For random variable X~N(3,0.75), what is the probability that X takes on a value within two standard deviations on either side of the mean?

A principal gathered data about the distance in miles that his teachers and bus drivers live from the school. then, the interquartile range of the distances for the bus drivers in 5 miles less than the interquartile range of the distance for the teacher.

Interquartile Range:

In descriptive statistics, the interquartile range (IQR) is a measure of the statistical distribution, the distribution of data. IQR can also be referred to as bad reading, 50% mean, fourth distribution, or H-distribution. It is defined as the difference between the 75th and 25th percentile of the data. To calculate the IQR, the data set is divided into quartiles, or four parts of equal rank by linear interpolation. These quartiles are represented by Q1 (also known as the lower quartile), Q2 (the median) and Q3 (also known as the upper quartile).

The lower quartile is the 25th percentile and the upper quartile is the 75th percentile, so IQR = Q3 − Q1

Basically, the interquartile range represents the width or “spread” of the collection. The interquartile range is determined by the difference between the upper quartile (highest 25%) and lower quartile (lowest 25%) points of a data set.

From the figure, we can find:

The interquartile range of the bus driver is: 20 -10 = 10

The interquartile range of the teacher is: 30 -15 = 15

Therefore,

the interval interquartile distance is bus The driver's distance was 5 miles less than the interquartile range of the teacher's distance.

Complete Question:

A principal gathered data about the distance in miles that his teachers and bus drivers live from the school .The box plots below show these data.

(1) The inter Quartile range of the distances for the bus driver is twice the interquartile range of the distances for the teachers.

(2) The range of the distances for the teachers is twice the range of the distances for the bus drivers.

(3) the interquartile range of the distances for the bus drivers in 5 miles less than the interquartile range of the distance for the teacher.

(4) The range of the distances for the teachers is 5 miles less than the range of the distances for the bus driver.

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Answer: C. The interquartile range of the distances for the bus drivers is 5 miles less than the interquartile range of the distances for the teachers.

Answer:

Yes they are congruent

Option B is correct

Step-by-step explanation:

Opisite sides of parallelogram are congurent so,

BA is congruent to CD (side)

And

BE I congruent to ED (Side)

AE is congruent to EC (Side)

So according to side-side-side congurence theorem triangle ABE is congruent to triangle CDE

Hope you understand :)

The average productivity of the workforce, A(x), is given by

A(x) = p(x)/x,

where p(x) is the total value of the production when there are x workers in the plant.

A'(x) is the derivative of A(x) with respect to x.

A'(x) = (p(x)/x)' = (p'(x)x - p(x))/x^2.

The company wants to hire more workers if A'(x) > 0 because it means that the average productivity of the workforce is increasing with additional workers.

A'(x) > 0 if p'(x) is greater than the average productivity, which is p(x)/x.

Therefore, A'(x) > 0 if p'(x) > p(x)/x.
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Answer:

Answer is in the picture

Step-by-step explanation:

Hope you understand :)

Answer:

-----------------------------

According to one of the properties of a parallelogram, any two consecutive interior angles are supplementary.

We know supplementary angles add up to 180°.

Apply this property to the given parallelogram and set up the following equation:

Answer:

You didn't give any options, but I'm guessing one of them has a 3 in the tens digits, which should be the right answer

Step-by-step explanation:

300?

Answer:

She will draw 120 times for a red marble

Step-by-step explanation:

Therefore, the value of 'a' when the shaded cross-sections of the solids have the same area is

:a = √(4A/π).

To find out the value of a (side length of the base of the square prism) when the shaded cross-sections of the solids have the same area, we need to use the formula for the area of a square.

The area of a square is given by the formula: A = a², where 'a' is the side length of the square.

Now, let's look at the two solids given in the question.

The first solid is a square prism with base 'a' and height 'a'.The second solid is a right circular cylinder with radius 'a' and height '2a'.The cross-section of the square prism is a square with side length 'a'.The cross-section of the right circular cylinder is a circle with radius 'a'.

