Find the mass of an object with a density of 2.01g/mL and a volume of 3.77mL

Answer:

Volume of ammonia produced = 398.7 dm³

Explanation:

Given data:

Volume of N₂ = 200 dm³

Pressure and temperature = standard

Volume of ammonia produced = ?

Solution:

Chemical equation:

N₂ + 3H₂     →      2NH₃

Number of moles of N₂:

PV = nRT

1 atm× 200 L = n× 0.0821 atm.L/mol.K × 273 K

n = 200 atm.L /22.41 atm.L/mol

n = 8.9 mol

Now we will compare the moles of ammonia and nitrogen.

               N₂          :         NH₃

                1            :           2

              8.9          :        2/1×8.9 = 17.8 mol

Volume of ammonia:

1 mole of any gas occupy 22.4 dm³ volume

17.8 mol ×22.4 dm³/1 mol = 398.7 dm³

Answer:

F4

Explanation:

Friction is a force that opposes motion

Answer:

Heat waves

Explanation:

The appetite effect cause one to believe is those who witness violence in the media see the world as threatening.

The appetite effect is used as a slang here, if someone is consuming violent media.

If someone is consuming violent media, then his appetite effect will be threatening from the world.

Thus, the correct option is B. Those who witness violence in the media see the world as threatening.

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Answer:

b

Explanation:

edge 2022

Answer:

0.0835 M

Explanation:

Step 1: Write the balanced equation

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

0.0250 L of 0.105 M HCl react.

0.0250 L × 0.105 mol/L = 2.63 × 10⁻³ mol

Step 3: Calculate the reacting moles of NaOH

The molar ratio of NaOH to HCl is 1:1. The reacting moles of NaOH are 1/1 × 2.63 × 10⁻³ mol = 2.63 × 10⁻³ mol.

Step 4: Calculate the molarity of NaOH

2.63 × 10⁻³ moles of NaOH are in 0.0315 L of solution.

M = 2.63 × 10⁻³ mol / 0.0315 L = 0.0835 M

Answer: 1.4666667e+14

Explanation:

Answer:

b. 1

Explanation:

If we consider it carefully we will notice that the electronic configuration of iron III is; [Ar] 3d5 4s0.

Now, three electrons from the d orbital are paired with the three electrons from three F atoms according to the valence bond theory. This leaves out one pair of electrons localized on the d orbital of iron.

Hence the compound has one lone pair of electrons.

The energy levels of an atom is the quantized amount of energy found at different levels n = 1,2, 3 etc. Thus option B is correct.

Electrons in an atom are revolving around the nucleus through circular paths of fixed energy. These circular paths are called orbits and the different energy levels in these paths are called orbitals.

The quantized energy levels are termed as n = 1, 2, 3 that is lowest level to higher levels of energy. Electrons are able to transit between these energy levels.

Thus, a level of n=1 is the ground level or first energy level n =2 is second energy level and so on. These energy level cannot be fractions and therefore, they are said to quantised. Hence, option B is correct.

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Answer: n = 1, 2, 3,

a quantized amount of energy found at the different levels

Explanation:

Answer:

Explanation:

The time spent in driving can be found by using the formula

[tex]t = \frac{d}{v} \\ [/tex]

d is the distance

v is the velocity

From the question we have

[tex]t = \frac{2952}{82} \\ [/tex]

We have the final answer as

Hope this helps you

Answer: The religious fanaticism of Aurangzeb overshadowed his virtues. His reversal of Akbar's policy of religious toleration resulted in weakening the entire structure of the Mughal empire. It led to several conflicts and wars in different parts of the country.

Answer:

M = 0.23 M

Explanation:

Given data:

Molarity of solution = ?

Mass of NH₄Br = 4.50 g

Volume of solution = 213 mL (213 mL× 1L /1000 mL = 0.213 L)

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of NH₄Br:

Number of moles = mass/molar mass

Number of moles = 4.50 g / 97.94 g/mol

Number of moles = 0.05 mol

Molarity:

M = 0.05 mol/ 0.213 L

M = 0.23 M

Answer:

a. H₂S(aq) + H₂O(l) ⇄ HS⁻(aq) + H₃O⁺(aq)

b. NH₄⁺(aq) + H₂O(l) ⇄ NH₃(aq) + H₃O⁺(aq)

Explanation:

According to Bronsted-Lowry acid-base theory,

a. When dissolved in water, H₂S behaves as an acid according to the following equation.

H₂S(aq) + H₂O(l) ⇄ HS⁻(aq) + H₃O⁺(aq)

b. When dissolved in water, NH₄⁺ behaves as an acid according to the following equation.

