help me please

Explain what you would do first to simplify the expression below. Justify why, and then state the result of performing this step.

Help Me PleaseExplain What You Would Do First To Simplify The Expression Below. Justify Why, And Then

Answers

Answer 1

First clear the bracket of the inner fraction's numerator. This would allow you to reduce the inner fraction to lowest terms.

Given the expression

[tex](\frac{(2r^2t)^3}{4t^2})^2[/tex]

In order to simplify, note that the numerator and denominator of the fraction

[tex]\frac{(2r^2t)^3}{4t^2}[/tex]

have common factors. So, we would first remove the bracket in the numerator. This would allow us to reduce the fraction to lowest terms.

To clear the numerator's bracket, note that

[tex](2r^2t)^3=(2r^2t)\times(2r^2t)\times(2r^2t)\\=(2\times2\times2)\times(r^2\times r^2\times r^2)\times(t\times t\times t)\\=8\times r^6 \times t^3=8r^6 t^3[/tex]

that was long. The shorter way was to do the following

[tex](2r^2t)^3=2^3\times r^{2\times3}\times t^3=8r^6t^3[/tex]

so back to the original question, to simplify

[tex](\frac{(2r^2t)^3}{4t^2})^2[/tex]

we would do

[tex](\frac{(2r^2t)^3}{4t^2})^2=(\frac{2^3r^{2\times3}t^3}{4t^2})^2\\\\=(\frac{8r^6t^3}{4t^2})^2[/tex]

Now that we have removed the bracket from the numerator, we can now accomplish the step of reducing the fraction to lowest terms

[tex](\frac{8r^6t^3}{4t^2})^2=(\frac{8}{4}\times r^6\times \frac{t^3}{t^2})^2\\=(2\times r^6\times t^{3-2})^2\\=(2\times r^6\times t^1)^2\\=(2r^6t)^2[/tex]

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Learning Task 3: Write at least three equivalent ratio of the given ratio. Write your answer in your notebook. 6.) 8/10 = 7.) 3/5 = 1.) 2/4 = . = 2.) 5/10 = 3.) 4/5 = = I 8.) 2/8 = 9.) 3/7 = 10.) 6/8 4.) 3/9 = 5.) 2/5 = - cond and colon form. Do this in​

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Answer:

Equivalent Ratio

A ratio shows the comparison of quantities. It describes a part-to-part or a part-to-whole comparison. It can be written in three ways: fraction form, colon form and word form. Ratios that have the same values are called equivalent ratio. You can find the equivalent ratio by multiplying or dividing both quantities by the same number.

Solution:

Let us now find the equivalent ratios of the given ratios above by multiplying or dividing.