Given that the shaded cross-sections of the solids have the same area, we can equate the area of the square with the area of the circle.

A = πr², where 'r' is the radius of the circle Substituting the values of 'r' and 'a', we get:A = πa²/4 = a²/4Multiplying both sides by 4, we get:4A = πa²

Now we can solve for 'a' by taking the square root of both sides a = √(4A/π).

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Amina's percentage profit is 25%, as the percentage profit must be rounded down to the nearest whole number.

Profit is an important concept in economics and finance, referring to the difference between the cost of production and the revenue generated from the sale of goods and services. It is a measure of success and financial performance and is used to analyze the profitability of a business. Profit is generally expressed as a percentage of revenue or as a dollar amount.

To calculate this, first find the cost of the article after the trade discount:
Article Cost = 0.75p - (0.75p * 0.25) = 0.75p * 0.75 = 0.5625p
Next, find the cost of the article after the cash discount:
Article Cost = 0.5625p - (0.5625p * 0.05) = 0.5625p * 0.95 = 0.5343p
Finally, calculate the percentage profit:
Percentage Profit = (0.75p - 0.5343p) / 0.75p * 100 = 0.2167 / 0.75 * 100 = 28.89%
Amina's percentage profit is 25%, as the percentage profit must be rounded down to the nearest whole number.

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You answer would be mate it would be x=66

Barbara will get $7.20 back in change.

A sales tax that is typically added to the selling price by the seller.

Without tax, the total cost of the shirt and pants is:

$15.00 + $25.00 = $40.00

The sales tax is 7% of $40.00, which is as follows:

0.07 x $40.00 = $2.80

So, with tax, the total cost of the shirt and pants is:

$40.00 + $2.80 = $42.80

If Barbara pays with a $50 bill, she will receive the following change:

$50.00 - $42.80 = $7.20

As a result, Barbara will receive $7.20 in change.

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Here are the solutions:

a) R4 = {(a, b, c, d) | a, b, c, d ∈ R}

b) P3 = {a0 + a1x + a2x^2 + a3x^3 | a0, a1, a2, a3 ∈ R}

c) M22 = {(aij) | i, j = 1, 2}

d) M23 = {(aij) | i = 1, 2, j = 1, 2, 3}

For the given vector space R4 with the standard vector addition/scalar multiplication, the zero vector is the following: 0 = [0, 0, 0, 0].b) For the given vector space P3 with standard polynomial addition/scalar multiplication, the zero vector is the following: 0(x) = 0.c) For the given vector space M22 with standard matrix addition/scalar multiplication, the zero vector is the following:[0 0] [0 0]d) For the given vector space M23 with standard matrix addition/scalar multiplication, the zero vector is the following:[0 0 0][0 0 0].

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If Idil drove 12 miles in 1/5an hour on average, then she drove at an average speed of 60 miles per hour.

To calculate the average speed of Idil's car in miles per hour, we need to divide the distance she drove (12 miles) by the time it took her to drive that distance (1/5 hour):

Average speed = distance ÷ time

Average speed = 12 miles ÷ (1/5) hour

To divide by a fraction, we can multiply by its reciprocal, so:

Average speed = 12 miles × 5/1 hour

Average speed = 60 miles per hour

Therefore, Idil drove at an average speed of 60 miles per hour.

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By using Pythagοrean theοrem, the angle οf elevatiοn tο the sun, vertical height, hοrizοntal distance, slant height, tangent and angle οf elevatiοn is 51°

The Pythagοrean theοrem is a fundamental result in Euclidean geοmetry that describes the relatiοnship between the three sides οf a right-angled triangle.

