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Answer:

30

Explanation:

Plug in p to get 4(8) - 2

32 - 2 = 30

Answer:

Choice a. Approximately [tex]0.83\; \rm A[/tex] on average.

Explanation:

The electric current through a wire is the rate at which electric charge flows through a cross-section of this wire.

Assume that electric charge of size [tex]Q[/tex] flowed through a wire cross-section over a period of time [tex]t[/tex]. The average current in that wire would be:

[tex]\displaystyle I = \frac{Q}{t}[/tex].

For this question:

Therefore, the average current in this circuit would be:

[tex]\displaystyle I = \frac{Q}{t} = \frac{500\; \rm C}{10\; \text{minutes}} = 50\; \rm C /\text{minute}[/tex].

However, the units in the choices are all in [tex]\rm A[/tex] (for Amperes.) One Ampere is equal to one [tex]\rm C / \text{second}[/tex]. It will take some unit conversations to change the unit of [tex]I = 50\; \rm C/ \text{minute}[/tex] (coulombs-per-minute) to coulombs-per-second.

[tex]\begin{aligned}I &= 50\; \rm C/ \text{minute} \\ &= \frac{50\; \rm C}{1\; \rm \text{minute}} \times \frac{1 \; \text{minute}}{60\; \rm \text{seconds}} \approx 0.83\; \rm C/ \text{second} = 0.83 \; \rm A\end{aligned}[/tex].

Hence, the most accurate choice here would be choice a.

Answer:

Low

Explanation:

Radio waves have photons with the lowest energies.

Answer:

3.1 m/s²

Explanation:

Apply Newton's second law:

∑F = ma

40 N = (13 kg) a

a ≈ 3.1 m/s²

Answer:

10.2 % efficiency.

Explanation:

Percent efficiency formula: (output / input) * 100%

The output energy (in Joules) is how much was used eventually. - It is 10 J

The input energy (in Joules) is how much energy was put into the lightbulb initially. It is 98 J

(10 J / 98 J) * 100% = 10.2 % efficiency.

Answer:

a. Muscular endurance

is correct answer

please mark me as brainliest

(a) The average kinetic energy of a molecule of an ideal gas is 6.21 x 10⁻²¹ J.

(b) The total random kinetic energy of the molecule in 1 mole of this gas is 3,741.3 J.

(c) The RMS speed of the oxygen molecule is 215.25 m/s.

The average kinetic energy of a molecule of an ideal gas is calculated as follows;

[tex]K .E = \frac{3}{2} K T[/tex]

Where;

[tex]K.E = \frac{3}{2} \times (1.38 066 \times 10^{-23}) \times 300\\\\K.E = 6.21 \times 10^{-21} \ J[/tex]

The total random kinetic energy of the molecule in 1 mole of this gas is calculated as follows;

[tex]K.E = \frac{3}{2} nRT\\\\K.E = \frac{3}{2} (1) (8.314)(300)\\\\K.E = 3,741.3 \ J[/tex]

The RMS speed of the oxygen molecule is calculated as follows;

[tex]K.E = \frac{1}{2} mV_{rms}^2\\\\V_{rms}^2 = \frac{2K.E}{m} \\\\V_{rms} = \sqrt{\frac{2 K.E}{m} }[/tex]

one mole of oxygen gas = 32 g = 0.032 kg

[tex]V_{rms} = \sqrt{\frac{2 \times 741.3 }{0.032} }\\\\V_{rms} = 215.25 \ m/s[/tex]

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Answer:

Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.

Explanation:

sorry if this is wrong or is incorrect... but at least I tried right.

Answer:

As per Provided Information

Distance travelled by motorcycle is 420 miles

Time taken by motorcycle is 8.5 hours

we have been asked to determine the average speed of the motorcycle .

[tex] \bf \: Speed_{(Average)} = \cfrac{total \: distance \: travelled}{time \: taken} [/tex]

Now let's put the given value to find the average speed of motorcycle

[tex] \longrightarrow \sf \: Speed_{(Average)} \: = \cfrac{420}{8.5} \\ \\ \\ \longrightarrow \sf \: Speed_{(Average)} \: = \cfrac{4200}{85} \\ \\ \\ \longrightarrow \sf \: Speed_{(Average)} \: = \cancel\cfrac{4200}{85} \\ \\ \\ \longrightarrow \sf \: Speed_{(Average)} \: = 49.41 \: miles \: per \: hour[/tex]

Therefore,

Answer:

150 km/h

Explanation:

It is given that,

Speed of a bus is 100 km/h and it can carry a maximum of 6 persons.

If speed of bus decreases in fixed proportion with increase in number of person, then we need to find the speed when 3 person are traveling in bus.​

6 person = 100 km/h

1 person = (100/6) km/h

Ans

3 person = [tex]\dfrac{100}{6}\times 3=50\ km/h[/tex]

Net speed = 100 km/h + 50 km/h = 150 km/h

Hence, if the required speed is 150 km/h.

