I need this done because i really do not want to fail

The sustainable growth rate is calculated by subtracting the payout ratio from the ROE.

The sustainable growth rate is calculated by subtracting the payout ratio from the ROE. To calculate the sustainable growth rate for Gold Corp., we must first calculate the retention ratio. The retention ratio is calculated by subtracting the payout ratio from 100%. In this case, the retention ratio would be 100% - 20% = 80%. The sustainable growth rate is then calculated by multiplying the retention ratio by the ROE. In this case, the equation would be 80% * 12% = 9.6%. The sustainable growth rate for Gold Corp. is 9.6%, which can be rounded to 9.6%.

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It would be 20 because of the numbers

Answer:

D

Step-by-step explanation:

The notation is not what I am used to, but I think that I understand.  To go from the large figure to the smaller figure.  You need to dilate your figure by 1/3 .  The length of the big figure is 6 and 1/3 of that is a length of 2.  The width of the big figure is 3.  !/3 of that is 1 and that is what I see on the smaller figure.

Assuming the center of the dilation is point J.  If you move the shrunken figure 2 to the left and 5 down, it would fit right on top of the smaller figure.

The correct translation rule is given as -

(D_1/3 . T_<-2,-5> ) JKLM.

Translation is defined as the movement of graphical image over the two

dimensional plane. In genera, we can write the translation as -

(x, y) → (x ± k, y ± a)

here, we have,

Given is the composition of transformations that maps JKLM to PQRS.

Firstly →

The image is first translated according to the rule -

(x, y) → (x - 2, y - 5).

Secondly -

The image is then dilated by the scale factor -

{K} = 1/3.

Therefore, the correct translation rule is given as -

(D_1/3 . T_<-2,-5> ) JKLM.

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The square root of 7 is approximately 2.65 when rounded to the nearest hundredth.

If Sam is not an expert sailor, then he will not be allowed on Signe's racing boat. and If Sam is allowed on Signe's racing boat, then he is an expert sailor.

are both correct if-then forms of the given statement, with the first being the contrapositive of the second. The other options are not correct if-then forms.

The original statement is "Sam will be allowed on Signe's racing boat only if he is an expert sailor." This statement can be rewritten in if-then form using the formal definition of "only if," which means "if and only if" or "implies and is implied by."

One possible if-then form is "If Sam is not an expert sailor, then he will not be allowed on Signe's racing boat." This is the contrapositive of the original statement, which means that it is logically equivalent to the original statement. It asserts that if Sam is not an expert sailor, then he cannot be on Signe's racing boat.

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The tenth term of the second sequence is 80 and sequence 2 is formed by multiplying by 2 to sequence 1. Then the correct option is C.

Let a₁ be the first term and d be a common difference. Then the nth term of the arithmetic sequence is given as,

aₙ = a₁ + (n - 1)d

From the table, the first term of the first sequence is 4 and the first term of the second sequence is 8. If the first sequence is multiplied by 2 then we obtain the second sequence.

The common difference of the second sequence is given as,

d = 16 - 8

d = 8

Then the tenth term of the second sequence is given as,

a₁₀ = 8 + (10 - 1) x 8

a₁₀ = 8 + 72

a₁₀ = 80

The tenth term of the second sequence is 80 and sequence 2 is formed by multiplying by 2 to sequence 1. Then the correct option is C.

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The complete question is attached below.

Jack may not be obligated to pay Sam the $100 reward because he revoked the offer before Sam found the wallet.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value. Unitary method is a technique by which we find the value of a single unit from the value of multiple devices and the value of more than one unit from the value of a single unit. It is a method that we use for most of the calculations in math.

We are given that;

The amount of reward= $100

Now,

An offer can be revoked at any time before acceptance, and the revocation must be communicated to the offeree. In this case, Jack placed a second ad in the same newspaper revoking his offer before Sam found the wallet. Therefore, Sam did not accept the offer before it was revoked.

Additionally, Sam may not have provided consideration for the reward. Consideration is something of value given in exchange for a promise. In this case, Sam found the wallet before the reward was offered, so he did not provide consideration for the reward when he returned the wallet.

since the offer was revoked before acceptance and Sam did not provide consideration for the reward,

Therefore, by unitary method Jack may not be obligated to pay Sam the $100.

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The expression showing the distance between point J and point K is |-9|-|-2|

Distance between two points is the length of the line segment that connects the two given points.

