How many cups of chocolate would Linda need for 2 cups of cream

How Many Cups Of Chocolate Would Linda Need For 2 Cups Of Cream

Answers

Answer 1
I don’t know how to solve this one but use Y and find the slope and get Y alone

Related Questions

The doll was considered a "feminine" toy. Do these data provide convincing evidence that the mean percentage of the time spent playing with the doll is greater for female monkeys than for male monkeys?

Answers

Answer:

yes it does because men comes before women

A shoe repairman is working with his assistant, who takes 1.5 times as long to repair a pair of shoes.
Together they can fix 10 pairs of shoes in six hours. How long does it take the repairman to fix one pair
of shoes by himself?

Answers

Answer:

1/2 or 0.5 hours

Step-by-step explanation:

r = time for repairman to fix one pair of shoes.

a = time for assistant to fix one pair of shoes.

a = r×1.5

x×r + y×a = 6

x = number of pairs of shoes repaired by repairman.

y = number of pairs of shoes repaired by assistant.

x+y = 10

y = 10-x

x = y×1.5 (based on the a/r ratio : as the assistant needs 1.5 times longer, the repairman will have repaired 1.5 times more pair of shoes in the same time)

y = 10 - y×1.5

y + y×1.5 = 10

2.5×y = 10

y = 4

=> x = 6

6×r + 4×r×1.5 = 6

6×r + 6×r = 6

12×r = 6

r = 6/12 = 1/2 or 0.5 hours

6th grade math help me pleaseeee

Answers

The correct answer is C. 78

Answer:

i think C because both of the percentages shown should get what the question is asking

Step-by-step explanation:

Complete the table fraction | decimal

Answers

Answer:

1/5=0.2

0.3=3/10

1/2=0.5

7/10=0.7

3/4=0.75

13. The function y=16 cos(x)+k has a minimum value of -4. What is its maximum value? Explain.

Answers

Answer:

It's maximum value is 28.

Step-by-step explanation:

Cosine function:

The cosine function has the following format:

[tex]f(x) = A\cos{x}[/tex]

The difference between the maximum and minimum point is 2A.

y=16 cos(x)+k

A = 16, so 2A = 32.

Minimum value of -4. What is its maximum value?

[tex]M - (-4) = 32[/tex]

[tex]M + 4 = 32[/tex]

[tex]M = 32 - 4 = 28[/tex]

It's maximum value is 28.

A rectangle has a perimeter of 54 cm. It has a length of 15 cm. What is its area? *

Answers

the area is 180 cm. to find the perimeter you would do 15+15+14+14 to get 54 cm. So for area you do (l×w) which is 15×14=180.

Please help I’ll give brainliest

Answers

Answer:

Option A

Step-by-step explanation:

Please Mark me brainliest

Which function is graphed below?

Answers

Answer:

[tex]g(x)=\sqrt{x+2}[/tex]

Step-by-step explanation:

Parent function of the given graph is,

f(x) = [tex]\sqrt{x}[/tex]

If the parent function is shifted 2 units to he left the new function or image function will be,

g(x) = [tex]\sqrt{x+2}[/tex]

Therefore, graph will represent the graph of the function g(x) = [tex]\sqrt{x+2}[/tex].  

The expression \sqrt[3]{3}\cdot \sqrt[5]{3^6}
3

3


5

3
6


is equivalent to

Answers

3/6 because I got it right on the quiz and it was easy txt me if you need help

By simplifying the given expression, the expression [tex]\sqrt[3]{3}[/tex] * [tex]\sqrt[5]{3^6}[/tex] is equivalent to [tex]3^(23/15).[/tex]

How to find equivalent value

To simplify the given expression,  combine the two radicals using the property of exponentiation.

