Answers
STEP
1
:
5
Simplify —
4
Equation at the end of step
1
:
1 5
(— + a) - — = 0
3 4
STEP
2
:
1
Simplify —
3
Equation at the end of step
2
:
1 5
(— + a) - — = 0
3 4
STEP
3
:
Rewriting the whole as an Equivalent Fraction
3.1 Adding a whole to a fraction
Rewrite the whole as a fraction using 3 as the denominator :
a a • 3
a = — = —————
1 3
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
3.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
1 + a • 3 3a + 1
————————— = ——————
3 3
Equation at the end of step
3
:
(3a + 1) 5
———————— - — = 0
3 4
STEP
4
:
Calculating the Least Common Multiple :
4.1 Find the Least Common Multiple
The left denominator is : 3
The right denominator is : 4
Number of times each prime factor
appears in the factorization of:
Prime
Factor Left
Denominator Right
Denominator L.C.M = Max
{Left,Right}
3 1 0 1
2 0 2 2
Product of all
Prime Factors 3 4 12
Least Common Multiple:
12
Calculating Multipliers :
4.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 4
Right_M = L.C.M / R_Deno = 3
Making Equivalent Fractions :
4.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. (3a+1) • 4
—————————————————— = ——————————
L.C.M 12
R. Mult. • R. Num. 5 • 3
—————————————————— = —————
L.C.M 12
Adding fractions that have a common denominator :
4.4 Adding up the two equivalent fractions
(3a+1) • 4 - (5 • 3) 12a - 11
———————————————————— = ————————
12 12
Equation at the end of step
4
:
12a - 11
———————— = 0
12
STEP
5
:
When a fraction equals zero :
5.1 When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
12a-11
—————— • 12 = 0 • 12
12
Now, on the left hand side, the 12 cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
12a-11 = 0
Solving a Single Variable Equation:
5.2 Solve : 12a-11 = 0
Add 11 to both sides of the equation :
12a = 11
Divide both sides of the equation by 12:
a = 11/12 = 0.917
a = 11/12 = 0.917
Answer:
11/12
Step-by-step explanation:
You want to subtract 5/4 minus 1/3 but you cant so you have to find the greatest denominator first which would be 12 because 3x4=12.
Since you multiplied 4x 3 to get 12 then you will multiply the 5 by 3 and the 1 by 4 to get this -> 5/4= 15/12 1/3= 4/12
Then subtract 15/12- 4/12= 11/12
a=11/12
Related Questions
The world population of a certain species is evaluated at 6.8 × 109. By some projections, this population will be 8 times more important in 30 years. Express the population at that time in scientific notation.
Answers
Using the multiplication operation, the population of the species in 30 years would be 8 times the current population. Hence, the population at the time would be [tex] 5.44 \times 10^{10}[/tex]
Current population = [tex] 6.8 \times 10^{9}[/tex]Therefore, 8 times the current population can be calculated thus :
[tex] 6.8 \times 10^{9} \times (8) = 54.4 \times 10^{9}[/tex]
Therefore, the population at the time would be [tex] 5.44 \times 10^{10}[/tex]
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If you start with 65 milligrams of Chromium 51, used to track red blood cells, which has a half-life of 27.7 days. How long will it take for 80% of the material to decay?
Answers
Answer:
Half-Life uses the formula N () = Noe # No = Initial Amount time h = length of half-life. Ifyou start with 65 milligrams of Chromium 51,used to track red blood cells, which has half-life of 27.7 days: How long will it take for 80% ofthe material to decay? t= (27.7) h5 (65) (h3) 4= (27.7) h; (05)
Step-by-step explanation:
For the given data it will take 8.69 days for 80% of the material to decay.
What is half-life?A radioactive substance's half-life is typically described as the amount of time it takes for one-half of its atoms to disintegrate or change into another substance.
It is given that, If you start with 65 milligrams of Chromium 51, used to track red blood cells, which has a half-life of 27.7 days.
