Answers
Answer:
Here’s something I wrote that can help you. I don’t really wanna do transformations but this should help you get the answer in a snap.
ONLY FOR REFLECTIONS
Over the x-axis: (x, y) — > (x, –y)
Over the y-axis: (x, y) — > (–x, y)
Over the line y = x: (x, y) — > (y, x)
Through the origin: (x, y) — > (–x, –y)
So for example E is (6,-1)
Over the y axis so following the coordinate plane rules, (6,-1) — > (-6, -1)
(-6, -1) over x axis which is following the rules
(-6, -1) — > (-6, 1)
Final answer (-6,1)
Answer:
(-6, 1)
Step-by-step explanation:
If you reflect over y-axis and x-axis it is just the opposite of each number.
Related Questions
If xcos(x)= 2, find (-x) • cos(-x)
Answers
[tex](-x) \cos(-x)\\\\=-x \cos x \\\\=-(x \cos x)\\\\=-2[/tex]
Solve each of the following equations. Show its solution set on a number line. Check your answers. 2|2-x|=-5
Answers
Answer:
Use the distributive property to multiply 2 by x−1.
l2x-2I=11
2x-2=-11
Add 2 to both sides of the equation.
2x=-9
Divide both sides by 2.
x=13/2
That's the final answer
Hope u have a great day!!
How does insurance reduce social burden?
A. Insurance ensures that people don't have to pay high deductibles.
B. Insurance ensures that losses are not passed on to society.
C. Insurance ensures that lenders publicize rates and treat all
customers equally.
D. Insurance ensures that people are treated fairly in hiring and
employment decisions.
Answers
Answer:
c po is the correct aswer
Step-by-step explanation:
correct me if im wrong hope it's help
thanks
Answer:
B. Insurance ensures that losses are not passed on to society
Hope this helps :)
Can someone help me please
Answers
Answer:
40 students earned a B on this paper.
40%×80=32 people who chose action as their fav.
what are the mean variacne and standard deviatioon of the values? round to the nerates tenth. 11,11,3,1,11
Answers
Answer:
Mean = 8
Variance = 22
Standard deviation = 4.6904
Step-by-step explanation:
To find out Mean the formula is : total sum of data set / number of values
(11 + 11 + 3 + 1 + 11 + 11) / 6 = 48 / 6 = 8
Mean = 8
Now for variance we will form a table
x 11 11 3 1 11 11
(x - Mean) 3 3 -5 -7 3 3
(x - Mean)² 9 9 25 49 9 9
Now we the formula of variance =
Variance = (9+9+25+49+9+9)/(6-1) = 110/5 = 22
Variance = 22
Now we know Standard deviation = √(variance)
Therefore standard deviation = √22 = 4.6904
Hope this helps!<3
Answer: Mean = 8
Step-by-step explanation:
Solve for X. 22 = 10x Simplify your answer as much as possible. x = 음. 6 08 ?
Answers
Answer:
x=11/5
Step-by-step explanation:
isolate x
22/10 = 10x/10
22/10 = x
simplify
11/5 = x
Is this a function or not a function?
Answers
Answer:
This is indeed a function
Which set of side lengths will form a triangle
A: 16ft, 4ft, 21ft
B: 30ft, 30ft, 60ft
C: 12ft, 12ft, 20ft
D: 3ft, 5ft, 10ft
PLS HELP
Answers
Answer:
the set of side lengths will be d
day!
Altea is making pumpkin spice cupcakes.
She needs 15 ounces of pureed pumpkin
for each batch. If she makes 16 batches of
the cupcakes, how many ounces of the
pureed pumpkin will she need?
o
Answers
Answer:
240oz.
Step-by-step explanation:
15oz=1batch
She needs 16 batches.
15oz. x 16batches = 240oz.
