Answer:
0.1m
Explanation:
k = 64N/m
Ep = 0.32J
x = ?
Ep = 1/2 * kx²
make x the subject of the formula
x² = 2Ep/k
x = √(2Ep/k)
x = √(0.64/64)
x = √0.01
x = 0.1m
How quickly will a 4 kg ball be accelerated if it is struck by a 12 N force?
Explanation:
Hey there!
Given that 4kg ball struck by 12 N force.
So, we need acceleration.
Force = Mass × Acceleration
And, so
Acceleration = Force / Mass.
Acceleration = 12/4
Acceleration is equal to 3m/s² in SI units.
Hope it helps :)
The air pressure inside a car tire is
3.00 atm, and it creates 41,500 N
of force pushing out on the tire.
What is the surface area of the
inside of the tire?
(Unit = m^2)
Answer:
[tex]A=0.136\ m^2[/tex]
Explanation:
The air pressure inside a car tire is 3 atm = 303975 Pa
The force of 41,500 N of force pushing out on the tire.
We need to find the surface area of the inside of the tire. The pressure acting on an object is given by :
[tex]P=\dfrac{F}{A}\\\\A=\dfrac{F}{P}\\\\A=\dfrac{41500}{303975}\\\\A=0.136\ m^2[/tex]
So, the surface area of the inside of the tire is [tex]0.136\ m^2[/tex].
scientific notation
1. 0,000034
2. 0,0054
3. 346574
4. 0,00125
5. 348954
Answer:
1. 3.4 x10^-5
2. 5.4 x10^-3
3. 346574
4. 12.5x10^-4
5. 348954
Hope this helps, please mark me brainliest if it does! :)
7. A ball is dropped from a height of 4.0 m. Just before it hits the ground it's momentum is
8.85 kg-m/s. What is the mass of the ball?
Answer:
Approximately [tex]1\; \rm kg[/tex]. (Assumption: [tex]g = 9.8\; \rm m \cdot s^{-2}[/tex].)
Explanation:
Let the mass of this ball be [tex]x\; \rm kg[/tex].
Initial gravitational potential energy of this ball: [tex]m \cdot g \cdot h \approx (39.2\, x) \; \rm J[/tex].
Just before the ball hits the ground, all [tex](39.2\, x)\; \rm J[/tex] of gravitational potential energy would have been converted to kinetic energy. Calculate the velocity of the ball at that moment:
[tex]\begin{aligned} \text{kinetic energy} = \frac{1}{2}\, m \cdot v^{2} \end{aligned}[/tex].
Therefore, right before hitting the ground, the velocity of the ball would be:
[tex]\begin{aligned} v&= \sqrt{\frac{2\, (\text{kinetic energy})}{m}} \\ &= \sqrt{\frac{2 \times (39.2\, x)}{x}}\\ & \approx \sqrt{2 \times 39.2} \approx 8.85\; \rm m \cdot s^{-1}\end{aligned}[/tex].
The momentum [tex]p[/tex] of an object of mass [tex]m[/tex] and velocity [tex]v[/tex] would be [tex]p = m \cdot v[/tex]. Rewrite this equation to find an expression for mass [tex]m\![/tex] given velocity [tex]v\![/tex] and momentum [tex]p\![/tex]:
[tex]\displaystyle m = \frac{p}{v}[/tex].
Right before collision, the momentum of this ball is [tex]p = 8.85\; \rm kg \cdot m \cdot s^{-1}[/tex] while its velocity is [tex]v \approx 8.85\; \rm m \cdot s^{-1}[/tex]. Therefore, the mass of this ball would be:
[tex]\begin{aligned}m &= \frac{p(\text{right before landing})}{v(\text{right before landing})} \\ &\approx \frac{8.85\; \rm kg \cdot m \cdot s^{-1}}{8.85\; \rm m \cdot s^{-1}} \approx 1\; \rm kg\end{aligned}[/tex].
An element has a charge of -3, has 8 protons, 11 neutrons, and electrons
Word Bank:
12 5 11 8 13
pls help
2. What is the y-component of a 95.3 N force that is exerted at 57.1
degree to the horizontal, *
Answer: 80N
Explanation:
The y-component would be the magnitude of the force multiplied by the sine of the angle.
[tex]95.3*\sin(57.1)=80N[/tex]
The y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.
What is Force?Force is defined as an external agent which is capable of changing the state of rest or motion of a body with magnitude and direction. The direction towards which the force is applied is known as the direction of the force, and the point of application of the force is where the force is applied.
It can be expressed as:
F = m a
Where, F= Force
m= mass of the object
a= acceleration
In the given example, the force acts as vector which is broken down into the components. Given the angle θ along the horizontal axis,
so, For x component [tex]F_x[/tex] = Fcosθ
For y component [tex]F_y[/tex] = F sinθ
Given, F= 95.3 N ; θ= 57.1 °
[tex]F_y = (95.3) * (sin 57.1)\\ F_y= 80.0N[/tex]
Thus, the y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.
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An ice skater accelerates backward for 5.0 second to final speed of 12m/s. If the acceleration backward was at a a rate of 1.5m/s2 what was the skater's initial speed
Answer:
Initial velocity, U = 4.5m/s
Explanation:
Given the following data;
Final velocity, v = 12m/s
Time, t = 5 seconds
Acceleration, a = 1.5m/s²
To find the initial velocity, we would use the first equation of motion.
[tex] V = U + at[/tex]
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Substituting into the equation, we have;
12 = U + 1.5*5
12 = U + 7.5
U = 12 - 7.5
Initial velocity, U = 4.5m/s
no one can answer
why electrons are negetive?
Answer:
they're negative bc a proton is positive. a proton attracts an electron by the fact that opposite charges attract each other, while two electrons repel each other. Thus it shows that polarity of the charge on an electron and a proton is opposite.
Explanation:
Which of the following represents a chemical change?
A. Melting
of ice to water.
B. Combustion of a firecracker
C. Salt dissolves in water
D. The iron stretched into wires-ductile and iron pounded into sheets-malleable.
Explain why the following statement is either true or false: The idea that all matter consists of the elements was first introduced a few hundred years ago
It is a true statement that the idea that all matter consists of elements was first introduced a few hundred years ago.
What is the matter?Anything which has mass and occupies space is known as matter, mainly there are four states of matter solid liquid gas, and plasma.
These different states of matter have different characteristics according to which they vary their volume and shape.
Individuals have believed that earth, air, water, and fire are the only four elements that make up matter for roughly two thousand years.
For more than two thousand years, Aristotle's theory that all matter is composed of just four elements was accepted, but only around 500 years ago did scientists begin to find all of the elements that are currently recognized.
Beginning around five hundred years ago, scientists started learning about all of the elements that are currently recognized.
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To test the strength of a retainment wall designed to protect a nuclear reactor,
a rocket-propelled F-4 Phantom jet aircraft was crashed head-on into a
concrete barrier at high speed in Sandia, New Mexico, on April 19, 1988. The
F-4 phantom had a mass of 19,100 kg, while the retainment wall's mass was
469,000 kg. The wall sat on a cushion of air that allowed it to move during
impact. If the wall and F-4 moved together at 8.41 m/s during the collision,
what was the speed of the F-4 Phantom upon impact?
Answer:
The speed of the F-4 Phantom upon impact is approximately 214.92 m/s
Explanation:
The given parameter of the motion of the F-4 Phantom jet aircraft are;
The mass of the F-4 phantom rocket, m₁ = 19,100 kg
The mass of the retaining wall, m₂ = 469,000 kg
The velocity of the combined mass of the wall and the F-4 after collision, v₃ = 8.41 m/s
The retainment wall was initially at rest, therefore, v₂ = 0 m/s
Let 'v₁', represent the speed of the F-4 Phantom upon impact
By the principle of conservation of linear momentum, we have;
m₁·v₁ + m₁·v₂ = m₁·v₃ + m₂·v₃ = (m₁ + m₂)·v₃
Plugging in the values, we have;
19,100 × v₁ + 469,000 × 0 = (19,100 + 469,000) × 8.41
∴ v₁ = (19,100 + 469,000) × 8.41/(19,100) = 214.917329843
v₁ ≈ 214.92
The speed of the F-4 Phantom upon impact, v₁ ≈ 214.92 m/s.
How do limiting factors impact Pacific Coast organisms?
Answer:
Limiting factors include a low food supply and lack of space. Limiting factors can lower birth rates, increase death rates, or lead to emigration. When organisms face limiting factors, they show logistic growth (S-shaped curve, curve B: Figure below). ... Limiting factors determine the carrying capacity of a population.
Explanation:
The planet Jupiter has much more mass than Earth. What would happen to an astronaut who landed on Jupiter
A. The astronaut would weigh somewhat less on Jupiter than on Earth
B. The astronaut would have the same weight on Jupiter as on Earth
C. The astronaut would be weightless on Jupiter
D. The astronaut would weigh mire on Jupiter than on Earth
Answer:
A. The astronaut would way somewhat less
The planet Jupiter has much more mass than Earth, is an astronaut who landed on Jupiter would weigh more on Jupiter than on Earth. Thus, the correct option is D.
What is Jupiter?
Jupiter is a planet of the Solar system of the Milkyway galaxy. It is made up of mostly hydrogen and helium gas. The temperature on this planet is extremely hot and an astronaut landing on this planet will experience free-floating in mid-Jupiter with no way of escaping.
Jupiter has more mass than that of the Earth thus, it exerts greater gravitational force than the Earth, and the weight is equal to the product of the mass and the gravitational acceleration. So, the mass of an astronaut will remain constant when he or she move from earth to jupiter however the weight of the astronaut will increase on jupiter.
Therefore, the correct option is D.
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If you have observed something about the world and want to
investigate it further, what are you seeking to do?
a Do background research
b Construct a hypothesis
C Ask a question
d Report the results
Answer: a
Explanation: :)
An excited 92 kg football player celebrates a touchdown by carelessly running straight into the goalpost at 9.4 m/s. He bounces straight backward at 6.2 m/s. What was the change in velocity? What was the impulse of the player?
Answer:
i. 15.6 m/s
ii. I = 1.44 KNs
Explanation:
The impulse, I, on a body is the product of force applied on it and the time it acts.
i.e I = F x t
Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.
i. mass, m, of the player = 92 kg
initial velocity of the player, u = 9.4 m/s
final velocity of the player, v = 6.2 m/s
Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.
So that,
change in velocity of the player = final velocity - initial velocity
= 6.2 - (-9.4)
= 6.2 + 9.4
= 15.6 m/s
change in velocity of the player is 15.6 m/s
ii. Impulse, I = m(v - u)
= 92 x 15.6
= 1435.2
Impulse on the player is 1.44 KNs.
A bird is flying with a speed of 18.0 m/s over water when it accidentally drops a 2.00 kg fish. If the altitude of the bird is 5.40 m and friction is ignored, what is the kinetic energy of the fish when it hits the water?
its in the pic plz help
Answer:
Hand soap: basic
chocolate milk: neutral
apple juice: acidic
shampoo: acidic
mouthwash: acidic
tap water: basic
Explanation:
Check your PH scale
1-6 = acidic
7 = neutral
8-14 = basic
3. A ferryboat accelerates from rest at a rate of 0.500 m/s2.
a. What is the velocity of the boat after it has traveled 4.75 m?| I
Answer:
2.18 m/s.
Explanation:
Formula for angular acceleration
Answer:
[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]
Explanation:
The angular acceleration is given by the relation as follows :
[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]
Where
[tex]\omega_i\ and\ \omega_f[/tex] are the initial and final angular velocities
t is time
The SI unit of angular acceleration is rad/s². Hence, this is the required solution.
A book of mass 1.5 ,kg exerted a downward force on the table
What is the direction of this second force?
Answer:
up ward force it is balanced by dow ward force
A tennis ball is dropped from a height of 1.21m above the ground. Calculate its velocity when it is 0.27m from the ground.
The velocity of hitting the ground is 4.86 m/s and the velocity after hitting the ground is 4.53 m/s.
What is Velocity?Velocity can be defined as the direction of movement of the body or object. Velocity is a vector quantity. It is the rate of change of displacement.
Given data,
Initial velocity when dropped(u)=0 m/s
Distance traveled(s)=1.21 m/s
Distance traveled after leave the ground(s1) = 1.05 ms
According to third law of motion,
v² = u² + 2gs
Initial velocity u=0
v² = 2gs or v = [tex]\sqrt{2gs}[/tex]
by putting the value of s
v (hitting) = √(2 × 9.8 × 1.21) = [tex]\sqrt{23.71}[/tex] = 4.86m/s
After leaving ground at 1.21 m final velocity will be zero
So, velocity just after left the ground will be
2 = √(2 × 9.8 × 1.05) = [tex]\sqrt{20.58}[/tex] = 4.53m/s
So, velocity of hitting the ground is 4.86 m/s and after hitting is 4.53 m/s.
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A 9 V battery produces a current of 18 amps. What is the resistance?
[tex] \sf• \: Battery \: Voltage \: (V) = 9 \: v[/tex]
[tex] \sf• \: Current \: (I) = 18 \: Amps.[/tex]
[tex] \\ [/tex]
[tex]\bf{ \underline{To \: Find :- }}[/tex][tex] \sf• \: The \: Resistance. [/tex]
[tex] \\ [/tex]
[tex] \huge\bf{ \underline{Solution :- }}[/tex]
[tex] \bf \red{ \bigstar{ \: Formula \: of \: Resistance \: (R) = \frac{V}{I}}}[/tex]
[tex] \rightarrow \sf R = \frac{9}{18} [/tex]
[tex] \rightarrow \sf R = \frac{1}{2}[/tex]
[tex] \rightarrow \sf R = 0.5[/tex]
[tex] \\ [/tex]
[tex] \bf \purple{Therefore, \: the \: \: resistance \: \: is \: \: 0.5 \: Ω \: .}[/tex]A hockey puck that has a mass of 0.170 kg travels with a speed of 42.0 m/s.
What is the momentum of the puck?
Answer:
Momentum = 7.14 Kgm/s
Explanation:
Given the following data;
Mass = 0.170 kg
Velocity = 42m/s
To find the momentum;
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
Momentum = mass * velocity
Substituting into the equation, we have;
Momentum = 0.170 * 42
Momentum = 7.14kgm/s
Therefore, the momentum of the honey puck is 7.14 Kgm/s.
You toss a walnut at a speed of 15.0 m/s at an angle of 50.0∘ above the horizontal. The launch point is on the roof of a building that is 20.0 m above the ground.
a)How long after it is launched does the walnut reach the ground?
b)How far does the walnut travel horizontally from launch point to landing point?
c) What are the horizontal and vertical components of the walnut’s velocity just before it reaches the ground? Suppose that the +y-axis is directed upward and the +x-axis is directed horizontally from the launch point toward the landing point.
Answer:
a.3.51s
b.33.8m
c. 9.64,-22.9
Explanation:
(a) The time taken be "3.5083 sec".
(b) The distance will be "33.82 m".
(c) The horizontal and vertical components be "9.64 m/s and -22.89 m/s".
Velocity and DirectionAccording to the question,
Speed, V₀x = 15 Cos (50.0°)
= 9.64 m/s
V₀y = 15 Sin (50.0°)
= 11.49 m/s
Vertical displacement = -20.0 m
(a) We know the relation between displacement, time and acceleration
→ y = vt + [tex]\frac{1}{2}[/tex]at²
By substituting the values,
→ -20.0 = 11.49 t - 4.9 t²
4.9 t² - 11.49 t - 20.0 = 0
t = [tex]\frac{11.49 + \sqrt{132.02+392} }{9.8}[/tex]
= [tex]\frac{11.49 + 22.89}{9.8}[/tex]
= 3.5083 sec
(b) We know the formula,
Distance = Speed × Time
or,
→ X = 9.64 t
= 9.64 × 3.5083
= 33.82 m
(c) Again by using the above relation, we get
Vx = V₀x
= 9.64 m/s
Vy = V₀y - gt
By substituting the values,
= 11.49 - 9.8 × 3.5083
= 11.49 - 34.38
= -22.89 m/s
Thus the response above is correct.
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27. Julie and Ashwin were doing an experiment in the classroom. They
each had to move a 15 kg box. Julie was able to move her box, but
Ashwin was only able to move his after removing half the items in the
box. Which is true regarding the force he applies after removing the
items from the box?
a
He has to apply more force to lift the box
because the mass is greater.
b
He has to apply less force to lift the box
because the mass has decreased.
С
He has to apply a different type of force after
changing the mass.
d
He has to apply the same amount of force to
the box to overcome gravity.
Answer:
b. He has to apply less force to lift the box because the mass has decreased.
Explanation: i just took a ck12 test and it was right lol
If a 5.5 kg object experiences 15 N of force for .15 seconds what is the speed change
The speed change : Δv = 0.41 m/s
Further explanationGiven
mass = 5.5 kg
Force = 15 N
time = 0.15 s
Required
the speed change
Solution
Newton 2nd's law
Impulse and momentum
F = m.a
F = m . Δv/t
F.t = m.Δv
Input the value :
15 N x 0.15 s = 5.5 kg x Δv
Δv = 0.41 m/s
need help someone please
Answer:
C would be the correct answer.
What is the net force of a scooter acting on the road with an impulse of 550 Ns for 10s.
Answer:
55N
Explanation:
Impulse is the product of Force and Time
Impulse = Force * Time
Given
Impulse = 550Ns
Time = 10s
Force = Impulse/Time
Force = 550/10
Force = 55N
Hence the net force on the scooter is 55N
walks 5 meters in 5 seconds what is the average speed
Answer:
10 is the speed
Explanation:
this is y
When you push an object, it pushes back with an equal and opposite force
Answer:
I would say false
Explanation:
Because friction slows it down which means when the object bounces back it will not have the same energy or force that was applied before.