Given samples of water:

Sample 1: 100. Grams of water at 10. °C

Sample 2: 100. Grams of water at 20. °C

Compared to sample 1, sample 2 contains

A) molecules with a lower average kinetic energy

B) molecules with a lower average velocity

C) less heat energy

D) more heat energy

The given reaction is Zn + 2AgNO₃ → 2Ag + Zn(NO₃)₂. So 14.20 g of zinc nitrate would be produced when 16.2 g of silver was produced.

Let us calculate the number of moles of silver using the given data:

Hence, 14.20 g of zinc nitrate would be produced.

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The left side of this equilibrium constant equation for the reaction of hypochlorous acid with water is filled as

HClO + H₂O ⇌ H₃O⁺ + ClO⁻

When HClO reacts with water, it can undergo a reversible dissociation reaction, which results in the formation of hydronium ions (H3O+) and hypochlorite ions (ClO-). Therefore, we can fill in the left side of the equation as follows,

HClO + H₂O ⇌ H₃O⁺ + ClO⁻

Note that the reaction can occur in both directions, and the equilibrium constant (K) expresses the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium.

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--The complete question is, Fill in the left side of this equilibrium constant equation for the reaction of hypochlorous acid with water

HClO + H2O ⇌ _____ + _____--

The main difference between nucleic acids and carbohydrates is that nucleic acids are made up of nucleotides, while carbohydrates are made up of monosaccharides.

Therefore, the property that distinguishes nucleic acids from carbohydrates is their composition of nucleotides, which are the basic structural units of nucleic acids.

What are nucleic acids?

Nucleic acids are the biomolecules that encode and transmit genetic information in cells.

They are primarily composed of carbon, nitrogen, oxygen, and phosphorus, and are formed by polymerization reactions in which nucleotides are joined by phosphodiester bonds to form polynucleotide chains.

What are carbohydrates?

Carbohydrates are organic compounds composed of carbon, hydrogen, and oxygen, with the general formula CnH2nOn.

They are classified based on the number of monosaccharide units they contain, with monosaccharides being the simplest and most basic carbohydrate units.

Carbohydrates serve as a source of energy and a structural component in living organisms.

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When 1.00 kcal of heat is applied, the water sample's final temperature is T = 50.0°C + 40.0°C = 90.0°C.

The amount of energy required to raise a substance's temperature is measured in terms of specific heat. It is the amount of energy (measured in joules) required to increase a substance's temperature by one degree Celsius per gram.

We must first determine the water sample's original temperature. The formula is as follows:

Q = mcΔT

Inputting the values provided yields:

700.00 cal = 25.0 g x 1.00 cal/g °C x (50°C - 22.0°C)

When we simplify this equation, we obtain:

ΔT = 700.00 cal / (25.0 g x 1.00 cal/g °C) = 28.0°C

Therefore, the initial temperature of the water sample is 22.0°C + 28.0°C = 50.0°C.

Inputting the values provided yields:

1.00 kcal = 25.0 g x 1.00 cal/g °C x (T - 50.0°C)

When we simplify this equation, we obtain:

T - 50.0°C = 1.00 kcal / (25.0 g x 1.00 cal/g °C) = 40.0°C

Therefore, When 1.00 kcal of heat is applied, the water sample's final temperature is T = 50.0°C + 40.0°C = 90.0°C.

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The corrective term to the volume in the Van der Waals equation is subtracted and not added because this allows the equation to accurately predict the behavior of real gases.

The Van der Waals equation is an equation of state, which describes the behavior of real gases. Since the actual behavior of real gases is to decrease in volume as the pressure increases, subtracting the corrective term allows the equation to predict this behavior.
The Van der Waals equation is an equation that describes the behavior of real gases. It is based on the Ideal Gas Law but includes two corrective terms:

one for the volume and one for the pressure. The equation is as follows: (P + a(n/V)²)(V - nb) = nRT

where: P = pressure ,V = volume , n = number of moles , R = gas constant , T = temperature , a = a constant that takes into account the attractive forces between gas particles, b = the volume of one mole of gas particles

For the volume term in the equation, the corrective term is -nb.

