The possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are [tex]\mathbf{\pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}[/tex]
How to determine the possible zeros?The function is given as:
f(x) = 3x^6 + 4x^3 -2x^2 + 4
The leading coefficient of the function is:
p = 3
The constant term is
q = 4
Take the factors of the above terms
p = 1 and 3
q = 1, 2 and 4
The possible zeros are then calculated as:
[tex]\mathbf{Zeros = \pm\frac{Factors\ of\ q}{Factors\ of\ p}}[/tex]
So, we have:
[tex]\mathbf{Zeros = \pm\frac{1,2,4}{1,3}}[/tex]
Expand
[tex]\mathbf{Zeros = \pm\frac{1,2,4}{1},\pm\frac{1,2,4}{3}}[/tex]
Solve
[tex]\mathbf{Zeros = \pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}[/tex]
Hence, the possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are [tex]\mathbf{\pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}[/tex]
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Solve the equation 5 (x + 1) = 5x
[tex]\textbf{Heya !}[/tex]
✏[tex]\bigstar\textsf{Given:-}[/tex]✏
an equation = [tex]\sf{5(x+1)=5x}[/tex]✏[tex]\bigstar\textsf{To\quad find:-}[/tex]
x = ?✏[tex]\bigstar\textsf{Solution \quad steps:-}[/tex] ✏
first use the distributive property
[tex]\sf{\longmapsto{ 5x+5=5x}[/tex]
subtract both sides by 5x
[tex]\sf{\longmapsto{0x+5=0}[/tex] (strange expression right)
[tex]\sf{\longmapsto 0=-5}[/tex] (whattt ?!)
the above statement's false, so the equation has no solutions
`hope that was helpful to u ~
Andy is preparing the company's income statement. His first line item is the company's service revenue. What will he deduct from this line item to obtain the net income?
Andy needs to subtract _______ from the service revenue.
Fill in the blank
Andy needs to subtract cost from the service revenue.
What does Andy need to subtract?
Revenue is the total income earned before any deductions are made. Net income is the total revenue less total expenses or cost.
Net income = total revenue - cost
For example, if a company sold 100 loaves of bread for $100 dollars. The cost of making the bread is $50. The revenue is $100 and the net income is $50 (100 - 50).
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Resuelve los siguientes ejercicios:
Hallar la ecuación de la circunferencia:
a) Centro (2,-1) y radio 4
b) Centro C (1,3) y que pasa por el punto P (4, 6)
3. Hallar la ecuación de la parábola, las coordenadas de su foco y la longitud de su lado recto, si el vértice es el origen y pasa por el punto P:
a) Eje focal coincidente con el eje coordenado en x, P(2,4)
b) Eje focal coincidente con el eje coordenado en, P (6,3)
4. Hallar el foco, la ecuación de la directriz y la longitud del lado recto de las siguientes parábolas.
a) 4 x2 = 32y
b) 2y2 = -3x
5. Dadas las ecuaciones de las elipses, hallar las longitudes del semieje mayor y semieje menor, las coordenadas de los focos, los vértices y la longitud del lado recto.
a) 81 x2 + 144 y2 = 11664
b) 36x2+25y2 = 3600
Por restricciones de longitud no es posible resumir las respuestas asociadas a esta pregunta, invitamos cordialmente a leer la explicación para mayores detalles sobre el análisis de secciones cónicas.
¿Cómo analizar ecuaciones de secciones cónicas?
Según la geometría analítica, existen cinco tipos de secciones cónicas: (i) Circunferencia, (ii) Parábola, (iii) Elipse, (iv) Hipérbola, (v) Recta. 2) a) La ecuación estándar de la circunferencia se caracteriza con el centro (h, k) y la longitud del radio (r):
(x - h)² + (y - k)² = r²
(x - 2)² + (y + 1)² = 4²
b) La longitud del radio de la circunferencia se obtiene por el teorema de Pitágoras sobre la longitud del segmento CP:
r = √[(4 - 1)² + (6 - 3)²]
r = √(3² + 3²)
r = 3√2
(x - 1)² + (y - 3)² = 18
3) a) El eje focal forma parte del eje de simetría de la parábola. La ecuación estándar de la parábola es:
4 · p · x = y²
Donde p es la distancia entre el foco y el vértice.
