The statement that every diagonal of a trapezoid divides it into two congruent triangles is false.
What is Congruence of Triangles?Two or more triangles are said to be congruent if and only if sides and angles of one triangle is equal to the corresponding sides and angles of another triangle.
A trapezoid is a quadrilateral which has at least one pair of parallel sides.
The sides may or may not be equal.
Consider an isosceles trapezium, ABCD, given below which has two parallel opposite sides and the other pair of sides are equal.
If we draw a diagonal, AC, we have two triangles ABC and ADC.
AC = AC (common side)
AD = BC (given)
But AB ≠ CD
Hence the triangles cannot be congruent.
Hence the given statement is false.
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Another customer calls you wanting to know how much fence they should install around the circumference of their circular garden if they bought 210 feet of topsoil. assume the customer created a circle out of the soil and calculate the circumference in linear feet.
The circumference of a circular garden is 51.5 feet.
What is area of a circle?The area of a circle is the space occupied by the circle in a two-dimensional plane. Alternatively, the space occupied within the boundary/circumference of a circle is called the area of the circle. The formula for the area of a circle is A = πr², where r is the radius of the circle.
Given that, the area of a circular garden is 210 square feet.
Here, 210=3.14×r²
r²=210/3.14
r²=66.87
r=8.2 feet
Now, circumference =2πr
= 2×3.14×8.2
= 51.5 feet
Therefore, the circumference of a circular garden is 51.5 feet.
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write a function count element : 'a list -> 'a -> int such that count element l m returns the number of elements in the input list l that are equal to m. the function is required to use (only) tail recursion (no other form of recursion). you may not use any library functions.
Here's an implementation of the "count_element" function in OCaml:
| x :: xs -> count (if x = m then acc + 1 else acc) xs
in count 0 l
ocaml
let count_element l m =
let rec count acc = function
| [] -> acc
x = m, then acc + 1; otherwise, acc) | x:: xs -> count 0 xs in count
The function takes a list l and a value m to count, and returns the number of elements in the list that are equal to m. The function uses tail recursion by accumulating the count of matching elements in the acc variable, which is passed along with the remaining list to the recursive call.
The base case is when the input list is empty, in which case the accumulated count is returned. The recursive case checks whether the head of the list matches the target value, and updates the accumulator accordingly. The function then recurses on the tail of the list.
Note that the function is not specific to any particular type of elements in the list, so it should work with any type that supports equality.
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What is the length of the third side, or c?
The length of the third side or c=30 feet.
What is length?Length is defined as the measurement of distance of an object from one end to the other.
The length of the sides of a triangle is given by ,
a=24 feet, b=18 feet. c=?.
By Pythagorean theorem,
“In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“.
[tex]c^{2}=a^{2} +b^{2}[/tex]
[tex]c^{2} = 24^{2} +18^2[/tex]
= 900
⇒c=30 feet.
Hence, the length of the third side or c=30 feet.
Question:
The given diagram forms the triangle with the length of the sides ,
a=24 feet, b=18 feet. Find the length of the side c.
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An oil tank is to be drained for cleaning. There are V(t) gallons of oil left in the tank t minutes after the draining began, where V(t)= 45(60-t)^2.
a) Find the average rate at which oil drains during the first 15 minutes.
b) Find the average rate at which oil drains during the time interval [10, 15].
c) Find the rte at which oil is flowing out of the tank 15 minutesafter the draining began.
a - The average rate at which oil drains during first 15 minutes is -4725 gallons/min
b - The average rate at which oil drains during time interval [10 , 15] is -4275 gallons/min
c - The rate of oil flowing out 15 min after the drain began is -4050 gallon/min
We have ,
V(t) = 45(60 - t)²
The average rate at which oil drains during first 15 minutes can be given as:
V(0,15)=[tex]\frac{V(15)-V(0)}{t2-t1}[/tex]
= (45(60-15)²-45(60-0)²)/15
= -70875/15
= -4725 gallons/min
Similarly , the average rate for time interval [10 , 15] is
V(10 , 15) = [tex]\frac{V(15)-V(10)}{t2-t1}[/tex]
= (45(60-15)²-45(60-10)²)/(15-10)
= -21375/5
= -4275 gallons/min
Now , to find rate of oil flowing out 15 min after the drain began
For that we will differentiate the given equation with respect to t
V(t) = 45(60 - t)²
= 45(3600 - 120t + t²)
= 16200 - 5400t + 45t²
Differentiating with respect to t we have
V'(t) = -5400 + 90t
V'(t) = -5400 + 90(15)
= -4050 gallon/min
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Write and evaluate the definite integral that represents the volume of the solid formed by revolving the region about the y-axis. y = √49 - x^2
The volume of the solid formed by revolving the region about the y-axis is (1372/3)π.