Hence , This term subtracts the volume of the gas particles themselves from the total volume. This is necessary because gas particles occupy some volume and therefore reduce the total volume of the gas. Without this corrective term, the equation would not accurately predict the behavior of real gases.

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To determine how much sodium chloride will not dissolve, we need to know the solubility of NaCl at 80°C. At 80°C, the solubility of NaCl in water is 37.8 g/100 mL.

We have 100 grams of water which is equivalent to 100/1000 = 0.1 L of water.

The maximum amount of NaCl that can dissolve in 0.1 L of water at 80°C is:

37.8 g/100 mL x 0.1 L = 0.378 x 10 g = 3.78 g

Since we have 50 grams of NaCl, which is greater than the maximum amount that can dissolve, the excess amount that will not dissolve is:

50 g - 3.78 g = 46.22 g

Therefore, 46.22 grams of NaCl will not dissolve.

The molecules that can absorb light in the visible range are called pigments.

What is a pigment?

Pigments are compounds that absorb light and reflect only some wavelengths, resulting in color production.

The molecules are capable of absorbing specific wavelengths of light, giving them the potential to interact with photons.

The visible range of light is absorbed by pigments.

The term "chromophore" is used to describe the light-absorbing portion of a pigment molecule.

The portion of the molecule that absorbs light in the visible region is the chromophore.

The pigments' physical and chemical properties affect the absorption spectrum.

Pigments have a characteristic absorption spectrum, which is the range of wavelengths they can absorb.

When pigments absorb light, they become excited, and this energy is used to fuel biological processes.

Pigments are an essential component of photosynthesis, which is the process by which plants use sunlight to make energy.

Chlorophyll a, chlorophyll b, and carotenoids are examples of pigments in plants that absorb light energy from the sun. In humans, pigments such as melanin and hemoglobin are involved in coloration and oxygen transportation, respectively.

In conclusion, molecules that can absorb light in the visible range are called pigments.

The term "chromophore" is used to describe the light-absorbing portion of a pigment molecule.

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Answer: Centimeters

Explanation: no explanation needed

According to the Beer-lambert law, as the concentration of a substance decreases so should the absorbance of the solution. Thus, the given statement is true.

The Beer-Lambert Law, also known as Beer's Law, Lambert's Law, or the Beer-Lambert-Bouguer Law, is a linear relationship between the attenuation of light and the properties of the material through which the light is traveling.

The Beer-Lambert Law relates the attenuation of light to the properties of the material it travels through. When light passes through a material, it is absorbed, reflected, or scattered in different amounts. The Beer-Lambert Law explains the attenuation of light as a result of the following factors:

Attenuation of light = Absorption of light + Scattering of light + Reflection of light

The Beer-Lambert Law states that the concentration of a material is directly proportional to the amount of light it absorbs. Absorbance decreases as the concentration of the solution decreases according to the Beer-Lambert Law.

Hence, the given statement is true.

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The organic product that is expected to form when the following compound is treated with aqueous NaOH is RCOONa + H₂O .

The given compound is a carboxylic acid. When treated with aqueous NaOH, it will undergo a reaction known as neutralization to form the corresponding salt of the carboxylic acid.The reaction mechanism is as follows;The first step is the dissociation of NaOH into its ions

NaOH → Na⁺ + OH⁻

Secondly, there will be proton transfer between the carboxylic acid and the OH ion of NaOH as follows:

RCOOH + OH⁻ → RCOO⁻ + H₂O

With this, we can draw the organic product expected to form when the given compound is treated with aqueous NaOH as shown below:  OR  RCOONa + H₂O. The product formed is the salt of the given carboxylic acid.

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17.0 g of Al₂O₃ forms from 16 g of O₂ and excess Al ,and when the molar mass of  Al₂O₃ is 102 g/mol.

