The volume of the solid is 72π. of the x-axis, the volume of the solid is 72π of y axis, the volume of the solid is 192π of the line x=6 and the volume of the solid is 99π of the line x=9.
(a) Spinning the locale about the x-hub will make a strong with a round and hollow shape. The volume of the strong can be tracked down utilizing the equation:
[tex]V = ∫[a,b] πy^2 dx[/tex]
where an and b are the x-directions of the marks of convergence of the bends y=x and y=0.
The convergence focuses are (0,0) and (6,6). In this way, the restrictions of coordination are 0 and 6.
V = [tex]V = ∫[a,b] πy^2 dx[/tex]
=[tex]π(6^3)/3[/tex]
= 72π
The volume of the strong is 72π.
(b) Spinning the locale about the y-hub will make a strong with a round and hollow shape. The volume of the strong can be tracked down utilizing the equation:
V = [tex]∫[a,b] πx^2 dy[/tex]
where an and b are the y-directions of the marks of convergence of the bends y=x and y=0.
The convergence focuses are (0,0) and (6,6). In this way, the restrictions of coordination are 0 and 6.
V = [tex]∫[0,6] πy^2 dy[/tex]
= [tex]π(6^3)/3[/tex]
= 72π
The volume of the strong is 72π.
(c) Rotating the district about the line x=6 will make a strong with a washer shape. The volume of the strong can be tracked down utilizing the recipe:
V = [tex]∫[a,b] π(R^2 - r^2) dx[/tex]
where an and b are the x-directions of the marks of convergence of the bends y=x and y=0, R is the separation from the line of upheaval to the external edge of the strong (y=x), and r is the separation from the line of transformation to the internal edge of the strong (y=0).
The convergence focuses are (0,0) and (6,6). R=6 and r=0, since the strong stretches out from the line of insurgency to the bend y=x.
V =[tex]∫[0,6] π(6^2 - x^2) dx[/tex]
= [tex]π(6^3 - 2(6^3)/3)[/tex]
= 32π(6)
The volume of the strong is 192π.
(d) Rotating the locale about the line x=9 will make a strong with a washer shape. The volume of the strong can be tracked down utilizing the recipe:
V =[tex]∫[a,b] π(R^2 - r^2) dx[/tex]
where an and b are the x-directions of the marks of convergence of the bends y=x and y=0, R is the separation from the line of upheaval to the external edge of the strong (y=x), and r is the separation from the line of transformation to the internal edge of the strong (y=0).
The convergence focuses are (0,0) and (6,6). R=3, since the separation from the line x=9 to the bend y=x is 3 units. r=0, since the strong reaches out from the line of transformation to the bend y=x.
V = [tex]∫[0,6] π(3^2 - x^2) dx[/tex]
= [tex]π(3^3 - 2(6^2)(3) + 6^3/3)[/tex]
= 18π(6) - 27π
= 99π
The volume of the strong is 99π.
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at 12/31 accounting records of Gordon Inc contain
AP $2500, Building $31250, Land $30,000, Notes Payable $ ?, Retained earnings
$125,000, AR $18750, Cash ?, Equipment $40,000, Captial Stock $12500
If the cash balance at 12/31 is $67,500 The notes payable balance is
To find the Notes Payable balance, we need to use the accounting equation:
Assets = Liabilities + Equity
We are given the following information:
AP = $2,500
Building = $31,250
Land = $30,000
Notes Payable = ?
Retained Earnings = $125,000
AR = $18,750
Cash = $67,500
Equipment = $40,000
Capital Stock = $12,500
We can add up the assets to get:
Assets = AP + Building + Land + AR + Cash + Equipment
= $2,500 + $31,250 + $30,000 + $18,750 + $67,500 + $40,000
= $190,000
We can rearrange the accounting equation to solve for liabilities:
Liabilities = Assets - Equity
Plugging in the values we have:
Liabilities = $190,000 - ($125,000 + $12,500)
= $190,000 - $137,500
= $52,500
Therefore, the Notes Payable balance is:
Notes Payable = Liabilities - AP
= $52,500 - $2,500
= $50,000
Richard used a radius measure of a circle to be 3.6 inches when he calculated the area of a circle. The correct radius measure was actually 3.5 inches. What is the difference between Richard’s measured area of the circle and the actual area of the circle?
a. 0.1π square inches
b. 0.71π square inches
c. π square inches
d. 0 square inches
e. 2.4 square inches
As a result, the answer is (e) 2.4 square inches, which is the difference between Richard's measured and real circle area.
