Answer:
6° because some heat is released out of surrounding. if 100 over six which is equal to sixtenn point four
A block slides down a frictionless plane having an inclination of θ=15.00. The block starts from rest at the top, and the length of the incline is 2.00m. (a) Draw a free-body diagram of the block. Find (b) the acceleration of the block and (c) its speed when it reaches the bottom of the incline.
(a) Free-body diagram of block is as given below. (b) Acceleration of the block is 2.529 m/s². (c) Speed of the block when it reaches the bottom of the incline is 3.18 m/s.
What is frictionless surface?Frictionless surface is an invented concept of surface that is based on imagination and creative ideas of scientists where assumed friction of surface is zero.
(a) Free-body diagram of block is:
/|
/ |
/ | m
/ θ |
/ |
/_____|
f ||
||
||
||
\/
where m is mass of the block, θ is angle of inclination, f is force of friction (which is zero in this case), and g is acceleration due to gravity acting vertically downwards.
(b) The force acting along incline is component of the weight of block parallel to the incline, given by mg sin θ, where m is the mass of the block and g is acceleration due to gravity. Since there is no friction, this force is equal to net force acting on block, which is ma, where a is acceleration of block along the incline. Therefore,
mg sin θ = ma
a = g sin θ
a = 9.81 m/s² * sin 15.00 = 2.529 m/s²
Therefore, the acceleration of the block is 2.529 m/s².
(c) v² = u² + 2as
where u is the initial velocity (which is zero), s is the displacement (which is 2.00 m along the incline), and a is the acceleration (2.529 m/s²). Solving for v, we get:
v = √(2as) = √(2 * 2.00 m * 2.529 m/s²) = 3.18 m/s
Hence, speed of block when it reaches bottom of incline is 3.18 m/s.
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Many roller coasters function by mechanically transporting the cars up a large incline. The cars then roll down and up a series of hills, turns, and spirals until the cars come to rest at the passenger loading station. At which point will the roller coaster have the greatest amount of gravitational potential energy?
The roller coaster will have the greatest amount of gravitational potential energy at the top of the incline, just before the cars are released to roll down the track.
Electrical energy is transferred between the main and secondary coils of a transformer through a magnetic circuit that is created by the iron core. A magnetic field that is continuously changing is produced in the iron core when an alternating current is fed through the primary coil. Energy is transferred between the coils as a result of the magnetic field's induction of a matching current in the secondary coil. Because of its high permeability and sensitivity to magnetism, the iron core can magnetize. A greater induced current is produced in the secondary coil as a result of the first coil's magnetic field being amplified by the iron core's magnetization. The effective transmission of electrical energy in a transformer depends on the magnetic characteristics of the iron core. The roller coaster will therefore have the most potential energy at the highest point of the trip.
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A bicycle wheel is rotating at 40 rpm when the cyclist begins to pedal harder, giving the wheel a constant angular acceleration of 0.47 rad/s^2.
(a) What is the wheel's angular velocity, in rpm, 7.0 s later?
(b) How many revolutions does the wheel make during this time?
a) The wheel's angular velocity after 7.0 s is 43.29 rpm.
b) The wheel makes 4.66/2π or 0.74 revolutions in this time.
What is Angular velocity?a)The angular velocity, constant angular acceleration:
ω = ω0 + αt
Where, ω is the final angular velocity
ω0 is the initial angular velocity
α is the constant angular acceleration
t is the time elapsed
Substituting the given values,
ω = ω0 + αt
= 40 rpm + 0.47 rad/s² × 7 s
= 40 rpm + 3.29 rpm
= 43.29 rpm
B)The number of revolutions, the total angle rotated by the wheel is in radians.
θ = ω0t + 1/2αt²
Where θ is the total angle rotated in radians t is the time elapsed
Substituting the given values,
θ = ω0t + 1/2αt²
= (2π × 40 rpm/60) × 7.0 s + 0.5 × 0.47 rad/s² × (7.0 s)²
= 4.66 rad
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the third kepler law: relationship between the distance from the sun and the orbital period for a planet. we discussed the third kepler law in class. scientists are still using telescopes to observe the space beyond neptune in our solar system. in principle, it is possible that scientists will find astronomical bodies larger than eris/pluto in the future. let us assume that a new planet with an orbital period ~ 6548 years is discovered in our solar system. please take earth as a reference and calculate the average distance from the sun for the newly-discovered planet in our solar system.A. ∼200AUB. ∼220AUC. ∼240AUD. ∼260AU
According to the Third Kepler Law, the average distance from the Sun (A) is directly proportional to the cube root of the orbital period (T). So, for a new planet with an orbital period of 6548 years, we can calculate the average distance (A) using the equation: A = (T^(1/3)) x (A_earth^(2/3)), where A_earth is the average distance of the Earth from the Sun, which is approximately 150 million km.
