Answer:
Specialisation in the knowledge society and its need
Posted by Bernardo Lajus on Mon, 01/07/2013 - 11:54.
Contemporary society is characterized by globalization. The information and the speed with which they reach society amaze anyone who has experienced the 1980s and 1990s. Because of the technology and facilities it brings, the recipients of this information become increasingly demanding, in every way. Demanding with you, with others, with things, with everything, making the world so demanding, to the point that services and information are insufficient, exhausting, poor.
Because of this, the world specializes. The professions have gained new directions, new perspectives. The courses that were previously generic, such as engineering, law, medicine, became insufficient and were gaining tributaries. If before the general practitioners of mechanical engineering and law realized the professional demand, over the years and the evolution of society, it required professionals to become specialists, creating branches and opening possibilities.
Today, specialists, masters and doctors are essential for the rapid development of society, required everywhere. Despite the harm spawned (such as time demanded, or "knowing much about little), specialization in the knowledge society brings inegulable benefits. The creation of new jobs, the deepening of knowledge and the quality of services makes society evolve even more.
Thus, although the human being, in his individuality, is not expanding his way of knowing, but rather reducing himself to specificity, society as a whole plunges into a profound expansion of knowledge, bringing this to everyday life, from the most trivial to the most complex of works, specialization is necessary and beneficial.
Explanation:
Fill in the blank. ________were marked by total disregard of knowledge of motion and/or anatomical detail.
Early depictions of human movement were marked by total disregard of knowledge of motion and/or anatomical detail.
There was a complete disregard for knowledge of motion and/or anatomical detail in abstract or stylized artwork. Artists purposefully distorted or dispersed the portrayal of objects, including the human figure, in several creative movements or styles, such as Cubism or Surrealism, in order to express a subjective or symbolic meaning. Artworks that prioritised intellectual or emotional expression over accurate representations of motion or anatomical precision were the outcome of this break from realism. Artists sought to challenge preconceived notions and investigate novel ways of expressing the world by ignoring strict fidelity to physical fact. The subject matter was open to creative and thought-provoking interpretations thanks to this deliberate distortion or abstraction.
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The basic chromosome number of yeast cells is 16. A haploid MATa yeast cell trisomic for chromosome 10 is mated to a haploid MATα yeast cell that is disomic for chromosome 1. Indicate all of the following statements about this experiment that are TRUE.
A. The resulting diploid is euploid.
B. The resulting diploid is polyploid.
C. The haploid MATa parent contains 17 chromosomes.
D. The haploid MATa parent is aneuploid.
E. The haploid MATα parent contains 17 chromosomes.
F. The chromosome number of the resulting diploid is 35.
G. The chromosome number of the disomic haploid is written n + 1.
H. The chromosome number of the trisomic haploid is written n + 1 + 1.
In this experiment, we have a haploid MATa yeast cell trisomic for chromosome 10 and a haploid MATα yeast cell disomic for chromosome 1. The basic chromosome number of yeast cells is 16.
C. The haploid MATa parent contains 17 chromosomes. (True - it has one extra copy of chromosome 10, making it trisomic)
D. The haploid MATa parent is aneuploid. (True - since it has an abnormal number of chromosomes)
E. The haploid MATα parent contains 17 chromosomes. (False - it has one extra copy of chromosome 1, making it disomic and having 17 chromosomes)
F. The chromosome number of the resulting diploid is 35. (True - 17 chromosomes from MATa parent and 18 chromosomes from MATα parent)
G. The chromosome number of the disomic haploid is written n + 1. (True - it has one extra copy of a chromosome)
H. The chromosome number of the trisomic haploid is written n + 1 + 1. (False - it should be written as n + 2 since it has two extra copies of a chromosome)
Based on the information provided, statements C, D, F, and G are true.
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Can the sticky ends created by XhoI and SalI ligate to each other? If yes, can the resulting sequences be cleaved by XhoI or SalI?
Yes, Both XhoI and SalI are restriction enzymes that cleave DNA at specific sequences, creating "sticky ends."
Both XhoI and SalI are restriction enzymes that cleave DNA at specific sequences, creating "sticky ends." The sticky ends created by XhoI and SalI cannot ligate to each other because they have different overhang sequences. XhoI creates a 5'-CTCGAG-3' overhang, while SalI generates a 5'-GTCGAC-3' overhang. Since these sequences are not complementary, they cannot anneal or ligate to each other.
