if a cars engine is 27.5 effeicient at converting the fuels energt ubti necgabucal eberft if 1L of gasoline has 33.5J of input energy how much useful energy output will 2.50L of fuel provide

Answers

Answer 1

The efficiency of the engine is given 27.5%. The input energy of 2.5 L gasoline is 83.75 J. Then, the energy output will be 23.01 J.

What is engine efficiency ?

The efficiency of an engine is the ratio of its output work done to the energy input. No engine can have 100% efficiency. Hence, some energy is lost in the form of heat.

Given that, the efficiency of the car's engine is 27.5 %. Input energy of 1 L gasoline is 33.5 J. Then, energy input for 2.5 l is:

input energy = 2.5  × 33.5 = 83.75 J.

Engine efficiency = energy output/ input energy × 100

O/ 83.75J × 100 = 27.5 %

O/83.75 = 0.275

then output energy = 83.75 × 0.275 = 23.01 J.

Therefore, the energy output of the fuel is 23.01 J.

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Related Questions

how you would orient the magnets and what you would do with the magnets to achieve maximum repulsion

Answers

The orientation of the magnets that gives the strongest repulsion because these poles and facing each other that is then leaves highest flux density of the poles for a force of repulsion to be very high

1. Compare the speed that light waves travel in air to the speed that sound waves travel in the air. How many times faster do light waves travel in air in comparison to sound waves in air?
Water-1500 meters per second
steel-5000 meters per second
Air-335 meters per second

Answers

Answer:

895522 times faster.

Explanation:

From the question given above, the following data were obtained:

Speed of sound in air (v) = 335 m/s

Speed of light in air (c) = 3×10⁸ m/s

How many times faster =.?

To obtain how many times faster light travels in air than sound, do the following

c : v => 3×10⁸ : 335

c/v = 3×10⁸ / 335

c/v = 895522

Cross multiply

c = 895522 × v

From the illustrations made above, we can see that the speed of the light in air (c) is 895522 times the speed of sound in air.

Thus, light travels 895522 times faster than sound in air.

Which box depicts the simplest level of organization?
A) P
B) Q
C) R
D) S

Answers

Answer: C) R

Explanation: This answer is a cell, which is the smallest organism depicted. It would then go Q (tissue) which is made up of cells, then P) which is made of tissue, then S) the human body which is made of organisms, tissues, and cells.

The box that depicts the simplest level of organization is R. Thus, option C is correct.

What is cell ?  

Cell is defined as the structural and functional base of life and it has been the building block of all living things and the cell is surrounded by a protective membrane known as cell membrane.Prokaryotic cell is made up of single cell and found in unicellular animals.

Cell is generally of two types and these are eukaryotic as well as prokaryotic cell. Prokaryotic cell is made up of single cell and found in unicellular animals. The eukaryotic cell is made up of multiple cell and they contain cell organelles and these are present in multicellular animals.

The outermost part of brain has been known as dura mater that consist of a strong membrane layering and it is thick located just behind the skull and vertebral column.

Therefore,The box that depicts the simplest level of organization is R. Thus, option C is correct.

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Please help (choose a b or c)
(the image is attached)

In the adjacent circuit, the voltage across the terminals of the dry cell is equal to 12 V.
The value displayed by the voltmeter is:

a- 0 V
b- 12 V
c- -12 V

The two terminals that correspond to the correct connection of a voltmeter in a circuit are:

a- A and COM
b- A and V
c- V and COM​

Answers

I GEUSS A and COM is correct answer to this question

Answer:

1. (a) =0

2.(c) = v and COM

the Himalayas are the highest mountain in the world (positive)​. grammar question

Answers

Answer:

positive degree:

No other peak of the Himalayas is as high as Mount everest

What patterns are caused by the Earth, Sun, and Moon systems?

Answers

Earth's rotation and orbit and the Moon's orbit cause observable patterns (Day and night, seasons, phases of the Moon, tides).

The Earth, Sun, and Moon systems create several patterns, including the day and night cycle, seasons, lunar phases, tides, and solar and lunar eclipses. These patterns have been studied and understood by scientists for centuries and have played an important role in shaping our understanding of the universe and our place in it. Understanding these patterns is essential in comprehending the workings of the universe and the impact they have on our planet.

What patterns are caused by the Earth, Sun, and Moon systems?

The Earth, Sun, and Moon systems create several patterns, including:

Day and Night cycle: The rotation of the Earth on its axis causes the alternating cycle of day and night as different parts of the planet face towards or away from the Sun.

Seasons: The tilt of the Earth's axis (23.5 degrees) causes the seasons to change as different parts of the planet receive varying amounts of sunlight throughout the year.

Lunar Phases: The Moon orbits the Earth, causing it to appear to change shape in the sky as different amounts of sunlight reflect off its surface.