Answer:

plenty of exercise

Explanation:

If you are unhealthy or not happy with yourself. try this. Do a 30 minute walk everyday and eat normal amounts of food portions a human should have an in a day. Make sure you drink plenty of water. If that doesn't work maybe taking to someone about it and see what information they have for you. These things do work because i was over weight and lost 73 pound just by doing those few things.

Answer:

D lithosphere colliding

Reason:

Image result for what causes the formation of trenches in Earth’s crust

Trenches are formed by subduction, a geophysical process in which two or more of Earth's tectonic plates converge and the older, denser plate is pushed beneath the lighter plate and deep into the mantle, causing the seafloor and outermost crust (the lithosphere) to bend and form a steep, V-shaped depression.

The formation of trenches in Earth's crust is caused by the collision of lithospheric plates, so the correct answer is "lithosphere colliding."

Trenches are long, narrow depressions or canyons in the Earth's crust that form at subduction zones, where one lithospheric plate is forced beneath another plate into the Earth's mantle. Trenches are primarily found on the ocean floor, where they can be several kilometers deep and hundreds of kilometers long.

Trenches are formed by the process of subduction, which occurs when one tectonic plate moves beneath another plate. As the denser plate sinks into the mantle, it creates a deep trench in the ocean floor. This process is associated with volcanic activity, as the sinking plate often triggers the melting of rock in the mantle, which can then rise to the surface and form volcanic islands or arcs.

Trenches are important features of the Earth's crust because they provide evidence for the movement and interaction of tectonic plates over time. Additionally, they are often associated with earthquakes and can serve as warning signs of potential seismic hazards in the surrounding region.

Therefore, lithosphere colliding causes the formation of trenches in Earth’s crust.

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Answer: a = 30 m/s^2

t = .33 s

Explanation:

(v final)^2 = (v initial)^2 + 2*a*d → 20^2 = 10^2 + (2)(a)(5) → a = 30 m/s^2

Acceleration = change in velocity / time → 30 = (20 - 10) / t → t = .33 s :)

The range of force exerted at the end of the rope is 285.7 N to 1,000 N.

The net horizontal force of the cylinder when it is at equilibrium position is determined by applying Newton's second law of motion.

∑F = 0

F - μFn = 0

F - 0.2(5,000) = 0

F - 1,000 = 0

F = 1,000 N

The strength of the applied force increases as the number of turns of the rope increases.

minimum force = total force/number of turns of rope

minimum force = 1,000/3.5

minimum force = 285.7 N

Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.

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Answer:

Parallelogram law of vector addition states that. if two vectors are considered to be the adjacent sides of a parallelogram, then the resultant of the two vectors is given by the vector that is diagonal passing through the point of contact of two vectors.

Answer:

Most likely 2ft

Explanation:

Your arm aint that long

Answer:

The atomic number uniquely identifies a chemical element. It is identical to the charge number of the nucleus. In an uncharged atom, the atomic number is also equal to the number of electrons. The sum of the atomic number Z and the number of neutrons N gives the mass number A of an atom.

Explanation:

Answer:

I believe that the atomic number of an atom represents the number of protons in one atom of an element. It also tells you the number of electrons in a neutral atom of that element

Explanation:I hope that this is helpful.

Answer:

Explanation:

To solve this problem we need to know the direction in which the ball was moving to start with.

The answer will be different depending n the original angle of the ball's movement.

It might be reasonable to assume that the ball is meant to approach along the x-axis,

but if so, the initial speed of 6.42m/s would be irrelevant to the answer.

So I will solve the problem for the general case of two objects colliding at arbitrary angles, and

tell you how to specialize it for any assumption about the initial conditions.

Let

m1 = 7.5 kg be the mass of the ball,

m2 = 1.6 kg be the mass of the pin,

v1 = 6.42 m/s be the velocity of the ball before the strike,

v2 = 0 m/s be the velocity of the pin before the strike,

α1 be the angle of v1,

α2 be the angle of v2,

w1 be the velocity of the ball after the strike,

w2 = 14.8 m/s be the velocity of the pin after the strike,

β1 be the angle of w1,

β2 = -47° be the angle of w2.

By conservation of momentum:

m1v1 + m2v2 = m1w1 + m2w2

Since the velocities are vectors, the addition is vector addition, and the equality is vector equality.

"Vector equality" means that the x-coordinates are equal and the y-coordinates are equal.

The problem cares only about y-coordinates, specifically the y-coordinate of w1, which is w1sin(β1).

(In general, the y-coordinate of any vector is obtained by multiplying the vector's norm by the sine of its angle.)

Conservation of momentum in the y-coordinate is then

m1v1sin(α1) + m2v2sin(α2) = m1w1sin(β1) + m2w2sin(β2)

Expressing the sought quantity

w1sin(β1) = (m1v1sin(α1) + m2v2sin(α2) - m2w2sin(β2))/m1

Substituting known quantities:

w1sin(β1) = (7.5×6.42×sin(α1) + 1.6×0×sin(α2) - 1.6×14.8×sin(-47°))/7.5

= (48.15×sin(α1) + 17.3)/7.5

In the above expression we do not know α1.