Si tenemos que (x, y) = (2, 4), entonces la ecuación de la parábola es:
4 · p · 2 = 4²
p = 2
8 · x = y²
Las coordenadas del foco de la parábola son de la forma (x, y) = (h + p, k):
F(x, y) = (2, 0)
Ahora se determinan los extremos del lado recto: (x = 2)
8 · 2 = y²
y = ± 4
Los extremos del lado recto son (2, 4) y (2, - 4), cuya longitud de segmento es 8 unidades.
b) El eje focal forma parte del eje de simetría de la parábola. La ecuación estándar de la parábola es:
4 · p · x = y²
Si tenemos que (x, y) = (6, 3), entonces la ecuación de la parábola es:
4 · p · 6 = 3²
p = 8 / 3
(32 / 3) · x = y²
Las coordenadas del foco son F(x, y) = (8 / 3, 0).
Ahora se determinan los extremos del lado recto: (x = 6)
(32 / 3) · 6 = y²
y = ± 8
Los extremos del lado recto son (6, 8) y (- 6, - 8), cuya longitud de segmento es 16 unidades.
4) a) Tenemos una ecuación estándar de la forma 4 · p · y = x². A continuación, hallamos todas las variables requeridas:
x² = 8 · y
p = 2
Directriz: y = - 2, Foco: F(x, y) = (0, 2), Longitud del lado recto: 4
b) Tenemos una ecuación estándar de la forma 4 · p · x = y². A continuación, hallamos todas las variables requeridas:
y² = - (3 / 2) · x
p = - 3 / 8
Directriz: x = 3 / 2, Foco: F(x, y) = (- 3 / 2, 0), Longitud del lado recto: 3.
5) En esta parte debemos manipular algebraicamente las ecuaciones hasta su forma estándar para determinar los datos requeridos de cada caso. La ecuación estándar de la elipse tiene el siguiente problema:
(x - h)² / a² + (y - k)² / b² = 1
Donde:
(h, k) - Centro de la elipse.a, b - Longitudes de los semiejes.a) 81 · x² + 144 · y² = 11664
x² / 144 + y² / 81 = 1
x² / 12² + y² / 9² = 1
Longitud del semieje mayor: 12
Longitud del semieje menor: 9
c = √(12² - 9²)
c ≈ 7.937
Coordenadas de los focos: F₁ (x, y) = (- 7.937, 0), F₂ (x, y) = (7.937, 0)
Vértices: V₁ (x, y) = (- 12, 0), V₂ (x, y) = (12, 0)
Longitud del lado recto
144 · y² = 11664 - 81 · x²
y² = (11664 - 81 · x²) / 144
y = ± (1 / 12) · √(11664 - 81 · x²)
y = ± (1 / 12) · √(11664 - 81 · 7.937²)
y = ± 6.750
La longitud del lado recto es 13.5.
b) 36 · x² + 25 · y² = 3600
x² / 10² + y² / 12² = 1
Longitud del semieje mayor: 12
Longitud del semieje menor: 10
c = √(12² - 10²)
c ≈ 6.633
Coordenadas de los focos: F₁ (x, y) = (0, - 6.637), F₂ (x, y) = (0, 6.637)
Vértices: V₁ (x, y) = (0, - 12), V₂ (x, y) = (0, 12)
Longitud del lado recto
36 · x² = 3600 - 25 · y²
x² = 100 - (25 / 36) · y²
x = √[100 - (25 / 36) · y²]
x = √[100 - (25 / 36) · 6.637²]
x = ± 8.331
La longitud del lado recto es 16.662.
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What are the domain and range of g(x)=√x+4?
