If a baseball player hits a baseball from 4 feet off the ground with an initial velocity of 64 feet per second, how long will it take the baseball to hit the ground? Use the equation h = −16t2 + 64t + 4.

Answer options:

2 plus or minus square root of 17 end root over 2

quantity of 2 plus or minus square root of 17 all over 2

2 plus or minus 4 square root of 17

quantity of 16 plus or minus square root of 17 all over 2

Answers

Answer 1

Answer:

option c is the correct answer


Related Questions

Solve for y please and thank you

Answers

Answer:

c)  y = 8[tex]\sqrt{3}[/tex]

Step-by-step explanation:

in a 30-60-90° Δ the ratio of the sides, respectively, is 1: [tex]\sqrt{3}[/tex] : 2

if the side opposite the 30°∡ is 8 then 'y' is 8[tex]\sqrt{3}[/tex] and 'x' is 16

Hey, can anyone help me with this pls

Answers

Answer:

it's B

Step-by-step explanation:

I'm quite sure it is. Hope it helps u

Mark Brainliest please

Answer is C

Find the area of the trapezoid. Leave your answer in simplest radical form.

Answers

Answer:

[tex]Area = 52\sqrt3 \ ft^2[/tex]

Step-by-step explanation:

Area of trapezoid

                         [tex](\frac{a+ b}{2}) \times h[/tex]      -----------( 1 )

We will split the trapezoid into Triangle and rectangle. To find the height and full length of base.

[tex]sin 60 = \frac{opposite}{hypotenuse}[/tex]   [tex][ opposite \ in \ the \ equation \ \ is \ the \ height \ of \ the \ trapezoid ][/tex]

[tex]\frac{\sqrt3}{2} = \frac{opposite }{ 8}\\\\\frac{\sqrt3}{2} \times 8 = opposite\\\\4\sqrt3 = opposite[/tex]

Therefore, h = 4√3 ft

[tex]cos 60 = \frac{adjacent}{hypotenuse}[/tex]    [tex]adjacent \ in \ the\ equation \ is \ the\ base \ of \ the \ triangle ][/tex]

[tex]\frac{1}{2} = \frac{adjacent}{hypotenuse}\\\\\frac{1}{2} \times 8 = adjacent\\\\4 = adjacent[/tex]

Therefore, a = 11 feet, b = 11 + 4 = 15 feet

Substitute the values in the Area equation :

                                                [tex]Area = \frac{11 + 15}{2} \times 4 \sqrt3 = \frac{26}{2} \times 4\sqrt3 = 13 \times 4\sqrt3=52\sqrt3 \ ft^2[/tex]


Learning Activities
Solve the following problems. Choose
the letter of the correct answer
(Show your complete solutions)
1.) The sum of all the sides of a STOP sign is 104 inches. A STOP sign is an
with all sides equal. How many inches does each side measure?
B. 11 in
C. 13 in
D. 16 in
2.) In A ABC, LA and Beach measure 70% How many degrees are there in 202
A. 400
B. 50°
C. 60
D700
3.) The measures of the three angles of a quadrilateral are 49. 58, and 127. What
is the measure of the fourth angle?
A. 116
B. 126
C. 54
D. 64
A. 8 in
4.) Solve for the value of x in DEFG.
E
D
(x + 40)
130
A 400
B. 70°
C. 500
D. 90°
F
(2x-10)
G
5.) if the length of the two sides of an isosceles triangle are 3 cm and 7 cm, then
what must be the length of the third side?

Answers

Step-by-step explanation:

answers I the above photo

some of the questions are not clear

Answer:

1. C(13inches)

2. A(40°)

3. B(126°)

4. C(50°)

5. 7cm

Step-by-step explanation:

According To the Question,

1. Given, The sum of all the sides of a STOP sign is 104 inches. A STOP sign is Octagon  with all sides equal.

Thus, Octagon has 8 equal side

So, Each Side Measure = 104/8 ⇔ 13inches

2. Given, In Triangle ABC, ∠A & ∠B each measure 70°

And, We Know Sum of all angles of a triangle is 180°.

Thus, ∠C = 180° - (∠A + ∠B)  ⇔  180°-140° ⇒ 40°

3. Given, The measures of the three angles of a quadrilateral are ∠A=49° ,∠B=58° & ∠C=127° .

And, We know sum of all angles of quadrilateral is 360°.

Thus, ∠D=360° - (∠A+∠B+∠C)  ⇔ 360°-234° ⇒ 126°

4. Given, The measure of all the Four angles of a quadrilateral are ∠A=(x+40)°, ∠B=130°, ∠C=x° & ∠D=(2x-10)° .

And, We know sum of all the angles of quadrilateral is 360°.