Given that, two points J(6, -2) and k(6, -9), we need to find the distance between them,

The distance between two pints is given by,

D = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Here, the points are, (6, -2) and (6, -9)

Therefore,

|JK| = [tex]\sqrt{(0-0)^2+(-9+2)^2}[/tex]

|JK| = √7²

|JK| = 7 units

Therefore, the expression showing the distance between point J and point K is |-9|-|-2|

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Brandon have a total of $32 originally

From the question, we have the following parameters that can be used in our computation:

When he spends $24, he has 3/4 of the original amount left

Using the above as a guide, we have the following:

24 = Original * 3/4

Make "Original" the subject of the formula

So, we have the following representation

Original = 24/(3/4)

Evaluate the expression

Original = 32

Hence, the amount is $32

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Answer:

Below

Step-by-step explanation:

You have ONE equation and TWO unknowns, so there is infinite solutions for a and c......you cannot solve for a specific a and c unless you have another equation relating the two or a definition of one of them.

 You can Solve for a

  20a + 15 c = 340

     20 a = 340-15c

        a = ( 340 -15c) / 20 = 17 - 3/4 c

Similarly:

   20 a + 15 c = 340

  15c = 340 - 20 a

c = (340-20a)/15

Mean absolute deviation of the data is 1.

The mean absolute deviation of a dataset is the average distance between each data point and the mean. It gives us an idea about the variability in a dataset.

Given, In bar chart

Number of artists n = 4

Number of albums for Lil Shane x₁ = 7

Number of albums for Ben Raises x₂ = 9

Number of albums for Nicky x₃ = 6

Number of albums for Underdog x₄ = 6

Mean of the number of albums

μ = (7 + 9 + 6 + 6)/4 = 28/4 = 7

|μ - x₁| = |7 - 7| = 0

|μ - x₂| = |7 - 9| = |-2| = 2

|μ - x₃| = |7 - 6| = 1

|μ - x₄| = |7 - 6| = 1

Mean absolute deviation = ∑|x - μ|/n

= (0 + 2 + 1 + 1)/4

= 1

Hence, 1 is the mean absolute deviation (MAD) of the data in the bar chart.

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hola i can help... all you have to do is grab a calculator and add 100 to each number, them sbract them by 302

The amount to be paid by Bo is 0.82B

A percent of a number is the 100th part of it.

Given that, the board game costs B dollars. Price is reduced by 18%.  we need to calculate the final bill.

Cost of game = B dollars

Discount = 18% = 0.18

Discount amount = 0.18B

Final cost = B-0.18B

Amount to pay = 0.82B

Hence, the amount to be paid by Bo is 0.82B

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The complete question is:-

Bo is buying a board game which usually costs B dollars. The game is on sale, and the price has been reduced by 18% There are different ways of thinking about how to calculate Bo's final bill. Match the expressions to their meanings.

The range of the given data is 15, the sum is 110, variance is 37.

The sample variance is a value that measures the variability of values in the data set and how much the observed values deviate from the value of the mean or central value of the data set.

X=[23,17,15,30,25]

(a)

The value of the range is the difference between the maximum value and minimum value:

range=30-15=15

(b)

Sum(x)= 23+17+15+30+25=110

the sum of x2 = [tex]23^2+17^2+15^2+30^2+25^2=2568[/tex]

(c)

from part (b)

[tex]s^2=\sum x_i-nX^2]/[n-1]\\\\=[2568-5(22)^2][5-1]\\\\=37[/tex]

(d)

Using the definition of the variance, first we calculate the mean,

u=110/5=22

u=22

[tex]v^2=\frac{1}{n-1}\sum (x_i-u)^2\\\\=148/4\\=29.6\\s=6.083.[/tex]

e)

The value of population variance is v =5.44

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The actual dimensions of the rectangular garden are 17.5 cm by 12.5 cm

From the question, we have the following parameters that can be used in our computation:

Scale: 1.6 cm = 2 cm

A scale is the ratio of the size of the drawing to the size of the actual object.

Given that the dimension is

14 cm by 10 cm

Using the above as a guide, we have the following equation

Actual = 14 * 2/1.6 cm by 10 * 2/1.6 cm

Evaluate

So, we have the following representation

Actual = 17.5 cm by 12.5 cm

Hence, the actual is 17.5 cm by 12.5 cm

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i. The assumptions required to use Theorem 7.4 are that the daily downtimes are independent and identically distributed with a mean of 4 hours and a standard deviation of .8 hour.

ii. The approximate probability that the average daily downtime for a period of 30 days is between 1 and 5 hours is about 0.998.

b. The approximate probability that the total downtime for a period of 30 days is less than 115 hours is about 0.03.

a) i) The assumptions that must be true to use the result of Theorem 7.4 (Central Limit Theorem) are:

The daily downtime observations must be independent.

