heat transferred per mole of NH3(g) formed in the reaction shown below N2(g) + 3 H2(g) ? 2 NH3(g) ?H = – 92.2 kJ is -46.1 kJ/mole.
The heat transferred per mole of NH3(g) formed in the reaction can be calculated using the enthalpy change (ΔH) of the reaction, which is given as -92.2 kJ. The reaction is:
N2(g) + 3 H2(g) → 2 NH3(g). The coefficient of NH3(g) in the balanced equation is 2. Therefore, 2 moles of NH3(g) are formed for every mole of N2(g) and 3 moles of H2(g) that react. So, the heat transferred per mole of NH3(g) formed is -92.2 kJ/2 moles = -46.1 kJ/mole.
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How many moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas?
Taking into account the reaction stoichiometry, 340.0 moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas
Reaction stoichiometryIn first place, the balanced reaction is:
CO₂ + 4 H₄ → CH₄ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
CO₂: 1 moleH₄: 4 moles CH₄: 1 moleH₂O: 2 molesMoles of CH₄ formedThe following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?
[tex]moles of CH_{4} =\frac{85.1 moles of CO_{2}x4 moles of CH_{4} }{1 moles of CO_{2}}[/tex]
moles of CH₄= 340.4 moles
Then, 340.0 moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas
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A 36.65g sample of solid is placed in a flask. Toluene in which the solid is insoluble ,is added to the flask so that the volume of solid and liquid together is 50.00mL.The solid and toluene together weigh 58.58 g .The density of toluene at temperature of the experiment is 0.864g/ml .what is the density of the solid?
The density of the solid is =0.3076g/ml
Calculation of the density of solidThe mass of solid in flask = 36.65g
The volume of both solid and Toluene = 50ml
The mass of both solid and Toluene = 58.58g
The density of toluene = 0.864g/ml
The density of the solid = X
Note: The density of the solid is calculated from the density of both the solid and toluene.
But the density of solid+ toluene;
=mass/volume
= 58.58g/50ml
= 1.1716g/ml
Therefore the density of solid alone = density of both solid +toluene - density of toluene.
= 1.1716g/ml - 0.864g/ml
= 0.3076g/ml
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How do you separate Sand Potassium Nitrate and Champhor
In this activity, you are tasked with designing an airbag for a company that creates airbags for automobiles. You must design the driver’s front airbag for a specific car model so it will protect the driver as effectively as possible. For this car, the airbag must have a volume of 58 liters when fully inflated. To provide an adequate cushion for the driver’s head, the air pressure inside the airbag should be 4.4 psi. This pressure value is in addition to the normal atmospheric pressure of 14.7 psi, giving a total absolute pressure of 19.1 psi, which equals 1.30 atmospheres.
The airbag is designed to produce the volume of nitrogen gas required to fill up the airbag.
What is the function of an airbag?An airbag is a bag which is designed to self-inflate and serve as a cushion for the head and neck of a driver to prevent injuries when an impact occurs head-on on the car.
The gas that inflates the airbag is nitrogen which is produced from sodium azide according to equation below:
2NaN₃ → 2Na + 3N₂In conclusion, the design of the airbag is such that the correct amount of sodium azide is present to produce the volume of nitrogen required to fill up the airbag.
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help me out with this question
The concentration will be 12 M. The first option is the correct one.
ConcentrationIt is calculated by dividing the number of moles of solute present in a solution by the volume of the solution.
In this case, the number of moles of solute = 1.2 mols
volume of solvent = 100 mL or 0.1 L
Concentration of the solution = 1.2/0.1 = 12 mol/L or 12 M
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Allowing water to cascade or bubble in a fountain during the purification process is an example of
a chemical reaction
O a solid dissolving in a liquid
O only a and b
O ion exchange
O a gas dissolving in a liquid
Answer:
ion exchange
Explanation:
because in the time period of chemical reactions it product ion
what are the factors affecting qualitative analysis in chemistry
Answer:
Techniques and Tests
Qualitative analysis typically measures changes in color, melting point, odor, reactivity, radioactivity, boiling point, bubble production, and precipitation.