The given region is a semicircle with a radius of 7 centered at the origin, so we can find its volume by revolving it about the y-axis using the disk method.
The area of a disk at a distance y from the y-axis is given by π(√(49 - y²))², so the volume of the solid is given by the integral:
V = ∫(from -7 to 7) π(√(49 - y²))² dy
Simplifying the integrand, we get:
V = ∫(from -7 to 7) π(49 - y²) dy
Evaluating this integral, we get:
V = π[(49y - (1/3)y³)](from -7 to 7)
V = π[(49(7) - (1/3)(7³)) - (49(-7) - (1/3)(-7³))]
V = π[686/3 + 686/3]
V = (1372/3)π
So the volume of the solid formed by revolving the region about the y-axis is (1372/3)π.
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let fxn; n 0g be a dtmc on state space f1; 2; : : : ; ng. suppose it incurs a cost of c.i / dollars every time it visits state i. let g.i / be the total expected cost incurred by the dtmc until it visits state n starting from state i. derive the following equations: g.n / d0; g.i / dc.i / c pn jd1 pi;j g.j /; 1 j n 1
We can derive the equations using the principle of optimality for Markov decision processes. This principle states that an optimal policy for a process must satisfy the property that whatever the initial state and initial decision are, the remaining decisions must constitute an optimal policy with regard to the state resulting from the first decision.
Let g(i) denote the total expected cost incurred by the DTMC until it visits state n starting from state i. We can express this as:
g(i) = c(i) + p(i, i+1)g(i+1) + p(i, i+2)g(i+2) + ... + p(i, n-1)g(n-1)
Here, p(i, j) denotes the transition probability from state i to state j. The first term c(i) represents the cost incurred by visiting state i for the first time, and the second term p(i, i+1)g(i+1) represents the expected cost of moving from state i to state i+1 and continuing optimally from state i+1. The same applies to the following terms, with the last term p(i, n-1)g(n-1) representing the expected cost of moving from state i to state n-1 and continuing optimally from state n-1 to state n.
To solve for g(n), we note that the expected cost to reach state n from state n is zero since we are already at the target state. Therefore, we have:
g(n) = 0
Now, we can use the principle of optimality to solve for the remaining g(i)'s. Specifically, we consider the expected cost of moving from state i to state i+1 and continuing optimally from state i+1. This can be expressed as:
c(i) + p(i, i+1)g(i+1)
The optimal decision is to minimize this cost, which can be achieved by choosing the state j that minimizes the cost of moving from state i to state j and continuing optimally from state j. Therefore, we have:
g(i) = c(i) + min_j{p(i, j)g(j)}, for 1 <= i < n
This equation states that the expected cost of visiting state i and continuing optimally to state n is the sum of the cost of visiting state i and the expected cost of moving from state i to the state j that minimizes the expected cost of moving from state i to state j and continuing optimally from state j.
Combining the two equations, we obtain the desired results:
g(n) = 0
g(i) = c(i) + min_j{p(i, j)g(j)}, for 1 <= i < n
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Discuss the pros and cons of different times in a person's life when taxes can be withheld.
Early tax withholding offers predictability and facilitates effective financial planning but restricts financial flexibility and investment potential. Meanwhile, late tax withholding fosters short-term financial flexibility and investment opportunities but carries the risk of miscalculations, underestimations, and potential penalties.
Explanation:The timing of tax withholding can have different pros and cons depending on an individual's current financial status, revenue predictions, and personal preferences.
