how do i solve for x? thank you!

Answer:

100

Step-by-step explanation:

rounding to 1 sig figure

494.37 ≈ 500

5.12 ≈ 5

Estimating

500 ÷ 5 = 100

Answer:

[tex]{ \tt{ = 2 \frac{1}{2} }} \\ \\ = \frac{5}{2} \\ \\ { \tt{ = 2.5}}[/tex]

Step-by-step explanation:

a. increased b. discreased c. increased d. decreased

Answer:

Below.

Step-by-step explanation:

The first term (where k = 1)

= 3(2)^1-1

= 3*1

= 3,

The last term ( k = 10)

= 3(2)^(10-1)

= 3(2)^9

= 3* 512

= 1536.

Answer:

3

1536

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

When you ask "which of the following"

you must include the choices

p+q = 12

Squaring both the sides

(p+q)^2 = 12^2

p2 + q2 + 2pq = 144

p2 + q2 + 2x 22 = 144

p2 + q2 = 144 - 44

p2 + q2 = 100

Answer:

q2=

Step-by-step explanation:

The formula for p^2+q^2p

2

+q

2

is

p^2+q^2 = (p+q)^2 -2pqp

2

+q

2

=(p+q)

2

−2pq

Answer:is that 3i or what?

-

Step-by-step explanation

Answer:

It's answer is d) 9

.........

Answer:

4

Step-by-step explanation:

If 15% of quizzes don't have to be A's, that means that its 9 quizes that can be lower than an A. She already lost 5 which means she has four left.

Answer:

D; 4

Step-by-step explanation:

Step 1:

Let us figure out exactly how many As Liya has to earn for the year. We must find 85% of 60:

[tex]85 \%\ of\ 60=\\\frac{85}{100}*\frac{60}{1}=\\\frac{85}{5} *\frac{3}{1} =\\17*3=\\51[/tex]

Liya must earn 51 As this year to reach her goal. This also means that she can earn 9 grades lower than an A to still reach her goal ([tex]60-51=9[/tex]).

Step 2:

So far, Liya has earned 35 As out of 40 tests in total. This means that so far, Liya has earned 5 test grade lower than an A:

[tex]40-35=5[/tex]

In total, Liya can only have 9 grades lower than an A. Therefore:

[tex]9-5=\fbox{4}[/tex]

Liya can only earn [tex]\fbox{4}[/tex] grades lower than an A in the remaining quizzes.

I hope this helps! Let me know if you have any questions :)

Answer:

0.5x = 25.5

Step-by-step explanation:

Peter was thinking of a number x, then he halves it's

Answer:

-9/ 11 ____-5/11 _____ - 2/11

Step-by-step explanation:

-2/11, -5/11, -9/11

All the numbers are negative ; the fraction which is largest is 9/11 ; then 5 /11 ; then 2 /11 ; however, since they are negative, they largest fraction becomes the least value.

Numbers on a number line are arranged from least to highest. Hence the numbers will be arranged in a number line as follows :

-9/ 11 ____-5/11 _____ - 2/11

Answer:

% increase = 100 x [(new price) - (original price)] / (original price)] = 100 (9.67 - 9.56) / 9.56

% increase ≅ 1.2% (to the nearest tenth)

Answer:

(2,0)

x-value: [1+3]/2 = 4/2 = 2

y-value: [2+-2]/2 = 0/2 = 0

Step-by-step explanation:

Answer:

3.3 m

Step-by-step explanation:

the height = 2/3 × 5 = 10/3 = 3.3 m

Please delete my answer. I made a mistake

Answer:

[tex]x=54^{o}[/tex]

Step-by-step explanation:

Angles of straight line: 126 and x = 180

[tex]x+126=180[/tex]

[tex]x=180-126[/tex]

[tex]x=54^{o}[/tex]

{CHECK: [tex]54+126=180[/tex]}

hope this helps.....

