(3.5x10^5)x(4x10^-3)=exponent form
Answer:
1.4 x 10³
Explanation:
Given:
(3.5 x 10⁵)x(4 x 10⁻³)
Find:
Exponent form
Computation:
⇒ (3.5 x 10⁵)x(4 x 10⁻³)
⇒ 3.5 x 4 x 10²
⇒ 14 x 10²
1.4 x 10³
A sample of nitrogen gas is in a 65.0-L automobile air bag and has a pressure of 745 mm Hg. What is the pressure of this sample of gas at the same temperature if it is placed into a 25.0-L bag
Answer:
the pressure = 1937mmhg using standered unit of volume
How can a galvanic cell become an electrolytic cell?
A. The cathode is oxidized.
B. The salt bridge is removed.
C. The electrolytes are swapped.
D. The redox reaction is reversed.
(The answer is D.)
help I. have until 11:59 to hand it in
This chemical reaction can also be written as
2C2H6+7O2-->4CO2+6H2O
This is a chemical reaction because reactants are converted into products. This is the combustion of ethane where ethane and oxygen have been converted into carbon dioxide and water
Plz help me
What is a challenge in wild animal photography?
A. They are easy to close to
B. They don’t move much
C. You can’t position them
D. All of the above
Answer:
c
Explanation:
Because they are in the wild and they move a lot because they freedom. They are easy to close but you can not position so it is c. Pls tell if I am wrong.
When you lift an object, you add the energy of lifting the object to the object
Answer:
Which is kinetic energy at its best, cause you are moving your arm or hand in motion, bu the object is in potential energy, where it isn't moving
Explanation:
By studying the distribution of different types of fossils, geologists have determined that some plates have traveled great distances. Evidence to support this comes from the fact that –
A.fossils of organisms that lived in warm climates have been found in arctic environments.
B. Species of organisms in the fossil record have changed over geologic time.
C. Some fossilized organisms have only been found on one continent.
D. The oldest known fossils, found in the deepest rock layers, represent ocean organisms.
Answer:
A. Fossils of organisms that lived in warm climates have been found in arctic environments.
Explanation:
One of the logic used by Geologists to justify plate movement over a region of space is that the fossils of organisms that lived in warm climates have been found in arctic environments.
this is as a result of plate tectonics. organisms that are well adapted to warm climates in times past have their relics preserved as fossils. their fossils are no found today around the arctic environment which are coldthis suggests that the plate must have drifted or movedWhen 2.00 g of silver nitrate and 2.50 g of sodium sulfide in different solutions combine to react, 1.25 g of precipitate are collected. * The text box will not allow you to use subscript. If you want to type the chemical formula for iron(III) sulfate, Fe2(SO4)3, it will need to be typed as Fe2(SO4)3. Remember that the symbol for iron, Fe, is not "fe" or "FE." Do not include the state of matter for each formula. • What is the chemical formula* for the product? Remember that spectator ions do not form a product in solutions. • What is the theoretical yield, in gram(s) for the solid product? • What is the chemical formula for the limiting reagent? • What is the chemical formula for the excess reagent? • What is the percent yield for the reaction? • How many gram(s) of the excess reagent is/are left over?
Answer:
See Explanation ...
Explanation:
2AgNO₃(aq) + Na₂S(aq) => 2NaNO₃(aq) + Ag₂S(s)
given 2.0g 2.5g Spec Ions Driving Force ppt
= 2.0g/169.8g·mol⁻¹ =2.5g/78g·mol⁻¹
= 0.012mol =0.032mol
0.012/2=>0.006* 0.032/1=>0.032*
Limiting Reactant => *Dividing moles by respective coefficient => Limiting Reactant is the smaller resulting value. Therefore AgNO₃ is the Limiting Reagent
Theoretical Yield of ppt Ag₂S(s) = 1/2(0.012 mol) = 0.006 mol Ag₂S(s) = 0.006mol(246g·mol⁻¹ ) = 1.48g Ag₂S(s)
%Yield = (Lab Yield/Theoretical Yield) x 100% = (1.25g/1.48g)100% = 84%
Reagent in Excess => Na₂S(aq) => 0.032mol is given but only 0.016mol is consumed in the reaction. That is, (0.032 - 0.016)mol = 0.016mol Na₂S(aq) remains in excess = (0.016mol)(78g·mol⁻¹) = 1.25g Na₂S(aq) in excess.
