g(m) = m3 - 10m² + 25m + 2 at m = 6.

Answer: (4,-2)

Step-by-step explanation: step1.- -1/2x=-x+2 (solving for x) x=4

Step 2- y=-1/2x4(substitute the value of X)

Step 3- y=-1/2x4 (solve the equation for y) =2

Step 4- (x,y)=(4,-2) simplify —>(x,y)=(4,-2)

Answer:

a. 138 + x = 180

Step-by-step explanation:

Because the angles given are 69+69

which equal 138

and x being the missing angle

finally the total of all angles in a triangle = 180

Answer:

F=ma

Step-by-step explanation:

F is force and its measured in Newtons (N)

m is mass measured in kg

a is acceleration measured in metres per second per second

Answer:

A

Step-by-step explanation:

Answer:

=32x−24

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

The possible trigonometric function is option (C) [tex]sec \theta = \frac{3}{\sqrt{5} }[/tex] and [tex]tan \theta = \frac{-2}{\sqrt{5} }[/tex] is the correct answer.

Trigonometry is mainly concerned with specific functions of angles and their application to calculations. Trigonometry deals with the study of the relationship between the sides of a triangle (right-angled triangle) and its angles.

For the given situation,

The trigonometric function, sin θ = -2/3

We know that [tex]sin \theta = \frac{opposite}{hypotenuse}[/tex]

So, opposite = -2, hypotenuse = 3

The other side of the right triangle adjacent side can be found by using the Pythagoras theorem,

[tex]adjacent=\sqrt{hypotenuse^{2} -opposite^{2} }[/tex]

⇒ [tex]adjacent=\sqrt{3^{2} -(-2)^{2} }[/tex]

⇒ [tex]adjacent=\sqrt{9-4 }[/tex]

⇒ [tex]adjacent=\sqrt{5}[/tex]

Now, [tex]cos \theta = \frac{adjacent}{hypotenuse}[/tex] and [tex]tan \theta = \frac{opposite}{adjacent}[/tex]

Then, [tex]cos \theta = \frac{\sqrt{5} }{3}[/tex]

[tex]sec \theta = \frac{1}{cos \theta}[/tex]

⇒ [tex]sec \theta = \frac{1}{\frac{\sqrt{5} }{3} }[/tex]

⇒ [tex]sec \theta = \frac{3}{\sqrt{5} }[/tex]

[tex]tan \theta = \frac{-2}{\sqrt{5} }[/tex]

Hence we can conclude that the possible trigonometric function is option (C) [tex]sec \theta = \frac{3}{\sqrt{5} }[/tex] and [tex]tan \theta = \frac{-2}{\sqrt{5} }[/tex] is the correct answer.

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Answer:

The second one is right

The third one is wrong.

Answer:

pretty sure its d

Step-by-step explanation:

Answer:

A = -19

Step-by-step explanation:

Answer:

[tex]The~triangles~AED~and~ABC~are~similar.\\So,\\\frac{AD}{AB} = \frac{DE}{BC} [Corresponding~sides~of~similar~triangles~are~proportional.]\\or, \frac{30}{15} = \frac{34}{x} \\or, x = \frac{15(34)}{30} = 17inches[/tex]

Answer:

C i think but I could be wrong

Step-by-step explanation:

Answer:

45.50 (StartFraction 7 over 10 EndFraction) = n

Answer:

the correct answer on edge is B. 45.50=0.7n

Step-by-step explanation:

Answer:

360°

Step-by-step explanation:

Based on what I know that the total of degrees has to be 360°. So, two sides of the rhombus have to have two acute angles and two obtuse angles. So, the  Image shows that the 63° is an acute angle. So, multiply 63 by 2 which is 126. Then subtract 126 from 360 which is 234. Then, divide 234 by 2 which is 117. Lastly, add 63 with 63 and 117 with 117 which is 360.

Hopefully, you understand.