N₀ = 65 milligrams
t1/2=27.7 days
N(t)=0.8(65 milligrams)=52 milligrams
[tex]N(t) = N_0(1/2)^ {\frac{t}{t_{1/2}} }[/tex]
Here,
N(t) is the amount of the substance remaining
N₀ is the initial substance amount
t is the time elapsed
t1/2 is the half-life
Substitute the given values,
[tex]N(t) = N_0(1/2)^ {\frac{t}{t_{1/2}} } \\\\ 52 = 65(1/2)^\frac{t}{27.7} \\\\ 52=65\left(\frac{1}{2}\right)^{\frac{t}{27.7}} \\\\ \frac{65\left(\frac{1}{2}\right)^{\frac{t}{27.7}}}{65}=\frac{52}{65} \\\\ \left(\frac{1}{2}\right)^{\frac{t}{27.7}}=\frac{4}{5} \\\\ \frac{t}{27.7}\ln \left(\frac{1}{2}\right)=\ln \left(\frac{4}{5}\right) \\\\ t =-\frac{27.7\ln \left(\frac{4}{5}\right)}{\ln \left(2\right)}[/tex]
[tex]t = 8.69 \ days[/tex]
Thus, for the given data it will take 8.69 days for 80% of the material to decay.
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Help please
Answer question 2 please
Answers
On the list of facts, the second fact says "A quarter of the nuts are walnuts.".
A quarter of 956 is => 239 <= .
NEED HELP!! THANK YOU
Answers
Answer:
Expression: -7 + 8f - 2b - f + 3b + 6
# of Terms: 6
Like Terms: 8f and f, -2b and 3b, and -7 and 6
Coefficients: 8, 1, -2, and 3
Constants: -7 and 6
Expression: -11x + 4 + 8x - 4 + 3x
# of Terms: 5
Like Terms: -11x, 8x, and 3x & 4 and -4
Coefficients: -11, 8, and 3
Constants: 4 and -4
Step-by-step explanation:
The coefficient is the number in front of the variable.
The variable is any letter that you may see in an expression.
Terms are the numbers and variables, that are separated by the different signs.
Like terms are the terms that share the same variable/exponent.
Constants are the terms without variables.
Hope this helps you :)
Sorry if it's somehow wrong.
Write 7% as a fraction or mixed number in simplest form
Answers
Answer:
7/100
Step-by-step explanation:
:)
Add or subtract. write fractions in simplest form.
-5/3 + 2 1/3
how do i do this problem? i will mark you brainliest. please help!
Answers
Answer:
2/3
Step-by-step explanation:
-5/3 + 2 1/3 =
= 2 1/3 - 5/3
= 2 1/3 - 1 2/3
= 1 4/3 - 1 2/3
= 2/3
Answer:
2/3
Step-by-step explanation:
First, change 2 1/3 into an improper fraction.
2 1/3 --> 7/3
Substitute that value back into the equation
-5/3 + 7/3
At this point, you can rewrite the equation into:
7/3 - 5/3
Since they have the same denominator, just subtract the numerator's values.
2/3
Marking as brainliest! Find the missing side
Answers
Answer:
The trick for these is finding out what makes the largest known value into the corresponding lower value. Then we use that number to find the missing side length based on the value we know.
1. The missing side length is 40.
We can find this by dividing 70 by 56 to get 1.25. We then multiply this by 32 to get our missing side length.
2. The missing side length is 91.
We can find this by dividing 130 by 30 to get 4.333(repeating decimal). We then multiply this by our known value (21) to get our answer of 91.
3. The missing side length is 21.
We can fid this by dividing 36 by 12 to get 3. Then we multiply this by 7 (our known value) to get our answer.
Step-by-step explanation:
hope this helps. . .<3
good luck! UwU
Evaluate ∫ y2dx + x dy along the following paths. (a) C = C1 is the line segment from (-13, -7) to (0, 6) (b) C = C2 is the arc of the parabola x = 36 - y2 from (-13, -7) to (0, 6).
