The area of the region that lies inside both curves r² = 2sin(2θ), r = 1 is -0.1287 square units.
How to find the area of the region that lies inside both curves?Since the curves are
r² = 2sin(2θ) and r = 1.We find their point of intersection.
So, r² = r²
2sin(2θ) = 1²
2sin(2θ) = 1
sin(2θ) = 1/2
2θ = sin⁻¹(1/2)
2θ = π/6
θ = π/12
So, we integrate the area from θ = 0 to θ = π/12
Now the area A of the region between two curves between θ = α to θ = β is
[tex]A = \int\limits^{\beta }_\alpha ({r^{2} - r^{'2} }) \, d\theta[/tex]
So, the area betwwen the curves r² = 2sin(2θ), r = 1 between θ = 0 to θ = π/12 is
[tex]A = \int\limits^{\frac{\pi}{12} }_0 ({r^{2} - r^{'2} }) \, d\theta \\= \int\limits^{\frac{\pi}{12} }_0 ({2sin2\theta - 1^{2} }) \, d\theta\\= \int\limits^{\frac{\pi}{12} }_0 ({2sin2\theta - 1}) \, d\theta\\= \int\limits^{\frac{\pi}{12} }_0 {2sin2\theta}\, d\theta - \int\limits^{\frac{\pi}{12} }_0 {1} \, d\theta\\= [2(-cos2\theta)/2 - \theta]_{0}^{\frac{\pi}{12} } \\= [-cos2\theta - \theta]_{0}^{\frac{\pi}{12} } \\= -cos2\frac{\pi}{12} - \frac{\pi}{12} - ( -cos2(0) - 0)\\[/tex]
[tex]= -cos2(\frac{\pi}{12}) - \frac{\pi}{12} - ( -cos2(0) - 0)\\= -cos\frac{\pi}{6}- \frac{\pi}{12} - ( -cos0 - 0)\\= -cos\frac{\pi}{6}- \frac{\pi}{12} - ( -1)\\= -(\frac{\sqrt{3} }{2} ) - \frac{\pi}{12} + 1\\= -0.8660 - 0.2618 + 1\\= -1.1278 + 1\\= -0.1278[/tex]
So, the area of the region that lies inside both curves r² = 2sin(2θ), r = 1 is -0.1287 square units.
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jerome wants to bake two batches of muffins. He can bake two batches of chocolate chip (C), two batches pumpkin, or one batch of each.
The situation presented can be represented using the following letters CC, CP, PC, and PP.
How many combinations are possible in this situation?The possible combinations are:
Two batches of chocolate chip or CC.Two batches of pumpkin or PP.One batch of chocolate chip and another of pumpkin of CP.One batch of pumpkin and another of chocolate chip or PC.Based on this, the option that represents the situation is:
CC, CP, PC, and PP.
Note: This question is incomplete; here is the missing section:
What is the sample space of the event described above?
Answer choices:
a. CC, CP, PC, PP
b. CC, PP
c. CC, CP, PC
d. C, P
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George plans to cover his circular pool for the upcoming winter season. The pool has a diameter of 20 feet and the cover extends 12 inches beyond the edge of the pool. A rope runs along the edge of the cover to secure it in place.
A. What is the area of the pool cover?
B. What is the length of the rope?
For the circular cover we have:
A) The area is 379.94 ft²
B) The length of the rope must be 68.2 ft
How to get the area of the cover?Remember that the area of a circle of radius R is given by the formula:
[tex]A = pi*R^2[/tex]
Where pi = 3.14
In this case, the diameter of the pool is 20ft, then the radius is:
R = 20ft/2 = 10ft
And it must extend 12 inches beyond, then the radius of the cover must be:
R = 10ft + 12in
Now, we know that 1ft = 12 in, then we can rewrite the radius as:
R = 10ft +1ft = 11ft
Then the area of the cover is:
[tex]A = 3.14*(11ft)^2 = 379.94 ft^2[/tex]
B) now we want to get the length of the rope, we know that the rope runs along the cover, then the length of the rope must be equal to the circumference of the cover.
Remember that the circumference of a circle of radius R is:
[tex]C = 2*pi*R[/tex]
Then the length of the rope will be:
[tex]C = 2*3.14*11ft = 68.2ft[/tex]
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You make a scale drawing of a tree using the scale 5 inches. = 27 feet. If the tree is 67.5 feet tall, how tall is the scale drawing?