Plugging in the given values, we get: A = (6548^(1/3)) x (150x10^6 km)^(2/3) = ∼260AU.
Therefore, the average distance from the Sun for the newly-discovered planet in our solar system is ∼260AU.
The average distance from the sun for the newly-discovered planet in our solar system is approximately 240AU.Kepler's third law states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. It states that "the square of the period of revolution of a planet is proportional to the cube of the semi-major axis of its orbit." Kepler's third law mathematically connects the distance of a planet from the sun and its orbital period, that is, a planet's "year" or "revolution."The equation used to relate the third Kepler law is: T2 = (4π2 a3) / GMWhere T is the orbital period, a is the semi-major axis of the orbit, G is the gravitational constant, and M is the mass of the Sun. The value of T is provided as 6548 years, which is substituted in the equation above:6548^2 = (4π2 × a3) / (6.674 × 10-11 × 1.989 × 1030)Solving for a, we get:a = 239.8 ≈ 240 AU.Hence, the answer is option C. ~240AU.
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a 135-kg k g astronaut (including space suit) acquires a speed of 2.70 m/s m / s by pushing off with her legs from a 1900-kg k g space capsule. use the reference frame in which the capsule is at rest before the push.
A) What is the velocity of the space capsule after the push in the reference frame? B)If the push lasts 0.660 s , what is the magnitude of the average force exerted by each on the other? C)What is the kinetic energy of the astronaut after the push in the reference frame? D)What is the kinetic energy of the capsule after the push in the reference frame? I am down to only one answer left on A and B and cannot seem to get them correct, so if you could work it out for me that would be the best. Thank you.
A) Velocity of the space capsule after the push in the reference frame= - 0.042 m/s .B) Magnitude of the average force exerted by each on the other= 462 N.C) Kinetic energy of the astronaut after the push in the reference frame= 614 J. D) Kinetic energy of the capsule after the push in the reference frame= 22.8 J
Explanation:Given dataMass of astronaut= 135 kgSpeed of astronaut= 2.70 m/sMass of space capsule= 1900 kgTime taken by astronaut to acquire speed= 0.66 secondsWe have to find- the velocity of the space capsule after the push in the reference frame- the magnitude of the average force exerted by each on the other- the kinetic energy of the astronaut after the push in the reference frame- the kinetic energy of the capsule after the push in the reference frameThe first step is to use conservation of momentum to find the velocity of the space capsule after the push in the reference frame.Conservation of momentum Initial momentum= Final momentum(1900 kg) (0 m/s) = (1900 kg + 135 kg) (v)V = -0.042 m/sThis negative sign indicates that the space capsule moves backward. A) Velocity of the space capsule after the push in the reference frame= - 0.042 m/sThe second step is to use the impulse-momentum theorem to find the average force exerted by each on the other. Impulse= change in momentum .We have the initial and final momenta from the conservation of momentum.Velocity before push= 0Velocity after push= -0.042 m/sImpulse= mΔv= (1900+135)(-0.042-0)NΔt= Impulse = Δp = 1900.042/0.66N= 462 NC) Magnitude of the average force exerted by each on the other= 462 NThe third step is to find the kinetic energy of the astronaut after the push in the reference frame.Kinetic energy= ½ mv²Kinetic energy of astronaut= ½ (135) (2.70)²J= 614 JD) Kinetic energy of the capsule after the push in the reference frame.Kinetic energy of space capsule= ½ (1900) (-0.042)²J= 22.8 J.
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A student investigated how the mass of water in an electric kettle affected the time taken for the water to reach boiling point.
The kettle switched off when the water reached boiling point.
Figure 1 shows the kettle.
(a) The heating element of the kettle was connected to the mains supply.
Explain why the temperature of the heating element increased.
___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
(2)
(b) Give one variable that the student should have controlled.
___________________________________________________________________
___________________________________________________________________
(1)
Figure 2 shows how the mass of water in the kettle affected the time taken for the kettle to switch off.
Figure 2
(c) Suggest why the line on Figure 2 does not go through the origin.
___________________________________________________________________
___________________________________________________________________
(1)
(d) Suggest why the results give a non-linear pattern.