What is area?In mathematics, area is a measure of the amount of space occupied by a two-dimensional object, such as a rectangle, triangle, circle, or any other shape. It's a scalar quantity that describes the size of a region in two-dimensional space. The units of area are typically square units, such as square inches, square centimeters, square meters, etc. In general, the area of a shape is a measure of how much space it occupies, and it is an important concept in geometry, engineering, and many other fields.
Here,
The formula for the area of a circle is given by:
A = πr²
Where r is the radius of the circle.
Using the incorrect radius of 3.6 inches, the calculated area would be:
A = π * (3.6 inches)² = 40.44 square inches
Using the correct radius of 3.5 inches, the actual area would be:
A = π * (3.5 inches)² = 38.5 square inches
So, the difference between Richard's measured area of the circle and the actual area of the circle would be:
40.44 square inches - 38.5 square inches = 1.94 square inches
Therefore, the answer is (e) 2.4 square inches that is the difference between Richard’s measured area of the circle and the actual area of the circle.
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7. a certain college graduate borrows $8000 to buy a car. the lender charges interest at an annual rate of 10%. assuming that interest is compounded continuously and that the borrower makes payments continuously at a constant annual rate k, determine the payment rate k that is required to pay off the loan in 3 years. a
The payment rate that is required to pay off the loan in 3 years is $3139.88 per year. The borrower will pay approximately $1695.64 in interest over the 3-year period.
The differential equation that models this situation is:
dy/dt = 0.10y - k
where y(t) is the amount owed at time t, 0.10 is the annual interest rate, and k is the annual payment rate. The initial condition is y(0) = $8000.
The first term on the right-hand side represents the interest that accumulates on the loan, and the second term represents the payments made by the borrower.
To determine the payment rate k that is required to pay off the loan in 3 years, we need to solve the differential equation with the initial condition y(0) = $8000 and the terminal condition y(3) = 0.
The general solution to the differential equation is:
y(t) = (8000/k) e^(0.10t) - (8000/k)
Setting t = 3 and y(3) = 0, we get:
0 = (8000/k) e^(0.30) - (8000/k)
Solving for k, we get:
k = 3139.88
Therefore, the payment rate that is required to pay off the loan in 3 years is $3139.88 per year.
To determine how much interest is paid during the 3-year period, we can integrate the interest rate over the time interval [0, 3]:
∫[0,3] 0.10y(t) dt = ∫[0,3] 0.10[(8000/k) e^(0.10t) - (8000/k)] dt
= (8000/k) [e^(0.30) - 1] - 2400
Substituting k = 3139.88, we get:
∫[0,3] 0.10y(t) dt ≈ $1695.64
Therefore, the borrower will pay approximately $1695.64 in interest over the 3-year period.
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____The given question is incomplete, the complete question is given below:
A certain college graduate borrows $8000 to buy a car. The lender charges interest at an annual rate of 10%. Assume that interest is compounded continuously and that the borrower makes payments continuously at a constant annual rate k. (a) Write a differential equation that models this situation, including the initial condi- tion. (b) Determine the payment rate k that is required to pay off the loan in 3 years. (c) Determine how much interest is paid during the 3-year period.
If Fn denotes the nth Fibonacci number, describe the quotients and remainders in the Euclidean Algorithm for gcd(Fn+1, Fn).
The remainder when Fn+1 is divided by Fn is Fn-1, and the remainder when Fn is divided by Fn-1 is Fn-2.
Let's denote the greatest common divisor of Fn+1 and Fn as d. We can use the Euclidean Algorithm to find d by repeatedly taking remainders.
First, we have:
Fn+1 = 1*Fn + Fn-1
So, the remainder when Fn+1 is divided by Fn is Fn-1.
Next, we have:
Fn = 1*Fn-1 + Fn-2
So, the remainder when Fn is divided by Fn-1 is Fn-2.
We can continue this process by repeatedly dividing the larger number by the smaller number and taking remainders until we reach a remainder of 0. The last nonzero remainder we obtain is the greatest common divisor of Fn+1 and Fn.