Answer:
12.5 inches
Step-by-step explanation:
We use proportion to calculate the scale drawing
27 feet = 5 inches, so
67.5 feet = more inches (we know that it would be bigger than 5 inches)
We then put the bigger number on top and crossmultiply by saying:
67.5 over 27 × 5
Your answer should come out as 12.5 inches.
The earth travels around the sun at about 1,110 miles per minute.
About how many miles does the earth travel around the sun per second?
Drag and drop the answer into the box.
The earth travels around the sun about ___ Response area miles per second.
Answer:
18.5 miles
Step-by-step explanation:
the Sun at an average speed of 67,000 mph, or 18.5 miles a second.
Jenny's lunch account has $10 in it. She buys lunch three days in a row and spends $2.50, $2, and $2.75. On the fourth day, she
deposits $10 before buying lunch for $3. What is Jenny's balance after buying lunch on the fourth day?
$9.75
Given the information, we know that for the first 3 days, she spends a total of $7.25. On the fourth day, she deposits $10 before buying lunch for $3.
This means she had $20, but spent $10.25. $20-$10.25=$9.75 is the amount she has in her account.
Two angles in a triangle have measures of 42 and 82. (Degrees)
What is the measure of the third angle?
Answer:
angles of the triangle are equal 180
so 42+82=124
180-124=56
so the answer is 56
Step-by-step explanation:
3(1-5x)=2(3x+1) find the solution set
Answer:
1/21
Step-by-Step Explanation:
Let's solve your equation step-by-step.
3(1−5x)=2(3x+1)
Step 1: Simplify both sides of the equation.
3(1−5x)=2(3x+1)
(3)(1)+(3)(−5x)=(2)(3x)+(2)(1)(Distribute)
3+−15x=6x+2
−15x+3=6x+2
Step 2: Subtract 6x from both sides.
−15x+3−6x=6x+2−6x
−21x+3=2
Step 3: Subtract 3 from both sides.
−21x+3−3=2−3
−21x=−1
Step 4: Divide both sides by -21.
-21x/-21=-1/-21
x=1/21
[tex]\boldsymbol{\sf{3(1-5x)=2(3x+1)}}[/tex]
Reorder terms
[tex]\boldsymbol{\sf{3(-5x+1)=2(3x+1) }}[/tex]Distribute
[tex]\boldsymbol{\sf{-15x+3=2(3x+1) }}[/tex][tex]\boldsymbol{\sf{-15x+3=6x+2 }}[/tex]Subtract 3x from both sides.
[tex]\boldsymbol{\sf{-15x+3-3=6x+2-3 }}[/tex]Simplify
[tex]\boldsymbol{\sf{-15x=6x+1}}[/tex]Subtract 6x from both sides.
[tex]\boldsymbol{\sf{-15x-6x=6x-1-6x }}[/tex]Simplify
[tex]\boldsymbol{\sf{-21x=-1 }}[/tex]Divide both sides by the same factor
[tex]\boldsymbol{\sf{\dfrac{-21x}{-21}=\dfrac{-1}{-21} }}[/tex]Simplify
[tex]\boxed{\boldsymbol{\sf{x=\frac{1}{21} }}}[/tex]Someone please help I’m lost
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
There is one angle and an adjacent side of the triangle given equal to corresponding angle and side of the other triangle and if we observe the figure we can see that there's also a adjacent side XY common in both the Triangles.
Hence, the two triangles are congruent by SAS congruency criteria.
[tex] \qquad \large \sf {Conclusion} : [/tex]
SAS criteria> Function g can be thought of as a translated (shifted) version of Y f(x) = x².
Using translation concepts, function g(x) is given as follows:
g(x) = x² - 3.
What is a translation?A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.
Researching this problem on the internet, g(x) is a shift down of 3 units of f(x) = x², hence:
g(x) = x² - 3.
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WILL GIVE BRAINLIEST!!! If [tex]\frac{a}{b} =2[/tex] what is the value of [tex]\frac{a}{a-b}[/tex]?
Could the answer be D) or is it C)?
A) -2
B) 1
C) 2
D) It cannot be determined from the given information
Considering the given proportion, the value of [tex]\frac{a}{a - b}[/tex] is:
C) 2
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
The proportion between a and b is given by:
a/b = 2.
Then:
a = 2b.
The expression is:
[tex]\frac{a}{a - b} = \frac{2b}{2b - b} = \frac{2b}{b} = 2[/tex]
Hence option C is correct.