A primary advantage of early tax withholding is increased predictability. By setting aside funds for taxes in advance, an individual can have a clearer picture of their net income and employ effective financial planning strategies. However, this approach does have a notable drawback. Specifically, the individual may miss potential investment opportunities as a result of having their money tied up in tax withholdings.
On the other hand, late tax withholding allows greater short-term financial flexibility, providing the opportunity to use funds for immediate personal or business needs. It can also enable investment in lucrative opportunities. However, the main downside is the potential for miscalculation and underestimation of the tax liability, which can lead to financial strain or penalties.
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Please help answer this math problem!
Answer:
357
Step-by-step explanation:
0.22x=49.95+0.08x
Answers basically x+1
write the expression as a square of a monomial. 64x^6
The expression 64x^6 can be written as a square of a monomial by taking the square root of both sides of the expression:
√(64x^6) = √(64) * √(x^6) = 8 * x^3
So, the expression 64x^6 can be written as the square of the monomial 8x^3.
Answer: √(64x^6) = √(64) * √(x^6) = 8 * x^3 So, the expression 64x^6 can be written as the square of the monomial 8x^3. The exact thing that legoslucaswang had said but it's just a different way of saying it.
STEVE HAS A BUDGET OF 45.00 TO SPEND ON DECORATION FOR A PARTY HE BOUGHT 5 PACKAGES OF STREAMERS FOR 1.59 EACH HE ALSO WANTS TO BUY BALLOONS THAT COST 3.29 PER PACKAGE WRITE AN INEQULITY TO MODEL THE STIUATION USE THE VARIABLE N TO REPRESENT PACKAGES OF BALLOONS THEN SOLVE
Step-by-step explanation:
Inequality: 1.59(5) + 3.29n ≤ 45.00
Explanation: 1.59(5) represents the total cost of the streamers, and 3.29n represents the total cost of the balloons (since we don't know how many packages of balloons Steve will buy, we use the variable n to represent this unknown quantity). The sum of these costs must be less than or equal to Steve's budget of $45.00.
To solve for n:
1.59(5) + 3.29n ≤ 45.00
7.95 + 3.29n ≤ 45.00
3.29n ≤ 37.05
n ≤ 11.27 (rounded to two decimal places)
So Steve can buy a maximum of 11 packages of balloons within his budget.
in a ballroom dance competition, each couple is identified by a number worn on the leader's back. at a recent competition, forty couples competed. their numbers are listed below:
The average value of the competition is 193.525.
To find the average value of the competition, we need to add up all the assigned numbers and divide by the total number of couples. In other words, we need to find the arithmetic mean of the data set.
In a ballroom dance competition, each couple is assigned a number for identification purposes. In this particular competition, forty couples competed, and we are interested in finding the average value of their assigned numbers.
First, we add up all the numbers:
=> 103 + 105 + 112 + 116 + 117 + 122 + 126 + 130 + 139 + 147 + 154 + 159 + 165 + 170 + 176 + 178 + 182 + 184 + 187 + 193 + 196 + 199 + 206 + 207 + 211 + 216 + 224 + 227 + 230 + 237 + 242 + 246 + 249 + 252 + 258 + 264 + 267 + 270 + 275 + 281 = 7741
Next, we divide by the total number of couples, which is 40:
7741 ÷ 40 = 193.525
It is important to note that the average is not necessarily a value that is present in the data set. In this case, none of the couples were assigned the exact number 193.525.
Instead, the average represents a central tendency of the data set, which can be useful in comparing and analyzing different competitions.
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Complete Question:
In a ballroom dance competition, each couple is identified by a number worn on the leader's back. At a recent competition, forty couples competed. Their numbers are listed below: 103 105 112 116 117 122 126 130 139 147 154 159 165 170 176 178 182 184 187193 196 199 206 207 211 216 224 227 230 237 242 246 249 252 258 264 267 270 275 281
Find the average value of the competition
Let f(x) = 4x2 – 63. We want to estimate f(3.05) using linear approximations. That is, using an appropriate tangent line. First, we will build the tangent line at (x, y)=_____ Enter as an ordered pair (a,b). The slope of the tangent line comes from f'. For this problem, f'(x) = ______
And mtan = _____
The equation of the tangent line, in slope intercept form, is y = T(x) = ______
Now, f(3.05) = T(3.05) =______
Compare to actual value f(3.05) =_____
The tangent line at (x, y) = (3, 33) is y = 25x + 8.Enter as an ordered pair (a,b). The slope of the tangent line comes from f'. For this problem,f'(x) = 8x. And mtan = f'(3) = 24.The equation of the tangent line in slope-intercept form is y = T(x) = 24x - 69.