Answers
a. Parameterize C₁ by
[tex](x(t),y(t)) = (1-t)(-13,-7) + t(0,6) = (-13+13t,-7+13t)[/tex]
with 0 ≤ t ≤ 1. Then both dx = 13 dt and dy = 13 dt, so that the line integral along C₁ is
[tex]\displaystyle \int_C y^2\,dx + x\,dy = \int_0^1 (-7+13t)^2(13\, dt) + (-13+13t)(13\,dt)[/tex]
[tex]\displaystyle \int_C y^2\,dx + x\,dy = 13 \int_0^1 (169t^2 - 169t + 36) \, dt[/tex]
[tex]\displaystyle \int_C y^2\,dx + x\,dy = 13 \left(\frac{169}3-\frac{169}2+36\right) = \boxed{\frac{611}6}[/tex]
b. Parameterize C₂ by
[tex](x(t),y(t)) = (36-t^2,t)[/tex]
with -7 ≤ t ≤ 6. Then dx = -2t dt and dy = dt, so the line integral is
[tex]\displaystyle \int_C y^2\,dx + x\,dy = \int_{-7}^6 t^2(-2t\,dt) + (36-t^2)\,dt[/tex]
[tex]\displaystyle \int_C y^2\,dx + x\,dy = \int_{-7}^6 (36-t^2-2t^3) \, dt[/tex]
[tex]\displaystyle \int_C y^2\,dx + x\,dy = \left(36\cdot6-\frac{6^3}3-\frac{6^4}2\right) - \left(36\cdot(-7)-\frac{(-7)^3}3-\frac{(-7)^4}2\right) = \boxed{\frac{5005}6}[/tex]
5. Use the point-slope formula to determine the equation of a line that passes through the points (1, 2) and (-2, 1).
Answers
Answer:
In point-slope form the equation is:
[tex]y - 2 = \binom{1}{3} \times (x - 1)[/tex]
Find the critical points, relative extrema, and saddle points of the function. (If an answer does not exist, enter DNE.) f(x, y) = 25 − (x − 5)2 − y2
Answers
Take the first partial derivatives of f(x, y):
∂f/∂x = -2 (x - 5) = 10 - 2x
∂f/∂y = -2y
The critical points occur where both derivatives are zero:
10 - 2x = 0 ===> x = 5
-2y = 0 ===> y = 0
So there is only critical point at (5, 0), which takes on a value of f(5, 0) = 25.
Compute the Hessian matrix for f :
[tex]H(x, y) = \begin{bmatrix}\frac{\partial^2f}{\partial x^2} & \frac{\partial^2f}{\partial x\partial y} \\ \frac{\partial^2f}{\partial y\partial x} & \frac{\partial^2f}{\partial y^2}\end{bmatrix} = \begin{bmatrix}-2&0\\0&-2\end{bmatrix}[/tex]
Since det(H(x, y)) = 4 > 0 for all x, y, the critical point (5, 0) is a relative minimum.
f has no saddle points.
What two numbers multiply to -15 and add to 8
Answers
Explaining
3x5=15
3+(5)=15
The length of a rectangular garden is 7 feet longer than its width. The garden's perimeter is 178 feet. Find the length of the garden.
Answers
Answer: 48
Step-by-step explanation:
l = w + 7
2w + 2l = 178
2w + 2(w + 7) = 178
2w + 2w + 14 = 178
4w = 164
w = 41
l = w + 7
l = 41 + 7
l = 48
Check
2L + 2W = 178
2(46.25) + 2W = 178
92.5 + 2W = 178
-92.5. -92.5
2W = 85.5
Divide by 2 on both sides
W = 42.75
2(46.25) + 2(42.75) = 178
92.5 + 85.5 = 178
178 = 178 ✅
Find the median for the following group of data items.
