Five different substances added breakers of water. Each substance begins as a white, solid powder. Which substances do not dissolve in water? Salt,sugar,starch,chalk, and bakeing powder

Answer:

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Answer:

Explanation:

Molarity of NaOAc needed

Using the Henderson-Hasselbalch Equation calculate base molarity needed given [HOAc] = 1.00M and pKa(NaOAc) = 4.75 and [HOAc] = 1.00m.

pH = pKa + log [NaOAc]/[HOAc]

5.00 = 4.75 + log[NaOAc]/[1.00M]

5.00 - 4.75 = log [NaOAc] - log[1.00M]

log [NaOAc] = 0.25 => [NaOAc] = 10⁰·²⁵ M = 1.78

Given 10ml of HOAc, how much (ml) 1.78M NaOAc to obtain a buffer pH of 5.00.

Determine Volume of Base Needed

(M·V)acid = (M·V)base => V(base) = (M·V)acid / (M)base

Vol (NaOAc) needed = (1.00M)(0.010L)/(1.78M) = 0.0056 liter = 5.6 ml.

Checking Results:

5.00 = 4.75 + log [1.78M]/[1.00M] = 4.75 + 0.25 = 5.00    QED.

The volume of 1.00 M sodium acetate solution needed to prepare an acetic/acetate buffer of pH 5.00 using 10.0 mL of 1.00M acetic acid solution is 17.8 mL.

We can find the volume of the acetate solution with the Henderson-Hasselbalch equation:

[tex]pH = pka + log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]})[/tex]   (1)  

Where:

[CH₃COOH] = 1.00 M                      

[CH₃COONa] =?

pH = 5.00

pKa = 4.75

From equation (1), we have:

[tex] log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]}) = pH - pKa [/tex]

[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{pH - pKa} [/tex]

[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{5.00 - 4.75} = 1.78 [/tex]

Now, the volume of the acetate solution is:

[tex]\frac{n_{CH_{3}COONa}/Vt}{n_{CH_{3}COOH}/Vt} = 1.78[/tex]  

Since the total volume is the same, we have:

[tex]\frac{n_{CH_{3}COONa}}{n_{CH_{3}COOH}} = 1.78[/tex]  

[tex] \frac{[CH_{3}COONa]_{i}*V_{b}}{[CH_{3}COOH]_{i}*Va} = 1.78 [/tex]  

Solving for Vb

[tex] Vb = \frac{1.78*[CH_{3}COOH]_{i}*Va}{[CH_{3}COONa]_{i}} = \frac{1.78*1.00M*10.0mL}{1.00 M} = 17.8 mL [/tex]

Therefore, we need to add 17.8 mL of sodium acetate solution.

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Answer:

2)

[tex]\% Mg=20.2\%\\\\\% S=26.6\%\\\\\% O=53.2\%[/tex]

3)

[tex]\% Ag=93.1\%\\\\\% O=6.9\%[/tex]

Explanation:

Hello!

2) In this case, since magnesium sulfate is MgSO₄, we can see how magnesium weights 24.305 g/mol, sulfur 32.06 g/mol and oxygen 64.00 g/mol as there is one atom of magnesium as well as sulfur but four oxygen atoms for a total of g/mol; thus the percent compositions are:

[tex]\% Mg=\frac{24.305}{120.36 } *100\%=20.2\%\\\\\% S=\frac{32.06}{120.36 } *100\%=26.6\%\\\\\% O=\frac{64.00}{120.36 } *100\%=53.2\%[/tex]

3) In this case, although the element seems to contain Ag and O, we infer its molecular formula is Ag₂O; thus, since we have two silver atoms weighing 215.74 g/mol and one oxygen atom weighing 16.00 g/mol for a total of 231.74 g/mol, we obtain the following percent compositions:

[tex]\% Ag=\frac{215.74}{231.74} *100\%=93.1\%\\\\\% O=\frac{16.00}{231.74} *100\%=6.9\%[/tex]

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Answer:

They are symbols of elements.

