Answers
Answer:
y=5, y=[tex]\frac{38}{11}[/tex]
Step-by-step explanation:
Hi there!
We are given the equation
[tex]\frac{y+2}{y-3}[/tex]+[tex]\frac{y-1}{y-4}[/tex]=[tex]\frac{15}{2}[/tex] and we need to solve for y
first, we need to find the domain, which is which is the set of values that y CANNOT be, as the denominator of the fractions cannot be 0
which means that y-3≠0, or y≠3, and y-4≠0, or y≠4
[tex]\frac{y+2}{y-3}[/tex] and [tex]\frac{y-1}{y-4}[/tex] are algebraic fractions, meaning that they are fractions (notice the fraction bar), but BOTH the numerator and denominator have algebraic expressions
Nonetheless, they are still fractions, and we need to add them.
To add fractions, we need to find a common denominator
One of the easiest ways to find a common denominator is to multiply the denominators of the fractions together
Let's do that here;
on [tex]\frac{y+2}{y-3}[/tex], multiply the numerator and denominator by y-4
[tex]\frac{(y+2)(y-4)}{(y-3)(y-4)}[/tex]; simplify by multiplying the binomials together using FOIL to get:
[tex]\frac{y^{2}-2y-8}{y^{2}-7y+12}[/tex]
Now on [tex]\frac{y-1}{y-4}[/tex], multiply the numerator and denominator by y-3
[tex]\frac{(y-1)(y-3)}{(y-4)(y-3)}[/tex]; simplify by multiplying the binomials together using FOIL to get:
[tex]\frac{y^{2}-4y+3}{y^{2}-7y+12}[/tex]
now add [tex]\frac{y^{2}-2y-8}{y^{2}-7y+12}[/tex] and [tex]\frac{y^{2}-4y+3}{y^{2}-7y+12}[/tex] together
Remember: since they have the same denominator, we add the numerators together
[tex]\frac{y^{2}-2y-8+y^{2}-4y+3}{y^{2}-7y+12}[/tex]
simplify by combining like terms
the result is:
[tex]\frac{2y^{2}-6y-5}{y^{2}-7y+12}[/tex]
remember, that's set equal to [tex]\frac{15}{2}[/tex]
here is our equation now:
[tex]\frac{2y^{2}-6y-5}{y^{2}-7y+12}[/tex]=[tex]\frac{15}{2}[/tex]
it is a proportion, so you may cross multiply
2(2y²-6y-5)=15(y²-7y+12)
do the distributive property
4y²-12y-10=15y²-105y+180
subtract 4y² from both sides
-12y-10=11y²-105y+180
add 12 y to both sides
-10=11y²-93y+180
add 10 to both sides
11y²-93y+190=0
now we have a quadratic equation
Let's solve this using the quadratic formula
Recall that the quadratic formula is y=(-b±√(b²-4ac))/2a, where a, b, and c are the coefficients of the numbers in a quadratic equation
in this case,
a=11
b=-93
c=190
substitute into the formula
y=(93±√(8649-4(11*190))/2*11
simplify the part under the radical
y=(93±√289)/22
take the square root of 289
y=(93±17)/22
split into 2 separate equations:
y=[tex]\frac{93+17}{22}[/tex]
y=[tex]\frac{110}{22}[/tex]
y=5
and:
y=[tex]\frac{93-17}{22}[/tex]
y=[tex]\frac{76}{22}[/tex]
y=[tex]\frac{38}{11}[/tex]
Both numbers work in this case (remember: the domain is y≠3, y≠4)
So the answer is:
y=5, y=[tex]\frac{38}{11}[/tex]
Hope this helps! :)
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Answers
Using it's concept, the probability that a student liking music given they already like art is of 10/17 = 0.5882 = 58.82%.
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2
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Answers
Answer:
x = 32°
Step-by-step explanation:
The two angles form a straight line, so therefore they are supplementary.
The sum of supplementary angles always equal 180°, so we know that:
(3x - 4) + (3x - 8) = 180°
Now you have the equation, solve for x.
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Make t the subject of this formula.
r = 7 (t + 3)
Answers
Answer:
t= r-21
7
Step-by-step explanation:
r = 7(t+3)
expanding the bracket
r = 7t + 21
bringing t to the left hand side
7t = r - 21
divide both sides by seven
t= r-21
7
Answer:
t = (r/7) - 3
Step-by-step explanation:
Given equation,
→ r = 7(t + 3)
Now the value of t will be,
→ r = 7(t + 3)
→ r = 7t + 21
→ r - 21 = 7t
→ 7t = r - 21
→ t = (r - 21)/7
→ t = (r/7) - 3
Hence, value of t is (r/7) - 3.