Tides: The gravitational pull of the Moon and the Sun on the Earth's oceans creates a regular cycle of high and low tides.

Solar and Lunar Eclipses: The alignment of the Earth, Sun, and Moon can cause a shadow to be cast on one celestial body by another, resulting in either a solar or lunar eclipse.

These patterns have been studied and understood by scientists for centuries and have played an important role in shaping our understanding of the universe and our place in it.

Therefore, The day and night cycle, seasons, lunar phases, tides, and solar and lunar eclipses are just a few of the patterns that the Earth, Sun, and Moon systems produce. Scientists have been analyzing and studying these patterns for centuries, and they have had a significant impact on how we view the cosmos and our place in it. Knowing these patterns is crucial to understanding how the cosmos functions and how they affect our world.

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Long Answer Type Questions
1 Can you differentiate between opaque, transparent and translucent objects
2 What is reflection of light?
3. What are the conditions for a shadow to be formed?
4. Prove through an experiment that light travels in straight lines.
5. What is pinhole camera? Explain its working with the help of a diagram
6. What are the main differences between a reflected image and shadows?​

Answers

(1).....opaque -object that not allow light to pass through it

we can't look through opaque objects

ex..wall

translucent... objects that all some light to pass through it

we can partially see through it

ex...coloured glass window

transparent... objects that wholly allow light to pass through it

we can clearly see through it

ex...glass of specs

(2)..the bouncing back of light from a smooth polished surface is called reflection of light

(3)/.....there must be a solid ,opaque to block light

there must be a source of light

there must be a surface to have shadow on it..

(6)...reflected images r formed by light reflection from a smooth polished surface while shadows are formed by blockage of light by an solid,opaque object...

Explanation:

we should talk here thanks

3. Gather data: Use the values above to fill in the first row of the table. Then run your own experiments to fill
in the last two rows.
f
d.
d,
h.
h,
ร”
S
d
de
2.0
h;
h.
2.0
s.
2.0
S
f
2.0
15
10
30

Answers

Answer:

urjshsus uevus e survey dydvd dydvdyd d dgdv gdyr yrgdvv yth yrhvthr

Explanation:

ydgdydvd yd dv ydvr dyve dysdvdyr gdvr

The electrostatic force between two charged metal spheres is 2N. If the charge on each sphere is doubled, what is the new force between the spheres?

Question 2 options:
A. 2N
B. 4N
C. 1N
D. 8

Answers

Answer:

8 N

Explanation:

The force between two charges is given by :

[tex]F=\dfrac{kq_1q_2}{d^2}[/tex]

Where

k is electrostatic constant

d is the distance between two charges

It means,

[tex]F\propto \dfrac{1}{d^2}[/tex]

When the distance is d, the force is 2 N. If the charge on each sphere is doubled, q₁' = q₂' = 2q₁ = 2q₂. New force will becomes:

[tex]F'=\dfrac{kq_1'q_2'}{d^2}\\\\F'=\dfrac{k2q_1\times 2q_2}{d^2}\\\\F'=4\times \dfrac{kq_1q_2}{d^2}\\\\F'=4\times 2\\\\F'=8\ N[/tex]

So, the new force becomes 8N. Hence, the correct option is (d).

calculate the pressure exerted on the floor when an elephant who weighs 2400N stands on one foot which has an area of 0.4m squared​

Answers

Answer:

6000pa

Explanation:

force= 2400N

area= 0.4m

pressure=?

now,

p= f/a

p= 2400/ 0.4

therefore,P=6000 pa.

Two objects, A and B, are in contact with one another. Initially, the temperature of A is 50 °C and the temperature of B is 100 °C. 1. **The particles of which object (A or B) initially have a greater average kinetic energy? How do you know?​

Answers

Answer:

B

Explanation:

because kinetic energy is directly proportional to temperature so the hottor the object, the more kinetic energy.

What is the SPEED of a train that travels 15000 meters in 1200 seconds (20 minutes)?

PLEASE SHOW WORK!!!! EASY POINTS!!!!

Answers

Answer:

27.9617 mi/h

Explanation:

Speed= distance/time

S= 15000/1200

a ball rolled a velocity of 20m/s after 5s it comes to stop what is the acceleration of the ball​

Answers

Answer:

please find the attached pdf

Explanation:

The ability of a halogen to react with a metals to form a salt is an example of a ________________ property.

Answers

The answer is a CHEMICAL property.

what is equilibrium state​

Answers

Answer:

A state of rest or balance due to the equal action of opposing forces.

Answer:

a state of rest or balance due to the equal action of opposing forces. equal balance between any powers, influences,etc

Explanation:

5. A car accelerates from 0 to 72 km/hour in 8.0 seconds. What is the car's acceleration?

Answers

Answer:

2.5 m/s

Explanation:

There are calculators online that can help you easily calculate the accerlation.

