for general star-forming disk galaxies you can assume a bulk mass-to-light ratio of

By using concave lens, we can correct Myopia and Hyperopia can be corrected by convex lenses.

To find the answer, we need to know about Myopia and Hyperopia.

Thus, we can conclude that, by using concave lens, we can correct Myopia and Hyperopia can be corrected by convex lenses.

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Myopia can be corrected using concave lenses, while the Hyperopia is corrected by convex lenses.

We need to be aware of myopia and hyperopia in order to locate the solution.

Thus, we can deduce that myopia and hyperopia can be corrected using concave lenses and convex lenses, respectively.

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A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 [tex]m^{3}[/tex]/sec .

Discharge rate = velocity * area

                 = velocity * depth * width

                 = 2 * 2 * 10 = 40 [tex]m^{3}[/tex]/sec

A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 [tex]m^{3}[/tex]/sec .

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From counting craters on each asteroids , astronomers have realized that the surface of ida is older than the surface of gaspra.

Ida, and Gaspra are three objects located in the asteroid belt between Mars and Jupiter.

Crater counting is a method for estimating the age of a planet's surface based upon the assumptions that when a piece of planetary surface is new, then it has no impact craters; impact craters accumulate after that at a rate that is assumed known.

Counting how many craters of various sizes there are in a given area allows determining how long they have accumulated and consequently, how long ago the surface has formed. Hence , from counting craters on each asteroids ,astronomers have realized that the surface of ida is older than the surface of gaspra.

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The cause for a molecular cloud forming fragments when it collapses is indicated correctly by option D. density variations from place to place grow larger as the cloud collapses.

Molecular cloud:

A molecular cloud, also known as a stellar nursery, is a specific kind of interstellar cloud, whose density and size allow the development of molecules, absorption nebulae, and H II regions. In contrast, some regions of the interstellar medium mostly consist of ionized gas.

Molecular clouds are cold, dense areas of space where stars form. The cloud collapses into a proto-star when the gravitational force pulling it in outweighs the internal pressure pushing it in.

When a molecular cloud collapses, it is observed that the density varies from place to place with the variation increasing with collapse. As a result, the collapse is characterized by fragmentation of the cloud.

Thus the correct option is: D. density variations from place to place grow larger as the cloud collapses.

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The force needed to give a car of mass 800 kg an acceleration of 2.0 ms-² is 1600N.

The force needed to push an object can be calculated by multiplying the mass of the object by its acceleration as follows:

Force = mass × acceleration

According to this question, a car of mass 800 kg has an acceleration of 2.0 ms−². The force is calculated as follows:

Force = 800kg × 2m/s²

Force = 1600N

Therefore, the force needed to give a car of mass 800 kg an acceleration of 2.0 ms-² is 1600N.

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The acceleration of a body traveling in a circular route is known as centripetal acceleration. The radius of the turn if the falcon will be 19.7 m.

The acceleration of a body traveling in a circular route is known as centripetal acceleration. Because velocity is a vector quantity. It has both a magnitude and a direction.

Given:

a is the centripetal acceleration = 1.5g

v is the velocity = 17 m/sec

To Find:

r is the radius of circular turn = ?

Mathematically centripetal acceleration is given as

a = v^2/r

r = v^2/a. = (17)^2/1.5 x 9.81

r = 19.7 m

Hence the radius of the turn if the falcon will be 19.7 m.

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Answer:

0.19m/s²

Explanation:

Initial velocity(u) = 50×1000/60×60

=13.88 m/s

Final velocity(v) = 36.5×1000/60×60

=10.13 m/s

Acceleration(a) = v-u/t

=10.13-13.88/19.5

a= -0.19m/s²

-a = 0.19m/s²

The magnitude of retar dation is 0.19m/s²

Answer:

[tex]\sf 0.192\:ms^{-2}\:\:(3\:s.f.)[/tex]

Explanation:

Given:

First, convert the velocities into meters per second by dividing by 3.6:

[tex]\implies \sf 50.0\: km h^{-1}=\dfrac{50.0}{3.6}\:ms^{-1}= \dfrac{125}{9}\:ms^{-1}[/tex]

[tex]\implies \sf 36.5\: km h^{-1}=\dfrac{36.5}{3.6}\:ms^{-1}= \dfrac{365}{36}\:ms^{-1}[/tex]

