Answer:
is there an image where i can see?
Step-by-step explanation:
A car is traveling at a steady speed. It travels 1 3/4 miles in 2 1/3 minutes. How far will it travel in 39 minutes ? In 1 hour ?
Step-by-step explanation:
1 and 3/4 miles ???? miles
-------------------- = ---------------------
2 and 1/3 minutes 39 minutes
Cross multiplies:
(1 and 3/4) x 39 = (2 and 1/3) x ?
7/4 x 39/1 = 7/3 x ?
273/4 = 7/3 x ?
? = 273/4 * 3/7 = 39*3/4 <---- 7 x 39 = 273
= 117/4
= 29 and 1/4
---------------------------------------------------------------
1 and 3/4 miles ?
------------------ = ------------------
2 and 1/3 min 60 min
(1 and 3/4) * 60 = (2 and 1/3) * ?
7/4*60/1 = 7/3 * ?
105 = 7/3 * ?
? = 105*3/7
= 315/7
= 45
The length of Andy's bed is 123 what is the length in feet
Answer:
4.068 feet
Step-by-step explanation:
Solve 7(x+1) + 2(3x-1) = 15
Answer:
what is x worth?
Step-by-step explanation:
The answer is 10/13
You can see the step by step explaination in the image
P is a rectangle with length 40 cm and width x cm.
Q is a rectangle with width y cm.
Р
The length of Q is 25% more than the length of P.
The area of Q is 10% less than the area of P.
Work out the ratio xiy
Give your answer in its simplest form.
x cm
40 cm
Q
y cm
Answer:
we know that
the length of Q is 25% more than the length of p
so
length Q=1.25*40--------> 50 cm
the area of Q is 10% less than the area of p
Area Q=50*y
Area P=40*x
so
50*y=0.90*[40*x]---------> 50*y=36*x-------> x/y=50/36---> 25/18
the answer
the ratio x:y is 25:18
Can i have brainliest? please?
- Calculate the median and range
of the data in the dot plot. Then
compare the results to the dot
plot for Exercise in Example 2.
A triangle has an area of 41.5 square centimeters and a base of 8.3 centimeters. What is the height?
Answer:
10 cm
Step-by-step explanation:
[tex]\boxed{area \: of \: traingle = \frac{1}{2} \times base \times height}[/tex]
Substitute known values into the formula:
41.5= ½ ×8.3 ×height
41.5= 4.15 ×height
height
= 41.5 ÷4.15 (÷4.15 on both sides)
= 10cm
Answer:
10 cm.
Step-by-step explanation:
You will first need the formula for finding the Area of a Triangle:
Area = 1/2(Base x Height)
Next, we need our known measurements to plug into the Equation:
41.5 Sq Cm = 1/2(8.3cm x Height)
After that, multiply the equation by 2
2 x 41.5 = (2 x 1/2) x (8.3cm x Height)
∨
83 sq cm = 8.3 cm x Height
Finally, divide your area by 8.3 cm:
83 / 8.3 = 10cm = Height
So, the answer is Height = 10 cm.
Good Luck!Who knows this answer
solve each equation.
Answer:
1. D. 7, -13
2. A. no solution
3. C. 5, -9
Step-by-step explanation:
Brainliest stars
21)
In which container is the probability of randomly selecting a red ball on one draw 3/7?
Answer: Your answer is going to be C)
Here is my explanation, very simple! So if you count all the balls together in answer's A) B) and D) there aren't 3 balls in each, so for example answer A) has 4 red ball's. B) only has 1 red ball, D) also has 1 ball, so C) is your only reasonable answer because although all the containers have a total of 7 ball's there is not enough for your probability. being said your container/answer is C!
Answer: c
Step-by-step explanation: the girl up there said it
What equation can be written for 29 is 6 more then k? what is K?
Answer:
k = 23
Step-by-step explanation:
which diagram shows 1 and 2 as vertical angles
working conditions in the United States in the early 1900's can best be described as?
a. beneficial
b.atroious
c. rewarding
d. simple
triangle CAT is translated using the rule (x,y) (x-3, y+4) to create triangle C’A’T’. if a line segment is drawn from point c to point C’ and from point A to point A’. which statement would best describe the line segments drawn
Answer:
They are parallel and congruent
Step-by-step explanation:
Melany takes her little sister to the zoo. They go see their favorite animal, the giraffe. At the gift shop, Melany buys a stuffed giraffe for her little sister that has a scale on 4 in : 3 ft. If the real giraffe is 18 feet tall, how tall is the stuffed giraffe, in inches?
