The perimeter of a square is equal to 4 times the side length.
=4
P
=
4
s
where
P
is the perimeter and
s
is the side length of the square.
If the side length of the square is 3−2
3
x
−
2
units, then let =3−2
s
=
3
x
−
2
The perimeter would be:
=4(3−2)
P
=
4
(
3
x
−
2
)
=4(3)−4(2)
P
=
4
(
3
x
)
−
4
(
2
)
=12−8
P
=
12
x
−
8
Therefore the perimeter of the square is: 12−8
12
x
−
8
units.
Regards,
. ℎ
A
a
r
o
n
M
.
C
h
a
o
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Arturo Ordonez-Hernandez, Associate Programmer/Analyst at Weber State University (2018-present)
Answered March 8
A square is an equilateral rectangle.
So, we know that, for a rectangle,
=2+2
P
=
2
l
+
2
w
For a square,
=
l
=
w
so,
=4=4
P
=
4
l
=
4
w
Therefore,
=4(3−2)
P
=
4
(
3
x
−
2
)
=12−4
P
=
12
x
−
4
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Len Fyfe, B.Ed. Mathematics & Physics, Chemistry, Maths, and Computer Science, Lakehead University (2005)
Answered March 4
side length is 3x-2
each of the four sides is the same length
P = 4(3x-2) factored form
P = 12x - 8 expanded form
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I hope this is what you mean!
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Here,
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or
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[tex]\frac{1+3(n-1)}{3+4(n-1)}[/tex]
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What is the equation of the following line? Be sure to scroll down first to see
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10+
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(0,0)
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- 10+
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Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Terms/CoefficientsFunctionsFunction NotationExpand by FOILStep-by-step explanation:
Step 1: Define
Identify
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[tex]{ \tt{f(x) = {x}^{2} + 1 }} \\ { \tt{f(a + 1) = {(a + 1)}^{2} + 1 }} \\ { \tt{f(a + 1) = ( {a}^{2} + 2a + 1) + 1 }} \\ { \tt{f(a + 1) = {a}^{2} + 2a + 2}}[/tex]
A watch that originally cost $110 has been marked down to $88. What was the percent of the markdown ?
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10%
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[tex]\frac{finalvalue - inititalvalue}{initialvalue} * 100[/tex]
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Please help I’ve been struggling for ages!
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"D" only 1 & 2
Step-by-step explanation:
Sin 0 = 7/25 and cos 0 = -24/25. Find tan 0
Answer:
[tex]tan \theta = - \frac{7}{24}[/tex]
Step-by-step explanation:
[tex]sin \theta = \frac{7}{25} \ , \ cos\theta = \frac{-24}{25}\\\\tan \theta = \frac{sin\theta}{cos\theta}[/tex]
[tex]=\frac{\frac{7}{25}}{\frac{-24}{25}} \\\\=\frac{7}{25} \times \frac{25}{-24}\\\\= - \frac{7}{24}[/tex]
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Match the graph with the correct set of equations for each linear system.
Please help ASAP. Differentiating polynomials
Answer:
Step-by-step explanation:
If the function is
[tex]y=x^2-4x[/tex], then its derivative is
y' = 2x - 4. This is equal to 0 where
2x - 4 = 0 and
2x = 4 so
x = 2. When x = 2 in the original equation:
[tex]y =2^2-4(2)[/tex] so
y = -4. So the coordinate is (2, -4). On to the next one:
If the function is
[tex]y=25x +\frac{1}{x}[/tex] then its derivative is
[tex]y'=25-\frac{1}{x^2}[/tex]. This is equal to 0 where
[tex]25-\frac{1}{x^2}=0[/tex] and
[tex]-\frac{1}{x^2}=-25[/tex] or, in simpler terms:
[tex]\frac{1}{x^2}=\frac{25}{1}[/tex] so
[tex]25x^2=1[/tex] and
[tex]x^2=\frac{1}{25}[/tex] so
x = ±[tex]\sqrt{\frac{1}{25} }[/tex] so
x = [tex]\frac{1}{5},- \frac{1}{5}[/tex]. When you plug those into the original equation, you get the coordinates
[tex](\frac{1}{5},10)[/tex] and [tex](-\frac{1}{5},-10)[/tex]
1 Solve the compound inequality 4x>-16 or 6x <-48
Answer:
Step-by-step explanation:
4x > -16 reduces to x > -4: All numbers greater than x = -4 (shaded area to the right of -4).