Minute maid states that a bottle of juice contains 473 ml. Consumer groups are interested in determining if the bottles contain less than the amount stated on the label. To test their claim, they sample 30 bottles. The sample mean was 472ml and the standard deviation is 0. 2. What does mu represent here?.
The term mu here represents the average contents of all bottles of juice in the population, which is unknown. Option B
What is the standard deviation?The term standard deviation has to do with the extent that values are scattered around the mean. Now we know that the mean is the average of the distribution.
The standard deviation shows the extent to which the values differ from the mean value of the distribution. It is a measure of dispersion.
Thus, the term mu here represents the average contents of all bottles of juice in the population, which is unknown. Option B
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Missing parts;
Minute Maid states that a bottle of juice contains 473 mL. Consumer groups are interested in determining if the bottles contain less than the amount stated on the label. To test their claim, they sample 30 bottles. The sample mean was 472mL and the standard deviation is 0.2.
What does mu represent here?
A. The average contents of all bottles of juice in the sample, which is unknown.
B. The average contents of all bottles of juice in the population, which is unknown.
C. The average contents of all bottles of juice in the population, which is 472mL.
D. The average contents of all bottles of juice in the sample, which is 472mL.
How can mechanical waves help in the treatment of cancer?
Mechanical waves can help in the treatment of cancer due to heat generated by the high frequency waves.
What is mechanical wave?A mechanical wave is a wave that requires material medium for its propagation, example include;
water waves, sound waves, and seismic waves. Mechanical waves in treatment of cancersSound wave in example of mechanical wave because it requires material medium for its propagation.
High-frequency sound waves (HIFU) is used in the treatment of cancer because the strong beam generates heat which is directed to a specific part of a cancer.
The heat generated destroys the cancer cells.
Thus, mechanical waves can help in the treatment of cancer due to heat generated by the high frequency waves.
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A mixture contains NaHCO3
together with unreactive components. A 1.68 g sample of the mixture reacts with HA
to produce 0.561 g of CO2
.
The molar mass of NaHCO3
is 84.01 g/mol
and the molar mass of CO2
is 44.01 g/mol.
What is the percent by mass of NaHCO3
in the original mixture?
Answer: 63.75 %
Explanation:
The balanced chemical equation for this reaction is:
NaHCO3 + HA = NaA + H2O + CO2
According to the chemical equation, one mole of NaHCO3 will react with one mole of HA to form one mole of NaA, H2O and CO2. All the components are in same mole ratio of 1:1:1:1
So,
Moles of CO2 = weight/molar mass = 0.561/44 = 0.01275 moles
Moles of CO2 will be equal to moles of NaHCO3 = 0.01275 moles
Moles = weight/mass
Weight = moles × mass
So the weight of NaHCO3 = 0.01275 × 84.01 = 1.071 g
The percentage mass of NaHCO3 in the original mixture =(1.071/1.68)× 100% = 63.75 %
Therefore, the percent by mass of NaHCO3 in the original mixture was 63.75 %
How many atoms of oxygen are present in 7.51 grams of
glycine with formula C₂H5O2N?
1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.
How to calculate number of atoms?
The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.
However, the number of moles of oxygen in glycine can be calculated using the following expression:
Molar mass of C₂H5O2N = 75.07g/mol
Mass of oxygen in glycine = 32g/mol
Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine
Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles
Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms
Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.
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What is common to solving all mola mass problems?
All you need to do is to follow these 3 steps.
1. Estimate the number of each kind of atom present in the compound using the chemical formula in order to determine the molar mass of the molecule.