For example, to find the greatest common divisor of F6 = 8 and F7 = 13, we have:
F7 = 1F6 + F5, so the remainder is F5 = 5
F6 = 1F5 + F4, so the remainder is F4 = 3
F5 = 1F4 + F3, so the remainder is F3 = 2
F4 = 1F3 + F2, so the remainder is F2 = 1
F3 = 2*F2 + 0, so we stop here
Therefore, the greatest common divisor of F7 and F6 is d = 1, and the remainders in the Euclidean Algorithm are 5, 3, 2, and 1.
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Solve the formula for h.
S =6pi squared +5pi x r
squared
Therefore, the formula for h, given the assumption that the formula is for the surface area of a cylinder, is: h = 3πr/2 + 3πr²/4.
What is equation?An equation is a mathematical statement that two expressions are equal to each other. It contains an equals sign (=) between two expressions, with one on each side. An equation can be used to describe a relationship between variables, to solve problems, or to represent a mathematical model. Equations can also be more complex and involve multiple variables and operations, such as the quadratic equation: ax² + bx + c = 0, where a, b, and c are constants and x is the variable. Solving equations is an important part of mathematics and many other fields of study, as it allows us to find solutions to problems and to model and understand real-world phenomena.
Here,
The given formula is:
S = 6π² + 5πr²
To solve for h, we need an equation that relates h to S and r. However, there is no h in the given formula. So either the formula is incomplete or we have to assume some relationship between h, S, and r.
If we assume that the formula is for the surface area of a cylinder, then we can relate h to S and r using the formula for the lateral surface area of a cylinder:
L = 2πrh
where L is the lateral surface area, h is the height, and r is the radius.
The total surface area S of a cylinder can be found by adding the area of the two circular bases (2πr²) to the lateral surface area:
S = 2πr² + L
S = 2πr² + 2πrh (substituting L with 2πrh)
Now we can rearrange this formula to solve for h:
S - 2πr² = 2πrh
h = (S - 2πr²) / (2πr)
Substituting the given value of S:
h = (6π² + 5πr² - 2πr²) / (2πr)
h = (6π² + 3πr²) / (2πr)
h = 3πr/2 + 3πr²/4
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Consider the following parametric equation.
a. Eliminate the parameter to obtain an equation in x and y.
b. Describe the curve and indicate the positive orientation.
x=−10cos2t, y=−10sin2t; 0≤t≤π
a. Eliminating the parameter yields the equation [tex]x2+y2=100[/tex], which is a circle centered at the origin with a radius of 10.
b. The curve is a circle with a positive orientation, going counterclockwise from the origin.
a. To eliminate the parameter, we first square both sides of the equations to obtain: [tex]x2=(−10cos2t)2 and y2=(−10sin2t)2.[/tex]Then, since cos2t and sin2t are both between -1 and 1, the terms on the right hand side of each equation can be simplified to 100. Thus, the equation [tex]x2+y2=100[/tex]is obtained.
b. This equation describes a circle centered at the origin with a radius of 10. The positive orientation of the curve is counterclockwise from the origin, i.e. it starts at the origin and moves up, then to the right, then down, and then to the left.
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Determine each product. a. (x-2) (3x+5)
Answer:
3x^2 - x - 10
Step-by-step explanation:
Foil (First, outside, inside, last)
3x^2 + 5x + -6x - 10
combine like terms
3x^2 - x - 10
Prove the second part of Theorem 6: Let w be any solution of Ax = b, and define vh = w - p. Show that vh is a solution of Ax = 0. This shows that every solution of Ax = b has the form w = p + vh with p a particular solution of Ax = b and vh a solution of Ax = 0.
The second part of Theorem 6 states that if w is any solution of the linear system Ax=b, and p is a particular solution of Ax=b, then the difference vector v=h−p is a solution of the homogeneous system Ax=0.
We will now prove this statement.
Since p is a particular solution of Ax=b, we have A*p = b. Then we can write w = p + v, where v = w - p.
To show that v is a solution of Ax=0, we need to show that Av=0.
We have:
Av = A(w-p) = Aw - Ap
Since Aw = b (by the assumption that w is a solution of Ax=b) and Ap = b (by the assumption that p is a particular solution of Ax=b), we can simplify this to:
A*v = b - b = 0
Thus, v is a solution of Ax=0, as required.
Therefore, every solution of Ax=b has the form w=p+v, where p is a particular solution of Ax=b and v is a solution of Ax=0.
