Eric and Kelsey each work after school to earn money. Eric charges $10, plus an additional $4 per hour to babysit. Kelsey charges $15, plus an additional $3 per hour to rake. Eric and Kelsey work the same number of hours. Which system of equations can be used to determine how many hours, x, they need to work to earn the same amount of money, y?
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Answer: Hi here go your answer is

25 divides by 36 is 0.69444 or 0.69

Step-by-step explanation:

Answer:

- 11 < x < 8

Step-by-step explanation:

inequalities of the type | x | < a have solutions of the form

- a < x < a

then

| 2x + 3 | < 19

- 19 < 2x + 3 < 19 ( subtract 3 from each interval )

- 22 < 2x < 16 ( divide each interval by 2 )

- 11 < x < 8

The measure of the length and width of the rectangle is given as 135 feet and 92 feet respectively.

From the information given, we have the following proofs;

Length, l = 2x + 30 - 49

Length = 2x - 19

The formula for perimeter of a rectangle is given as;

Perimeter = 2( length + width)

Substitute the expressions into the formula

Perimeter =  2 ( x+ 15 + 2x - 19 )

Perimeter = 2 (3x - 4)

Perimeter = 6x - 8

We have that the area is  162 more than 27 times the perimeter, which is Area = 27 (perimeter )+ 163

Area = 27(6x-8) + 162

Expand the bracket

Area= 162x - 216 + 162

Area = 162x - 54

But we know that

Area = length × width

Substitute the expressions

Area = (x+15)(2x-19)

Area =  2x² - 19x +30x - 285

Area = 2x² + 11x - 285

Equate the two formulas for area

162x - 54 = 2x² +11x - 285

Collect like terms

2x² + 11x - 285 - 162x + 54 = 0

2x²  - 151x - 231 = 0

Solve the quadratic equation

(2x + 3)(x-77) = 0

Let's solve for x

x - 77 = 0

x = 77

The expression for the width;

Width = x+15

Width = 77 + 15

Width = 92 feet

The expression for the length

Length = 2(x+15) - 49

Length = 2 ( 77 + 15) - 49

Length = 154 + 30 - 49

Length = 184 - 49

Length = 135 feet

Thus, the measure of the length and width of the rectangle is given as 135 feet and 92 feet respectively.

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Answer:

280

Step-by-step explanation:

Set up a ratio to solve.

Mr. Fraser's class has 20 soccer playing students, and 14 are boys.

14/20 = x/400

Cross multiply. 20x= 5600

Divide by 20 to solve

x= 280

The least positive integer, written only by numbers 0, 1, and 2, which is divisible by 225 is 1,222,200.

A number (A) is divisible by another number (K) when the division of A by K, leaves a remainder of 0.

In the question, we are asked to find the least positive integer, written only by numbers 0, 1, and 2, which is divisible by 225.

Now, we need to know that the multiples of 225 end with 00, 25, 50, and 75.

So, to have a multiple with digits 0, 1, and 2, we need the last digits to be 00.

The smallest multiple of 225, ending with 00 is 225*4 = 900.

So, we need to have the least multiple of 900, with digits 0, 1, and 2.

We know that a multiple of 9, has a sum of its digit as 9.

The smallest multiple of 9, with digits 1, and 2, will be 12222.

Adding the last 00 to this, we get the least multiple as 1,222,200.

Thus, the least positive integer, written only by numbers 0, 1, and 2, which is divisible by 225 is 1,222,200.

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The Outcome of event A and B is simply the intersection of both sets written as A ∩ B is; C: {seagull, crow}

From the image, we are given the animals namely; Pig, Penguin, Seagull, Tiger, Crow, Bat, Mosquito.

Now, these animals are classified as either a bird or can fly.

Animals that are birds are; Penguin, Seagull, Crow

Animals that can fly are; Seagull, Crow, Bat, Mosquito.

Now, we are told that;

Event A is the animal is a bird. Thus, the set notation that represents this event A is written as;

A = {Penguin, Seagull, Crow}

Event B is that the animal can fly and again the set notation that represents event B is written as;

B = {Seagull, Crow, Bat, Mosquito}

Now, Outcome of event A and B is simply the intersection of both sets. Thus; A ∩ B = {seagull, crow}

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Answer:

6

Step-by-step explanation:

The arc length is (2)(pi)(27)(40/360)=6pi.

So, k=6.

The function f(x) = -(1/1500)(x³ + 10x² - 275x - 1500) the zeros are at (-20, 0), (-15, 0) and (15, 0). Hence the factors of the function are x + 20, x + 15 and x - 15.

An equation is an expression that shows the relationship between two or more numbers and variables.

From the graph of the function f(x) = -(1/1500)(x³ + 10x² - 275x - 1500) the zeros are at (-20, 0), (-15, 0) and (15, 0). Hence the factors of the function are x + 20, x + 15 and x - 15.

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Answer:

30

Step-by-step explanation:

Since ABC is isosceles, BC = CA.

So, AB = 9(3)+3 = 30.