OD: [4, ∞) and R: [0, ∞)
OD: (-4, ∞) and R: (-∞, 0)
OD: [-4, ) and R: [0, ∞)
OD: (4,) and R: (-∞, 0)
Answer:
Domain [-4 , +∞)
Range [0 , +∞)
Step-by-step explanation:
the function g such that g(x)=√(x+4) ,is defined
for the values of x that verify :
x + 4 ≥ 0
⇔ x ≥ -4
Then
The domain of g is [-4 , +∞)
………………………………………………
Let x ∈ [-4 , +∞)
then x ≥ -4
then x + 4 ≥ 0
then g(x) = √(x+4) ≥ 0
Therefore, we can affirm that the range of g is [0 , +∞)
The length of the major axis of the ellipse below is 14, and the length of the
red line segment is 3. How long is the blue line segment?
Answer:
11
Step-by-step explanation:
The focal length is 14, and thus the sum of the lengths of the blue and red segments is also 14.
Fill in the missing term in the pair of equivalent ratios. *
5:30 15:
Your answer
The state low temperatures for five states are as follows: -42
Express v=
(2,1,5) as a linear combination of (1,2,1), (1,0,2) and (1,1,0)
The expression of v = (2,1,5) as a linear combination of (1,2,1), (1,0,2) and (1,1,0) is [tex](2,1,5)=1(1,2,1)+2(1,0,2)+-1(1,1,0)[/tex]
Linear CombinationsTo express v= (2,1,5) as a linear combination of (1,2,1), (1,0,2) and (1,1,0), it will be written as:
[tex](2,1,5)=x(1,2,1)+y(1,0,2)+z(1,1,0)[/tex]
This will yield the following equations:
x + y + z = 2........(1)
2x + z = 1..........(2)
x + 2y = 5........(3)
The solution to the system of equations above is:
x = 1, y = 2, z = -1
Therefore, the linear combination is:
[tex](2,1,5)=1(1,2,1)+2(1,0,2)+-1(1,1,0)[/tex]
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Find the area of the triangle
A
47°
b
32 ft
C
19 ft
Answer:
222 [ft²].
Step-by-step explanation:
1. the required area can be calculated according to the formula:
A=0.5*b*c*sin(A);
2. after substitution of b=32; c=19 and sin(A)≈0.7313537:
A=0.5*32*19*0.7313537=222.3315248 [ft²].
On a piece of graph paper, plot the following points: A (3, 1), B (1, 5), C (9, 9), and D (11, 5). These coordinates will be the vertices of a quadrilateral. How would you use the distance formula and the slope formula to prove that this figure is actually a rectangle?
The given coordinates are actually a rectangle
How to determine the quadrilateral type?
The coordinates are given as:
A (3, 1), B (1, 5), C (9, 9), and D (11, 5).
Calculate the distance between the coordinates using:
[tex]d = \sqrt{(x_2 -x_1)^2 +(y_2 -y_1)^2[/tex]
So, we have:
[tex]AB = \sqrt{(3 -1)^2 +(1-5)^2} =\sqrt {20[/tex]
[tex]BC = \sqrt{(1 -9)^2 +(5-9)^2} =\sqrt {80[/tex]
[tex]CD = \sqrt{(9 -11)^2 +(9-5)^2} =\sqrt {20[/tex]
[tex]DA = \sqrt{(11 -3)^2 +(5-1)^2} =\sqrt {80[/tex]
The above shows that the opposite sides are congruent
Next, we calculate the slopes using:
m = (y2- y1)/(x2- x1)
So, we have:
AB = (1- 5)/(3-1) = -2
BC = (5- 9)/(1-9) = 1/2
CD = (9- 5)/(9-11) = -2
DA = (5- 1)/(11-3) = 1/2
The slopes of adjacent sides are opposite reciprocals.
This means that the sides are perpendicular
Hence, the given coordinates are actually a rectangle
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When the sum of a number and 3 is subtracted from 10 the result is 5 solve om algebraic equation?
