Explanation:
Hey there!
Given that 4kg ball struck by 12 N force.
So, we need acceleration.
Force = Mass × Acceleration
And, so
Acceleration = Force / Mass.
Acceleration = 12/4
Acceleration is equal to 3m/s² in SI units.
Hope it helps :)
Pleaseeeeeeeeeeeeeeeeeee
The initial velocity is referring how fast the object is moving at the end of the scenario or problem.
True
False
Answer:
Fasle. , is correct answer hope it helps
A crane lifts an air conditioner to the top of a building. If the building is 12 m high, and the air conditioner has a mass of 200 kg, how much work did the crane do to lift it? (Hint: the force the crane exerts is equal to the weight of the air conditioner)
Work needed = 23,520 J
Further explanationGiven
height = 12 m
mass = 200 kg
Required
work needed by the crane
Solution
Work is the transfer of energy caused by the force acting on a moving object
Work is the product of force with the displacement of objects.
Can be formulated
W = F x d
W = Work, J, Nm
F = Force, N
d = distance, m
F = m x g
Input the value :
W = mgd
W = 200 kg x 9.8 m/s²x12 m
W = 23520 J
what is electric switch
Answer:
A device that is used to break an electric circuit is called electric switch
Need help ASAP
Thanks + BRAINLIST only for correct answer
1.Cell phones convert sound waves into______waves.
-light waves
-sound waves
-radio waves
2.Electromagnetic waves used in cell phone communications are called?
-microwave
-radio wave
-infrared
-all of the above
3.To send out a radio signal far and wide...it is called?
-broadcast
-casting
-antenna
Answer:
.Cell phones convert sound waves into______waves.
-sound waves
.Electromagnetic waves used in cell phone communications are called?
-radio wave
.To send out a radio signal far and wide...it is called?
antenna
Explanation:
i might be wrong in ans c ok
Which examples best demonstrate likely tasks for Legal Services workers? Check all that apply.
Cisco inspects an office building to make sure it meets fire safety regulations.
Gina gathers information about a court case.
Saul oversees inmates at a correctional facility.
Hana interviews and advises a person who has been accused of a crime.
Pamela pursues and arrests a person suspected of a crime.
Dewayne creates the paperwork for a business contract.
Answer:
b. d. f.
Explanation:
Got it right on Edge
Answer:
2. Gina gathers information about a court case.
4. Hana interviews and advises a person who has been accused of a crime.
6. Dewayne creates the paperwork for a business contract.
A student is preparing to take a bath when she realizes the hot water tap in the bathroom is not working. The student goes to the kitchen and prepares 10 of 100°C water to mix with 10 L of 10°C water.
Answer:
(10 L)(100° C) + (90 L)(10°) = (100 L)T
1,000 + 900 = 100T
1,900 = 100T
100T = 1,900
T = 1,900/100
Explanation:
Suppose a mass of 0.500 kg falls from 3050m. What potential energy is associated with the coin when its speed is 30.0 m/s?
Answer:
14945 J
Explanation:
Glad you asked this question!
The speed is irrelevant in this question. It perhaps was put out to throw you off.
P.E = mgh = (0.5 * 9.8 * 3050) = 14945 Joules
Which one of the following is NOT a phenotype?
O Red Hair
O Brown Eyes
O Red/Green Blood
O Five foot tall girl
O These are all phenotypes
which of the following cannot be used for measurement of time
a A leaking tap
b simple pendulum
c shadow of object during the day
d blinking of eyes
Answer:
D. blinking ofeyea
Explanation:
not really sure
Read through the and calculate the predicted change in kinetic energy of the oblect compared to 50 kg ball traveling at 10 m/s . 50 kg ball traveling at 20 n / s would havekinetic energy 50 kg traveling at 5 m/s would have energy 50 kg person falling at 10 m/s would havekinetic energy
Answer:
A 50 kg ball traveling at 20 m/s would have 4 times more kinetic energy.
A 50 kg ball traveling at 5 m/s would have 4 times less kinetic energy.