If somehow, the XhoI and SalI sticky ends were to be ligated, the resulting sequence would no longer contain the original recognition sites for XhoI (5'-CTCGAG-3') or SalI (5'-GTCGAC-3'). Therefore, the ligated sequence could not be cleaved by either XhoI or SalI.
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Yes, sticky ends created by XhoI and SalI can ligate to each other because they have complementary overhangs.
However, the resulting sequence would not be able to be cleaved by either XhoI or SalI, as the overhangs generated by these enzymes are specific and cannot be recognized by the other enzyme.
For example, if XhoI and SalI were used to digest a plasmid DNA, the XhoI would generate a 5'-CTCGAG-3' overhang, while SalI would generate a 5'-GTCGAC-3' overhang. If these overhangs were allowed to anneal and ligate together, the resulting sequence would have a new sequence of 5'-CTCGAC-3', which would not be recognized by either XhoI or SalI. This means that the resulting sequence cannot be cleaved by these enzymes, making it a unique sequence.
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Which of the following statements about how cells control the size of the poly-A tail on mRNA molecules in order to regulate translation initiation is FALSE?
If a kinase inhibitor was introduced, then CPEB would be phosphorylated, so no conformational change would occur.
If a kinase inhibitor was introduced, then Maskin and PARN would be able to continue to exert their inhibitory effect on translation initiation.
To inhibit translation initiation, a protein called CPEB binds to the CPE sequence on the mRNA. This will then bring in an enzyme called PARN.
To initiate translation, the protein CPEB gets phosphorylated by a specific kinase. This causes a conformational change that excludes both Maskin and PARN.
Without Maskin and PARN, the poly-A tail can extend and eIF4E and eIF4G can interact with each other to initiate translation.
The false statement about how cells control the size of the poly-A tail on mRNA molecules in order to regulate translation initiation is "If a kinase inhibitor was introduced, then CPEB would be phosphorylated, so no conformational change would occur" (Option A).
The statement "If a kinase inhibitor was introduced, then CPEB would be phosphorylated, so no conformational change would occur " is incorrect because if a kinase inhibitor is introduced, it would prevent the phosphorylation of CPEB, not promote it. Without phosphorylation, there would be no conformational change in CPEB, and translation initiation would not be initiated.
The phosphorylation of CPEB by a specific kinase is necessary for the conformational change that excludes both Maskin and PARN, allowing for the extension of the poly-A tail and the initiation of translation.
Thus, the correct option is A.
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the gel-like fluid substance within a mitochondrion is called the
The gel-like fluid substance within a mitochondrion is called the matrix.
Matrix composed of DNA forming mitochondrial genome and enzymes for Citric acid cycle. The enzymes involved in the conversion of fatty acid and pyruvate into acetyl co A are found here. The initial components fatty acids and pyruvates are transported into mitochondria through membrane permeases. The folding inside the mitochondria results in the increase of surface area for many chemical reactions within mitochondria. It consists of ionic granules that help in maintaining ion balance within the matrix. All enzymes are found within the matrix for the TCA cycle but an enzyme succinate dehydrogenase is found in the inner membrane of mitochondria in eukaryotes and cytoplasm in prokaryotes.Know more about mitochondria here
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two organisms have inherited the same gene from a common ancestor. this gene might have different sequences in the two organisms because _____.
Two organisms having different sequences for the same gene inherited from a common ancestor can be attributed to several factors.
Firstly, genetic mutations can occur over time, leading to changes in the DNA sequence. Mutations can arise through various mechanisms, such as errors during DNA replication or exposure to environmental factors. These mutations can accumulate in each organism's lineage, resulting in sequence divergence for the same gene.
Secondly, natural selection can influence the fixation of different variations of the gene in each organism's population. If certain mutations provide a selective advantage in one organism's environment, those variants are more likely to be passed on to subsequent generations, leading to sequence differences.
Genetic drift, which is the random change in allele frequencies over time, can also play a role. In small populations, genetic drift can lead to the fixation of different gene variants, contributing to sequence variation between organisms.
Overall, genetic mutations, natural selection, and genetic drift are key factors that can cause different sequences for the same gene in two organisms descended from a common ancestor.
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Which term can be used to refer to an egg cell at any stage of development, from primary oocyte through fertilization?
The term that can be used to refer to an egg cell at any stage of development, from primary oocyte through fertilization is "oocyte."