Thus, ∠A+∠B+∠C+∠D = 360°

Put all the Values, we get

x+40+130+x+2x-10 = 360

4x+160 = 360

4x = 200 ⇔ 200/4 ⇒ 50°

5. Given, the length of the two sides of an isosceles triangle are 3cm and 7cm .

Now, in order to form a triangle the sum of any two side of a triangle is always greater than the third side of a triangle.

So, We have an isosceles triangle in which two sides is always equal & we have given two sides of 3cm & 7cm .

Assume, if third side be 3cm (First Side+Third side > Second side)

3+3 ⇒6cm which is not greater than 7cm(thus, the Triangle not possible if we assume 3cm as triangle's third side)

Hence, The other Side of Triangle Surely be 7 cm.  

Determina la masa molar y el volumen que ocupa la siguiente sustancia CO2, si su masa es de 28 gr. *

Answers

Answer:

Para el CO₂ sabemos que:

densidad = 0,001976 g/cm³

Sabemos que:

densidad = masa/volumen

Entonces, si tenemos una masa de 28 g, podemos escribir:

volumen = masa/densidad

volumen = (28g)/(0,001976 g/cm³) = 14,170 cm^3

Para obtener la masa molar (es decir, la masa de un mol de esta sustancia) simplemente sumamos la masa de un mol de cada componente.

Carbono: tiene una masa molar de 12 g/mol

Oxígeno: tiene una masa molar de 16 g/mol (y tenemos dos oxígenos)

entonces la masa molar va a ser:

masa molar = 12g/mol + 2*16g/mol = 44 g/mol

Es decir, un mol de CO₂, pesa 44 gramos.

solutia reala a ecuatiei 4x la a doua = 6 intregi si 1/4 (dau coroana)

Answers

Answer:

x = + 5/4 or x = - 5/4

Step-by-step explanation:

[tex]4 x^2 = 6\frac{1}{4}\\\\4 x^2 = \frac{25}{4}\\\\x^2 =\frac{25}{16}\\\\x = \pm \frac{5}{4}[/tex]

f(x) =-x²+16 and g(x) =x+4​

Answers

f(x)/g(x) = (x2-16)/(x+4)

The domain is all real numbers except x = -4 (because the denominator is zero at x = -4 and division by zero is undefined.)

We can simplify by factoring the numerator:

(x2-16)/(x+4) = (x-4)(x+4)/(x+4) = (x-4)

The domain is the same as the original expression: all real numbers except x = -4

HURRY !!!!!! Which describes the correlation shown in the scatterplot?

Answers

No correlation is shown.

Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.

r = 4 cos 5θ

Answers

Answer:

y-acis

Step-by-step explanation:

the function graph is symmetric about

- y-axis when it is an even function

-the origin ehen it is an even function

A symmetrical graph about the x-axis is not a function graph

f(×) is a even if and only if f(×) =f(×)

f(×) is a odd if and only f(×)=f(×)

We have the function r(0) = 4cos (50)

(only symmetry about the y-acis or about the origin)

Check r(-0)

r(-0) = 4cos (5-0) = 4cos (-50 = 4 cos (50)

Used cos (-× = cos ×

We have r(0). Therefore the graph of r(0) is symmectric about the y-axis.

A² + b² = 7b and b² + (2b-a)² = 7² find (a - b)².

Answers

Answer:

(a - b)^2 = 49 - 4b^2 +2ab

Step-by-step explanation:

Given: a^2 + b^2 = 7b (assuming A is really “a”)

b^2 + (2b - a)^2 = 7^2

Find; (a - b)^2

Plan: Use Algebraic Manipulation

Start with b^2 + (2b - a)^2 = 7^2 =>

b^2 + 4b^2 - 4ab + a^2 = 49 by expanding the binomial.

a^2 + b^2 + 4b^2 - 4ab = 49 rearranging terms

a^2 + b^2 -2ab - 2ab + 4b^2 = 49 =>

a^2 - 2ab + b^2 = 49 - 4b^2 +2ab rearranging and subtracting 4b^2 and adding 2ab to both sides of the equation and by factoring a^2 - 2ab + b^2

(a - b)^2 = 49 - 4b^2 +2ab

Double Check: recalculated ✅ ✅

(a - b)^2 = 49 - 4b^2 +2ab

Find the quadratic equation whose parabola has vertex (3,-2) and y-intercept (0, 16). Give your
answer in vertex form.

Answers

Answer:

y = 2*(x - 3)^2 - 2

Step-by-step explanation:

Remember that a quadratic equation of vertex (h, k) is written as:

y = a*(x - h)^2 + k

Where a is the leading coefficient.