The number of daily downtime observations, n = 30, must be large enough such that the normal approximation is valid. A general guideline is n >= 30, but for this specific case, n = 30 is sufficient.

The individual daily downtime observations must have the same mean and standard deviation, with mean μ = 4 hours and standard deviation σ = 0.8 hours.

ii) Under these assumptions, we can use the Central Limit Theorem to approximate the distribution of the average daily downtime as normal with mean μ = 4 hours and standard deviation σ/√n = 0.8/√30 = 0.17 hours.

Using a standard normal table or calculator, we can find that the approximate probability that the average daily downtime for a period of 30 days is between 1 and 5 hours is:

P(1 < μ_bar < 5) = P( (1-4)/0.17 < Z < (5-4)/0.17 ) = P(-23.53 < Z < 2.94) = 0.998

So, the answer is approximately 0.998 or 99.8%.

b) Under the same assumptions, the total downtime for a period of 30 days is a sum of 30 independent daily downtime observations, and we can use the central limit theorem to approximate its distribution as normal with mean 30*4 = 120 hours and standard deviation 0.8 * sqrt(30) = 2.7 hours.

Using a standard normal table or calculator, we can find that the approximate probability that the total downtime for a period of 30 days is less than 115 hours is:

P(X < 115) = P((115-120)/2.7 < Z) = P(-1.85 < Z) = 0.03

So, the answer is approximately 0.03 or 3%.

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The signficant changes that are happening as per the information provided in the question will be as follows:

1. The p-value for Factor A is 0.4194 option e. greater than 0.10.

2. The conclusion with respect to Factor A will be option b. Factor A is not significant.

3. The conclusion with respect to Factor B will be option b. Factor B is not significant.

4. The p-value for the interaction of factors A and B is 0.1621 option e. greater than .10

5. There is no effect of decreasing the waiting time and changing the loading and unloading methods  between the rides.

Here, we are going to perform two-way ANOVA Observation

A       B               C                

41, 43, 49 52, 44, 46 50, 46, 48

49, 50, 48 50, 46, 48 48, 44, 46          

Sums of row and column

A      B        C          Row total (xa)

133     142   144                    419

147     144   138                    429

Col total (xb)

280   286 282                    848

For A,

∑x²=412+432+492+...+482+442+462=40088

∑x²b/ra =1/3⋅2(280²+286²+282²)

=1/6(78400+81796+79524)

=1/6(239720)

For B,

=39953.3333

∑x²a/rb=1/3⋅3(419²+429²)

=1/9(175561+184041)

=1/9(359602)

For C,

=39955.7778

∑∑x²ab/r=  1/3(133²+142²+144²+147²+144²+138²)

=1/3(17689+20164+20736+21609+20736+19044)

=1/3(119978)

=39992.6667

For D,

(∑x)²/rab

=(848)²/3⋅2⋅3

=719104/18

=39950.2222

Sum of squares total

SST=∑x²-(∑x)²/n

Now we subtract A and D

=(A)-(D)

=40088-39950.2222

=137.7778

Sum of squares between rows will be,

SSA=∑x²a/rb-(∑x)²/n

Now, we subtract C and D

=(C)-(D)

=39955.7778-39950.2222

=5.5556

Sum of squares between columns

SSB=∑x²b/ra- (∑x)²/n

Now, we subtract B and D

=(B)-(D)

=39953.3333-39950.2222

=3.1111

Sum of squares between columns

SSAB=∑∑x²ab/r-(∑x)²/n-SSA-SSB

Now we subtract B, D and Sum of squares between columns

=(B)-(D)-SSA-SSB

=39992.6667-39950.2222-5.5556-3.1111

=33.7778

The residual value of sum of squares Error,

SSE=SST-SSA-SSB-SSAB

=137.7778-5.5556-3.1111-33.7778

=95.3333

ANOVA table

Source. Sums    Degrees Mean Squares Square

of squares of freedom variation freedom

                       SS              DF          MS              F        

A         SSA=5.5556     a-1=1 MSR=5.5556    0.6993   0.4194 (p-value)

B            SSB=3.1111      b-1=2 MSC=1.5556    0.1958

0.8247 (p-value)

AB       SSAB=33.7778   2   MSAB=16.8889   2.1259 0..1621 (p-value)

Error (residual) SSE=95.33      12         MSE= 7.9444            

Total of SST=137.7778      will be    17  

In conclusion,

1. F for between columns, the critical value F(1,2) at 0.05 level of significance will be 4.7472. As computed that FR=0.6993<4.7472

H0 has been accepted, thus, there is no significant difference between rows.