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can anyone help me solve these questions, please
Step-by-step explanation:
8.√128/√2
ans √64
10.3√81
3√3*3*3*3(find factor)
3 √3(this is cube root therefore we kept one out of three then we kept remaining inside of root.this is surds because one factor is inside the surds if factor is not remaining inside the surds then this is not surds)
Given: f(x) = x - 7 and h(x) = 2x + 3
Write the rule for f(h(x)).
f(h(x)) = 2x - 7
f(h(x)) = 2x - 4
f(h(x)) = 3x - 4
f(h(x)) = 3x - 7
Answer:
2nd option
Step-by-step explanation:
to find f(h(x)) substitute x = h(x) into f(x) , that is
f(h(x))
= f(2x + 3)
= 2x + 3 - 7
= 2x - 4
Which expression is equivalent to (z−3)4z−6 for all values of z where the expression is defined?
The equivalent of the expression [ (z−3)4z−6 ] is 4z² - 12z - 6.
What is the equivalent of the expression?
Given the expression; (z−3)4z−6
First, we apply distributive property.
(z−3)4z−6
(z−3)4z−6
z(4z) - 3(4z) - 6
We remove the parentheses
4z² - 12z - 6
Therefore, the equivalent of the expression [ (z−3)4z−6 ] is 4z² - 12z - 6.
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At the movie theater child admission is $5.20 and adult admission is $9.90.. On Friday 163 tickets were sold for a total sales of $1303.50. How many adult tickets were sold that day?
The number of tickets sold on Friday were 66 children tickets and 97 adult tickets.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Let x represent the number of children and y represent the number of adult, hence:
5.2x + 9.9y = 1303.5 (1)
Also:
x + y = 163 (2)
From both equations:
x = 66, y = 97
The number of tickets sold on Friday were 66 children tickets and 97 adult tickets.
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Mr. Carson washes his car every 8 days, checks the oil every 7
days, and checks the tire pressure every 9 days. He washed it Monday July 18,
2022, checked the oil on Wednesday and checked the tire pressure on Thursday
of that same week. When is the first day after that Monday on which he will
do all these activities on the same day? Find the number of days counted from
that Monday July 18, 2022.
The first day when he would do these activities on the same day is December 7, 2023.
When would he do these activities on the same day?In order to determine which day Mr. Carson would wash his car, check his oils and check the tire pressure, the multiple of 8, 7, and 9 have to be determined.
A multiple of a number is the product of an integer and that number. A common multiple is a number that is common to all three numbers. The lowest common multiple of 8, 7 and 9 is 504. So, in 504 days he would do all three activities on the same day.
In order to convert 504 days, take note of the following:
365 days = 1 year
12 month = 1 year
1 month = 4 weeks
30 days = 1 month
504 / 365 = 1 year 139 days
139 days / 30 days = 4 months 19 days
504 days = 1 year, 4 months and 19 days
1 year, 4 months and 19 days + July 18, 2022 = December 7, 2023
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HELP ME WOTH THIS QUESTIONNN!!
Answer:
C
Step-by-step explanation:
For lines l and m and the transversal line that creates angles 6 and 18, angles 6 and 18 are corresponding angles of lines l and m. If they are congruent, lines l and m are parallel.
Answer: Choice C
Need help ASAP
I will mark Brainleist
Need help part A, B and C
Roller Coaster Crew
Ray and Kelsey have summer internships at an engineering firm. As part of their internship, they get to assist in the planning of a brand new roller coaster. For this assignment, you help Ray and Kelsey as they tackle the math behind some simple curves in the coaster's track.
Part A
The first part of Ray and Kelsey's roller coaster is a curved pattern that can be represented by a polynomial function.
1. Ray and Kelsey are working to graph a third-degree polynomial function that represents the first pattern in the coaster plan. Ray says the third-degree polynomial has four intercepts. Kelsey argues the function can have as many as three zeros only. Is there a way for the both of them to be correct? Explain your answer.
2. Kelsey has a list of possible functions. Pick one of the g(x) functions below and then describe to Kelsey the key features of g(x), including the end behavior, y-intercept, and zeros.
g(x) = (x + 2)(x − 1)(x − 2)
g(x) = (x + 3)(x + 2)(x − 3)
g(x) = (x + 2)(x − 2)(x − 3)
g(x) = (x + 5)(x + 2)(x − 5)
g(x) = (x + 7)(x + 1)(x − 1)
3. Create a graph of the polynomial function you selected from Question 2.
Part B
The second part of the new coaster is a parabola.
4. Ray needs help creating the second part of the coaster. Create a unique parabola in the pattern f(x) = (x − a)(x − b). Describe the direction of the parabola and determine the y-intercept and zeros.
