if 1.00 kg of zn reacted with excess sulfur, how much energy would be released? enter your answer as a positive value.

The amount of silver required if the temperature of the silver was increased by 7.5°C is 170.94 g.

To calculate the amount of silver required if 2.5 kJ of energy is absorbed and the temperature of the silver increases by 7.5°C, we can use the formula:

q = m x c x ΔT

where

q = amount of energy absorbed (kJ)

m = mass of silver (g)

c = specific heat of silver (J/g°C)

ΔT = change in temperature (°C)

Converting the given values to the required units, we have:

q = 2.5 kJ = 2500 J

c = 0.2330 J/g°C

ΔT = 7.5°C

Plugging these values into the formula, we get:

2500 = m x 0.2330 x 7.5m = 170.94 g

Therefore, 170.94 g of silver is required if 2.5 kJ of energy is absorbed and the temperature of the silver increases by 7.5°C.

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Answer:

PCI3(g) + Cl2(g) ⟶ PCI3(Cl)(g) , K = 6.5At a given moment in time, a 1.00 L solid response vessel has 1.5 mol of PCI3(a), 1.0 mol of Cl2[g), and 2.5 mol of PCI3(g). The estimated pressure in the response vessel will alter is The pressure will decrease because Q < K. Answer.b

Explanation:

For the given reaction:PCI3(g) + Cl2(g) ⟶ PCI3(Cl)(g)K = 6.5.Here, the number of moles of reactants and products is given as:

Initial number of moles:

PCI3 = 1.5 molCl2 = 1.0 molPCI3(g) = 2.5 mol

We can calculate the initial partial pressures of the reactants and product as follows:

PPCI3 = (1.5 mol / 4 mol) x Ptotal = 0.375Ptotal

PCl2 = (1.0 mol / 4 mol) x Ptotal = 0.25Ptotal

PPCI3(Cl) = 0 moles / 4 moles x Ptotal = 0

So, Ptotal = 1 atm (given). Therefore, PPCI3 = 0.375 atmPCl2 = 0.25 atm

PPCI3(Cl) = 0 atm

The reaction quotient, Qc is given by:Qc = [PCI3(Cl)] / [PCI3] [Cl2]

On substituting the initial concentrations, we get:

Qc = (0) / (1.5) (1) = 0

The reaction quotient, Qc is less than the equilibrium constant, Kc. Therefore, the reaction will proceed in the forward direction to reach equilibrium. As the reaction proceeds forward, the concentration of PCI3 will decrease and the concentration of PCI3(Cl) will increase.

As a result, the total number of moles of gas in the container will decrease and the pressure will decrease.The equilibrium concentration of PCI3(Cl) will be determined by the value of the equilibrium constant, Kc. Since the value of Kc is quite large, the concentration of PCI3(Cl) will be much larger than the initial concentration of PCI3.

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The property of the alkaline earth metals that is not accurate among the given options is (d) They are gases.

Alkaline earth metals are in Group 2 on the periodic table, and they include six chemical elements:

beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra).

The properties of alkaline earth metals are:

React with oxygen in a 1:1 ratio: Alkaline earth metals react with oxygen to create oxides, which contain one oxygen atom per metal atom. These metals are highly reactive, and they burn brightly when exposed to air.

2Mg + O2 → 2MgO

They are shiny: These metals are shiny in appearance, and their surfaces have a metallic lustre.

Conduct electricity: Alkaline earth metals are good conductors of electricity, which makes them essential in electrical engineering applications. They also have high melting points and low densities.

They are gases: This is not an accurate property of alkaline earth metals. These metals are in a solid state at room temperature and atmospheric pressure. Barium and radium are radioactive, and they decay to produce gases that can be highly dangerous to human health.

Hence, Option D they are gases is correct.

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a) The maximum amount of work (AG) from/for this reaction when [A] = 0.96 M is -4.00 kJ (atol=1e-08).
b) When AG = –3.80 kJ, the concentration of B is 0.18 M (rtol=0.03, atol=1e-08).
c) When AG = -8.00 kJ, the reaction quotient (Q) is 0.036 (rtol=0.03, atol=1e-08).
d) At equilibrium, when [A] = 0.39 M and the temperature is 165.5 °C, the enthalpy (AH°) of the reaction is -11.10 kJ/mol (rtol=0.02, atol=1e-08) and the entropy (AS°) of the reaction is -0.53 J/mol.K (rtol=0.03, atol=1e-08).

