F₂ = 1.723 x 10⁸ N
Further explanationGiven
Area of small piston : 0.004 m²
Area of large piston : 3.5 m²
Force 225 N
Required
Force applied
Solution
Pascal Law :
F₁/A₁=F₂/A₂
225/0.004 m² = F₂/3.5² m²
F₂ = 1.723 x 10⁸ N
V,? = V2 + 2a Ax
1. A toy car increases velocity over a displacement of 15.2 m. If
the car starts at rest and has a final velocity of 0.76 m/s, what
is the magnitude of its acceleration?
Answer:
Explanation:
[tex]V^2=V^2_i+2a(x_f-x_i)[/tex]
[tex]0.76^2=0^2+2a(15.2)[/tex]
[tex]0.5776=30.4a[/tex]
[tex]a=0.019m/s^2[/tex]
A tennis ball is dropped from a height of 1.21m above the ground. Calculate its velocity when it is 0.27m from the ground.
The velocity of hitting the ground is 4.86 m/s and the velocity after hitting the ground is 4.53 m/s.
What is Velocity?Velocity can be defined as the direction of movement of the body or object. Velocity is a vector quantity. It is the rate of change of displacement.
Given data,
Initial velocity when dropped(u)=0 m/s
Distance traveled(s)=1.21 m/s
Distance traveled after leave the ground(s1) = 1.05 ms
According to third law of motion,
v² = u² + 2gs
Initial velocity u=0
v² = 2gs or v = [tex]\sqrt{2gs}[/tex]
by putting the value of s
v (hitting) = √(2 × 9.8 × 1.21) = [tex]\sqrt{23.71}[/tex] = 4.86m/s
After leaving ground at 1.21 m final velocity will be zero
So, velocity just after left the ground will be
2 = √(2 × 9.8 × 1.05) = [tex]\sqrt{20.58}[/tex] = 4.53m/s
So, velocity of hitting the ground is 4.86 m/s and after hitting is 4.53 m/s.
Learn more about Velocity here:
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An object that is slowing down is accelerating.
True
False
mary travelled 70mph due north
this is an example of
Acceleration
distance
speed
velocity
James is planning a science fair project on sound waves. He places an alarm inside a jar which he can remove the
air from. Before he removes the air, he can hear the alarm ringing. After he removes the alr, he cannot hear the
alarm ringing. What condusion can you draw from this experiment?
A. Sound waves can travel in a vacuum
B. Sound waves are transverse waves and are loud
C. Sound waves cannot travel through a medium
D. Sound waves require a medium to travel through
Answer: c
Explanation:
Sound waves cannot travel through a medium
Part C
How many combined bits of storage are there on the two tablets?
Answer:
IVE BEEN TRYNA FIND THE ANSWER FOR THE PAST HOUR T-T
Explanation:
Answer:
3.2 x10^11 bits of storage
Explanation:
As the Sun ages, what will happen to life here on Earth? Why?
Answer:
As the Sun ages it will enter another stage of stellar evolution where it's atmosphere begins to inflate.As the Sun heats up and expands, life on Earth will become increasingly difficult. Long before the Sun becomes a red giant some 4 or 5 billion years from now, our planet will be rendered uninhabitable.
~I HOPE IT HELPS♡
How much heat energy is given out when 500g of steam at 100 degrees celcius condenses to water at 100 degrees celcius
Explanation:
How much thermal energy is released when 500g of steam at 100° C condenses into water and cools to 50°C
Givens: m=0.5 kg
t = 50
c = 2.010
Qtotal = Q1 + Q2
Qtotal = QmcΔt + mLv
Qtotal = (0.5kg)(2.010)(50) + (0.5)(2.3*10^6)
Qtotal = 1.15 * 10^6
The book says that the answer is 1.3*10^6?
What did I do wrong here?
Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelength of d/15. The lasers produce separate interference patterns on a screen a distance 4.60 mm away from the slits.
A) Which laser has its first maximum closer to the central maximum?
B) What is the distance between the first maxima (on the same side of the central maximum) of the two patterns?
Answer:
A. Laser 1 has its first maximum closer to the central maximum.
B. 0.077 mm
Explanation:
A) Which laser has its first maximum closer to the central maximum?
Since for a double slit interference, sinθ = mλ/d where θ is the angle between the central axis and the maximum point, m = order of fringe, λ = wavelength of light and d = width of slit.
Also tanθ = y/D where θ is the angle between the central axis and the maximum point, y = distance between maximum point and central axis and D = distance between slit and screen = 4.60 mm.