To find the vehicle's acceleration, use one of the constant acceleration equations with the given values:

[tex]\implies \sf v=u+at[/tex]

[tex]\implies \sf \dfrac{365}{36}=\dfrac{125}{9}+19.5a[/tex]

[tex]\implies \sf \dfrac{365}{36}-\dfrac{125}{9}=19.5a[/tex]

[tex]\implies \sf 19.5a=-3.75[/tex]

[tex]\implies \sf a=-\dfrac{3.75}{19.5}[/tex]

[tex]\implies \sf a=-0.1923076923...\:ms^{-2}[/tex]

Therefore, the magnitude of acceleration is:

[tex]\implies \sf |a|=|-0.19230...|=0.192\:ms^{-2}\:\:(3\:s.f.)[/tex]

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The frequency of oscillation is 2.153 Hz

What is the frequency of spring?

Spring Frequency is the natural frequency of spring with a weight at the lower end. Spring is fixed from the upper end and the lower end is free.

For the mass-spring system in this problem,

The Frequency of spring is calculated with the equation:

[tex]f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }[/tex]

Where,

f = frequency of spring

k = spring constant = 64 N/m

m = mass attached to spring = 350g = 0.350 kg

a = maximum acceleration = 5.3 m/s^2

Substituting the values in the equation,

[tex]f = \frac{1}{2\pi } \sqrt{\frac{64}{0.350} }[/tex]

[tex]f = \frac{1}{2\pi } ( 13.522)[/tex]

[tex]f = 2.1535 Hz[/tex]

Hence,

The frequency of oscillation is 2.153 Hz

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After conducting a search directly above the floor of a fire in a high rise building what is your next priority is  that their own safety is the first priority.

What are the three incident priorities?

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The ice melts because Thermal energy from Jan’s hand is transferred to the ice.

Thermal energy is the energy due to temperature difference.

Thermal energy flows from hotter to colder bodies.

The ice Jan is holding melts because heat is transferred from his hands t the ice.

In conclusion, thermal energy flow causes melting.

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Answer:

its b

Explanation:

because the heat from your hand makes the ice melt!

The distance travelled  is 10 m and the velocity gained at the end of this time is 2 m/s.

F = mv/t

where;

Ft = mv

v = Ft/m

v = (50 x 10)/250

v = 2 m/s

v² = u² + 2as

where;

u is initial velocity = 0

a is acceleration

a = F/m

a = 50 N/ 250 kg

a = 0.2 m/s²

v² = 0 + 2as

s = v²/2a

s = (2²)/(2 x 0.2)

s = 10 m

Thus, the distance travelled  is 10 m and the velocity gained at the end of this time is 2 m/s.

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Answer:potential energy

Explanation:

The beat frequency will be 8.1 Hz  when the horns are sounded on a day when the speed of sound is 340 m/s

frequency = speed / wavelength

f1 = 340 / 6 = 56.67 Hz

f2 = 340 / 7 =  48.57 Hz

Beat frequency  = fb = | f2 - f1 |

                                   = | 48.57  - 56.67 |

                                   = 8.1 Hz

The beat frequency will be 8.1 Hz  when the horns are sounded on a day when the speed of sound is 340 m/s

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Answer:

[tex]\huge\boxed{\sf m = 2 \ moles}[/tex]

Explanation:

No. of particles = 12.04 × 10²³ particles

Avogadro's number = 6.02 × 10²³

No. of moles = n = ?

[tex]\displaystyle No. \ of\ moles\ = \frac{no.\ of \ particles}{Avogadro's \ number}[/tex]

Put the given in the above formula

[tex]\displaystyle n =\frac{12.04 \times 10^{23}}{6.02 \times 10^{23}} \\\\n = 2 \times 1 \ moles\\\\m = 2 \ moles\\\\\rule[225]{225}{2}[/tex]

Because starlight cannot pass through black space, we are unable to view all of the stars in the Milky Way galaxy, even with the best and largest telescopes.

In the Milky Way galaxy, the Earth is situated. Part of it can be seen as a broad, opaque ring of stars and dust on a clear night (from sufficiently dark areas). We can see thousands of these stars with our unaided eyes, and a telescope can reveal many more.

