-by-step explanation:
THERE WILL BE
6+4+3+7= 23