In equatiοn fοrm, this can be written as:

[tex]c^2 = a^2 + b^2[/tex]

Where c is the length οf the hypοtenuse, and a and b are the lengths οf the οther twο sides (alsο knοwn as the legs) οf the right-angled triangle.

a) The Name οf the angle οf elevatiοn is: angle οf elevatiοn tο the sun

b) The Name οf the Hypοtenuse side is: vertical height (bοdy height)

c) The Name οf the Oppοsite side is: hοrizοntal distance (shadοw length)

d) The Name οf the Adjacent side is: slant height (hypοtenuse οf the triangle fοrmed by the bοdy, the tip οf the shadοw, and the sun)

e) The Trig Ratiο I will be using is: tangent (οppοsite/hypοtenuse) because we are given the οppοsite side and the hypοtenuse.

f) Shοw the wοrk tο find the angle οf elevatiοn. Rοund tο the nearest degree:

tan(angle οf elevatiοn) = οppοsite/hypοtenuse

tan(angle οf elevatiοn) = 45/34

angle οf elevatiοn [tex]= tan^{-1(45/34)[/tex]

angle οf elevatiοn ≈ 51°

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(a) The recursive formula for An is: An = (1.015)An-1 - 100.

(b) The explicit formula for An in summation notation is: An = 4000(1.015)^n - 100[1 + (1.015) + (1.015)^2 + ... + (1.015)^(n-1)].

(a) This formula says that to find the balance for month n, we take the balance for month n-1, multiply it by 1.015 (to account for the interest rate), and subtract 100 (to account for the withdrawal). This formula is consistent with the results for n=1,2,3 on the previous page.

(b) The explicit formula for An in summation notation is: An = 4000(1.015)^n - 100[1 + (1.015) + (1.015)^2 + ... + (1.015)^(n-1)].

This formula says that to find the balance for month n, we take the starting balance of 4000 multiplied by the interest rate raised to the power of n, and then subtract the sum of 100 multiplied by the geometric series (1 + r + r^2 + ... + r^(n-1)), where r = 1.015. This formula is consistent with the results for n=1,2,3 on the previous page.

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a) d/dt [√(289 - 8²)] = d/dt [√(255)] = d/dt [√(5²*17)] = 5/2√17 m/s.

b) The required value is the rate of change of x when the top of the ladder is 8 feet from the ground, then y = 15 feet.

a) Determine how fast the bottom of the ladder is sliding away when the top of the ladder is 8 feet from the ground. As the ladder leans against the side of the house, it makes a right angle with the ground. Using Pythagorean Theorem, the length of the ladder is given by.

Ladder length = √(hypotenuse)² - (height)²= √(17² - height²) meters. Taking the derivative of both sides of this equation, we get: dL/dt = [d/dt √(289 - h²)] meters/sec. Let h = 8 feet, dL/dt = -5 feet/sec.

Thus, the rate of change of the bottom of the ladder is d/dt [√(289 - h²)] meters/sec when the top of the ladder is 8 feet from the ground, and the bottom of the ladder is sliding away at a rate of 5 feet/sec.

b) At what rate is the angle o between the ladder and the ground changing then. Let y be the height of the ladder and the angle it makes with the ground be x. From the given values, y = 17 cos x.

Taking the derivative of both sides with respect to time: dy/dt = -17 sin x (dx/dt)In the given problem, dx/dt = -5/17sin x. Then, dy/dt = 5 sin x cos x= (5/2) sin 2x.

Solving this value of sin x by Pythagorean Theorem, sin x = 8/17. Substituting the value in the equation for the derivative, we get: dy/dt = (5/2) * sin 2x= (5/2) * sin 2(arc sin(8/17))= (5/2) * (2*8/17 * 15/17)= (600/289) ft/sec.

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Answer:

-11

Step-by-step explanation:

48 ÷8=6-15=-9

99÷-9=-11

The ribbon cost $0.60 per foot.

[tex]\text{Total number of ribbon used} = (5.75 + 11.75) = 17.50 \ \text{feet}[/tex]

[tex]\text{17.50 feet of ribbon cost} = \$10.50[/tex]

[tex]\text{1 foot of ribbon cost = x}[/tex]

[tex]17.50 \times x = 1 \ foot \times \$10.50[/tex]

[tex]x = 1 \ foot \times 10.50\div17.50[/tex]

[tex]x = \$0.60[/tex]

Therefore, The ribbon cost per foot $0.60 per foot.