Divide each element's atomic weight (found in the periodic table) by the quantity of that element's atoms in the compound.Add up the total, then follow the number with the units of grams/mole.eg. Water
2 hydrogen atoms and 1 oxygen atom make up the chemical formula H20.H- 1's atomic weightO-16's atomic weightNumber of H atoms overall in formula 2Number of O atoms overall in formula 1The molar mass will thus be as follows: H 2 x 1= 2 O 1 x 16= 16 16+2= 18Water's molar mass is 18 g/mol as a result.Identify the Brønsted–Lowry acid and the Brønsted–Lowry
base on the left side of each of the following equations, and
also identify the conjugate acid and conjugate base of each
on the right side:
HCOOH(aq) + PO43-(aq) gives HCOO-(aq) + HPO42-(aq)
The following applies to the above equation:
Brønsted–Lowry acid - HCOOHBrønsted–Lowry base - PO43-Conjugate acid - HPO42-Conjugate base - HCOO-What is Bronsted-Lowry acid and base?Brønsted-Lowry acid is the any chemical species that acts as a donor of protons while Brønsted-Lowry base is any chemical species that acts as a proton acceptor.
In the following equation: HCOOH(aq) + PO43-(aq) = HCOO-(aq) + HPO42-(aq)
HCOOH is the proton (H+) donor, hence, is the Brønsted-Lowry acidPO43- is the donor acceptor, hence, is the Brønsted-Lowry baseHCOO- is the conjugate base that forms from the acidHPO42- is the conjugate acid that forms from the baseLearn more about Brønsted-Lowry acid and base at: https://brainly.com/question/15885173
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A gaseous compound containing hydrogen and carbon is decomposed and found to contain 90.00% carbon and 10.00% hydrogen by mass. The mass of 371 mL of the gas, measured at 415 mm Hg and 41°C, is found to be 0.315 g. What is the molecular formula of the compound?
The molecular formula of the compound is C₃H₄.
What is the molecular formula of the compound?The molecular formula of the compound is determined from the molecular mass of the compound.
The molecular mass of the compound is derived using the general gas equation as follows:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂/P₂T₁
Volume at STP, V₂ = (415 * 371 * 298(760 * 314)
V₂ = 192.26 mL = 0.192 L
Molar mass of gas = 22.4/0.192 * 0.315 = 36.75 g
Molecular formula is then determined from the mole ratio of the elements;
Carbon = 0.9 * 36.75/12 = 3
Hydrogen = 0.1 * 40/1 = 4
Thus, the molecular formula of the compound is C₃H₄.
In conclusion, the molecular formula of the gas is derived from the molecular mass.
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Select the correct structure that
corresponds to the name.
1,1,1-trifluoroethane
The correct chemical structure that corresponds to 1,1,1-trifluoroethane is (a).
What is 1,1,1-trifluoroethane?
A chemical structure is a spatial arrangement of atoms in a molecule. It determines the molecular geometry and when necessary the electronic chemistry as well .1,1,1-Trifluoroethane or simply known as trifluoroethane is Hydrofluorocarbon (HFC) compound that is colourless and highly inflammable gas with ether like odour. One method of preparation of 1,1,1-Trifluoroethane is by fluorination of 1-chloro-1,1-difluoroethane in the presence of hydrofluoric acid. The chemical formula for 1,1,1-Trifluoroethane is [tex]C__{2} } H_{3} F_{3}[/tex]. The high stability of it's chemical structure because of being heavier than air makes it a greenhouse gas with high infrared absorbent power. It can be used as a propellant or refrigerant and in cleaning of electrical equipments.
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1. given 5 mols of the compound below what is the mol ratio between the compound and O? Ca_4Si_2O_6(CO_3)(OH)_2
2. Given 2 mols of the compound in problem one what is the mol to mol ratio os Si?
3. Given 5 mols of the compound in problem one what is the mol to mol ratio between the compound and Ca?
4. Given 3.5 mols of the compound in problem one what is the mol to mol ratio between the compound and C?
5. in the reaction below give the mol to mol ratio between the underlined species
Pb(NO_3)_2(ap)+2KI(aq) -> PbI_2(s)+2KNO_3(aq)
underline underline
The mole ratio of the compound and its constituent elements are as follows:
The mole ratio between the compound and O is 5 : 22The mole ratio between the compound and Si is 2 : 4The mole ratio between the compound and Ca is 5 : 20The mole ratio between the compound and C is 1 : 1What is mole ratio?Mole ratio is the ratio of the moles of one or more elements or compounds to another.