36, 33, 32, 31, 37, 34, 30, 32
Answers
Answer:
32.5
Step-by-step explanation:
order the numbers) 30, 31, 32, 32, 33, 34, 36, 37
cancel the numbers from each side to the middle) 32 and 33
add the values together and divide by two) [32+33] divide by 2=65/2=32.5
Claudia trabaja en una fábrica de carritos de supermercado, como criterio de calidad de la fábrica se establece que un carrito con mercancia que tenga una masa de 30kg no debe superar los 30N de fuerza de empuje para comenzar a moverse, ni los 20N para mantenerse en movimiento, cual es el valor de la aceleración que experimentara al soltarse?
Answers
El carro de mercancía experimenta una aceleración neta de 0.333 metros por segundo al cuadrado al soltarse.
En esta situación se requiere una fuerza de 30 N para alcanzar la fuerza estática máxima ([tex]f_{s}[/tex]), entonces la fuerza de fricción ([tex]f_{k}[/tex]) se reduce a 20 N mientras se encuentre en movimiento. Si consideramos que la fuerza externa de 30 N se mantiene durante el fenómeno físico, entonces tenemos que la aceleración neta ([tex]a[/tex]), en metros por segundo al cuadrado, experimentada por el carrito de mercancía es determinada a partir de las leyes de Newton:
[tex]a = \frac{F-f_{k}}{m}[/tex] (1)
Donde [tex]m[/tex] es la masa del carrito de mercancía, en kilogramos.
Si sabemos que [tex]F = 30\,N[/tex], [tex]f_{k} = 20\,N[/tex] and [tex]m = 30\,kg[/tex], entonces la aceleración neta del carro de mercancías es:
[tex]a = \frac{30\,N-20\,N}{30\,kg}[/tex]
[tex]a = 0.333\,\frac{m}{s^{2}}[/tex]
El carro de mercancía experimenta una aceleración neta de 0.333 metros por segundo al cuadrado al soltarse.
Invitamos a consultar esta pregunta sobre la fricción seca: https://brainly.com/question/19115001
The ratio of boys and girls are 2:5. If the total number of students in school are 350, find the number of girls.
Answers
Answer:
250 girls
Step-by-step explanation:
Add the ratio together (2+5=7), then do 350÷7=50
50 is one part of the ratio so to find how many girls, you would do 50x5=250
Solve the equation.
-9x + 1 = -x + 17
Answers
Step-by-step explanation:
-9x + 1 = -x + 17
collect like terms
-9x + x = 17-1
-8x = 16
divide both sides by -8
-8x/-8 = 16/8
x = 2
Lauren spends her allowance $50 a month on make up and CDs. She spends $10 more a month on CDs than she does on make up. How much money does she spend every month on each product
Answers
Answer:
$30 on CDs
$20 on Makeup
hope it helps
Step-by-step explanation:
The money spent on each product is $20 and $30 respectively.
How to solve a linear equation?A linear equation can be solved by equating the LHS and RHS of the equation following some basic rules such as by adding or subtracting the same numbers on both sides and similarly, doing division and multiplication with the same numbers.
Given that,
The money spent by Lauren on make up and CDs is $50.
Suppose the money spent on CDs be x.
Then, the money spent on make up is x + 10.
As per the question the following equation can be formed,
x + x + 10 = 50
=> 2x + 10 = 50
=> 2x = 40
=> x = 20
Thus, money spent on make up is 20 + 10 = 30 dollars.
Hence, the money spent on CDs and make up is $20 and $30 respectively.
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6 Cyclist A travels 55 km in 2 hours and 20 minutes.
Cyclist B travels 135 km in 5 hours and 36 minutes.
Which cyclist is travelling faster?
Answers
cyclist a speed is d = v × t
so you can find velocity of a and b.
then compare them both.
[tex]2 {}^{3} \times 2 - {}^{3} [/tex]
I need answers
Answers
Step by step
2^3 x 2 - 3=
2 x2 x2=8
8 x2=16
16-3=13
If f(x) = 4x + 3x2 + 1, then what is the remainder when f(x)
is divided by X -2?
