I provided the question above.

Explanation:

The gravitational potential at a point in a gravitational field is the work done per unit mass that would have to be done by some externally applied force to bring a massive object to that point from some defined position of zero potential,

Answer:

1.6 x 10^{-19} Coulombs

Explanation:

In Physics, the standard unit of measurement of a charge is Coulombs and it's denoted by C. Also, the symbol for denoting a charge is Q.

In Chemistry, electrons can be defined as subatomic particles that are negatively charged and as such has a magnitude of -1.

The minimum charge on any object such as an electron cannot be less than​ 1.6 x 10^{-19} Coulombs and it's usually referred to as the fundamental unit of charge.

Answer:

We know that in a string with two fixed points (like the one you will find in a guitar, where the string is "fixed" at the bridge and at the nut) the only thing that defines the speed (the frequency) at which the string vibrates is the tension (the length is also important, but for the 6 strings in the guitar all of them have the same length, but, as you know, when you press in a given fret the note changes, this happens because you are changing the length of the string, finally, the mass of the string is also important, but all the strings have almost the same mass, so we can ignore this).

Then for the open notes (the notes that you play when you don't fret any note) the only thing that defines the note that will sound is the tension of the string.

And a musician can tune the stringed instrument by changing the tension of each string using a tuner, which is the mechanism in the headstock of the instrument). As more tense is the string, higher will be the open note.

Explanation:

The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value.

Answer:

Sentences with many clauses and phrases are difficult to understand because the clauses and phrases typically _____.

modify other clauses and phrases in the sentence

refer to other sentences in the passage

make it hard to determine where the sentence ends

change the intended meaning of the sentence

Explanation:

Answer:

the other colours get absorbed by the paper

Answer:

The other colors are absorbed by the paper and not reflected.

Answer:

[b] it id heated from 4o

Explanation:

Answer:

a)[tex]MV=3.118[/tex]      

b)[tex]AD=0.0416[/tex]  

c)[tex]TSD=0.00302[/tex]  

d)[tex]SD=0.00242[/tex]  

e)[tex]%E=0.75%[/tex][tex]PE=0.75\%[/tex]

Explanation:

a)

The mean value equation is:

[tex]MV=\frac{\Sum x}{n}[/tex]

Where:

[tex]MV=\frac{3.14+3.11+3.20+3.06+3.08}{5}[/tex]

[tex]MV=3.118[/tex]      

b)

The average deviation equations is:

[tex]AD=\frac{\Sum |x-MV|}{n}[/tex]    

[tex]AD=\frac{0.208}{5}[/tex]  

[tex]AD=0.0416[/tex]  

c)  

The true Standard Deviation equation is:

[tex]TSD=\sqrt{\frac{\Sum (x-MV)^{2}}{n-1}}[/tex]    

[tex]TSD=\sqrt{\frac{0.01208}{5-1}}[/tex]      

[tex]TSD=0.00302[/tex]    

d)

The  Standard Deviation equation is:

[tex]TSD=\sqrt{\frac{\Sum (x-MV)^{2}}{n}}[/tex]    

[tex]TSD=\sqrt{\frac{0.01208}{5}}[/tex]      

[tex]SD=0.00242[/tex]    

e)

The percent error equation is:

[tex]%E=\frac{|Measured value - True value|}{|True value|}[/tex][tex]PE=\frac{|Measured value - True value|}{True value}[/tex]

[tex]%E=\frac{|Measured value - True value|}{|True value|}[/tex][tex]PE=\frac{|3.118-3.14159|}{3.14159}*100[/tex]

[tex]%E=\frac{|Measured value - True value|}{|True value|}[/tex][tex]PE=0.75\%[/tex]

[tex]%E=0.75%[/tex]

I hope it helps you!

Answer:

the weight of an object is the same on earth and moon

Explanation:

bcoz weight depends on both mass and gravity

since the gravity of earth and moon is different then the weight is also different

mass doesn't change not weight

Answer:

9.7 trillion kilometers

Explanation:

Answer:

D and E

Ionic bonds are formed between metals and non-metals and both of those are metals

Answer:

I think -7 N. Netforce is 3N-10N= -7N

Explanation:

Answer:

∴ [T]=[WF−1V−1]

Hope this answer is right!!

Answer :

[T] = [W(F)^-1(V)^-1]

Explanation:

Energy input = F×d = (150 N)(5.5 m) = 825 J

Energy output = mgh = (66 kg)(9.8 m/s^2)(1.10 m) = 711 J

efficiency = [tex]\dfrac{\text{output}}{\text{input}}[/tex]×100% = 86.2%

Answer:

Using biofuels

Explanation:

The emissions of NOx and total VOCs lead to the formation of ozone in the troposphere, the main component of smog. ... Biofuels has a number of health and environmental benefits including improvement in air quality by reducing pollutant gas emissions relative to fossil fuels

Answer:

The weight of the hanging mass provides tension in the string, which helps to accelerate the cart along the track. A small frictional force will resist this motion. 

Answer:

B

Explanation:

The seasons are measured in how far or close the earth is to the sun.

Answer:

The right solution is "4.8° east of north".