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If angle C and angle E are opposite angles of parallelogram CDEF, then they are supplementary.
true or false
Answer:
False
Step-by-step explanation:
This is because the opposite angles would be congruent, or equal.
I hope this helps! :)
Create a scatter plot with the data. What is the correlation of this scatter
plot?
The solution is given below.
What is scatter plot?A scatter plot is a type of plot or mathematical diagram using Cartesian coordinates to display values for typically two variables for a set of data. If the points are coded, one additional variable can be displayed.
here, we have,
A scatter plot is a graph in which the values of two variables are plotted along two axes. Every data of the table is the coordinate of a point in the plot. To make a scatter plot, first assign a variable to x-axis and the other variable to y-axis, in this question speed was assigned to x-axis and distance was assigned to y-axis. And then, locate the points as coordinates, for example, the first point is (2, 5).
See picture attached.
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A customer bought an item for N$640 and paid N$160 down with an agreement to pay the balance plus a charge fee of N$16 in three months. Find the simple interest rate at which the customer was paying for the item.
The simple interest rate for the item is 13 1/3%.
What is the simple interest rate?
Simple interest is the charge on borrowing calculated as a linear function of the amount borrowed, time and the interest rate.
Interest rate = interest / (time x amount borrowed)
Interest = N$16time = 3/12 = 0.25 Amount borrowed = N$640 - N$160 = N$480Interest rate = N$16 / (N$480 x 0.25)
= 0.13333 = 13 1/3 %
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For each value of w, determine whether it is a solution to 2w-1 < -13. pls answer fast
A. -9 B. -6 C. 6 D. 9
The required inequality of the solutions of the given equation is (-∞, -6).
What is inequality?The idea of inequality, which is the state of not being equal, especially in terms of status, rights, and opportunities, is at the core of social justice theories. However, because it frequently has diverse meanings to different people, it is prone to misunderstanding in public discourse.
According to question:We have;
2w-1 < -13
2w < -13 + 1
2w < - 12
w < -6
Thus, required inequality of the solutions of the given equation is (-∞, -6)
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find all numbers whose absolute value is -4
All absolute values are greater than or equal to zero so there is no such absolute value of - 4.
What is an absolute value function?We know the absolute value function of the modulus function always outputs a positive value irrespective of the sign of the input.
In piecewise terms | x | = x for x ≥ 0 and | x | = - x for x < 0.
We know, |a| = a, |- a| = a, and |0| is 0 therefore, The least possible value of a modulus is zero.
Therefore, There is no such numbers whose modulus value is - 4.
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Find the component form and magnitude of the vector v with the given initial and terminal points. Then find a unit vector in the direction of v.
Initial point:
(1, 6, 0)
Terminal point:
(4, 1, 6)
The component form of the vector is <3, -5, 6>, the magnitude of the vector is √70, then the unit vector is <0.386, -0.643, 0.643>.
The initial and terminal points to find the component form of the vector, calculated its magnitude, and then divided the component form by the magnitude to find a unit vector in the direction of v.
To find the component form of the vector, you can subtract the coordinates of the initial point from the coordinates of the terminal point. In this case, we have:
v = (4, 1, 6) - (1, 6, 0)
v = (3, -5, 6)
So the component form of the vector is v = <3, -5, 6>.
To find the magnitude of the vector, we can use the formula:
|v| = √(3² + (-5)² + 6²)
|v| = √70
Therefore, the magnitude of the vector is √70.
Finally, to find a unit vector in the direction of v, we can divide the component form of v by its magnitude:
u = v/|v|
u = <3/√70, -5/√70, 6/√70>
So the unit vector in the direction of v is u = <0.386, -0.643, 0.643>.
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Please help me answer this question ASAP!!
Answer:
let the Becky's age be x
21=3x
x = 7
Answer:
a = 21 / 3
Step-by-step explanation:
If he's 3 times older than her, then you divide by 3.
At a small part consisting of 10 men and 12 women, 2 door prizes were awarded. find the probability that both prizes were won by two people of the same sex. assume that the ticket is not replaced after the first draw.
The probability that both prizes were won by two people of the same sex is 0.48
Let's call the number of men in the small party "m" and the number of women in the small party "w". The total number of people in the party is "m + w = 10 + 12 = 22".
The number of ways to choose two people of the same sex can be calculated as follows:
The number of ways to choose two men is "C(m,2) = C(10,2) = 45".
