[tex]~~~~~~~~~~~~\stackrel{\textit{payments at the beginning of the period}}{\textit{Future Value of an annuity due}}\\ ~~~~~~~~~~~~ \\\\ A=pmt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]\left(1+\frac{r}{n}\right)[/tex]
[tex]\begin{cases} A=\textit{accumulated amount} \\ pmt=\textit{periodic payments}\dotfill &1700\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=1700\left[ \cfrac{\left( 1+\frac{0.04}{1} \right)^{1\cdot 5}-1}{\frac{0.04}{1}} \right]\left(1+\frac{0.04}{1}\right) \\\\\\ A=1700\left( \cfrac{1.04^5~~ - ~~1}{0.04} \right)(1.04)\implies A\approx 9576.06[/tex]
can someone please help me
Answer:
y = x - 5
Step-by-step explanation:
Line A
It has 1/2 the slope of Line BIts y-intercept is 2 x 2.5 spaces belowEquation
Line A ⇒ y = 1/2(2x) + 2(-2.5)Line A ⇒ y = x - 5Solve this linear system using determinants:
2x + 3y = 6
- 8x - 3y = 12
A=
Az =
[Ayl =
2×+3y=6
-8×-3y=12
-6×=18
×=18/-6
×=-3
——————
2×+3y=6
2(3)+3y=6
6+3y=6
3y=6-6
3y=0
Y=0/3
Y=0
——————
×=3
Y=0
————
2×+3y=6
2(3)+3(0)=6
6=6
xLasersx✨Pls help!!
Question:
The polynomial f (x) = ax2 + bx + c has zeros 4 and 5, and f (−1) = 60. Evaluate a, b and c.
a = 2, b = -18, c = 40
Step-by-step explanation:[tex]Given:\ Polynomial\ f(x)=ax^2+bx+c\ has\ zoroes\ 4\ aud\ 5[/tex]
[tex]and\ f(-1)=60[/tex]
[tex]Tofind:\ a,\ b,\ c[/tex]
[tex]Solution:\ As\ 4\ and\ 5\ are\ zeroes\ so\ f(4)=f(5)=0[/tex]
[tex]f(4)=a(4)^2+b(4)+c=0\Rightarrow16a+4b+c=0-(1)[/tex]
[tex]f(5)=a(5)^2+b(5)+c=0\Rightarrow25a+5b+c=0[/tex]
[tex]f(-1)=a(-1)^2+b(-1)+c=60\Rightarrowa-b+c=60-(3)[/tex]
[tex]subtracting\ (1)\ from\ (2)[/tex]
[tex]25a+5b+c-(16a+4b+c)=0\Rightarrow9a+b=0\Rightarrowb=-9a[/tex]
[tex]subtracting\ (3)\ from(2):[/tex]
[tex]25a+5b+c-(a-b+c)=0-60\Rightarrow24a+6b=-60[/tex]
[tex]putting\ b=-9a[/tex]
[tex]24a+6(-9a)=-60\Rightarrow24a-54a=-60\Rightarrow-30a=-60[/tex]
[tex]a=\frac{-60}{-30}=2[/tex] [tex]\Rightarrow[/tex] [tex]a=2[/tex]
[tex]b=-9a=-9\times2=-18[/tex]
[tex]c=-a+b\neq60=-2-18+60=-20+60=40[/tex]
I hope this helps you
:)
Marvin is saving $5.25 a week to buy a new video game that costs 69.15. How many
weeks will he have to save to buy the game?
Answer: 10.62 irrational
Step-by-step explanation: You can divide 69.15 by 5.25 which equals 74.4 then divide by 7 which equals 10.62
Joey has 23 cards in his baseball card collection. Monica has 24 cards in her collection. How many times more cards does Monica have than Joe?
Answer:
Monica has 1 more card than Joey
Step-by-step explanation:
its simple math
If the area of a circle is 64 pie square centimeters, then what is its radius
Answer:
8
Step-by-step explanation:
A=πr^2
64π=πr^2
since answer is in terms of pi, ignore the pi.
sqrt(64)=8
can someone please help!!
I need the answer and explanation pls
Step-by-step explanation:
percentage of green marbles=
(total green marbles÷ total marbles )×100
f the last 18 trains to pull into Castroville Station, 12 were full. Considering this data, how many of the next 12 trains would you expect to be full?
Answer:
8
Step-by-step explanation:
first multiple 12 by 12 then divide by 18 then you'll get 2 times 4 and that's how you get 8.