Answer:
y = 2
Step-by-step explanation:
Algebraic Equation is an equation where alphabets are used to represent numbers.
Solving the above question,
Let the number = y
Therefore,
Sum of the number = y + 3
If it's subtracted from 10 it becomes
10 - ( y + 3 )
The result : 10 - y - 3 = 5
- y = 5 - 10 + 3
- y = -2
Therefore,
y = 2
The vertices of a quadrilateral are A(-3,-1), B(1,5), C(5,5), and D(5,-1). Select the statement that represents this quadrilateral. A. ABCD is a rectangle because it has exactly one pair of right angles. B. ABCD is a trapezoid because it has at least one pair of parallel sides. C. ABCD is a square because it has all equal sides. D. ABCD is a parallelogram because it has two pairs of parallel sides.
Answer:
B. ABCD is a trapezoid because it has at least
one pair of parallel sides.
Step-by-step explanation:
the two points A(-3,-1) and D(5,-1) have the same y-coordinates
Then
The line AD is parallel to the x-axis
On the other hand,
the two points B(1,5) and C(5,5) have the same y-coordinates
Then
The line BC is parallel to the x-axis.
We obtain :
• AD is parallel to the x-axis
• BC is parallel to the x-axis.
Therefore
AD // BC
Conclusion:
ABCD is a trapezoid because it has at least
one pair of parallel sides.
Answer:
b
Step-by-step explanation:
plato
;
Use the expression in the accompanying discussion of sample size to find the size of each sample if you want to estimate the
difference between proportions of men and women who own smartphones. Assume that you want 99% confidence that your
error is no more than 0.035.
Click the icon to view the discussion of sample size.
The sample should include men and
(Type whole numbers.)
women.
The sample should include 2702 men and 2702 women.
Given that you want to be 99% sure your error doesn't exceed 0.035.
A sample is a group of people selected from a larger population to provide data to researchers. The number of members of the population included in the sample is called the sample size.
The significance level is the probability that the test statistic is in the critical range if the null hypothesis is actually true. The confidence interval is 99% or 0.99.
The level of significance α = 1-0.99 = 0.01
the margin of error, ME = 0.035
The Z-critical value at the 99% confidence level or at the significance level of 0.01 is 2.575 (from standard normal tables).
We will now use the formula:[tex]n=\frac{Z^2_{critical}}{2(ME)^2}[/tex].
Substitute the values in the above formula, we get
n = (2.575) ² / (2 × (0.035) ²)
n = 6.630625 / (2 × 0.001225)
n = 6.630625 / 0.00245
n = 2701.966
Therefore, the sample should include 2702 males and 2702 females with a 99% certainty that the error does not exceed 0.035
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Carlos spent 1\dfrac141
4
1
1, start fraction, 1, divided by, 4, end fraction hours doing his math homework. He spent 1\dfrac141
4
1
1, start fraction, 1, divided by, 4, end fraction as much time practicing piano.
How many hours did Carlos spend practicing piano?
write as a fraction
The time Carlos spend practicing his multiplication facts in fraction is 5/16 hours.
FractionA fraction is a value which has a numerator (upper or top value) divided by a denominator (lower or bottom value).
Time Carlos spent doing his math homework = 1 1/4 hoursTime spent practicing his multiplication facts = 1/4 of 1 1/4 hours
= 1/4 × 1 1/4
= 1/4 × 5/4
= (1 × 5) / (4 × 4)
= 5/16 hours
Therefore, the time Carlos spend practicing his multiplication facts is 5/16 hours.
Complete question:
Carlos spent 1 1/4 hours doing his math home work. He spent 1/4 of this time practicing his multiplication facts.
How many hours did Carlos spend practicing his multiplication facts?
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What is the area of a poster that is 1 1/2 feet by 2 1/2 feet?
The area of the poster is 28.75 feet square.