T(3.05) = 24(3.05) - 69 = -18.2.
f(3.05) = 4(3.05)^2 - 63 = -16.73.
We want to estimate the value of f(x) = 4x^2 - 63 at x = 3.05 using linear approximations. This means we need to find the equation of the tangent line to the graph of f at x = 3, which will give us a good approximation of f(3.05) near x = 3.
To find the tangent line, we first need to find the slope of the tangent line, which is given by the derivative of f at x = 3. We have f(x) = 4x^2 - 63, so f'(x) = 8x. Therefore, f'(3) = 24, which is the slope of the tangent line at x = 3.
Next, we need to find a point on the tangent line. We can use the point (x, y) = (3, 33), which is on the graph of f and also happens to be at x = 3. This means the tangent line at (3, 33) will be very close to the graph of f near x = 3.
Using the point-slope form of a line, we can find the equation of the tangent line at (3, 33):
y - 33 = 24(x - 3)
Simplifying this equation gives us the slope-intercept form of the tangent line:
y = 24x - 69
Now we can use this equation to estimate the value of f(3.05) by plugging in x = 3.05:
T(3.05) = 24(3.05) - 69 = -18.2
This means the tangent line predicts that f(3.05) is approximately -18.2.
To compare this to the actual value of f(3.05), we can plug it into the original function:
f(3.05) = 4(3.05)^2 - 63 = -16.73
So the actual value of f(3.05) is approximately -16.73, which is close to the estimate given by the tangent line.
In summary, using linear approximations, we found that the tangent line at (3, 33) has a slope of 24 and passes through the point (3, 33). The equation of the tangent line is y = 24x - 69. Using this equation, we estimated that f(3.05) is approximately -18.2, which is close to the actual value of -16.73.
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use the distributive property to create an equivalent expression.
7(x +2y + 3z)
Pls help
7 (x + 2y + 3z)
Distribute 7
7x + 7 x 2y + 7 x 3z
Calculate
7x + 14y + 21z should be your answer.
Tim and Jessica plan to rent a camper van for a vacation. The can costs $183 per day. The rental includes 120 miles for free then charges $0.39 per mile.
The total price Tim and Jessica paid to rent the camper van is 598.74. An equation that models the cost of the van rental in terms of miles traveled, m, is 598.74 = 183 + 0.39 (m - 120)
Use the equation to determine how many miles Tim and Jessica tracked if they paid 598.74
The equation that represents the cost of the van rental is $598.74 = 136.20 + $0.39m .
What is equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
The general form of linear equations is:
y = a + bx
Where:
a = intercept
b = slope
The form of the equation that models the cost is:
Total cost = cost of renting the van + [cost per mile x (m - 120 miles)
$598.74 = $183 + [$0.39 x (m - 120)
$598.74 = $183 + $0.39m - 46.80
$598.74 = 136.20 + $0.39m
Thus, they travelled 1186 miles.
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A flagpole casts a 17-foot shadow on the ground when the sun is at a 59° angle of
elevation. Which of the following expressions can be used to determine the height (h), in
feet, of the flagpole? (Assume the flagpole is perpendicular to the ground.)
A. cos59° =h/17
B. tan59° =h/17
C. sin59° =h/17
D. cot59° =h/17
The expression tan59° = h/17 can be used to determine the height (h), in feet, of the flagpole.
What is the right triangle?A right triangle is defined as a triangle in which one angle is a right angle or two sides are perpendicular.
The height of the flagpole is the opposite side of the right triangle formed by the flagpole, its shadow on the ground, and the line from the top of the flagpole to the end of the shadow.
The angle of elevation of the sun is opposite the height of the flagpole, and the length of the shadow is the adjacent side.