Explanation:

Given:

Distance,

= 500 km

Speed,

[tex]\vec{v}=120 \ m/s[/tex]

Wind (towards west),

[tex]v_0=10 \ m/s[/tex]

According to the question, we get

The angle will be:

⇒ [tex]\Theta=Cos^{-1}(\frac{v_0}{v_1} )[/tex]

       [tex]=Cos^{-1}(\frac{10}{120} )[/tex]

       [tex]=85.21[/tex] (north of east)

hence,

The direction must be:

⇒ [tex]\Theta'=90-85.21[/tex]

        [tex]=4.79^{\circ}[/tex]

or,

        [tex]=4.8^{\circ}[/tex] (east of north)

Answer:

M L1 = m L2       torques must be zero around the fulcrum

M = m L2 / L1 = .3 kg * 28 cm / 22 cm = .382 kg

Answer:

Explanation:

For very low values of the ionic strength the value of the denominator in the expression above becomes nearly equal to one. In this situation the mean activity coefficient is proportional to the square root of the ionic strength. This is known as the Debye–Hückel limiting law.

Answer:

7 ft/s

Explanation:

Applying,

V(t) = ds(t)/dt

Where V(t) = velocity of the ball at a given time

From the question,

Given: s(t) = 39t-16t²

Therefore,

V(t) = ds(t)/dt = 39-32t............. Equation 1

at t = 1 seconds,

Substitute the value of t into  equation 1

V(t) = 39-32(1)

V(t) = 39-32

V(t) = 7 ft/s

Explanation:

I remember that notation! The expression

[tex]dQ = dU = (\dfrac{\partial U}{\partial T})_{V} dT+ (\dfrac{\partial U}{\partial V})_{T}dV[/tex]

is the 1st law of thermodynamics and it refers to the heat supplied to the system dQ which is also a change in its internal energy dU. The first term is the partial derivative of the internal energy U with respect to temperature T while the volume V is kept constant, as denoted by the subscript V. The 2nd term is similar but this time, temperature is kept constant while its volume partial derivative is being taken.

Ah, memories!

Answer:

[tex]\mathbf{\mu_s = \dfrac{g}{\omega^2r}}[/tex]

Explanation:

From the given information:

The force applied to the child should be at equilibrium in order to maintain him vertically hung on the wall.

Also, the frictional force acting on the child against gravitational pull is:

[tex]F_f = \mu _sN[/tex]

where,

the centripetal force [tex]F_c[/tex] acting outward on the child is equal to the normal force.

[tex]F_c= N[/tex]

SO,

[tex]F_f = \mu_s F_c[/tex]

Since the centripetal force [tex]F_c = \dfrac{mv^2}{r}[/tex]

Then:

[tex]F_f = \dfrac{ \mu_s \times mv^2}{r}[/tex]

Using Newton's law, the frictional force must be equal to the weight

[tex]F_f = W[/tex]

[tex]\dfrac{ \mu_s \times mv^2}{r} = mg[/tex]

[tex]\dfrac{ \mu_s v^2}{r} = g[/tex]

Recall that:

The angular speed [tex]\omega = \dfrac{v}{r}[/tex]

Therefore;

[tex]g = \mu_s \omega^2 r[/tex]

Making the coefficient of friction [tex]\mu_s[/tex] the subject of the formula:

[tex]\mathbf{\mu_s = \dfrac{g}{\omega^2r}}[/tex]

Answer:

A. & B. Heat energy is needed to convert solid into a liquid because heat energy increases the kinetic energy of the particles. The heat energy that it used to change 1 kg of solid into liquid at atmospheric pressure and at its melting point is called the latent heat of fusion.

Two things are said to be in contact if the smallest distance between a point in one of them and a point in the other one is zero.

Answer:

a)  [tex]X_1=7.36rev[/tex]

b)  [tex]X_2=46.22radians[/tex]

c) [tex]X_3=2649.6^o[/tex]

Explanation:

From the question we are told that:

Diameter [tex]d=9.00[/tex]

Distance [tex]x=208[/tex]

Generally the equation for circumference of a circle is mathematically given by

[tex]C=2 \pi r\\\\C=2*\pi*4.5[/tex]

[tex]C=28.3[/tex]

Therefore

Angular distance that the pie plate has moved through in revolutions is

[tex]X_1=\frac{x}{C}[/tex]

[tex]X_1=\frac{208}{28.3}[/tex]

[tex]X_1=7.36rev[/tex]

Generally Angular distance that the pie plate has moved through in radians is

[tex]X_2= 7.36rev* 2 \pi[/tex]

[tex]X_2=46.22radians[/tex]

Generally Angular distance that the pie plate has moved through in degrees is

[tex]X_3=7.36rev* 360[/tex]

[tex]X_3=2649.6^o[/tex]

Answer:

False.

Explanation:

Suppose that we have an object that moves with constant acceleration A.

Then the acceleration of the object is defined by the equation:

a(t) = A

The acceleration is the rate of change of the velocity, then the velocity equation is given by the integration of the acceleration equation, we will get:

v(t) = A*t + V₀

Where V₀ is the velocity of the object at the time t = 0s.

Now, if we integrate it again, we will get the position equation:

p(t) = (1/2)*A*t^2 + V₀*t + P₀

Where P₀ is the initial position equation.

Here, we can see that the position equation is a quadratic equation (not a linear equation), then the statement is false.