The number of ways to choose two women is "C(w,2) = C(12,2) = 66".
The total number of ways to choose two people without replacement is "C(22,2) = 231".
The probability that both prizes were won by two people of the same sex is then given by the sum of the probabilities for two men or two women:
P(same sex) = (C(10,2) / C(22,2)) + (C(12,2) / C(22,2)) = (45/231) + (66/231) = 111/231 = approx. 0.48
So, the probability that both prizes were won by two people of the same sex is approximately 0.48
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A fluctuating electric current I may be considered a uniformly distributed random variable over the interval (9, 11). If this current flows through a 2-ohm resistor, find the probability density function of the power P = 2I 2.
The Probability density function for the power P is f(P) = 1/2 * (1/P) for 162 < P < 242.
The power P is equal to 2I^2, so we can find the probability density function of P by finding the distribution of I first. A uniformly distributed random variable X over an interval (a, b) has a probability density function given by:
f(x) = 1/(b - a) for a < x < b
Since I is uniformly distributed over (9, 11), its probability density function is:
f(I) = 1/(11 - 9) = 1/2
Now, to find the distribution of P, we can use the transformation function P = 2I^2:
f(P) = f(I) * |dI/dP|
Using the chain rule, we have:
dI/dP = dI/d(2I^2) * d(2I^2)/dP = 1/2 * (2I) = I/P
So:
f(P) = f(I) * (1/P) = 1/2 * (1/P)
Now, we need to find the bounds for P. The power P can be calculated for any value of I between 9 and 11, so the bounds for P are:
P_min = 2 * 9^2 = 162
P_max = 2 * 11^2 = 242
Therefore, the probability density function for the power P is:
f(P) = 1/2 * (1/P) for 162 < P < 242
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____The given question is incomplete, complete question is given below:
A fluctuating electric current I may be considered a uniformly distributed random variable over the interval (9, 11). If this current flows through a 2-ohm resistor, find the probability density function of the power P = 2I^2.
Consider a 1 x n checkerboard (1 by n). The squares of the checkerboard are to be painted white and gold, but no two consecutive squares may both be painted white. Let p(n) denote the number of ways to paint the checkerboard subject to this rule (restriction).
Find a recursive formula for p(n) valid for n>=3.
The recursive formula for p(n) is; p(n) = p(n-2) + p(n-3) for n >= 3. Case 1: The last square is painted white. If the last square is painted white, then the second to last square must be painted gold.
There are p(n-2) ways to paint the remaining n-2 squares of the checkerboard subject to the restriction.
Case 2: The last square is painted gold. If the last square is painted gold, then the second to last square can be painted either white or gold. If the second to last square is painted white, then there are p(n-3) ways to paint the remaining n-3 squares of the checkerboard subject to the restriction.
If the second to last square is painted gold, then there are p(n-2) ways to paint the remaining n-2 squares of the checkerboard subject to the restriction.
Therefore, the recursive formula for p(n) is: p(n) = p(n-2) + p(n-3) for n >= 3
with initial conditions p(1) = 2 and p(2) = 3.
The base case for the recursion is p(1) = 2 and p(2) = 3, which are the number of ways to paint a 1 x 1 checkerboard and a 1 x 2 checkerboard subject to the restriction, respectively.
The recursive formula counts the number of ways to paint a 1 x n checkerboard subject to the restriction by considering the last column of the checkerboard.
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Find the perimeter and the
area of this triangle
18.5cm
8.5cm
4cm
Answer:
Perimeter: 31 cm
Step-by-step explanation:
18.5 + 8.5 + 4 = 31 cm.
Can you send a picture of the math problem?
In 2000, a forest covered an area of 1500 km². Since then, this area has decreased by 6.25% each year.
Lett be the number of years since 2000. Let y be the area that the forest covers in km².
Write an exponential function showing the relationship between y and t.
The relationship between y and t can be modeled by an exponential function of the form:
y = a x e^(-rt)
What are exponential functions?An exponential function is a mathematical function which we write as a
f(x) = aˣ, where a is constant and x is variable term. The most commonly used exponential function is eˣ , where e is constant having value 2.7182
The relationship between y and t can be modeled by an exponential function of the form:
y = a x e^(-rt)
where a is the initial area of the forest (1500 km²), r is the rate of decrease (6.25%), and t is the number of years since 2000.
