Identify the independent /manipulated variable

Answers

Answer 1

Answer:

independent- test variable

manipulated - outcome variable; if needed, there could be changes.

Explanation:

knowledge


Related Questions

As you move from left to right in the third period of the periodic table…
A. Each group loses an outer electron
B. Each group gains an outer electron
C. Each group gains a neutron
D. The number of outer electrons remains constant across the period

Answers

Answer:

B

Explanation:

2.8.1 Na

2.8.2 Mg

and so on and so forth

If 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate, determine the molarity of the lead (II) nitrate solution. Note: First write the balance equation between potassium iodide and lead (II) nitrate.

Answers

The molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.

How to calculate molarity?

The molarity of a solution can be calculated using the following formula:

CaVa/CbVb = na/nb

Where;

Ca = concentration of acidCb = concentration of baseVa = volume of acidVb = volume of basena = number of moles of acidnb = number of moles of base

The balanced equation of the reaction is as follows:

Pb(NO3)2 (aq) + 2KI (aq) → 2KNO3 (aq) + PbI2 (s)

22 × 2/18 × Cb = 2/1

44/18Cb = 2

Cb = 44 ÷ 36

Cb = 1.2M

Therefore, the molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.

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what is safe storage of produced materials exlain long ​

Answers

Answer:

Stacking storage sacks/ bags by interlocking, and placing heavier object on lower shelves.

Explanation:

Not sure what you meant exactly, but this is my best guess.

Identifying My Interests
List five activities that you enjoy

Answers

Answer:

BIKE riding, Watching yt, Hanging with friends, Food,Dogs

How much heat is required to raise the temperature of 1,500 g of water from 25°C to 52°C? The specific heat of water is 4.184 J/g-oC.

Answers

Mass=1500g=m∆T=52-25=27°CSpecific heat capacity=c=4.184J/g°C

Apply thermodynamics

[tex]\\ \rm\rightarrowtail Q=mc\delta T[/tex]

Q is heat

[tex]\\ \rm\rightarrowtail Q=1500(4.184)(27)[/tex]

[tex]\\ \rm\rightarrowtail Q=169452J[/tex]

why are hydrocarbons insoluble in water

Answers

Answer:

Hydrocarbons are insoluble in water because they are non-polar compounds while water is a polar solvent. By principle, like dissolves like. Nonpolar solvents dissolve nonpolar solutes and polar solvents dissolve polar solutes.

Explanation:

please brainliest me

hope it helps

Hydrocarbons are insoluble in water because :-

1)Hydrocarbons are nonpolar whereas water is polar. (like dissolves like).

2) Hydrocarbons and water do not exhibit appropriate solvent-solute interactions. Hydrocarbons only form very weak dispersion forces whereas water produces strong polar hydrogen bonding interactions.

Explanation:

Hope it helps you!!


Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, how many
moles of ozone would be produced?

Answers

337.92 moles of Ozone will be produced

1 Oxygen atom is 8 g

1 mole of ozone, O3 = 8 * 3 = 24 g

7.92 * 1024 = 8110.08 g

1 mole = 24 g

? moles = 8110.08 g

? = 337.92 moles


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Hope it helps

Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, then 337.92 moles of ozone will produce.

What is molecular formula?

Molecular formula is defined as an expression that defines a number of atoms of each element in one molecule of a compound.

It can also be defined as a chemical formula that gives the total number of atoms of each elements in each molecules of a substance.

Ozone is defined as a highly reactive gas composed of three oxygen atoms and form a layer above the earth surface called as ozone layer.

1 oxygen atom = 8 g

1 mole of ozone = 8 x 3 = 24 g

7.92 x 10²⁴ = 8110.08 g

24 g = 1 mole

So, 8110.08 g = 337.92 moles

Thus, Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, then 337.92 moles of ozone will produce.