First, simplify the expression inside the second radical:

√[5]{[tex]3^6[/tex]}

Since the index is 5,  rewrite the expression as:

[tex](3^6)^(1/5)[/tex]

Using the property of exponentiation, multiply the exponents:

[tex]3^(6/5)[/tex]

Now combine this result with the first radical:

[tex]3\sqrt3 * 3^(6/5)[/tex]

Since ∛3 can be written as [tex]3^(1/3)[/tex],  rewrite the expression as:

[tex]3^(1/3) * 3^(6/5)[/tex]

To multiply two numbers with the same base, add the exponents:

[tex]3^(1/3 + 6/5)[/tex]

To simplify further, we need a common denominator for the fractions:

[tex]3^(5/15 + 18/15)[/tex]

Combining the fractions:

[tex]3^(23/15)[/tex]

Therefore, the given expression is equivalent to [tex]3^(23/15).[/tex]

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Nina and Jo both ran an 8 km race. Nina took 55 minutes to run the whole race. Jo started the race 3 minutes later than Nina but caught up when they had both travelled 6 km. If Nina and Jo both ran at constant speeds, what is Jo's speed to 2 dp?

Answers

Answer:

Step-by-step explanation:

First we figure out how fast Nina can run. If Nina can run 8 km in 55 minutes, then her rate is

[tex]\frac{8km}{55min}=.145\frac{km}{min}[/tex] and we can use that in a d = rt table:

                 d        =        r        *        t

Nina                            .145

Jo

Now we can fill in the distance which is 6 for both, since that is the distance where they met:

                d        =        r       *        t

Nina         6        =     .145

Jo             6        =

Now we go to the info given about the time. If Jo started the race 3 minutes after Nina, that means that Nina is running 3 minutes longer than Jo. Filling in the time info:

                d        =        r        *        t

Nina          6       =       .145    *      t + 3

Jo              6       =         r       *         t

As you can see, right now we have 2 unknowns in Jo's row. But we don't have to! We will go to Nina's row where the only unknown is time and solve for t. If d = rt, then

6 = .145(t + 3) and

6 = .145t + .435 and

5.55 = .145t so

t = 38.379 minutes. This means that Jo was running 38.379 minutes when she caught up to Nina (it took Nina 3 minutes longer than that to go 6 km since she was already running for 3 minutes when Jo started the race). If Jo's time is 38.379, we can use that in her row for t and solve for r. If d = rt, then

6 = r(38.379) and

r = .16 km/min

Let's check it without the rounding (rounding takes away from the accuracy). If 6 = .145(t + 3) and Nina's rate not rounded is .145454545 and t = 38.37931034, then, rewriting without rounding:

6 should equal .145454545( 38.37931034 + 3)

6 ?=? .145454545(41.37931034)

6 ?=? 6.0 so

Jo's rate is .16 km/min rounded

5. In the triangle ABC, M is the midpoint of [AB] and N is the midpoint of [CM].
Find the coordinates of N. Given that A(-1,3), B(7.-3) and C(1,6).

Answers

Answer:

The coordinates of the point N is (2,3)

Step-by-step explanation:

For us to find the midpoint between two points

We use the midpoint formula which is;

(x,y) = (x1 + x2)/2, (y1 + y2)/2

We start by finding the midpoint of AB to get the coordinates of the point M

A(-1,3) and B(7,-3)

(x,y) = (-1 + 7)/2, (3-3)/2 = (6/2,0/2) = (3,0)

Now that we have the coordinate of M, we can find the midpoint of CM to get the coordinates of N

C(1,6) and M (3,0)

(x,y) = (1 + 3)/2, (6+0)/2 = (4/2, 6/2) = (2,3)

Question 7 of 10
Classify the following triangle. Check all that apply.
109
15
14
D A. Right
B. Equilateral
O C. Acute
D D. Scalene
O E. Isosceles
M F Obtuse

Answers

Answer:

A & D

Step-by-step explanation:

A. acute because all angles are less than 90 degrees

D. scale because all sides have different

if you look up the definition of the properties you will see they don't apply

Answer:

F.Obtuse angle

because the angles are between 90-180

Figure B is a scaled copy of Figure A.
Figure A
14
Figure B
56
16
7
64
28
What is the scale factor from Figure A to Figure B?

Answers

Answer:

4

Step-by-step explanation:

Notice each side was increased by 4 times

You can set up a ratio of

[tex]\frac{new}{old}[/tex]

then reduce or divide


Find the volume of a right circular cone that has a height of 18.8 m and a base with a
radius of 19.3 m. Round your answer to the nearest tenth of a cubic meter.