To find the value of r, we can convert 6.25% to a decimal:
r = 0.0625
Now we can plug in the values for a and r into our exponential function:
y = 1500 x e^(-0.0625t)
This exponential function shows the relationship between the area of the forest and the number of years since 2000.
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Estimate the mean of the number of homework problems completed by students in an hour given in the following grouped frequency table. • Round the final answer to one decimal place. (Please do not include the units in your answer.) Value Interval Frequency 3 3-6. 7-10 11-14 15-18 Provide your answer below: mean estimate QUESTION 21 . 1 POINT QUESTION 21 · 1 POINT A Trial best fits which of the following descriptions? Select the correct answer below: O a subset of the set of all outcomes of an experiment O one specific execution of an experiment O a planned activity carried out under controlled conditions a particular result of an experiment QUESTION 22.1 POINT If A and B are independent events, P(A) = 0.13, and P(B) = 0.72, what is P(BA)? Provide your answer below:
Let's denote the midpoint of each value interval by x and the frequency by f. Then the estimated mean is given by:
(mean) = (Σxf) / (Σf)
where the summation is taken over all value intervals.
Using the provided grouped frequency table, we can calculate the estimated mean as follows:
Midpoint (x) Frequency (f) xf
4.5 12 54
8.5 18 153
12.5 24 300
16.5 14 231
Total 68 738
The sum of the xf column is 738, and the sum of the f column is 68. Therefore, the estimated mean is:
(mean) = (Σxf) / (Σf) = 738 / 68 ≈ 10.85
Answer to Question 22:
Since A and B are independent events, we have:
P(B|A) = P(B)
Also, from the definition of conditional probability, we have:
P(B|A) = P(BA) / P(A)
Solving for P(BA), we get:
P(BA) = P(B) * P(A) = 0.13 * 0.72 = 0.0936
Therefore, P(BA) = 0.0936.
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A game manufacturer is designing a pocket travel-edition of one of its top-selling games. The tull-size triangular game board and the proposed travel board are represented below
where ABC-A XYZ and the given side lengths are measured in centimeters
32
52
Which of these are true? Choose all that are comect
The perimeter of the full-size game board is six times the perimeter of the travel-edition game board
The travel-edition side comesponding to the 48-cm side on the tull-size board will measure 13 centimeters.
The travel-edition side comesponding to the 48-cm side on the full-size board will measure 12 centimeters
The three angles represented on the travel-edition board are congruent to their comesponding angles on the full-size board
Based on the given information and measurements, the following statements are true:
What are the true statements?The perimeter of the full-size game board is six times the perimeter of the travel-edition game board: This statement is false. The perimeter of the full-size game board can be calculated as the sum of the lengths of its three sides: AB + BC + AC = 32 + 52 + 52 = 136 cm. The perimeter of the travel-edition game board can be calculated as the sum of the lengths of its three sides: AX + XY + YZ = 13 + 21 + 18 = 52 cm. Therefore, the perimeter of the full-size game board is 2.62 times the perimeter of the travel-edition game board, not 6 times.
The travel-edition side corresponding to the 48-cm side on the full-size board will measure 12 centimeters: This statement is false. The travel-edition side corresponding to the 48-cm side on the full-size board is side XY. The length of XY can be calculated using proportions: XY/48 = YZ/52, which gives XY = 48*18/52 = 16.62 cm (rounded to two decimal places).
The travel-edition side corresponding to the 48-cm side on the travel-edition board will measure 13 centimeters: This statement is true. The travel-edition side corresponding to the 48-cm side on the travel-edition board is side AX, which has a length of 13 cm.
The three angles represented on the travel-edition board are congruent to their corresponding angles on the full-size board: This statement is true. The three angles of a triangle are determined by the lengths of its sides, so if two triangles have the same side lengths, their angles must be congruent as well.
Therefore, the three angles represented on the travel-edition board (at vertices A, X, and Y) are congruent to their corresponding angles on the full-size board (at vertices A, B, and C).
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Ella participated in a race each week for four weeks. She recorded her race times in this chart. What inequality about her race times is true?
Jim has a triangular shelf system that attaches to his showerhead. The total height of the system is 18 inches, and there are three parallel shelves as shown above. What is the maximum height, in inches, of a shampoo bottle that can stand upright on the middle shelf?
To determine the maximum height of a shampoo bottle that can stand upright on the middle shelf, we need to consider the height of the shelf above and below it.