Molar mass is the mass of one mole of a substance. It is usually expressed in units of grams per mole (g/mol). For example, the molar mass of carbon is 12.01 g/mol, which means that one mole of carbon has a mass of 12.01 grams. Molar mass is useful in chemistry because it allows us to convert between mass and moles of a substance, which is important for many chemical calculations.

The molar mass of  Al₂O₃ is 102 g/mol, which means that for every 102 g of  Al₂O₃ produced, 3 × 32 g (or 96 g) of O₂ is consumed.

We can use this ratio to find the mass of  Al₂O₃ formed from 16 g of O₂:

96 g of O₂ produces 102 g of  Al₂O₃

1 g of O₂ produces (102 g / 96 g) of Al₂O₃

16 g of O₂ produces (102 g / 96 g) × 16 g = 17.0 g of  Al₂O₃

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The concentration of ammonia in the solvent rises, the solubility of AgCl increases. Thus, in the solvent aqueous ammonia, AgCl is most soluble.

AgCl is most soluble in aqueous ammonia. AgCl is a chemical compound that is formed when silver nitrate and hydrochloric acid are combined. It is a white solid that is moderately soluble in water.

The solubility of AgCl in various solvents, such as water, ethanol, and aqueous ammonia, has been studied. AgCl is most soluble in aqueous ammonia.

When AgCl is dissolved in aqueous ammonia, a complex ion called the diammine silver(I) cation, [Ag(NH3)2]+, is formed. The AgCl crystal structure is disrupted by the presence of ammonia molecules, resulting in increased solubility. Here is the equation for the dissolution of AgCl in aqueous ammonia:

AgCl(s) + 2NH3(aq) → [Ag(NH3)2]+(aq) + Cl−(aq)

The solubility of AgCl in aqueous ammonia is temperature-dependent. As the temperature increases, the solubility of AgCl in aqueous ammonia increases. As the temperature decreases, the solubility of AgCl in aqueous ammonia decreases.

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The energy emitted by 4.09 g of strontium chloride salt is 8.01 8.00 x 10⁻²⁴ kJ  (rounded to 2 decimal places).

To determine the energy of the emission at 641 nm, we can use the formula:

E = hc/λ

where;

First, we need to convert the wavelength from nanometers to meters:

641 nm = 641 x 10⁻⁹ m

Next, we can plug in the values and solve for E:

E = (6.626 x 10⁻³⁴J·s)(3 x 10⁸ m/s)/(641 x 10⁻⁹ m)

E = 3.10 x 10⁻¹⁹ J

To convert from joules to kilojoules, we divide by 1000:

E = 3.10 x 10⁻²² kJ

Now we can use the molar mass of the chloride salt of strontium to calculate the total energy released:

SrCl₂ has a molar mass of 158.53 g/mol, so 4.09 g is equivalent to:

n = 4.09 g / 158.53 g/mol

n = 0.0258 mol

The energy released by 0.0258 mol of strontium chloride at 100% efficiency is:

E_total = nE

E_total = (0.0258 mol)(3.10 x 10⁻²² kJ/mol)

E_total = 8.00 x 10⁻²⁴ kJ

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NH₃ with NH₄NO₃ equimolar mixture would result in a buffer with a pH less than 7. The answer is (d) .

A buffer solution is made up of a weak acid and its conjugate base or a weak base and its conjugate acid. The pH of a buffer solution depends on the pKa of the weak acid or the weak base and the ratio of the concentrations of the weak acid and its conjugate base, or the weak base and its conjugate acid.

In this case, NH₃ is a weak base with a pKa of 9.25, and NH⁴⁺ is its conjugate acid. NH₄NO₃ is a salt of NH4+ and NO³⁻, and it will dissociate in water to form NH⁴⁺ and NO³⁻. Since NH⁴⁺ is the conjugate acid of NH₃, it will react with any added OH⁻ ions, preventing the pH from rising above 7. Therefore, NH₃ with NH₄NO₃ would result in a buffer with a pH less than 7.

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An object is said to be acted upon by an unbalanced force only when there is an individual force that is not being balanced by a force of equal magnitude and in the opposite direction.