___________________________________________________________________
___________________________________________________________________
(1)
Can someone please answer part (c)? Please
The line does not go through the origin because there is some inherent delay in the heating process that is not dependent on the mass of water in the kettle.
Part (c) asks to suggest why the line on Figure 2 does not go through the origin. The line on Figure 2 represents the relationship between the mass of water in the kettle and the time taken for the kettle to switch off.
Boiling point refers to the temperature at which a liquid substance turns into a gas or vapor. The boiling point of a substance depends on various factors, such as its molecular structure, intermolecular forces, and atmospheric pressure.
The boiling point of a substance remains constant under a given pressure, and any additional heat input during boiling will only cause the temperature of the vapor to increase rather than the liquid. The boiling point is an important physical property of a substance, and it can be used to determine the purity of a liquid through the process of distillation. The boiling point of water is 100 degrees Celsius at standard atmospheric pressure (1 atm), while the boiling point of ethanol is 78.5 degrees Celsius.
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f the initial energy of a conservative system is ei and the final energy is ef, what can we say about the relationship between these two energies in such a system?
In a conservative system, the total energy is conserved, which means that the initial energy (ei) is equal to the final energy (ef).
What are conservative system?Conservative systems are those where the total energy remains constant over time, such as in a pendulum swinging back and forth or a planet orbiting a star under the influence of gravity.
In such systems, the energy can be converted from one form to another, but the total amount of energy remains constant.
Therefore, we can say that in a conservative system, the initial energy (ei) and the final energy (ef) are equal. This means that any changes in the system's energy, such as potential energy being converted into kinetic energy, must be balanced by an equal and opposite change in some other form of energy, such as potential energy being converted into kinetic energy.
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The skater with a mass of 50 kg slides on an ice track with a speed of 5 m/s. How fast will she move if she throws a 2kg stone horizontally, once in front of her and once behind her, at a speed of 2m/s? Friction is not considered.
4.92 m/s for her final velocity.
Explanation:The momentum of the skater before throwing the stone is:
p1 = m1 * v1 = 50 kg * 5 m/s = 250 kg*m/s
where m1 is the mass of the skater and v1 is her initial velocity.
When the skater throws the stone, the total momentum of the system (skater + stone) is conserved. The momentum of the stone is:
p2 = m2 * v2 = 2 kg * 2 m/s = 4 kg*m/s
where m2 is the mass of the stone and v2 is its velocity.
Let's assume the skater throws the stone in front of her. To conserve momentum, the skater will move in the opposite direction to the stone. Let's call the skater's final velocity v3. Then:
p1 = p2 + p3
where p3 is the momentum of the skater after throwing the stone. Substituting the values we get:
250 kgm/s = 4 kgm/s + 50 kg * v3
Solving for v3, we get:
v3 = (250 kgm/s - 4 kgm/s) / 50 kg = 4.92 m/s
So the skater's speed after throwing the stone in front of her is 4.92 m/s.
If the skater throws the stone behind her, the same conservation of momentum principle applies, and we get the same result of 4.92 m/s for her final velocity.
Sorry if I'm wrong
A 2. 00-kg object is attached to an ideal massless horizontal spring of spring constant 100. 0 N/m and is at rest on a frictionless horizontal table. The spring is aligned along the x-axis and is fixed to a peg in the table. Suddenly this mass is struck by another 2. 00-kg object traveling along the x-axis at 3. 00 m/s, and the two masses stick together. What are the amplitude and period of the oscillations that result from this collision? 0. 300 m, 1. 26 s 0. 424 m, 5. 00 s 0. 424 m, 0. 889 s 0. 300 m, 0. 889 s 0. 424 m, 1. 26 s
The correct option is A, the amplitude and period of the oscillations that result from this collision are 0.300 m in 1.26s.
The expression for Period of spring is,
[tex]T = 2\pi\sqrt{\frac{2m}{k} }[/tex]
Here, m is the mass of the spring and k is the spring constant
Substitute 2 kg
for m
and 100N/m
for k
in equation [tex]T = 2\pi\sqrt{\frac{2m}{k} }[/tex]
and solve for T .
[tex]T = 2\pi\sqrt{\frac{(2)2 kg}{100 N/m} }[/tex]
T = 1.26s
In physics, amplitude refers to the maximum displacement or distance moved by a wave from its equilibrium or mean position. It is a measure of the intensity or strength of a wave, and it is usually represented as the height of the crest or depth of the trough of the wave.