The given compound is Ca₄Si₂O₆(CO₃)(OH)₂
Moles of oxygen present in 1 mole of compound = 11 moles
Moles of Si present in 1 mole of compound = 2 moles
Moles of Ca present in 1 mole of compound = 4 moles
Moles of C present in 1 mole of compound = 1 mole
Given 5 moles of the compound below, the mole ratio between the compound and O is 5 : 22Given 2 moles of the compound below, the mole ratio between the compound and Si is 2 : 4Given 5 moles of the compound below, the mole ratio between the compound and Ca is 5 : 20Given 3.5 moles of the compound below, the mole ratio between the compound and C is 1 : 1Given the equation of the reaction below;
Pb(NO₃)₂ (aq) + 2 KI (aq) --> PbI₂ (s) + 2 KNO₃ (aq)the mole ratio of the reactants and products are as follows:
Pb(NO₃)₂ : 2 KI (aq) = 1 : 2Pb(NO₃)₂ : PbI₂ (s0 = 1 : 1Pb(NO₃)₂ : 2 KNO₃ (aq) = 1 : 2In conclusion, the mole ratio of reaction is the ratio in which moles of the substances combine.
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What would the hydrogen ion concentration be if the pOH was 6?
Answer:
10-6mol/l
Explanation:
hope i helped
what is the solubility of KCI?
Answer:
Potassium chloride.
What would the hydrogen ion concentration be if the pOH was 6?
Taking into account the definition of pH and pOH, the hydrogen ion concentration will be 1×10⁻⁸ M.
Definition of pHpH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:
pH= - log [H⁺]= - log [H₃O⁺]
Definition of pOHSimilarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
Relationship between pH and pOHThe following relationship can be established between pH and pOH:
pOH + pH= 14
Hydroxide ion concentrationIn this case, you know that pOH= 6.
Replacing in the relationship established between pH and pOH, the pH can be calculated as:
pH + 6= 14
Solving:
pH= 14 - 6
pH= 8
Replacing in the definition of pH the concentration of H⁺ ions is obtained:
- log [H⁺]= 8
Solving:
[H⁺]= 10⁻⁸
[H⁺]= 1×10⁻⁸ M
In summary, the hydrogen ion concentration will be 1×10⁻⁸ M.
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what is the name of p214
diphosphorus tetraiodide is the name of the p2I4 compound.
What is the name of p2I4?The name of p2I4 is diphosphorus tetraiodide because there are two atoms with phosphorus and four atoms with iodine. We know that 'di' word is used for two while on the other hand, tetra word is used for four.
So we can conclude that diphosphorus tetraiodide is the name of the p2I4 compound.
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The question is in the photo
The concentration of LiOH in the reaction is 0.103 M
What is the concentration of lithium hydroxide?This is a neutralization reaction and the equation of the reaction is written as; H2SO4(aq) + 2LiOH(aq) ---->Li2SO4(aq) + H2O(l)
The average volume of acid used is obtained from;
8.54 + 8.51 + 8.68/ 3 = 8.58 mL
CA = 0.150 M
VA = 8.58 mL
CB = ?
VB= 25.0 mL
NA = 1
NB = 2
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CB = CAVANB/VBNA
CB = 0.150 * 8.58 * 2/25.0 * 1
CB = 0.103 M
The concentration of LiOH in the reaction is 0.103 M
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Analyze the following reaction and the given scenarios to discuss the relationship between volume and reaction rate. Determine which reaction will happen at a faster rate and explain why.
NH3(g) + 2O2(g) → HNO3(l) + H2O(l)
The first reaction is started in a gas chamber with a volume of 10 L. The second reaction is started in a gas chamber with a volume of 5 L.
The second reaction with the volume of 5L will occur faster as compared to the first reaction of volume 10L.
Volume is inversely proportional to the rate of reaction.
As volume increases rate of reaction decreases and as volume decreases rate of reaction increases.
Let's consider a reaction A → B.
r is rate of reaction and K is rate constant, A is the concentration of reaction.
r = k(A)
r is directly proportional to the A.