`Acids have many useful properties that can be exploited for our own benefit. They are commonly used to make many things that we use. For example, which of these is associated with making fertilizer?
Answer:
HNO3
Explanation:
HNO3 is nitric acid. Nitric acid as a compound contains Hydrogen, Nitrogen and Oxygen molecules, therefore its chemical formula is HNO3. Very useful for fertiliser and chemical making. This acid can be manufactured from ammonia and it is a very important chemical that is used for manufacturing fertilizers.
Nitric acid is useful for the manufacturing of ammonium nitrate and calcium ammonium nitrate which have uses as fertilizers.
Can anyone please tell me what I did wrong and why the answer I put was wrong, and why the answer that is correct, right? Giving Brainliest, PLEASE help!
Answer:
Lithium is reduesednas it gains electrons gold
Answer:
Look at Lithium on the Periodic Table, look at the amount of electrons. When Lithium and Gold are together, Lithium loses while Gold(Au) gains.
what statement is true?
A. interia causees bodies to slow in their motion, unless they're pushed by a force.
B. Interia resist changes to the state of motion of a body.
C. Interia decelerates a body.
D. Interia is due to friction.
Answer:
B. Inertia resist changes to the state of motion of a body.
Explanation:
The force of inertia is an inherent property of matter in which it allows a body to resist changes to the state of motion of the body.
According to Newton's first law of motion "a body will remain at rest or in constant motion unless if an external force acts on it".
This is the law inertia.
The ability of a body to resist changes to the motion of the body is its inertia. Therefore, the correct choice is B.Please help I need this done
Answer:
they arent alcohols.
Explanation:
neon, a monatomic gas, that starts out at conditions of standard temperature and pressure (273.15 K, 105 Pa). Alice heats the gas at constant volume until its pressure is doubled, then Bob further heats the gas at constant pressure until its volume is doubled. If Alice and Bob assume that neon behaves as an ideal gas, then how much heat have they added to the gas for the entire process.
Answer:
819.45 K
Explanation:
Use the Ideal Gas Law to make sense of this problem, PV = nRT. From this equation, we know that pressure is directly proportional to temperature and that volume is also directly proportional to temperature. Therefore, doubling the temperature would double the pressure, and doubling the temperature would also double the volume. In the described scenario, the temperature is doubled twice, so the temperature is quadrupled (i.e. three times its original amount has been added).
The initial temperature was 273.15 K. Multiply this by 3 to get your answer of 819.45 K.
how many grams of water can be produced the combination of 10 grams of oxygen and 8 grams of hydrogen
Answer:
Mass = 11.16 g
Explanation:
Given data:
Mass of hydrogen = 8 g
Mass of oxygen = 10 g
Mass of water produced = ?
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen:
Number of moles = mass / molar mass
Number of moles = 8 g/ 2 g/mol
Number of moles = 4 mol
Number of moles of oxygen:
Number of moles = mass / molar mass
Number of moles = 10 g/ 32 g/mol
Number of moles = 0.31 mol
now we will compare the moles of hydrogen and oxygen with water.
O₂ : H₂O
1 : 2
0.31 : 2/1×0.31 = 0.62
H₂ : H₂O
2 : 2
4 : 4
Number of moles of water formed by oxygen are less this it will act as limiting reactant.
Mass of water:
Mass = number of moles × molar mass
Mass = 0.62 mol × 18 g/mol
Mass = 11.16 g
A gas is enclosed in a cylinder fitted with a piston. The volume of the gas is 5.00 L at 0.500
atm pressure. The piston is moved to increase the volume to 3.00 L. Which of the
following is a reasonable value for the pressure of the gas at the greater volume?
Answer:
0.8333 L. P1v1=p2v2
Explanation:
I dont now if this is wht you were looking for so srry
The pressure of the gas at which the final volume of the gas has been 3 L has been 0.833 atm.
The gas has been assumed to be at constant temperature. The change in the pressure and volume of gas at constant temperature can be given by:
Initial pressure × Initial volume = Final pressure × Final volume
The initial pressure of gas has been 0.5 atm, and the initial volume has been 5L. The increased volume or final volume of the system has been 3 L.