A 50 kg person falling at 10 m/s would have the same kinetic energy.
Explanation:
hope this helps:)
A man can row a boat at 4kmhr in still water. He rows the boat 2km upstream and 2 km back to his starting place in 2 hours. How fast is the stream flowing
Answer:
2.83km/hr
Explanation:
Let stream flowing at the rat x km/hr
In still water
Speed of boat=4km/hr
Upstream speed=4-x
Downstream speed=4+x
Total time=2 hr
Time=Distance/speed
According to question
[tex]\frac{2}{4+x}+\frac{2}{4-x}=2[/tex]
[tex]\frac{8-2x+8+2x}{(4+x)(4-x)}=2[/tex]
[tex]\frac{16}{4^2-x^2}=2[/tex]
Using the formula
[tex](a+b)(a-b)=a^2-b^2[/tex]
[tex]4^2-x^2=\frac{16}{2}[/tex]
[tex]16-x^2=8[/tex]
[tex]16-8=x^2[/tex]
[tex]8=x^2[/tex]
[tex]x=\sqrt{8}=2.83km/hr[/tex]
Hence, the stream is flowing at 2.83km/hr
What part of the eye protects your eye from scratches?
retina
pupil
cornea
iris
Answer:
Cornea
Explanation:
The outer layer of the cornea is covered by epithelial cells that protect the surface. A corneal abrasion may result from dragging a piece of debris across the surface and scraping off the epithelial cells.
How does Boyle's laws describe the relationship between gas pressure and volume?
Answer:
For a fixed mass of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional. Or Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship. If volume increases, then pressure decreases and vice versa, when the temperature is held constant.
A body at rest is given an instal
uniform acceleration of 8.0m/s² for 30
seconds after which the acceleration is
reduced at 50m/s² for the next 20
second the body maintains the speed
attain for 60 seconds after which it is
brought to rest in 20 seconds
v=u+at
v=0+8.0×30
v=240
Gravitational force acts on all objects in proportion to their masses. Why then, a heavy object does not fall faster than a light object?
Plss help!!!!
Answer:
This is because the acceleration of objects due to gravity is independent of the mass of the object and is constant for all objects, therefore, all objects fall with the same speed.
Explanation:
The weight of an object or force of gravity acting on an object on the surface of earth is a product of its mass and acceleration due to gravity.
Mathematically, w = mg
where, m=mass of the object; g = acceleration due to gravity
Also, from newton's law of gravitation, gravitational force on the object ,F = GMm/r²
where G is the gravitational constant; M is mass of Earth; m is mass of object; r is the distance of separation between the object and the center of mass of the earth which is approximately the radius of earth.
Since the weight of an object is equal to the force of gravitation acting on it
W = F
mg = GMm/r²
g = GM/r²
The expression above is that of the relationship between the force of gravity acting on a body on the earth's surface, the weight of that body and the acceleration due to gravity, g.
It can be seen that the acceleration due to gravity g is independent of the mass of the object. Therefore, the acceleration of objects due to gravity is constant for all objects and all objects fall with the same speed.
Answer:
The time of fall of an object is dependent only on the height of fall for a given acceleration due to gravity and it is independent of the object's mass
Explanation:
The gravitational force acting on an object on Earth can be observed as the weight, 'W', of the object which is a function of the mass, 'm', of the object and the relationship between the gravitational force and the mass of the object is given as follows;
W = m × g
Where;
g = The acceleration due to gravitational force = Constant
The relationship between the speed, 'u', and therefore, the time, 't', with which an object falls, the distance or height of fall, 'h', and the acceleration of the motion, 'g' is given as follows;
h = u·t + 1/2·g·t²
Given that the initial velocity of the object, 'u', of the object allowed to fall is u = 0 m/s, we have;
h = u·t + 1/2·g·t² = 0 × t + 1/2·g·t²
h = 0 × t + 1/2·g·t² = 1/2·g·t²
h = 1/2·g·t²
t² = 2·h/g
t = √(2·h/g)
Therefore, the time, 't', it takes every object to fall from a height, 'h', is dependent only on the height, 'h', for a given acceleration due to gravity, 'g' and it is independent of the mass, 'm', of the object.