Therefore, the tan of the angle of elevation is equal to the height of the flagpole divided by the length of the shadow:
tan59° = h/17
Thus, the correct expression to determine the height of the flagpole is:
B. tan59° = h/17
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write each number as fraction or mixed number in simplest form 9.355
The fraction form or mixed number in simplest form of number 9.355 is,
⇒ 1871 / 200
What is mean by Fraction?The number is expressed as a quotient in which the numerator is divided by the denominator is called fraction.
Given that;
The number is,
⇒ 9.355
Now, We can simplify the number to change in fraction as,
⇒ 9.355
Multiply and divide by 1000;
⇒ 9355/1000
Multiply and divide by 5;
⇒ 1871 / 200
Thus, We get;
The fraction form or mixed number in simplest form of number 9.355 is,
⇒ 1871 / 200
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c) Find the perimeter
The measure of the perimeter of the shape is 12.78cm
Finding the perimeter of a composite figureThe given figure consists if a right triangle and a semicircle. The perimeter of the shape is calculated using the expression;
Perimeter = perimeter of the semicircle + 4.5cm + 2cm
Perimeter of the figure = πr + 6.5cm
Perimeter of the figure = 3.14(2) + 6.5
Perimeter of the figure = 6.28 + 6.5
Perimeter of the figure = 12.78cm
Hence the perimeter of the given composite figure is 12.78cm
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Andrew's bank account started off with a deposit of $750, and after 4 years he earned $165 in interest. The interest is simple interest, calculated on the basis of the initial deposit. What is the interest rate that Andrew's bank provides? Give your answer as a percentage to the nearest tenth of a percent.
The solution is, 5.5% is the interest rate that Andrew's bank provides.
What is interest?Interest is the price you pay to borrow money or the cost you charge to lend money. Interest is most often reflected as an annual percentage of the amount of a loan. This percentage is known as the interest rate on the loan.
here, we have,
Andrew's bank account started off with a deposit of $750,
and after 4 years he earned $165 in interest.
we know,
formula: I = Prt.
let, the interest rate that Andrew's bank provides = r%
so, solving we get,
r = 5.5%
Hence, The solution is, 5.5% is the interest rate that Andrew's bank provides.
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jack and diane are designing a trellis for some special plants they are planning to put in their backyard garden. use the values provided on the sketch of the trellis to find the missing values for and . (round your answers to the nearest hundredth.)
Using the values provided on the sketch of the triangular trellis, the values for x, y, and z are 13.33 ft, 6.75 ft, and 17.37 ft, respectively.
From the provided sketch of the trellis, we can use the similar triangles and similar trapezoids to solve the values of x, y, and z.
Consider similar trapezoids at the bottom of the trellis.
10/(10 + 6) = x/(8 + x)
80 + 10x = 16x
6x = 80
x = 40/3 = 13.33
Consider the similar triangles at the top of the trellis.
9/(9 + x) = 7/z
9/(9 + 40/3) = 7/z
z = 469/27 = 17.37
y/(y + 10) = 9/(9 + x)
y/(y + 10) = 9/(9 + 40/3)
(67/3)y = 9y + 90
(40/3)y = 90
y = 27/4 = 6.75
Hence, the length of x, y, and z is 13.33 ft, 6.75 ft, and 17.37 ft, respectively.
The problem seems incomplete, it must have been...
"Jack and Diane are designing a trellis for some special plants they are planning to put in their backyard garden. Use the values provided on the sketch of the trellis to find the missing values for x, y, and z. (Round your answers to the nearest hundredth.)
See attached copy of the complete question."
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I need help please i dont understand this
The distance from where it is tied to the base of the pole is 7.25ft
Solving angles of elevation and depressionThen given resulting figure that translated the statement is a right triangle with the following
Hypotenuse = 28 feet
Angles made with the base = 15 degrees
The distance from where it is tied to the base of the pole (height of the triangle) is required
Using the trigonometry identity
sin theta = opposite/hypotenuse
sin 15 = h/28
h = 28sin15
h = 7.25ft
Hence the distance from where it is tied to the base of the pole is 7.25ft
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In the figure, triangle UVW is similar to triangle RST, VU=48, VW=26, and SR=24.