The oocyte is the female germ cell that undergoes meiosis to produce the haploid egg cell, which can then be fertilized by a sperm cell. During its development, the oocyte goes through different stages, such as the primary oocyte, which is the immature stage that is arrested in prophase I of meiosis until ovulation, and the secondary oocyte, which is the mature stage that is released during ovulation and can be fertilized by a sperm. After fertilization, the oocyte becomes a zygote and begins to divide and develop into an embryo. Overall, the term "oocyte" encompasses the entire process of egg cell development, from the initial primary oocyte to the mature egg that can be fertilized.
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the only known regulatory mechanism for pyruvate carboxylase is
The only known regulatory mechanism for pyruvate carboxylase is allosteric activation by acetyl-CoA.
Pyruvate carboxylase is an enzyme involved in the metabolic pathway known as gluconeogenesis, where it plays a crucial role in the conversion of pyruvate into oxaloacetate. This enzyme is regulated by several factors, but the only known regulatory mechanism is allosteric activation by acetyl-CoA.
Acetyl-CoA is a molecule formed during the breakdown of carbohydrates, fats, and proteins. It serves as a key regulator of pyruvate carboxylase activity by binding to the enzyme and enhancing its catalytic function. When acetyl-CoA levels are high, it signals the need for increased gluconeogenesis to produce glucose for energy.
The binding of acetyl-CoA to pyruvate carboxylase induces conformational changes in the enzyme's structure, leading to an increase in its catalytic activity. This allosteric activation allows pyruvate carboxylase to effectively convert pyruvate into oxaloacetate, facilitating the continuation of gluconeogenesis.
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the former organic compounds on early earth came from which energy source ?
Answer: the sun's radiation' electrical discharges in form of lightning' and heat from the cooling earth
Explanation:
In animal tissues, the rate of conversion of pyruvate to acetyl-CoA is regulated by the ratio of inactive, phosphorylated pyruvate dehydrogenase complex (PDH) to active, unphosphorylated FD. What happens to the rate of this reaction (increase or decrease) when a preparation of rabbit muscle mitochondria containing the PDH complex is treated with each of the following? Explain your rationale in 1 - 2 sentences. (a) the kinase of pyruvate dehydrogenase, ATP, and NADH (b) the phosphatase of pyruvate dehydrogenase and Ca2+
(a) The rate of the reaction would decrease when the kinase of pyruvate dehydrogenase, ATP, and NADH are added. This is because the kinase enzyme phosphorylates the PDH complex, rendering it inactive and preventing the conversion of pyruvate to acetyl-CoA.
ATP and NADH are necessary cofactors for the kinase reaction.
(b) The rate of the reaction would increase when the phosphatase of pyruvate dehydrogenase and Ca2+ are added. This is because the phosphatase enzyme removes the phosphate group from the PDH complex, activating it and allowing the conversion of pyruvate to acetyl-CoA.
Ca2+ is a necessary cofactor for the phosphatase reaction.
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Name three adaptations that helped plants survive on land, and describe how each of them helped. (2 points)
Three adaptations that helped plants survive on land are cuticle, stomata, and roots. The cuticle protects plants from water loss and UV radiation. Stomata regulate gas exchange, and roots absorb water and nutrients.
When plants moved to land, they had to develop adaptations that would enable them to survive in an environment with fewer resources than they were accustomed to. Three adaptations that helped plants survive on land are discussed below:Cuticle: The cuticle is a waxy layer on the surface of the plant that protects it from water loss and desiccation. This layer is made up of cutin, a waterproof polymer, and is secreted by epidermal cells. The cuticle prevents water from evaporating from the surface of the plant, which is critical for survival in a dry environment. In addition, it also protects the plant from harmful ultraviolet radiation that can damage its DNA.Stomata: Stomata are tiny pores in the leaves and stems of plants that regulate gas exchange and water loss. They are surrounded by guard cells that regulate the opening and closing of the stomata. When there is a need to conserve water, the guard cells can close the stomata to prevent water from evaporating from the plant's surface. When there is a need for carbon dioxide, such as during photosynthesis, the guard cells can open the stomata to allow gas exchange.Roots: Roots are organs that anchor the plant to the ground and absorb water and nutrients from the soil. They allow plants to access water and nutrients that are necessary for survival. Furthermore, roots also help prevent soil erosion and provide support to the plant.Summary: Three adaptations that helped plants survive on land are cuticle, stomata, and roots. The cuticle is a waxy layer on the surface of the plant that prevents water loss and protects the plant from harmful ultraviolet radiation. Stomata are tiny pores that regulate gas exchange and water loss, and roots anchor the plant to the ground and absorb water and nutrients from the soil.For more questions on adaptations
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true/false. casts are fibrous or protein materials, such as pus and fats, that are thrown off into the urine in kidney disease.
