. has endpoints B(5, 9) and C(–4, –3). Find the coordinates of the midpoint of . (0.5, 1.5) (1, 3) (0.5, 3) (1, 6)

Answer:

Let's define:

S as the rate at which Sara can weed a garden.

We know that:

S*30min = 1 garden

And let's define H as the rate at which Hamdan can weed a garden, we know that when they work together, they can complete the job in 20 minutes, then

(S + H)*20min = 1 garden

a) Here we get:

H*n = 1 garden

where n is the number of hours that he would take (note that in two previous equations we have minutes, so we need to use a change of units)

b) The equation is

(S + H)*20min = 1 garden

c) ok, we know two things:

(S + H)*20min = 1 garden

S*30min = 1 garden

first, let's convert both times to hours:

60 min = 1 hour

then:

30 min = (30/60) hours = 0.5 hours

20 min = (20/60) hours = 0.33 hours

Then the equations become:

(S + H)*0.33 hours = 1 garden

S*0.5 hours = 1 garden

Le's solve the second equation for S:

S = (1 garden /0,5 hours) = 2 gardens/hour.

Now we can replace this in the other equation to get:

(2 garden/hour + H)*0.33 hours = 1 garden

2 garden/hour + H = (1 garden)/(0.33 hours) = 3 gardens/ hour

H = 3 gardens/hour - 2 gardens/hour = 1 gardens/hour

This means that the rate of Hamdan is 1 gardens/hour, so he can weed a garden in one hour.

Then:

(1 garden/hour)*n = 1 garden

n = ( 1 garden)/((1 garden/hour)) = 1 hour

Answer:

B.

3m - 11 = 2m + 9

Amount Maddie earns = m = $20

Step-by-step explanation:

Let

Amount Maddie earns = m

Amount Lauren earns = 3m - 11

Amount Shannon earns = 2m + 9

If Lauren and Shannon both earned the same amount of money, how much money, m, did Maddie earn?

Amount Lauren earns = Amount Shannon earns

3m - 11 = 2m + 9

Collect like terms

3m - 2m = 9 + 11

m = 20

Amount Maddie earns = m = $20

B.

3m - 11 = 2m + 9

Answer:

d) x + 3

Step-by-step explanation:

= x² + 5x + 6

Factorise :-

= x² + 2x + 3x + 6

= x(x + 2) + 3(x + 2)

= (x + 2)(x + 3) [Taking common]

Here we are getting (x + 3) as a factor of x² + 5x + 6 which will be either length or the width

Answer:

all positive real numbers, (0, ∞)

Step-by-step explanation:

The log function is not defined for 0 or for negative numbers.

The domain of the log function is all positive real numbers.

Answer: all positive real numbers

Answer:

Vertex is (-a, -6), where a ≠ 0.

General Formulas and Concepts:

Algebra I

Algebra II

Vertex Form: y = a(bx - h)² + k

Step-by-step explanation:

Step 1: Define

y = -3(x + a)² - 6

↓ Identify variables

a = -3

b = 1

(h, k) = (-a, -6)

Answer:

The outcomes produced by A would be greater than B. A further explanation is provided below.

Step-by-step explanation:

Given:

In process A,

Produced units = [tex]32x^{1.5}[/tex]

In process B,

Produced units = [tex]4x^3[/tex]

If the outcomes are equivalent then,

⇒ [tex]32x^{1.5}=4x^3[/tex]

⇒     [tex]x^{1.5} = 8[/tex]

By taking log both  sides, we get

⇒    [tex]log \ 8= 1.5 \ log \ x[/tex]

⇒          [tex]x=3.99[/tex]

Answer:

[tex]m^{\frac{1}{2} }[/tex] . [tex]n^{\frac{1}{2} }[/tex]

Step-by-step explanation:

Using the rules of exponents/ radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]

[tex]\sqrt{a}[/tex] = [tex]a^{\frac{1}{2} }[/tex]

Given

[tex]\sqrt{mn}[/tex]

= [tex]\sqrt{m}[/tex] × [tex]\sqrt{n}[/tex]

= [tex]m^{\frac{1}{2} }[/tex] . [tex]n^{\frac{1}{2} }[/tex]

Answer:

[tex] {(mn)}^{ \frac{1}{2} } \\ {m}^{ \frac{1}{2} } {n}^{ \frac{1}{2} } [/tex]

Answer:

5.4 units

Step-by-step explanation:

Hi there!