What is the value of x? Show all your work.
x = 13
set the problem up using ratios.
given VU = 48, VW = 26 and SR = 24, find ST = x
VW / VU = ST / SR
26 / 48 = x / 24 and solve for x.
x = 13
Using the PERIOD method, design an experiment that compares how four different tires perform. You decide to run an experiment that tests all four tires on dry, damp, and wet roads for decelerations
lerations of 1, 3, 5, 7, and 9 m/s². If each experiment is repeated two times, how many measurements are needed?
measurements are needed. (Type a whole number)
640 measurements are needed to compare the performance of four different tires on dry, damp, and wet roads for decelerations of 1, 3, 5, 7, and 9 m/s², with two measurements per experiment.
How did we get the value?The PERIOD method stands for:
P: Performance metric (Deceleration)
E: Environmental condition (Dry, Damp, Wet)
R: Replicates (Two measurements per experiment)
I: Inputs (Four tires)
O: Output (Measurement result)
D: Design (Full factorial)
The number of measurements can be calculated as:
Measurements = R * (number of inputs)^E * P
In this experiment, there are:
R = 2 replicates
E = 3 environmental conditions (Dry, Damp, Wet)
P = 5 different decelerations (1, 3, 5, 7, 9 m/s²)
Inputs = 4 tires
Therefore, the number of measurements can be calculated as:
Measurements = 2 * 4^3 * 5 = 2 * 64 * 5 = 640
So, 640 measurements are needed to compare the performance of four different tires on dry, damp, and wet roads for decelerations of 1, 3, 5, 7, and 9 m/s², with two measurements per experiment.
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I need to complete the tables using the equation..
The values of y when the equation is y = 8x + 5 will be -3,5,13,21,29.
How to calculate the valuesAn equation simply has to do with the statement that illustrates the variables given. In this case, it is vital to note that two or more components are considered in order to be able to describe the scenario.
Since y = 8x + 5
when x = -1, y will be:
= 8(-1) + 5
= -3
when x = 0, y will be:
= 8(0) + 5
= 5
when x = 1, y will be:
= 8(1) + 5
= 13
when x = 2, y will be:
= 8(2) + 5
= 21
when x = 3, y will be:
= 8(3) + 5
= 29
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The tailgate of a truck is 2 feet above the ground. The incline of a ramp used for loading the truck is 11°, as shown below. 2' 11° Find, to the nearest tenth of a foot, the length of the ramp.
The required length of the ramp is approximately 10.4 feet.
What is trigonometry?Trigonometry is essentially the study of triangle calculations (hence the name trigonometry). It is a mathematical study of connections involving the lengths, heights, and angles of various triangles. The discipline was created in the third century BC as a result of the use of geometry in astronomical research.
According to question:Let's call the length of the ramp "x". We can then use the sine function to relate the angle and the height of the ramp:
sin(11°) = opposite/hypotenuse
sin(11°) = 2/x
We can then solve for x:
x = 2/sin(11°)
x ≈ 10.4 feet
Therefore, the length of the ramp is approximately 10.4 feet.
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If 2x+1/3x=4, then find the value of 27x³+1/8x³
Answer: We can find the value of x by solving the equation 2x + 1/3x = 4.
Combining the terms on the left side, we get:
(6/3)x = 4
Dividing both sides by 6/3, we get:
x = 2
Substituting the value of x back into the expression 27x³ + 1/8x³, we get:
27 * 2³ + 1/8 * 2³ = 27 * 8 + 1/8 * 8 = 216 + 1 = 217
So the value of the expression 27x³ + 1/8x³ is 217.
Step-by-step explanation:
I’m stuck on this one, please help me!
x+2+x+7=6+8
x+x+2+7=14
2x+9=14
2x=14-9
2x=5
2x/2=5/2
x=5/2. or 2.5 in a decimal form.
Witch equation is equivalent to n+4=11
The Equation which is Equivalent to n+4=11 is (n + 4) x 2 = 11 x 2.
What is Equivalent Expression?Expressions that are equivalent do the same thing even when they have distinct appearances. When we enter the same value for the variable, two algebraic expressions that are equivalent have the same value.