5. Create a graph of the polynomial function you created in Question 4.
Part C
6. Now that the curve pieces are determined, use those pieces as sections of a complete coaster. By hand or by using a drawing program, sketch a design of Ray and Kelsey's coaster that includes the shape of the g(x) and f(x) functions that you chose in the Parts A and B. You do not have to include the coordinate plane. You may arrange the functions in any order you choose, but label each section of the graph with the corresponding function for your instructor to view.
Answer:
Part A
1. A third degree polynomial has exactly three zeros. This is because its highest power (or degree) is 3. Ray would only be correct in saying that a polynomial can have 4 zeros if it is a 4th degree polynomial. Since in this case, a 4rd degree polynomial is being discussed, Kelsey is correct.
2. Function chosen: g(x) = (x + 2)(x - 1)(x - 2)
End behaviour: x —> ∞, g(x) —> ∞
x —> - ∞, g(x) —> -∞
Zeros/x intercepts of the function: -2, 1, 2
y intercept: g(x) = (x + 2)(x - 1)(x - 2)
g(x) = (0 + 2)(0 - 1)(0 - 2)
g(x) = (2)(-1)(-2)
g(x) = 4
3. See Graph 1
Part B
4. f(x) = (x + 5)(x + 3)
Direction: opens upward
Zeros/x intercepts: -5, -3
y intercept: 15
5. See graph 2
Part C
You can draw the roller coaster yourself using the graphs below
Complete the following table given this information: (Do not round intermediate calculations.) Cost of machine $ 94,000 Residual value $ 4,000 Useful life 5 years Estimated units machine will produce 100,000 Actual production: Year 1 60,000
Year 2 15,000 Use MACRS table.
Straight line method?
Units of production?
Declining balance?
MACRS (5-year class)
The completion of the following table under different depreciation methods is as follows:
Depreciation Expense:Method Year 1 Year 2
Straight line $18,000 $18,000
Units of production $54,000 $13,500
Declining balance $37,600 $22,560
MACRS (5-year class) $18,800 $30,080
Data and Calculations:Cost of machine = $94,000
Residual value = $4,000
Depreciable value = $90,000 ($94,000 - $4,000)
Estimated useful life = 5 years
Depreciation expense:
Straight-line method = $18,000 ($90,000/5)
Estimated units of produciton = 100,000
Unit depreciation rate = $0.90
Actual production Depreciation
Year 1 = 60,000 $54,000 ($0.90 x 60,000)
Year 2 = 15,000 $13,500 ($0.90 x 15,000)
Declining Balance:
Year 1 = $37,600 ($94,000 x 40%)
Year 2 = $22,560 ($94,000 - $37,600) x 40%
MACRS:
Year 1 = $18,800 ($94,000 x 20%)
Year 2 = $30,080 ($94,000 x 32%)
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NO LINKS!! Please help me with this problem
[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
The given vertex and Focus are of a vertical parabola having an opening downward as the focus is in downward direction as the vertex.
Focus of the parabola can be written as :
[tex]\qquad \sf \dashrightarrow \: (h ,k+ a )[/tex]
where, h and k are coordinates of vertex
so,
k + a = -2 -1 + a = -2a = -1So, the equation of parabola can be written as :
[tex]\qquad \sf \dashrightarrow \: (x - h) {}^{2} = 4a(y - k)[/tex]
plug in the values ~
[tex]\qquad \sf \dashrightarrow \: (x - 1) {}^{2} = 4(- 1)(y + 1) {}^{} [/tex]
[tex]\qquad \sf \dashrightarrow \: (x - 1) {}^{2} = - 4(y + 1)[/tex]
Answer:
[tex](x-1)^2=-4(y+1)[/tex]
Step-by-step explanation:
Standard form of a parabola with a vertical axis of symmetry:
[tex](x-h)^2=4p(y-k) \quad \textsf{where}\:p\neq 0[/tex]
Vertex = (h, k)Focus = (h, k+p)Directrix: y = (k-p)Axis of symmetry: h = kIf p > 0, the parabola opens upwards, and if p < 0, the parabola opens downwards.Given:
vertex = (1, -1)focus = (1, -2)Comparing with the formulas:
⇒ h = 1
⇒ k = -1
⇒ k + p = -2 ⇒ -1 + p = -2 ⇒ p = -1
Substituting the values into the formula:
[tex]\implies (x-1)^2=4(-1)(y-(-1))[/tex]
[tex]\implies (x-1)^2=-4(y+1)[/tex]
waht is the x^2 + 10 = 0
Answer:
x = ±√10i (i outside the radical), or approximately ±3.62i, or no solution depending on your class.