1) ‌2⁄4‌ = ‌1⁄2, ‌4⁄8, ‌6⁄12

‌2÷2 / 4÷2 = 1⁄2

2×2 / 4×2 = 4⁄8

2×3 / 4×3 = 6⁄12

2) 5⁄10 = 1⁄2, 20⁄40, 30⁄60

5÷5 / 10÷5 = 1⁄2

5×4 / 10×4 = 20⁄40

5×6 / 10×6 = 30⁄60

3) 4⁄5 = 8⁄10, 16⁄20, 28⁄35

4×2 / 5×2 = 8⁄10

4×4 / 5×4 = 16⁄20

4×7 / 5×7 = 28⁄35

4) 3⁄9 = 1⁄3, 9⁄27, 21⁄63

‌3÷3 / 9÷3 = 1⁄3

3×3 / 9×3 = 9⁄27

3×7 / 9×7 = 21⁄63

5) 2⁄5 = 4⁄10, 8⁄20, 14⁄35

2×2 / 5×2 = 4⁄10

2×4 / 5×4 = 8⁄20

2×7 / 5×7 = 14⁄35

6) 8⁄10 = 4⁄5, 24⁄30, 56⁄70

‌8÷2 / 10÷2 = 4⁄5

8×3 / 10×3 = 24⁄30

8×7 / 10×7 = 56⁄70

7) 3⁄15 = 1⁄5, 6⁄30, 12⁄60

‌3÷3 / 15÷3 = 1⁄5

3×2 / 15×2 = 6⁄30

3×4 / 15×4 = 12⁄60

8) 2⁄8 = 1⁄4, 6⁄24, 14⁄56

‌2÷2 / 8÷2 = 1⁄4

2×3 / 8×3 = 6⁄24

2×7 / 8×7 = 14⁄56

9) 3⁄7 = 6⁄14, 12⁄28, 18⁄42

3×2 / 7×2 = 6⁄14

3×4 / 7×4 = 12⁄28

3×6 / 7×6 = 18⁄42

10) 6⁄8 = 3⁄4, 24⁄32, 36⁄48

6÷2 / 8÷2 = 3⁄4

6×4 / 8×4 = 24⁄32

6×6 / 8×6 = 36⁄48

Step-by-step explanation:

Answer:Equivalent Ratio

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Answer: 42 I think

Step-by-step explanation:

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Answer:

  (a)  A is steeper; 4/5 > 2/5

Step-by-step explanation:

The slope of A is the coefficient of x, so is 4/5. This eliminates choices B and D.

The line in the graph has a rise of 2 units for each run of 5 units, so has a slope of ...

  slope = rise/run = 2/5

This eliminates choice C.

The correct description of the relationship is the first one:

  Equation A has a steeper slope, because 4/5 is greater than 2/5.

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Answer:

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Step-by-step explanation:

-7 +3 is -4

-4+-20 is -24

-7 + 3 - 20

= -4 - 20

= -4 + -20

= -24

______

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Step-by-step explanation:

7. A value of n is substituted in each expression to get the number
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---

Answers

Answer:

a. n=6

b. n = 4

c. n =2

d. n = 11 ÷ 5

e. n = 10

f. 20

Step-by-step explanation:

a. 5n = 30

n=30÷5

n=6

b. 3n-1 = 11

3n= 11 + 1

n = 12 ÷3

n=4

c. 4n + 7 = 15

4n = 15 - 7

n = 8 ÷ 4

n = 2

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e. 4 + n = 40

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Step-by-step explanation:

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Recal the binomial theorem:

[tex]\displaystyle (a+b)^n = \sum_{k=0}^n \binom nk a^{n-k} b^k[/tex]

Then

[tex]\displaystyle (2q+p)^{21} = \sum_{k=0}^{21} \binom{21}k (2q)^{21-k} p^k = \sum_{k=0}^{21} \binom{21}k 2^{21-k} q^{21-k} p^k[/tex]

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Answers

[tex]-4[/tex] is a part of the solution set to all of the inequalities

We will consider each inequality in turn:

For [tex]x>-5[/tex]:

The solution set is [tex]\{{-4,-3,-2,-1,...\}[/tex]

So [tex]-4[/tex] is a part of the solution set of [tex]x>-5[/tex]

For [tex]2>x[/tex], or [tex]x<2[/tex]:

The solution set is [tex]\{{1,0-1,-2,-3,-4,...\}[/tex]

So [tex]-4[/tex] is a part of the solution set of [tex]2>x[/tex]

For [tex]3x+4\ge -8[/tex]:

We have to solve first

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The solution set is [tex]\{{-4,-3,-2,-1,0,...\}[/tex]

So [tex]-4[/tex] is a part of the solution set of [tex]3x+4\ge -8[/tex]

For [tex]5x\le 2x-3[/tex]:

We have to solve first

[tex]5x\le 2x-3\\5x-2x\le-3\\3x\le-3\\x\le-1[/tex]

The solution set is [tex]\{{-1,-2,-3,-4,-5,...\}[/tex]

So [tex]-4[/tex] is a part of the solution set of [tex]5x\le 2x-3[/tex]

For [tex]-6<4-2x[/tex]:

We have to solve first

[tex]-6<4-2x\\2x<4+6\\2x<10\\x<5[/tex]

The solution set is [tex]\{{4,3,2,...,-3,-4,-5,...\}[/tex]

So [tex]-4[/tex] is a part of the solution set of [tex]-6<4-2x[/tex]

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Step-by-step explanation:

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Step-by-step explanation:

Given, ∠POR=120

o

Hence, ∠POR=2∠PQR (half angle property)

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∠PSR=180−60

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[tex]how \: do \: i \: solve \: reflection[/tex]

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Step-by-step explanation:

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