Geometry problem above ^ ABC is similar to...

The inequality which shows all possible values of m is; m < 9.

It follows from the task content that the variable in discuss, m is described as less than 9.

On this note, the most appropriate inequality to represent the set of all possible values of m is; m < 9.

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Answer:

Line A

Step-by-step explanation:

Hello!

Given that the x-values is the time in minutes, and the y-axis is the number of dishes stacked, for every minute, the line should go up by 7.

This means, that the value of y when x is 1 should be 7. The line that follows this rule is Line A. For every minute, 7 dishes are stacked.

The answer is Line A.

Answer:

the answer is congruent making d midpoint

Answer:

The correct awnser is A : )

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

When x = 1, 3x² + 2x - 7 = -2.

Answer:

Angle D & Angle E

Step-by-step explanation:

Angle C & Angle F are ALTERNATE EXTERIOR angles.

Angle B & Angle E are CONSECUTIVE angles.

Angle D & Angle G are CORRESPONDING angles.

Al aplicar operaciones de aritmética básica, tenemos que la mitad de 980 es igual a 490.

En esta pregunta tenemos un número par de tres dígitos que termina en cero. De acuerdo con la teoría numérica, un número de base 10 de más de un dígito que tenga un número par relacionado con números impares como último dígito, tendrá un número impar si es dividido por 2.

Ahora bien, si tenemos un número par con más de un dígito que termina en cero, entonces tendrá un número par que termina en 0 si es dividido por 2.

Si dividimos 980 por 2, entonces tenemos 490 como resultado:

980/2 = 98/2 × 10 = 49 × 10 = 490

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The five-number summary is: 41, 56, 65, 67, 69.

The box plot that represents the data is: option B.

Correct statement for the shape of the distribution is: B. the distribution is skewed to the left.

The five-number summary is a five data value that describes the distribution of a data set, which include: lower and upper quartiles, minimum and maximum values, and the median of the data.

The five-number summary is used to construct a box plot.

Given the data, 65, 56, 67, 68, 66, 66, 67, 69, 48, 57, 59, 68, 59, 41, 44, the five-number summary for the data is:

This means that the box plot that will represent this data will have a box that ranges between 56 and 67, and the data at both whiskers will be 41 and 69, while the data at the point where the vertical line divides the box would be 65.

Thus, the box plot that represents the data is: option B.

The median is closer to the right of the third quartile/upper quartile, therefore: B. the distribution is skewed to the left.

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Answer:

A = 228 tickets

Step-by-step explanation:

We need to set up a system of equation to find the number of adult tickets sold, where A represents the adult tickets and S represents the student tickets.

Because the number of adult and student tickets together equals 506, we have A + S = 506.

Because there are 56 more student tickets than adult tickets we have A + 56 = S

And the way the system is already set up allows us to use substitution.

Thus, we have:

[tex]A + S=506\\A+56 = S\\\\A+A+56 =506\\2A+56=506\\2A=456\\\\A=228\\228+56=S\\278=S[/tex]

The number of student tickets was not necessary to find in this problem, but I found anyway just in case you wanted check the work or wanted to prove the validity of the values.

In accordance with the function velocity, the car will have a complete stop after 6 seconds.

Herein we have a function of the velocity of a car (v), in feet per second, in terms of time (t), in seconds. The car stops for t > 0 and v = 0, then we have the following expression:

0.5 · t² - 10.5 · t + 45 = 0

t² - 21 · t + 90 = 0

By the quadratic formula we get the following two roots: t₁ = 15, t₂ = 6. The stopping time is the least root of the quadratic equation, that is, the car will have a complete stop after 6 seconds.

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Answer:

5) y = 1x + 2

6) y = -0.5x + 6

Explanation:

5)

Given points are (-3, -1), (2, 4)

[tex]\sf slope \:formula: \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{\triangle y}{\triangle x} \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]

Here, find slope:

[tex]\rightarrow \sf slope \ (a) = \dfrac{4-(-1)}{2-(-3)} = \dfrac{5}{5} = 1[/tex]

Find Equation:

y = ax + q

Here found that a = 1, take (x, y) = (-3, -1)

[tex]\sf -1 = 1(-3) + q[/tex]

[tex]\sf q - 3 = -1[/tex]

[tex]\sf q = -1 + 3[/tex]

[tex]\sf q = 2[/tex]

So, in total equation:

y = 1x + 2

-------------------------------------------------------------------------------------

6)

Given points are (-2, 7), (2, 5)

[tex]\sf slope \:formula: \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{\triangle y}{\triangle x} \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]

Here, find slope:

[tex]\rightarrow \sf slope \ (a) = \dfrac{5-7}{2-(-2)} = -0.5[/tex]

Find Equation:

y = ax + q

Here found that a = -0.5, (x, y) = (-2, 7)

[tex]\sf 7 = -0.5(-2) + q[/tex]

[tex]\sf 7 = 1 + q[/tex]

[tex]\sf q = 7-1[/tex]

[tex]\sf q = 6[/tex]

So, in total equation:

y = -0.5x + 6

Answer:

The equation of the line that is perpendicular to y = 1/6 is: B. x = -8.