Since there are three shelves, the middle shelf is located at the height of 9 inches (half of the total height).
To find the maximum height of a shampoo bottle that can stand upright on the middle shelf, we need to subtract the height of the middle shelf from the total height of the system, and then divide the result by two, since there are two spaces above and below the middle shelf.
Therefore, the maximum height of a shampoo bottle that can stand upright on the middle shelf is: (18 - 9) / 2 = 4.5 inches
So, the maximum height of a shampoo bottle that can stand upright on the middle shelf is 4.5 inches.
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Find an autonomous differential equation with all of the following properties:
equilibrium solutions at y=0 and y=3,
y' > 0 for 0 y' < 0 for -inf < y < 0 and 3 < y < inf
dy/dx =
The differential equation dy/dt = y(3-y) smug all of the given conditions.
One possible autonomous differential equation with equilibrium solutions at y=0 and y=3, and with y' > 0 for 0 < y < 3 and y' < 0 for -∞ < y < 0 and 3 < y < ∞, is:
dy/dt = y(3-y)
We can see that y=0 and y=3 are equilibrium solutions by setting dy/dt = 0 and solving for y:
dy/dt = y(3-y) = 0
y = 0 or y = 3
To check the sign of y', we can use the derivative of y(3-y) with respect to y: d/dy (y(3-y)) = 3 - 2y
For y < 0, we have y(3-y) < 0, so d/dy (y(3-y)) < 0, which says that y' < 0.
For 0 < y < 3, we have y(3-y) > 0, so d/dy (y(3-y)) > 0, which implies that y' > 0.
For y > 3, we have y(3-y) < 0, so d/dy (y(3-y)) < 0, which implies that y' < 0.
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: A tank is is half full of oil that has a density of 900 kg/m3. Find the work w required to pump the oil out of the spout. (Use 9.8 m/s2 for g. Assume r = 15 m and h = 5 m.) W = h A tank is full of water. Find the work required to pump the water out of the spout. (Use 9.8 m/s2 for g. Use 1000 kg/m3 as the density of water. Assume r = 3 m and h = 1 m.) 3.11.107 X h A tank is full of water. Find the work W required to pump the water out of the spout. (Use 9.8 m/s2 for g. Use 1000 kg/m3 as the weight density of water. Assume that a = 4 m, b = 4 m, c = 9 m, and d = 4 m.) W = 96000 kb
The work required to pump water out of the spout is calculated by multiplying the density of water (1000 kg/m3) by the height of the tank (h) and the area of the spout (a x b x c x d). The acceleration due to gravity (g) is 9.8 m/s2.
1. Calculate the volume of the tank:
V = a x b x c x d = 4 x 4 x 9 x 4 = 576 m3
2. Calculate the mass of the water in the tank:
m = V x density = 576 x 1000 = 576000 kg
3. Calculate the height of the tank:
h = m / density = 576000 / 1000 = 576 m
4. Calculate the work required to pump the water out of the spout:
W = m x g x h = 576000 x 9.8 x 576 = 3.11.107 x 576 = 1.79.107 J
The work required to pump water out of a spout can be calculated by multiplying the density of water (1000 kg/m3) by the height of the tank (h) and the area of the spout (a x b x c x d). The acceleration due to gravity (g) is 9.8 m/s2.To calculate the work, first we need to find the volume of the tank (V) by multiplying the length (a), width (b), height (c), and depth (d). Then we can calculate the mass (m) by multiplying the volume with the density of water. We can then calculate the height of the tank (h) by dividing the mass with the density. Finally, we can calculate the work required (W) by multiplying the mass, acceleration due to gravity, and the height of the tank.
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1. Jonathan's family had a pizza party with their neighbors, and they ordered 7 pizzas.
Everyone ate 1 1/4 pepperoni pizza, 2 3/4 sausage pizza, and 3/4 of the cheese pizza. How
much pizza was leftover after the party?
Answer: 2.25 slices which is 9/4 slices i think im right
Step-by-step explanation:
add 1 1/4+2 3/4+3/4 which makes 4.75 slices or 19/4 slices do 7-4.75=2.25/9/4 slices
given a matrix of non-negative reals, show it is a non-negative linearr combination of permutation matrices
Q is a non-negative linear combination of permutation matrices.