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#SPJ2

When 20.4g of sodium metal are mixed with chlorine gas, are 52.0 g of sodium chloride
produced? Explain (use calculations to prove your answer.
.ves or no
-with amounts shown)

Answers

Answer: True

Explanation:

[tex]\mathrm{The\ balanced \ chemical \ equation\ is\ :}\\$2 \mathrm{Na}{(s)}+\mathrm{Cl}_{2}(g) \rightarrow 2 \mathrm{NaCl}(s)[/tex]

For Na

[tex]\\$Given mass $=20.4 \mathrm{~g}$ \ \ Molecular mass $=23 \mathrm{~g}\ \ $Number of moles $=\frac{\text { Given mass }}{\text { Molecular mass }}$$$\begin{aligned}&=\frac{20.4}{23} \\&=0.887 \text { moles }\end{aligned}$$Stoichiometric ratio of $\mathrm{Na}$ is same as that of $\mathrm{NaCl}$ i.e., $1: 1$.$\therefore$ Moles of $\mathrm{NaCl}=0.887$ motes[/tex]

For NaCl

[tex]$$\\\begin{aligned}\text { Molecular mass } &=23+35.5 \\&=58.5 \mathrm{~g}\end{aligned}$$[/tex]

[tex]\begin{aligned}\\& $\therefore$ Mass of $\mathrm{NaCl}$ produced will be=\text { No.of moles } \times \text { Molecular mass } \\&=0.887 \times 58.5 \\&=51.9 \\&\simeq 52 \mathrm{~g} \quad\end{aligned}$$[/tex]

Therefore, it is true that when 20.4g of sodium metal are mixed with chlorine gas, 52.0 g of sodium chloride is produced

Explanation:

The answer: True

I explained the answer to your question in the submitted photo

A chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves. What is the solute in this scenario?

Answers

Answer:

The answer is the Sodium Chloride.

Explanation:

A solute is the minor component in a solution, dissolved in the solvent, and the sodium is being dissolved in water ( or the solvent).

A chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves, in this scenario sodium chloride is solute.

What are solute?

Those substance which are present in the solution relatively in less amount is known as solute.

In the question given that 36 grams of sodium chloride is added in the 200 grams of water. From this it is clear that sodium chloride is a solute and water is a solvent, which additionally makes a solution.

Hence, sodium chloride is a solute.

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If a metal reacts violently with water, in which group is it likely to be found?

Answers

Answer:

Alkali metals (Li, Na, K, Rb, Cs, and Fr)

Explanation:

Answer:

Group 1

Explanation:

Alkali metals such as (Lithium, Sodium, Rubidium, Francium, Cesium, etc.) react violently with waterThey are termed "alkali" due to their nature of forming hydroxides on reacting with water

write an equation to show the effect of heat on the nitrate of silver​

Answers

Answer:

2AgNO³(l) → 2Ag(s) + O²(g) + 2NO²(g)

Explanation:

I used powers ³,²,²

So change them to be down

When Thomas Edison first sold electricity, he used zinc coulometers to measure charge consumption. (In a coulometer the cathode is weighed before a current is passed through it, and then again after the passage of current. The weight increase is proportional to the amount of current that flows through the cathode.) If the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, how much charge had passed through it

Answers

When the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

Ionization of zinc

The zinc metal will ionize as shown below;

Zn²₊ + 2e⁻ → Zn

The molar mass of zinc metal is given as 65.38 g/mol

Amount of charge passed through 65.38 g/mol

Amount of charge that will deposite the given mass of zinc is calculated as follows;

e⁻ = 96500 C

2e⁻ = 2 x 96500 C = 193,000 C

Amount of charge passed through 7.85 g

65.38 g -------> 193,000 C

7.85 g -----------> ?

= (7.85 x 193,000)/(65.38)

= 23,173 C

Thus, when the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

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• Calculate the entropy change when 1.00 mol of
water at 0°C freezes to form ice. (AHfus for water
is +6.02 kJmoll)
1

Answers

Answer:

the enthalpy change of this is 5.02mol

Which of the following mainly drives surface runoff?
A. magnetism
B. gravity
C. electricity
D. thermal energy​

Answers

I think its D. I hope this helped
The answer is Either C or D. Sorry if I’m wrong!

Calculate the pOH for a solution with a hydroxide ion, (OH-) of concentration of 6.49 X 10-11 M.