Answer:

Infinity

Step-by-step explanation:

x+8 = x+8

-x .      -x

8 = 8 = always true  

Answer:

[tex]84mm^{2} [/tex]

I think this is true

Answer = 84

BECAUSE

 8x6/2 for triangles (24)

 x2 bc two triangles (48)

6x6 for square (36)

add it all = (84)

Answer:

About $1627.5

Step-by-step explanation:

15.50 x 35 = 542.5

542.5 x 3 (the amount of weeks in a month) = $1627.5

Answer:

y=9

Step-by-step explanation:

6y=79-25

= 6y= 54

= y=54/6

= y= 9

Answer:

4mn+2m+2n+1

Step-by-step explanation:

Hope I helped!

Answer: 4mn+2n+1

2(2mn+m+2)+1

Step-by-step explanation:

Answer:

[tex]x=2y-4[/tex]

Step-by-step explanation:

[tex]y=\frac{1}{2} x+2[/tex]

"To make x the subject" means to have the equation with all the terms in x on one side. As of now, y is the subject of the equation.

You start by subtracting 2 from both sides, you should get the following.

[tex]y-2=\frac{1}{2} x[/tex]

Then you multiply by 2 from both sides, you should end up with the following.

[tex]2(y-2)=x[/tex]

Therefore, you get the following.

[tex]x=2(y-2)[/tex]

Finally, you distribute and get the answer.

[tex]x=2y-4[/tex]

Answer:

The answer is "717.25 minutes".

Step-by-step explanation:

In this question first, we arrange the value in ascending order that are:

307,311,321,322,354,363,377,406,425,435,461,464,474,499,505,513,517,534,548

The median is always in an orderly position that is [tex]= \frac{(n+1)}{2}[/tex].

[tex]\to \frac{(n+1)}{2} = \frac{(20+1)}{2} = 10.5[/tex]  position orders

[tex]10^{th} \ and \ 11^{th}[/tex] place an average of observations so, the

[tex]Average = \frac{(425 +435)}{2} = \frac{(860)}{2} =430[/tex]

Because as medium stands at 10.5 that median is as below 10 are greater than the level.

[tex]Q_1[/tex] often falls throughout the ordered BELOW average is [tex]= \frac{(n+1)}{2}[/tex] place.

[tex]\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}[/tex]ordered position

Average [tex]5^{th} \ and \ 6^{th}[/tex]  location findings

[tex]Q_1 = \frac{(354+363)}{2} = \frac{(717)}{2}= 358.5[/tex]

In  [tex]= \frac{(n+1)}{2}[/tex] the ordered place, Q3 always falls ABOVE the median.

[tex]\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}[/tex] ordered At median ABOVE 

Consequently [tex]Q_3[/tex] falls between [tex]5^{th} \ and \ 6^{th}[/tex] ABOVE the median position

[tex]15^{th}\ and \ 16^{th}[/tex]place average of observations

[tex]\to Q_3 = \frac{(499+505)}{2}=\frac{(1004)}{2} = 502[/tex]

[tex]\to IQR = Q_3 - Q_1= 502-358.5= 143.5[/tex]  

[tex]\to \text{Upper fence} = Q_3 + 1.5 \times IQR= 502 + 1.5 \times 143.5 = 717.25[/tex]

it would be A

Step-by-step explanation:

I'm good at math

$60 divided by 5 = $12

$12 per session.

Pls mark me brainliest!

Answer:$12 per session

Step-by-step explanation: divide 60 by 5 you get 12.

Answer:

the answer is:

a=-2

b=-4

Step-by-step explanation:

Shape P is translated to shape Q using vector [tex]\left[\begin{array}{ccc}2\\4\end{array}\right][/tex].

"A translation in math moves a shape left or right and/or up or down. The translated shapes look exactly the same size as the original shape, and hence the shapes are congruent to each other."

Given, the shape P is mentioned on the graph.

Now, shape P is translated to shape Q.

Therefore, in order to reach Q from P, the shape needs to shift to the left 2.

After that the shape needs to shift downwards 4 places.

Therefore, the required vector is [tex]\left[\begin{array}{ccc}2\\4\end{array}\right][/tex].

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Answer:

60 grams

Step-by-step explanation:

120 years / half-life of 30 years = it will grow half the size 4 times

960 * 1/2 ^ 4 = 960 * 1/2  * 1/2 * 1/2 * 1/2 = 60 grams

Answer:

cualeeeeeeeeeeeeeeeeeeeeees fffffleeeeeccccchhhhaaaasssss