Let us set up a proportion.
4/3 = 18/t
Let t = height of giraffe (in inches)
We also have to change units to make our math work easier.
There are 12 inches in one foot.
So, 3 feet = 36 inches and 18 feet = 216 inches.
Our new proportion set up is:
4/t = 36/216
36t = 4(216)
36t = 864
t = 864/36
t = 24
The toy giraffe is 24 inches tall.
What is the answer to114 times 12
A n s w e r :
1368.00
Help on this question pleaseeeeeeee
Step-by-step explanation:
F-27=19
F= 19+27
F=46
I hope it is helpful have a nice day
Answer:
answer is 46
Step-by-step explanation:
Solution for f-27=19 equation:
Simplifying
f + -27 = 19
Reorder the terms:
-27 + f = 19
Solving
-27 + f = 19
Solving for variable 'f'.
Move all terms containing f to the left, all other terms to the right.
Add '27' to each side of the equation.
-27 + 27 + f = 19 + 27
Combine like terms: -27 + 27 = 0
0 + f = 19 + 27
f = 19 + 27
Combine like terms: 19 + 27 = 46
f = 46
Simplifying
f = 46
There are currently 12 frogs in a large) pond. The frog population grows exponentially, tripling every 8 days.
How long will it take in days) for there to be 240 frogs in the pond?
Time to 240 frogs?
The pond's ecosystem can support 1800 frogs. How long until the situation becomes critical?
Time to 1800 frogs?
Answer:
24 days till 240 frogs in the pond
40 days till 1800
Step-by-step explanation:
8 1/16-5 1/2 I need help with this.pls
Step-by-step explanation:
I hope this helps. Ans:41/16 alternate form: 2 9/16, 2.5625
Which methods can be used to run a query? Check all that apply.
On the Create tab, in the Queries group, click Run.
In query Design view, on the Design tab, click Run.
Switch to Datasheet view before any other commands.
Close the Show Table dialog box in the Datasheet view.
On the Create tab, in the Queries group, click Create Query.
Answer: B & C
Edg2021
A share of ABC stock was worth $60 in 2000 and worth $1920 in 2005.
Write an exponential function that models the value of the stock starting
from 2005.
Answer:
A share of ABC stock was worth $60 in 2005 and only worth $45 in 2010. ... diftolence b. Write an exponential function that ...
Need Help ASAP WILL MARK YOU BRAINLYEST
he divided by 2 instead of taking the square root so the actual answer should be 26 and for the second the 20 is across from the 90 so its suppose to be c
the answer should be 16
potatoes cost $0.85 per pound. Luke bought 2.75 pounds of potatoes. How much did he pay for the potatoes? Round to the nearest cent.
I know the answer is 2.34 (approximately) but please explain how you get from 2.3375 to 2.34
Answer:
you round the .0075 up, getting 2.34
Step-by-step explanation:
Not sure how to find angle C
Answer:
Need picture please
Step-by-step explanation:
Help me please help help help
Answer:
Step-by-step explanation:
at least.
My cake recipe calls for 2/3 cup of chocolate chips. I want my cake to be three
times more chocolatey than that. How many cups of chocolate chips should I
use? *
Someone help please
Answer:
x = 30
Step-by-step explanation:
PLEASE HELP‼️
A
B
C
D
Answer:
D
Step-by-step explanation:
hope this helps >.<
how do you find the area of a rectangle that has a width of 20,length of 25,
Answer:
20 times 25 which is 500.
Step-by-step explanation:
To get the area of a rectangle do length times width, just like a square!
Can someone tell me how to do this task please?