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The given compound can be prepared using the Diels-Alder reaction. The two different ways to prepare the given compound by the Diels-Alder reaction are as follows:

Preferred Pathway A: The first step is the preparation of cyclopentadiene. It is made by the deprotonation of cyclopentadiene using sodium hydroxide. The next step is the preparation of maleic anhydride. It is prepared by heating maleic acid. Now, the Diels-Alder reaction is carried out between the cyclopentadiene and maleic anhydride. This results in the formation of the given compound.

Less Reactive Pathway B: The first step is the preparation of a less reactive diene. Here, the less reactive diene is furan. It is obtained by the dehydration of furfural. The next step is the preparation of a less reactive dienophile. Here, the less reactive dienophile is ethyl vinyl ether. It is prepared by the reaction of ethanol and acetylene. Now, the Diels-Alder reaction is carried out between furan and ethyl vinyl ether. This results in the formation of the given compound.

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A monoprotic acid only has one acidic proton per molecule, but a polyprotic acid can donate numerous protons per molecule and possesses more than one acidic proton.

The capacity of an acid to contribute protons (H+ ions) determines its strength. Each acidic proton in a polyprotic acid becomes tougher to remove as each donation results in a greater loss of negative charge. Hence, polyprotic acids are susceptible to partial or whole dissociation reactions and can have a variety of dissociation constants (Ka values). Phosphoric acid (H3PO4) and sulfuric acid are examples of polyprotic acids (H2SO4).

Monoprotic acids, on the other hand, only have one acidic hydrogen atom per molecule, which can give one proton. For monoprotic acids, the dissociation reaction is complete and can be described by a single dissociation constant (Ka). Acetic acid and hydrochloric acid (HCl) are examples of monoprotic acids (CH3COOH).

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An engine using gasoline to power a car and mixing glue and laundry powder to create putty are both examples of chemical reactions.

Gasoline is considered an energy source due to its ability to release stored chemical energy in the form of heat and mechanical work when it is burned in an engine. When gasoline is ignited in an engine, the chemical energy stored in its molecular bonds is released, causing a rapid combustion reaction that generates heat and expanding gases that push the pistons and create mechanical work.

The energy content of gasoline is typically measured in units of joules or British thermal units (BTUs), which are used to quantify the amount of energy released during combustion. Gasoline is a widely used and important energy source, but its combustion also produces harmful emissions that contribute to air pollution and climate change.

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When sodium reacts with water, sodium hydroxide and hydrogen are produced. The balanced equation for this reaction is 2 Na (s) + 2 H2O (l) → 2 NaOH (aq) + H2 (g)

Sodium is an alkali metal that reacts vigorously with water, releasing hydrogen gas and forming an aqueous solution of sodium hydroxide.

The reaction between sodium and water is a highly exothermic reaction, meaning that it releases a large amount of heat energy.

The balanced chemical equation for this reaction is as follows:2 Na (s) + 2 H2O (l) → 2 NaOH (aq) + H2 (g)

This equation can be interpreted in several ways. One interpretation is that two moles of sodium react with two moles of water to produce two moles of sodium hydroxide and one mole of hydrogen gas.

Another interpretation is that the mass of the reactants is equal to the mass of the products, since this is a balanced equation.

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Approximately 11.8 grams of KCl will dissolve in 25 grams of water at 80°C.

Potassium chloride (KCl) is a chemical compound that consists of the elements potassium and chlorine.

The solubility of potassium chloride (KCl) in water depends on the temperature of the solution. At 80°C, the solubility of KCl in water is approximately 47.2 g/100 g of water.

To determine how much KCl will dissolve in 25 grams of water at 80°C, we can use the following equation:

mass of KCl = solubility of KCl x mass of water

mass of KCl = 47.2 g/100 g x 25 g

mass of KCl = 11.8 g

Therefore, approximately 11.8 grams of KCl will dissolve in 25 grams of water at 80°C.