98. In Fig. 24-71, a metal sphere
with charge q = 5.00 uC and radius
r = 3.00 cm is concentric with a
larger metal sphere with charge Q =
15.0 uC and radius R = 6.00 cm. (a)
What is the potential difference be-
tween the spheres? If we connect the
spheres with a wire, what then is the
charge on (b) the smaller sphere and
(c) the larger sphere?
Answer:
(a) The potential difference between the spheres is 750 kVA
(b) The charge on the smaller sphere is 6.[tex]\overline 6[/tex] μC
(c) The charge on the smaller sphere, Q₁ = 13.[tex]\overline 3[/tex] μC
Explanation:
(a) The given parameters are;
The charge on the inner sphere, q = 5.00 μC
The radius of the inner sphere, r = 3.00 cm = 0.03 m
The charge on the larger sphere, Q = 15.0 μμC
The radius of the larger sphere, R = 6.00 cm = 0.06 m
The potential difference between two concentric spheres is given according to the following equation;
[tex]V_r - V_R = k \times q \times \left ( \dfrac{1}{r} - \dfrac{1}{R} \right)[/tex]
Where;
R = The radius of the larger sphere = 0.06 m
r = The radius of the inner sphere = 0.03 m
q = The charge of the inner sphere = 5.00 × 10⁻⁶ C
Q = The charge of the outer sphere = 15.00 × 10⁻⁶ C
k = 9 × 10⁹ N·m²/C²
Therefore, by plugging in the value of the variables, we have;
[tex]V_r - V_R = 9 \times 10^9 \times 5.00 \times 10^{-6} \times \left ( \dfrac{1}{0.03} - \dfrac{1}{0.06} \right) = 750,000[/tex]
The potential difference between the spheres, [tex]V_r - V_R[/tex] = 750,000 N·m/C = 750 kVA
(b) When the spheres are connected with a wire, the charge, 'q', on the smaller sphere will be added to the charge, 'Q', on the larger sphere which as follows;
[tex]Q_f[/tex] = Q + q = (5 + 15) × 10⁻⁶ C = 20 × 10⁻⁶ C
[tex]Q_f[/tex] = 20 × 10⁻⁶ C
From which we have;
Q₁/Q₂ = R/r
Where;
Q₁ = The new charge on the on the larger sphere
Q₂ = The new charge on the on the smaller sphere
[tex]Q_f[/tex] = 20 × 10⁻⁶ C = Q₁ + Q₂
∴ Q₁ = 20 × 10⁻⁶ C - Q₂ = 20 μC - Q₂
∴ (20 μC - Q₂)/Q₂ = 0.06/(0.03) = 2
20 μC - Q₂ = 2·Q₂
20 μC = 3·Q₂
Q₂ = 20 μC/3
The charge on the smaller sphere, Q₂ = 20 μC/3 = 6.[tex]\overline 6[/tex] μC
(c) Q₁ = 20 μC - Q₂ = 20 μC - 20 μC/3 = 40 μC/3
The charge on the smaller sphere, Q₁ = 40 μC/3 = 13.[tex]\overline 3[/tex] μC.