How to determine the areaNote that the area of a rectangle is given as;
Area = length × width
Length = 11. 5 feet
Width = 2. 5 feet
Area = 11. 5 × 2. 5
Area = 28. 75 feet square
Thus, the area of the poster is 28.75 feet square.
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Sarah had three times as many quarters as nickels. She had $3.20 in all. How many quarters did she have?
A. 12
B. 15
C. 4
Answer:
A. 12
Step-by-step explanation:
If she had 12 quarters, then she would have to have 4 nickels according to the problem.
12 * .25 = $3 (money in quarters)
4 * .05 = $.2 ( money in nickels)
Adding those 2 together, we get $3.2.
She have 12 quarters
what is unitary method?It is a method where we find the value of a single unit from the value of multiple units and the value of multiple units from the value of a single unit.
There are two situation in Unitary method:
There are 5 ice-creams. 5 ice-creams cost $125.
Step 1: Let’s find the cost of 1 ice cream. In order to do that, divide the total cost of ice-creams by the total number of ice-creams. The cost of 1 ice-cream = Total cost of ice-creams/Total number of ice-creams = 125/5 = 25. Therefore, the cost of 1 ice cream is $25.
Step 2: To find the cost of 3 ice-creams, multiply the cost of 1 ice cream by the number of ice-creams. The cost of 3 ice-creams is cost of 1 ice-cream × number of ice-creams = 25 × 3 = $75. Finally, we have the cost of 3 ice-creams i.e. $75.
Given:
If she had 12 quarters, then
12 * .25 = $3 ( quarters)
4 * .05 = $.2 ( in nickels)
Hence, she have 12 quarters.
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convert this into a standard number
[tex]10^{12}[/tex]
10^12 in standard number is 1000000000000
How to convert the number?The number is given as:
[tex]10^{12[/tex]
Expand the expression
[tex]10^{12} = 10 * 10 * 10 * 10 *10 * 10 * 10 * 10*10 * 10 * 10 * 10[/tex]
Evaluate the product
[tex]10^{12} = 1000000000000[/tex]
Hence, 10^12 in standard number is 1000000000000
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The amount of detergent dispensed into bottles of liquid laundry detergent bottles for a particular brand is normally distributed with a mean of 84.5 ounces with a standard deviation of 1.1 ounces. If seventeen bottles are randomly chosen from the factory, what is the probability that the mean fill is more than 84.8 ounces
The probability that the mean fill is more than 84.8 ounces is 0.39358
How to determine the probability that the mean fill is more than 84.8 ounces?From the question, the given parameters about the distribution are
Mean value of the set of data = 84.5Standard deviation value of the set of data = 1.1The actual data value = 84.8The z-score of the data value is calculated using the following formula
z = (x - mean value)/standard deviation
Substitute the given parameters in the above equation
z = (84.8 - 84.5)/1.1
Evaluate the difference of 84.8 and 84.5
z = 0.3/1.1
Evaluate the quotient of 0.3 and 1.1
z = 0.27
The probability that the mean fill is more than 84.8 ounces is then calculated as:
P(x > 84.8) = P(z > 0.27)
From the z table of probabilities, we have;
P(x > 84.8) = 0.39358
Hence, the probability that the mean fill is more than 84.8 ounces is 0.39358
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1!+2(2!)+3(3!)+...+n(n!)=(n+1)!-1
Step-by-step explanation:
OK, let's assume it this way:
Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!
Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!=(2.1!-1!)+(3.2!-2!)+(4.3!-3!)+...+((n-1)n!-n!)=(2!-1!)+(3!-2!)+(4!-3!)+
Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!=(2.1!-1!)+(3.2!-2!)+(4.3!-3!)+...+((n-1)n!-n!)=(2!-1!)+(3!-2!)+(4!-3!)+...+(n+1)!-n!=(n+1)!-1!=(n+1)!-1
and boom problem solved
In a one tail hypothesis where you only in the lower tail, what is the p-value if
P-Value becomes 0.8599 when (z < 1.08).