False. Casts are cylindrical structures formed in the kidney tubules due to the accumulation of various substances, such as proteins, cells, and debris. They are not thrown off into the urine but rather get washed out along with the urine during urination.
Casts are solid cylindrical structures that can be seen in microscopic examination of urine samples. They are formed within the kidney tubules when certain substances, such as proteins, red or white blood cells, epithelial cells, or cellular debris, accumulate and clump together. The presence of casts in urine can indicate various underlying conditions or diseases affecting the kidneys, such as glomerulonephritis, renal tubular injury, or chronic kidney disease. Different types of casts can be identified based on their composition, including hyaline casts (composed of proteins), granular casts (composed of cellular debris), red blood cell casts, or white blood cell casts. The detection and analysis of casts in urine can provide valuable insights into the functioning and health of the kidneys.
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which system creates blood cells? system
Answer: The Immune system
Explanation:
Answer:
Bone marrow is the soft, spongy area inside most bones. It makes blood cells.
Explanation:
The pliable, squishy interior of most bones is called the bone marrow. It produces the blood cells.
Red and yellow bone marrow are the two primary varieties. Stem cells transform into red blood cells, white blood cells, and platelets in the red bone marrow. Fatty tissue is kept in the yellow bone marrow.
The hip bones (bones of the pelvis), the shoulder bones (scapula), the vertebrae in the spine, the ribs, the breast bone (sternum), and the skull are where adults find the bone marrow that produces the majority of blood cells.
the goal of the census of marine life is to .multiple choice question.maximize the production of marine seafoodcount the population of each species in the marine ecosystemsequence the full dna of each organism in the oceancreate an online encyclopedia that categorizes every existing form of marine life
The goal of the Census of Marine Life is to create an online encyclopedia that categorizes every existing form of marine life.
The Census of Marine Life was a global scientific initiative that aimed to assess and document the diversity, distribution, and abundance of marine organisms. Its primary objective was to create a comprehensive online encyclopedia known as the Ocean Biogeographic Information System (OBIS), which would serve as a resource for researchers, policymakers, and the public. The focus was on cataloging and categorizing every known form of marine life, including species, habitats, and ecosystems. By compiling and organizing data from various sources, the Census of Marine Life aimed to provide a comprehensive understanding of marine biodiversity and the interconnectedness of marine ecosystems. This ambitious project involved collaboration among scientists from around the world and spanned a decade, from 2000 to 2010. The ultimate goal was to enhance our knowledge of marine life, contribute to conservation efforts, and support informed decision-making regarding the sustainable use and management of marine resources.
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explain why acetals do not react with nucleophiles.
Acetals do not react with nucleophiles because they lack a carbonyl group, which is a characteristic feature of aldehydes and ketones that make them susceptible to nucleophilic attack.
Acetals are formed when an aldehyde or ketone reacts with an alcohol in the presence of an acid catalyst. The resulting acetal molecule has two ether linkages (R-O-R') instead of a carbonyl group (C=O). These ether linkages are relatively stable and do not undergo nucleophilic addition or substitution reactions.
In addition, the oxygen atom in an acetal is electron-deficient due to the electron-withdrawing effect of the two alkyl groups attached to it. This makes the oxygen less nucleophilic and less likely to undergo nucleophilic attack. Therefore, acetals are generally inert towards nucleophiles and can be used as protective groups for carbonyl compounds in organic synthesis, as they can be easily removed under mild acidic conditions.
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An owl eats small vertebrates- so does a fox. How is it possible for them to live in the same community? Explain.
Despite the fact that an owl and a fox consume small vertebrates, they can live in the same community due to the fact that they have different hunting techniques, prey choices, and time of activity.
The following are some of the reasons why owls and foxes can live in the same community:
1. Hunting Techniques Owls, as we all know, are nocturnal animals and are capable of hunting in complete darkness. They use their eyesight and hearing to detect and capture prey. Foxes, on the other hand, are opportunistic predators that are more active during the day.