Last one i promise but i need help
Answer:
a
Step-by-step explanation:
Find the common factor of all the terms of the polynomial 16x2 - 14x. O A. 2x² O B. 44² O c. 2x O D. 4x
Answer:
c. 2x.
Step-by-step explanation:
16x2 - 14x
Common factor of 16 and 14 = 2'
for x2 and x it is x,
Answer: 2x.
In circle C with m \angle BCD= 46m∠BCD=46 and BC=3BC=3 units, find the length of arc BD. Round to the nearest hundredth.
The length of arc of the given circle, to the nearest hundreth, is: 2.41 units.
What is the Length of an Arc?Length of arc = ∅/360 × 2πr, where the radius of the circle is r, and the reference angle is ∅.
We are given the following:
Radius (r) = 3 units
Reference angle (∅) = 46°
Plug in the values into the length of arc formula:
Length of arc = 46/360 × 2π(3)
Length of arc = 2.41 units.
Therefore, the length of arc of the given circle, to the nearest hundreth, is: 2.41 units.
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The graph of g(x) is shown. Determine the transformations from the parent function f(x)=x2 to the new function g(x)=15x2+5
Answer:
The graph of g is translated down 5 units from the graph of f and stretched horizontally
Step-by-step explanation:
was correct on test :)
pls brainliest XD
.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.
Can someone please help me with this? It's urgent! I need to turn it in tomorrow, please
Answer:
Step-by-step explanation:
Anything going from lower left to upper right is a positive slope.
The lines are not easily seen. My best estimate is that one point is (2,5)
Use the two points you are sure of.
(0,-1) and (1,2)
Givens
x1 = 0x2 = 1y1 = - 1y2 = 2Formula
m = (y2 - y1)/(x2 - x1)
Solution
m = (2 - - 1) / (1 - 0)
m = 3/1
m = 3
What is the coefficient for the 5th term of (2x-y)^8
Answer:
256x^8
Step-by-step explanation:
Hope this helped
Maybe mark brainiest?
travis measured 5 different-colored pencils to the nearest inch, 1/2 inch, and 1/4 inch. He records the measurements in the chart below. He draws a star next to the measurements that are exact.
Answer:
5x/1/2 = 1x
answer 1.12 <3
hope it helps
use brainly<3
Step-by-step explanation:
Right equation of the line that is perpendicular to the line Y equals negative 3X +8 and passes through the point -2, 3. Right equation in point slope form
=======================================================
Perpendicular lines have slopes that are opposite reciprocals.
This means we take a number, flop it over, and change its sign.
In this case, we take [tex]\boxed{-3}[/tex], change its sign:
[tex]\boxed{3}[/tex]
3 can also be written as
[tex]\boxed{\frac{3}{1} }[/tex]
Now the numerator & denominator switch places:
[tex]\boxed{\frac{1}{3}}[/tex]
So that's the slope of the new line.
Now, let's write the equation in point-slope form:-
[tex]\bigstar{\underline{\boxed{\pmb{y-y_1=m(x-1)}}}[/tex]
Where
y₁ is the y-coordinate of the point (in this case, y₁ = 3)
m = slope (1/3)
x₁= the x-coordinate of the point (in this case, it's -2)
Plug in the values:-
[tex]\bigstar{\boxed{\pmb{y-3=\frac{1}{3}(x-(-2)}}[/tex]
[tex]\bigstar{\boxed{\pmb{y-3=\frac{1}{3}(x+2)} }\longleftarrow\sf{Point-Slope~Formula:)}}[/tex]
===============================================
note:-Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)
A boy sees a bird sitting on a tree at an angle of elevation of 20°. If a boy is standing 10 miles away from the tree, at what height bird is sitting?
Let that be x
[tex]\\ \rm\rightarrowtail tan\theta=\dfrac{Perpendicular}{Base}[/tex]
[tex]\\ \rm\rightarrowtail tan20=\dfrac{x}{10}[/tex]
[tex]\\ \rm\rightarrowtail 0.364=\dfrac{x}{10}[/tex]
[tex]\\ \rm\rightarrowtail x=10(0.364)[/tex]
[tex]\\ \rm\rightarrowtail x=3.64mi[/tex]
Answer:
[tex]\displaystyle 4\:mi.[/tex]
Step-by-step explanation:
[tex]\displaystyle \frac{10}{h} = cot\:20 \hookrightarrow 10 = hcot\:20 \hookrightarrow \frac{10}{cot\:20} = h; 3,6397023427... \\ \\ \boxed{4 \approx h}[/tex]
OR
[tex]\displaystyle \frac{h}{10} = tan\:20 \hookrightarrow 10tan\:20 = h; 3,6397023427... \\ \\ \boxed{4 \approx h}[/tex]
I am joyous to assist you at any time.