NH₄⁺(aq) + H₂O(l) ⇄ NH₃(aq) + H₃O⁺(aq)

To determine the mass of CO₂, the following must be known :

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

Given the mass of  CaCO₃, so to determine the mass of CO₂ :

1. Find the mol of  CaCO₃ from the molar mass of  CaCO₃

[tex]\tt n_{CaCO_3}=\dfrac{mass~CaCO_3}{MW~CaCO_3}[/tex]

2. Find the mole ratio of  CaCO₃ : CO₂(from equation = 1 : 1)

[tex]\tt n_{CaCO_3}\div n_{CO_2}=1\div 1[/tex]

3. Find the mass of CO₂ from the molar mass of CO₂

[tex]\tt mass_{CO_2}=n_{CO_2}\times MW_{CO_2}[/tex]

Answer:

1 3 and 5

Explanation:

Answer:

yes I would

Explanation:

but I would like to advice you to add more info about project and be precise

Answer:

To balance a reaction, the amount of reactants must be equal to the amount of products, as stated by the Law of Conservation of Matter. It may help you to keep track of  the number of each element in a list as you try to balance. It's not able to be balanced.

Answer:

2,1,1,1

Explanation:

Hope this helped!

Answer:

1.3×10²³ formula unit

Explanation:

Given data:

Mass of CaCl₂ = 23.8 g

Number of formula unit = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 23.8 g/110.98 g/mol

Number of moles = 0.21 mol

1 mole of any substance contain 6.022×10²³ formula unit

0.21 mol × 6.022×10²³ formula unit / 1mol

1.3×10²³ formula unit

Answer:

the correct answer is A, Hg22+ on edge 2020

Explanation:

i took the review

The only cation that can form an ionic bond with an anion in the list is Hg22+.

The term "anion" refers to a negatively charged ion. An ionic bond is a kind of bond that is formed between an anion and a cation. As a result, ionic compounds are actually an ion pair.

If we look at the options closely, the only cation that can form an ionic bond with an anion in the list is Hg22+.

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Answer: 1.95 g of oxygen is present.

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

[tex]p_{total}=p_{methane}+p_{oxygen}[/tex]

Given : [tex]p_{total}[/tex] =total pressure of gases = 727 mm Hg

[tex]p_{methane}[/tex] = partial pressure of methane = 571 mm Hg

[tex]p_{oxygen}[/tex] = partial pressure of oxygen = ?

[tex]727=571+p_{oxygen}[/tex]  

[tex]p_{oxygen}=156mmHg[/tex]

Also [tex]p_{oxygen}=x_{oxygen}\times p_{total}[/tex]

Given : 3.62 g of methane is present

moles of methane = [tex]\frac{\text{Given mass}}{\text {Molar mass}}=\frac{3.62g}{16g/mol}=0.226moles[/tex]

[tex]x_{oxygen}[/tex] = mole fraction of oxygen  

=[tex]\frac{\text {moles of oxygen}}{\text {total moles}}=\frac{y}{y+0.226}[/tex]

[tex]156=\frac{y}{y+0.226}\times 727[/tex]

[tex]y=0.061[/tex]

mass of oxygen = [tex]moles\times {\text {Molar mass}}=0.061\times 32=1.95g[/tex]

Thus 1.95 g of oxygen is present.

We prepare the volume of the 8.61 M stock solution of 0.102 L, then we dilute it by adding water to 0.5 L

Given

5.00 × 10² mL of a 1.75 M H₂SO₄ solution

8.61 M stock solution

Required

The volume of stock solution

Solution

Molarity from 8.61 M to 1.75 M ⇒Dilution

We can use dilution formula :

[tex]\tt \boxed{\bold{M_1.V_1=M_2.V_2}}[/tex]

M₁=8.61 M

V₂=500 ml = 0.5 L

M₂=1.75 M

[tex]\tt V_1=\dfrac{M_2.V_2}{M_1}\\\\V_1=\dfrac{1.75\times 0.5}{8.61}\\\\V_1=0.102~L[/tex]

Answer: I think that is C, a light sensor but im not sure

Explanation:

Answer:

temperature probe

Explanation:

Answer:

Metals

Explanation:

Answer: The resulting isotope is [tex]^{231}_{92}\textrm {U}[/tex]

Explanation:

Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.

[tex]^{235}_{92}\textrm{U} \rightarrow ^{231}_{90}\textrm {Th}+^{4}_{2}n[/tex]

Beta Decay : It is a type of decay process, in which a proton gets converted to neutron and an electron. This is also known as -decay. In this the mass number remains same but the atomic number is increased by 1.

[tex]^{231}_{90}\textrm{Th}\rightarrow ^{231}_{92}\textrm {Th}+2^{0}_{-1}n[/tex]

The resulting isotope is [tex]^{231}_{92}\textrm {U}[/tex]

Answer: The empirical formula is [tex]CH_2[/tex] and molecular formula is [tex]C_4H_8[/tex]

Explanation:

We are given:

Mass of [tex]CO_2[/tex] = 18.95 g

Mass of [tex]H_2O[/tex]= 7.759 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, =[tex]\frac{12}{44}\times 18.59=5.07g[/tex] of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, =[tex]\frac{2}{18}\times 7.759=0.862g[/tex] of hydrogen will be contained.