The amplitude of a wave can be measured in various units, depending on the type of wave and the context in which it is being studied. For example, the amplitude of a sound wave is measured in decibels (dB), while the amplitude of an electromagnetic wave is measured in volts per meter (V/m). Amplitude plays an important role in the behavior of waves. It determines the energy carried by the wave and affects other properties such as frequency, wavelength, and phase.
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Complete Question: -
A 2.00-kg object is attached to an ideal massless horizontal spring of spring constant 100.0 N/m and is at rest on a frictionless horizontal table. The spring is aligned along the x-axis and is fixed to a peg in the table. Suddenly this mass is struck by another 2.00-kg object traveling along the x-axis at 3.00 m/s, and the two masses stick together. What are the amplitude and period of the oscillations that result from this collision
A) 0.300 m, 1.26 s
B) 0.300 m, 0.889 s
C) 0.424 m, 0.889 s
D) 0.424 m, 1.26 s
E) 0.424 m, 5.00 s
How much force would you exert if your car weighs 1,302 and your acceleration rate is -6.1 m/s
Answer:
-7,942.2 Newtons
Explanation:
Car Force Calculation.
How much force would you exert if your car weighs 1,302 and your acceleration rate is -6.1 m/s
To calculate the force exerted by a car, we can use the formula:
force = mass x acceleration
where mass is the mass of the car in kilograms, and acceleration is the acceleration rate in meters per second squared (m/s^2).
Given that the car weighs 1,302 kg and the acceleration rate is -6.1 m/s^2, we can plug these values into the formula:
force = 1,302 kg x (-6.1 m/s^2)
force = -7,942.2 Newtons (N)
The negative sign indicates that the force is in the opposite direction of the acceleration, which in this case is towards the back of the car.
Point charges 1 mC and -2 mC are located at (3, 2, -1) and (-1, -1, 4) respectively. Calculate the electric force on a 10 nC charge located at (0, 3, 1) and the electric field intensity at that point.
The electric field intensity at the same point due to the two point charges is -4.13e5 N/C.
Electric force is the force experienced by a charged object placed in an electric field. The electric force formulation is sometimes confused with Coulomb's law, but the electric force is more general than Coulomb's law and applies only to two-point charges.
The electric force on a 10 nC charge located at (0, 3, 1) due to the two point charges is given by:
F = (1e-7 N m²/C²) × [(1e-3 C) / (3² + 4² + 5²)³/2 + (-2e-3 C) / (8² + 8² + 9²)³/2]
F = -4.13e-5 N
The electric field intensity at the same point due to the two point charges is given by:
E = F / (10e-9 C)
E = -4.13e5 N/C
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Two students are working together to build a birdhouse. Student 1 applies a force of 10 N to a wooden board in order to slide it across the table to Student 2.
Answer:
6n
Explanation:
Given:
Force acting by student 1 = 10 N
Force acting by student 2 = 4 N
Find:
Net force acting on the board
Computation:
Net force acting on the board = Force acting by student 1 - Force acting by student 2
Net force acting on the board = 10 N - 2 N
Net force acting on the board = 6 N
a fireman' s hose is pointed vertically upward at a height of 1.5 m above the ground and a stream of water is coming from it . when the water is shut off, the noise of the water hitting the ground continues for another 2.0 s . what was the speed of the water as it left the hose?
The fireman's hose is pointed vertically upwards at a height of 1.5 m above the ground and a stream of water is coming from it. When the water is shut off, the noise of the water hitting the ground continues for another 2.0 s, the speed of the water as it left the hose is 4.31 m/s.
What is the definition of a fireman?A firefighter, also known as a fireman or firewoman, is a professional who is trained and equipped to put out fires, rescue people and animals from dangerous situations, and manage other emergency situations.
The water comes to rest after it reaches the ground, so it moves at constant acceleration in the vertical direction. Since the final velocity is zero, the initial velocity and the displacement can be used to calculate the time of flight.
The speed at which the water left the hose can then be determined using the time of flight and the height of the hose above the ground.
Initial velocity = v₀, Final velocity = vf = 0.
Displacement = h = 1.5 m
Acceleration = a = g = 9.8 m/s²
Time of flight = t
Using the formula ,vf = v₀ + at₀ = v₀ + gt
v₀ = -gt
displacement = v₀×t + 1/2×at²
h = -1/2 × gt²
t = sqrt(2h/g) = sqrt(2(1.5)/9.8) = 0.44 s.
Using the formula, vf = v₀ + at
vf = 0 + gtvf = 9.8 × 0.44 = 4.31 m/s.
The water's speed as it leaves the hose is 4.31 m/s.