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex] where two given points are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

Plug in the given points (1,5) and (3,0)

[tex]d=\sqrt{(3-1)^2+(0-5)^2}\\d=\sqrt{(2)^2+(-5)^2}\\d=\sqrt{4+25}\\d=\sqrt{29}\\d=5.4[/tex]

Therefore, the distance between the two points when rounded to the nearest tenth is 5.4 units.

I hope this helps!

Answer:

The factor is polynomial

Step-by-step explanation:

trust me broski

Answer:

[tex]7[/tex]

Solution:

This is a linear function. This means means that r is our rate of change.

To find r recal following formula

[tex]r=\frac{\Delta y}{\Delta x} = \frac{y_2-y_1}{x_2-x_1}[/tex]

Since this is a linear function we can choose any two points. I will choose the first two for simplicity

[tex]\Displaystyle \therefore r = \frac{42-14}{6-2}=\frac{28}{4}=7[/tex]

Complete question:

4x³ - 4x + 3 is divided by (2x - 1). Find the quotient and the remainder

Answer:

The quotient =  2x² +  x  - ³/₂  and the remainder = ³/₂

Step-by-step explanation:

Given function;

4x³ - 4x + 3 divided by (2x-1)

Use long division method to obtain the remainder and the quotient.

                               2x² +  x  - ³/₂

                            -----------------------

                 2x - 1 √4x³ - 4x + 3

                           - (4x³ - 2x²)

                           ----------------------------

                                    2x²  - 4x + 3

                                 - ( 2x² - x)

                             -----------------------------

                                        -3x + 3

                                      -(-3x + ³/₂)

                               ----------------------------

                                            ³/₂

Therefore, the quotient =  2x² +  x  - ³/₂  and the remainder = ³/₂

Answer:

In other words y = 2-x

Put in some values of x and see which graph matches the given ys.

The last graph

Answer:

b

Step-by-step explanation:

Answer:

113.04 is the answer

Step-by-step explanation:

Use the formula for finding the area of a circle.

Area= pi times radius to the second power.

First you had to divide your diameter by 2 to get 6. Then 6 squared, to get 36. Then finally 36x3.14.

Answer:

Each term is 4 less than the previous term.

Step-by-step explanation:

If this helps you mark as brainlist!

Answer:

B and D are your answers for that whole page

Step-by-step explanation:

Identify the rule that correctly describes each sequence.

12, 8, 4, 0, –4, …

Each term is 4 more than the previous term.

This Is the right one: Each term is 4 less than the previous term.

Each term is 1/2 the previous term.

Each term is 2/3 the previous term.

6, 12, 24, 48, 96, …

Each term is 6 more than the previous term.

Each term is 12 more than the previous term.

Each term is 1/2 the previous term.

This is the right one: Each term is 2 times the previous term.

Answer: Graph A

Step-by-step explanation:

Answer:

x = 1, -5.56

Step-by-step explanation:

x^2 = -7x - 8

shift -7x and -8 to the other side . Remember when u shift minus changes into plus.

x^2 + 7x + 8 = 0

using quadratic equation formula

in quadratic equation one value comes positive and other comes in negative

a = 1  , b = 7 and c = 8

taking positive sign

x = (-b + [tex]\sqrt{b^2 - 4*a*c}[/tex]) /2*a

x = (-7 + [tex]\sqrt{7^2 - 4*1*8}[/tex] ) /2*1

x = (-7 + [tex]\sqrt{49 + 32}[/tex] ) /2

x = (-7 + [tex]\sqrt{81}[/tex] )/ 2

x = -7 + 9 / 2

x = 2/2

x = 1

taking negative sign

(-b - [tex]\sqrt{b^2 - 4*a*c}[/tex] ) /2*a

x = (-7 - [tex]\sqrt{7^2 - 4*1*8}[/tex] ) /2*1

x = (-7 - [tex]\sqrt{49 - 32}[/tex] ) /2

x = -7 - [tex]\sqrt{17}[/tex] / 2

x = -7 - 4.12 / 2

x = -11.12/2

x = -5.56

therefore x = 1 , - 5.56

Answer:

[tex]x = \frac{- 7 + \sqrt{17}}{2} \ , \ x = \frac{-7 - \sqrt{17}}{2}[/tex]

Step-by-step explanation:

[tex]x^2 = - 7x - 8\\\\x^2 + 7x + 8 = 0 \\\\[/tex]

[tex]x = \frac{- b \pm \sqrt{b^2 - 4ac}}{2a}\\\\[/tex]               [tex][ \ a = 1 , \ b = 7 , \ c = 8 \ ][/tex]

[tex]x = \frac{-7 \pm \sqrt{49 - (4\times 8)}}{2} \\\\x = \frac{-7 \pm \sqrt{17}}{2} \\\\x = \frac{-7 + \sqrt{17}}{2} , \ , \frac{-7 - \sqrt{17}}{2}[/tex]

The fundamental counting principle is used to count the total number of possible outcomes that are in a situation.

The fundamental counting principle states that if there are n ways of doing something, as well as m ways of doing another thing, then there are n×m ways to perform both of these actions.

The Fundamental Counting Principle helps when determining the sample space of probability as it figures out the total number of ways the combination of events can occur. Therefore, it is used as a guide when determining the sample space of a probability.

Lastly, the limitation is that the Fundamental Counting Principle is that it assumes that each basic event is equally probable, which does not necessarily have to be true.

Learn more about counting principle on:

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Answer:

The fundamental counting principle is used to count the total number of possible outcomes that are in a situation

Step-by-step explanation:

Answer:

See explanation

Step-by-step explanation:  

(Please Find Diagram in the attachment)⇒Answer Drawing is Given There

According to the question,

Answer: Choice C

Yes, holidays are a subset and proper subset of the calendar year.

=========================================================

Explanation:

The set of days in the calendar year spans from Jan 1st to Dec 31st.

The set of holidays is a small subset of the previous set mentioned. Any holiday is found on the calendar, but not every day on the calendar is a holiday.

------------

Here's another example of a subset

A = set of all animals

B = set of dogs

Set B is a subset of set A because any dog is an animal. In other words, any individual in set B is also in set A, but not the other way around.

------------

Going back to the calendar example, the set of holidays is a subset and it's also a proper subset of all the days in the year. We say that set B is a proper subset of set A if B has less items in it compared to A.

If we had these two sets

A = {1,2,3,4,5,6}

B = {1,2,3}

We can see that B is a proper subset of set A since everything in B is found in A, and B is smaller than A. The only time we have a subset and not a proper subset is when we talk about the set itself. Any set is a subset of itself (not a proper subset of itself).

The True statement is

Yes, holidays are a subset and proper subset of the calendar year.

Sets are represented as a collection of well-defined objects or elements that are consistent from one person to the next. A capital letter represents a set. The cardinal number of a set is the number of items in a finite set.

The order of a set determines the number of elements in the set. It refers to the size of a set. The order of the set is often referred to as the cardinality.

The set of days in the calendar year spans from Jan 1st to Dec 31st.

The set of holidays is a subset of the previously described set. Any holiday can be found on the calendar, however not every day is a holiday.

let Set B is a Proper subset of set A if it contains fewer elements than A.

So, A = {1,2,3,4,5,6}

B = {1,2,3}

We can see that B is a proper subset of set A since everything in B is found in A, and B is smaller than A.

So, holidays are a subset and proper subset of the calendar year.

Learn more about Set here:

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Answer:

Step-by-step explanation:

Answer:

A. x + 5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \frac{x^2 - 25}{x - 5}[/tex]

Step 2: Simplify

Answer:

please mark as brilliant

Answer:

Step-by-step explanation:

736

Answer:ln is called the natural log, or log to the base e. ln can also be written as

So, we can write the given expression as

The property of logs is:

This mean if the number a is raised to log whose base is the same as the number a itself, then the answer will be equal to the argument of the log which is x.

In the given case, the number e and the base of log are the same. So the answer of the expression will be the argument of log which is 6.

so, we can write

Thus, the correct answer is option D

Step-by-step explanation:

Step-by-step explanation:

three solutions of the equation:

y = -2x - 1

=>

1) (0, -1)

2) (1, -3)

3) ( -1, 1)

the diagram isn't available.Please fix that