P value is 0.4194 > 0.05. Hence, we fail to reject H0

2. F for between columns, the critical value F(2,2) at 0.05 level of significance will be 3.8853. As computed, FC=0.1958<3.8853. Thus, H0 is accepted and there is no significant difference between columns. P value is 0.8247 > 0.05. Hence, we fail to reject H0

3. The interaction between the Factors AB, there is no sufficient evidence to support the claim of interaction between the factors. Thus, P value is 0.1621 > 0.05. Hence, we fail to reject H0.

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Note that the full question is:

An amusement park studied methods for decreasing the waiting time (minutes) for rides by loading and unloading riders more efficiently. Two alternative loading/ unloading methods have been proposed. To account for potential differences due to the type of ride and the possible interaction between the method of loading and unloading and the type of ride, a factorial experiment was designed. Use the following data to test for any significant effect due to the loading and unloading method, the type of ride, and interaction. Use α = .05. Use both p-Value and Critical-Value approaches.Type of Ride

Roller Coaster Screaming Demon Log Flume

Method 1 41 52 50

43 44 46

49 46 48

Method 2

49 50 48

51 46 44

47 48 46

1. The p-value for Factor A is:__________.

a. less than .01

b. between .01 and .025

c. between .025 and .05

d. between .05 and .10

e. greater than .10Item 18

2. What is your conclusion with respect to Factor A?

a. Factor A is significant

b. Factor A is not significant

3. The p-value for Factor B is:_______.

a. less than .01

b. between .01 and .025

c. between .025 and .05

d. between .05 and .10

e. greater than .10

3. What is your conclusion with respect to Factor B?

a. Factor B is significant

b. Factor B is not significant

4. The p-value for the interaction of factors A and B is:_______.

a. less than .01

b. between .01 and .025

c. between .025 and .05

d. between .05 and .10

5. What is your recommendation to the amusement park?

The linear equation is y = $25 + $10*w, and its graph is on the image at the end.

Here we know that he started with $25 He adds $10 to the cookie jar each week. Then we can model this with a linear equation:

y = $25 + $10*w

Where w is the number of weeks.

Now we want to graph this, to do so, we just need to find two points on the line.

if w = 0

y = $25 + $10*0 = $25

if w = 6

y = $25 + $10*6 = $85

So we need to graph the points (0, 25) and (6, 85) and connect them witha  line.

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The value of h such that the matrix is the augmented matrix of a consistent linear system is 2

For the given matrix to be the augmented matrix of a consistent linear system, we need to check whether the matrix is in row echelon form or not. If the matrix is in row echelon form and the last row is not all zeros, then the linear system is consistent.

We can use elementary row operations to transform the matrix into row echelon form.

[tex]\left[\begin{array}{ccc}1&h&4\\3&6&8\end{array}\right][/tex]

R2 <- R2 - 3R1

[tex]\left[\begin{array}{ccc}1&h&4\\0&6-3h&-4\end{array}\right][/tex]

The matrix is in row echelon form. Now, we need to check whether the last row is all zeros or not.

If 6-3h = 0, then the last row will be all zeros, which implies that the linear system is inconsistent.

If 6-3h ≠ 0, then the last row will not be all zeros, which implies that the linear system is consistent.

Therefore, we need to solve the equation 6-3h = 0 to determine the value of h that makes the linear system consistent.

6-3h = 0

3h = 6

h = 2

So, the value of h that makes the matrix the augmented matrix of a consistent linear system is h = 2.

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Answer: 63

63-15=48

Step-by-step explanation:

(a) Glen Cove's current population is 5,000.

In order to determine Glen Cove's current population, we must calculate P(0) because P(t) provides the population (in thousands) for t years in the future. In other words,

P(0) = (35(0)2 + 125(0) + 200) / (02 + 4(0) + 40)

      = 200 / 40

      = 5.

Since P(t) yields the population in thousands, Glen Cove's current population is 5,000.