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what process produces the light and heat of the sun?
Answer:
The light and heat of the sun are produced by the process of nuclear fusion, where hydrogen atoms combine to form helium, releasing vast amounts of energy in the process.
a charge is passing through a static magnetic field. the velocity of the charge makes a 90o angle with the field. the force exerted by the magnetic field does work on the charge.
The statement is True, A charge is passing through a static magnetic field. the velocity of the charge makes a 90o angle with the field. the force exerted by the magnetic field does work on the charge.
The magnetic force exerted on a moving charge with a velocity in the presence of a magnetic field is given by F = qvBsinθ
Magnetic force is a fundamental force that arises due to the motion of electric charges. It is the force that acts between two magnetic poles or between a magnetic pole and a moving charged particle. Magnetic force is a vector quantity and is described in terms of its direction, magnitude, and point of application.
The force between two magnetic poles is governed by the inverse square law, which means that the force decreases as the distance between the poles increases. The direction of the magnetic force is perpendicular to the direction of motion of the charged particle and to the direction of the magnetic field in which it moves. The magnitude of the magnetic force is proportional to the charge of the particle, its velocity, and the strength of the magnetic field.
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a compacted sample of hma contains 5.1 percent asphalt by weight of total mix, and the bulk density of the hma specimen is 2455kg/m3. the specific gravity of aggregate and the asphalt binder are 2.735 and 1.022, respectively. determine the vma, vtm, and vfa, neglect-ing absorption. draw sketch and write out full equations used. no sketch and missing full equations written out, minus -5 points. fyi, following solution is not solved completely as above solution requirement.
The void in mineral aggregate (VMA) is -12.35%, the void in total mix (VTM) is 0.000990 and the voids filled with asphalt (VFA) is -12.35%.
To determine the VMA, VTM, and VFA neglecting absorption, we need to calculate the following:
[tex]VMA = [(Gmb - Gsb) / Gmb] \times 100[/tex]
[tex]VTM = Gmb / ρb[/tex]
[tex]VFA = [(Gmb - Ga) / Gmb] \times 100[/tex]
Where, Gmb = bulk specific gravity of the compacted specimen of HMA.
Gsb = bulk specific gravity of the aggregate in the HMA specimen.
ρb = bulk density of the HMA specimen
Ga = apparent specific gravity of the aggregate in the HMA specimen.
Substitute the given values we get:
[tex]Gmb = 2.435, Gsb = 2.735, \rho b = 2455\ kg/m^3[/tex],
[tex]Ga = (Gmb \times Gsa) / (5.1 + 0.049 (Gmb - 2.435)) = (2.435 \times 2.735) / (5.1 + 0.049 (2.435 - 2.435)) = 2.449[/tex]
By substituting these values in the above formula, we get:
[tex]VMA = [(2.435 - 2.735) / 2.435] \times 100 = -12.35[/tex]%
[tex]VTM = 2.435 / 2455 = 0.000990[/tex]
[tex]VFA = [(2.435 - 2.735) / 2.435] \times 100 = -12.35[/tex]%
Hence, VMA = -12.35%, VTM = 0.000990, VFA = -12.35%.
The minus sign indicates that the voids are insufficient. Therefore, the mix is unstable.
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water stands at a depth H in a large, open tank whose sidewalls are vertical. a hole is made in one of the walls at adepth h below the water surface.
a)at what distance R from the foot of the wall does theemerging stream strike the floor?
b)how far above the bottom of the tank could a second hole becut so that the stream emerging from it could have the same rangeas for the first hole?
2hcosθsinθ is the distance R from the foot of the wall the emerging steam strike the floor.
the second hole should be cut at a height of (H - h/4) above the bottom of the tank in order to get the same range as the first hole.
Let's derive an expression for the velocity of water coming out of the hole. The water coming out of the hole is a free fall under gravity .
So we can use Bernoulli's equation to find the velocity of the water coming out of the hole as:
P + (1/2)ρv² + ρgh = constant ….(1)
where P is the pressure of the water inside the tank,
ρ is the density of water,
v is the velocity of the water coming out of the hole,
h is the height of the water level inside the tank, and g is the acceleration due to gravity.
Since the hole is below the water's surface, the pressure at the hole is the pressure due to water at the second hole should be cut at a height of (H - h/4) above the bottom of the tank in order to get the same range as for the first hole.
depth h. So, the pressure due to water is ρgh.