Mass of C = 5.07 g

Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles[/tex]

Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =[tex]\frac{0.422}{0.422}=1[/tex]

For H =[tex]\frac{0.862}{0.422}=2[/tex]

The ratio of C : H = 1: 2

Hence the empirical formula is [tex]CH_2[/tex].

The empirical weight of [tex]CH_2[/tex] = 1(12)+2(1)= 14 g.

The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4[/tex]

The molecular formula will be=[tex]4\times CH_2=C_4H_8[/tex]

Answer:

water

Explanation:

because the others are in compounds and can not be considered as  products lonely.

Answer:

D) will not form any stereoisomers since the product is a saturated hydrocarbon.

Explanation:

Stereoisomerism, or spatial isomerism,refers to a type of isomerism in which  two or more molecules have the same molecular formula and atom to atom connectivity but different three-dimensional orientations of those atoms in space.

Stereoisomerism occurs in alkenes because free rotation about the C=C bond is hindered. Thus, the molecule is "locked" in a particular orientation. In a saturated alkane, there is unrestricted free rotation about the C-C bond hence straight chain alkanes do not have steroisomers.

The product formed is 3,4-dimethyl hexane which is a straight chain saturated alkane. This compound does not exhibit stereoisomerism.

Answer:

CaO, CaF2, or CaCl2

Explanation:

In an ionic compound, the charges need to balance out. This is the only set of compounds that fits this criteria.

Answer:

CaO CaF2 CaCl2 are ionic

Explanation:

Because electronegativity difference between calcium and other atom is more than 1.7

Answer:

29273.178 joules have been added to the gas for the entire process.

Explanation:

The specific heats of monoatomic gases, measured in joules per mol-Kelvin, are represented by the following expressions:

Isochoric (Constant volume)

[tex]c_{v} = \frac{3}{2}\cdot R_{u}[/tex] (1)

Isobaric (Constant pressure)

[tex]c_{p} = \frac{5}{2}\cdot R_{u}[/tex] (2)

Where [tex]R_{u}[/tex] is the ideal gas constant, measured in pascal-cubic meters per mol-Kelvin.

Under the assumption of ideal gas, we notice the following relationships:

1) Temperature is directly proportional to pressure.

2) Temperature is directly proportional to volume.

Now we proceed to find all required temperatures below:

(i) Alice heats the gas at constant volume until its pressure is doubled:

[tex]\frac{T_{2}}{T_{1}} = \frac{P_{2}}{P_{1}}[/tex] (3)

([tex]\frac{P_{2}}{P_{1}} = 2[/tex], [tex]T_{1} = 273.15\,K[/tex])

[tex]T_{2} = \frac{P_{2}}{P_{1}} \times T_{1}[/tex]

[tex]T_{2} = 2\times 273.15\,K[/tex]

[tex]T_{2} = 546.3\,K[/tex]

(ii) Bob further heats the gas at constant pressure until its volume is doubled:

[tex]\frac{T_{3}}{T_{2}} =\frac{V_{3}}{V_{2}}[/tex] (4)

([tex]\frac{V_{3}}{V_{2}} = 2[/tex], [tex]T_{2} = 546.3\,K[/tex])

[tex]T_{3} = \frac{V_{3}}{V_{2}}\times T_{2}[/tex]

[tex]T_{3} = 2\times 546.3\,K[/tex]

[tex]T_{3} = 1092.6\,K[/tex]

Finally, the heat added to the gas ([tex]Q[/tex]), measured in joules, for the entire process is:

[tex]Q = n\cdot [c_{v}\cdot (T_{2}-T_{1})+c_{p}\cdot (T_{3}-T_{2})][/tex] (5)

If we know that [tex]R_{u} = 8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K}[/tex], [tex]n = 2\,mol[/tex], [tex]T_{1} = 273.15\,K[/tex], [tex]T_{2} = 546.3\,K[/tex] and [tex]T_{3} = 1092.6\,K[/tex], the heat added to the gas for the entire process is:

[tex]c_{v} = \frac{3}{2}\cdot \left(8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K} \right)[/tex]

[tex]c_{v} = 12.471\,\frac{J}{mol\cdot K}[/tex]

[tex]c_{p} = \frac{5}{2}\cdot \left(8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K} \right)[/tex]

[tex]c_{p} = 20.785\,\frac{J}{mol\cdot K}[/tex]

[tex]Q = (2\,mol)\cdot \left[\left(12.471\,\frac{J}{mol\cdot K} \right)\cdot (536.3\,K-273.15\,K)+\left(20.785\,\frac{J}{mol\cdot K} \right)\cdot (1092.6\,K-546.3\,K )\right][/tex]

[tex]Q = 29273.178\,J[/tex]

29273.178 joules have been added to the gas for the entire process.

Explanation:

[tex]answer[/tex]

The overall cell potential can be calculated by using the equation E0cell=E0red−E0oxid. Step 2: Solve. Before adding the two reactions together, the number of electrons lost in the oxidation must equal the number of electrons gained in the reduction. The silver half-cell reaction must be multiplied by two.