Ra is the symbol of the element Radium

Ah is the symbol of the element Arrhenium

Ma  is the symbol of the element Molybdenum

Ga  is the symbol of the element Gallium

La  is the symbol of the element Lanthanum

Answer:

Ra is the symbol of the element Radium

Ah is the symbol of the element Arrhenium

Ma  is the symbol of the element Molybdenum

Ga  is the symbol of the element Gallium

La  is the symbol of the element Lanthanum

Explanation:

They are elements

Answer:

a switch

Explanation:

Answer:

a switch is the answer hope it helps

Answer:

Less in the top

your well wisher

Answer:

0.500-Molarity solution

Explanation:

The moles of the compound is given as the number of atomic mass unit in the compound. The moles of potassium nitrate in the solution are 0.6 mol

The molarity is the concentration unit, and it can be defined as the moles of compound present in the liter of solution.

The molarity can be expressed as:

[tex]\rm Molarity=\dfrac{Moles}{Volume(L)}[/tex]

The given potassium nitrate solution has, molarity = 2 M

The volume of the solution is 0.3 L.

Substituting the values for the moles of the compound:

[tex]\rm 2\;M=\dfrac{Moles}{0.3\;L} \\\\Moles=2\;\times\;0.3\;mol\\Moles=0.6\;mol[/tex]

The moles of potassium nitrate in 2 M solution is 0.6 mol.

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Answer: B. It must show that the mass of each element involved is conserved  by a chemical reaction.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The correct statement why a chemical equation must be balanced is It must show that the mass of each element involved is conserved  by a chemical reaction.

Answer:

B. It must show that the mass of each element involved is conserved

by a chemical reaction.

Explanation:

a p e x, just took the quiz

Answer:

0.0103 mol

Explanation:

Step 1: Given data

Step 2: Convert "m" to grams

We will use the conversion factor 1 g = 1000 mg.

200. mg × 1 g/1000 mg = 0.200 g

Step 3: Calculate the moles (n) of naproxen sodium

We will use the following expression.

n = m/M = 0.200 g / (252 g/mol) = 7.94 × 10⁻⁴ mol

Step 4: Calculate the moles of hydrogen in 7.94 × 10⁻⁴ moles of naproxen sodium

According to the chemical formula, the molar ratio of naproxen sodium to H is 1:13. The moles of H are 13/1 × 7.94 × 10⁻⁴ mol = 0.0103 mol.

Answer:

Zn + 2HCl → ZnCl₂ + H₂

Explanation:

First we write the equation using the molecular formulas instead of words:

We know zinc chloride is ZnCl₂ as the problem tells us the oxidation state of zinc in the products is +2, and chloride means Cl⁻¹.

Now we proceed to balance the reaction:

There are 2 Cl atoms and 2 H atoms on the right side, so we add a coefficient of 2 to HCl on the left side:

5.972 × 10^24 kg

hope it helps

Answer:

5.972 × 10^24 kg

hope this helps

Answer:

Gravitational potential energy depends on basically two factor;

Explanation:

The distances between both the bodies, as well as the mass within each object, are factors that influence gravitational potential energy.

Answer: 22.3 *10^23 S atoms

Explanation:

Answer:

1

Explanation:

touching a metal spoon ....................water.

Answer:

[tex]m_{Ag}=135.8gAg[/tex]

[tex]Y=88.4\%[/tex]

Explanation:

Hello there!

In this case, according to the described chemical reaction, it is possible to compute the theoretical mass of silver as mass via the 1:2 mole ratio of copper to silver and their atomic mass in the periodic table, in order to perform the following stoichiometric setup:

[tex]m_{Ag}=40.gCu*\frac{1molCu}{63.55gCu}*\frac{2molAg}{1molCu}*\frac{107.87gAg}{1molAg}\\\\ m_{Ag}=135.8gAg[/tex]

Next, given the actual yield of 120 g, we compute the percent yield via:

[tex]Y=\frac{120g}{135.8g}*100\%\\\\Y=88.4\%[/tex]

Regards!

Explanation:

as the Hydrogen (acid) ion decreases there is a corresponding increase in the Hydroxide (basic) ion.

Answer:

Mole fraction of KCl = 0.4056

Explanation:

We'll begin by calculating the number of mole of each compound. This can be obtained as follow:

For NaCl:

Mass NaCl = 0.564 g

Molar mass of NaCl = 58.44 g/mol

Mole of NaCl =?