Hope this helps :)
The other dud explained it
please help me i’ll give brainlist and points
Answers
Answer:
Area solution
Step-by-step explanation:
A=(16+10)×12/2= 156 m^2
-(b-z)-(-2b+z)-(-3b-z)
Answers
Step-by-step explanation:
4b + z I think lol I honestly looked it up
need help with these two math problems
Answers
Answer:
y = (x - 1)(x - 3)
y = (x + 2)^2
Step-by-step explanation:
3)
Has roots at x = {1, 3}
y = (x - 1)(x - 3)
4)
Has double root at x = -2
y = (x + 2)^2
Dora opens a savings account and puts in $ 290 at the start. Every week, she deposits $ 30 in the account. Which type of function would you use to model the relationship between the number of weeks since Dora opened the account, and the amount of money in the account
Answers
Answer:
f(x)=290+30x
Step-by-step explanation:
the 290 is for the money initially put in, the 30 is for the thirty dollars, and the x represents the number of weeks.
1.
Write the equation of the parabola in vertex form.
A. y = –(x – 1)2 + 3
B. y = –x2 – 4
C. y = –x2 + 3
D. y = –x2 + 4
Answers
[tex]~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{o pens~\cap}\qquad \stackrel{"a"~is~positive}{o pens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]
[tex]\begin{cases} h= 0\\ k = 4 \end{cases}\implies y=a(x-0)^2+4~\hfill \textit{we also know that} \begin{cases} x = 1\\ y = 3 \end{cases} \\\\\\ 3=a(1-0)^2+4\implies 3=1a+4\implies \boxed{-1=a} \\\\\\ y=-1(x-0)^2+4\implies \blacktriangleright y = -x^2+4\blacktriangleleft[/tex]
Answer:
A. y = –(x – 1)2 + 3 = Rewrite in vertex form and use this form to find the vertex (h,k). (1,3)= Already in vertex form. y=−(x−1)2+3
OR
D. y = –x^2 + 4 = Rewrite in vertex form and use this form to find the vertex (h,k). (0,4)= Find the vertex form. y=−(x+0)2+4
Step-by-step explanation:
A. y = –(x – 1)2 + 3 = Rewrite in vertex form and use this form to find the vertex (h,k). (1,3)= Already in vertex form. y=−(x−1)2+3
B. y = –x^2 – 4 = Rewrite in vertex form and use this form to find the vertex (h,k). (0,−4)= Find the vertex form. y=−(x+0)2−4
C. y = –x^2 + 3 = Rewrite in vertex form and use this form to find the vertex (h,k). (0,3)= Find the vertex form. y=−(x+0)2+3
D. y = –x^2 + 4 = Rewrite in vertex form and use this form to find the vertex (h,k). (0,4)= Find the vertex form. y=−(x+0)2+4
Seventy-nine ÷ nine and five
Answers
Answer:
13.77777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777
What is 6 3/4 percent of 800
Answers
Answer:
319973/400
Step-by-step explanation:
800 - 27/4%
800 - ( 27/4 × 1/100)
800 - 27/400
= 319973/400
There are 550 calories in 100 g of bacon. There are 196 calories in a fried egg. Philip has 60 g of bacon and two fried eggs for breakfast. Work out the total number of calories in this breakfast.
Answers
Answer:
509.6 calories
Step-by-step explanation:
196+196=392 calories
10g of bacon=19.6 calories
60g of bacon=19.6×6=117.6 calories
392+117.6=509.6 calories
How many eggs are 5dozens
Answers
Answer:
60
Step-by-step explanation:
1 dozen=12 eggs. 12 ×5=60
Answer:
60
Step-by-step explanation:
dozen=12
5x12=60
Write the first five terms for the following recursive rule.
f(1)=7
f(n)=f(n-1)+12
Answers
Answer:
PLEASE MARK ME AS BRANLIEST!!!!!
Step-by-step explanation:
a1 = first term; an= an-1 + d a1 = the first term in the sequence an = the nth term in the sequence an-1 = the term before the nth term n = the term number d = the common difference.
