help plsssss ayuda pls

Answer:

289 meters I believe.

Step-by-step explanation:

The required fraction of the pizza Rachel eat is 1 / 6.

Given that,
After a party, 1/3 of a pizza remains. Rachel eats 1/2 of the remaining pizza. What fraction of a pizza she eat is to be determined.

The technique in mathematics to perform and solve the expression to make the expression simple or more understandable is called simplifying and the process is called simplification.

The ratio can be defined as the comparison of the fraction of one quantity towards others. e.g.- water in milk.

Here, remaining pizza = 1 / 3
Rachel eats 1 /2 of the remaining pizza so,
=  1 / 2 * 1 / 3
= 1 / 6

Thus, the required fraction of the pizza Rachel eat is 1 / 6.  

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Answer:

The final set of ordered pairs represents a function.

Step-by-step explanation:

Each X value corresponds to exactly one y- value. Essentially, none of the x values are the same in the final set.

Answer:

$8 an hour

Step-by-step explanation:

56/7= 8

Answer:

$8 per hour.

Step-by-step explanation:

56/7=8

Answer:

this is an identity which is true for all x values

Step-by-step explanation:

Perform the indicated multiplication.  We get:

6x - 1 = 6x -1

and see that this is an identity which is true for all x values.

Answer:

Percentage = 14.2%

Step-by-step explanation:

Given the following data;

Cost of plane ticket = £588

Airport tax = $130

£1 = $1.34

To find the percentage of the total cost spent on airport tax;

First of all, we would convert the ticket cost in pounds (£) to dollars ($).

Cost of plane ticket = £588 to $ = 588 * 1.34 = $787. 92

Total cost = Cost of plane ticket + Airport tax

Total cost = 787. 92 + 130

Total cost = $917.92

[tex] Percentage \; cost = \frac {130}{917.92} * 100 [/tex]

[tex] Percentage = 0.1416 * 100 [/tex]

Percentage cost = 14.16 to 1 d.p = 14.2%

Therefore, the percentage of the total cost spent on airport tax by Rimo is 14.2 percent.

Answer: 32%

Step-by-step explanation:

Number of students in grade 9-10 who likes rap = 40

Total number of students in grade 9-10 = 125

The percentage of the students in grades 9–10 who like rap music will be:

= Number of students in grade 9-10 who likes rap / Total number of students in grade × 100

= 40/125 × 100

= 0.32

= 32%

Answer:

32%

Step-by-step explanation:

Answer:

16 percent

Step-by-step explanation:

Answer:

32%

Step-by-step explanation:

50% of the first solution is HCL, so it has

80 ml x 50% = 80 ml x 0.5 = 40 ml of HCL

Similarly the second solution has 20% of HCL, so

120 ml x 20% = 120 ml x 0.2 = 24 ml of HCL

The combined solution will have 40 ml + 24 ml = 64 ml of HCL.

The total volume of the 2 solutions is 80 ml + 120 ml = 200 ml.

We can now calculate the concentration of HCL in the mixed solution, by dividing the volume of HCL by the total volume of the solution,

64 ml / 200 ml = 0.32 = 32%

Answer:30

Step-by-step explanation: please

Lisa take approximately 30 minutes(time) to run 5 miles at the same rate she ran 3 1/2 miles in 21 minutes.

To find out how long it will take Lisa to run 5 miles at the same rate, we can set up a proportion using the distance and time data.

Let's denote the time it will take her to run 5 miles as "t" (in minutes).

The proportion can be set up as follows:

(3.5 miles) / (21 minutes) = (5 miles) / (t minutes)

Now, cross-multiply and solve for "t":

3.5 × t = 21 × 5

3.5t = 105

Divide both sides by 3.5 to isolate "t":

t = 105 / 3.5

t = 30

So, it will take Lisa approximately 30 minutes to run 5 miles at the same rate she ran 3 1/2 miles in 21 minutes.

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Answer:

3927

Step-by-step explanation:

How I did this was just trial and error. 1315 doesn’t work as it only adds up to 10. Lets try 2618. It still only adds up to 17. Let’s try 3927. It Works! Many get confused as they assume “The number formed by the last (right-most) two digits is three times the second digit from the left.” As adding up the last two digits. However, getting 21 is not possible considering the circumstances If you add the last two digits as a multiple. If you have 1234, the 3” and 4” aren’t separate numbers. The 3” and 4” is 34” not 3+4.