So, if we know that the vertex is at (3, - 2)

we have:

y = a*(x - 3)^2 + (-2)

And we want the y-intercept to be (0, 16)

This means that, when we take x = 0, we must have y = 16

if we replace these in the above equation we get:

16 = a*(0 - 3)^2 - 2

now we can solve this for a

16 = a*(-3)^2 - 2

16 = a*9 - 2

16 + 2 = a*9

18 = a*9

18/9 = a

2 = a

Then the quadratic equation is:

y = 2*(x - 3)^2 - 2

In a bowl of fruit, there are green grapes and black grapes in the ratio 3:4 If there are 24 green grapes, how many black grapes are there?
answer is 32
ask me more questions any time

Answers

The answer would be 32 because the ratio sets a big difference with the grapes and black grapes but the answer is 32

How many solutions exist for the system of equations in the graph?

Answers

Answer:

Two solutions

Step-by-step explanation:

The number of points of intersections represents the number of solutions to the system of equations. Since the parabola intersects the circle at two points, there are two solutions to the circle.

Furthermore, these two points of intersection are exactly the solutions to the system of equations. Finding the coordinates of the points of intersection will give you the solutions to the system of equations.

Help find x and angle BEC

Answers

Answer:

x = 32 and BEC = 43

Step-by-step explanation:

3X + 41 = 137

3X = 96

X = 32

FOR BEC:

137 + 137 = 274

360-274=86 ( ANGLES AROUND A POINT ADD UP TO 360)

86/2 = 43

BEC/AED = 43 ( VERTICALLY OPPOSITE ANGLES ARE EQUAL)

hope this helps good luck!

X=32 BEC=43
Have a nice day or night!

Find missona value in the equation below

Answers

Answer:

[tex] \sqrt[5]{96x {}^{7} y {}^{11} } = 2xy {}^{2} \sqrt[5]{3x {}^{2}y } [/tex]

the measures of the angles of a triangle are shown in the figure. solve for x

Answers

Answer:

solution,

x+41+59=180⁰ ( the sum of total angle of triangle is 180⁰)

or, x+ 100=180

or, X=180-100

so , X=80

Step-by-step explanation:

let us check

59+41+80=180

Find the area of an equilateral triangle whose value is 18 cm​

Answers

Answer:

[tex]18 + 18 + 18 = 18 \times 3 = 54[/tex]

Step-by-step explanation:

I ain't sure but it might help you out:D

Answer:

140.3 cm²

Step-by-step explanation:

area of an equilateral triangle

[tex] = \frac{\sqrt{3} }{4} {a}^{2} [/tex]

where a is the side of the triangle

[tex] = \frac{ \sqrt{3} }{4} \times {18}^{2} \\ = 140.3 \: cm {}^{2} [/tex]

Help me solve these 4 plssss ASAP

Answers

Step-by-step explanation:

[tex]1) \\ - 2 \leqslant x \leqslant 1 \\ 2) \\ - 3 > x \geqslant 2 \\ 3) \\ x> 0[/tex]

[tex]4) \\ x \leqslant - 3 \\ 5) \\ - 4 \leqslant x \geqslant 1[/tex]

[tex]6) \\ - 2< x \leqslant 0[/tex]

13-?=7-2x
In the equation above what must ? be so that x has value of 2

Answers

Answer:

? = 10

Step-by-step explanation:

13 - (10) = 7-4 ....... 2×2 =4

3 = 3

10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.

Answers

Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

A success is 5 or 6.

A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:

[tex]p = \frac{4}{6} = 0.6667[/tex]

10 normal six sided dice are thrown.

This means that [tex]n = 10[/tex]

Find the probability of obtaining at least 8 failures.

This is:

[tex]P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)[/tex]

So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951[/tex]

[tex]P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867[/tex]

[tex]P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174[/tex]

Then

[tex]P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992[/tex]

0.2992 = 29.92% probability of obtaining at least 8 failures.

A car left the house traveling north at 10 A.M. Another car left the house traveling south two hours later. If the cars traveled at the same rate and were 550 miles apart at 4 P.M , what was the rate of each car.

Answers

Answer:

55 mph

Step-by-step explanation:

the equation cos(x)( cos(x)-tan(x)sin(x)) simplifies to

Answers

I am sorry but I do not know but if someone else know help

if f(x)=3x-1 and g(x)=x+2, find (f-g)(x)​

Answers

Answer:

2x - 3

Step-by-step explanation:

3x-1 - (x+2)

3x-1 -x -2

2x - 3

use these functions a(x) =4x +9 and b(x) =3x -5 to complete the function operations listed below

Answers

Consider that we need to find [tex](a+b)(x), (a-b)(x), (ab)(x),\left(\dfrac{a}{b}\right)(x)[/tex].