According to the statement
We have given that the Z-stat value is 1.08 and we have to find the P value with the help of Z-stat value.
So,
A Z-score is a numerical measurement that describes a value's relationship to the mean of a group of values.
and we know that
The P-Value is calculated by converting your statistic (such as mean / average) into a Z-Score.
So, If the z-stat is 1.08, the p-value for a left-tail test is the probability that (z < 1.08), which is 0.8599.
So, P-Value becomes 0.8599 when (z < 1.08).
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What is the equation of the line that is parallel to line R, y = 2x + 5, and passes through the
point (-2, 2)?
Answer:
y = 2x + 6
Step-by-step explanation:
We are given the line R, which is y=2x+5, and we want to find the equation of the line that is parallel to this line, and that also passes through the point (-2, 2).
Parallel lines have the same slope, yet different y-intercepts.
So, we should first find the slope of y=2x+5.
The line is written in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept.
As 2 is in the place of where m (the slope) should be, 2 is the slope of the line.
It is also the slope of the line parallel to it.
We can write the equation of the new line in slope-intercept form as well; here is the equation so far, with what we know:
y = 2x + b
We need to find b.
As the equation passes through the point (-2, 2), we can use its values to help solve for b.
Substitute -2 as x and 2 as y.
2 = 2(-2) + b
Multiply.
2 = -4 + b
Add 4 to both sides.
6 = b
Substitute 6 as b.
y = 2x + 6
During an unusual storm, the temperature fell 8° C, rose 5° C, fell 4° C,
and then rose 6° C. If the temperature was 32° C at the outset of the storm,
what was it after the storm was over?
The diameter of a pipe is normally distributed, with a mean of 0.8 inch and a variance of 0.0004. What is the probability that the diameter of a randomly selected pipe will exceed 0.84 inch? (You may need to use the standard normal distribution table. Round your answer to three decimal places.) . Hint: take the square root of the variance to find the standard deviation.
The probability that the diameter of a randomly selected pipe will exceed 0.84 inch is 0.977
What is probability?Probabilities are used to determine the chances, likelihood, possibilities of an event or collection of events
How to determine the probability?The given parameters are:
Mean = 0.8
Variance = 0.0004
Calculate Standard deviation using
σ = √σ²
This gives
σ = √0.0004
Evaluate
σ = 0.02
Calculate the z-score at x = 0.84 using
z = (x - [tex]\bar x[/tex])/σ
This gives
z = (0.84 - 0.8)/0.02
Evaluate
z = 2
The probability is then represented as:
P(x > 0.84) = P(z > 2)
Next, we look up the value of the z table of probabilities
From the z table of probabilities, we have:
P(x > 0.84) = 0.977
Hence, the probability that the diameter of a randomly selected pipe will exceed 0.84 inch is 0.977
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Please Help! Multiple Choice
Using the z-distribution, the z-statistic would be given as follows:
c) z = -2.63.
What are the hypothesis tested?At the null hypothesis we test if the means are equal, hence:
[tex]H_0: \mu_D - \mu_C = 0[/tex]
At the alternative hypothesis, it is tested if they are different, hence:
[tex]H_1: \mu_D - \mu_C \neq 0[/tex]
What are the mean and the standard error for the distribution of differences?For each sample, they are given as follows:
[tex]\mu_D = 12, s_D = \frac{5.2}{\sqrt{73}} = 0.6086[/tex][tex]\mu_C = 14, s_C = \frac{4.1}{\sqrt{81}} = 0.4556[/tex]Hence, for the distribution of differences, they are given by:
[tex]\overline{x} = 12 - 14 = -2[/tex].[tex]s = \sqrt{0.6086^2 + 0.4556^2} = 0.76[/tex]What is the test statistic?The test statistic is given by:
[tex]z = \frac{\overline{x} - \mu}{s}[/tex]
In which [tex]\mu = 0[/tex] is the value tested at the null hypothesis.