Since θ is small, sinθ ≅ θ and tanθ ≅ θ
So, sinθ ≅ tanθ
mλ/d = y/D
So, y = mλD/d for the first maximum, m = 1.
So, y = (1)λD/d
y = λD/d
For the Laser 1, λ = d/20
So, y = λD/d
y = (d/20)D/d
y = D/20
y = 4.60 mm/20
y = 0.23 mm
For the Laser 2, λ' = d/15
So, y' = λ'D/d
y' = (d/15)D/d
y' = D/15
y' = 4.60 mm/15
y' = 0.307 mm
Since y = 0.23 mm < y' = 0.307 mm, Laser 1 has its first maximum closer to the central maximum.
B) What is the distance between the first maxima (on the same side of the central maximum) of the two patterns?
The distance between the first maxima (on the same side of the central maximum) of the two patterns is Δy = y' - y = 0.307 mm - 0.23 mm = 0.077 mm
Which distance increases?
Answer:
wY
Explanation:
it increases my mercury righy basically also on the atmosphere pressure
how find \empirical formula
what kind of waves travel as transverse waves
A. Only mechanical
B. All waves
C. Some waves
D. No waves
Answer:
C. Some waves
Explanation:
The answer is some waves because transverse waves are not the only types of waves we have on the earth. We also have longlitudal waves, which means only some waves can only be transverse. The answer to the question should be C. Some waves.
To test the strength of a retainment wall designed to protect a nuclear reactor,
a rocket-propelled F-4 Phantom jet aircraft was crashed head-on into a
concrete barrier at high speed in Sandia, New Mexico, on April 19, 1988. The
F-4 phantom had a mass of 19,100 kg, while the retainment wall's mass was
469,000 kg. The wall sat on a cushion of air that allowed it to move during
impact. If the wall and F-4 moved together at 8.41 m/s during the collision,
what was the speed of the F-4 Phantom upon impact?
Answer:
The speed of the F-4 Phantom upon impact is approximately 214.92 m/s
Explanation:
The given parameter of the motion of the F-4 Phantom jet aircraft are;
The mass of the F-4 phantom rocket, m₁ = 19,100 kg
The mass of the retaining wall, m₂ = 469,000 kg
The velocity of the combined mass of the wall and the F-4 after collision, v₃ = 8.41 m/s
The retainment wall was initially at rest, therefore, v₂ = 0 m/s
Let 'v₁', represent the speed of the F-4 Phantom upon impact
By the principle of conservation of linear momentum, we have;
m₁·v₁ + m₁·v₂ = m₁·v₃ + m₂·v₃ = (m₁ + m₂)·v₃
Plugging in the values, we have;
19,100 × v₁ + 469,000 × 0 = (19,100 + 469,000) × 8.41
∴ v₁ = (19,100 + 469,000) × 8.41/(19,100) = 214.917329843
v₁ ≈ 214.92
The speed of the F-4 Phantom upon impact, v₁ ≈ 214.92 m/s.
Student agrees to do only 300 joules of work, how far will the student push the box using a constant 84 N force
Answer:
Explanation:
Work = Force*Distance
300 = 84*d
d = 3.57 meters
how much potential energy does the ball have when it reaches the top of its ascent
PE = 450 m
Further explanationGiven
The initial problem might be like this
A 1.0-kg ball is thrown into the air with an initial velocity of 30 m/s.
Required
Potential energy
Solution
h max = vo²sin²θ/2g
h max = 30²sin²90/2.10
h max = 45 m
PE = m.g.h
PE = 1 x 10 x 45
PE = 450 m
Which green shape is the least reactive?
(Subjective is actually science)
Answer:
the green smiley face
Explanation:
its is farthest from the right
and as stated on the chart, the farther left, the more reactive
less stable=more reactive
more stable= less reactive
Horse's Motion
Pamond
25
20
Account
Velocity
(meters per second)
15
10
Dashboard
5
0
Courses
0 5 10 15 20 25
Time (seconds)
Groups
Based on the information in the graph, which statement is
true?
Calendar
The horse maintained a constant acceleration during this portion of the race.
Inbox
The horse maintained a constant velocity during this portion of the race.
The horse increased its acceleration during this portion of the race.
History
The horse decreased its velocity during this portion of the race.
Studio
Answer:
The answer will be the number 15 because it is subtracted to the number itself
1
AI
A3
If A1 = 27A and A3 = 1.9A, what would A2 read?