Answers

Step-by-step explanation:

Height of the right circular cone = 18.8 metres

And base is 19.3 metres

Volume of the right circular cylinder is given by,

= πr²h

= 3.14 × (19.3)² × 18.8

= 21999.98(approx.) cubic metre

Rounding off nearest tenth

= 21999 cubic metres

The volume of the right circular cone is 280,199.5 m³

What is a right circular cone?

'A right circular cone is a cone where the axis of the cone is the line meeting the vertex to the midpoint of the circular base.'

According to the given problem,

Height = 18.8 m

Radius = 19.3 m

Volume of right circular cone = [tex]\frac{\pi r^{2}h }{3}[/tex]

                                                 = [tex]\frac{\pi * 19.3^{2} * 18.8}{3}[/tex]

                                                 = 280199.499 m³

                                                 = 280199.5 m³

Hence, we can conclude that the volume of the right circular cone is 280199.5 m³.

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SAT A bag contains 3 red marbles, 2 green
marbles, and 4 blue marbles. One marble is
randomly drawn and replaced. Then a second marble
is drawn. Find the probability of drawing three blue
marbles.

Answers

Answer:

[tex] \frac{1}{21} [/tex]

Step-by-step explanation:

refer to solution in picture

What is the slope of the line? y+5=2(x+1)

Answers

Answer:

2

Step-by-step explanation:

Convert the equation to slope-intercept form:

[tex]y+5=2(x+1)\\y+5=2x+2\\y=2x-3[/tex]

Therefore, the slope of the line is 2.

Answer:

2

Step-by-step explanation:

y+5=2(x+1) will turn into y=2x-3. Then you can see that the slope is 2 because 2x is = mx and m is slope.

Find the area of this triangle in square centimeters .

Answers

Step-by-step explanation:

The answer is 24 I think.

using the formula for finding the area of a triangle, which is....

Area= b times height divided by 1/2 or 2

First step is to multiply 6 which is the base by the height 8 to get 48. Then 48 divided by 2 is 24.

Step-by-step explanation:

the area of the triangle can be find by using the heron's formula...

that is:

√s-a×s-b×s-c

So,

a=8cm,b=6cm,c=10cm

Semi perimeter= 8+6+10/2=24/2=12

√12(12-8)(12-6)(12-10)

=√12×4×6×2

=√ 2×2×3×2×2×2×3×2

= √2×2×2×3

= 12 cm...

Lucas suele gastar $150 en gaseosas al mes, pero, para cuidar su salud decidió dejar de consumir gaseosas ¿cuánto dinero a dejado de gastar en cinco meses?

Answers

Answer:

$750

Step-by-step explanation:

Primero, Lucas gastaba $150 cada mes en gaseosas.

Al decidir cuidar su salud, deja de comprar gaseosas, entonces ya no gasta esos $150 al mes.

Es decir, a dejado de gastar $150 al mes.

Nosotros queremos saber:

¿cuánto dinero a dejado de gastar en cinco meses?

Bueno, si en un solo mes a dejado de gastar $150

En 5 meses a dejado de gastar 5 veces esa cantidad, que es:

5*$150 = $750

A car travels 22 miles for every gallon of gasoline used. The table below represents this relationship

Answers

Answer:

the answer would be 1/22 = x/3

Step-by-step explanation:

because 1 gallon of gasoline got him to travel 22 miles so your trying to solve for x for 3 gallons

Let $z$ and $w$ be complex numbers satisfying $|z| = 5, |w| = 2,$ and $z\overline{w} = 6+8i.$ Then enter in the numbers \[|z+w|^2, |zw|^2, |z-w|^2, \left| \dfrac{z}{w} \right|^2 \]below, in the order listed above. If any of these cannot be uniquely determined from the information given, enter in a question mark. Don't even know where to start.

I got 49 for the first one, 100 for the second one, 9 for the 3rd one, and 6.25 for the 4th one. But it was wrong, so I don't know how to do this question.

Answers

Answer:

1st entry: 41

3rd entry: 17

Step-by-step explanation:

The 1st and 3rd entry are incorrect.

We will use the following for the 1st and 3rd:

[tex]|z+w|=|z|^2+|w|^2+2R(z\overline{w})[/tex]

[tex]|z-w|=|z|^2+|w|^2-2R(z\overline{w})[/tex]

where [tex]R(z\overline{w})[/tex] means 'real part of [tex]z\overline{w}[/tex]'.