Find the average squared distance between the points of r{(x,y): 0x, 0y} and the point (,)
The average squared distance between the points is their variance
The average squared distance is 8/3
How to determine the average squared distance?The given parameters are:
R={(x,y): 0<=x<=2, 0<=y<=2}
The point = (2,2).
f(x,y) = (x-2)² + (y-2)²
The squared distance is calculated as:
D² = f(x,y) = (x-2)² + (y-2)²
Where the area (A) is:
A = xy
Substitute the maximum values of x and y in A = xy
A = 2 * 2
A = 4
The minimum values of x and y are 0.
So, the limits for the integrals are 0 to 2
The integral becomes
[tex]D\² = \int \int (x-2)\² + (y-2)\² dx dy[/tex]
Expand
[tex]D\² = \int \int x\² -4x + 4 + (y-2)\² dx dy[/tex]
Evaluate the inner integral with respect to x from 0 to 2
[tex]D\² = \int \frac 13x^3 -2x^2 + 4x + x(y-2)\² |\limits^2_0 dy[/tex]
Expand
[tex]D\² = \int [\frac 13(2)^3 -2(2)^2 + 4(2) + (2)(y-2)\²] dy[/tex]
Simplify
[tex]D\² = \int \frac 83 + (2)(y-2)\² dy[/tex]
Expand
[tex]D\² = \int \frac 83 + 2y^2-8y + 8 \ dy[/tex]
Evaluate the integral with respect to y from 0 to 2
[tex]D\² = [\frac 83y + \frac 23y^3- 4y^2 + 8y ]|\limits^2_0[/tex]
Expand
[tex]D\² = \frac 83*2 + \frac 23*2^3- 4*2^2 + 8*2[/tex]
D² = 32/3
The average squared distance (AD²) is calculated as:
AD² = D²/A
So, we have:
AD² = 32/3 [tex]\div[/tex] 4
Evaluate the quotient
AD² = 32/12
Simplify
AD² = 8/3
Hence, the average squared distance is 8/3
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The average squared distance between the points of R = {(x,y): 0<=x<= h, 0<=y<=k } is 8/3.
How do determine the average squared distance?
From the given parameters R = {(x,y): 0<=x<= h, 0<=y<=k }
The squared distance from point (h, k) is calculated as
D² = f(x,y) = (x-2)² + (y-2)²
Where the area (A) will be
A = xy
Substitute the maximum values of x and y
A = 2 × 2 = 4
The minimum values of x and y are 0.
So, The integral becomes
[tex]D^{2} = \int \int(x-2)^2 +(y-2)^2 dx dy\\\\D^{2} = \int \int\limits^2_0 (x)^2 -4x + 4+(y-2)^2 dx dy\\\\D^{2} = \int1/3(x)^3-2x^{2} +4x + 4+x(y-2)^2 dy\\\\D^{2} = \int8/3+2y^{2} -8y +8 dy[/tex]
[tex]D^2 = {8/3y +2/3y^2 -4y^2+8y[/tex]
By expanding we get,
D^2 = 32/3
The average squared distance (AD²) is calculated as:
AD² = D²/A
AD² = 32/3 4
AD² = 32/12
AD² = 8/3
Hence, the average squared distance is 8/3
Read more about average distance;
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Find the length of side a.
A. 4
B. 2
C. 34
D. 16
Answer:
Side A is 4
Step-by-step explanation:
Answer:
A.4
Step-by-step explanation:
a = √(c² - b²)
a= √(5² -3b²)=4
a yard is a shape of a triangle the height is 35 ft, and the width of 50 ft. what is the area.
Answer:
1,750
Step-by-step explanation:
35x50 that's the entire process
Solve this QUICKLY and explain, please
Answer:
Step-by-step explanation:
c
so you have to combine like terms so subtract 8 - 4 and the 4 disappears so it be like this
8 - 2x = 4 + x
-4 -2x = -4 + x
4 - 2x = x
next combine the like terms of the 2x so
4 - 2x = x
4 + 2x = +2x
4 = 2x
now you divide 4 by 2 so like this
4 = 2x
2 2
and your answer is x = 2 try to solve the other one if you need help ask me
Point K is shown on the number line below .