Hence:
[tex]z = \frac{\overline{x} - \mu}{s}[/tex]
[tex]z = \frac{-2 - 0}{0.76}[/tex]
z = -2.63.
Hence option B is correct.
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Intelligence test.
If you get it right ,you are a critical thinker.
You were in the garden, there are 34 people in the yard. You killed 30 .How many people are in the garden.
I
Answer: 5
Step-by-step explanation:
Because there are 35 when you add yourself so u subtract 30 to get 5
There would be 4 people left in the garden.
34 - 30 = 4.
Subtraction of NumbersSubtraction is a mathematical operation that involves taking away one number from another to find the difference between them. For the question, At first, there were 34 people in the garden and later 30 people were no longer alive in the garden, so the difference between 30 people and 34 people is 4.
Subtraction is the opposite of addition, and it is used to measure the distance between two values on the number line.
Subtraction is represented by minus Sign (-). For example, subtracting 5 from 10 gives you a difference of 5 (10 - 5 = 5).
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What are the solutions of the equation 9x4 - 2x2 - 7 = 0? Use u substitution to solve.
Aperson invest 10,000 shillings for 40 months compounded monthly. Find the accumulated amount If the rate is 5% per annum.
hi
monthly interest rate is : [tex]\sqrt[12]{1.05}[/tex]
So in forty month there will be : 10 000 * ( [tex]\sqrt[12]{1.05}[/tex] )^40 ≈11 776,06
Money savers bank offers a savings account that earns 6% interest compounded continuously. If Manuel deposits $2200, how much will he have in the account after three years?
Answer:
2633.88
Step-by-step explanation:
Pe^rt
2200*e^.06*3
How much will you have saved after 6 years by contributing $1,200 at the end of each year if you expect to earn 11% on the investment?
Savings after 6 years would be $ 1992.
What are savings?Savings is the money that remains after expenses and other commitments have been subtracted from income.
Savings are the sum of money that would otherwise be lying about, not being risked on investments or used for consumption.
Savings and investing can be compared because the latter includes putting money at risk in an effort to try to increase wealth.
Indicators of household debt or a negative net worth include negative savings.
According to the question,
Amount contributed(P)= $1200
Rate(R)= 11%
Time(T)= 6 years
Interest(SI)=P*R*T/100
= 1200*11*6/100
= 792
Savings after 6 years = P+ SI
= 1200 + 792
= $ 1992
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solve (6b^2+5)+(8b-20)
The sum of the given expression is 6b^2+8b-15
Sum of expressionGiven the following expression
(6b^2+5)+(8b-20)
We are to take the sum. On expansion;
6b^2+5 + 8b-20
Collect the like terms
6b^2+8b +5 - 20
6b^2+8b-15
Hence the sum of the given expression is 6b^2+8b-15
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Someone help quickly pls :(
Assignment
Practice finding solutions to systems of equations using
substitution.
The value of x in this system of equations is 1.
3x + y = 9
y=-4x+10
1. Substitute the value of y in the first equation:
2. Combine like terms:
3. Apply the subtraction property of equality:
4. Apply the division property of equality:
What is the value of y?
y=
3x + (-4x+10) = 9
-x+10=9
-x=-1
x=1
Answer:
y = 6
Step-by-step explanation:
Solving system of linear equation using substitution method:3x + y = 9 ---------------(I)
y = -4x + 10 -----------------(II)
Substitute y = -4x + 10 in equation (I)
3x - 4x + 10 = 9
Combine like terms,
-x + 10 = 9
Subtract 10 from both sides. (subtraction property of equality)
-x = 9 - 10
-x = -1
Divide both sides by (-1). {Division property of equality}
[tex]\sf \dfrac{-x}{-1}=\dfrac{-1}{-1}\\\\ \boxed{x = 1}[/tex]
Now, substitute x = 1 in equation (II) and find the value of y.
y = -4*1 + 10
= -4 + 10
[tex]\sf \boxed{\bf y = 6}[/tex]