If a car is moving backward and has negative acceleration, what can be said about the speed of the car?

a. its speed is degreasing
b. its speed is increasing
c. its speed can either increase or decrease
d. its speed does not change ​

Answer: I put the importance of the lab in the topic is to find how dense an object is and if it can sink or float and it's important to answer the question so you can also find mass and volume.

Explanation: I dunno haha...

Explanation:

Answer:

meteor

Explanation:

big rock or metal maybe

Answer:

0.2 A

Explanation:

V= IR

3 = I × 15

I = 3/15

= 1/5 = 0.2 A

The flow of current in a battery will be "0.2 A". To understand the calculation, check below.

According to the question,

Voltage, V = 3 V

Resistance, R = 15 ohm

We know the relation,

→ Voltage (V) = Current (I) × Resistance (R)

or,

→ Current, I = [tex]\frac{V}{R}[/tex]

By substituting the values,

                    = [tex]\frac{3}{15}[/tex]

                    = 0.2 A

Thus the above answer is correct.  

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Answer:

12 g i think

Explanation:

brainliest pls

Answer:

4

Explanation:

Waves that are squished have higher frequency. It has short wavelength.

Answer:

4

Explanation:

frequency and wavelength are inverses, so since this has the smallest wavelength it has the highest frequency. The smaller the wavelength, the more waves (more/high frequency) fit in a certain area in comparison to larger wavelengths fit fewer waves (less frequent).

Answer:

the density of the wooden cube is 204.1 kg/m³

Explanation:

Given;

applied force, F = 54 N

length of each side of the solid wooden cube, L = 30 cm = 0.3 m

mass of the wooden cube is calculated as;

F = mg

m = F/g

m = 54/9.8

m = 5.51 kg

The volume of the wooden cube is calculated as;

V = L³

V = (0.3)³

V = 0.027 m³

The density of the wooden cube is calculated as;

ρ = m/V

ρ = (5.51 kg) / (0.027 m³)

ρ = 204.1 kg/m³

Therefore, the density of the wooden cube is 204.1 kg/m³

Answer:

21.2m/s

Explanation

Given data

P=6.36 x 10⁴kg·m/s.

M=3000kg

From the momentum expression

P=mv

v=p/m

Substitute

v=63600/3000

v=21.2m/s

Hence the Velocity is 21.2m/s

The speed of the truck is 21.2 m /s

Momentum is the product of the mass of the object and the velocity of the object. Therefore,

p = mv

where

m  = mass

v = velocity

m = 3000 kg

p = 6.36 x 104 kg·m/s.

lets find the velocity

6.36 x 10⁴  = 3000 × v

v = 6.36 x 10⁴ / 3000

v = 21.2 m / s

The speed of the truck is 21.2 m /s

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Answer:

Ccccv

Explanation:

EN İYİ SEÇERMİSİN

Yes. Many people either know the answer, or can figure it out using the information in the picture.

Answer:

I have know idea what that means lol.

Thanks for the free points. Hope you have a fantastic rest of your life!

Answer:

Trough

Explanation:

cuz physics you see

Answer:

2 sec

Explanation:

time taken = [tex]\frac{v-u}{a} = \frac{12-7}{2.5} = 2[/tex]

Answer:

2 Mg + O2 = 2MgO

Type: Synthesis

Answer:

It's very simple- 8 valence electrons

Answer:

it's 8

Explanation:

that the answer for the question

Answer:

9.8N

Explanation:

Given the following data;

Mass = 1kg

We know that acceleration due to gravity is equal to 9.8m/s²

To find the force:

Force = mass * acceleration

Substituting into the equation, we have:

Force = 1 * 9.8

Force = 9.8N

Answer: about 1,100,000,000 to 1,500,000,000 Joules/second

Explanation:

1 MW (megawatt) = 1,000,000.00 J/s (joules per second)

1100(1,000,000) = 1,100,000,000

1500(1,000,000) = 1,500,000,000

Answer:

the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².

Explanation:

Given;

applied force, F = 5000 N

cross sectional area of the steel wire, A = 0.2 m²

The tensile stress of the steel wire, is calculated as;

[tex]\sigma = \frac{F}{A} \\\\\sigma = \frac{500}{0.2} \\\\\sigma = 2500 \ N/m^2\\\\\sigma = 2.5 \ \times \ 10^3 \ Nm^{-2}[/tex]

Therefore, the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².

Answer:

c

Explanation:

Answer:

The momentum of an object varies directly with the speed of the object.

Explanation:

Two objects of different mass are moving at the same speed; the more massive object will have the greatest momentum. A less massive object can never have more momentum than a more massive object.

Answer:0.060

Explanation:

The mass of the tennis ball is equal to 0.23 Kg.

According to the law of conservation of linear momentum, the sum of the momentum of the bodies which are collided with each other must be equal before and after the collision.

m₁ .u₁ + m₂.u₂ = m₁ .v₁ + m₂.v₂

where m₁ and m₂ is the masses, u₁ and u₂ are initial speed while v₁ & v₂ is their final speed of the collieded objects.