(b) The population in the long run (as t approaches infinity) is 35,000.

As t approaches infinity, we must discover the limit of P(t) in order to determine the population over the long term. To do this, we can divide the function's numerator and denominator by t2, which results in the formula: P(t) = (35 + 125/t + 200/t2) / (1 + 4/t + 40/t2).

The terms 125/t and 200/t2 get smaller and smaller as t increases, so we can ignore them in the numerator. We can therefore disregard the terms 4/t and 40/t2 because they also degenerate in the denominator to lower and smaller values. Thus, we are left with:

P(t) ≈ 35/1 \s = 35

Since P(t) represents the population in thousands, the population in the long run (as t approaches infinity) is 35,000.

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One possible set of positive integers that satisfies the given condition is the set of powers of 2, i.e., {2, 4, 8, 16, 32, ...}.

To see why this set works, note that any two distinct powers of 2 have a different binary representation, differing in at least one bit. This means that their sum will have one more "1" bit in its binary representation than either of the two numbers being added.

Since any prime number greater than 2 is odd, it follows that the sum of any two distinct powers of 2 will have an even number of distinct prime factors, namely the powers of 2 that appear in its binary representation.

First, let's note that every positive integer can be uniquely expressed as a product of prime powers, e.g., 36 = 2^2 * 3^2. The prime factors of an integer are the primes that appear in its prime factorization, e.g., the prime factors of 36 are 2 and 3.

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Step-by-step explanation:

To find the greatest common factor (GCF) of the expression (8 + 12), we need to first simplify the expression by finding the sum, which is 20. Therefore, the GCF of (8 + 12) is simply the GCF of 20, which is 20.

To rewrite the expression as a multiple of a sum of two whole numbers with no common factor, we can factor out the GCF of 4 from both 8 and 12, giving us:

(8 + 12) = 4(2 + 3)

The expression (8 + 12) is thus a multiple of the sum of the whole numbers 2 and 3, which have no common factor.

For x ≤ -1, the function is given by f(x) = 4x + 1. This is a linear function with a slope of 4 and y-intercept of 1. The graph of this part of the function is a straight line passing through (0, 1) with a steep slope, extending towards negative x-values.

In mathematics, a function is a rule that associates each element in one set (called the domain) to a unique element in another set (called the range). Functions are one of the most important concepts in mathematics and have a wide range of applications in various fields.

A function is usually denoted by a letter, such as f(x), where x is an element in the domain and f(x) is the corresponding element in the range. The domain of a function is the set of all possible values of x for which the function is defined, and the range is the set of all possible values of f(x).

To graph the piecewise function f(x), we will graph each part of the function separately.

For -1 < x < 2, the function is given by f(x) = -2x - 3. This is also a linear function with a slope of -2 and y-intercept of -3. The graph of this part of the function is a straight line passing through (-1, 1) with a gentle slope, extending towards positive x-values until it reaches x=2.

For x ≥ 2, the function is given by f(x) = 5. This is a horizontal line at y=5, which is a constant function. The graph of this part of the function is a horizontal line at y=5 starting from x=2.

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We can see from a t-table with right-tail probabilities that the probability value that is closest to 2.5% is 0.0250, which is represented by a t-score.

The row in the table that corresponds to the number of degrees of freedom (df) must be found before the column that corresponds to the desired level of significance or alpha value in order to use the t-table to determine a t-score that cuts off a specific percentage in the upper tail for a t-distribution with a given number of df.

Since there are 24 degrees of freedom in this situation, we need to identify the t-score that removes 2.5% of the upper tail. We will be looking at the column for the right-tail probabilities because this test has one tail (upper tail), making it a one-tailed test.

Therefore, We can see from a t-table with right-tail probabilities that the probability value that is closest to 2.5% is 0.0250, which is represented by a t-score.

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Answer: It is D.

Step-by-step explanation:

Answers:

B ' (6, 4)

C ' (2, 3)

D ' (3, -1)

E ' (7, 0)

=================================================

Explanation:

The y-axis reflection rule is:

[tex](\text{x},\text{y})\to (-\text{x},\text{y})[/tex]

The x coordinate flips from positive to negative, or vice versa. The y coordinate stays the same.

So for example, the point B(-6,4) moves to B ' (6, 4).

You can use a graphing tool like GeoGebra to confirm the answers are correct.

Answer:

Step-by-step explanation:

if we simplify both of them,

5/10=1/2

and

6/12=1/2

then it means they are equal