The final pressure of the gas has been given by:
0.5 atm × 5 L = 3 L × Final pressure
Final pressure = 0.833 atm.
The pressure of the gas at which the final volume of the gas has been 3 L has been 0.833 atm.
For more information about the pressure of the gas, refer to the link:
https://brainly.com/question/6534127
PLS HELP WILL GIVE BRAINLYEST What happens when the magnet is removed from the coil in a circuit?
a.
The current stops
c.
The voltage decreases
b.
The current changes direction
d.
Power output increases
Answer:
b
Explanation:
g The energy associated with the lowest n = 1 state in a hydrogen atom is – 13.6 eV. The wavelength of the emission line corresponding to the transition from n = 4 to n = 3 is
Answer:
10.9 * 10^-7 m
Explanation:
We know that the Rydberg constant (R) is – 13.6 eV = -2.18 * 10^-18 J
ΔE= -R(1/nf - 1/ni)
Where;
nf = final state
ni= initial state
ΔE= -2.18 * 10^-18(1/3 - 1/4)
ΔE= -2.18 * 10^-18(1/12)
ΔE= -1.81 * 10^-19 J
From;
ΔE=hc/λ
h = plank's constant = 6.6 * 10^-34 Js
c = 3 * 10^8 ms-1
λ = ?
λ = hc/ΔE
λ = 6.6 * 10^-34 * 3 * 10^8/ 1.81 * 10^-19
λ = 10.9 * 10^-7 m
(a) Some sodium chloride was found to be contaminated with Copper (ii) oxide. Describe
how a sample of sodium chloride can be separated from the mixture.
Answer:
A mixture of sodium chloride and sand in water can be separated by the process of filtration and then by the process of distillation.
Answer:
Explanation:
As this oxide is insoluble in water you would dissolved the sample of sodium chloride in water and filter off the oxide.
Then concentrate the liquid by boiling and cooling, to get crystals of pure sodium chloride.
please I need this just look at the picture for the question
iii. A sound wave can be modelled by using a slinky spring. A wavelength in this model is...
a. the distance between a rarefaction and a compression.
b. the length of one compression.
c. the length of one rarefaction.
d. the distance between two rarefactions,
Answer: d. the distance between two rarefactions,
Explanation:
Wavelength is the distance between two identical adjacent points in a wave. This means that it is the distance between two adjacent compressions or two adjacent rarefactions.
Wavelengths are inversely related to frequency because the longer the wavelength, the less the number of wave cycles per second.
Atomic number of a member of halogens
During laparoscopic surgery , carbon dioxide gas is used to expand the abdomen to help create a larger working space. If 4.80 L of CO 2 gas at 18 °C at 785 mmHg is used, what is the final volume , in liters, of the gas at 37 degrees * C and a pressure of 745 mmHg if the amount of CO 2 does not change ?
Answer:
5.37 L
Explanation:
To solve this problem we need to use the PV=nRT equation.
First we calculate the amount of CO₂, using the initial given conditions for P, V and T:
P = 785 mmHg ⇒ 785/760 = 1.03 atmV = 4.80 LT = 18 °C ⇒ 18 + 273.16 = 291.16 K1.03 atm * 4.80 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 291.16 K
We solve for n:
n = 0.207 molThen we use that value of n for another PV=nRT equation, where T=37 °C (310.16K) and P = 745 mmHg (0.98 atm).
0.98 atm * V = 0.207 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 310.16 KAnd we solve for V:
V = 5.37 LPlease help this is a big grade please
Answer:
the answer Is d
Explanation:
or the last option is the answer if u need an explanation I may help u and tell me if u are from India
Answer:
dvis you're answer please like me
component of fuel for engines is organic compound or hydrocarbons
CnHm is the general closed chemical formula of liquid hydrocarbons used as a fuel in the internal combustion engines. However, hydrocarbons consist of hydrogen and carbon and also small amounts of O2, H2, S, H2O, and some metals containing crude oil derivatives .
how mant liters at STP are in 0.575 moles of Kr
Answer:
12.9 L Kr
General Formulas and Concepts:
Chemistry - Gas Laws
Using Dimensional AnalysisSTP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 KExplanation:
Step 1: Define
0.575 mol Kr
Step 2: Identify Conversions
1 mol= 22.4 L at STP
Step 3: Convert
[tex]0.575 \ mol \ Kr(\frac{22.4 \ L \ Kr}{1 \ mol \ Kr} )[/tex] = 12.88 L Kr
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
12.88 L Kr ≈ 12.9 L Kr
2.55 gram of an alloy of silver and zinc on treatment with excess dilute hydrochloric acid gave 170 CC Of
hydrogen gas of STD. If silver remained unsolved calculate the percentage Composition of the alloy .