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The CNO cycle and the proton-proton chain don't release the same amount of energy per He nucleus produced.

Let's understand this in detail:

1. The CNO cycle produces more energy than the proton-proton chain per He nucleus produced. The proton-proton chain and CNO cycle produce energy by nuclear fusion in the sun's core.

2. In the core of the Sun, the proton-proton chain occurs. It converts four hydrogen nuclei (protons) into one helium nucleus via a series of nuclear reactions. This reaction liberates a significant amount of energy through gamma rays and neutrinos.

3. The CNO cycle also takes four hydrogen nuclei, producing one helium nucleus. The key difference between these two processes is the method in which helium is produced.

4. In the proton-proton chain, two protons combine to form deuterium. This then combines with another proton to form helium-3, and two helium-3 nuclei combine to form helium-4.

5. In the CNO cycle, hydrogen is fused with carbon, nitrogen, and oxygen isotopes to create helium. The CNO cycle releases more energy than the proton-proton chain per He nucleus produced because it has more intermediate steps.

5. The CNO cycle requires more heat and pressure to function because it involves carbon, nitrogen, and oxygen isotopes, which are heavier elements. The proton-proton chain is simpler because it only involves hydrogen and doesn't require as much energy.

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The complete ionic equation for the reaction that occurs when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed is as follows: 2 Li+(aq) + S2-(aq) + Cu2+(aq) + 2 NO3-(aq) → CuS(s) + 2 Li+(aq) + 2 NO3-(aq)

It is important to write the complete ionic equation when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed. The reaction of lithium sulfide with copper (II) nitrate is a double displacement reaction. Lithium sulfide reacts with copper (II) nitrate to form copper sulfide and lithium nitrate.

The balanced chemical equation for the reaction is given as follows:Li2S(aq) + Cu(NO3)2(aq) → CuS(s) + 2 LiNO3(aq)The complete ionic equation can be written by representing all the ions in the aqueous solutions as dissociated ions.

Thus, the complete ionic equation for the reaction that occurs when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed is as follows:2 Li+(aq) + S2-(aq) + Cu2+(aq) + 2 NO3-(aq) → CuS(s) + 2 Li+(aq) + 2 NO3-(aq.

)In the above equation, the lithium and nitrate ions do not take part in the reaction and are present in the same form in the reactant and product side. Hence, they are called spectator ions.

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The concentration (m/m percent) of the solution is 11.53%.

To find out the concentration (m/m percent) of the solution, first we need to calculate the mass of the solution. Then we can calculate the concentration (m/m percent) of the solution.

Given the mass of Potassium chloride (KCl) = 10.50 g and mass of Water (H2O) = 80.60 g

Therefore, the total mass of the solution = 10.50 g + 80.60 g = 91.10 g

Now, we can calculate the concentration (m/m percent) of the solution using the following formula:

Concentration (m/m percent) = (mass of solute / mass of solution) x 100%

Concentration (m/m percent) = (10.50 g / 91.10 g) x 100% = 11.53%

Therefore, the solution has a concentration in (m/m percent) of 11.53%.

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The change that is useful for the environment and living things is called "positive environmental change."

Positive environmental change refers to any alteration or modification in the environment that improves or benefits living organisms' well-being. Examples of positive environmental changes include reducing pollution, conserving water, using renewable energy sources, and recycling waste products. Positive environmental change is essential to ensure a sustainable future and to maintain the planet's biodiversity.

It can be achieved by implementing new policies, practices, and technologies that promote sustainable development and reduce the negative impact on the environment. Positive environmental change can also help to address climate change and other environmental challenges faced by humanity. By taking positive steps to protect the environment, we can ensure that future generations can also enjoy a healthy, prosperous, and sustainable planet.

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Answer:

a) Vmax= 964,320,000,000,000 molecules/m3·sec

b) Vo=0.089 mol/L·sec

c) catalytic efficiency of fumarase=1.6 × 10^8 M-1 s-1

Explanation:

(a) To calculate the Vmax, we use the following formula:

Vmax = kcat × [ET] ,Where [ET] is the total enzyme concentration.