Calculate the pH.



Note: the answers should have three significant figures



The pOH is: Blank 1

The pH is: Blank 2

Answers

Answer:

Calculate the pOH for a solution with a hydroxide ion, (OH-) of concentration of 6.49 X 10-11 M.

Calculate the pH.

Note: the answers should have three significant figures

The pOH is: Blank 1

The pH is: Blank 2

Explanation:

How much 1.75 M H3PO4, in mL, would you need to add to 50.00 mL of 3.50 M Ca(OH)2 in order to neutralize the solution

Answers

The volume of the 1.75 M H₃PO₄ solution required to neutralize 50 ml of 3.5 M Ca(OH)₂ solution is 66.67 mL

Balanced equation

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

The mole ratio of the acid, H₃PO₄ (nA) = 2The mole ratio of the base, Ca(OH)₂ (nB) = 3

How to determine the volume of H₃PO₄ Molarity of acid, H₃PO₄ (Ma) = 1.75 MVolume of base, Ca(OH)₂ (Vb) = 50 mLMolarity of base, Ca(OH)₂ (Mb) = 3.5 MVolume of acid, H₃PO₄ (Va) =?

MaVa / MbVb = nA / nB

(1.75 × Va) / (3.5 × 50) = 2/3

(1.75 × Va) / 175= 2/3

Cross multiply

1.75 × 3 × Va  = 175 × 2

5.25 × Va = 350

Divide both side by 5.25

Va = 350 / 5.25

Va = 66.67 mL

Thus, the volume of the H₃PO₄ solution needed is 66.67 mL

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based on the electron configuration of the two atoms predict the ratio of metal cationic (+) atom to nonmetal anionic (-) atom in the compound. hydrogen and fluorine

Answers

The  metal cationic (+) atom to nonmetal anionic (-) atom ratio in the compound formed between hydrogen and fluorine is 1:1.

What is a compound?

A compound is madeup of two or more atoms that are chemically combined together. In this case, we have the atoms; hydrogen and fluorine.

The electronic configuration of the atoms  are not shown here but the  metal cationic (+) atom to nonmetal anionic (-) atom ratio in the compound formed between hydrogen and fluorine is 1:1.

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According to Bohr's Model, which one is correct about a transition from n=2 to n=1 in a hydrogen atom?

Answers

When an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.

What happen in transition from n= to n=1?

During transition from n=2 to n=1 in a hydrogen atom, the electron emits energy in the form of photon. We know that when electron absorb energy, it moves from lower level to higher level and vice versa.

So we can conclude that when an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.

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2. The gas from an erupting volcano had the following composition: 494 torr CO₂, 0.054 atm HCI, 0.028 atm HF, 0.017 atm 50₂. 0.76 mmHg H₂5, and H₂. If the total pressure is 1.00 atm, what is the partial pressure of H₂?

3. When a 10L balloon is heated from 22.0°C to 97.0°C, to what volume does it inflate?

4. Calculate the pressure of a gas in a 205 mL container at 0.0°C when the container was initially at a volume of 300.0 mL and a pressure of 1.05 atm

Answers

Answer: The gas from an erupting volcano had the following composition: 494 torr CO₂, 0.054 atm HCI, 0.028 atm HF, 0.017 atm 50₂. 0.76 mmHg H₂5, and H₂. If the total pressure is 1.00 atm, what is the partial pressure of H₂?

Explanation:

Referring to your benzene model, explain why there is no directionality for a substituent group bonded directly to a benzene ring.

Answers

The benzene molecule is flat and planar. As a result of this planarity, the substituent is also in the plane of molecule and do not show any directionality.

What is the benzene molecule

The benzene molecule is a flat and planar molecule owing to the fact that all the bond lengths and bond angles in the molecules are the same. This results from resonance in the molecule.

Hence, owing to the planarity of the molecule, the substituent is also in the plane of molecule and do not show any directionality.

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Suppose you are provided with a 35.83 g sample of potassium chlorate to perform this experiment. What is the mass of potassium chloride you expect to release upon heating?

