Helppppppppppppppppppppp!!!!!!!!

Ruiz would get back 55 dollars 0 cents

Answer:

45%

trust me i took this test before

Step-by-step explanation:

Answer:

is there anything to go with this?

Step-by-step explanation:

Answer: D

Step-by-step explanation: Saw your recent comment on this

Answer: The percentage of 0.20 is 20%.

Step-by-step explanation: 0.20 represents the 20% of 100%.

Answer: 20%

Step-by-step explanation: You just move the dot 2 times to the right and it will be 20%

Answer:

Its the division of x axis divided by y axis

Answer:

The slope of the line is a measure of its steepness. You can find it with rise/run. The formula for slope is m=y2-y1/x2/x1

Answer:

its the second one

Step-by-step explanation:

u just mulitply the terms together and add the exponents

Answer:

where is the picture

Step-by-step explanation:

u need a pic

Answer:

The answer is i have no clue

Answer:

The answer in a subtraction problem is called the difference.

Step-by-step explanation:

Hi there!

The answer to a subtraction problem is called rest or difference while the top thats being subtracted is called the minuend and the middle one is called the subtrahend.

Answer:

slope = 3

Step-by-step explanation:

Choose any two points: For example, (2, 4) and (4, 10)

Find the difference in y. This is called the "rise."

rise = 10 - 4 = 6

In the same order, find the difference in x. this is called the "run."

run = 4 - 2 = 2

slope = rise/run

slope = 6/2

slope = 3

Answer:

The value of [tex]x[/tex] is approximately -1.531.

Step-by-step explanation:

Let [tex]3.3^{2\cdot x + 1}-103^{x+1} = 0[/tex], we proceed to solve this expression by algebraic means:

1) [tex]3.3^{2\cdot x + 1}-103^{x+1} = 0[/tex]  Given

2) [tex]3.3^{2\cdot x}\cdot 3.3 -103^{x}\cdot 103 = 0[/tex] [tex]a^{b}\cdot a^{c} = a^{b+c}[/tex]

3) [tex](3.3^{x})^{2}\cdot 3.3 -\left[\left( \sqrt{103} \right)^{2}\right]^{x}\cdot 103 = 0[/tex] [tex](a^{b})^{c} = a^{b\cdot c}[/tex]

4) [tex](3.3^{x})^{2}\cdot 3.3 - \left[\left(\sqrt{103}\right)^{x}\right]^{2}\cdot 103 = 0[/tex] [tex](a^{b})^{c} = a^{b\cdot c}[/tex]/Commutative property

5) [tex]\left[\left(\frac{3.3}{\sqrt{103}}\right)^{x}\right] ^{2}-\frac{103}{3.3} = 0[/tex] Existence of multiplicative inverse/Definition of division/Modulative property/[tex]a^{b}\cdot a^{c} = a^{b+c}[/tex]

6) [tex]\left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\frac{103}{3.3}[/tex] Existence of additive inverse/Modulative property/[tex](a^{b})^{c} = a^{b\cdot c}[/tex]

7) [tex]\log \left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\log \frac{103}{3.3}[/tex] Definition of logarithm.

8) [tex]2\cdot x\cdot \log \left(\frac{3.3}{\sqrt{103}} \right)= \log \frac{103}{3.3}[/tex]     [tex]\log_{b} a^{c} = c\cdot \log_{b} a[/tex]

9) [tex]2\cdot x \cdot [\log 3.3-\log \sqrt{103}] = \log 103 - \log 3.3[/tex]      [tex]\log_{b} \frac{a}{d}[/tex]

10) [tex]x\cdot (2\cdot \log 3.3-\log 103) = \log 103 - \log 3.3[/tex]     [tex]\log_{b} a^{c} = c\cdot \log_{b} a[/tex]/Associative property

11) [tex]x = \frac{\log 103-\log 3.3}{2\cdot \log 3.3-\log 103}[/tex]   Existence of multiplicative inverse/Definition of division/Modulative property

12) [tex]x \approx -1.531[/tex]  Result

The value of [tex]x[/tex] is approximately -1.531.

Answer:

≈ 70.87 (rounded to the nearest hundredth)

Step-by-step explanation:

-When you do 4,819 ÷ 68, you’ll get:

70.867647058....

-So, just round it to the nearest hundredth:

70.87

Answer:

10y²+24.5

Step-by-step explanation:

distribute.

10y²+24.5

Hope this helps plz hit the crown :D

The equivalent expression for the given expression is 10y²+24.5.

The given expression is 10(y² + 2.45).

Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value when we plug in the same value for the variable.

The equivalent expression is

10(y² + 2.45)

=10y²+24.5

Therefore, the equivalent expression for the given expression is 10y²+24.5.

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slopev=

[tex]diffrence \: in \: y \: coordinate \\ diffrence \: in \: x \: coordinate[/tex]

so

Y=11_5 =6

X = -7_(-3) = -4.

slope = (-4,6)

make as brainlist

Answer:

125°

Step-by-step explanation:

Find the value of x first.

5x = 3x + 50 (corresponding angles are congruent)

Subtract 3x from each side

2x = 50

Divide both sides by 2

x = 25

Angle MPQ = 3x + 50

Plug in the value of x

Angle MPQ = 3(25) + 50 = 125°

60 x 5 + 45 = 345 Seconds

Answer:

n= -10

Step-by-step explanation:

50-20= 30 so -3n=30. So n= -10.

Answer:

n=-10

Step-by-step explanation:

-3n+20=50 move constant to the right hand side

-3n=50-20 subtract the numbers

-3n=30 divide both sides by -3 and the answer is n=-10

Answer:

tel:+18446450594

Step-by-step explanation:

9514 1404 393

Answer:

  $9,437.65

Step-by-step explanation:

Fill in the given numbers and do the arithmetic.

  [tex]V=Pe^{rt}\\\\V=\$6860\cdot e^{0.029\cdot 11}=\$6860\cdot 1.375751\\\\\boxed{V=\$9{,}437.65}[/tex]

Answer:

3

Step-by-step explanation:

27^1/3

= 3√27

=3 is the collect option

Answer:

a. V = $109,600  - $5,750(t)

b.  $69,350

Step-by-step explanation:

a. The expression of the value of the bulldozer is as follows

V = $109,600 - (m) × (t)

where,

m = depreciation

t  = time in years

Now the equation would be

$109,600 - 16(m) = $17,600

m = ($109,600 - $17,600) ÷ (16)

= $5,750

Now the expression would be

V = $109,600  - $5,750(t)

b. Now the value of the bulldozer is

= $109,600 - $5,750 × 7 years

= $109,600 - $40,250

= $69,350

Answer:

x>15/7

Step-by-step explanation:

Answer:

4:120

Step-by-step explanation:

for 120 student they would be 4 teacher needed per 30 student

4:120

Answer:

what numbers do you need answering??

Step-by-step explanation:

Answer:

90

Step-by-step explanation:

81/x=90/100

8100=90x

90=x

The total number of problems given in exam was 90.

Percentage, which is a relative figure used to denote hundredths of any quantity. One percent (symbolised as 1%) is equal to 100 parts; hence, 100 percent denotes the complete amount, and 200 percent designates double the amount specified.

Divide one number by the other, then multiply the result by 100 to get the percentage of the two numbers.

A student correctly answered 81 problems.

Grade received by student is 90%

Let the total number of question given in the test be 'x'.

Thus,

90% of x = 81

(90/100)x = 81

x = (81×100)/90

x = 90

Therefore, the total number of question allotted to the student is 90.

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Answer:

B, C, E

Step-by-step explanation:

On edge 2021