Ocean waves are hitting a beach with a frequency of 0.100 Hz. Their average wavelength is 15.0 m. What is their average speed?
What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of 0.32 m?

Answers

Answer:

Average speed=1.5 m/s

Frequency of pendulum=93.75Hz

Explanation:

We are given

Frequency, [tex]f=0.100Hz[/tex]

Average wavelength =[tex]\lambda=15m[/tex]

Speed of pendulum, [tex]v=30m/s[/tex]

Wavelength, [tex]\lambda'=0.32m[/tex]

We have to find the average speed and frequency of pendulum.

We know that

Speed,[tex]v=\lambda f[/tex]

Using the formula

Average speed,[tex]v=15\times 0.1=1.5m/s[/tex]

Hence, the average speed =1.5m/s

Frequency, [tex]f=\frac{v}{\lambda'}[/tex]

Using the formula

[tex]f=\frac{30}{0.32}[/tex]

[tex]f=93.75Hz[/tex]

Hence, the frequency of a pendulum=93.75Hz

A que profundidad esta nadando una persona dentro de una alberca si la presión absoluta sobre ésta es de 156kPa?

Answers

Answer:

La persona está nadando en la alberca a una profundida de 5.575 metros.

Explanation:

La presión absoluta ([tex]P_{tot}[/tex]) experimentada por la persona es la suma de la presión atmosférica ([tex]P_{atm}[/tex]) y la presión hidrostática de la columna de agua de la alberca ([tex]P_{h}[/tex]), medidas en kilopascales. Es decir,

[tex]P_{tot} = P_{atm}+P_{h}[/tex] (1)

[tex]P_{tot} = P_{atm} + \frac{\rho\cdot g \cdot z}{1000}[/tex] (2)

Donde:

[tex]\rho[/tex] - Densidad del fluido de la alberca, medida en kilogramos por metro cúbico.

[tex]g[/tex] - Aceleración gravitacional, medida en metros por segundo al cuadrado.

[tex]z[/tex] - Profundidad de la persona en la alberca, medida en metros.

Si sabemos que [tex]P_{atm} = 101.325\,kPa[/tex], [tex]\rho = 1000\,\frac{kg}{m^{3}}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] y [tex]P_{tot} = 156\,kPa[/tex], entonces la profundidad de la persona en la alberca es:

[tex]156 = 101.325 +\frac{(1000)\cdot (9.807)\cdot z}{1000}[/tex]

[tex]54.675 = 9.807\cdot z[/tex]

[tex]z = 5.575\,m[/tex]

La persona está nadando en la alberca a una profundida de 5.575 metros.

6. Suppose the resistance of your body between your right and left hands is 500,000 N. What
would be the current flowing through your body if you touched the plus and minus terminals of
a 120 V battery? The threshold of sensation for electric current through your body is about
300 PA. Would you feel the current?


HELP PLS

Answers

Explain more please (lesson)

A car is moving with 15000J of energy. If the car has a mass of 1500kg, how fast is it moving?

Answers

Answer:

V=4.5 m/s

Explanation:

KE=1/2mv^2

1500=1/2(15000)v^2

answer :4.5m/s

Explanation:

V=30,000J/1500kg

V=20m²/s²

V=4.5m/s

what are the unique characteristics of romantic music which are not present in Original Pilipino Music (OPM)​

Answers

Answer:

ITU Sangat bermanfaaat

write any four importance of pressure​

Answers

Answer:

Here is your ans

Explanation:

hope it helps you tq

Motion and acceleration may only be used to refer to physical objects moving or changing speed/direction

Answers

Answer:

True

Explanation:

It is TRUE that Motion and acceleration may only be used to refer to physical objects moving or changing speed/direction.

This is because if an object is not moving or changing speed/direction to a determined point of reference, the object is considered to be at rest or motionless, thereby, with no absolute point of reference, absolute motion or acceleration cannot be distinguished.

lonic and Covalent compound formed through atomic bond formation. With the given
chemical formula, write the characteristic of the given properties.​

Answers

Answer:

1) Sucrose C₁₂H₂₂O₁₁

Common name; Sugar

Types of Compound ; Covalent Compound

Melting point; No melting point, it decomposes when heated

Electrical conductivity; Does not conduct electricity when dissolved in water

Solubility in water; Soluble in water

2) C₉H₈O₄ (Acetyl Salicylic acid)

Common name; Aspirin

Types of Compound ; Covalent Compound

Melting point; High

Electrical conductivity; Does not conduct electricity when dissolved in water

Solubility in water; Slightly soluble in water

3) NaCl (Sodium Chloride)