Given:

The functions are:

[tex]a(x)=4x+9[/tex]

[tex]b(x)=3x-5[/tex]

To find:

The function operations [tex](a+b)(x), (a-b)(x), (ab)(x),\left(\dfrac{a}{b}\right)(x)[/tex].

Solution:

We have,

[tex]a(x)=4x+9[/tex]

[tex]b(x)=3x-5[/tex]

Now,

[tex](a+b)(x)=a(x)+b(x)[/tex]

[tex](a+b)(x)=4x+9+3x-5[/tex]

[tex](a+b)(x)=7x+4[/tex]

Similarly,

[tex](a-b)(x)=a(x)-b(x)[/tex]

[tex](a-b)(x)=4x+9-(3x-5)[/tex]

[tex](a-b)(x)=4x+9-3x+5[/tex]

[tex](a-b)(x)=x+14[/tex]

And,

[tex](ab)(x)=a(x)b(x)[/tex]

[tex](ab)(x)=(4x+9)(3x-5)[/tex]

[tex](ab)(x)=12x^2-20x+27x-45[/tex]

[tex](ab)(x)=12x^2+7x-45[/tex]

And,

[tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{a(x)}{b(x)}[/tex]

[tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{4x+9}{3x-5}[/tex]

Therefore, the required functions are [tex](a+b)(x)=7x+4[/tex], [tex](a-b)(x)=x+14[/tex], [tex](ab)(x)=12x^2+7x-45[/tex] and [tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{4x+9}{3x-5}[/tex].

Express as simply as possible with a rational denominator
7/√10

Answers

Answer:

7√10 / 10.

Step-by-step explanation:

7/√10

Multiply top and bottom by √10:

= 7√10 / 10

What is the monthly net income?? Show work plz

Answers

More info please! I cannot solve it

Ryder used front end estimation to estimate the product of -24.98 - 1.29 what is the zestimate​

Answers

Answer:

20

Step-by-step explanation:

The numbers whose product are to be obtained :

(–24.98)(–1.29)

To use front end approximation, numbers are rounded to the greatest place value :

For :

(-24.98) is rounded to - 20 (4 is rounded here to 0)

(-1.29) is rounder to - 1 (2 is rounded to 0)

Then, the product of the two numbers will be :

-20 * - 1 = 20

if 1/a+1/b+1/c=1/a+b+c then prove that 1/a^9+1/b^9+1/c^9=1/a^9+1/b^9+1/c^9​

Answers

Answer:

The given relation is presented as follows;

[tex]\dfrac{1}{a} + \dfrac{1}{b} +\dfrac{1}{c} = \dfrac{1}{a + b + c}[/tex]

Where 'a', 'b', and 'c' are member of real numbers, we have;

a⁹, b⁹, and c⁹ are also member of real numbers

When a⁹ = x, b⁹ = y, and c⁹ = z

By the above relationship, we have;

[tex]\dfrac{1}{x} + \dfrac{1}{y} +\dfrac{1}{z} = \dfrac{1}{x + y + z}[/tex]

Substituting x = a⁹, y = b⁹, and z = c⁹, we get;

[tex]\dfrac{1}{a^9} + \dfrac{1}{b^9} +\dfrac{1}{c^9} = \dfrac{1}{a^9 + b^9 + c^9}[/tex]

Step-by-step explanation:

10. What are the coordinates of point on the directed segment from A(2,-3) to B(8,-6) that
partitions the segment such that AC:CB is 4:2?
(1) (6,-5)
(3) (2,0)
(2) (-2, 2)
(4) (1, 1)

Answers

Answer:

(4, -4)

Step-by-step explanation:

Using the midpoint formula;

M(X,Y) = {(ax1+bx2)/a+b, (ay1+by2)/a+b}

X = (ax1+bx2)/a+b

Y = (ay1+by2)/a+b

Substitute

X = 4(2)+2(8)/4+2

X = 8+16/6

X = 24/6

X = 4

Also

Y = 4(-3)+2(-6)/6

Y = -12-12/6

Y = -24/6

Y = -4

Hence the required partition is (4, -4)

The length of a spring varies directly with the mass of an object that is attached to it. When a 30-gram object is attached, the spring stretches 9 centimeters. Which equation relates the mass of the object, m, and the length of the spring, s?
s = StartFraction 3 Over 10 EndFraction m
s = StartFraction 10 Over 3 EndFraction m
m = StartFraction 3 Over 10 EndFraction s
m = StartFraction 1 Over 30 EndFraction s

Answers

Answer:

it is b

Step-by-step explanation:

Answer:

it is b

Step-by-step explanation:

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