Given:
n+4=11
Solving the Equation
n= 11-4
n= 7
1. (n + 4) x 2 = 11
2n + 8 = 11
2n = 3
n= 3/2
2. (n + 4) x 2 = 11 / 2
2n + 8 = 11/2
2n = -5/2
n = -5/4
3. (n+ 4) x2 = 11 x 4
2n+ 8 = 44
2n = 36
n= 18
4. (n + 4) x 2 = 11 x 2
2n+ 8 = 22
2n = 14
n= 7
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The Question attached here is missing the options which are as follow:
(n + 4) x 2 = 11
(n + 4) x 2 = 11 / 2
(n+ 4) x2 = 11 x 4
(n + 4) x 2 = 11 x 2
These tables represent the relationships between x and y for two different sets of data. Which statements correctly describe the relationships between x and y for each table? Responses Table A represents an additive relationship because y is 1.5 more than x, and Table B represents a multiplicative relationship because y is 3 times x. Table A represents an additive relationship because , y, is 1.5 more than , x, , and Table B represents a multiplicative relationship because , y, is 3 times , x, . Table A represents a multiplicative relationship because y is 2.5 times x, and Table B represents an additive relationship because y is 2 more than x. Table A represents a multiplicative relationship because , y, is 2.5 times , x, , and Table B represents an additive relationship because , y, is 2 more than , x, . Both data sets represent multiplicative relationships. In Table A, y is 2.5 times x, and in Table B, y is 3 times x. Both data sets represent multiplicative relationships. In Table A, , y, is 2.5 times , x, , and in Table B, , y, is 3 times , x, . Both tables represent additive relationships. In Table A, y is 1.5 more than x, and in Table B, y is 2 more than x. Both tables represent additive relationships. In Table A, , y, is 1.5 more than , x, , and in Table B, , y, is 2 more than , x, . Table A x 1 2 3 4 y 2.5 5.0 7.5 10.0 Table B x 1 2 3 4 y 3 6 9 12
Correct expression is,
Table A represents an additive relationship because y is 5.5 more than x.
Table B represents a multiplicative relationship because , y, is 4.5 times x.
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
These tables represent the relationships between x and y for two different sets of data.
Hence, The equation for table A is,
Two points from the table A are, (1, 6.5) and (2, 7.5)..
Thus, The equation fop table is,
y - 6.5 = (7.5 - 6.5) / (2 - 1) (x - 1)
y - 6.5 = 1 (x - 1)
y - 6.5 = x - 1
y = x - 1 + 6.5
y = x + 5.5
Thus, Table A represents an additive relationship because y is 5.5 more than x.
Hence, The equation for table B is,
Two points from the table A are, (1, 4.5) and (2, 9)..
Thus, The equation fop table is,
y - 4.5 = (9 - 4.5) / (2 - 1) (x - 1)
y - 4.5 = 4.5 (x - 1)
y - 4.5 = 4.5x - 4.5
y = 4.5x
Thus, Table B represents a multiplicative relationship because , y, is 4.5 times , x,.
Therefore, We get;
Correct expression is,
Table A represents an additive relationship because y is 5.5 more than x.
Table B represents a multiplicative relationship because , y, is 4.5 times x.
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How much does the water in a 6-person hot tub weigh?
Answer: A six-person model typically weighs approximately 1,000 pounds empty or 6,000 pounds full.
The following box plot shows the typical gas mileage, in miles per gallon, for 20 different car models. Based on the box plot, the top 25 percent of the cars have a typical gas mileage of at least how many miles per gallon?
By using the box plot, the top 25 percent of the cars have a typical gas mileage of at least 30 miles per gallon.
To find the value of the typical gas mileage for the top 25 percent of cars, we need to look at the upper quartile (Q3) of the box plot. The upper quartile is the point that separates the highest 25 percent of the data from the lowest 75 percent.
In the box plot, the upper quartile (Q3) is represented by the top of the box (the horizontal line inside the box) and the vertical line extending from the top of the box (the "whisker" above the box). We can estimate the value of Q3 by looking at the scale on the vertical axis and reading off the approximate value at the top of the box and the end of the whisker.
Assuming the scale on the vertical axis is in miles per gallon, we can estimate that Q3 is around 30 miles per gallon. Therefore, we can conclude that the top 25 percent of the cars have a typical gas mileage of at least 30 miles per gallon.
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