Answer:
0.8A
Explanation:
because im very intelligent and beautiful so the answer is correct and its 0.8A
Question 1
3 pts
When eating out in a restaurant, you
should
Answer:
Wear a mask and keep a solid 6 feet of social distance
Explanation:
Answer:
Be polite, wear a mask, social distance, don't eat sloppy, have a good time lol
Explanation:
need some help!!!!!!! please
Think about a situation at school where you or someone you know
has demonstrated grit. Describe the situation. Pls help me
Answer:
to have courage and show the strength of your character. ... A person with true grit has passion and perseverance. Goals are set and followed through.
Explanation:
for example: i had the passion and the courage to finish my school work and chores for i can go out with my friends and to get out of the house for a bit and have fun so i had the courage to finish chores from the house and do some schoolwork for i can finish ad hang out with some friends. so i had the strength to finish everything because i didn't want to be doing school work and chores any more so i had the passion to finish up quickly
What is the gravitational force between two 1 kg objects that are 1 m apart?
Answer:
[tex]F=6.67\times 10^{-11}\ N[/tex]
Explanation:
Given that,
The masses of two objects, m₁ = m₂ = 1 kg
The distance between masses, d = 1 m
We need to find the gravitational force between two masses. The force is given by the relation as follows :
[tex]F=G\dfrac{m_1m_2}{d^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1\times 1}{(1)^2}\\F=6.67\times 10^{-11}\ N[/tex]
So, the force between two masses of 1 kg is [tex]6.67\times 10^{-11}\ N[/tex].
A book of mass 1.5 ,kg exerted a downward force on the table
What is the direction of this second force?
Answer:
up ward force it is balanced by dow ward force
What force will accelerate a 20 kg object at 4 m/s 2? *
Answer:
80 N
Explanation:
mass = 20 kg
acceleration = 4 m/s^2
Force = mass * acceleration
= 20 *4
= 80 N
If the small piston has an area of .004 square
meters and Bob pushes down on it with 225 N of
force, what is the magnitude of the pressure
increase in the system?
The magnitude of the pressure : P = 56,250 N/m
Further explanationGiven
Area of 0.004 m²
Force 225 N
Required
the magnitude of the pressure
Solution
Pressure = force exerted per unit of surface area(perpendicular)
Can be formulated :
P = F/A
Input the value :
P = 225 N / 0.004 m
P = 56,250 N/m
a car takes 4 hours to cover a distance if it takes at a speed of 40mph. what should be it's speed to cover the same distance in 1.5 hours
Answer:
Speed = 106.67mph
Explanation:
Let the first motion be A.
Given the following data;
Speed A = 40mph
Time A = 4 hours
To find the distance covered in A;
Distance = speed * time
Distance = 40 * 4
Distance = 160 miles.
To find the speed required to cover the above distance in 1.5 hours;
Speed = distance/time
Speed = 160/1.5
Speed = 106.67mph
If a girl does 1,350 Joules of work to pedal her bike using a force of 75 N, how far did she ride her bike?
Answer:
D = 18m
Explanation:
We use this formula:
Work = Force * Distance
Now, we replace it:
W = F*D
1,350J = 75N * D
D = 1,350/75
D = 18m
Hope it was helpful ;)
What is the centripetal acceleration of an object moving 25 m/s around a 6 m curve?
O 104.2
O 84.2
O 64.2.
O 44.2
Answer:
Centripetal acceleration = 104.2 (Approx)
Explanation:
Find:
Centripetal acceleration
Given:
Velocity = 25 m/s
Radius r =6 m
Computation:
Centripetal acceleration = v² / r
Centripetal acceleration = 25² / 6
Centripetal acceleration = 104.467
Centripetal acceleration = 104.2 (Approx)
When there are too many neutrons compared to the number of protons, the atomic nucleus is
A. Stable
B. Unstable
C. Explosive
D . Noble gases
Answer:
99.9% sure it B. Unstable but if that’s wrong try A.stable
Explanation:
Too many protons (or too few neutrons) in the nucleus result in an imbalance between forces, which leads to nuclear instability.
if a nucleus is unstable due to too many neutrons, it will undergo Beta decay - this means they become stable by emitting a beta particle.
Robert hook used an early microscope to observed a cork sample. How did this help contribute to cell theory?
Answer:
Robert Hooke used an early microscope to observe a cork sample. How did this help contribute to cell theory? It helped to show that cells contain water. ... It helped to show that some cells are visible to the naked eye.
Explanation:
If your teacher checks if it was copied just put it in your on words