Which number sentence BEST describes the value represented by point K?
Answer: B. K < 13. K is 12.5, 12.5 is less than 13
1. Its not D because at the ending points of the number line; 10-20, which is less than 30.
2 It is not C because K is not on 15
3 It is not A because 12.5 is less than 13.
Hope it helps!!
$20,000 is borrowed at an interest rate of 15% p.a. (per annum) to be paid back over 10
years, calculate the amount of interest, the total repayment and the monthly repayment.
Answer:
30000 simple interest ,50000 total repayment.
Step-by-step explanation:
sorry iam terrible at explaining,
44 friends evenly divided up an nnn-slice pizza. One of the friends, Harris, ate 111 fewer slice than he received.
How many slices of pizza did Harris eat
Answer:
(n/4)-1
Step-by-step explanation:
: A group of 28 people bought tickets to a museum. The total cost for the tickets was $315. What was the cost of each ticket?
Answer:
he correct answer is D. 12 adult tickets, 4 child ticket
Step-by-step explanation:
Find the area of the quadrilateral
Answer:
58.58
Step-by-step explanation:
[tex] \frac{1}{2} \times 10 \times 3 \\ 5 \times 3 = 15.....(1)[/tex]
[tex] \frac{1}{2} \times 10 \times 10 \\ 5 \times 10 = 50...(2)[/tex]
Add one and two :- 15+ 50 = 65
Please help me answer this question on congruent triangles. 30 points
Answer:
h = 24 cm
Step-by-step explanation:
Let [tex]x[/tex] = height of ΔCBD
Let [tex]h[/tex] = height of ΔABE
As ΔABE ~ ΔCBD then AE : CD = [tex]h[/tex] : [tex]x[/tex]
Given:
AE = 20 cmCD = 10 cm[tex]\implies 20 : 10 = h : x[/tex]
[tex]\implies \dfrac{20}{10}=\dfrac{h}{x}[/tex]
Cross multiply:
[tex]\implies 20x=10h[/tex]
Simplify:
[tex]\implies 2x=h[/tex]
As we are told that [tex]x+h=36 \ \sf cm[/tex]
[tex]\implies h=36-x[/tex]
Equate the two equations for [tex]h[/tex] and solve for [tex]x[/tex]:
[tex]\implies 2x=36-x[/tex]
[tex]\implies 3x=36[/tex]
[tex]\implies x=12[/tex]
Since [tex]h=2x[/tex] then
[tex]\implies h=2 \cdot 12[/tex]
[tex]\implies h=24 \ \sf cm[/tex]
The volume of the triangular block is 4 cubic inches. A triangular prism has a volume of 4 cubic inches. The right triangle bases have side lengths of x and a hypotenuse length of y. THe height of the prism is x. What is the approximate length of y? Round to the nearest tenth of an inch. 1. 4 in. 2. 0 in. 2. 8 in. 3. 5 in.
The value of the hypotenuse y will be equal to y = 2.8 inches.
What is volume of prism?The volume of the prism is equal to the product of the area of its base and the height of the prism.
[tex]\rm V=Area \ of\ triangular \ base\times Height \ of \ prism[/tex]
The volume oif the prism is =4 cubic inches
Height of the prism = x inches
Base of the right angle isosceles triangle will be =x inches
The hypotenuse is given = y
Now
[tex]\rm V=\dfrac{1}{2}\times Base\times Height \times height \ of \ prism[/tex]
[tex]V=\dfrac{1}{2} \times x \times x \times x[/tex]
[tex]x^3=8[/tex]
[tex]x=2[/tex]
Now by pythagorus theorem
[tex]y^2=h^2+b^2[/tex]
[tex]y^2=x^2+x^2[/tex]
[tex]y^2=2x^2=2\times 2^2[/tex]
[tex]y=2\sqrt{2}=2.82[/tex]
Thus the value of the hypotenuse y will be equal to y = 2.8 inches.
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Answer:
2.8 INCHES
Step-by-step explanation:
Omg please help! NO LINKS NO FILES PLEASE!
Answer: Square is a 17*17. Ok so its 121-25=96
Step-by-step explanation:
96
perform the translation (x, y) - (x-2, y+3)
Answer:
The coordinate of the image of a point is (2, +3) under the translation (x , y) → (x - 2),( y + 3). Find the coordinate of the preimage.
We are just looking for x and y and we know (2, +3) → (x - 2, y + 3)
2 = x - 2
x = 4
-3 = y + 3
y = -6
(x , y) = (4, -6)
How to find a