Find the solution to the linear system of differential equations satisfying the initial conditions a(0) 0 and y(0) 2 y(t) Note: You can earn partial credit on this problem.

The variation in length between the longest and shortest scraps of wood is 0.875.

The sum of both an entire number and a legal fraction is contained in a mixed fraction or number.

We translate an improper fraction into such a mixed fraction and use the basic arithmetical operations. An incorrect fraction is one in which the numerator exceeds the denominator.

Longest value ; 5

Shortest value; 4 1/8 (mixed fraction)

Convert mixed fraction in to proper fraction.

4 1/8 = ( 4*8 + 1 )/8

4 1/8 = 33/8

difference = longest pieces of scrap wood - shortest  pieces of scrap wood

difference =  5 - 33/8

difference = 0.875

Thus, the difference in length between the longest and shortest scraps of wood is 0.875.

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The probability of picking a vowel, replacing it, and then picking a consonant from the word "SLEEP" is approximately 0.096 or 9.6%.

Probability is usually expressed as a number between 0 and 1, with 0 meaning that the event is impossible and 1 meaning that the event is certain.

There are two vowels (E) and three consonants (S, L, P) in the word "SLEEP".

The probability of picking a vowel on the first draw is 2/5, because there are two vowels out of five letters total.

Since we replace the vowel we picked, the probability of picking another vowel on the second draw is also 2/5.

The probability of picking a consonant on the third draw is 3/5, because there are three consonants left out of five letters total.

Therefore, the probability of picking a vowel, replacing it, and then picking a consonant from the word "SLEEP" is:

(2/5) x (2/5) x (3/5) = 12/125 or approximately 0.096 or 9.6%.

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The coordinates of D are: B. (2.5, 0.5).

The product of the slopes of CD and AB is: C. -1.

This shows that AB is perpendicular to CD. Therefore, C lies on the perpendicular bisector of AB.

In order to determine the midpoint of a line segment with two (2) endpoints, we would add each point together and divide by two (2).

Midpoint = [(x₁ + x₂)/2, (y₁ + y₂)/2]

Substituting the given parameters into the midpoint of a line segment formula, the midpoint of line AB is given by;

Midpoint AB = [(4 + 1)/2, (-2 + 3)/2]

Midpoint AB = [5/2, 1/2]

Midpoint AB = (2.5, 0.5).

5, 2

Next, we would determine the slopes of line segment CD and AB:

Slope (m) of CD = (0.5 - 2)/(2.5 - 5)

Slope (m) of CD = -1.5/-2.5 = 3/5

Slope (m) of AB = (-2 - 3)/(4 - 1)

Slope (m) of AB = -5/3 = 0.6

Product of the slopes = 3/5 × -5/3 = -3/3 = -1.

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The width of the blanket to the nearest tenth of an inch is approximately 67.4 inches.

What is width in rectangle ?

In a rectangle, the width refers to the measurement of the shorter side of the rectangle, which is perpendicular to its length.

Let x be the width of the blanket in inches. Then the length of the blanket is x + 18 inches.

The area of the blanket is given by:

Area = Length x Width

5760 sq inches = (x + 18) inches * x inches

Expanding the right-hand side and solving for x, we get:

[tex]x^2 + 18x - 5760 = 0[/tex]

We can solve this quadratic equation using the quadratic formula:

[tex]x = (-b \pm \sqrt{(b^2 - 4ac)}) / 2a[/tex]

where a = 1, b = 18, and c = -5760. Plugging in these values, we get:

[tex]x = (-18 \pm \sqrt{(18^2 - 4(1)(-5760))}) / 2(1)[/tex]

[tex]x = (-18 \pm \sqrt{(18^2 + 23040)}) / 2[/tex]

x ≈ 67.42 or x ≈ -85.42

Since the width cannot be negative, the width of the blanket to the nearest tenth of an inch is approximately 67.4 inches.

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The two cars are approaching each other at a rate of 36 km/hr at the given instant.

We can solve this problem by using the Pythagorean theorem and differentiating with respect to time. Let's call the distance of the first car from the intersection "x" and the distance of the second car from the intersection "y". We want to find the rate at which the two cars are approaching each other, which we'll call "r".