Answer:

smaller piece is 65cm

larger piece is 115cm

Step-by-step explanation:

let 's' = smaller piece

let '180-s' = larger piece

3(180-s) = 85 + 4s

540 - 3s = 85 + 4s

540 = 85 + 7s

455 = 7s

s = 455/7 which is 65cm

larger piece = 180-65 or 115cm

Answer:

x = 14

Step-by-step explanation:

Triagle GIA and Triangle GNT are congruent.

Answer:

it is x

Step-by-step explanation:

The volume of a shape is the amount of space in it.

The graph that satisfies the above condition is the (b) graph X:

The volume of a rectangular-shaped swimming pool is

[tex]\mathbf{V=l \times w \times h}[/tex]

Where:

[tex]\mathbf{l,w,h \ge 0}[/tex] ---all the dimensions are greater than 0

[tex]\mathbf{l,w,h \ge 0}[/tex] means that:

From the given graphs, the graph that satisfies the above condition is the graph X:

This is so because it crosses the x-axis three times, and it does not pass through the origin

Read more about volumes at:

https://brainly.com/question/13338592

Given:

Total bill = $67.65

Mr. Scott paid with four $20 bills.

To find:

The amount of change he have received.

Solution:

It is given that, Mr. Scott paid with four $20 bills. So, the total amount paid by him is:

[tex]\$20\times 4=\$80[/tex]

Total bill = $67.65

Now,

Amount of change = Total amount paid - Total bill

                               = $80 - $67.65

                               = $12.35

Therefore, he should have received $12.35.

The sum of two numbers and their difference is 30.

Answer:

(2x - y )2 - (y + 2)2 = 4 (x - y - 1)

Step-by-step explanation:

[tex](2x -y) 2 - ( y + 2 ) 2 = (4x -2y) -(2y + 4) \\\\[/tex]

                             [tex]= 4x - 2y -2y - 4\\\\=4x - 4y - 4\\\\=4(x-y-1)[/tex]

Answer:

25/30 and 12/30

Step-by-step explanation:

6 and 5 have a least common multiple of 30

6*5 = 30

5/6 * 5/5 = 25/30

2/5 *6/6 = 12/30

Answer:

10/12       4/10

Step-by-step explanation:

Answer:

y = 1/2x - 3

Step-by-step explanation:

The line intercepts with the y-axis at -3 and its pattern is going right two and up one.

Answer:

B) 5

Step-by-step explanation:

The given parameters are;

The number of shots at the basket = 5 shots

The number of ways to make exactly 4 shots is given by combination as follows;

The number of ways to shoot exactly 4 shots = ₅C₄ = 5!/(4!×(5 - 4)!) = 5

The number of ways to shoot exactly 4 shots = 5 ways

Step-by-step explanation:

[tex] \frac{ \frac{4x}{5 + x} }{ \frac{6x}{x + 2} } [/tex]

[tex] \ \frac{2(x + 2)}{3(5 + x)} [/tex]

[tex] \frac{2x + 4}{3x + 15} [/tex]

Answer:

2x+4 over 3x+15

Step-by-step explanation:

First divide 4x over 5+x by 6x over x+2 when multiplying 4x over 5+x by the reciprocal of 6x over x+2

Step 2: cancel out 2x in both numerator and denominator

Last step:use distributive property to multiply 2 by x+2 and 3 by x+5

Answer:

? = 24/23 or 1 1/23

Step-by-step explanation:

In order to do this you have to:

1) Isolate the variable

            -  you do this by dividing each side by factors that don't contain the variable

            - you divide because it is the opposite of multiplication

Hope this helps!

X =12

Step-by-step explanation:

Supplementary Angels means the angles are added up to 180 degrees.

So , <1 + <2 = 180

Given that,

<1 = 2x +6

Now lets find the size of <2.

We know that,

Angles in a Straight line is also added up to 180 degrees.

So,

<2+ < 3 = 180

Let's Solve.