Answers
Answer:
remainder = 21
Step-by-step explanation:
If f(x) is divided by (x - h) then the remainder is f(h)
Here f(x) is divided by (x - 2) with h = 2 , then remainder is
f(2) = 4(2) + 3(2)² + 1 = 8 + 3(4) + 1 = 8 + 12 + 1 = 21
A coach divided his team into two groups of equal size.
.
of the first group drinks at least 2 glasses of water a day
• 75% of the second group drinks at least 2 glasses of water a day.
What fraction of the team drinks at least 2 glasses of water a day?
Answers
Applying the percentages, and considering that 70% of the first group drinks at least 2 glasses of water a day, it is found that 0.725 = 72.5% of the team drinks at least 2 glasses of water a day.
The team is divided into two equal groups, hence, each represents 50%.
The percentages associated with drinking at least 2 glasses of water a day is:
70% of 50%(first group)75% of 50%(second group)Hence, applying the weighed percentage, the total percentage is:
[tex]T = 0.7(0.5) + 0.75(0.5) = 0.725[/tex]
0.725 = 72.5% of the team drinks at least 2 glasses of water a day.
A similar problem is given at https://brainly.com/question/1517088
Help no links Pleaseeeeeee
Answers
Answer:
[tex]\huge\boxed{z=6;\ x=12.5}[/tex]
Step-by-step explanation:
If two figures are similar, then corresponding sides are in proportion.
Therefore:
[tex]\dfrac{z}{15}=\dfrac{4}{10}\qquad|\text{cross multiply}\\\\10z=(15)(4)\\\\10z=60\qquad|\text{divide both sides by 10}\\\\\boxed{z=6}[/tex]
[tex]\dfrac{x}{5}=\dfrac{10}{4}\qquad|\text{cross multiply}\\\\4x=(5)(10)\\\\4x=50\qquad|\text{divide both sides by 4}\\\\x=\dfrac{50}{4}\\\\\boxed{x=12.5}[/tex]
14 out of the 70 people in a company meeting were managers. What percentage of the
meeting attendees were managers?
Write your answer using a percent sign (%).
Answers
Answer:
20%Step-by-step explanation:
14 out of 70 given as percentage:
14/70*100% = 20%Lets see
14/70(100)1/5(100)20%$4800 is 60% of what number?
Answers
Answer:
8000
Step-by-step explanation:
100 points if you answer - if it's correct ill give brainliest
(01.04 MC)The elevation of city A is 60 feet above sea level; the elevation of city C is 12 feet above sea level. The elevation of city D is 1 over 2 of the elevation of city C.
Part A: Write an expression to represent the elevation, in feet, of city D. (5 points)
Part B: Solve the expression and explain why the answer is negative or positive. (5 points)
Answers
Answer & Step-by-step explanation:
A = 60 ft
C = 12
D = 1/2 of C
1/2 of 12 = 6
Part A:
e = 6ft
Part B:
It's positive because it is above sea level
Answer:
Step-by-step explanation:
gg I got the points
Are the expressions 0.85b-0.2b and 0.65b equivalent?
Answers
Hello!
0.85b-0.2b
0.65b
0.65b=0.65b
So these expressions are equivalent.
Hope it helps!
~Just a determined gal
#CarryOnLearning
[tex]MysteriousNature[/tex]
Please helpppp I will mark you branliest pleaseee
Answers
Answer:
no
Step-by-step explanation:
the ratios shown in this table are not proportionate. You will also never get (0,0) in this table.
Jack’s truck had used 30 gallons of fuel from a 50 gallon tank. What percentage was used? *
Answers
anwers: is 15 because I did 30 percent of 50
Help I’ll mark you brainlist
Answers
Answer:
24.0
Step-by-step explanation:
do 34sin(45) to solve for x
Could I get help…………
Answers
Answer:
B
Step-by-step explanation:
HOPE IT HELPS <3
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