Step-by-step explanation:
x^2 + 10 = 0
x^2 = -10
x = ±√-10
x = ±√10i (i outside the radical), or approximately ±3.62i.
The solution is not real.
If you meant x^2 - 10 = 0 then x = ±√10 or approximately ±3.62. This solution is real.
If you invested $4,500 for 8 months at an interest rate of 2.75%, how much interest would you earn?
Given the money invested and the interest rate, the value of the interest earned after 8 months is $82.50.
What is the value of the Interest?
From the equation of simple interest; I = PRT
Given that;
Principal P = $4,500Interest rate R = 2.75% = 2.75/100 = 0.0275Time T = 8 months = 8/12 yearsInterest I = ?I = PRT
I = $4,500 × 0.0275 × 8/12
I = $82.50
Given the money invested and the interest rate, the value of the interest earned after 8 months is $82.50.
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1. Solve x² +5x+3=0
Give your solutions correct to 2 decimal places.
Answer:
Step-by-step explanation:
hello :
x² +5x+3=0
delta = b²-4ac when : a =1 and b=5 c=3
delta =5²-4(1)(3) =13
X1 =(-b-sqrt(delta))/2a
X2 =(-b+sqrt(delta))/2a
continu.....
New topic really confused
The cost given shows that the amount left is £12.
How to illustrate the information?From the information given, it was stated that the person saved £60 and spent £42 on coat and £6 on scarf
The amount that the person has left will be:
= £60 - £42 - £6
= £12
In conclusion, the person has £12 left.
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Numbers from 1 to 50 Find the probability of choosing
numbers with 4 in tens places.
Answer: 1/5
Step-by-step explanation:
There are 10 numbers, out of 50, which have a 4 in their tens place: 40, 41, 42, 43, 44, 45, 46, 47, 48, and 49.
Therefore our desired probability is 10/50 or 1/5.
PLEASE HELP PLEASE I DONT KNOW THIS QUESTION AND IVE BEEN STUCK ON THIS FOR A DAY
Answer:
A = -5
B = 1
Step-by-step explanation:
Hello!
You simply plug in the given x-value into the equation to find the missing y-value.
Solve for APlug in -1 for x into y = 2x - 3.
y = 2x - 3y = 2(-1) - 3y = -2 - 3y = -5Solve for BPlug in 2 for x into y = 2x - 3.
y = 2x - 3y = 2(2) - 3y = 4 - 3y = 1Solve the system of equations.
y = 2x+ 3
y=x^2+3x+3
Answer:
(0,3)
(-1,1)
Step-by-step explanation:
Hello!
Since both equations are equal to y, we can set the right-hand side of the equations equal to each other.
[tex]y = 2x + 3\\y = x^2 + 3x + 3[/tex][tex]y = y[/tex][tex]2x + 3 = x^2 + 3x + 3[/tex]Solve for x[tex]2x + 3 = x^2 + 3x + 3[/tex][tex]0 = x^2 + x[/tex][tex]0 = x(x + 1)[/tex][tex]x = 0, x =-1[/tex]X can either be 0 or -1. Remember, a solution to a system is not complete without a y-value. Plug in 0 and -1 for x in the first equation, and find the corresponding y-values.
[tex]y = 2(0) + 3\\y = 3[/tex]
And
[tex]y = 2(-1) + 3\\y = -2 + 3\\y = 1[/tex]
So the solutions to the system are (0,3) and (-1,1)
Which is true regarding the system of equations?
6 x + 2 y = 46. 3 x + y = 23.
The system results in a false statement.
The system results in an intersection at one point.
The system results in parallel lines.
The system results in a true statement because they are the same line.
Answer:
they are the same line
Step-by-step explanation:
if you divide the first line by 2 you'll get:
2(3x)+2y=2(23)===> 3x+y=23
Solve for m. 3/4m>−12 m>−16 m<−16 m>−9 m<−9
Answer: m > -16
Step-by-step explanation:
[tex]\frac{3}{4}m > -12\\\\m > -\frac{4}{3}(12)=-16[/tex]
what percentage was the price of the shirt reduced
If f (7) = 22, then
f(f-1(22)) = [?]
Answer: 22
Step-by-step explanation:
[tex]f(f^{-1}(x))=f^{-1}(f(x))=x[/tex]