The given fumarase enzyme concentration = 2nM = 2 × 10^9 molecules/m3

[ET] = 2nM × 6.02 × 10^23 molecules/mole× 1mole/10^9nM = 1.2044 × 10^15 molecules/m3

Vmax = kcat × [ET]Vmax = 800/sec × 1.2044 × 10^15 molecules/m3= 964,320,000,000,000 molecules/m3·sec

(b) To calculate the Vo when fumarate is 47.5 μM, we use the following formula:

Vo = Vmax × [S]Km + [S]

Where [S] is the concentration of the substrate, fumarate.

Vmax = 964,320,000,000,000 molecules/m3·sec[S] = 47.5μM = 47.5 × 10^-6 mol/L

Km = 5uM = 5 × 10^-6 mol/L

Vo = Vmax × [S]Km + [S]Vo = (964,320,000,000,000 molecules/m3·sec × 47.5 × 10^-6 mol/L

)5 × 10^-6 mol/L + 47.5 × 10^-6 mol/L

Vo = 0.089 mol/L·sec

(c) The catalytic efficiency of fumarase is given by the ratio of kcat to the Km of the substrate catalyzed by an enzyme.

Catalytic efficiency = kcatKm= 800/sec5uM= 1.6 × 10^8 M-1 s-1

Therefore, the catalytic efficiency of fumarase is 1.6 × 10^8 M-1 s-1.An enzyme with a high catalytic efficiency has a high turnover number (kcat) and low substrate concentration (Km).

The enzyme fumarase has a very high catalytic efficiency of 1.6 × 10^8 M-1 s-1, indicating that it can catalyze the reaction with a high rate even at a low concentration of the substrate.

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The role of sulfuric acid in the synthesis of pyrylium bisulfate is to create a favorable reaction condition by promoting protonation.

Pyrylium bisulfate is an organic compound with the formula C5H5SO4H. It is a white crystalline powder that has an interesting history in the area of color chemistry. The compound was first synthesized by Henry Gilman and Edith Roberts in 1937.
Pyrylium bisulfate is synthesized through the reaction of pyridine with sulfuric acid. In the reaction, the pyridine molecule reacts with a sulfuric acid molecule to produce pyrylium bisulfate as a result. The chemical reaction can be expressed as follows:
C5H5N + H2SO4 → C5H5SO4H + H2O
Sulfuric acid plays an important role in this reaction as it acts as a catalyst. The catalyst helps to promote protonation of the pyridine molecule. This protonation is essential to the reaction because it allows the pyridine to react with the sulfuric acid. When the pyridine is protonated, it is more reactive and can easily react with the sulfuric acid.
The reaction between pyridine and sulfuric acid results in the formation of a pyridinium cation. This cation then reacts with another sulfuric acid molecule to produce pyrylium bisulfate. The process is repeated until the desired amount of pyrylium bisulfate is formed.
In summary, the role of sulfuric acid in the synthesis of pyrylium bisulfate is to create a favorable reaction condition by promoting protonation. This protonation allows the pyridine molecule to react with sulfuric acid and form pyrylium bisulfate as a result.

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The correct order of the amino acids in the translation portion is Methionine-Leucine-Histidine-Glycine-Glutamine-Threonine-Arginine, assuming Methionine is the first amino acid.

The order of amino acids in a polypeptide chain is determined by the sequence of codons in the mRNA transcript during the process of translation. The given sequence of amino acids: leucine, histidine, glycine, methionine, glutamine, threonine, and arginine, represents the sequence of amino acids coded for in the translation portion. The first amino acid is usually methionine, which serves as the start codon in most protein-coding genes. Thus, assuming methionine is the first amino acid, the correct order would be a methionine, leucine, histidine, glycine, glutamine, threonine, and arginine. This sequence of amino acids forms a polypeptide chain that would fold into a specific protein with a unique three-dimensional structure, which ultimately determines its function in the cell.