The potential difference is 7.5*10^5V and the charge on the smaller sphere is 6.67uC while the charge on the larger sphere is 13.34uC
Data;
q = 5.0 uCr = 3.0cm= 0.03mQ = 15.0uCR = 6.0cm = 0.06mPotential Difference between the Spheresfor the inner sphere;
[tex]v_i = \frac{kq}{r} = \frac{(9*10^9)(5*10^-^6)}{0.03} \\v_i = 1.5*10^6V[/tex]
for the outer sphere;
[tex]v_o = \frac{KQ}{R} = \frac{(9*10^9)(15*10^-^6)}{0.06} = 2.25 * 10^6V[/tex]
The difference in potential is
[tex]\delta V = v_o - v_i = 2.25*10^6 - 1.5*10^6 = 7.5*10^5V[/tex]
Charge on the Smaller Plate[tex]q + Q = 5 + 15 = 20 \mu C = 20*10^-^6C ..eq(i)[/tex]
The sharing of charge continues till they attain a point of equal potential
[tex]v_i = v_o \\\frac{kq}{r} = \frac{kQ}{R} \\\frac{q}{0.03} = \frac{Q}{0.06} \\Q= 2q ...eq(ii)\\[/tex]
let's solve for equation (i) and equation (ii)
[tex]q+2q = 20\mu C\\q = 6.67 \mu C[/tex]
The charge on the smaller sphere is 6.67uC
The charge on the larger sphereThe charge on the larger sphere is
[tex]Q = 2q\\q = 6.67 \mu C\\Q = 2 * 6.67 = 13.34 \mu C[/tex]
The charge on the larger sphere is 13.34uC
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In any collision (crash) the_
is ALWAYS constant
Answer:
In any collision (crash) the momentum
is ALWAYS constant
In any collision (crash) the momentum is always constant, whether it is an elastic collision or an inelastic collision the momentum before and after the collision is conserved
What is elastic collision?It is the type of collision in which the total momentum, as well as the kinetic energy of the system, is conserved.
The momentum is always preserved before and after any collision (crash), regardless of whether it is an elastic collision or an inelastic collision.
In the inelastic collision, the momentum is conserved but the kinetic energy of the quantity is not conserved.
The momentum of a quantity is preserved regardless of the type of collision, whether it be an elastic collision or an inelastic collision; the momentum of the quantity will always be conserved.
Hence, The momentum is always preserved before and after any collision (crash), regardless of whether it is an elastic collision or an inelastic collision.
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impossible because fractional charges do not exust
There are two main types of exercise: (1) exercise, which uses oxygen for energy, and (2) exercise, which does not.
a)
1= anaerobic, 2= aerobic
b)
1= aerobic, 2= anaerobic
Answer:
b
Explanation:
Answer:
B
Explanation:
Determine the momentum of a system that consists of two objects. One object, m1, has a mass of 6 kg and a velocity of 13 m/s towards the east and a second object, m2, has a mass of 14 kg and a velocity of 7 m/s in that same direction.
Momentum = (mass) x (velocity)
Momentum m₁ = (6 kg) x (13 m/s east) = 78 kg-m/s east
Momentum m₂ = (14 kg) x (7 m/s east) = 98 kg-m/s east
Since they're both in exactly the same direction you can simply addum up to get their total momentum. It's 176 kg-m/s east .
The momentum of a system that consists of two objects should be 176 kg m/s on east hand side.
Calculation of the momentum:Since we know that
Momentum = (mass) x (velocity)
So,
Momentum m₁ = (6 kg) x (13 m/s east) = 78 kg-m/s east
Momentum m₂ = (14 kg) x (7 m/s east) = 98 kg-m/s east
Since they are on same direction so the total momentum should be
= 78 + 98
= 176 kg-m/s east
hence, The momentum of a system that consists of two objects should be 176 kg m/s on east hand side.
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A stack of 10 quarters weighs 0.1255 lb. what is the mass in grams of one quarter?
Answer:
one quarter= 5.69 g
Explanation:
if 10 quarters = 0.1255 lbs
then 1 quarter = 0.01255 lbs (0.1255 divided by 10)
0.01255 lbs = 5.69 g
Planets A and B have the same mass, but planet A is half the size of planet B. Which statement correctly explains the weight you would experience on each planet? O A. You would weigh more on planet A because the distance between you and the planet's center of gravity would be smaller. B. You would weigh the same on both planets because the masses of the planets are the same. 2 C. You would weigh the same on both planets because your mass would be the same on both. D. You would weigh less on planet A because the distance between you and the planet's center of gravity would be smaller.
Answer:
I would say A
Explanation:
the closer you are to a planets center of gravity i feel you would weigh more.
Give me the example of junction law and loop law?