Answers

For a 35.83 g sample of potassium chlorate,  the mass of potassium chloride is mathematically given as

M Kcl=21.62g

What is the mass of potassium chloride you expect to release upon heating?

Generally, the equation for the Chemical Reaction  is mathematically given as

2KClO_3----->2KCl+2O_2

Therefore

[tex]Mole of KCl=\frac{35.57}{122.55}[/tex]

Mole of KCl=0.29mol

Mass of Kcl=0.29*74.55

Mass of Kcl=21.62g

In conclusion, Mass of Kcl

M Kcl=21.62g

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Ignoring the contributions of wind, a baseball would be expected to travel farther in warm, humid air because: Select one: a. water vapor helps to lift the baseball even higher. b. water vapor sticks to baseballs. c. water vapor is less dense than dry air. d. none of these

Answers

Answer:

water vapor is less dense than dry air

How many grams of Na2S will be produced if you react 35.0g sodium

Answers

If you don’t mind can u add the picture?? It helps me answer the question better ;)

What is the first principle energy level called

Answers

Answer is s orbital. Hopes this helps

Answer:

S orbital

Explanation:

no explanation, just a name you memorize

When a sodium atom becomes an ion, the size of the atom
A
decreases by losing an electron,
B
decreases by gaining an electron,
с
increases by losing an electron,
D
increases by gaining an electron,

Answers

decreases by losing an electron

Sodium has an electron configuration of 2-8-1. Since sodium is a metal, it loses that one electron and becomes a positive ion. Since it is losing an electron, it is decreasing in size.

3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0
mL water initially. What is the density of this unknown metal if the final reading from
the graduate cylinder was 65.0 mL?

Answers

For 3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0mL water initially,  the density of this unknown meta  is mathematically given as

D= 0.23 g/ml

What is the density of this unknown metal if the final reading from the graduate cylinder was 65.0 mL?

Generally, the equation for the Volume of water  is mathematically given as

Vw= Volume of water after metal addition - Volume of water initial

Therefore

Vw = 65 ml - 50 ml

Vw= 15 ml

In conclusion,

D= Mass of metal / Volume

D= 3.5 / 15

D= 0.23 g/ml

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What is the isotope notation of selenium

Answers

Answer:

It is Se.

hope this helps.

Determine which reaction has the highest activation energy.
A. Burning charcoal
B. Melting ice
C. Combusting gasoline
D. Reacting metal and acid

Answers

Answer:

A.

Explanation:

Which of the compounds below will dissociate in water? Check all that apply.
Ba(NO3)2
CaSO4
CO2
H2CO3
Mg3(PO4)2
those numbers are subscripts

Answers

An ionic compound does dissociate to a large extent in water. The compound that will completely dissociate in water here is Ba(NO3)2.

What is a soluble compound?

A soluble compound is a compound that can dissociate to a large extent in water. Not all compounds are soluble in water. Only ionic compounds are soluble in water.

The compound that  would dissolve in water among the list of compounds here is Ba(NO3)2.

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Answer:

A) Ba(NO3)2

B) CaSO4

C) CO2

D) H2CO3

E) Mg3(PO4)2

Explanation:

Wish I could give a good explanation, but I am still learning myself. Try searching up a video explaining this concept!

A buffer was prepared containing 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). The Ka of formic acid is 1.7 x 10-4. What will be the pH after 0.010 mol of NaOH(s) is added to 100.0 mL of the buffer

Answers

For a buffer that was prepared contain 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). the pH is mathematically given as

pH=3.95

What is the pH after 0.010 mol of NaOH(s) is added to 100.0 mL of the buffer?

Generally, the equation for the Hendersons equation   is mathematically given as


pH=pKa+log(SALT)/(ACID)

Where

moles of  (NaCOOH)=100*0.05/1000

moles of  (NaCOOH)=0.05moles

and  formic acid

moles of formic acid=100*0.05/1000

moles of  formic acid=0.05moles

Therefore

pKa=-logka

pKa=1.4*10*3.77

pH=3.77+log{0.06/0.04}

pH=3.95

In conclusion, the pH is

pH=3.95

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