At the hole, the velocity of water is v, and the height of the water surface above the hole is (H - h). Therefore, the pressure at the surface of the water is ρg(H - h). Putting these values in equation (1), we get:
P + (1/2)ρv² + ρgh = ρg(H - h) + P₀
Where P₀ is atmospheric pressure, which can be considered constant. This is the Bernoulli's equation.
Let's apply the law of conservation of mechanical energy.
Let the velocity of the water coming out of the hole be v.
The kinetic energy of the water at the hole is (1/2)ρv².
The gravitational potential energy of the water at the hole is ρgh.
The gravitational potential energy of the water at the point where it hits the floor is zero.
Hence, by the law of conservation of mechanical energy, we can write:
(1/2)ρv² + ρgh = 0
Solving for v, we get:
v = √(2gh)
Part a) of the question:
We know the velocity of the water coming out of the hole. Let's assume that the stream coming out of the hole makes an angle of θ with the horizontal, as shown in the figure.
We need to find the horizontal distance R from the foot of the wall at which the stream hits the floor. This is given by:
R = (v²/g)sin2θ
sin2θ can be written as 2sinθcosθ. Therefore, we get:
R = (v²/g)sinθcosθ
Using the value of v from above, we get:
R = (2gh/g)sinθcosθ = 2hcosθsinθ
Part b) of the question:
Let's assume that the second hole is cut at a depth x above the bottom of the tank. We need to find the value of x such that the stream emerging from it could have the same range as for the first hole.
This means that the horizontal distance R must be the same for both holes. Using the expression for R from above, we get:
2hcosθsinθ = (2gh/g)sinθcosθ
Simplifying, we get:
x = H - h/4
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Since moving charges create magnetic fields and magnetic fields exert forces on moving charges, devices that are used to measure field strengths often affect the system they are being used to measure. Consider the wire segment in the figure, which is used to measure the magnetic field by determining the foree exerted on the current flowing through it. Part (a) Estimate the field the loop creates by calculating the field strength, in teslas, at the center of a circular loop 20.0 cm in diameter carrying
Part (b) What is the smallest field strength this loop can be used to measure with a 4.5 -A current, if its field should alter the measured field by 0.0100% or less?
a) The magnetic field at the center of loop 20.0 cm in diameter carrying is equals to the 2.8274×10⁻⁵ T.
b) Smallest magnetic field that change measured value by 0.0100% is equals to the 2.8274×10⁻⁹ T.
We know that moving charges create magnetic fields and magnetic fields exert forces on moving charges, devices that are used to measure field strengths. Consider the wire segment present in above figure.
A) Diameter of wire segment, d = 20 cm or 0.2 m carrying current I = 4.5 A
Magnetic Field at the center of current loop of segment, B= μ₀I/d
= 4π×10⁻⁷×4.5/0.2
= 2.8274×10⁻⁵ T
Therefore magnetic Field at the center of current loop 2.8274×10⁻⁵ T.
B) Current in carrying wire, I = 4.5 A
The field should be less than the measured field by 0.0100%. So, smallest field that change measured value by 0.0100% = 0.0100% of 2.8274×10⁻⁵ T
= 2.8274×10⁻⁹ T
Therefore Smallest field that change measured value by 0.0100% = 2.8274×10⁻⁹ T
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Complete question:
The above figure completes the question.
Since moving charges create magnetic fields and magnetic fields exert forces on moving charges, devices that are used to measure field strengths often affect the system they are being used to measure. Consider the wire segment in the figure, which is used to measure the magnetic field by determining the foree exerted on the current flowing through it. Part (a) Estimate the field the loop creates by calculating the field strength, in teslas, at the center of a circular loop 20.0 cm in diameter carrying
Part (b) What is the smallest field strength this loop can be used to measure with a 4.5 -A current, if its field should alter the measured field by 0.0100% or less?
suppose the ring rotates once every 4.10 s . if a rider's mass is 51.0 kg , with how much force does the ring push on her at the top of the ride?
The ring rotates once every 4.10 s. If a rider's mass is 51.0 kg, how much force does the ring push on her at the top of the ride is 500 N.
The solution is explained below:
As the rider is at the top of the ride, the only force acting on him is the force of gravity, which is pointing downwards, and the force with which the ring is pushing him towards the center of the circular path. By equating both forces, we can determine the required force to maintain the rider at the top of the ride.
Hence, the answer to the question is that the force with which the ring pushes the rider at the top of the ride is equal to the force of gravity, which is given as F = mgF = (51.0 kg)(9.81 m/s^2) = 500 N
Therefore, the force with which the ring pushes on the rider at the top of the ride is 500 N.
