Find all solutions, if any, to the systems of congruences x ≡ 7 (mod 9), x ≡ 4 ( mod 12) and x ≡ 16 (mod 21).
What are the steps?
I know that you can't directly use the Chinese Remainder Theorem since your modulars aren't prime numbers.

x ≡ 859 (mod 756) is the solution to the system of congruences.

To solve the system of congruences x ≡ 7 (mod 9), x ≡ 4 ( mod 12) and x ≡ 16 (mod 21), we can use the method of simultaneous equations.

Step 1: Start with the first two congruences, x ≡ 7 (mod 9) and x ≡ 4 ( mod 12). We can write these as a system of linear equations:

x = 9a + 7

x = 12b + 4

where a and b are integers. Solving for x, we get:

x = 108c + 67

where c = 4a + 1 = 3b + 1.

Step 2: Substitute x into the third congruence, x ≡ 16 (mod 21), to get:

108c + 67 ≡ 16 (mod 21)

Simplify the congruence:

3c + 2 ≡ 0 (mod 21)

Step 3: Solve the simplified congruence, 3c + 2 ≡ 0 (mod 21), by trial and error or using a modular inverse. In this case, we can see that c ≡ 7 (mod 21) satisfies the congruence.

Step 4: Substitute c = 7 into the expression for x:

x = 108c + 67 = 108(7) + 67 = 859

Therefore, the solutions to the system of congruences are x ≡ 859 (mod lcm(9,12,21)), where lcm(9,12,21) is the least common multiple of 9, 12, and 21, which is 756.

Hence, x ≡ 859 (mod 756) is the solution to the system of congruences.

Learn more about congruences here

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