If three times the sum of two, numbers is 42 and five times their difference is 20, find the numbers​

Answers

Answer 1

Answer:

x=9 and y=5

Explanation:

You can use the substitution method to eleminate x in the first equation with the value you will get from the second equation

Answer 2

Answer:

The two numbers are 5 and 9.

Explanation:

Given the information in the problem, if three times the sum of two numbers is 42, we can attempt to work backwards by doing the opposite of "three times the sum", which is dividing 42 by 3:

[tex]42/3=[/tex]

[tex]14[/tex]

We've figured out that the sum of these two numbers is 14.

Again, given the information in the problem, five times the difference of these two numbers is 20. Now, the only number that can multiply by 5 to get 20, is 4. We have to think of two numbers that will both, add up to 14, and when subtracted, have a difference of 4.

We can conclude that our two numbers are:

[tex]5[/tex] & [tex]9[/tex]

-

To check your work, run through the problem and simulate the given processes:

(First: Three times the sum of two numbers = 42)

[tex]5+9=14[/tex]

[tex]14*3=42[/tex]

(Second: Five times their difference is 20)

[tex]9-5=4[/tex]

[tex]4*5=20[/tex]

Therefore, our solution is correct!


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Answer:

the calories from fat should be no more than 25 percent to 35 percent of your daily calorie intake. For example if you eat a 2,000 calorie diet, you shouldn't eat  more than 65 grams of fat per day. Saturated fat account for no more than five to six percent of total calories.

Please mark brainliest if  this helped, Hoped this helped and Have a great day!

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Answer:

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