[tex]y = 9x {}^{2} - 4 \\ flip \: x \: and \: y \\ x =9 (y ) {}^{2} - 4 \\ solve \: for \: the \: inverse \: of \: y \\ x + 4 = 9(y ) {}^{2} \\ y {} {}^{2} = \frac{x + 4}{9} \\ you \: can \: split \: it \: into \: two[/tex]

[tex]y {}^{(1)} = \sqrt{ \frac{x + 4}{9} } \\ y {}^{(2)} = - \sqrt{ \frac{x + 4}{9} } [/tex]

Answer:

3x + 18

Step-by-step explanation:

3x + 10 = 3y - 2(y + 4)

3x + 10 = 3y - 2y - 8

3x + 18 = y

Answer:

D, 3x + 18.

Step-by-step explanation:

3x + 10 = 3y - 2(y + 4)

3x + 10 = 3y - 2y - 8

3x + 10 = y - 8

y = 3x + 10 + 8

y = 3x + 18.

Answer-4,5

Step-by-step explanation:

The value of the given division operation is 3/7

From the question, we are to determine the quotient of the given division operation

The given division operation is

-3/2÷-7/2

[tex]\frac{-3}{2} \div \frac{-7}{2}[/tex]

[tex]=\frac{-3}{2} \times \frac{2}{-7}[/tex]

[tex]=\frac{-3}{-7}[/tex]

[tex]=\frac{3}{7}[/tex]

Hence, the value of the given division operation is 3/7

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The quantity of water left in the tank as described in the task content is; 111 l 220ml.

The tank described in the task content initially contains 200 liters, in which case, 1 liter corresponds to 1000ml.

Hence, when 88l 580ml was used, the remaining quantity of water is; 200l - (88l 580ml) = 111 l 420ml.

And finally, since 200 ml leaked, the quantity of water left is; 111l 220ml.

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Answer: 1/45

Step-by-step explanation: 10 total marbles. 4 are blue 3 are red 2 are green and 1 is yellow. The chance of drawing a green is 2/10 or 1/5. Then there are only 9 marbles left in the bag. So the chance of a yellow marble is 1/9. 1/5 x 1/9 = 1/45.

Answer:

B

Step-by-step explanation:

Cos(0)=1

since the diagram shows x as (1,0)

Answer:

41 years old

Step-by-step explanation:

2050-2022=28 years

13years old +28years = 41 years old (sorry if wrong)

Answer: Based on today's date of 7/19/2022, you will be 41 until October 21, 2050. On October 21, 2050 you will turn 42. You were born in 2008

Step-by-step explanation:

Answer:

y = 3x - 7

Step-by-step explanation:

Since the lines are parallel, the slopes will be the same.  In this case 3.  Now we have to find the y-intercept.  We will use the slope (3), the x (2) and  y (-1) to help us do this.  We get the x and the y from the ordered pair given(2,-1).

y = mx + b

-1 = 3(2) + b   Plug in what you know

-1 = 6 + b       Subtract 6 from both sides

-7 = b

Now we can write the equation

y = 3x -7

Answer: The function is even because [tex]f(x)=f(-x)[/tex].

Step-by-step explanation:

[tex]f(x)=3x^4 \\\\f(-x)=3(-x)^4 = 3x^4\\\\\therefore f(x)=f(-x)[/tex]

So, the function is even.

Answer:180 °

Step-by-step explanation:

Answer:

90 degrees

Step-by-step explanation:

The only numbers that are possible to be divided into 180 are these: 30, 45, 60, 90, & 180.

Now to figure out if this figure is symmetrical. It is. Why? Because you can put at least one line through each triangle. 8 in total but 180 cannot be divided by 8. So you could maybe split it in half. 180/4= 45

45x2= 90

Easy: Since there are now, two halves, since it is split up, it could be possible that the answer could be 90. Because 180/2 halves= 90.

The answer is 90

Answer: 3.217 & 12.434

Step-by-step explanation:

If we use w to represent the width, the length will be 6 more than 2 times w.

Hence, the length is [tex]2w+6[/tex].

The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.

[tex]A=w(2w+6)[/tex]

We can also substitute 40 in for A as it's given in the question.

[tex]40 = w(2w+6)[/tex]

Distributing w by multiplying it by both terms in the parentheses, we get

[tex]40 = 2w^2+6w[/tex]

We can make the equation simpler by dividing both sides by 2.

[tex]20 = w^2+3w[/tex]

Subtracting both sides by 20 will make the left-hand side 0.

[tex]0=w^2+3w-20[/tex]

Now that we have put this quadratic equation into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.

For reference, the quadratic formula is

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In this case, a is 1, b is 3, and c is -20.

Substituting, we get

[tex]w=\frac{-3\pm\sqrt{3^2-4(1)(-20)}}{2(1)}[/tex]

[tex]w= \frac{-3\pm\sqrt{9+80}}{2}[/tex]

[tex]w=\frac{-3+\sqrt{89}}{2}\hspace{0.1cm}or\hspace{0.1cm}\frac{-3-\sqrt{89}}{2}[/tex]

Since the second solution results in a negative number, it cannot be the length of w.