{10, 15, 20, 25, 30, 35, } first term = 10, common difference = 5 recursive formula: a1= 10; an= an-1 + 5
f(n) = f(n-1) + 12
f(1) = 7
f(2) = (7-1) + 12 = 18
f(3) = (18-1) + 12 = 29
f(4) = (29-1) + 12 = 40
f(5) = (40-1) + 12 = 51
7, 18, 29, 40, 51
pls help the will mean the world
Answers
Answer:
A: the area of the walls that are being painted
C: the cost per gallon of different paints
F: the number of square feet that can be painted per gallon of paint
Step-by-step explanation:
Differential Equation
Answers
1. The given equation is probably supposed to read
y'' - 2y' - 3y = 64x exp(-x)
First consider the homogeneous equation,
y'' - 2y' - 3y = 0
which has characteristic equation
r² - 2r - 3 = (r - 3) (r + 1) = 0
with roots r = 3 and r = -1. Then the characteristic solution is
[tex]y = C_1 e^{3x} + C_2 e^{-x}[/tex]
and we let y₁ = exp(3x) and y₂ = exp(-x), our fundamental solutions.
Now we use variation of parameters, which gives a particular solution of the form
[tex]y_p = u_1y_1 + u_2y_2[/tex]
where
[tex]\displaystyle u_1 = -\int \frac{64xe^{-x}y_2}{W(y_1,y_2)} \, dx[/tex]
[tex]\displaystyle u_2 = \int \frac{64xe^{-x}y_1}{W(y_1,y_2)} \, dx[/tex]
and W(y₁, y₂) is the Wronskian determinant of the two fundamental solutions. This is
[tex]W(y_1,y_2) = \begin{vmatrix}e^{3x} & e^{-x} \\ (e^{3x})' & (e^{-x})'\end{vmatrix} = \begin{vmatrix}e^{3x} & e^{-x} \\ 3e^{3x} & -e^{-x}\end{vmatrix} = -e^{2x} - 3e^{2x} = -4e^{2x}[/tex]
Then we find
[tex]\displaystyle u_1 = -\int \frac{64xe^{-x} \cdot e^{-x}}{-4e^{2x}} \, dx = 16 \int xe^{-4x} \, dx = -(4x + 1) e^{-4x}[/tex]
[tex]\displaystyle u_2 = \int \frac{64xe^{-x} \cdot e^{3x}}{-4e^{2x}} \, dx = -16 \int x \, dx = -8x^2[/tex]
so it follows that the particular solution is
[tex]y_p = -(4x+1)e^{-4x} \cdot e^{3x} - 8x^2\cdot e^{-x} = -(8x^2+4x+1)e^{-x}[/tex]
and so the general solution is
[tex]\boxed{y(x) = C_1 e^{3x} + C_2e^{-x} - (8x^2+4x+1) e^{-x}}[/tex]
2. I'll again assume there's typo in the equation, and that it should read
y''' - 6y'' + 11y' - 6y = 2x exp(-x)
Again, we consider the homogeneous equation,
y''' - 6y'' + 11y' - 6y = 0
and observe that the characteristic polynomial,
r³ - 6r² + 11r - 6
has coefficients that sum to 1 - 6 + 11 - 6 = 0, which immediately tells us that r = 1 is a root. Polynomial division and subsequent factoring yields
r³ - 6r² + 11r - 6 = (r - 1) (r² - 5r + 6) = (r - 1) (r - 2) (r - 3)
and from this we see the characteristic solution is
[tex]y_c = C_1 e^x + C_2 e^{2x} + C_3 e^{3x}[/tex]
For the particular solution, I'll use undetermined coefficients. We look for a solution of the form
[tex]y_p = (ax+b)e^{-x}[/tex]
whose first three derivatives are
[tex]{y_p}' = ae^{-x} - (ax+b)e^{-x} = (-ax+a-b)e^{-x}[/tex]
[tex]{y_p}'' = -ae^{-x} - (-ax+a-b)e^{-x} = (ax-2a+b)e^{-x}[/tex]
[tex]{y_p}''' = ae^{-x} - (ax-2a+b)e^{-x} = (-ax+3a-b)e^{-x}[/tex]
Substituting these into the equation gives
[tex](-ax+3a-b)e^{-x} - 6(ax-2a+b)e^{-x} + 11(-ax+a-b)e^{-x} - 6(ax+b)e^{-x} = 2xe^{-x}[/tex]