At any moment, the distance between the two cars is the hypotenuse of a right triangle with legs x and y, so we can use the Pythagorean theorem

r^2 = x^2 + y^2

To find the rates of change of x and y, we differentiate both sides of this equation with respect to time

2r(dr/dt) = 2x(dx/dt) + 2y(dy/dt)

Simplifying and plugging in the given values

dr/dt = (x(dx/dt) + y(dy/dt)) / r

dr/dt = (0.2 x 90 + 0.15 x (-60)) / sqrt((0.2)^2 + (0.15)^2)

dr/dt = (18 - 9) / sqrt(0.04 + 0.0225)

dr/dt = 9 / sqrt(0.0625)

dr/dt ≈ 36 km/hr

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Descriptive statistics are the most useful in life. Descriptive statistics provide information about a data set and can help to summarize and interpret data. Specifically, I find the mean and median to be the most useful.

Descriptive statistics involves the use of measures such as the mean, median, mode, and range, as well as graphical representations of the data, such as histograms, box plots, and scatter plots.

The mean is the average of a set of data and is useful for summarizing and interpreting data. For example, when I am studying for a test, I often use the mean of my practice test scores to understand my overall performance.

The median is the middle value of a set of data and is useful for understanding the spread of the data. For example, when I am tracking my monthly expenses, I often use the median to understand how much I am spending each month. By taking the median of my monthly expenses, I can get an idea of which expenses are taking up the most of my budget.

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Some of the tips which is used to conduct a survey are:

Conducting a survey is an important tool for gathering information from a large and diverse group of people. Its allows allow researchers to obtain data from a representative sample of the population, which can then be used to make informed decisions, identify trends, and measure changes over time.

Also important, its can provide insight into people's attitudes, beliefs, and behaviors, which can be valuable in developing marketing strategies, designing programs and policies, and making important decisions.

A paragraph in a designed questionnaire which can remind participants why your doing the survey and that their information will kept confidential is as follows: "Thank you for taking the time to participate in this survey. The purpose of this questionnaire is to gather information about your experiences and opinions on a particular topic. Your participation is crucial to help us gain insights and make informed decisions. All of the information provided in this survey will be kept strictly confidential and will only be used for research purposes".

Full question "In a designed questionnaire, remind participants why your doing the survey and that their information will kept confidential".

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The function for this problem is given as follows:

[tex]f(x) = \sqrt{57 - x}[/tex]

The derivative of the function is given as follows:

[tex]f^{\prime}(x) = -\frac{1}{2\sqrt{57 - x}}[/tex]

The slope of the tangent line at point (8,7) is given by the numeric value of the derivative of f(x) at x = 8, hence:

[tex]f^{\prime}(8) = -\frac{1}{2\sqrt{57 - 8}}[/tex]

m = f'(8) = -1/14.

Hence the equation of the tangent line, which is a linear function, is given as follows:

y = -x/14 + b.

When x = 8, y = 7, hence the intercept b is obtained as follows:

7 = -8/14 + b

b = 7 + 8/14

b = 49/7 + 4/7

b = 53/7.

Hence the equation is given as follows:

y = -x/14 + 53/7.

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Answer:

350.3 g

Step-by-step explanation:

310 * 113% = 310 * 1.13 = 350.3 g

Hope this helps!

Answer:

No diagram provided here

The solutions to the given equation in the interval $[0,2\pi)$ are:

[tex]$x=\frac{\pi}{6}, \frac{5\pi}{6}, \frac{3\pi}{2}$$[/tex]

The given equation is:

[tex]$$\cos(2x) + \sin(x) = 0$$[/tex]

We can write [tex]$\cos(2x)$[/tex] as [tex]$1-2\sin^2(x)$[/tex]using double angle formula for cosine. Substituting this in the given equation, we get:

[tex]$$1-2\sin^2(x) + \sin(x) = 0$$[/tex]

Rearranging and factoring, we get:

[tex]$$(2\sin(x) - 1)(\sin(x) + 1) = 0$$[/tex]

So, either [tex]$2\sin(x) - 1 = 0$[/tex] or  [tex]$\sin(x) + 1 = 0$[/tex].

Solving [tex]$2\sin(x) - 1 = 0$[/tex], we get:

[tex]$$\sin(x) = \frac{1}{2}$$[/tex]

which has solutions [tex]x=\frac{\pi}{6}$[/tex] and $[tex]x=\frac{\pi}{6}$[/tex] in the interval [tex]$[0,2\pi)$[/tex].