An unbalanced force refers to a situation where the net force acting on an object is not equal to zero, which causes the object to accelerate in a particular direction. In other words, when the forces acting on an object are unbalanced, the object will either speed up, slow down, or change direction.

According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. Therefore, when an unbalanced force acts on an object, it will experience an acceleration proportional to the force applied. an unbalanced force is a force that causes an object to accelerate in a particular direction due to an imbalance in the forces acting on it.

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In isoelectronic species, the species that have the least number of electrons will have the smallest radius. Therefore, K+ has the smallest radius amongst K, K+ and K-.The order of the radius of the given species can be given as follows:

K > K⁻ > K⁺

The effective nuclear charge experienced by the K atom is +1, as it has one valence electron which can shield 18 electrons. Therefore, the attraction between the valence electron and the nucleus is weak which makes the atomic size larger than that of K- and K+.

The effective nuclear charge experienced by the K-atom is +1, as it has one valence electron which can shield 17 electrons. The attraction between the valence electron and the nucleus is stronger than in K due to less screening effect by electrons. Therefore, the atomic size is smaller than that of K.

The effective nuclear charge experienced by the K⁺ atom is +1, as it has one valence electron which can shield 19 electrons. The attraction between the valence electron and the nucleus is maximum in K+ due to the absence of one electron from the 4s orbital. Therefore, the atomic size is the smallest among the given species.

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The cage size of zeolites is in the centimeters scale. This statement is false.

Zeolites are microporous aluminosilicate minerals that have a framework structure composed of aluminosilicate tetrahedra. These tetrahedra are linked together to form a 3-dimensional pore structure with uniform size and shape. Zeolites are widely used as adsorbents, catalysts, and ion-exchangers due to their unique properties such as high surface area, thermal stability, and molecular sieving properties.Cage size of zeolitesZeolites are known for their uniform pore size and shape. The size of the pores in zeolites ranges from 2-10 Å (angstroms), which is too small to be measured in centimeters. Therefore, the cage size of zeolites is not in the centimeters scale, but rather in the angstroms scale.

This means that zeolites have a cage size that is much smaller than a nanometer. Their pore size makes them selective towards certain molecules based on their size and shape.Properties of zeolitesThe properties of zeolites are attributed to their pore structure, which is composed of channels and cages. These channels and cages provide a surface area that is accessible to molecules that can be adsorbed. The size and shape of the pores in zeolites allow them to be selective towards certain molecules based on their size and shape. The high surface area of zeolites also makes them an effective catalyst for a wide range of reactions, including the conversion of petroleum feedstocks to gasoline and diesel fuel.

SummaryIn conclusion, the statement "The cage size of zeolites is in the centimeters scale" is false. Zeolites have a uniform pore size and shape that ranges from 2-10 Å, which is much smaller than a nanometer. This size allows them to be selective towards certain molecules based on their size and shape, and makes them an effective adsorbent, catalyst, and ion-exchanger.

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According to the octet rule, atoms tend to achieve eight electrons in the outermost shell. The reason behind this tendency is that the atoms try to achieve a stable electronic configuration, which is similar to the noble gases, whose electronic configuration is stable.

The arrangement of an atom's or molecule's (or other physical structure's) electrons in their atomic or molecular orbitals is known as the electron configuration in atomic physics and quantum chemistry. For instance, the neon atom's electron configuration is 1s2 2s2 2p6, which means that 1, 2 and 6 electrons, respectively, are present in each of the 1s, 2s, and 2p subshells. According to electronic configurations, each electron moves individually within an orbital while being surrounded by an average field produced by all other orbitals. Slater determinants or configuration state functions are used to mathematically describe configurations. For systems with a single electron, the laws of quantum mechanics state that each electron configuration has a specific amount of energy, and that under certain circumstances, electrons can switch between configurations.

Electronic configuration is the distribution of electrons in various shells or orbitals. According to the octet rule, the outermost shell of the atoms must contain eight electrons for the atom to be stable. The octet rule is one of the essential rules that govern the formation of chemical compounds. It states that atoms tend to combine with other atoms in such a way that they will have eight electrons in their outermost shell or valence shell, which makes them more stable. The octet rule explains that the atoms combine or share electrons to form a compound in a way that each atom achieves eight electrons in its valence shell.