2. Prey Choices Owls prefer to consume rodents, insects, and small vertebrates, while foxes are omnivores that consume a range of foods, including small vertebrates. Although they consume the same food, their preferences may differ. Owls, for example, may prefer to consume mice, whereas foxes may prefer to consume rabbits.
3. Different time of Activity Foxes are more active during the day than owls, which are nocturnal. As a result, their activity periods are different, allowing them to coexist in the same community.
The fact that both animals have different activity periods and prey choices enable them to live in the same community, as they would not be in direct competition for food. Their hunting strategies also differ significantly. Owls prefer to hunt from above, while foxes prefer to stalk their prey from the ground.
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o- and ab are two of the least common blood types. what are some of the characteristics of these two blood types?
The O- and AB blood types are two of the least common blood types. O- is a universal donor blood type, while AB is a universal recipient blood type.
The O- blood type is characterized by the absence of A and B antigens on the red blood cells and the presence of the Rh factor. O- is considered a universal donor blood type, meaning that it can be safely transfused to individuals with other blood types without causing an adverse immune reaction. However, individuals with O- can only receive blood from O- donors.
On the other hand, the AB blood type is characterized by the presence of both A and B antigens on the red blood cells and the presence of the Rh factor. AB is considered a universal recipient blood type, as individuals with AB blood can receive transfusions from donors with any blood type (A, B, AB, or O) without the risk of immune reactions. This is because individuals with AB blood type have both A and B antigens, which makes them compatible with all blood types.
Due to their unique characteristics, O- and AB blood types play important roles in blood transfusion compatibility and are crucial for ensuring the safety and availability of blood for medical procedures.
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Research indicates that stereotyped gender roles are more psychologically constrictive for:
a. girls.
b. boys.
c. children from nuclear families.
d. children from single-parent families.
Research indicates that stereotyped gender roles are more psychologically constrictive for boys. The correct option is B.
Gender stereotypes are beliefs about the characteristics and behaviors that are appropriate for males and females. These stereotypes can be harmful because they can limit the opportunities and choices that people have.
For example, gender stereotypes can lead to boys being discouraged from expressing emotions or pursuing interests that are considered to be feminine. This can have a negative impact on boys' mental health and well-being.
It is important to challenge gender stereotypes and to promote gender equality. This can help to create a more just and equitable society for everyone.
Therefore, the correct option is B, boys.
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Which statement best describes the relationshipbetween the blood of a human fetus and theblood of the mother?a. Their blood systems are separate only at certain times in development and connected at other times.b. The blood flows directly from the mother into the fetus.c. Their blood systems are separate and no materials are exchanged.d. Their blood systems are separate, but certain materials pass from one to the other.
The relationship between the blood of a human fetus and the blood of the mother is complex and dynamic throughout pregnancy. At the very beginning of pregnancy, the embryo implants in the wall of the uterus and forms structures called chorionic villi, which will eventually become the placenta. The placenta is an organ that connects the developing fetus to the mother's blood supply and allows for the exchange of oxygen, nutrients, and waste products.
In general, the blood systems of the fetus and the mother are separate, meaning that they do not actually mix with one another. However, there are small spaces called intervillous spaces in the placenta where maternal blood and fetal blood come very close to one another. This allows for the exchange of materials between the two blood supplies, such as oxygen and carbon dioxide, nutrients like glucose, and waste products like urea.
In summary, the best statement to describe the relationship between the blood of a human fetus and the blood of the mother is that their blood systems are separate, but certain materials pass from one to the other through the placenta.
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which of the follwoing hormones acts on target cells via secondary messenger system? A. Thyroid hormone
B. Aldosterone
C. Cortisol
D. Epinephrine
Epinephrine acts on target cells via a secondary messenger system. Option d. is correct.
Epinephrine, also known as adrenaline, acts on target cells through a secondary messenger system. When epinephrine binds to its specific receptor on the surface of target cells, it triggers a cascade of intracellular signaling events.
These events involve the activation of secondary messengers, such as cyclic adenosine monophosphate (cAMP) or inositol triphosphate (IP3), which relay the signal from the cell surface to the intracellular machinery.
The secondary messenger system allows for amplification and fine-tuning of the cellular response. Upon binding of epinephrine to its receptor, the secondary messengers can activate various intracellular enzymes or ion channels, leading to specific physiological responses.
Examples of these responses include increased heart rate, dilation of blood vessels, and mobilization of energy stores.
In contrast, hormones such as thyroid hormone, aldosterone, and cortisol exert their effects on target cells through direct binding to nuclear receptors and subsequent modulation of gene expression.
These hormones do not rely on secondary messenger systems for their cellular actions.
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some regulatory proteins interact with other proteins or dna sequences to increase or decrease the rate of transcription of a gene.T/F
Some regulatory proteins interact with other proteins or dna sequences to increase or decrease the rate of transcription of a gene. The statement is true.
Regulatory proteins are proteins that bind to DNA and regulate the rate of transcription of genes. They can either increase or decrease the rate of transcription, depending on their specific function.
There are two main types of regulatory proteins: activators and repressors. Activators bind to DNA and increase the rate of transcription. Repressors bind to DNA and decrease the rate of transcription.
Activators and repressors can bind to DNA sequences called promoters and enhancers. Promoters are located upstream of genes, and they are the binding sites for RNA polymerase. Enhancers are located anywhere in the genome, and they can increase the rate of transcription of genes that are located far away from them.
The binding of regulatory proteins to DNA can affect the chromatin structure of the gene. Chromatin is the material that DNA is wrapped around. When regulatory proteins bind to DNA, they can change the way that chromatin is folded, which can either increase or decrease the accessibility of the gene to RNA polymerase.
The binding of regulatory proteins to DNA can also affect the recruitment of other proteins to the gene. These proteins can then modify the DNA or RNA, which can further affect the rate of transcription.
The regulation of gene transcription is a complex process that is controlled by a variety of factors, including regulatory proteins, DNA sequences, and chromatin structure. This regulation is essential for the proper functioning of cells and organisms.
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Amera is discussing the movement of water molecules. What word describes what high temperatures do to water molecules?
A.
expand
B.
constrict
C.
convert
D.
react
The correct option is A. expand.
When water is heated, the water molecules move faster and bump into each other more often. This causes the water to expand, or take up more space.
This is why water boils and turns into steam when it is heated to a high temperature. The water molecules are moving so fast that they break free from the liquid and become a gas.
The other options are incorrect because they do not describe what happens to water molecules when they are heated. Constrict means to make something smaller or narrower, convert means to change something into something else, and react means to act in response to something.
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Biology sol review part three
33) chromosomic mutations are as follow: Mutation 1: AC-DEF ⇒ deletion. Mutation 2: ABBC-DEF ⇒ duplication. Mutation 3: ABC-JKL and GH-IDEF ⇒ Translocation. Mutation 4: AED-CBF ⇒ inversion. 34) Three ragments (two of them double-stranded, one single-stranded). 35) Yes.
What are chromosomic mutations?DNA suffers different mutations and changes. These mutations might affect chromosomes by altering a gene sequence or a chromosomal fragment.
There are two types of chromosomal mutations which depend on the mutation type,
- If the mutation affects the number of the chromosomes (haploidy, polyploidy, aneuploidy)
- If the mutation affects the chromosome structure.
Among the mutations that affect the structure of the chromosome, we can mention,
The ones affecting the number of genes- Deletion ⇒ Occurs a loss of genes
- Duplication ⇒ The number of genes increases
The ones affecting the sequence of genes- Inversion ⇒ genes order or sequence is inverted
- Translocation ⇒ genes are interchanged between chromosomes
33) In the e posed example,
Original sequence: ABC-DEF
Mutation 1: AC-DEF ⇒ deletion (B is lost)Mutation 2: ABBC-DEF ⇒ duplication (B is duplicated)Mutation 3: ABC-JKL and GH-IDEF ⇒ Translocation (DEF changed by JKL)Mutation 4: AED-CBF ⇒ inversion (The fragment BC-DE was inverted)34) Restriction enzyme
A A T G A A T T C C G A T T G A A T T C
T T A C T T A A G G C T A A C T T A A G
A A T G A A ------- T T C C G A T T G A A ------- T T C
T T A C T T A A G ------ G C T A A C T T A A G ----
There would be two double-stranded fragments, and one single-stranded fragment.
A A T G A A
T T A C T T A A G
T T C C G A T T G A A
G C T A A C T T A A G
T T C
35) Electrophoresis
Yes, I believe the defendant committed the crime because the defendant's shirts are all covered in the victim's blood. You can see this because the victim's blood band pattern in the electrophoresis matches the band pattern in the shirts.
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the movement of substances from the nephron tubule back into the bloodstream is referred to as____
Answer: Tubular reabsorption
Explanation:
Tubular reabsorption is the process that moves solutes and water out of the filtrate and back into your bloodstream.
This process is known as reabsorption, because this is the second time they have been absorbed; the first time being when they were absorbed into the bloodstream from the digestive tract after a meal.
move the terms into the correct empty boxes to complete this concept map about epidemiological statistics.
As a text-based AI, I cannot directly manipulate images or move objects in graphical representations. However, I can provide you with a detailed explanation of the main components in an epidemiological concept map and help you understand their relationships. You can use this information to fill in the empty boxes on your map.
1. Epidemiological statistics: These are quantitative data used to study the distribution and determinants of health-related events and diseases in populations.
2. Prevalence: This is a measure of the proportion of individuals in a population who have a specific health-related event or disease at a given time. It is calculated as the number of existing cases divided by the total population.
3. Incidence: This is the rate at which new cases of a health-related event or disease occur in a population during a specified period. It is calculated as the number of new cases divided by the population at risk during the time period.
4. Mortality rate: This is the measure of the number of deaths in a population due to a specific cause during a specified time period. It is calculated as the number of deaths from a specific cause divided by the total population.
6. Risk factors: These are characteristics or exposures that increase the likelihood of developing a disease or health-related event. Examples include age, gender, smoking, and obesity.
7. Protective factors: These are characteristics or exposures that decrease the likelihood of developing a disease or health-related event. Examples include regular exercise, a balanced diet, and immunizations.
By understanding these terms and their relationships, you can complete your concept map about epidemiological statistics effectively.
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the turnover number for an enzyme is known to be 5000 min-1. From the following set of data, compute the Km and the total amount of enzyme present int these experiments.
Substrate concentration (mM) Initial velocity (\mumol/min)
1 167
2 250
4 334
6 376
100 498
1000 499
The Km is 0.0017 mM and the total amount of enzyme present in these experiments is 0.117 μmol.
To compute the Km and the total amount of enzyme present, we first need to plot the initial velocity against the substrate concentration.
Once we plot the data, we can see that it follows Michaelis-Menten kinetics, which is a rectangular hyperbola.
To determine the Km and the total amount of enzyme present, we can use the Lineweaver-Burk plot, which is a double reciprocal plot of 1/V0 versus 1/[S].
To obtain the slope and intercept of the Lineweaver-Burk plot, we can use the following equation:
1/V0 = (Km/Vmax)(1/[S]) + 1/Vmax
Where Vmax is the maximum velocity and Km is the Michaelis constant.
Using the data provided, we can calculate the Vmax by finding the maximum initial velocity, which is 499 μmol/min at a substrate concentration of 1000 mM.
Substituting this value into the equation, we get:
1/Vmax = 1/499 = 0.002
Using the remaining data points, we can calculate the slopes and intercepts of the Lineweaver-Burk plot and obtain the values for Km and Vmax.
Slope = Km/Vmax
Intercept = 1/Vmax
Using the data, we get:
1/167 = 0.006
1/250 = 0.004
1/334 = 0.003
1/376 = 0.003
1/498 = 0.002
1/499 = 0.002
Plotting these values on a graph and drawing the line of best fit, we can calculate the slope and intercept.
Slope = 1.006 mM/min
Intercept = 0.0017 min/μmol
Using the equations for slope and intercept, we can solve for Km and Vmax:
Slope = Km/Vmax
Intercept = 1/Vmax
Km = Slope x Intercept = 1.006 mM/min x 0.0017 min/μmol = 0.0017 mM
Vmax = 1/Intercept = 1/0.0017 min/μmol = 588 μmol/min
Now that we have calculated the values for Km and Vmax, we can use the turnover number (5000 min-1) to calculate the total amount of enzyme present.
Turnover number = Vmax/[E]
Where [E] is the total amount of enzyme present.
Substituting the values we obtained, we get:
5000 min-1 = 588 μmol/min / [E]
[E] = 0.117 μmol
Therefore, the Km is 0.0017 mM and the total amount of enzyme present in these experiments is 0.117 μmol.
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identify whether members of the following genus are always pathogens or an opportunistic pathogen: salmonella pathogen opportunistic pathogen
Salmonella is an opportunistic pathogen, causing infections when it enters a susceptible host, typically through contaminated food or water.
Salmonella is an opportunistic pathogen, meaning it is not always harmful but can cause infections in certain situations, such as entering a susceptible host.
This genus comprises multiple species, with some causing foodborne illnesses such as Salmonella enterica serovar Typhimurium and Salmonella enterica serovar Enteritidis.
These infections can result from ingesting contaminated food or water, leading to symptoms like diarrhea, fever, and abdominal cramps.
Although salmonella is not always pathogenic, proper food handling and hygiene practices are crucial in preventing illness and the spread of these opportunistic pathogens.
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Salmonella is a genus of bacteria that includes two species, Salmonella enterica and Salmonella bongori. While some strains of Salmonella are capable of causing diseases in humans, animals, and birds, not all members of the genus are always pathogens. Therefore, Salmonella can be considered as an opportunistic pathogen.
Salmonella enterica is the species responsible for the majority of human illnesses caused by Salmonella. This bacterium is typically found in the intestines of infected individuals, where it can cause gastroenteritis and other symptoms. Salmonella infections can occur through the consumption of contaminated food or water, contact with infected animals, or person-to-person transmission.
On the other hand, Salmonella bongori is typically found in cold-blooded animals and is less commonly associated with human infections. It is not generally considered a human pathogen but can cause disease in immunocompromised individuals.
Therefore, while some strains of Salmonella can be considered obligate pathogens, not all members of the genus are always pathogenic. The pathogenicity of Salmonella depends on several factors, including the strain, the host, and the environment.
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a mutation in a cell leads to it being unable to produce signal recognition particles (srps). what would be the most likely outcome of this mutation on the cell’s protein production? the cell would…
The most likely outcome of this mutation on the cell's protein production would be that the cell would have difficulty targeting proteins to the endoplasmic reticulum (ER) for further processing and transportation.
SRPs play a critical role in guiding newly synthesized proteins to the correct cellular compartment, and without them, the proteins would likely accumulate in the cytosol or be mis localized to other parts of the cell. This could lead to a variety of problems, including disrupted cellular function and potentially harmful effects on the organism as a whole.
This is because SRPs play a crucial role in protein targeting by recognizing and binding to the signal sequence of newly synthesized proteins. They help guide the ribosome-protein complex to the ER membrane, where the protein can be translocated into the ER lumen. Without SRPs, the cell would have a hard time correctly targeting and processing these proteins, leading to inefficient protein production and potential accumulation of misfolded proteins.
Therefore, If a mutation in a cell leads to it being unable to produce signal recognition particles (SRPs), then the most likely outcome of this mutation on the cell's protein production is that the proteins produced by the cell will not be properly transported to their intended destinations.
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the __________ or living component of any environment includes all individuals of each species that interact in that habitat.
Answer:
Explanation:
Biotic
how can oil spills reduce the photosynthetic ability of phytoplankton?
Oil spills can reduce the photosynthetic ability of phytoplankton through various mechanisms like Light blockage, Toxicity, Disruption of gas exchange, Formation of oil-emulsion mixtures.
1. Light blockage: Oil forms a slick on the water surface, which reduces the penetration of sunlight into the water column. Phytoplankton rely on sunlight for photosynthesis, so the reduced light availability hinders their ability to carry out photosynthesis effectively.
2. Toxicity: Oil contains toxic compounds, including hydrocarbons and heavy metals, which can directly harm phytoplankton. These toxic substances can damage the photosynthetic machinery of phytoplankton cells, disrupting their metabolic processes and inhibiting photosynthesis.
3. Disruption of gas exchange: Phytoplankton require access to carbon dioxide for photosynthesis. Oil spills can create a physical barrier on the water surface, limiting the exchange of gases between the atmosphere and the water. This restricts the availability of carbon dioxide for phytoplankton, impeding their photosynthetic activity.
4. Formation of oil-emulsion mixtures: Oil spills can form emulsion mixtures with water, resulting in the formation of tiny oil droplets suspended in the water column. These oil droplets can adhere to phytoplankton cells, coating their surfaces and interfering with their nutrient uptake and gas exchange, leading to reduced photosynthetic rates.
Overall, oil spills have detrimental effects on phytoplankton's photosynthetic ability by reducing light availability, introducing toxicity, disrupting gas exchange, and interfering with nutrient uptake processes. This can have cascading impacts on marine ecosystems, affecting the entire food web and ecosystem productivity.
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