Solving [tex]$\sin(x) + 1 = 0$[/tex], we get:

[tex]$$\sin(x) = -1$$[/tex]

which has solution [tex]x=\frac{3\pi}{2}$[/tex]in the interval [tex]$[0,2\pi)$[/tex]

Therefore, the solutions to the given equation in the interval $[0,2\pi)$ are:

[tex]$x=\frac{\pi}{6}, \frac{5\pi}{6}, \frac{3\pi}{2}$$[/tex]

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The process to show that subspace (a, b) of r is homeomorphic with (0, 1) and the subspace [a, b] of r is homeomorphic with [0, 1] is explained below.

To prove that the subspace (a, b) of the real numbers is homeomorphic to the interval (0, 1), we can define a function f(x) = (x-a)/(b-a).

This function maps the interval (a, b) onto (0, 1) by scaling and shifting the values of x so that "a" maps to "0" and "b" maps to "1", while preserving the order and continuity of the values.

The inverse function is g(y) = ay + (1-y)b, which maps (0, 1) onto (a, b) by reversing the scaling and shifting of the values of y so that "0" maps to "a" and "1" maps to "b", while preserving the order and continuity of the values.

So, f(x) and g(y) are both continuous and bijective, and their inverses are also continuous, so (a, b) and (0, 1) are homeomorphic.

Similarly, to show that the subspace [a, b] of the real numbers is homeomorphic to the interval [0, 1], we can define a function h(x) = (x-a)/(b-a).

This function maps the interval [a, b] onto [0, 1] by scaling and shifting the values of x so that "a" maps to "0" and "b" maps to "1", while preserving the order and continuity of the values.

The inverse function is k(y) = ay + (1-y)b, which maps [0, 1] onto [a, b] by reversing the scaling and shifting of the values of y so that "0" maps to "a" and "1" maps to "b", while preserving the order and continuity of the values.

So, h(x) and k(y) are both continuous and bijective, and their inverses are also continuous, so [a, b] and [0, 1] are homeomorphic.

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Consider relation Ron set A, where R = {(a, b)| a divides b), and A is the set of positive Integers. The relation have antisymmetric. So the option A is correct.

A relation is antisymmetric if and only if it is not symmetric and for all elements a and b in the set, if (a,b) is in the relation, then (b,a) is not in the relation. In other words, if a is related to b and b is related to a, then a must be equal to b.

A relation is antisymmetric if for all elements (a,b) in the relation, if a divides b and b divides a then a=b. In this case, if a divides b and b divides a, then a and b must both be the same number since a positive integer cannot divide itself. Therefore, Ron set A is antisymmetric. So the option A is correct.

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The complete question is:

Consider relation Ron set A, where R = {(a, b)| a divides b), and A is the set of positive Integers. Which of the following properties does the relation have? Check all that apply.

A. Antisymmetric

B. Transitive

C. Reflexive

D. Symmetric

Answer:

A and B are not mutually exclusive

Step-by-step explanation:

A and B are not mutually exclusive because P(A and B) > 0. If A and B were mutually exclusive, then they would have no outcomes in common and the probability of their intersection would be zero. However, in this case, they do share some outcomes, since P(A and B) is greater than zero.

The average rate of change between the points (17, 5) and (19, -1) is -3.

If we have a given function y = f(x) with two known points (a, f(a)) and (b, f(b)), then the average rate of change in that interval [a, b] is:

R = ( f(b) - f(a))/(b - a)

Here we have the two points (17, 5) and (19, -1)

So we have:

a = 17 and f(a) = 5

b = 19 and f(b) = -1

Replacing that in the formula for the average rate of change we will get:

R = (-1 - 5)/(19 - 17)

R = -6/2

R = -3

The average rate of change is -3

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After labeling with the corresponding boxes , The statements which describes Red pulp and white pulp are as follow:

1. Red pulp           2. Red Pulp        3. White Pulp        4. Red pulp    

5. White Pulp        6. White Pulp        7. Red Pulp.

Red Pulp:

The red pulp of the spleen is made up of connective tissue (also known as Bill Roth's cord) and numerous sinusoids of the spleen which appear red due to excess blood. Its main function is to filter antigens, microorganisms and defective or worn out red blood cells from the blood.