The sharing or transfer of electrons from one atom to another results in the formation of ionic or covalent bonds, which is the basis of chemical reactions.

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The percent recovery is the ratio of the actual amount of the desired substance to the original amount present. The total percent recovery can be calculated by using the formula given below.

The units and the correct significant digits should be used in the calculation. We expect that the percent recovery will be less than 100 % for this experiment because of the loss of product due to impurities or mistakes in the experimental procedure. For example, if the product is left on the filter paper while washing, then the actual yield will be less than the theoretical yield.

Calculate the total percent recovery. show calculation with units and correct significant digits. The percent recovery formula is:

Percent recovery = Actual yield ÷ Theoretical yield × 100%

Given, Actual yield = 70 theoretical yield = 80

percentage recovery = Actual yield ÷ Theoretical yield × 100 %

Percentage recovery = 70 ÷ 80 × 100 %

Percentage recovery = 0.875 × 100 %

Percentage recovery = 87.5 %

Therefore, the total percent recovery is 87.5 % with the correct significant digits. Why do we expect that the percent recovery will be less than 100 % for this experiment? We expect that the percent recovery will be less than 100 % for this experiment because of the loss of product due to impurities or mistakes in the experimental procedure.

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If some solid sodium hydroxide is added to a solu­tion that is 0.010–molar in (CH₃)₃CCl and 0.10–molar in NaOH, the reaction rate increases but k remains the same. Therefore, option D is correct.

In this scenario, when solid sodium hydroxide (NaOH) is added to a solution containing (CH₃)₃CCl and NaOH, a reaction between (CH₃)₃CCl and NaOH takes place. The balanced chemical equation for this reaction is:

(CH₃)₃CCl + NaOH ⇒ (CH₃)₃COH + NaCl

The reaction rate is determined by the concentration of the reactants. In this case, the concentration of (CH₃)₃CCl remains constant because only solid NaOH is added.

The rate constant depends on the specific reaction and the conditions under which it occurs. Since the temperature and volume remain constant, the rate constant (k) will also remain constant.

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When the mass of the solid increases, its volume will decrease, while when the volume of the liquid increases, its mass will increase. This is because the densities of these materials are determined by the amount of mass that can be held in a given volume.

The volume of the solid is directly proportional to its mass. It means, as the mass of the solid increases, its volume will also increase. Hence, we can predict that as the mass of the unknown solid increases, its density will also increase because the volume of the solid will increase, but the amount of space it occupies will not change.

The mass of the liquid is directly proportional to its volume. It means, as the volume of the liquid increases, its mass will also increase. Hence, we can predict that as the volume of the unknown liquid increases, its density will decrease because the mass of the liquid will increase, but the amount of space it occupies will also increase.

Therefore, we can conclude that the density of the unknown solid will increase with increasing mass, and the density of the unknown liquid will decrease with increasing volume.

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The empirical formula of caproic acid is [tex]C_4H_8O[/tex].

What is caproic acid? Caproic acid, also known as hexanoic acid, is a six-carbon, straight-chain fatty acid.

Caproic acid has a rancid odor and is commonly found in milk and other dairy items.

Caproic acid can be found in the milk of many mammals, including cows and goats.

What is the empirical formula of caproic acid? The following information was given: 0.225 g of caproic acid was burned, producing 0.512 g of [tex]CO_2[/tex] and 0.209 g of[tex]H_2O[/tex].

To solve the issue, you should start with the combustion reaction:

2 [tex]C_6H_1_2O_2[/tex] + 19 [tex]O_2[/tex] → 12 [tex]CO_2[/tex] + 12 [tex]H_2O[/tex]

The ratios of moles of [tex]CO_2[/tex] to moles of [tex]C_6H_1_2O_2[/tex] are 12:2, or 6:1, and the ratios of moles of [tex]H_2O[/tex] to moles of [tex]C_6H_1_2O_2[/tex] are 12:1, or 6:0.5. This signifies that the stoichiometry of the combustion reaction is [tex]C_6H_1_2O_2[/tex].