Let's do part 1 now)

25+4+2(6)

29+12

41

Let's do part 3 now)

25+4-2(6)

29-12

17

Please, can I get help?

Answers

Answer:

a- 14,11

b-13,63

Step-by-step explanation:

Joseph and Mark have $230. Joseph and Kevin have $130. Mark had 3 times as much money as Kelvin. How much money does Kelvin have?

Answers

Answer:

Step-by-step explanation:

Let's call Joseph "J", Mark "M", and Kevin "K" for ease. We need a system of equations to solve this, 3 equations for 3 unknowns. The first equation is

J + M = 230. The second equation is

J + K = 130. The third equation is

M = 3K. Sub that 3K into the first equation and get

J + 3K = 230. Now take th second equation and solve it for J:

J = 130 - K. Now sub 130 - K into the re-written first equation to get a whole new equation in terms of K only:

130 - K + 3K = 230 and

2K = 100 so

K = 50

Kevin has $50

Find x in circle O. Figure is not drawn to scale. HURRY PLEASE

Answers

Answer:

B. 23,5

Step-by-step explanation:

YALL REALLY NEED TO
HELP MEEEE
determine if the triangles are similar. Why are they similar or not similar ?
please show work

Answers

Answer:

Not similar

Step-by-step explanation:

In triangle MLN & WXY,

Right angles - > 1

There is nothing common in these 2 triangles other than (1)

Therefore,

Not similar

During a game of pool near hit a ball and it follow the path from B to C and then to de- the angles formed by the path of congruent to the nearest 10th of an inch which of the following represents the total distance the ball travels before it stopped at point D

Answers

Answer:

please mark me as brainleast

Answer for this question is 45 inch

Amanda works as a hostess at Red Robin on weekday nights and at the Pix movie theatre on the weekends. Amanda’s pay at Red Robin is 11.50ℎ+0.25+10and her pay at the Pix is 10.50ℎ+0.5−20. Find the polynomial that would represent Amanda’s total earnings from her two jobs.

Answers

Answer:

22h−9.25

Step-by-step explanation:

Hihi , please help if able.

Answers

Answer:

Option c

Step-by-step explanation:

multiply the expression in the parentheses by 4 and you get 12x+16

a doesn't fit, x³ is x*x*x, not plus

b 14x-2x is 12x, not 16x

d got a 5x expression with no correspondence on the other side and 12x² isn't 17x²

You use the Internet to purchase 9 tickets for a concert The tickets are $22 each you have to play a handling fee of $3 per ticket and a shipping fee of $5 for the entire order. Use a problem solving plan to find your total cost.

Answers

Answer: $206

Step-by-step explanation: 9(22)+8. 9 is the 9 tickets 22 is the cost of each ticket so they multiply to find the total cost of all tickets. and 8 from shipping and handling.

The equation C = 20n + 35 represents the relationship between the cost of school volleyball uniforms,
C, in dollars, and the number of uniforms ordered, n.
The uniform company requires that the school order a minimum of 15 uniforms.
The school has a maximum of $600 to spend on the uniforms.
Determine the possible values for n and C in this situation
.

Answers

Answer:

Given the equation

C = 20n + 35

We need:

n ≥ 15 and C ≤ 600

following

20n + 35 ≤ 60020n ≤ 565n ≤ 565/20n ≤ 28 (rounded to the whole number)

Considering that n ≥ 15, we have:

15 ≤ n ≤ 28

And the cost is going to be:

20*15 + 35 ≤ C ≤ 20*28 + 35335 ≤ C ≤ 595

1-x/11 [tex]1-x/11 =6\\[/tex]=6

Answers

Given:

Consider the equation is:

[tex]\dfrac{1-x}{11}=6[/tex]

To find:

The value of x.

Solution:

We have,

[tex]\dfrac{1-x}{11}=6[/tex]

After multiplying both sides by 11, we get

[tex]1-x=66[/tex]

[tex]-x=66-1[/tex]

[tex]-x=65[/tex]

Multiply both sides by -1.

[tex]x=-65[/tex]

Therefore, the value of x is -65.

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