The spleen consists of red and white pulp, separated by the marginal zone; 76-79% of a normal spleen is made up of red pulp. Unlike white pulp, which contains mostly lymphocytes (such as T cells), red pulp is made up of several types of blood cells, including platelets, granulocytes, red blood cells, and plasma.

White Pulp:

White pulp is the histological name for the areas of the spleen (so called because they appear whiter in rough sections than the surrounding red pulp), which make up approximately 25% of the spleen. The white pulp is entirely composed of lymphoid tissue.

Specifically, the white pulp contains several regions with distinct functions:

The periarteriolar lymphatic sheaths (PALS) are usually associated with the arteriolar supply to the spleen; they contain T lymphocytes.

Lymphoid follicles with dividing B lymphocytes located between the PALS and the marginal zone bordering the red pulp. This region produces IgM and IgG2.

These molecules play a role in the opsonization of extracellular organisms, in particular encapsulated bacteria.

The marginal zone exists between the white pulp and the red pulp. It is located away from the central arterioles, close to the red pulp. It contains antigen-presenting cells (APCs), such as dendritic cells and macrophages. Some white pulp macrophages are of a special type called metallolipid macrophages.

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It will take approximately 7.12 days for a culture with a doubling time of 934 minutes to grow from 15 cells/mL to 86,059 cells/mL. This is calculated using the exponential growth equation and logarithms.

If the doubling time is 934 minutes, it means that the number of cells in the culture doubles every 934 minutes. Let t be the time in minutes required to grow from 15 cells/mL to 86,059 cells/mL. We can set up the following equation:

86,059/15 = 2^(t/934)

Taking the logarithm of both sides, we get:

log(86,059/15) = (t/934) log(2)

Solving for t, we get:

t = (log(86,059/15)/log(2)) * 934 ≈ 10,288 minutes ≈ 7.12 days

Therefore, it will take approximately 7.12 days for the culture to grow from 15 cells/mL to 86,059 cells/mL under the given conditions.

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The area of the rectangle is 6272 mm² (to three significant figures).

Area is a physical quantity that refers to the amount of space within a two-dimensional shape or surface. It is typically measured in square units such as square meters, square centimeters, or square feet.

Radius is a measure of the distance from the center of a circle to any point on its circumference. It is often denoted by the letter "r" and is usually expressed in units of length, such as meters or millimeters.

In the given question,

We can start by drawing lines connecting the centers of the circles and the rectangle.

Let's call the width of the rectangle "w" and the height of the rectangle "h".

Since each circle touches the side of the rectangle, we know that the diameter of each circle is equal to the width of the rectangle, so:

diameter of each circle = radius of each circle = 28 mm

Therefore, we can write:

2 x 28 mm + w + w = h

Simplifying, we get:

w + 56 mm = h/22w + 56 mm = h

Now we can find the area of the rectangle by multiplying its width and height:

Area of rectangle = w x h

Substituting for "h", we get:

Area of rectangle = w x (2w + 56 mm)

Expanding and simplifying, we get:

Area of rectangle = 2w² + 56w mm²

To find the value of "w", we can use the fact that the radius of each circle is 28 mm and the circles touch each other, so:

w + 2 x 28 mm + w = 3 x diameter of each circle

Simplifying, we get:

2w + 56 mm = 3 x 2 x 28 mm

2w + 56 mm = 168 mm

2w = 112 mmw = 56 mm

Now we can substitute this value of "w" into the formula for the area of the rectangle:

Area of rectangle = 2w² + 56w mm²

Area of rectangle = 2 x (56 mm)² + 56 mm x 56 mm

Area of rectangle = 6272 mm²

Therefore, the area of the rectangle is 6272 mm² (to three significant figures).

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The required probability of W being greater than 6 is 0.065 or 6.5%.

A probability value represents the likelihood that an occurrence will take place. In terms of percentage notation, it is stated as a number between 0 and 1, or between 0% and 100%. The higher the probability, the more probable it is that the event will take place.

The complement of an event A is the event that A does not occur. In this case, the event A is "W ≤ 6", and its complement is "W > 6".

We are given that P(W ≤ 6) = 0.935. Using the complement rule of probability, we can find the probability of W > 6 as follows:

[tex]$$P(W > 6) = 1 - P(W \leq 6)$$[/tex]

Substituting the given value, we have:

P(W > 6) = 1 - 0.935 = 0.065

Therefore, the probability of W being greater than 6 is 0.065 or 6.5%.