Perpendicular lines have slope values that equals -1 when multiplied together, that is, they are negative reciprocals.

Given the equation, y = 1/6, the slope is 0. This means it is a vertical line, therefore, the line that is perpendicular to it would automatically be a vertical line with an undefined slope which passes through (,8, -2).

The line therefore, would intercept the x-axis at -8. The equation would be: x = -8.

Equation of the perpendicular line is therefore: B. x = -8.

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Using the law of cosines, it is found that the approximate length of side a is 3.99 units.

The law of cosines states that we can find the side c of a triangle as follows:

[tex]c^2 = a^2 + b^2 - 2ab\cos{C}[/tex]

in which:

In the context of this problem, we have that side a is opposite to the angle of 53º, hence:

[tex]a^2 = b^2 + c^2 - 2bc\cos{53^\circ}[/tex]

We are given that:

Then:

[tex]a^2 = 34 - 30\cos{53^\circ}[/tex]

a² = 15.95

[tex]a = \sqrt{15.95}[/tex]

a = 3.99.

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The expression that we need to get is:

[tex]N = \frac{(23)*(10.4) + (10.5)*(7.2)}{200}[/tex]

So the correct option is the second one.

We know that 1 gallon is enough to cover 200 ft².

We have two rectangular areas, one of:

23 feet by 10.4 feet, and other of 10.5 feet by 7.2 feet.

Then the total area is:

A = (23 ft)*(10.4 ft) + (10.5ft)*(7.2 ft)

The number of gallons needed is given by the quotient between the area that we want to cover, and the area that covers one gallon, so the expression is:

[tex]N = \frac{(23ft)*(10.4ft) + (10.5ft)*(7.2ft)}{200ft^2} \\\\N = \frac{(23)*(10.4) + (10.5)*(7.2)}{200}[/tex]

So the corerect option is the second one.

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The sum of the ten terms to the nearest whole number is 50857.

Using geometric sequence formula,

nth term = arⁿ⁻¹

where

r = 20 / 8 = 5 / 2

a = 8

Hence,

s₁₀ = a(rⁿ - 1) / r - 1

s₁₀ = 8((5 / 2)¹⁰ - 1) / 5 / 2 - 1

s₁₀ = 8(9535.74316406) / 1.5

s₁₀ = 50857.296875

s₁₀ = 50857

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Answer:  [tex]\frac{\sqrt{7}}{7}[/tex]

========================================================

Explanation:

The reciprocal of x is 1/x where x is nonzero. Multiplying x with 1/x leads to 1. For example, the numbers 9 and 1/9 are multiplicative inverses of each other.

We'll stick 1 over the given square root expression. Then follow these steps to rationalize the denominator.

[tex]\frac{1}{\sqrt{7}}\\\\\\\frac{1*\sqrt{7}}{\sqrt{7}*\sqrt{7}}\\\\\\\frac{\sqrt{7}}{(\sqrt{7})^2}\\\\\\\frac{\sqrt{7}}{7}\\\\[/tex]

In short, [tex]\frac{1}{\sqrt{7}}=\frac{\sqrt{7}}{7}[/tex]

The answer choice which explains that the three segments cannot be used to construct a triangle is; AC + CB < AB.

Since, It follows from the triangle inequalities theorem that sum of the side lengths of any two sides of a triangle is greater than the length of the third side.

Hence, since the sum of sides AC + CB is less than AB, it follows that the required inequality is; AC + CB < AB.

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Answer: Option 2 or B.  AC + CB < AB

Step-by-step explanation: Trust Me!  It is correct on Edge!

Q: Which inequality can be used to explain why these three segments cannot be used to construct a triangle?