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A conducting ring sits in a magnetic field directed into the page that is decreasing in magnitude as a function of time. Is a current induced in the ring? If so, what is the direction of current induced in the ring?
(a) clockwise
(b) counterclockwise
(c) The induced current is zero.
A conducting ring sits in a magnetic field directed into the page that is decreasing in magnitude as a function of time. A current induced in the ring, the direction of current induced in the ring is b. counterclockwise.
Electromagnetic induction is a phenomenon where an electromotive force (EMF) is produced in a closed-loop wire when there is a change in the magnetic field within the loop. Electromagnetic induction is based on Faraday's Law, which is one of Maxwell's equations. It's named after Michael Faraday, who discovered it. The magnetic flux through the loop (N = number of turns) and the time rate of change of the magnetic field (ΦB) is what produces the EMF, according to Faraday's Law.
The Faraday's Law is shown below:- ε = -N (dΦB / dt)Where ε is the EMF and ΦB is the magnetic flux. The negative sign indicates that the EMF's direction opposes the change in magnetic flux, according to Lenz's Law. A conducting ring sits in a magnetic field directed into the page that is decreasing in magnitude as a function of time. Is a current induced in the ring? Yes, a current is induced in the ring.What is the direction of current induced in the ring?The induced current in the ring is counterclockwise.
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If work is done on an object, the object has more energy than it did before. This energy can come from increases in kinetic energy, potential energy, and/or _____.
If work is done on an object, the object has more energy than it did before. This energy can come from increases in kinetic energy, potential energy, and/or internal energy.
The energy transferred into an object by an external force is the work done on that object. The unit of work is the joule (J). Work can be expressed as a dot product of the force and the displacement, as given below:
W = F . d
Energy is the capacity of a system to do work. There are many different forms of energy, which can be classified as kinetic, potential, or internal energy.
Kinetic energy is the energy of motion. The kinetic energy of an object of mass m and velocity v is given by the equation below:
K = (1/2)mv²
Potential energy is the energy that a system possesses because of its position in a gravitational or electric field. A body's potential energy depends on its mass, height, and position. An object has gravitational potential energy when it is in a position that can potentially fall to a lower height. A system's electric potential energy is a result of the potential difference between two points.
Internal energy is the energy that a system possesses due to the motion of its atoms and molecules. The total energy of a system is the sum of its kinetic and potential energy. The internal energy of a system is the sum of the energy associated with the motion and position of its atoms and molecules. When energy is transferred to a system by an external force, some of that energy is converted to internal energy.
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The graph shows the distance an object traveled in 11 seconds.
The best describes the movement of the object between the times of 0 and 6 on the graph is moving at a constant speed. Therefore, option A is correct.
What is the movement of an object ?Moving occurs when an object's location compared to a fixed spot changes. Even seemingly stationary things shift. When one item moves in connection to another, we say it is moving relative to the other object.
Kinematics is the field of physics concerned with forces and their effects on motion, whereas dynamics is concerned with forces and their effects on motion. When a force pushes or draws on an item, it moves in the same way as the force.
Thus, option A is accurate because the object moves at a consistent pace between periods 0 and 6 on the graph.
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Which of the following transitions would emit the shortest wavelength? select one; (a) n=2 to 1 (b) n=1 to 3 (c) n=1 to 2 (d) n=3 to 1
(d) n=3 to 1 would emit the shortest wavelength. Due to the largest energy differential between the two energy levels, the transition from n=3 to n=1 would emit the shortest wavelength.
Electromagnetic radiation, such as light, is released when an electron moves from a higher energy level (n) to a lower energy level (m). E = hc/, where E is the energy, h is Planck's constant, c is the speed of light, and is the wavelength of the radiation, relates the energy of the emitted radiation to the energy difference between the two levels.
Transitions to lower energy levels release greater energy photons with shorter wavelengths because as n decreases, energy levels move closer together. Option (d) is the appropriate response since the transition from n=3 to n=1 has the greatest energy difference and hence the shortest wavelength.
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why can astronomers not measure the diameters of stars directly?
Astronomers can't measure the diameter of stars directly due to their vast distance and small apparent sizes. Indirect methods, such as studying brightness, temperature, and gravitational influence, are used instead.
Since stars are so far away from Earth and appear to be very small, astronomers are unable to directly estimate the diameters of stars. When seen via a telescope, even the greatest stars in our galaxy are only visible as tiny specks of light. It is also challenging to pinpoint the exact stellar borders since the light that stars generate is a complex mixture of wavelengths and intensities. To determine the sizes of stars, astronomers may, however, use a range of indirect techniques, including examining the brightness and temperature of the stars, their gravitational pull on surrounding objects, and the way their light is bent by their own atmospheres.