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In the diagram given IJK≅LJK ,the length cannot be negative, the only valid solution is g = 6. Therefore, the length of the segment KJ is 6 meters.

Length is a physical dimension that measures the distance between two points or the size of an object along one dimension.

It is commonly measured using standard units of length such as meters, feet, inches, and centimeters.

Given that KM is the bisector line of line IM and J is the bisector point on line IL. Two triangles are formed, △IJK and △LJK, on line IL in the upward and downward direction, respectively. We are given the lengths of IK, JN, LM, and KJ, and we need to find the value of g such that IJK≅LJK.

Since the two triangles are similar, their corresponding sides are proportional. Using the side proportionality theorem, we have:

KJ/LM = IJ/JL

Substituting the given values, we get:

g/10 = 5/(4+g)

Cross-multiplying, we get:

g(4+g) = 50

Expanding and simplifying, we get:

g²+ 4g - 50 = 0

Using the quadratic formula, we get:

g = (-4 ± √(4² + 4(50)))/2

g = (-4 ± √(256))/2

g = (-4 ± 16)/2

g = -10 or g = 6

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In the figure below, YE bisects ZFYD. Use the figure to answer are  mZEYF.

Figure is a page in a book, magazine, website, or other printed material that contains a graphical representation of data, such as a chart, diagram, drawing, or photograph. Figures are often used to help explain complex concepts or to present data in an easily digestible way. Figures can also be used to highlight important information or to make an argument more visually appealing.

The angle YEZ is an inscribed angle, and it bisects the central angle ZFYD. Therefore, the measure of angle YEZ is equal to one-half the measure of angle ZFYD, which is mZYEF. Thus, mZEYF = mZYEF.

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Intersect Combining these two facts, we get mZCFR + mZRFY = 2mZEYF, which simplifies to m2FYD.

Intersect is a cloud-based platform that enables users to analyze, explore, and visualize data. It provides a variety of tools for data analysis, including interactive dashboards, real-time analytics, and data exploration. Intersect also offers features such as data preparation, data visualization, and machine learning capabilities to help users better understand their data. It can be used to analyze large datasets, uncover trends, and identify correlations.

We can use the fact that when two lines intersect, the opposite angles formed are equal. Therefore, we can say that mZCFR = mZRFY.

In addition, since YE bisects ZFYD, we can say that mZFYD = 2mZEYF.

Combining these two facts, we get mZCFR + mZRFY = 2mZEYF, which simplifies to m2FYD.

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Answer:

1. cosine

2. function

3. tangent

4. complementary

5. sine

6. cofunctions

v = u1 - 2u2 + u3 This means that v can be expressed as a linear combination of u1, u2, and u3. Specifically, we can take one copy of u1, subtract two copies of u2, and add one copy of u3 to obtain v.

To write v as a linear combination of u1, u2, and u3, we need to find constants a, b, and c such that v = au1 + bu2 + c*u3.

We can set up a system of equations to solve for these constants:

3a - b - 2c = -1

2a - 3b + c = 7

8a - b - 3c = 2

We can solve this system using row reduction, which yields:

a = 1

b = -2

c = 1

Therefore, we have:

v = u1 - 2u2 + u3

This means that v can be expressed as a linear combination of u1, u2, and u3. Specifically, we can take one copy of u1, subtract two copies of u2, and add one copy of u3 to obtain v.

It's worth noting that not every vector can be expressed as a linear combination of a given set of vectors. However, in this case, we were able to find constants that satisfy the equation v = au1 + bu2 + c*u3, so it is possible to write v as a linear combination of u1, u2, and u3.

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The total number of miles from Sharon's house to her mother's house would be = 60 miles.

The total amount of time it takes Sharon to reach the mother's house at constant speed = 180 minutes

The speed she used after the storm = 20 mile/hr

Therefore the miles she needs to cover before she reaches the mother's house = ?

That is;

20 miles = 1hr or 60 mins

X miles = 180 minutes

make X the subject of formula;

X miles = 20×180/60

= 3600/60

= 60 miles.

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Here's a graph of the cost function C = 25000p / (100 - p), using graphing utility. The graph shows that the cost function is continuous and defined for all values in its domain.