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Least  to most basic compounds;

a) Sodium acetate: LEAST basic; Sodium methoxide: MOST basic; Sodium phenoxide: blank

b) Sodium acetate: LEAST basic; Sodium chloroacetate: blank; Sodium fluoroacetate: MOST basic

c) Lithium ethoxide: LEAST basic; Lithium hydroxide: MOST basic; Lithium formate: blank

Sodium compounds are compounds containing the element sodium. Sodium is a group 1 alkali metal, which has a single electron in its outer shell and, as such, is highly reactive.

Sodium compounds tend to be strong bases and are very soluble in water. Sodium acetate is a compound formed from the combination of acetic acid and sodium.

It has a very high solubility in water and is used in many industrial and food processing applications. Sodium methoxide is the combination of methanol and sodium and is an even stronger base than sodium acetate.

It is also soluble in water, and is used as a catalyst in many chemical reactions.

Sodium phenoxide is a combination of phenol and sodium, and is an even stronger base than sodium methoxide. It is highly water soluble and is used in pharmaceuticals.

Lithium compounds are compounds containing the element lithium. Lithium is a group 1 alkali metal, similar to sodium. It is much less reactive than sodium, however, and lithium compounds tend to be weaker bases.

Lithium ethoxide is the combination of ethanol and lithium and is a relatively weak base. It is water soluble and is used in pharmaceuticals. Lithium hydroxide is the combination of lithium and water and is a strong base.

It is also water soluble and is used as a pH adjuster. Lithium formate is the combination of lithium and formic acid and is an even weaker base than lithium ethoxide. It is also water soluble and is used as a food preservative.

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The correct answer is B. Gaseous CO2 bubbles out of the solution.

The solubility of KNO3 in water generally increases as the temperature increases. Therefore, heating the solution to 75°C would not cause KNO3 to precipitate out of the solution.

A solution is a homogeneous mixture composed of two or more substances. The substance that is present in the largest amount is called the solvent, while the substance that is present in a smaller amount is called the solute. Solutions can be formed with solids, liquids, or gases, and they can be formed by dissolving a solute in a solvent.

Solutions are essential in many areas of chemistry, including analytical chemistry, biochemistry, and materials science. They are widely used in industry, for example, as solvents in chemical reactions or as carriers of active ingredients in pharmaceuticals. The properties of a solution, such as its boiling point, melting point, and density, depending on the nature and amount of the solute and solvent. The concentration of a solution can be expressed in a variety of units, including molarity, molality, and percent by weight or volume.

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Complete Question:

A solution is saturated in CO2 gas and KNO3 at room temperature. What happens when the solution is warmed to 75°C?

A). solid KNO, precipitates out of the solution

B). gaseous CO2 bubbles out of the solution

C). solid KNO, precipitates out, and gaseous CO2 bubbles out

D). nothing happens; both CO2 and KNO3 remain in solution

The proportion of students that scored higher than Willa is 1 - 0.2626 = 0.7374 or approximately 0.74.

C. 0.74 is correct option.

The grades on a chemistry exam have an approximately normal distribution with a mean of 78 and a standard deviation of 5. Willa scores a 74.8 on the exam. What proportion of the students scored higher than her on the exam?

The proportion of students who scored higher than Willa on the exam can be found using the normal distribution table. Given the mean, μ = 78, and the standard deviation, σ = 5, the distribution of the scores is approximately normal.

Let's first standardize Willa's score. Standardized Score = Z-score.

The formula for Z-score is as follows:

Z = (X - μ) / σ

where, X is the raw score

μ is the mean, and

σ is the standard deviation.

Z = (74.8 - 78) / 5Z

  = -0.64

Using the standard normal distribution table, we can find the proportion of students that scored higher than Willa. The area to the left of Willa's Z-score is 0.2626.

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Answer:

Heat always flows in the direct from hot to cold objects.

Endothermic has a Positive Reaction Δ H, exothermic has a Negative Reaction Δ H

q = mcΔT

:

Number of moles of Cl2 molecules in a sample that contains 7. 12×1025 molecules of Cl2 is 118.2 moles.