6x < -48 reduces to x < -8: All numbers to the left of -8 (shaded area to the left of -8).
Solution: (-infinity, -4) ∪ (-8, infinity)
The number line between -8 and -4 is not part of the solution set (is not shaded or darkened)
Draw an open circle at -8 and extend an arrow to the left of this circle. Then draw an open circle at -4 and extend an arrow to the right of this circle.
I have to solve the equation:
[tex] |4 \sqrt{2} - 6 | + |2 \sqrt{10} - 6| [/tex]
The first thing I tried is simply removing the modules, it seemed like the most logical solution and this is the answer I got, but it wasn't any of the options:
[tex]4 \sqrt{2} + 2 \sqrt{10} + 12[/tex]
The second thing I tried is putting both equations in one module and sum the first one with the second one in parentheses like this:
[tex] |4 \sqrt{2} - 6 + (2 \sqrt{10} - 6 | = \\ = |4 \sqrt{2} - 6 + 2 \sqrt{10} + 6 | = \\ = 4 \sqrt{2} + 2 \sqrt{10}[/tex]
But this wasn't in the answers either.
After I checked, the correct answer was:
[tex]2 \sqrt{10} - 4 \sqrt{2} [/tex]
So I was wondering where does the minus come from?
It is in a module and between the modules, there's a plus and even if that plus somehow turns into a minus when it goes inside the modules, which I'm not aware of, it would still turn into a plus because it is in a module ;-; Or I'm just st*pid, I don't know.
Think back to the definition of absolute value:
• If x ≥ 0, then |x| = x.
• If x < 0, then |x| = -x.
In other words, the absolute value always returns a positive number. So if x is positive, leave it alone; but if it's negative, then you have to negate it to get a positive number back.
This means that you cannot simply reduce |x - y | to x - y because you need to consider the possibility that x - y may be negative, in which case |x - y | would reduce to -(x - y) = y - x.
In this case,
|4√2 - 6| = -(4√2 - 6) = 6 - 4√2
because 4√2 < 6, which you can determine by comparing both of these numbers as square roots:
4√2 = √16 √2 = √32
6 = √36
and √32 < √36 because 32 < 36.
Similarly,
|2√10 - 6| = 2√10 - 6
because
2√10 = √4 √10 = √40
6 = √36
So ultimately,
|4√2 - 6| + |2√10 - 6| = (6 - 4√2) + (2√10 - 6) = 2√10 - 4√2
In order for the parallelogram to be a
rhombus, x = [?].
(x + 15)
(2x - 40)
Help pleaseeee
Answer:
Step-by-step explanation:
x+15 = 2x-40
Move x to the right side and you get 15 = x-40
Move -40 to the left side and you get x = 55
In order for the parallelogram to be a rhombus, x must equal 55.
What is a rhombus?A rhombus is a quadrilateral that has four equal sides.
Some of the properties we need to know are:
- The opposite sides are parallel to each other.
- The opposite angles are equal.
- The adjacent angles add up to 180 degrees.
We have,
If a parallelogram is a rhombus, it means that all four sides of the parallelogram have equal length.
We can set the expressions for the opposite sides of the parallelogram equal to each other and solve for x.
x + 15 = 2x - 40
First, we can simplify by adding 40 to both sides and getting:
x + 55 = 2x
Next, we can subtract x from both sides and get:
55 = x
Therefore,
In order for the parallelogram to be a rhombus, x must equal 55.
To verify this, we can substitute x = 55 back into the expressions for the sides:
x + 15 = 55 + 15 = 70
2x - 40 = 2(55) - 40 = 70
Both opposite sides have an equal length of 70, so the parallelogram is a rhombus.
Thus,
In order for the parallelogram to be a rhombus, x must equal 55.
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Write the equation of a line passing through (4,1) and parallel to y = 3/2x + 3.
Answer:
y = 3/2x - 5
Step-by-step explanation:
y = 3/2x + b
1 = 3/2(4) + b
1 = 6 + b
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please please help!! limited time! i don’t understand!
Answer:
option b ) 18
Step-by-step explanation:
The questions states 3 different values for f(x)
f(x) = 3x + 12, if x ≤ -2
f(x) = 4 , if -2 < x < 3
f(x) = 2x² if x ≥ 3
Evaluate f(3)
x = 3, that is x ≥ 3
So we will have to choose f( x ) = 2x²
f( 3 ) = 2 (3)²
= 2 x 9
= 18