Considering only the values of [tex]\beta[/tex] for which [tex]\sin \beta \tan \beta \sec \beta \cot \beta[/tex] is defined, which of the following expressions is equivalent to [tex]\sin \beta \tan \beta \sec \beta \cot \beta[/tex]?
a. [tex]\sec \beta \cot \beta[/tex]
b. [tex]\tan \beta[/tex]
c. [tex]\cot \beta \tan \beta[/tex]
d. [tex]\tan \beta \csc \beta \sec \beta[/tex]
[tex]\large\boxed{Answer:}[/tex]
We will use trigonometric identities to solve this. I will use θ (theta) for the angle.
First of all, we know that cotθ = 1/tanθ. This is a trigonometric identity.
We can replace cotθ in the expression with 1/tanθ.
[tex]sin\theta tan\theta sec\theta \frac{1}{tan\theta}[/tex]
Simplify: 1/tanθ * tanθ = tanθ/tanθ = 1
So now, we have:
[tex]sin\theta sec\theta[/tex]
Next, we also know that secθ = 1/cosθ. This is another trigonometric identity.
We can replace secθ with 1/cosθ in our expression.
[tex]sin\theta \frac{1}{cos\theta}[/tex]
Simplify:
[tex]\frac{sin\theta}{cos\theta}[/tex]
Our third trigonometric identity that we will use is tanθ = sinθ/cosθ.
We can replace sinθ/cosθ with tanθ.
Now we have as our final answer:
[tex]\large\boxed{b.\ tan\theta}[/tex]
Hope this helps!
Answer:
[tex] \huge \boxed{ \boxed{ \red{b) \tan( \beta ) }}}[/tex]
Step-by-step explanation:
to understand thisyou need to know about:trigonometryPEMDASgiven:[tex]\sin \beta \tan \beta \sec \beta \cot \beta[/tex]tips and formulas:[tex] \tan( \theta) = \dfrac{ \sin( \theta) }{ \cos( \theta) } [/tex][tex] \cot( \theta) = \dfrac{ \cos( \theta) }{ \sin( \theta) } [/tex][tex] \sec( \theta) = \dfrac{1}{ \cos( \theta) } [/tex]let's solve:[tex] \sf rewrite \: \tan( \beta ) \: as \: \dfrac{ \sin( \beta ) }{ \cos( \beta ) } : \\\sin (\beta ) \cdot\frac{ \sin( \beta ) }{ \cos( \beta ) } \cdot \sec (\beta ) \cdot\cot (\beta)[/tex][tex] \sf rewrite \: \sec( \beta ) \: as \: \dfrac{1 }{ \cos( \beta ) } : \\\sin (\beta) \cdot\frac{ \sin( \beta ) }{ \cos( \beta ) } \cdot \frac{1}{ \cos( \beta ) } \cdot\cot (\beta)[/tex][tex] \sf rewrite \: \cot( \beta ) \: as \: \dfrac{ \cos( \beta ) }{ \sin( \beta ) } : \\\sin (\beta) \cdot\frac{ \sin( \beta ) }{ \cos( \beta ) } \cdot \frac{1}{ \cos( \beta ) } \cdot \: \dfrac{ \cos( \beta ) }{ \sin( \beta ) }[/tex][tex] \sf \: cancel \: sin : \\\sin (\beta) \cdot\frac{ \cancel{\sin( \beta ) }}{ \cos( \beta ) } \cdot \frac{1}{ \cos( \beta ) } \cdot \: \dfrac{ \cos( \beta ) }{ \cancel{\sin( \beta ) }} \\ \sin (\beta) \cdot\frac{ 1 }{ \cos( \beta ) } \cdot \frac{1}{ \cos( \beta ) } \cdot \: \cos( \beta ) \\ [/tex][tex] \sf cancel \: cos : \\ \sin (\beta) \cdot\frac{ 1}{ \cos( \beta ) } \cdot \frac{1}{ \cancel{ \cos( \beta )} } \cdot \: \cancel{ \cos( \beta ) } \\ \\ \sin( \beta ) \: \cdot \: \dfrac{ 1 }{ \cos( \beta ) } [/tex][tex] \sf \: simplify \: multipication : \\ \dfrac{ \sin( \beta ) }{ \cos( \beta ) } [/tex][tex] \sf use \: \frac{ \sin( \beta ) }{ \cos( \beta ) } = \tan( \beta ) \: identity : \\ \therefore \: \tan( \beta ) [/tex]