To find out the number of moles of Cl2 molecules in a sample that contains 7.12 x 1025 molecules of Cl2, we can use the following formula:

moles = number of molecules / Avogadro's number

A mole is a unit of measurement that is used to calculate the quantity of a material. One mole of a material is the amount of that substance that has the same number of particles (atoms, molecules, or ions) as 12 grams of carbon-12. This particle number is known as Avogadro's number, and it is around 6.022 x 10^23 particles per mole.

Therefore, the calculation is:

moles = 7.12 x 10^25 / 6.022 x 10^23

moles = 118.2 moles

So, the number of moles of Cl2 molecules in the given sample is 118.2 moles.

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According to the given Information:

The aqueous solution that has the lowest freezing point is 1.0 M C2H5OH (ethanol).

Because it determines the concentration of solute particles in the solution.

Ionic solutes, such as NaCl, dissociate into multiple ions in water, producing a higher concentration of solute particles per unit concentration than molecular solutes, such as ethanol.

This results in a greater degree of freezing point depression for ionic solutes than molecular solutes.

An aqueous solution is one in which water serves as the solvent.

Aqueous solutions are very common in nature and in laboratory settings. Many substances can dissolve in water to form aqueous solutions, including salts, acids, bases, and gases.

Aqueous solutions are important in many fields of science, including chemistry, biology, and environmental science.

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The meltdown of Reactor core at a nuclear power plant, such as Chernobyl, would most likely lead to the accidental release of radiation.

The Chernobyl disaster was a major event that occurred on April 26, 1986, at the No. 4 reactor in the Chernobyl Nuclear Power Plant. It is generally regarded as the most catastrophic nuclear power plant accident in history, causing significant radioactive contamination in many regions of Europe, as well as in Ukraine and Belarus, the countries closest to the disaster. The meltdown of the reactor's core caused the release of large quantities of radioactive materials into the atmosphere. Many people, especially first responders and emergency personnel, were killed as a result of the accident.The accident's environmental and health consequences are still being felt today. Thousands of people who lived in contaminated areas died as a result of the incident, while others suffered lifelong consequences, including a higher risk of cancer, birth defects, and other illnesses.

A nuclear reactor is a facility that uses controlled nuclear reactions to produce power. Inside a nuclear reactor, uranium atoms are split in a process known as nuclear fission. This releases heat energy, which is used to create steam that drives turbines, which in turn generate electricity. As nuclear reactions occur, they produce a lot of heat, which must be contained and regulated to keep the reactor from overheating and possibly melting down. The reactor's coolant and control systems are responsible for maintaining safe temperatures and preventing accidents.

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Ernest Rutherford, a New Zealand physicist, conducted the gold foil experiment and discovered that the atom has a positively charged nucleus.

In 1911, he conducted an experiment in which he fired alpha particles at a thin sheet of gold foil. The majority of the particles went straight through the gold foil, but a small percentage of the particles bounced back. He discovered that the bouncing back was caused by a small, positively charged nucleus at the center of the atom. Rutherford's experiment was crucial to our understanding of the structure of the atom. Prior to his experiment, the prevailing model of the atom was that it was a solid, indivisible sphere.

However, Rutherford's experiment showed that the atom was mostly empty space, with a positively charged nucleus at its center. This discovery paved the way for future research into atomic structure and helped to lay the foundation for the development of nuclear physics.

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The number of moles of H+ ions present in the following aqueous solutions is as follows:-

(a) 1.40 L of 0.25 M perchloric acid= 0.35 mol H+ ions

(b) 6.8 mL of 0.92 M nitric acid= 0.00626 mol H+ ions

(c) 2.6 L of 0.085 M hydrochloric acid= 0.221 mol H+ ions

Molarity is used to determine the number of moles of a solute present in 1 liter of a solution.