Start with the weight of [tex]CO_2[/tex]: 0.512 g/44.01 g/mol = 0.012 mol [tex]CO_2[/tex]

Weight of [tex]H_2O[/tex]: 0.209 g/18.02 g/mol = 0.012 mol [tex]H_2O[/tex]

Since the stoichiometric ratio of the combustion reaction is 1:1, the number of moles of [tex]C_6H_1_2O_2[/tex] must be equal to the number of moles of [tex]CO_2[/tex] or [tex]H_2O[/tex].

Therefore, [tex]C_6H_1_2O_2[/tex] is 0.012 mol. Divide the molar mass of [tex]C_6H_1_2O_2[/tex] by 0.012 mol to get the molecular mass of [tex]C_6H_1_2O_2[/tex]: 0.225 g/72.09 g/mol = 0.00312 mol.

The subscripts of [tex]C_4H_8O[/tex] can be determined by dividing the number of atoms in [tex][tex]C_6H_1_2O_2[/tex][/tex] by the greatest common factor of all subscripts.

Divide all by 0.00312 to obtain the empirical formula: [tex]C_4H_8O[/tex]

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320.45 grams of hydrazine are needed to produce 10.0 mol of nitrogen gas.

What is Hydrazine?

It is a colorless, flammable, and highly toxic liquid with an ammonia-like odor. Hydrazine is used in a variety of industrial applications, including as a rocket propellant, polymerization catalyst, and in the production of pesticides, pharmaceuticals, and other chemicals.

a. The balanced chemical equation for the reaction between hydrazine and hydrogen peroxide is:

N2H4 (l) + H2O2 (l) → N2 (g) + 2H2O (l)

b. To determine the amount of hydrazine required to produce 10.0 mol of nitrogen gas, we can use stoichiometry and the balanced chemical equation.

From the equation, we can see that 1 mole of N2 is produced for every mole of N2H4 consumed. Therefore, the amount of N2H4 required can be calculated as:

10.0 mol N2H4 / 1 mol N2 = 10.0 mol N2H4

To convert from moles of N2H4 to grams, we need to use the molar mass of N2H4, which is 32.045 g/mol. Therefore, the mass of N2H4 required can be calculated as:

10.0 mol N2H4 x 32.045 g/mol = 320.45 g

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Option B Ar is the correct answer, which is not isoelectronic with the others. Therefore, S2−, Sc3+, Ti4+, and Ga3+ are isoelectronic.

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The gas law that is employed to deflate a football is Boyle's law.

Boyle's law states that for a fixed amount of gas at a constant temperature, the pressure and volume of the gas are inversely proportional to each other. The equation for Boyle's law is:

[tex]P_{1} V_{1} /P_{2} V_{2}[/tex]

Where [tex]P_{1}[/tex] is the initial pressure of the gas, [tex]V_{1}[/tex]  is the initial volume of the gas,[tex]P_{2}[/tex] is the final pressure of the gas, and [tex]V_{2[/tex] is the final volume of the gas. In the case of deflating a football, the pressure of the air inside the football is reduced by letting some of the air out. The volume of the football decreases as the pressure decreases, and this is in accordance with Boyle's law.

Therefore, The Boyle's Law is used to deflate a football. It states that the volume of a gas is inversely proportional to its pressure, when the temperature is constant.

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The volume of H₂ gas produced from 1.30 g of Mg in excess HCl is 0.0019 L.

The balanced equation for the reaction of magnesium metal with HCl is:

Mg + 2HCl → MgCl₂ + H₂

The molar mass of Mg is 24.31 g/mol.

The mass of Mg that reacted = 1.30 g

The moles of Mg that reacted = 1.30 g ÷ 24.31 g/mol = 0.0535 mol

According to the balanced equation, 1 mol of Mg reacts with 1 mol of H₂

Therefore, 0.0535 mol of Mg will produce 0.0535 mol of H₂.