Mole = mass /Molar mass

Mole of NaCl = 0.564 / 58.44

Mole of NaCl = 0.0097 mole

For KCl:

Mass KCl = 1.52 g

Molar mass of KCl = 74.55 g/mol

Mole of KCl =?

Mole = mass /Molar mass

Mole of KCl = 1.52 / 74.55

Mole of KCl = 0.0204 mole

For LiCl:

Mass LiCl = 0.857 g

Molar mass of LiCl = 42.39 g/mol

Mole of LiCl =?

Mole = mass /Molar mass

Mole of LiCl = 0.857 / 42.39

Mole of LiCl = 0.0202 mole

Next, we shall determine the total mole in the mixture. This can be obtained as follow:

Mole of NaCl = 0.0097 mole

Mole of KCl = 0.0204 mole

Mole of LiCl = 0.0202 mole

Total mole =?

Total mole = Mole of NaCl + Mole of KCl + Mole of LiCl

Total mole = 0.0097 + 0.0204 + 0.0202

Total mole = 0.0503 mole

Finally, we shall determine the mole fraction of KCl in the mixture. This can be obtained as follow:

Mole of KCl = 0.0204 mole

Total mole = 0.0503 mole

Mole fraction of KCl =?

Mole fraction of KCl = Mole of KCl /Total mole

Mole fraction of KCl = 0.0204 / 0.0503

Mole fraction of KCl = 0.4056

Answer:

.4 is correct

Explanation:

Answer:

2.562

Explanation:

First we convert 127 g of H₂CO₃ to moles, using its molar mass:

Then we convert 800 mL to L:

Finally we can calculate the concentration of the solution as molarity:

Answer:

Joan's hypothesis should make a prediction about the answer to the question. A hypothesis is just an educated guess on what you think the outcome will be on the experiment. The prediction must be testable and stated in if-then form. For example, a good hypothesis for Joan's experiment could be, I think that 1/2 cup of salt will make the water boil quicker, than water without salt.

Explanation:

Hope it helped!

Answer:

4.584*10^23 molecules

Explanation:

Find molar mass of nitrogen and oxygen on periodic table.

find molar mass of nitrogen dioxide

use this to find moles of nitrogen dioxide

multiply by avagadros number

Answer:

The answer is A. Surface currents are caused by wind deep water currents are caused by difference in water density.

Answer:

Explanation: There is no molecule or ion as ClO3. The correct formula of chlorate ion is ClO3-. bolivianouft and 4 more users found this answer helpful.

Explanation:

Answer:

Deer, Eagle, Raccoon, frog, turtle, fish, dragonfly.

Explanation:

They interact from the life cycle they eat each other...

Answer:

c. fluorine

Explanation:

A single replacement reaction is defined as the chemical reaction in which a strong molecule replaces the weak molecule from a compound.

In a single replacement reaction, the chloride ion in NaCl can be replaced     by fluorine and gives Sodium fluoride as fluorine (F) is stronger than chlorine (Cl) and from other given molecules also. So the single replacement reaction between NaCl and F will be:

NaCl + F2 => NaF + Cl2

Hence, the correct answer is "c. fluorine".

Answer:

ΔH = -44.029 KJ/mol

Explanation:

We are told that 60.0 g of NaOH is dissolved in one litre of water.

From conversion, 1 litre = 1000 g

From tables, specific heat capacity of water; c = 4.18 J/g/°C

We are given ΔT = 15.8 °C

Formula for the heat absorbed by the solution is given as;

Q = mcΔT

Where;

Q = Heat gained by the water

m = Mass of the water

c = Specific heat of water

ΔT = change in temperature

Thus;

Q = 1000 × 4.18 × 15.8

Q = 66044 J

The solution absorbed 66044 J and therefore it means that the dissolution of the salt gave off 66044 J.

Thus;

Enthalpy is; ΔH = -66044 J

Now, Mass of NaOH is 60 g.

We know that molar Mass of NaOH is 39.997 g/mol. Thus;

Converting to moles, we have;

n = 60/39.997

n = 1.5 mol

Now, enthalpy when 1.5 moles of NaOH are dissolved in water will be;

ΔH = -66044 J/1.5 moles

ΔH = -44029.33 J/mol

ΔH = -44.029 KJ/mol

Answer:

the second answer choice i think

Explanation: