Answer:
12
Step-by-step explanation:
2 of, 50 pence, = 1 pound. So multiply 6 by 2, you get 12. Your answer should be 12.
Hope this helps!
Maybe brainliest?
18h 19min 26s
+ 25h 45min 48s
Answer:
2 days 5 minuts 14 seconds
Step-by-step explanation:
1 1 1 1 1
18 19 26
+25 45 48
1 24 05 14
Suppose a day from this city is selected at random. Let
event A = heavy traffic and event B = bad weather. Are
events A and B independent?
Answer:
The two events are not independent
Step-by-step explanation:
Two events are said to be independent only when the change in one event affect the other event.
Here the two given events are not independent.
Band weathers such as heavy rainfall, snowfall etc. leads to failure of traffic management system and thereby causes heavy traffic. This is easily seen in all major urban cities.
Hence, the two events are not independent as the traffic is affected by the weather conditions.
Lorrie bought 3 1/2 yards of ribbon. She had 2 feet 6 inches of ribbon left after trimming a banner. How many inches of ribbon did Lorrie use for the banner?
Answer:
7 ft 11 inches
Step-by-step explanation:
Convert 3 1/2 yards into 10 ft 5 inches.
Subtract 2 ft 6 inches from 10 ft 5 inches.
Lorrie used 88 inches of ribbon for the banner.
What are Arithmetic operations?Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions.
The operator that performs the arithmetic operation is called the arithmetic operator.
We have been given that Lorrie bought 3 1/2 yards of ribbon. She had 2 feet 6 inches of ribbon left after trimming a banner.
We have to determine the number of inches of ribbon did Lorrie use for the banner.
Here the quantity of ribbon bought by Lorrie = 3 1/2 yard = 3.5 yard
The quantity of ribbon she has left.
⇒ 2 ft 6 inches
⇒ 2×12 + 6
∵ 1 feet = 12 inches
⇒ 30 inches
Since we know that 1 yard = 36 inch
So 3.5 yard = 36×3.5 inches = 126 inches
The quantity of ribbon which is trimmed :
⇒ 126 - 30 = 88 inches
Therefore, Lorrie used 88 inches of ribbon for the banner.
Learn more about Arithmetic operations here:
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The graph below represents a recent 10 meter race between two remote control cars.
A graph titled Remote Control Car Race has seconds after race start on the x-axis and distance from start line (meters) on the y-axis. A line labeled red car goes through (3, 2) and (6, 4). A line labeled blue car goes through (3, 0) and (5, 2).
Which statements about the race are true? Check all that apply.
The red car won the race because it started above the blue car.
The cars crashed at 9 seconds into the race because that is the point of intersection, and neither car continued on after that point in time.
The blue car passed the red car at 6 m into the race because that is the point of intersection, and the blue car has a greater distance than the red car after that time.
The blue car is faster because the slope of its line is steeper than the slope of the line representiong the red car.
The blue car started 3 seconds late because it has an x-intercept of (3, 0) and x represents the time and y represents the distance from the starting line.
Answer:
options c d e
Step-by-step explanation:
Answer:
C D E
Step-by-step explanation:
Expression Name
Expression
E
–8 + 4∕7
F
7 – 0.5
G
9 + (–3)
H
3.8 – 6.7
The table above shows four numeric expressions. Which expression is an integer when it's evaluated?
Answers
A)
H
B)
F
C)
E
D)
G
Answer:
G
Step-by-step explanation:
9+(-3) = 6
Find the equation of a line perpendicular to 3x−4y=6 that contains the point (2,−4).
Answer: y= -4x/3 - 4/3
Step-by-step explanation:
The equation of the line in the slope-intercept form is y=3x4−32.
The slope of the perpendicular line is negative inverse: m=−43.
So, the equation of the perpendicular line is y=−4x3+a.
To find a, we use the fact that the line should pass through the given point: −4=(−43)⋅(2)+a.
Thus, a=−43.
Therefore, the equation of the line is y=−4x3−43.
Answer:
Step-by-step explanation:
y=mx+b
3x-4y=6
4y=3x-6
y=(3x-6)/4
So the slope, m, is 3/4
For lines to be perpendicular m1(m2)=-1, in this case
3m/4=-1
m=-4/3 so our line so far is
y=-4x/3+b, using point (2,-4) we can solve for the y intercept or b
-4=-4(2)/3+b
b=-4/3 so
y=(-4x-4)/3
In ΔABC, a = 660 cm, b = 680 cm and c=100 cm. Find the measure of ∠B to the nearest degree.
Answer:
m∠B = [tex]97^{o}[/tex].
Step-by-step explanation:
Since the three sides of the triangle are given, then we apply cosine rule.
[tex]b^{2}[/tex] = [tex]a^{2}[/tex] + [tex]c^{2}[/tex] - 2ac Cos B
But, a = 660 cm, b = 680 cm, and c = 100 cm.
So that;
[tex]680^{2}[/tex] = [tex]660^{2}[/tex] + [tex]100^{2}[/tex] -2(660 x 100) Cos B
462400 = 435600 + 10000 - 132000 Cos B
462400 = 445600 - 132000 Cos B
132000 Cos B = 445600 - 462400
= -16800
Cos B = [tex]\frac{-16800}{132000}[/tex]
= -0.1273
B = [tex]Cos^{-1}[/tex] -0.1273
= [tex]97^{o}[/tex]
Thus, measure of ∠B is [tex]97^{o}[/tex].
Answer:
M∠B = 97 degrees
Step-by-step explanation:
⅔n = 10
pls help me again
Which value should be added to this data set to produce a mean of 13?
should be added to the data set to produce a mean of 13.
,Answer:
18
Step-by-step explanation:
edg 2021, i got this question correct, please mark me brainliest, I hope this helps, sorry for the late reply
select the equation of the line that passes through the point (3,-1) and is parallel to the line on the graph
At a factory that produces pistons for cars, Machine 1 produced 174 satisfactory pistons and 116 unsatisfactory pistons today. Machine 2 produced 180 satisfactory pistons and 20 unsatisfactory pistons today. Suppose that one piston from Machine 1 and one piston from Machine 2 are chosen at random from today's batch. What is the probability that the piston chosen from Machine 1 is satisfactory and the piston chosen from Machine 2 is unsatisfactory
Answer:
[tex]0.7[/tex] is the probability that the piston chosen from Machine 1 is satisfactory and the piston chosen from Machine 2 is unsatisfactory
Step-by-step explanation:
The two events are independent of each other.
Hence the probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 is equal probability of choosing satisfactory piston from Machine 1 + probability of choosing unsatisfactory piston from Machine 2
Substituting the given values we get
Probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 =[tex]\frac{174}{174 +116} + \frac{20}{180 +20}[/tex]
=[tex]\frac{174}{174 +116} + \frac{20}{180 +20}[/tex]
=[tex]= \frac{174}{290} + \frac{20}{200}\\= 0.6 + 0.1\\= 0.7[/tex]
which ordered pair would form a proportional relationship with the point graphed below?
Answer:
[tex](x,y) = (-30,10)[/tex]
Step-by-step explanation:
Given
[tex](x,y) = (60,-20)[/tex]
Required:
Determine a pair with a proportional relationship
A proportional relationship is:
[tex]k = \frac{y}{x}[/tex]
Where k is the constant of proportionality.
[tex](x,y) = (60,-20)[/tex]
So, we have:
[tex]k = \frac{-20}{60}[/tex]
[tex]k = -\frac{1}{3}[/tex]
This means that for a pair to have a proportional relation, k must be -1/3.
This is true for (c).
Where:
[tex](x,y) = (-30,10)[/tex]
So, we have:
[tex]k = \frac{10}{-30}[/tex]
[tex]k = -\frac{1}{3}[/tex]
A new process of more accurately detecting anaerobic respiration in cells is being tested. The new process is important due to its high accuracy, its lack of extensive experimentation, and the fact that it could be used to identify five different categories of organisms: obligate anaerobes, facultative anaerobes, aerotolerant, microaerophilic, and n anaerobes instead of using a single test for each category. The process claims that it can identify obligate anaerobes with 97.8% accuracy, facultative anaerobes with 98.1% accuracy, aerotolerant with 95.9% accuracy, microaerophiles with 96.5% accuracy, and n anaerobes with 99.2% accuracy. If any category is not present, the process does not signal. Samples are prepared for the calibration of the process and 31% of them contain obligate anaerobes, 27% contain facultative anaerobes, 21% contain microaerophiles, 12% contain nanaerobes, and 9% contain aerotolerant. A test sample is selected randomly.
Required:
a. What is the probability that the process will signal?
b. If the test signals, what is the probability thatmicroaerophiles are present?
Answer:
a) 0.97605 = 97.605% probability that the process will signal.
b) 0.2076 = 20.76% probability that microaerophiles are present.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
a. What is the probability that the process will signal?
It signals in these following moments:
97.8% of 31%(contains obligate anaerobes).
98.1% of 27%(contains facultative anaerobes).
96.5% of 21%(contains microaerophiles).
99.2% of 12%(contains nanaerobes).
95.9% of 9%(contains aerotolerant). So
[tex]p = 0.978*0.31 + 0.981*0.27 + 0.965*0.21 + 0.992*0.12 + 0.959*0.09 = 0.97605[/tex]
0.97605 = 97.605% probability that the process will signal.
b. If the test signals, what is the probability thatmicroaerophiles are present?
Event A: Test signals
Event B: Contains microaerophiles
0.97605 = 97.605% probability that the process will signal.
This means that [tex]P(A) = 0.97605[/tex]
Intersection of events A and B:
Signals containing microaerophiles, which is 96.5% of 21%. So
[tex]P(A \cap B) = 0.965*0.21 = 0.20265[/tex]
The probability that microaerophiles are present is:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.20265}{0.97605} = 0.2076[/tex]
0.2076 = 20.76% probability that microaerophiles are present.
Common ratio of 135,45, 15, 5,
9514 1404 393
Answer:
1/3
Step-by-step explanation:
If the ratio is common, you can choose any successive numbers to compute it. Smaller numbers may be more familiar. The ratio is ...
5/15 = 1/3
A rocket is fired into the air modeling the equation h = -16t2 + 512t + 50, where "t" is the time in seconds and "h" is the
3
height in feet
Find x for the trapezoid.
J
K
(2x+15).. (3x-20).
(x +15).
N4
M.
Answer:
50°
Step-by-step explanation:
All quadrilaterals' interior angles sum to 360°:
(x + 15)° + (2x + 15)° + (3x - 20)° + x° = 360°
x + 15 + 2x + 15 + 3x - 20 + x = 360
7x + 10 = 360
7x = 360 - 10
7x = 350
x = 50°
Tasha is packing gift bags that include
the same items. She has 72 glow sticks,
36 markers, and 24 bottles of bubbles.
Tasha believes that she can pack no
more than 6 bags using all of her
supplies. Do you agree with Tasha? Explain.
Answer:
No, I do not.
She can pack up to 12 bags
Step-by-step explanation:
Given
[tex]Glow\ sticks = 72[/tex]
[tex]Markers = 36[/tex]
[tex]Bubbles = 24[/tex]
Required
Is Tasha correct?
The maximum number of bags she can pack is determined by the greatest common factors (GCF) of the items.
i.e. GCF of 72, 36 and 24.
This is calculated as:
[tex]24 = 2*2*2*3[/tex]
[tex]36 = 2 * 2 *3*3[/tex]
[tex]72 = 2 * 2 * 2 *3*3[/tex]
Multiply all common factors:
[tex]GCF = 2 * 2 * 3[/tex]
[tex]GCF = 12[/tex]
The GCF is 12.
This implies that she can pack up to 12 bags
surface area of a sphere with radius 19
Answer:
A≈4536.46
Step-by-step explanation:
I hope this helps! ^^
☁️☁️☁️☁️☁️☁️☁️
Answer:
Radius 19
A ≈ 4536.46 .....ans
I’m so bad at math Can someone help
Answer:
B and C
Step-by-step explanation:
It fits the inequality
Step-by-step explanation:
step 1. no one is categorically bad at math; they just haven't practiced.
step 2. this reads: x is less than 30 and x is greater than 15.
step 3. x cannot be 15 but can be 22 and 29.
Two glasses of milk and three snack bars have a total of 72 carbs. and 4 glasses of milk and 2 snack bars have a total of 88 carbs. Determine how many carbs are one glass of mild and one snack bar.
Answer:
one glass of milk = 15 carbs
one bar = 14 carbs
Step-by-step explanation:
let 'm' = one glass of milk
let 'b' = one snack bar
system of equations:
2m + 3b = 72
4m + 2b = 88
I used the elimination method and multiplied the 1st equation by -2
-4m - 6b = -144
+ 4m + 2b = 88
-4b = -56
b = 14
now solve for 'm'
2m + 3(14) = 72
2m + 42 = 72
2m = 30
m = 15
What are the zeros of F(x)=(x-2)(x+7)
Answer:
Zero's are X = 2 and X = -7
Step-by-step explanation:
you would set the factorized parts equal to zero, as in x - 2 = 0 and x + 7 = 0, then solve for x, and whatever you get is where y will be zero
Answer:
zeros: x = 2 and x = -7
Step-by-step explanation:
use zero product property - set the polynomial equal to 0
(x-2)(x+7) = 0
then set each factor separately to 0:
x - 2 = 0 x + 7 = 0
solve for x by adding 2 to both sides in the equation on the right, and subtracting 7 from both sides in the equation on the left
x = 2 x = 7
Jenna has a rectangular pig pen that measures 8m wide by 10m long. She wants to increase the area to 168 m^2 by increasing the length and width by the same amount. What would you enter into desmos to represent the equation?
A) x^2 + 18x – 88
B) x^2 + 10x + 80
C) (8x)(10x)-168
D) None of the above
Answer:
The answer is A
Step-by-step explanation:
I just took the test and it was the answer!
The equation for the increase in length and width of the rectangular pig pen is x² + 18x - 88 = 0.
The correct option is (A).
What is Surface Area?The area is the area occupied by a two-dimensional flat surface. It has a square unit of measurement.
As per the given data:
The dimensions for the pig pen Jenna has is given.
The area of the pig pen is to be increased to 168 m² by increasing the length and width by the same amount.
Length of the rectangular pig pen = 10 m
Width of the rectangular pig pen = 8 m
Now, let's say that the length and width of the pig pen is increased by x m.
length = 10 + x
width = 8 + x
The expression for the area of the pig pen will be:
Area = length × width
168 = [10 + x][8 + x]
168 = 80 + 10x + 8x + x²
x² + 18x - 88 = 0
The equation for the increase in length and width of the rectangular pig pen is x² + 18x - 88 = 0.
Hence, The equation for the increase in length and width of the rectangular pig pen is x² + 18x - 88 = 0.
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To reason about the value of x in 1/4(12x - 8) =10, Joy and Paulo each rewrite the equation. Joy rewrites the equation as 3x - 2 = 10. Paulo rewrites the equation as
12x - 8 = 40. What are their strategies? Explain your reasoning.
Answer:
For Joy:
Strategy: Multiply through by 4
For Paulo:
Strategy: Evaluate the bracket
Explanation:
Given
[tex]\frac{1}{4}(12x - 8)=10[/tex]
Required:
Determine the strategies
For Joy:
Strategy: Multiply through by 4
[tex]4 * \frac{1}{4}(12x - 8)=10 * 4[/tex]
[tex]12x - 8 = 40[/tex]
Done
For Paulo:
Strategy: Evaluate the bracket
[tex]\frac{1}{4}*12x - \frac{1}{4}*8=10[/tex]
[tex]3x - 2 = 10[/tex]
Done
Shivani has two pieces of wire, one 48 feet long and the other 21 feet long. If she wants to cut them up to produce many pieces of wire that are all of the same length, with no wire left over, what is the greatest length, in feet, that she can make them?
Answer:
3 feet
Step-by-step explanation:
48 = 2⁴×3
21 = 3×7
Greatest common factor of 48 and 21 is 3.
Each piece will be 3 feet long.
Sam has a bag
full of 25 marbles
that contain 9 red,
7 blue, 5 green, and
the rest are purple.
What is the probability
that a randomly selected
marble will be purple?
Answer:
4/25
Step-by-step explanation:
25 - 9 - 7 - 5 = 4
There are 4 purple marbles.
Out of the 25 marbles, 4 are purple so the probability of getting a purple is 4/25
Which points are separated by a distance of 5 units? O A. (1,3) (6,3) ☆ O B. (3,5) (1,5) O C. (5,1) (1,1) O D. (2,3) (3,3)
Answer:
A
Step-by-step explanation:
A. (1,3) and (6,3) have the same y-coordinate, so the distance between them is the difference of the x-coordinates.
distance = 6-1 = 5
:::::
B. (3,5) and (1,5). Again, the same y-coordinate. Distance = 3-1 = 2 ≠ 5
:::::
C. distance = 5-1 = 4 ≠ 5
:::::
D. distance = 3-2 = 1 ≠ 5
correct 96897 to the nearest thousand
Kenji feeds his cats a mixture of wet and dry food at every meal. He mixes 5 spoonfuls of dry food and 10 spoonfuls of wet food for Tiger, his adult cat. He mixes a smaller meal with 3 spoonfuls of dry food and 5 spoonfuls of wet food for his kitten, Smokey. Do the two meals have the same ratio of dry food to wet food?
Yes or No
You can make 8 pints of purple paint by mixing 6 parts of blue paint to 2 parts of red paint. The employees in the paint department of a home improvement store use this table to determine the amounts of blue and red paint needed to create this color for their customers.
How much red paint is needed to create 40 pints of purple paint for their customers?
Answer & Step-by-step explanation:
Since we use 5 parts blue and 3 parts red, the total sections is 8.
28/8 = 3.5
We want to find the red which is 3 parts.
3.5 * 3 = 10.5.
Your answer should be 10.5 pints of red.
Hope this helps!
Six copies of the sum of nine fifths and three
Answer: What is the complete question? Can you comment it?
Step-by-step explanation: I can’t help unless I know what the full question is. Sorry.