Answer:

10km

Step-by-step explanation:

Pythagoras

Formula=[tex]a^2+b^2=c^2[/tex]

[tex]6^{2} +8^{2} =c^2\\c^2=100\\c=\sqrt{100} \\c=10km[/tex]

To refresh your memory of 9th-grade math, read Chapter 12. Complete the following table of angle and side measurements.

Right AnglesAngleA B C a b c

1 40 50 90 50 40 552 35 55 90 55 35 77

3 35 55 90 55 35 684 30 60 90 60 30 855 60 30 90 60 30 906 45 45 90 45 45 63

The above given table represents the values of angles and sides of the right-angled triangles. In the right-angled triangle, one angle measures 90°, and this angle is known as the right angle.

Further, the sum of other two angles measures 90°.In the above table, a, b and c are sides, and angles A, B, and C are opposite angles of a, b, and c, respectively.

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a. The answer to this question is the solution to the equation:

84000(1 + 0.04)^a = 132000

Where "a" represents the number of years since the beginning of 2020, and 0.04 is the decimal equivalent of 4%.

We use the formula for compound interest, which is A = P(1 + r/n)^(nt), where A is the final amount, P is the principal, r is the interest rate, n is the number of times interest is compounded per year, and t is the time in years. In this case, we assume that the population growth rate is compounded annually, so n = 1.

b. Solving the equation in part (a), we get:

(1 + 0.04)^a = 132000/84000

1.04^a = 1.5714

a = log(1.5714)/log(1.04)

a ≈ 9.9 years

Therefore, it will take approximately 9.9 years for the city's population to reach 132,000 people, assuming a 4% annual growth rate.

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The combined score on the 2022 SAT test ranges from 400 to 1600. If you were to randomly draw five numbers from a 400-1600 number set, the probability that the medium score of the actual 2022 SAT results is contained in between the highest and lowest value of these five random numbers is approximately 0.004%

To find the probability that the medium score of the actual 2022 SAT results is contained in between the highest and lowest value of these five random numbers, we need to find the probability of the following event: “the three other random numbers drawn lie between the highest and lowest values.

The probability of choosing one of the five numbers that falls within the range is (1600 – 400)/1201 = 1/2.25.

The first number can be any number within the 400-1600 range, so the probability is 1.The second number must lie within the range created by the highest and lowest values of the first number, which has a width of 1201. Thus, the probability is 1201/3201.

The third number must lie within the range created by the highest and lowest values of the first two numbers, which has a width of 801. Thus, the probability is 801/2401.The fourth and fifth numbers must lie within the range created by the highest and lowest values of the first three numbers, which has a width of 401.

Thus, the probability is 401/1601.Therefore, the probability of the medium score of the actual 2022 SAT results being between the highest and lowest values of these five random numbers is (1/2.25) * (1201/3201) * (801/2401) * (401/1601) * 1 = 0.000038 or approximately 0.004%.

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The correct option is B. The value of the quartile Q3 is 65.3 inches

Quartile is a type of statistical value that represents one-fourth of a dataset. It divides a dataset into four equal parts. Q1, Q2, and Q3 are the first, second, and third quartiles, respectively.

The formula for the third quartile is as follows:

Q3 = μ + (0.67 × σ), where μ is the mean and σ is the standard deviation.

Given:

Mean = μ = 63.6 inches

Standard deviation = σ = 2.5 inches

The value of the quartile Q3 can be found by substituting the given values in the formula.

Q3 = μ + (0.67 × σ)

Q3 = 63.6 + (0.67 × 2.5)

Q3 = 63.6 + 1.675

Q3 = 65.275 ≈ 65.3

Therefore, the value of the quartile Q3 is 65.3 inches. Therefore, option B is the correct answer.