A non-negative linear combination of permutation matrices is a matrix P that can be expressed as a linear combination of permutation matrices P1, P2, ..., Pn such that each coefficient in the linear combination is non-negative. This can be expressed as:
[tex]P = c1P1 + c2P2 + ... + cnPn[/tex]
where c1, c2, ..., cn are all non-negative real numbers. For example, consider the following matrix Q:
[tex]Q = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 1 & 0 \end{bmatrix}[/tex]
We can express Q as a non-negative linear combination of permutation matrices P1, P2, P3 as follows:
[tex]Q = \frac{1}{3}\begin{bmatrix} 0 & 1 & 0 \\ 0 & 0 & 1 \\ 1 & 0 & 0 \end{bmatrix} + \frac{1}{3}\begin{bmatrix} 0 & 0 & 1 \\ 1 & 0 & 0 \\ 0 & 1 & 0 \end{bmatrix} + \frac{1}{3}\begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}[/tex]
Therefore, Q is a non-negative linear combination of permutation matrices.
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for the following system of liner equation: x plus 2 y plus z equals negative 2 3 x plus 3 y minus 2 z equals 2 2 x plus y plus z equals 0 complete the row-echelon form matrix derived from the augmented matrix at the end of the gaussian elimination method. (if it is not a whole number, write the fraction form. for example, if the answer is 0.5, write 1/2) 1 2 1 -2 0 1 5/3 -8/3 0 0 1 -1
The following system of liner equation when converted into equivalent matrix gives us x =2, y = 3, z = -2.
Given that the augmented matrix is [AB] = [tex]\left[\begin{array}{cccc}1&2&2&4\\0&1&-3&9\\0&0&1&-2\end{array}\right][/tex]
Since p(A) = p(AB) = 3 = n = The number of variables
The system has unique solution
x + 2y + 2z = 4
y - 3z = 9
z = -2
y = 9 + 3z = 9 + 3(-2) = 3
x = 4-2y -2z
= 4 -2(3) -2(-2)
= 4 - 6 + 4
= 2
Therefore, the solution is x =2, y = 3, z = -2.
The abecedarian idea is to add multiples of one equation to the others in order to exclude a variable and to continue this process until only one variable is left. Once this final variable is determined, its value is substituted back into the other equations in order to estimate the remaining unknowns. This system, characterized by step ‐ by ‐ step elimination of the variables, is called Gaussian elimination.
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Complete question;
The augmented matrix of a system of equations has been transformed to an equivalent matrix in row-echelon form. Using x, y, and z as variables, write the system of equations corresponding to the following matrix. If the system is consistent, solve it.
left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 2 3rd Column 2 2nd Row 1st Column 0 2nd Column 1 3rd Column negative 3 3rd Row 1st Column 0 2nd Column 0 3rd Column 1 EndMatrix Start 3 By 1 Table 1st Row 1st Column 4 2nd Row 1st Column 9 3rd Row 1st Column negative 2 EndTable right bracket
a monkey presses the keys on a typewriter randomly. suppose the typewriter only contains the 26 letters of the alphabet (no space or other characters), and the monkey chooses the next key to press uniformly at random from the 26 options. suppose the monkey types n letters in total.
The probability of typing any particular sequence of n letters is (1/26)^n. The probability of word of length m (where m ≤ n) is (1/26)^m. The probability of at least one occurrence is 1 - (25/26)^(n-m+1). The number of times the monkey types a specific word of length m is (n-m+1)*(1/26)^m.
Assuming that the monkey's key presses are truly random and independent of each other, the probability of the monkey typing any particular sequence of n letters is (1/26)^n. This is because there are 26 choices for each letter, and the probability of the monkey choosing any particular letter is 1/26.
The probability of the monkey typing a specific word of length m (where m ≤ n) is (1/26)^m. This is because the monkey must type the specific sequence of m letters in order, and each letter has a probability of 1/26 of being typed.
The probability of the monkey typing at least one occurrence of a specific word of length m is 1 - (25/26)^(n-m+1). This is because the monkey has n-m+1 opportunities to type the word, and the probability of missing the word in any one opportunity is 25/26 (since there are 25 other letters that the monkey could type instead).
The expected number of times the monkey types a specific word of length m is (n-m+1)*(1/26)^m. This is the product of the probability of the monkey typing the word in any given opportunity (which is (1/26)^m), and the number of opportunities the monkey has to type the word (which is n-m+1).
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