[tex] < 2 + < 3 = 180 \\ < 2 +( 3x - 6) = 180 \\ < 2 = 180 - (3x - 6) \\ < 2 = 180 - 3x + 6 \\ < 2 = 186 - 3x[/tex]

Now we know the size of <2

lets find out the value of x

[tex] < 1 + < 2 = 180 \\ 2x + 6 + 186 - 3x = 180 \\ 186 + 6 - 180 = 3x - 2x \\ 12 = x[/tex]

Let's check whether the answer is correct.

We know that <1 =<3 (Alternative Angles)

[tex] < 1 = < 3 \\ 2x + 6 = 3x - 6 \\ 2 \times 12 + 6 = 3 \times 12 - 6 \\ 24 + 6 = 36 - 6 \\ 30 = 30[/tex]

Have a nice day

Option c is correct formula

Answer:

8640

Step-by-step explanation:

According to question,

P= 6000

T=3 year 8 months = 11/3 years

R= 12% per annum

Simple interest is given by :

[tex]SI=\frac{PRT}{100} \\SI=\frac{6000*12}{100} *\frac{11}{3} \\SI=24*11\\SI=2640 Rs[/tex]

Now,

Amount = P+SI

Amount=6000+2640

Amount=8640 Rs

8640 Rs amount which will clear her debt

Answer:

c(x) =  16x + 22736

R(x) = -2x^2 + 524x  

[ -2x^2 + 508x  - 22736] = 0

Factored: f(x) = -2(x - 196)(x - 58)

58 to break even

Step-by-step explanation:

Your cost is the amount it cost you to "make" stuff.

You have fixed and variable costs (cost of oven is fixed cost of flower and sugar is variable to make cupcakes)

your cost is c(x) =  16x + 22736

"your oven and building cost $22736 per month and you use $16 worth of sugar butter flour to make one cupcake ( it  must be a huge one) ...

your revenue is the amount of money that "comes into your business"...

the amount of money in the cash register.... Note: this is only money IN you still have to pay for the building, sugar flour etc.

R(x) = -2x^2 + 524x  

Note: the minus and the square basically say that the more you charge the less cupcakes you will sell...

Profit is the money in minus the money out

P - R - E   [ -2x^2 + 524x  ] - [16x + 22736]

the break even point is where the two functions are the same

in other words where C=R or R-C=0

[ -2x^2 + 524x  ] = [16x + 22736]

[ -2x^2 + 508x  - 22736] = 0

Factored: f(x) = -2(x - 196)(x - 58)

Answer:

Step-by-step explanation:

C(x)=16x+22736

R(x)=-2x²+524x

P(x)=R(x)-C(x)

=-2x²+524x-16x-22736

=-2x²+508-22736

when profit is zero then no gain or loss.

so -2x²+508x-22736=0

or x²-254x+11368=0

196+58=254

196×58=11368

x²-54x-196x+11368=0

x(x-54)-196(x-54)=0

(x-54)(x-196)=0

x=54,196

so x=54 is the smallest number of bins to break even.

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

[tex] \huge\underline{\sf{\red{Problem:}}}[/tex]

7.) Detemine the value of [tex] \sf{ {3a}^{2} -b.}[/tex]

[tex] \huge\underline{\sf{\red{Given:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{a = 2}[/tex]

[tex]\quad\quad\quad\quad\sf{b = - 1}[/tex]

[tex]\quad\quad\quad\quad\sf{c = - 3}[/tex]

[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{3a}^{2} - b}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶{(3)( 2)}^{2} -( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶3(4)-( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶12-( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶12 + 1 }[/tex]

[tex]\quad \quad \quad \quad ⟶ \boxed{ \sf{ 13}}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{\:13}}}}[/tex]

8.) Find the value of [tex] \sf{ {a}^{3} {b}^{3} - abc.}[/tex]

[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶ {a}^{3} {b}^{3} - abc}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{(2)}^{3} {( - 1)}^{3} - (2)( - 1)( - 3)}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{(8)}{( - 1)} - ( - 2)( - 3)}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{( - 8)} - ( 6)}[/tex]

[tex]\quad\quad\quad\quad ⟶\boxed{\sf{ - 14}}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{-14}}}}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

#CarryOnLearning

[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]