A: AC + CB < AB

The zeros of the given function are x = 2 and x = -1

From the question, we are to determine the zeros of the given function

The given function is

f(x) = (x - 2)(3x + 3)

To determine the zeros of a function, we will set the function equal to zero

That is,

(x - 2)(3x + 3) = 0

Then,

x - 2 = 0 OR 3x + 3 = 0

x = 2 OR 3x = -3

x = 2 OR x = -3/3

x = 2 OR x = -1

Hence, the zeros of the given function are x = 2 and x = -1

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Answer:

2=1289/17

Step-by-step explanation:

use the given functions to set up and simplify 2

The ordered pairs that is a solution to the linear inequality y > 3x + 2 is

(2, 9)

The inequality is as follows;

y > 3x + 2

Therefore, let's try option 1

(-1, -5)

-5 > 3(-1) + 2

-5 > -3 + 2

-5 > - 1 (This is false)

(–2, –7)

-7 > 3(-2) + 2

-7 > -6 + 2

-7 > -4 (This is false)

(2, 8)

8 > 3(2) + 2

8 > 6 + 2

8 > 8 (false)

(2, 9)

9 > 3(2) + 2

9 > 8 (This true)

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Answer: [tex]\frac{9g}{4y}[/tex]

Step-by-step explanation:

[tex]\frac{6g}{2} \times \frac{3}{4y}=\frac{18g}{8y}=\frac{9g}{4y}[/tex]

The correct matching of the exponential form is given.

1: 13^-11 × 13^16 × 13^-3 × 13^-4 × 13^-5

= 13

2. 13^-21 × 13^-4 × 13^-5 × 13^14 × 13^-6

= 13^-22

3. 13^0 × 13^10 × 13^-12 × 13^5 × 13^4

= 13^7

This illustrates the exponential form.

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hi,

the function is given with it's canonic form.  

canonic form is  :  f(x) = a ( x-α)² + β

α  and β are the value of the coordonnates of the vertex.

so here we  have : ƒ(x) = 2(x−1)² +3

with α = 1  and β = 3

so vertex is  V (1;3)

So yes, answer is   A.

This problem is about pension fund management. It is to be noted that the best Feasible Capital Allocation Line (CAL) is: 0.3162.

A graph's capital allocation line depicts all conceivable combinations of risky and risk-free assets, allowing investors to estimate future returns depending on risk.

It is to be noted that the optimal risky portfolio's stock percentage is determined by:

Weight of Stock = ((Return on Stock - Risk Free Rate) * Variance of bond) - ((Return on Bond - Risk Free Rate) * Co-Variance of bond & Stock)/ ((Return on Stock - Risk Free Rate) * Variance of bond + (Return on Bond - Risk Free Rate) * Variance of Stock - ((Return on Bond - Risk Free Rate + Return on Stock - Risk Free Rate + ) * Co-Variance of bond & Stock)

→ The weight of stock

= ((15% - 5.5%) * 529) - ((9% - 5.5%) * 110.40)/ ((15% - 5.5%) * 529) + (9% - 5.5%) * 1,024 - ((15% - 5.5% + 9% - 5.5%) * 110.40)

= [(50.255) * (3.864) /(50.255) + (46.08) - (14.352)]

Weight of Stock = 0.646628

Weight of  Bonds = 1 - 0.646628

Weight of  Bonds= 0.353372

Expected return of portfolio = 0.646628 * 15% + 0.353372 * 9%

= 12.88%

Standard Deviation of Portfolio (SDP)= (0.6466282² * 1,024 + 0.3533722² * 529 + 2 * 0.646628* 0.353372* 110.40)⁰·⁵

SDP = (544.67)⁰·⁵

SDP = 23.34%

Hence,

Best feasible CAL = (12.88% - 5.5%)/ 23.34%

Best feasible CAL = 0.3162

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Full Question

See the attached spread sheet for additional information related to the questions.

The probability of all three events happening when the dies are rolled is; 0.0083

A) On the first die, it has 6 sides and 3 must come out, that is, 1 event out of 6 possible, therefore the probability is: 1/6

B) On the second die, it has 20 sides and if 19 or 20 can come out, that is 2 events out of 20 possible, so the probability is: 2/20 = 1/10

C) On the third die, which is 12 sides, an odd number can come out. The odd numbers would be 1, 3, 5, 7, 9, 11; i.e, 6 events out of 12 possible numbers.

Thus, the probability would be: 6/12 = 1/2

The final probability would be;

(1/6) * (1/10) * (1/2) = 0.0083

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Answer:

Cinthia studied 2/3 of her time on Tuesday

Step-by-step explanation:

If a stock's price falls all the way to zero, shareholders end up with worthless holdings. Once a stock falls below a certain threshold, stock exchanges will delist those shares.strong earning result in the stock price moving up and vice versa.

in the question you asked,the situation that will make stock price move from -$2.85 to zero means the stock, bond, or commodity market, or an index representing them, currently trades higher than it did at some specific point in the past.