Linear momentum can be defined as the product of the mass times the velocity of that object.

Given, the initial velocity of the baseball is u₁ = 15 m/s

The initial velocity of the tennis ball u₂ = 22 m/s.

The mass of baseball, m₁ =0.15 Kg

From the law of conservation of momentum, find the  mass of the tennis ball:

m₁ u₁ + m₂ u₂ = m₁.v₁ + m₂.v₂

0.15 × 15 + m ×22 = 0.15 × 1.2 + m × 13

2.25 + 22 m = 0.18 + 13 m

9 m = 2.25

m = 0.23 Kg

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Answer:

a) At 0.20 m, the magnitude of the field is 675.0 kV

The direction of the field is acting outwards from the center of the charged spheres

b) At 0.10 m, the magnitude of the field is 135 kV

The direction is acting outwards from the center of the charged spheres

c) At 0.025 m

The magnitude of the field, V = -270.0 kV

The direction of the field is inwards, towards the center of the charged spheres

Explanation:

The charged spherical shell parameters are;

The charge on the inner sphere, q₁ = -1.50 × 10⁻⁶ C

The radius of the inner shell, R₁ = 0.050 m

The charge on the outer sphere, q₂ = +4.50 × 10⁻⁶ C

The radius of the outer shell, R₂ = 0.15 m

Let 'r', represent the distance at which the electric field is measured, the following relationships can be obtained;

When r < R₁ < R₂,

[tex]V = k \cdot \left( \dfrac{q_1}{R_1} + \dfrac{q_2}{R_2} \right )[/tex]

When R₁ < r < R₂,

[tex]V = k \cdot \left( \dfrac{q_1}{r} + \dfrac{q_2}{R_2} \right )[/tex]

When R₁ < R₂ < r,

[tex]V = k \cdot \left( \dfrac{q_1 + q_2}{r^2} \right )[/tex]

a) When r = 0.20 m, we have;

R₁ < R₂ < r, therefore

[tex]V = k \cdot \left( \dfrac{q_1 + q_2}{r^2} \right )[/tex]

By plugging in the values, we get;

[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} + 4.50\times 10^{-6} }{0.20^2} \right ) = 675.0 \ kV[/tex]

Therefore, the magnitude of the field, V = 675.0 kV

The direction of the field is outwards

b) When r = 0.10 m, we have;

When R₁ < r < R₂, therefore;

[tex]V = k \cdot \left( \dfrac{q_1}{r} + \dfrac{q_2}{R_2} \right )[/tex]

By plugging in the values, we get;

[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} }{0.10} + \dfrac{4.50\times 10^{-6}}{0.15} \right ) = 135 \ kV[/tex]

Therefore, the magnitude of the field, V = 135 kV

The direction of the field is outwards from the center

c) When r = 0.025 m, we have;

When r < R₁ < R₂, therefore;

[tex]V = k \cdot \left( \dfrac{q_1}{R_1} + \dfrac{q_2}{R_2} \right )[/tex]

By plugging in the values, we get;

[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} }{0.05} + \dfrac{4.50\times 10^{-6}}{0.15} \right ) = -270 \ kV[/tex]

Therefore, the magnitude of the field, V = -270.0 kV

The direction of the field is inwards, towards the center of the charged spheres.

Answ

Explanation:

HOPE IT HELPS..

The image formed by the location of object is beyond 2F the image by convex lenses is between F and 2F and is inverted, smaller and and real image. If it is at 2F, the image is inverted with the same size and real.

A convex lens is a type of lens that is projected outwards and shows the real image of an object.  Whereas a concave lens is curved inwards and shows virtual image of objects.

The image formed at by the location of convex lenses beyond 2F is inverted, smaller and and real image. If it is at 2F, the image is inverted with the same size and real. If the lens is placed between F and 2F the image formed is beyond 2F and it will be inverted, enlarged and real.

If the object is at F , no image will be formed. If it at between F and the lens, then the image forms beyond 2 F which is upright, enlarged and virtual.

The object be at any position with respect to the focal length of lens, the image formed by a concave lens is between F and the lens and upright, small and virtual.

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Answer:

PICK ONE

Explanation:

Answer:

En 1589 Galileo realizó un experimento lanzando dos bolas de diferentes masas desde la famosa Torre Inclinada de Pisa para demostrar que el tiempo de caída es independiente de la masa de la bola. A través de este experimento, Galileo descubrió que los cuerpos caían casi simultáneamente, refutando la teoría de Aristóteles de que la tasa de caída era proporcional a la masa del cuerpo.  

Debido a la imperfección de los equipo de medición de esa época, la caída libre de los cuerpos era casi imposible de estudiar. En busca de una forma de reducir la velocidad de movimiento, Galileo reemplazó la caída libre por rodar sobre una superficie inclinada, donde había velocidades y resistencia del aire significativamente más bajas. Se notó que con el tiempo, la velocidad del movimiento aumenta: los cuerpos se mueven con aceleración. Se concluyó que la velocidad y la aceleración no dependen ni de la masa ni del material de la pelota.

Answer:

the mass of object is 2000