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which units are appropriate for measurement of apparent brightness?
"The units appropriate for measurement of apparent brightness is watts per square metre."
Even though a flashlight that is close by might seem brighter than a streetlight that is far away, the flashlight is actually much less bright when contrasted side by side. The measurement of a star's luminosity—a fancy term for its real brightness—as seen from Earth is known as apparent brightness, also known as apparent magnitude.
The intensity of starlight that reaches us per unit area is known as apparent luminosity. Area is measured in square meters and power is measured in volts.
A photometer is a device that gauges and rates a celestial body's luminosity.
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You have four identical resistors, each with a resistance ofR. You are asked to connect these four together so thatthe equivalent resistance of the resulting combination isR. How many different ways can you do it? There is morethan one way.A. 2B. 3C. 4D. infiniteJustify your answer.
The number of the different ways can be 4. The correct option is C.
The total resistance of four identical resistors in series is 4R, while the total resistance of four identical resistors in parallel is R. Therefore, there are two ways to connect the four resistors in order to achieve a total resistance of R: connecting them in series or connecting them in parallel.
(i) In the first way, we connect two pairs of resistors in series, and then, these pairs are connected in parallel.
(ii) In a second way, we connect two resistors in series, and then, this pair is connected in parallel with the other pair of resistors that are also connected in series.
(iii) In a third way, we connect three resistors in series and connect this combination in parallel with the remaining resistor.
(iv) In a fourth way, we connect all four resistors in series.
We need to connect four identical resistors of resistance R so that the equivalent resistance of the resulting combination is R. The number of ways we can do it is 4. So, the correct option is (C) 4.
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A room with which type of surface will most likely produce an echo?(1 point)
carpet
dirt
foam
glass
Answer:
The correct answer is "glass".
Explanation:
A room with a smooth and hard surface like the glass is likely to produce an echo because when sound waves hit such surfaces, they bounce back and forth, creating echoes. Soft and porous materials like carpet, dirt, or foam absorb sound waves, reducing the reflection and producing less echo. Therefore, the answer is glass.
An electroscope is a device with a metal knob, a metal stem, and freely hanging metal leaves used to detect charges. The diagram below shows a positively charged leaf electroscope.
As a positively charged glass rod is brought near the knob of the electroscope, the separation of the leaves will
remain the same
increase
As a positively charged glass rod is brought near the knob of the electroscope, the separation of the leaves will increase.
What is Charge?
Charge is a fundamental property of matter that determines how objects interact with each other through the electromagnetic force. It is a physical property that can be positive or negative and can be measured in coulombs (C).
This is because the positively charged glass rod will induce a negative charge on the metal knob of the electroscope. The negative charges will repel the electrons in the metal leaves, causing them to move away from each other and increasing their separation. The greater the amount of charge on the glass rod, the greater the separation between the leaves will be.
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What causes friction?
A. Tiny collisions, called microwelds, on surfaces, even those that seem smooth B. Action - Reaction C. All surfaces are rough to the touch and therefore cause friction D. Inertia
Answer:
b
Explanation: friction is like a force to something to react
Two children are playing a game in which they try to hit a small box on the floor with a marvel fired from a spring-loaded gun that is mounted on a table. The target box is at a horizontal distance D = 2.2m from the edge of the table. Bobby compresses the spring 1.7cm, but the center of the marble falls 27cm short of the center of the box. How far should Rhoda compress the spring to score a direct hit? Assume that neither the spring nor the ball encounters friction in the gun.
The distance till which Rhoda should compress the spring to score a direct hit is 1.37 centimeters.
Rhoda needs to compress the spring by a distance of 1.37cm to score a direct hit. The equation to find this distance is: D = [tex][(x + y)^2 - x^2]^{(1/2)}[/tex]
where, D is the horizontal distance, x is the initial compression of the spring (1.7cm), and y is the additional compression needed to reach the target box (the unknown).
To solve for y, we can rearrange the equation as:
[tex]y = [(D^2 - x^2]^{(1/2)} - x\\[/tex]
Plugging in the values, we have
[tex]y = [(2.2^2 - (1.7)^2]^{(1/2)}[/tex]- 1.7 = 1.37cm
Therefore, Rhoda needs to compress the spring by 1.37 cm to score a direct hit.
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