But the concentration of A is in Moles/liters (i.e. moles per unit volume)
r is inversely proportional to the volume of vessel or chamber.
Hence as volume increases rate of reaction decreases.
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A 0.266-g sample of NaC1 (molar mass = 58.44 g/mol) is dissolved in enough water to make 5.20 mL of
solution. Calculate the molarity of the resulting solution.
O 0.875 M
O 4.55 x 10-3 M
O 0.987 M
O 1.14 M
O 0.731 M
Balance the following reactions
a) Ca (s) + H₂O (1)→ Ca(OH)2 (aq) + H₂ (g)
b) Al2O3 (s) + C(s) + Cl₂ (g) → AICI3 (s) + CO (g)
c) FeCl3 (aq) + H₂S (g) → Fe2S3 (s) + HCI (aq)
d) CaCO3 (s) + HCI (aq) → Ca Cl₂ (aq) + CO2 (g) + H₂O (1)
Answer:
a) Ca (s) + 2 H₂O (l) ---> Ca(OH)₂ (aq) + H₂ (g)
b) Al₂O₃ (s) + 3 C (s) + 3 Cl₂ (g) ---> 2 AICI₃ (s) + 3 CO (g)
c) 2 FeCl₃ (aq) + 3 H₂S (g) ---> Fe₂S₃ (s) + 6 HCI (aq)
d) CaCO₃ (s) + 2 HCI (aq) ---> CaCl₂ (aq) + CO₂ (g) + H₂O (l)
Explanation:
For an equation to be balanced, there must be an equal amount of each type of atom on both sides of the reaction. The reactants are on the left side and the products are on the right side.
a) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
Ca (s) + H₂O (l) ---> Ca(OH)₂ (aq) + H₂ (g)
Reactants: 1 calcium, 2 hydrogen, 1 oxygen
Products: 1 calcium, 4 hydrogen, 2 oxygen
The balanced equation:
Ca (s) + 2 H₂O (l) ---> Ca(OH)₂ (aq) + H₂ (g)
Reactants: 1 calcium, 4 hydrogen, 2 oxygen
Products: 1 calcium, 4 hydrogen, 2 oxygen
b) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
Al₂O₃ (s) + C (s) + Cl₂ (g) ---> AICI₃ (s) + CO (g)
Reactants: 2 aluminum, 3 oxygen, 1 carbon, 2 chlorine
Products: 1 aluminum, 1 oxygen, 1 carbon, 3 chlorine
The balanced equation:
Al₂O₃ (s) + 3 C (s) + 3 Cl₂ (g) ---> 2 AICI₃ (s) + 3 CO (g)
Reactants: 2 aluminum, 3 oxygen, 3 carbon, 6 chlorine
Products: 2 aluminum, 3 oxygen, 3 carbon, 6 chlorine
c) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
FeCl₃ (aq) + H₂S (g) ---> Fe₂S₃ (s) + HCI (aq)
Reactants: 1 iron, 3 chlorine, 2 hydrogen, 1 sulfur
Products: 2 iron, 1 chlorine, 1 hydrogen, 3 sulfur
The balanced equation:
2 FeCl₃ (aq) + 3 H₂S (g) ---> Fe₂S₃ (s) + 6 HCI (aq)
Reactants: 2 iron, 6 chlorine, 6 hydrogen, 3 sulfur
Products: 2 iron, 6 chlorine, 6 chlorine, 3 sulfur
d) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
CaCO₃ (s) + HCI (aq) ---> CaCl₂ (aq) + CO₂ (g) + H₂O (l)
Reactants: 1 calcium, 1 carbon, 3 oxygen, 1 hydrogen, 1 chlorine
Products: 1 calcium, 1 carbon, 3 oxygen, 2 hydrogen, 2 chlorine
The balanced equation:
CaCO₃ (s) + 2 HCI (aq) ---> CaCl₂ (aq) + CO₂ (g) + H₂O (l)