Answer:
According to the Junction rule, in a circuit, the total of the currents in a junction is equal to the sum of currents outside the junction. Kirchhoff’s Voltage Law goes by several names as Kirchhoff’s Second Law and Kirchhoff’s Loop Rule. According to the loop rule, the sum of the voltages around the closed loop is equal to null.
Explanation:
A 5 Kg bowling ball is thrown at a stationary 1.6 Kg bowling pin at 5 m/s. If the final velocity of the ball is 2.5 m/s. The final velicoty of the bowling pin is _____m/s.
Answer: hope this helps
Explanation:
If the final velocity of the ball is 2.5 m/s, the final velocity of the bowling pin is 7.8125 m/s.
What is principle of conservation of momentum?According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.
According to the principle of momentum conservation, total momentum of an system remains conserved.
Total initial momentum = total final momentum
5 kg × 5 m/s + 1.6 kg × 0 m/s = 5 kg × 2.5 m/s + 1.6 kg × v
1.6 kg × v = 5 kg × 5 m/s - 5 kg × 2.5 m/s
v = (5 kg /1.6 kg) (5 m/s - 2.5 m/s)
= 7.8125 m/s
Hence, If the final velocity of the ball is 2.5 m/s, the final velocity of the bowling pin is 7.8125 m/s.
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Which arrow correctly indicates the direction of friction acting on the box?
Answer: [tex]F_4[/tex]
Explanation:
The friction opposes motion. We can assume the motion to be downwards because the only force is the weight of the box mgsin(theta) aka F3.
Arrow 4 correctly indicates the direction of friction acting on the box.
What is the friction force?It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).
Mathematically it is defined as the product of the coefficient of friction and normal reaction.
On resolving the given force and accelertaion in the different components and balancing the equation gets.
Friction is a force that resists motion. Because the only force acting on the box is its own weight, we may conclude it is moving downhill. As the force approach the downhill the friction force is acting opposite to it.
Hence, arrow 4 correctly indicates the direction of friction acting on the box.
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Will mark BRAINLIST and thanks only for correct answers
1.What is the correct way a cell phone call goes out?
-The phone call goes out, transmits through microwaves, then moves to the central hub. Then the signals go to the nearest tower to the receiver of the call.
-The phone call goes out, transmits through radio waves, then moves to the central hub. Then the signals go to the nearest tower to the receiver of the call.
-The phone call goes out, transmits through microwaves, then moves to the tower. Then the signals go to the nearest hub to the receiver of the call.
2.Which property of AM frequencies allow them to travel over long distances?
-high amplitude
-high energy
-constant velocity
-long wavelength
3.what types of waves do cell phones use?
-radio waves
-gamma rays
-microwaves
Answer:
1. The correct way a cell phone call goes out is;
The phone call goes out, transmits through radio waves, then moves to the central hub. Then the signal go to the nearest tower to the receiver of the call
2. Long wavelength
3. Microwave
Explanation:
1. When making a call through a cell phone, the speech made is digitized such that it is converted to electrical signals which are then converted into number strings that are transmitted out of the antenna of the phone as radio waves which are then picked up by the closest cellphone tower mast which then transmit the signal to the applicable central hub from where the signal is transmitted to the tower closest to the intended call receiver
Therefore, the correct option is that the phone call goes out, transmits through radio waves, then moves to the central hub. Then the signal go to the nearest tower to the receiver of the call
2. The property of AM frequencies that allow them to travel over long distances is long wavelength
The frequency of AM radio waves is between 540 kHz and 1600 kHz, which can be propagated as ground wave or by the ionosphere at night
3. Cell phones makes use of the subcategory of microwave which is the super high frequency (SHF) band which with a range of 3 GHz to 30 GHz
What does vf stand for
a.fringe velocity
b.first velocity
c.final velocity
what is gas pressure
i’m stuck in B and D. which one is it?
Answer:
Option b is correct - Rocky, nearly continuous, found on earth surface.
The reason is it is the rocky surface area composed of crust and upper mantle part. Basically, it is the outer shell of earth.