The domain of the function is restricted to 0 ≤ p ≤ 100, since it doesn't make sense to supply recycling bins to more than 100% of the population, or to a negative percentage of the population.

As p approaches 100%, the cost of supplying recycling bins becomes very large, since it becomes increasingly expensive to provide bins to a large portion of the population. As p approaches 0%, the cost also approaches 0, since there are fewer bins needed for a smaller population.

The function has a vertical asymptote at p = 100, since the denominator of the fraction approaches 0 as p approaches 100 from the left. This means that the cost becomes infinitely large as the percentage of the population approaches 100%.

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Answer:

Step-by-step explanation:

7x - 2 = 5x + 14

2x - 2 = 14

2x = 16

x = 8

The quοtient is [tex]6x^2 - 8xy + 17y^2 - 34y + 70[/tex], and the remainder is [tex]8y^3 - 40.[/tex]

A polynomial is a mathematical expression made up of variables (like x, y, and z) and coefficients (constants multiplied by the variables), as well as addition, subtraction, and multiplication operators. The variables and coefficients are raised to n-negative integer powers, also known as degrees.

We can use long division to divide fractions. Divide 6x³ + 4xy² + 3y³ + 13xy + 8 by x + 2 as shown:

        [tex]6x^2 - 8xy + 17y^2 - 34y + 70[/tex]

  -------------------------------------

[tex]x + 2 | 6x^3 + 4xy^2 + 3y^3 + 13xy + 8[/tex]

       [tex]- 6x^3 - 12x^2[/tex]

       ---------------

           [tex]12x^2 + 4xy^2[/tex]

            [tex]- 12x^2 - 24x[/tex]

            --------------

                    [tex]4xy^2 + 24x[/tex]

                    [tex]- 4xy^2 - 8y^3[/tex]

                    --------------

                              [tex]24x - 8y^3 + 8[/tex]

                              [tex]- 24x - 48[/tex]

                              ------------

                                       [tex]8y^3 - 40[/tex]

Therefοre, the quοtient is [tex]6x^2 - 8xy + 17y^2 - 34y + 70[/tex], and the remainder is [tex]8y^3 - 40[/tex].

Thus, we can express the οriginal pοlynοmial as:

[tex]6x^3+4xy^2+3y^3+13xy+8[/tex]

[tex]= (x + 2)(6x^2 - 8xy + 17y^2 - 34y + 70) + (8y^3 - 40) \div (x + 2)[/tex]

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The radioactive decay will take approximately 3,051 years for 37 grams of the substance to remain.

What is radioactive decay ?

Radioactive decay is the process by which an unstable atomic nucleus loses energy (in terms of mass in its rest frame) by emitting ionizing particles or radiation such as alpha particles, beta particles, gamma rays, or positrons. As a result of this decay, the nucleus may transform into a different nuclide or isotope with a different number of protons or neutrons or into a different energy state. The rate of decay of a radioactive substance is measured by its half-life, which is the amount of time it takes for half of the original amount of the substance to decay.

According to the question:
The half-life formula for radioactive decay is:

[tex]N = N0 (1/2)^{t/h}[/tex]

where N is the amount of substance remaining after time t, N0 is the initial amount of substance, h is the half-life, and t is the time elapsed.

We can use this formula to find the time it takes for 37 grams of the substance to remain. Let N0 be the initial amount of substance, which is 128 g, and N be the amount of substance remaining, which is 37 g. We know the half-life is 1,250 years. Let's plug in these values and solve for t:

[tex]37 = 128 (1/2)^{t/1250}[/tex]

Dividing both sides by 128, we get:

[tex](1/2)^{t/1250} = 37/128[/tex]

Taking the logarithm of both sides with base 1/2, we get:

t/1250 = log(37/128) / log(1/2)

Simplifying, we get:

t = 1250 log(128/37) / log(1/2)

t ≈ 3,051 years

Therefore, it will take approximately 3,051 years for 37 grams of the substance to remain.

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Answer:

7,560 inches.

Step-by-step explanation:

Given: 7 in x 3 in x 6 in x 4 in x 15 in = ?

First, multiply 7 and 3:

21 in x 6 in x 4 in x 15 in

Then multiply 21 and 6:

126 in x 4 in x 15 in

Then multiply 4 and 15:

126 in x 60 in

Finally, multiply 126 and 60:

= 7,560 inches.