3+9=12.     12+2=14.     14+7=21.

Using the hit and trial method and the given condition Olivia's passcode can be determined. Olivia's passcode is 3927.

Given :

Olivia has four digits passcode.

The following steps can be used in order to determine Olivia’s passcode:

Step 1 - Let Olivia's passcode be 'wxyz'.

Step 2 - The sum of all the digits is given by the equation:

w + x + y + z = 21

Step 3 - The linear equation that represents the situation "The second digit from the left is three times the first (left-most) digit" is given by:

x = 3w

Step 4 - Now, use the hit and trial method first put (w = 1) and check all the given conditions. If w = 1 then x = 3 and but the third condition that is the last (right-most) two digits is three times the second digit from the left is not satisfied.

Step 5 - Now, put (w = 3) and check all the given conditions. If w = 3 then x = 9 and the last two digits become 2 and 7. And the sum of all the digits is equal to 21.

Step 6 - From the above steps, it can be concluded that the passcode is 3927.

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Answer:

(x,y)=(-3,3)

Step-by-step explanation:

Answer:

I think it's the last to they sound way more independent!!!

Answer:

i think 25.09 weighs more

Step-by-step explanation: well simply 25.018 has more decimal places down therefore making it a smaller number

sorry if you get it wrong :c

Answer:

2508

Step-by-step explanation:

We are given that

Principal ,P=2200

Rate of interest, r=7%

Time, t=2 year

We have to find the final account balance after two years.

[tex]S.I=\frac{P\times r\times t}{100}[/tex]

Using the formula

[tex]S.I=\frac{2200\times 7\times 2}{100}=308[/tex]

Amount=P+S.I

Amount=2200+308

Amount=2508

Hence,  the final account balance after two years=2508

Answer:

7.57

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The height of sunflowers is Normally distributed with mean 50 inches and standard deviation 8 inches.

This means that [tex]\mu = 50, \sigma = 8[/tex]

Percent of all sunflowers that are between 35 and 40 inches tall.

As a proportion, this is the pvalue of Z when X = 40 subtracted by the pvalue of Z when X = 35. So

X = 40

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{40 - 50}{8}[/tex]

[tex]Z = -1.25[/tex]

[tex]Z = -1.25[/tex] has a pvalue of 0.1057

X = 35

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{35 - 50}{8}[/tex]

[tex]Z = -1.88[/tex]

[tex]Z = -1.88[/tex] has a pvalue of 0.03

0.1057 - 0.03 = 0.0757

As percent: 0.0757*100% = 7.57%

Answer:

The probability that 2 or more of the original 5,100 components may fail during the useful life of the product is:

= 0.001

Step-by-step explanation:

Probability of operating without failure = 0.999

The probability of failed component = 0.001 (1 - 0.999)

The number of components of the electronic office product = 5,100

The number of components that may fail, given the above successful operation = 5.1 (0.001 * 5,100).

Therefore, the probability that 2 or more of the original 5,100 components may fail during the useful life of the product = 0.001

Probability of component failure is the likelihood that a component fails during the useful life of the product.  It is expressed as the number of likely failed components divided by the total number of components.  This result can be left in decimal form or expressed as a percentage.

Following are the solution to the given expression:

[tex]\to \text{p = p (failure)} = 1 -0.999 = 0.001 \\\\[/tex]

We employ the binomial approximation of the normal distribution with mean.

[tex]\to \mu = np = 5100(0.001) = 5.1 \\\\ \to \text{standard deviation} \ (\sigma) = \sqrt{np(1-P)}[/tex]

                                         [tex]= \sqrt{5100(0.001)(1-0.001)} \\\\ = \sqrt{5.1 \times (0.999)} \\\\= \sqrt{5.0949 } \\\\= 2.2572[/tex]

It require [tex]p(x\geq 2)[/tex] but we find [tex]p(x \geq 1.5)[/tex],  because of [tex]0.5[/tex] correction.