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The set of data that would produce the largest t-statistic for an independent-samples t-test is the one with the largest difference between the sample means and the smallest variability within each sample.When other factors are held constant, the t-statistic for an independent-samples t-test is given by the following formula:

t=(x1 − x2)/ SEwhere x1 and x2 are the means of the two samples, and SE is the standard error of the difference between the means. The standard error of the difference between the means is given by:SE = sqrt [s1^2/n1 + s2^2/n2]where s1 and s2 are the standard deviations of the two samples, and n1 and n2 are the sample sizes. Therefore, the t-statistic can be maximized by maximizing the difference between the sample means and minimizing the variability within each sample.Therefore, the set of data that would produce the largest t-statistic for an independent-samples t-test is the one with the largest difference between the sample means and the smallest variability within each sample.

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Answer: 19

Step-by-step explanation:

This is an isosceles trapezoid. Note that because this is an isosceles trapezoid, QN and MP are equal. Use the lengths given and solve:

3x + 1 + 6 = 6x - 5

3x = 12

x = 4

Plug x = 4 in 3x + 1 + 6, and we get 3(4) + 1 + 6 = 12 + 7 = 19

Hope this helps!

Step-by-step explanation:

a) Area=144m²

side²= 144

side=12m

b) perimeter=32m

4×side=32

side=32/4

side=8m

Answer:

∠ BAC and ∠ CAD

Step-by-step explanation:

• Complementary angles sum to 90°

∠ BCA and ∠ ACD are a linear pair and sum to 180°

∠ BCA + 110° = 180° ( subtract 110° from both sides )

∠ BCA = 70°

the sum of the 3 angles in a triangle = 180°

in Δ ABC

∠ BAC + 55° + 70° = 180°

∠ BAC + 125° = 180° ( subtract 125° from both sides )

∠ BAC = 55°

in Δ ACD

∠ CAD + 110° + 35° = 180°

∠ CAD + 145° = 180° ( subtract 145° from both sides )

∠ CAD = 35°

then

∠ BAC + ∠ CAD = 55° + 35° = 90°

∠ BAC and ∠ CAD are complementary

Answer:

  (a)  ∠BAC and ∠CAD

Step-by-step explanation:

You want to know which angles in the figure are complementary.

Two angles are complementary when the total of their measures is 90°. In the given figure, triangle ABD is a right triangle with the right angle at vertex A.

The two acute angles at vertices B and D will be complementary:

  ∠ABC and ∠CDA . . . . . not on the list of choices

Ray AC divides the right angle into two complementary parts:

  ∠BAC and ∠CAD . . . . . first choice on the list

__

Additional comment

The two smaller triangles are isosceles. Angles CDA and CAD are both 35°, so have a sum of 70°. Likewise, angles ABC and BAC are both 55°, with a sum of 110°.

Angles BCA and ACD are a linear pair, so have a sum of 180°. They are supplementary, not complementary.

Length of the median of the triangle is b. 18

How to find the length of the median of a triangle?
Given that the centroid of a triangle is located 12 units from one of the vertices of a triangle. We need to find the length of the median of the triangle drawn from that same vertex.

Let ABC be a triangle.

Let AD be median of the triangle.

Let E be centroid of ΔABC

Length of the median of triangle = AD

AD = Length of AE + Length of ED

But,

AE = 12

ED = x

So,

AD = 12 + x

Since, centroid divides median in 2:1 ratio.

Then,

[tex]12 : x = 2 : 1\\12/x = 2/1\\\\12= 2x\\[/tex]

Divide by 2 each side

[tex]x = 6[/tex]

So,  AD = 12 + x = 12 + 6 = 18

Thus, Length of the median of triangle is 18.

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Answer:

A is correct

Step-by-step explanation:

Whatever value you put in for "y" will keep both of the equations equal

Answer:

Pretty sure its C

Step-by-step explanation:

To cut through y axis, x axis is always 0, So it would be (0, a) where a is any real number, not (a,0) as is given in reason.

Answer:

m = -9/2

Step-by-step explanation:

Slope = rise/run or (y2 - y1) / (x2 - x1)

Points (4, -6) (2, 3)

We see the y increase by 9, and the x decrease by 2, so the slope is

m = -9/2