[tex]w=\frac{-3+\sqrt{89}}{2}\approx3.217[/tex]

The width/breadth of the rectangle is 3.217 cm.

To calculate the length, let's substitute the width into the expression for the length:

[tex]l=2(3.217)+6[/tex]

[tex]l=12.434[/tex]

The length of this rectangle is 12.434 cm.

abc =32 ft³  is the maximum volume of an open rectangular box (with no top face) if its surface area is 1 square foot.

A rectangle with all equal sides, commonly known as a square.  Multiplying the length by the length is the. Using L as the length of each side, solve for L X L = L2,

The maximum volume of an open rectangular box (with no top face) if its surface area is 1 square foot This Lagrange multiplier optimization is standard. If the box has a base of a, a height of c, and an area constraint of ab+2ac+2bc−48=0  we wish to optimize V= abc.

L(a,b,c,λ)= abc−λ(ab+2ac+2bc−48)

The four partial derivatives are zero at an ideal position, so:

δLδa=bc−λ(b+2c)=0

δLδb=ac−λ(a+2c)=0

δLδc=ab−λ(2a+2b)=0

Plus the restriction. The first two enlighten:

λ=bcb+2c=aca+2c

Consequently,  b(a+2c)=a(b+2c)  implies to b=a. The third partial, where b=a, now informs us that   a2=4aλ  and so  λ=a/4  nd by using this information in the second partial, we obtain  4c=a+2c  which informs us that c=a/2 .

Now that we've inserted these b and c expressions into the constraint, we get [tex]3a^2=1[/tex]  which means that a=4 feet, b=4 feet, and c=2 feet.

The maximum volume is therefore, abc=32 ft³

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Answer:

$ 7.52

Step-by-step explanation:

Find charge per minute

 59 - 23 min = 36 minutes   cost   16.32 - 10.56 = $ 5.76

      or   $5.76 / 36 min = 16 cents per min

   from 59 to 78 = 19 more minutes        x .16/min =  $ 3.04

            so from 59 to 78 will leave 10.56 - 3.04 = $7.52

The surface area of the composite figure shown in the figure attached is 233.6 cm²

An equation is an expression that shows the relationship between two or more numbers and variables.

The surface area of the composite = (6 * 8) + 2(8 * 3.6) + 2(0.5)(6 + 2 + 6 + 2)(3) + (8)(2 + 6 + 2) = 233.6 cm²

The surface area of the composite figure shown in the figure attached is 233.6 cm²

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The graph of a function f exists the set of all points in the plane of the form (x, f(x)).

The graph of a function f exists the set of all points in the plane of the form (x, f(x)). We could even describe the graph of f to be the graph of the equation y = f(x). So, the graph of a function exists as a special case of the graph of an equation.

Given: [tex]h(t)=0.6\cdot 3.2^t[/tex]

Substitute the values in the function, we get

t = -2, h(t) = 0.05859375

t = -1, h(t) = 0.1875

t = 0, h(t) = 0.6

t = 1, h(t) = 1.92

t = 2, h(t) = 6.144

t = 3, h(t) = 19.6608

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Using the mean concept, the average collection for a student in this school was of $16.13.

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations.

The number of students is given as follows:

82 + 74 + 96 + 99 = 351.

The sum is:

82 x 26.75 + 74 x 12.25 + 96 x 15.50 + 99 x 10.85 = $5662.15

Hence the mean is:

M = $5662.15/351 = $16.13.

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Answer:

2x⁴-45x-8

Step-by-step explanation:

The area of the paper that remains is 391.04 cm²

From the question, we are to calculate the area of the remaining part of the paper

Area of the paper that remains = Area of rectangle - 2×Area of semicircle

Area of the paper that remains = (l×w) - 2(πr²/2)

Area of the paper that remains = (l×w) - (πr²)

Where l is the length of the paper

w is the width if the paper

and r is the radius of the semicircle

From the given information,

l = 37 cm

w = 16 cm

r = w/2 = 16/2 = 8 cm

Putting the parameters into the equation,

Area of the paper that remains = (37×16) - (3.14(8)²)

Area of the paper that remains = 592 - (3.14×64)

Area of the paper that remains = 592 - 200.96

Area of the paper that remains = 391.04 cm²

Hence, the area of the paper that remains is 391.04 cm²

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The scale factor that can be applied to Cone 1 to make Cone 2 is 0.8

This are constants that is used to enlarge of diminish a given figure of sides of a figure

We can determine the scale factor by finding the ratio of the similar sides of two figures, From the given cones, the ratio of their radius can determine the scale factor that is applied to Cone 1 to make Cone 2

From the given figure;

scale factor = radius of cone 2/radius of cone 1

Given the following parameters

radius of cone 2 = 2 ft

radius of cone 1 = 2.5ft

Substitute

scale factor =  2/2.5

scale factor = 0.8

Hence the scale factor that can be applied to Cone 1 to make Cone 2 is 0.8

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