[tex](-ax+3a-b) - 6(ax-2a+b) + 11(-ax+a-b) - 6(ax+b) = 2x[/tex]
[tex]-24ax+26a-24b = 2x[/tex]
It follows that -24a = 2 and 26a - 24b = 0, so that a = -1/12 = -12/144 and b = -13/144, so the particular solution is
[tex]y_p = -\dfrac{12x+13}{144}e^{-x}[/tex]
and the general solution is
[tex]\boxed{y = C_1 e^x + C_2 e^{2x} + C_3 e^{3x} - \dfrac{12x+13}{144} e^{-x}}[/tex]
Solve the equation: 3.017 + k = 5.134
Answers
Answer:
k=2.117
Step-by-step explanation:
Answer:
3.017 + k = 5.134
So, k = 5.134 - 3.017
So, k = 2.117
What is the slope of the line that has a y-intercept of (0, 6) and passes through the point (2, 8)?
m= ?
Answers
Answer:
m=1
Step-by-step explanation:
[tex]m=\frac{8-6}{2-0} =\frac{2}{2} =1[/tex]
I hope this help you
Y1 - Y2
over
X1 - X2
So for you problem the equation is…
0-2
over
6-8
which equals…
-2/-2 which equals…
1
The slope is 1.
If a certian perosn has a mass of 250kg on earth, would that person's mass be on the moon, if the moon's gravity is 1.62m/s2? *
10 points
245kg x 1.62m/s2
245 x 1.62m/s2
It remains the same
The person would be weightless
Answers
Answer:
Weight On the Moon: 41.34 kilograms
Step-by-step explanation:
what is 5 sixths of a full rotation
Answers
Answer:
300°
Step-by-step explanation:
what is 5/6 of a full rotation?
A full rotation is 360°
360 * 5/6 = 300°
Factor this completely thank you
Answers
Answer:
4(2x raise to power 2-4-7x)
This table represents the number of pounds, p, a puppy grows after w, weeks.
When graphed, all of the points in the table lie on the same line.
What is the slope and y-intercept of the line?
slope=−94, y-intercept=−0.8
slope=−49, y-intercept = 2
slope=49, y-intercept=−0.8
slope=94, y-intercept = 2
Weeks, w Weight in pounds, p
0 2
2 6.5
4 11
6 15.5 help plz
Answers
Answer:
the answer is slope=94, y-intercept = 2
Step-by-step explanation:
i took the test
Need help!! Answer asap!! No links! What is the most likely reason that nonmetals are electrical insulators?
A. Since valence shells are mostly empty in nonmetal atoms, the atoms attract and hold any electrons they can in order to fill their valence shells.
B. Since valence shells in nonmetal atoms are almost full, the atoms attract electrons and hold them tightly to fill their valence shells.
C. Since all nonmetals have valence shells that are full, they hold electrons tightly to avoid changing.
D. Since all nonmetals have valence shells that are completely empty, they do not attract or release any electrons.
Answers
Answer:
B. because it just isssssssss I'm typing things to let me answerrr
What's the negative reciprocal of 5? Question 12 options: A) 1∕5 B) –5 C) –1∕5 D) 5
Answers
Answer:
[tex]\huge\boxed{C)\ -\dfrac{1}{5}}[/tex]
Step-by-step explanation:
The reciprocal of 5: [tex]\dfrac{1}{5}[/tex]
The negative reciprocal of 5: [tex]-\dfrac{1}{5}[/tex]
a line with slope -2 passes through the point (-2,3). What is the equation of the line?