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Answers
which value of x is in the domain of f (x) =v x-7?
Answers
Answer:
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Step-by-step explanation:
We are given the following function:
[tex]f(x) = \sqrt{x - 7}[/tex]
Domain of the square root function:
The square root does not exist for negative values, so the domain of a square root function:
[tex]g(x) = \sqrt{h(x)}[/tex]
Is [tex]h(x) \geq 0[/tex]
In this question:
[tex]f(x) = \sqrt{x - 7}[/tex]
Then:
[tex]h(x) = x - 7[/tex]
[tex]x - 7 \geq 0[/tex]
[tex]x \geq 7[/tex]
The domain of the function are values of x that respect the following condition: [tex]x \geq 7[/tex]
Answer:
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Step-by-step explanation:
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Answers
Answer:
Step-by-step explanation:
This is already factored for us, which is really nice, so now all we need to do is apply the Zero Product Property to the sets of parenthesis and solve for x, which will give us the 2 times that the object is on the ground.
x + 1 = 0 so
x = -1
x - 9 = 0 so
x = 9
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Answers
Step-by-step explanation:
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Answer:
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Pre-Algebra
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Answer:
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Step-by-step explanation:
Answer:
(x - 8)²
Step-by-step explanation:
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Then
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Answers
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Step-by-step explanation:
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Answers
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Step-by-step explanation:
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Answers
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Step-by-step explanation:
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The sum of two non-zero even numbers is even and greater than the addends.
The difference of two non-zero even numbers is odd and less than the larger number.
The difference of two non-zero even numbers is odd and greater than the larger number.
Answers
Answer:
The sum of two non-zero even numbers is even and greater than the addends
Step-by-step explanation:
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Answers
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Step-by-step explanation:
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Answers
Answer:
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Answers
Step-by-step explanation:
Here,
y= 2x
and x € (1,2,3)
now,
when x=1 , when x=2 , when x= 3
y=2x y= 2x y=2x
= 2×1 = 2×2 = 2×3
= 2 = 4 = 6
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252cm. Twice the man's height added to the height
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Answers
Answer:
son weight = 72
Step-by-step explanation:
D + S = 180
D + 2S = 252
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S = 72
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Answers
Answer:
A
Step-by-step explanation:
A
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the highest exponent of x is 2
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Answer:
option A
Step-by-step explanation:
A quadratic equation is a single variable polynomial of degree 2.
[tex]A ) y = ( x + 2)(2x-3) = 2x^2 -3x +4x - 6 =2x^2 + x - 6 \ - Yes \\\\B) y = 3(x - 4) \ - No\\\\C) y = \frac{1}{x^2} \ - No\\\\D) y = x(x-4)(x+3) = x(x^2 -x - 12) = x^3 -x^2 - 12x \ - No[/tex]
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Answers
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Answer:
(B). 265 miles
Step-by-step explanation:
She travelled 75 mph for 3 hours and 40 mph for 1 hour.
Therefore, 75 + 75 + 75 + 40 = 265 miles
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Answer:
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Answer:
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Step-by-step explanation:
half half
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Answer:
Step-by-step explanation:
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Answer:
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Answers
Answer:
12cm
Step-by-step explanation:
Area of square = Area of rectangle
Area of square = length x breadth
Area of square = 9 x 16 = 144(cm)^2
(side)^2 = 144
side = √144
side = 12cm
12cm
Step-by-step explanation:
area of square=area of rectangle
s^2=L*W
area of rectangle=length * width
area of rectangle=9cm*16cm=144cm^2
s^2 =144cm^2
s=12 cm
the cost for renting a car is $29.00 a day plus $0.29 for every kilometre after the first 100 km. what is the cost of renting a car after 14 days and 320 km?
(linear equations)
Answers
Answer:
$469.80
Step-by-step explanation:
First, let's find out how many fees would be paid exclusively for renting it out for 14 days.
29.00 * 14 = $406
They have to pay 406 dollars just for having the car for 14 days.
Now let's find out how much will need to paid for driving for 320 km.
We can first take away 100 km because the fee only starts afterwards.
320 - 100 = 220
220 * 0.29 = 63.8
63.80 + 406 = 469.80