However, a large number of the Milky Way's stars are obscured. The supermassive black hole at the centre of the galaxy and the bulge, which is made up of stars, gas, and dust, are to blame for this. The substance in this is opaque to all but the most powerful telescopes.

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Answer:

it is in explanation part

Explanation:

9

7

3

2

5

8

1

11

14

12

13

Answer:  

Explanation:

Answer:

31.43 Ω

Explanation:

Using Ohm's Law:

[tex]\displaystyle{V=IR}[/tex]

Where V = voltage (V) , I = electric current (A) and R = resistance (ohm)

We know that a computer uses 3.5 ampere at 110 volt, we want to know the resistance. Therefore substitute V = 110 and A = 3.5

[tex]\displaystyle{110=3.5R}\\\\\displaystyle{\dfrac{110}{3.5}=R}\\\\\displaystyle{R=31.43}[/tex]

Therefore, the resistance will be around 31.43 Ohm

Answer:

During dry season /Spring

Explanation:

Shearing is the removal of wool from a sheep. When you remove wool from sheep, you subject the sheep to cold since nothing is covering the entire body. Therefore, the most suitable season is during dry periods/ Spring since you won't subjects the sheep to cold but warm environment. Thus important to consider that.

Answer:

the quantity of matter contained in a body is called mass .si unit of mass is kilogram.weight is effected by gravity but mass is not effected by gravity.

Answer:

The quantity of matter contained in a body is called mass .si unit of mass is kilogram.weight is effected by gravity but mass is not effected by gravity.

Explanation:

Atomic radius of this metal is 0.85 x 10^23

Given:

density of metal = 7. 24 g/cm3

metal has the bcc crystal structure

atomic weight = 48. 9 g/mol

To Find:

atomic radius of this metal

Solution: Atomic radius is defined as half the distance between the centers of two neighboring atoms. the atomic radius of a simple cube and hcp is a/2 respectively, whereas it is a√2/4 and a√3/4 for fcc and bcc respectively.

density = Z x M/N• x a^3

a = edge length

Z = 2 atoms = numeber of atoms per unit cell

N• = 6.023 x 10^23 atoms/mol = Avogadro's number

a^3 = density x N•/Z x M

a^3 = 7.24 x 6.023 x 10^23/ 2 x 48. 9

a = 3√0.44 x 10^23

a = 1.98 x 10^23

4R = √3a

R = √3 x 1.98 x 10^23/4

R = 0.85 x 10^23

Atomic radius of this metal is 0.85 x 10^23

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If you lift twice the load twice as high, in half the time then, the increase in potential energy is 4 times that of initial potential energy.

To find the answer, we need to know more about the gravitational potential energy.

                    [tex]m'=2m\\h'=2h[/tex] where, m' and h' are the final mass and height.

                  [tex]U=mgh\\[/tex] , let us take this as the initial energy.

                 [tex]U'=m'gh'=2m*g*2h=4mgh.\\U'=4U[/tex]

Thus, we can conclude that, the final potential energy is 4 times the initial.

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The final potential energy will be 4 times that of the initial, if we are twice the height and load.

To find the answer, we need to study about the gravitational potential energy.

                    [tex]m_f=2m\\h_f=2h[/tex]

where the final mass and height are denoted by mf and hf.

                   [tex]U_i=mgh[/tex]

let's consider this to be the initial energy.

                 [tex]U_f=2m*2h*g=4mgh=4U_i[/tex]

As a result, we may say that the final potential energy is four times more than the original.

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The range of the projectile is maximum at angle 45°, the range is 10.2m,  the time to reach the maximum height is 0.72 s and the maximum height is 2.6 m

The stone, or object or anything projected in a trajectory path is known as a projectile.

In the given two-dimensional projectile motion problem involving a ball starting and ending at the same height. the projectile leaves the ground with an initial velocity of 10 m/s at some angle Ф with the horizontal,

(a) The value of the angle Ф (in degrees) which will makes the range of the projectile maximum is angle 45° because Range = u²sin2Ф ÷ g

At Ф = 45

Range = u²sin90° ÷ g

where sin 90 = 1

So, Range = u² / g which is the maximum range.