(a) The molarity of perchloric acid is given as 0.25 M. Thus, we can find the number of moles of H+ ions present in the given solution using the below formula:-

Moles of solute = Molarity x Volume in litres= 0.25 x 1.40= 0.35 mol H+ ions

(b) The volume of the given nitric acid is 6.8 mL, i.e. 0.0068 L. Thus, the number of moles of H+ ions present in this solution can be calculated using the below formula:-

Moles of solute = Molarity x Volume in liters= 0.92 x 0.0068= 0.00626 mol H+ ions

(c) The volume of the given hydrochloric acid is 2.6 L. Thus, we can find the number of moles of H+ ions present in the given solution using the below formula:-

Moles of solute = Molarity x Volume in liters= 0.085 x 2.6= 0.221 mol H+ ions

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The correct answer is B) Urea. Urea is a waste product of protein metabolism, and is released from the body through sweat, where the ammonia and other waste products form urea.

Lysozymes are enzymes that are naturally produced in most living organisms. They are responsible for helping to break down peptidoglycan, a substance found in the cell walls of various bacteria. This helps to prevent bacterial growth and spread, as well as helping to keep the cells intact. Lysozymes are also known to act as an antimicrobial agent, helping to destroy the cell walls of some types of bacteria.

Sebum is an oily substance produced by the sebaceous glands of the skin. The sebaceous gland is located in the hair follicles and it is responsible for secreting the sebum. Sebum production is regulated by hormones and usually occurs when the body needs more moisture (such as during puberty). Sebum can act as a barrier to protect the skin and prevent it from drying out. It helps to keep the skin hydrated, soft and supple. In addition, it helps to reduce bacterial buildup on skin. Sebum is also responsible for giving skin its natural glow.

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The volume of the ammonia that can be produced from the reaction that has been written is;  155 * 10^7 L

We know that;

PV = nRT

For the hydrogen;

n = PV/RT

n = 155 * 4.0 x 10^7 /0.082 * 776

n = 620 * 10^7/63.63

n = 9.7 * 10^7 moles

Now the reaction equation is;

N₂(g) + 3H₂(g) → 2NH3(g)

3 moles of hydrogen  produced 2 moles of ammonia

9.7 * 10^7 moles will produce  9.7 * 10^7 moles * 2 moles/ 3 moles

x = 6.5 * 10^7 moles

For the volume of the ammonia;

V = nRT/P

V =  6.5 * 10^7 moles * 0.082 * 293.6/1.007

V = 155 * 10^7 L

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The equilibrium shift when the concentration of H2 (gas) is increased by adding more hydrogen gas to the container at constant temperature is towards the right side of the reaction equation.

Let us understand how the reaction shifts with the help of the following chemical reaction equation. N2(g) + 3H2(g) ⇌ 2NH3(g).

Adding more H2 gas to the container at constant temperature will increase the concentration of H2 gas.

The reaction will shift towards the product side (right side of the reaction equation) to balance the reaction equation.

The concentration of NH3 gas will increase, and the concentration of N2 gas and H2 gas will decrease.

The reaction quotient (Qc) is used to predict the direction of the reaction.

If Qc is greater than Kc, the reaction shifts towards the left side of the reaction equation.

If Qc is less than Kc, the reaction shifts towards the right side of the reaction equation.

.f Qc is equal to Kc, the reaction is at equilibrium state with no shift in the reaction.

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Answer:

Boron,silicon,germanium,arsenic,antimony,tellurium, polonium, astatine.

When identifying whether each of the following statements applies to DNA, RNA, both or neither, the answers are as follows:

1. It can contain the purine guanine: Both DNA and RNA can contain the purine guanine.

2. It can contain the pyrimidine uracil: RNA can contain the pyrimidine uracil, but DNA cannot.

3. This contains the sugar 2'-deoxyribose: DNA contains the sugar 2'-deoxyribose, but RNA contains ribose.

4. In terms of base composition, the %T %G: This statement applies to DNA.

5. This contains the sugar ribose: RNA contains the sugar ribose, but DNA contains 2'-deoxyribose.

6. The bases are attached to sugar in a β-N glycosidic linkage: Both DNA and RNA have bases that are attached to sugar in a β-N glycosidic linkage.

7. It contains equal amounts of purines and pyrimidines: Neither DNA nor RNA contains equal amounts of purines and pyrimidines.

8. Sugars are connected with a 3-5' phosphodiester link: Both DNA and RNA have sugars that are connected with a 3-5' phosphodiester link.

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