( Alamic masses of Zn: 65, H:1)
The percentage composition of the alloy : 19.35% Zn, 80.65%Ag
Further explanationGiven
2.55 gram of an alloy
170 cc (170 ml=0.17 L) of Hydrogen gas(H₂)
Ar Zn = 65. H=1
Required
The percentage composition
Solution
Silver remained unsolved⇒no reaction
Hydrogen gas from reaction of Zn
Zn+2HCl⇒ZnCl₂ + H₂
mol H₂ at STP (STP⇒1 mol = 22.4 L) :
[tex]\tt \dfrac{0.17}{22.4}=0.00759~moles[/tex]
From equation, mol ratio Zn : H₂ = 1 : 1, so mol H₂ = 0.00759
Mass Zn :
[tex]\tt mass=mol\times Ar\\\\mass=0.00759\times 65\\\\mass=0.49335~g[/tex]
Mass Silver :
[tex]\tt 2.55-0.49335=2.05665~g[/tex]
Percent composition :
Zn[tex]\tt \dfrac{0.49335}{2.55}\times 100\%=19.35\%[/tex]
Ag[tex]\tt \dfrac{2.05665}{2.55}\times 100\%=80.65\%[/tex]
Gold has a density of 17.3 g/cm", what is the volume of 285g piece of gold?
(Show all work)
9514 1404 393
Answer:
about 16.5 cm³
Explanation:
Volume, mass, and density are related by ...
volume = mass/density
volume = (285 g)/(17.3 g/cm³) ≈ 16.5 cm³
what is a molecule? PLEASE DONT LOOK THIS UP I WILL GET IN TROUBLE!
Answer:
A molecule is a group of two or more atoms that form the smallest recognizable unit into which the structure and chemical properties of that substance can be divided and preserved by a pure substance.
Explanation:
What is the mass of Na2CO3∙10H2O that is needed to make 100 ml of sodium carbonate solution with the mass percentage of Na2CO3∙ equal to 2%? The density of the final solution is equal to 1 g/ml.
first we find the mass of the final solution
we know that
density=mass/volume
we know the density and volume
1=m/100
m=100g
now we calculate the mass ofNa2CO3
2% of 100 is equal with 2g of Na2CO3
Salt is poured from a container at 10 cm³ s-¹ and it formed a conical pile whose height at any time is 1/5 the radius of the above. At what rate is the height of the cone increasing when the height is 2 cm form the base of the cone?
Answer:
[tex]\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}[/tex]
Explanation:
Volume of a cone:
[tex]\displaystyle V=\frac{1}{3} \pi r^2 h[/tex]We have [tex]\displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec}[/tex] and we want to find [tex]\displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ?[/tex] when the height is 2 cm.
We can see in our equation for the volume of a cone that we have three variables: V, r, and h.
Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.
We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.
Plug this value for r into the volume formula:
[tex]\displaystyle V =\frac{1}{3} \pi (5h)^2 h[/tex] [tex]\displaystyle V =\frac{1}{3} \pi \ 25h^3[/tex]Differentiate this equation with respect to time t.
[tex]\displaystyle \frac{dV}{dt} =\frac{25}{3} \pi \ 3h^2 \ \frac{dh}{dt}[/tex] [tex]\displaystyle \frac{dV}{dt} =25 \pi h^2 \ \frac{dh}{dt}[/tex]Plug known values into the equation and solve for dh/dt.
[tex]\displaystyle 10 = 25 \pi (2)^2 \ \frac{dh}{dt}[/tex] [tex]\displaystyle 10 = 100 \pi \ \frac{dh}{dt}[/tex]Divide both sides by 100π to solve for dh/dt.
[tex]\displaystyle \frac{10}{100 \pi} = \frac{dh}{dt}[/tex] [tex]\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}[/tex]The height of the cone is increasing at a rate of 1/10π cm per second.