(b) The range at this angle will be

Range = 10² ÷ 9.8

Range = 100 / 9.8

Range = 10.2 m

(c) To calculate how long it takes the ball to reach maximum height, we will use the formula

t = usinФ ÷ g

t = 10 sin 45 ÷ 9.8

t = 0.72s

(d) The maximum height will be

H = u²sin²Ф ÷ 2g

H = 10²(sin45)² ÷ 2 × 9.8

H = 100 × 0.5 ÷ 19.6

H = 50 ÷ 19.6

H = 2.55 m

Therefore, the range of the projectile is maximum at angle 45°, the range is 10.2m,  the time to reach the maximum height is 0.72 s and the maximum height is 2.6 m

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The evolutionary cutoff between low- and high-mass stars occurs at eight (8) M.

The high-mass stars are celestial bodies that exhibit a high level of luminosity and lived for short periods of time.

Conversely, low-mass stars are small and cool stars that lived for a long period of time.

In conclusion, the evolutionary cutoff between low- and high-mass stars occurs at eight (8) M.

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The work-energy principle states that the work done by all the non-conservative forces acting on an object (or system of objects) causes a change in the total mechanical energy of the object or system.


What is the work-energy principle?
The work-energy principle states that the total work done on a system is equal to the change in kinetic energy of the system. It is given as:

W.D = ΔK.E

       = K.E₁ - K.E₂

where K.E₁ is the initial kinetic energy of the system

            K.E₂ is the final kinetic energy of the system

What is meant by non-conservative forces?

Non-conservative forces as the name suggests are not conserved i.e. these forces cause a loss of mechanical energy from the system. A prime example of non-conservative forces is friction.

The total mechanical energy of the system is the sum of the potential energy and kinetic energy that the system contains. This energy is conserved and follows the work-energy theorem.

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Answer:

» (a)

Explanation:

Velocity is the rate of change in displacement.

[tex]{ \rm{velocity = \frac{ \triangle displacement}{time} }} \\ [/tex]

The change from one position to another is displacement or distance between the points.

[tex] = { \rm{ \frac{22000}{200} }} \\ \\ = { \tt{110 \: m {s}^{ - 1} }}[/tex]

An athlete produced 840 watts of power in 0.6 seconds. And will produce 504 joule of work did this individual perform during the exercise.

Solution:

we know that power is the work done completed in a given interval of time.

Power = [tex]\frac{work}{time}[/tex]

also, Work = Power × Time

Work = 840 × 0.6 = 504 joule

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Explanation:

by taking a brisk walking about 150 minutes

2 days a week exercise that strengths muscles

drinking water

Answer: If the Moon takes 27.3 days to complete its orbital path around the Earth, and the orbit has a radius of 3.8 x 108 meters, then, the Earth's Mass is [tex]6*10^{24}kg[/tex].

Explanation: To find the answer, we have to know more about the Law of periods or the harmonic law.

                                              [tex]T^2[/tex]∝ [tex]r^3[/tex]

                                            [tex]T^2=\frac{4\pi ^2r^3}{GM}[/tex]

                                     [tex]M=\frac{4\pi ^2r^3}{GT^2}[/tex]

           [tex]M=\frac{4\pi ^2(3.8*10^8)^3}{6.67*10^-11*(27.3*24*60*60s)^2} =\frac{2.164*10^{27} }{371.08} =5.831*10^{24}=6*10^{24}kg[/tex]

Thus, we can conclude that, the mass of earth is [tex]6*10^{24}kg[/tex] .

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As the acceleration of gravity is less on the moon than on the Earth, thus the resonant frequency of the pendulum will be less on the moon.

Explanation:

The acceleration due to gravity is less on the moon than the gravitational acceleration on the earth. It is required to examine how the resonant frequency of a pendulum is changed on the moon compared to the earth.

We know that the resonant frequency is dependent on the acceleration of gravity.

[tex]$f=\frac{1}{2 \pi} \sqrt{\frac{g}{l}}$[/tex] where g is the acceleration due to gravity and l is the length of the string.

From the above equation, it is clear that the resonant frequency is directly proportional to the square root of the acceleration due to gravity.

The gravitational acceleration on the moon is less than that on the earth.

Therefore the resonant frequency of the pendulum on the moon is less than that on the earth.

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