If we assume that the ball is approaching along the x-axis then α1 = 0, and

w1sin(β1) = 17.3/7.5 = 2.3

Under that assumption the y-component of the ball's final velocity is 2.3 m/s;

being positive, it is opposite the direction of the pin.

Answer:

potential lines that are perpendicular to the electric field, they must be parallel to the plates

Explanation:

A and C) for this drawing, as the electric field lines go from the positive plate to the negative plate and are horizontal to the potential lines that are perpendicular to the field, they must be parallel to the plates, see attached part a

B) in this case the ground has an energy of zero and the lines are parallel to the ground, see attached part b

Answer:

same velocity

Explanation:

energy is conserved-

KE=PE

The flow speed of the fluid in the second section of the pipe is 0.98 m/s

Flow speed is the rate at which the distance of a fluid changes with respect to time as it moves in a pipe.

To calculate the flow speed in the second section, we use the formula below.

Formula:

Where:

Make V' the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, The flow speed of the fluid in the second section of the pipe is 0.98 m/s

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The effect of black papper on the field is that the black paper have a form of chimney effect. Thid is because the black paper heat up the space between the field and the body in order to allow an upward air current like a chimney. This air current adds to the cooling of the field.

Black paper absorb heat from the surrounding and generate it to current flow in the field.

A field refer to a egion in which each point has a physical quantity like time or gravitational or space which are connected and associated with the region.

Therefore, the black paper allow air current flow.

Learn more about field from the link below.

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Answer:

6.75m

Explanation:

To calculate the distance in this question, we can use the formula:

S = ut + 1/2at^2

Where; S = distance

u = initial velocity = 0m/s

t = 3s

a = 1.5m/s^2

Hence:

S = (0 × 3) + 1/2 (1.5 × 3 × 3)

S = 0 + 1/2 (13.5)

S = 13.5/2

S = 6.75

Therefore, the car will travel 6.75m in 3seconds.

To find the distance traveled by the car in 3 seconds is equal to 6.75 meters.

Given the following data:

To find the distance traveled by the car in 3 seconds, we would apply the second equation of motion:

Mathematically, the second equation of motion is given by the formula;

[tex]S=ut +\frac{1}{2} at^2[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]S=0(3) +\frac{1}{2} \times 1.5 \times 3^2\\\\S=\frac{1}{2} \times 1.5 \times 9\\\\S = 1.5 \times 4.5[/tex]

Distance, S = 6.75 meters.

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Time required to complete 60m:-

[tex]\\ \rm\longmapsto s=1/2at^2[/tex]

[tex]\\ \rm\longmapsto 60=1.99/2t^2[/tex]

[tex]\\ \rm\longmapsto 120=1.99t^2[/tex]

[tex]\\ \rm\longmapsto t^2=60.3[/tex]

[tex]\\ \rm\longmapsto t\approx 7.7s[/tex]

Time taken to complete last 40m

[tex]\\ \rm\longmapsto 80=-0.266t^2[/tex]

[tex]\\ \rm\longmapsto t^2=300.75[/tex]

[tex]\\ \rm\longmapsto t\approx 17.3s[/tex]

Total time:-

Answer:

Explanation:

Two kinematics equation

v = u + at

and

s = ut + 1/2(at^2)

where u is initial velocity, v is final velocity, a is acceleration, t is time and s is displacement.

For the first 60m, initial velocity is 0 and acceleration is 1.99.

60 = 0 + 1/2(1.99)t^2

t^2 = 120/1.99

t = 7.765s

Velocity at 60m = 0 + 1.99(7.765) = 15.453 m/s

For the final 40m, initial velocity = 15.453, acceleration is -0.266.

40 = 15.453t' + 1/2(-0.266)t'^2

0.133t'^2 - 15.453t' + 40 = 0

Using the quadratic formula, t' = 2.649s or 113.54s

The solution of 113.54s represents someone running pass the finish line and continuing the deceleration until one runs backwards to the finish line again. So that solution should be rejected.

The total time taken = 7.765 + 2.649

= 10.414s

Answer: the acceleration is (g( 1 - sinθ)) / 2

Explanation:

the tension in one bag is expressed as;

T = ma + mg sin θ ........................lets say equ 1

now the tension in another bag is expressed as;

T = -ma + mg..................lets say equ 2

so equate both equations

ma + mg sinθ = -ma + mg

2ma =  mg ( 1 - sinθ)

a = (g( 1 - sinθ)) / 2

therefore the acceleration is (g( 1 - sinθ)) / 2

Answer:

304.87 m/s

Explanation:

v2 = v1 × √T2÷√T2

v2 = 330 × √233÷√273

v2 = 304.87 m/s

Answer:

False

Explanation:

energy in terms I've heard at least energy cannot be created or destroyed