Since, the volume of gas produced is proportional to the number of moles of the gas, we can use the ideal gas equation to find the volume of H₂

PV = nRT

Where, P = 720 torr = 720/760 atm (1 atm = 760 torr)

T = 34 + 273 = 307 K

R = 0.0821 L·atm/mol·K

V = n × 0.0821 L·atm/mol·K × 307 K/ 720 torr = 0.0535 mol/ 720 torr × 25.2047 L/molK =0.0019 L

At 720 torr and 34 °C, 0.0535 mol of hydrogen occupies a volume of 0.0019 L.

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It's not true, no. The resultant solution will be unsaturated because it contains less KCl than the amount that will solubilize in 100 g of water at 40°C, which is 39 g, when 82 g of KCl is added to just 200 g of water.

The greatest quantity of solute that may dissolve in a given amount of solvent at a certain temperature and pressure to create a saturated solution is known as solubility. The solubility of KCl in this situation at 40°C is 39 g in 100 g of water. The solution will be unsaturated if 200 g of water are combined with 82 g of KCl at 40 °C. Because more KCl has been supplied than can dissolve in 200 g of water but less than can dissolve in 300 g of water, this has occurred (100 g for each 100 g of water).

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The technique of bioremediation involves using local microorganisms to absorb or degrade different parts of spilled oil in maritime environments.

Bacteria can be utilised to remediate oil spills in the marine through bioremediation. Hydrocarbons, which are found in oil and gasoline, are one type of specialised contamination that can be bioremediated using particular bacteria.

As a result of bioremediation, there is no longer a need to collect and shift the harmful substances to another location because natural organisms may convert the toxic molecules into harmless simple molecules (Venosa).

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Answer:

Bond enthalpy is always positive because energy is required to break chemical bonds. Energy is released when a bond forms between gaseous fragments.

Percentage by mass of chlorate 1 in calcium chlorate 1 is greater than the percentage by mass of chlorate 1 ions in Sodium chlorate.

An oxyanion is a polyatomic ion that contains at least one oxygen atom and one or more other elements, typically nonmetals. Examples of oxyanions include nitrate (NO3-), sulfate (SO42-), and phosphate (PO43-).

The molecular formula for calcium chlorate is Ca(ClO3)2, and the molecular formula for sodium chlorate is NaClO3.

To calculate the percentage by mass of chlorate 1 in calcium chlorate 1, we need to calculate the molar mass of Ca(ClO3)2 and the molar mass of chlorate 1.

Molar mass of Ca(ClO3)2 = 1 mol Ca + 2 mol ClO3

= 40.08 g/mol Ca + 2(35.45 g/mol Cl + 3(16.00 g/mol O))

= 238.06 g/mol

Molar mass of chlorate 1 = 35.45 g/mol Cl + 3(16.00 g/mol O)

= 99.45 g/mol

Now, we can calculate the percentage by mass of chlorate 1 in calcium chlorate 1:

% by mass of chlorate 1 in calcium chlorate 1 = (2 mol ClO3 x 99.45 g/mol) / (1 mol Ca(ClO3)2 x 238.06 g/mol) x 100%

= 83.3%

To calculate the percentage by mass of chlorate 1 in sodium chlorate, we only need to calculate the molar mass of NaClO3 and the molar mass of chlorate 1.

Molar mass of NaClO3 = 22.99 g/mol Na + 35.45 g/mol Cl + 3(16.00 g/mol O)

= 106.99 g/mol

Molar mass of chlorate 1 = 35.45 g/mol Cl + 3(16.00 g/mol O)

= 99.45 g/mol

Now, we can calculate the percentage by mass of chlorate 1 in sodium chlorate:

% by mass of chlorate 1 in sodium chlorate = (1 mol ClO3 x 99.45 g/mol) / (1 mol NaClO3 x 106.99 g/mol) x 100%

= 92.9%

Learn more about calcium chlorate here:

https://brainly.com/question/5923839

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