Reactants: 1 calcium, 1 carbon, 3 oxygen, 2 hydrogen, 2 chlorine
Products: 1 calcium, 1 carbon, 3 oxygen, 2 hydrogen, 2 chlorine
please help me with this question
1. The resulting concentration will be 0.00044 mol/L
2. The minimum mass of sodium sulfite to add will be 0.4032 grams.
Stoichiometric problems1. Using m1v1=m2v2
m1 = 0.01 mol/L, v1 = 20 mL, v2 = 450 mL
m2 = m1v1/v2 = 0.01 x 20/450 = 0.00044 mol/L
2. [tex]Na_2SO_3 + Ca(NO_3)_2 --- > 2NaNO_3 + CaSO_3[/tex]
Mole ratio of the reactants = 1:1
Mole of 80 mL, 0.0400 mol/L Ca(NO3)2 = 80/1000 x 0.0400 = 0.0032 mol
Equivalent mole of Na2SO3 = 0.0032 moles
Mass of 0.0032 moles Na2SO3 = 0.0032 x 126 = 0.4032 grams
Thus, the minimum mass of sodium sulfite to be added must be 0.4032 grams.
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What volume of barium chloride, BaCl2 is needed to make a 2.5 M barium
chloride solution with 0.45 mol BaCl2?
Answer:
0.18 L
Explanation:
You can find the volume using the molarity ratio:
Molarity = moles / volume (L)
You can plug the given values into the equation and simplify to find the volume.
Molarity = moles / volume <----- Molarity ratio
2.5 M = 0.45 moles / volume <----- Insert values
(2.5 M) x volume = 0.45 moles <----- Multiply both sides by volume
volume = 0.18 L <----- Divide both sides by 2.5
A[?] is a heterogeneous mixture which settles on standing and its components can be separated by filtration. colloid suspension
I think it should be suspension.
a gas has a density of 3.21 g/L at stp what is the gas
The gas is bromine. (This is a fact)
(Yield Problem)
3Mg+2FeCl3=2Fe+3MgCl2
When 20.5 g of Mg reacts with an excess of FeCl3, 25.9 g of Fe is produced. What is the percent
yield of the reaction?
Answer:
Percent Yield Fe = 82.5%
Explanation:
The actual yield is the value produced after an experiment is conducted. The theoretical yield is the value calculated using the balanced chemical equation and atomic/molar masses.
To find the percent yield of iron (Fe), you need to (1) convert grams Al to moles Al (via atomic mass), then (2) convert moles Al to moles Fe (via mole-to-mole ratio from equation coefficients), then (3) convert moles Fe to grams Fe (via atomic mass), and then (4) calculate the percent yield. It is important to arrange the ratios in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the sig figs of the given values.
Atomic Mass (Mg): 24.305 g/mol
Atomic Mass (Fe): 55.845 g/mol
3 Mg + 2 FeCl₃ -----> 2 Fe + 3 MgCl₂
20.5 g Mg 1 mole 2 moles Fe 55.845 g
----------------- x ----------------- x ---------------------- x ----------------- =
24.305 g 3 moles Mg 1 mole
= 31.4 g Fe
Actual Yield
Percent Yield = ---------------------------------- x 100%
Theoretical Yield
25.9 g Fe
Percent Yield = -------------------- x 100%
31.4 g Fe
Percent Yield = 82.5%
How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa)?
A. 163.2
B. 0.28
C. 152.3
D. 0.30
0.28 moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa).
Ideal gas law :
An ideal gas is a gas in which atoms dose not exert any force on each other even after collision which walls and other atoms (inelastic collisions).
Mole definition:
The mole is the amount of compound present in a given system which has molecular mass as that of the mass of carbon12 .carbon 12
Using ideal gas law ,
PV=nRT
Given,
pressure = P = 100kPa
Volume = V = 6.8 Lit
Temperature = room temperature = T = 293 K
R= universal gas constant = 8.314
n= moles = ?
∴[tex]n = \frac{PV}{RT}[/tex]
∴ n = 100 × 6.8 / 8.314 × 293
∴n = 0.28 moles
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