Here

[tex]\to z = \frac{X-\mu}{\sigma }[/tex]

       [tex]=\frac{1.5-5.1}{2.2572} \\\\ =\frac{-3.6}{2.2572} \\\\ = -1.59 \\\\[/tex]

Calculating the required probability:  

[tex]\to p(z \geq -1.59)[/tex]

[tex]=1+ p(z< 1.59) \\\\= 1+ 0.9440826[/tex] , by standard normal table  

[tex]= 1.9440826 \approx 1.944[/tex]

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Answer:

$87.50

Step-by-step explanation:

35 is the original price. we are increasing it by 150% i like to break it up

100 percent increase would just be adding another 35 to it. so 35+35=70

then we have a 50% increase 35/2=17.50

70+17.50=87.50

Answer:

D

Step-by-step explanation:

A and B cannot be the right answers, because the left part of the graph is inclusive (so the right answer has to include [tex]x\leq 1[/tex] instead of [tex]x<1[/tex]).

C can also not be the right answer, because for [tex]x=0[/tex], [tex]y=-1[/tex] instead of [tex]2(0)^2 = 0[/tex].

So D is the correct answer by elimination.

Answer:

The cost of that car in 2012 dollars is $20,755

Step-by-step explanation:

We take a look at inflation values of the dollar to solve this question.

100 dollars in 1976 are equivalent to 469.48 dollars in 2021.

100 dollars in 2012 are worth 113 dollars today.

So, to find the 2012 equivalent, we divide 469.48 by 113/100 = 1.13. So

469.48/1.13 = 415.5.

That is, 100 dollars in 1976 are equivalent to 415.5 dollars in 2012, that is, 1 dollar in 1976 was worth 4.155 dollars in 2012.

In 1976, a certain model of car cost $5,000. What would be the cost of that car in 2012 dollars?

Multiplying by 4.155

5000*4.155 = 20,755

The cost of that car in 2012 dollars is $20,755

Answer:

6x+8=35

35=8+6x

Step-by-step explanation:

id.k about 35=8+x+X+X+x+X+x

Answer:A

Step-by-step explanation: The letters are not in the correct order on letter A and the rest of the answers can prove it.

Answer:

Step-by-step explanation:

Answer:7  jogadore participaram do jogo

In this exercise we will use the differential equations to calculate finances, we find that:

a) [tex]Profit = (x - 3)f(x)[/tex]

b) [tex]P' = f(x) + (x - 1) f'(x)[/tex]

c) [tex]P' = 29400[/tex]

The cost of producing the items is the total expenses of production while the revenue is the amount of money generated from selling the item.

a)Then using the given formula and substituting for the known values ​​we find that;

[tex]Cost = \ cost \ of \ producing \ one \ item * number \ of \ items \ produced\\Cost = $3 * f(x) = 3f(x)\\Revenue = selling \ price \ of \ one \ item * number \ of \ items \ produced\\Revenue = x * f(x) = xf(x)\\Profit = Revenue - Cost = xf(x) - 3f(x)\\Profit = (x - 3)f(x)[/tex]

b) Applying knowledge of differential equations we find that:

[tex]P' = d/dx(xf(x) - 3f(x) )\\P' = f(x) + xf'(x) - f'(x)\\P' = f(x) + (x - 1) f'(x)[/tex]

c)Substituting the known values ​​into the formula given above, we find that:

[tex]f(x) = 3000, x = $45, f'(x) = -600 items / 1$\\P' = 3000 + (45 - 1)(-600)\\P' = 3000 + 26400\\P' = 29400[/tex]

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Answer:

[tex]\frac{24}{35}mi[/tex]

Step-by-step explanation:

Area = length • width

area = [tex]\frac{3}{5}mi^{2}[/tex]

length = [tex]\frac{7}{8} mi[/tex]

width = x

[tex]\frac{3}{5} = \frac{7}{8} x[/tex]                   multiply both sides by [tex]\frac{8}{7}[/tex] (the reciprocal of [tex]\frac{7}{8}[/tex])

[tex](\frac{8}{7})(\frac{3}{5}) = x[/tex]

x = [tex]\frac{24}{35}[/tex]

Answer:

24/35 is your answer

Divide 3/5 by 7/8 to get the answer of 24/35