Common name; Salt

Types of Compound ; Ionic Compound

Melting point; High

Electrical conductivity; Conducts electricity when dissolved in water

Solubility in water; Soluble in water

4) C₅H₈NO₄Na (Monosodium Glutamate (MSG)

Common name; Vetsin

Types of Compound ; Ionic Compound

Melting point; High

Electrical conductivity; Conducts electricity when dissolved in water

Solubility in water; Soluble in water

5) C₈H₁₈ (Octane)

Common name; Common gasoline

Types of Compound ; Covalent Compound

Melting point; Low

Electrical conductivity; Does not conducts electricity and insoluble in water

Solubility in water; Relatively insoluble in water

Explanation:

what type of em waves is fm radio? And how it is used in wireless communication?​

Answers

Answer:

Radio waves are used for wireless transmission of sound messages, or information, for communication, as well as for maritime and aircraft navigation. The information is imposed on the electromagnetic carrier wave as amplitude modulation (AM) or as frequency modulation (FM) or in digital form (pulse modulation).

Explanation:

Qué estudios se realizan en la actualidad para utilizar la electricidad de una manera más eficiente?

Answers

Answer:

Se realizan estudios en tres áreas: a) Procesos de transformación de la energía, b) Almacenamiento de la energía, c) Gestión inteligente entre consumo y generación.

Explanation:

Actualmente, se están realizando estudios en principalmente en tres áreas cruciales: a) Procesos de transformación de la energía, b) Almacenamiento de la energía, c) Gestión inteligente entre consumo y generación.

a) Se están desarrollando nuevos materiales que permiten mayor eficiencia entre la energía recibida y la energía eléctrica, además de una mayor durabilidad frente a las condiciones ambientales. Esto implica el mejoramiento del desempeño de las tecnologías basadas en las energías renovables y limpias, acortando su brecha con las energías no renovables.

b) Se están desarrollando nuevos materiales que garanticen una mayor densidad energética y mayor durabilidad, significando baterías más compactas, con mayor capacidad y más competitivas económicamente.

c) Se están desarrollando estrategias de control inteligente a tiempo que permite sincronizar el consumo y la generación, además de posibilitar el flujo bidireccional de la energía a través de una red inteligente (smart grid) e integrar mejor las fuentes renovables dentro de la matriz energética.

If a storm is 7.5 kilometers away, how much time is expected between observations of lightning and thunder?

Answers

Answer. Time taken to hear the thunder is : 7500 / 343 = 21.88 Seconds.

Answer:

≈ 22 seconds

Explanation:

7,5 km = 7500 m

Speed of light 300 000 000 m/s (for lightning)

Speed of sound 343 m/s (for thunder)

time = distance / speed

lightning time = 7500 m / 300 000 000 m/s = 0.000025 s

thunder time = 7500 m / 343 m/s ≈ 22 s

thunder time - lightning time = 22 s - 0.000025 s ≈ 22 s

All weather stations have to make weather observations at the same time of the day.

True
False

Answers

Answer:

false

Explanation:

Answer:

True

Explanation:

The answer is true do not listen to the other person they will get you wrong just look at the votes between mine and the other person's (hint like my answer and rate 5 stars so other people know what to pick)

True or false. Your weight will change on the moon

Answers

The answer to this is true
hi! i searched online, and it says an object on the moon weighs less than it does on earth, so true.

hope this helps!:)

Mercury has the most eccentric (least circular) orbit of all the planets in the Solar System. At aphelion it is 0.467 AU from the Sun while at perihelion it is only 0.308 AU from the Sun. What is Mercury's orbital period in Earth-days?

Answers

Answer:

Mercury's orbital period is approximately 88 days

Explanation:

Mercury's orbit parameters given in the question are;

Mercury's aphelion distance, Rₐ = 0.467 AU

Mercury's perihelion distance, [tex]R_p[/tex] = 0.308 AU

Therefore, the average distance from Mercury to the Sun, 'a', is given as follows;

[tex]a = \dfrac{R_a + R_p}{2}[/tex]

By plugging in the values of 'Rₐ' and '[tex]R_p[/tex]', we get;

[tex]a = \dfrac{R_a + R_p}{2} = \dfrac{0.467 \, AU + 0.308 \, AU}{2} = 0.3875 \, AU[/tex]

a = 0.3875 AU

According to Kepler's third law, we have;

P² = k·a³

Where;

P = The orbital period of the plane

a = The average distance from Mercury to the Sun

k = Constant

When k = 1, we have;

P² = a³

∴ P = √(a³)

From which we have;

P = √(0.3875 AU)³ ≈ 0.241216804711 years

P ≈ 0.2412168 years

1 year = 365 days

∴ 0.241216804711 years = 0.241216804711 years × 365 days/year ≈ 88.0441337 days

0.241216804711 years ≈ 88.0441337 days ≈ 88 days

Mercury's orbital period, P ≈ 88 days.

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