i’m confused on this worksheet can someone help

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Answer:

op

Explanation:

At a distance of 1 cm from the source, the flux from the isotropic source is one hundred times brighter. Which source is brighter fifty centimeters away

Answer:

Explanation:

Assuming x direction is horizontal any y direction is vertical

As the moment of inertia of the pulley is I = (½)mR²

The pulley mass will appear as ½ its actual mass in the system.

F = ma

5.00(9.81) = (5.00 + 2.60/2 + 12.0)a

a =  49.05 / 18.3

a = 2.6803278...

a = 2.68 m/s²

A) T = 12.0(2.68) = 32.16... = 32.2 N

B) T = 5.00(9.81 - 2.68) = 35.65 = 35.7 N

C) aₓ = 2.68 m/s²

D) Fx = 32.2 N

   Fy = 35.7 + 2.60(9.81) = 61.2 N

A)The tension in the horizontal segment of the wire will be  32.2 N

B)The tension in the vertical segment of the wire will be 35.7 N

Acceleration is defined as the rate of change of the velocity of the body. Its unit is m/sec².It is a vector quantity. It requires both magnitudes as well as direction to define.

The given data in the problem is;

m is the mass box resting on a horizontal  =12.0 kg

the uniform solid disk of mass of 2.60 kg

d is the diameter = 0.500 m.

A)The tension in the horizontal segment of the wire will be  32.2 N

The acceleration is found as;

[tex]\rm F = ma \\\\ a= \frac{49.05}{18.3} \\\\ \rm a= 2.68 \ m/sec^2[/tex]

The tension in the horizontal segment of the wire is found as;

T=ma

T= 12.0 ×2.68

T=32.2 N

Hence the tension in the horizontal segment of the wire will be  32.2 N

B)The tension in the vertical segment of the wire will be 35.7 N

T=m(g-a )

T= 5.00 × (9.8-2.68)

T=35.7 N

Hence the tension in the vertical segment of the wire will be 35.7 N

C)  the x-component of the acceleration of the box. will be 2.68 m/s².

aₓ = 2.68 m/s²

D)The x- and y-components of the force that the axle exerts on the pulley will be 32.2 and 61.2 N respectively.

Fx = 32.2 N

Fy = 35.7 + 2.60(9.81) = 61.2 N

Hence the x- and y-components of the force that the axle exerts on the pulley will be 32.2 and 61.2 N respectively.

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Answer:

thx for the points

Explanation:

no need brainliest

I think 1980is the answer because you add???

Identify:

In each case the forces are constant and the displacement is along a straight line, so

[tex]$$W=F s \cos \phi \text {. }$$[/tex]

Set-Up:

In part (a), when the cable pulls horizontally [tex]$\phi=0^{\circ}$[/tex] and when it pulls  [tex]$35.0^{\circ}$[/tex] above the horizontal [tex]$\phi=35.0^{\circ}$[/tex]. In part (b), if the cable pulls horizontally[tex]$\phi=180^{\circ}$[/tex]. If the cable pulls on the car  [tex]$35.0^{\circ}$[/tex] above the horizontal it pulls on the truck at below the horizontal and [tex]$\phi=145.0^{\circ}$[/tex]. For the gravity force [tex]$\phi=90^{\circ}$[/tex], since the force is vertical and the displacement is horizontal.

Execute:

(a) When the cable is horizontal, [tex]$W=(850 \mathrm{~N})\left(5.00 \times 10^{3} \mathrm{~m}\right) \cos 0^{\circ}=4.25 \times 10^{6} \mathrm{~J}$[/tex].

When the cable is[tex]$35.0^{\circ}$[/tex] above the horizontal,[tex]$W=(850 \mathrm{~N})\left(5.00 \times 10^{3} \mathrm{~m}\right) \cos 35.0^{\circ}=3.48 \times 10^{6} \mathrm{~J}$[/tex].

(b)[tex]$\cos 180^{\circ}=-\cos 0^{\circ}$[/tex] and [tex]$\cos 145.0^{\circ}=-\cos 35.0^{\circ}$[/tex],

So the answers are [tex]$-4.26 \times 10^{6} \mathrm{~J}$[/tex] and [tex]$-3.48 \times 10^{6} \mathrm{~J}$[/tex].

(c) Since [tex]$\cos \phi=\cos 90^{\circ}=0, W=0$[/tex] in both cases.

Evaluate: If the car and truck are taken together as the system, the tension in the cable does no net wnetwork

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Answer:

A

Explanation:

for every action there is an equal and opposite reaction

Answer:

Explanation:

v² = u² + 2as

v² = 33² + 2(3.0)(500)

v² = 4089

v = 63.9452...

v = 64 m/s

Answer:

Explanation:

ASSUMING the 52° is the angle of incidence measured from the perpendicular to the surface

          n₁sinθ₁ = n₂sinθ₂

          1 sin52 = 1.33sinθ₂

                  θ₂ = arcsin(sin52 / 1.33)

                  θ₂ = 36°

as measured from the perpendicular to the surface

Answer:

 |F| = 35 kN

Explanation:

a = F/m

100 km/hr(1000 m/km / 3600 s/hr) = 27.8 m/s

v² = u² + 2as

   a = (v² - u²) / 2s

F/m = (v² - u²) / 2s

   F = m(v² - u²) / 2s

   F = 5000(0² - 27.8²) / 2(55)

   F = - 35,072.9517...

The potential difference between the initial and final point is 3.0 V.

The given parameters:

The potential difference between the initial and final point is calculated as follows;

[tex]E = \frac{V}{d} \\\\\frac{V_1}{d_1} = \frac{V_2}{d_2}[/tex]

where:

[tex]d_2[/tex] is the distance of the electron between the positive and negative plate

[tex]0.1 + d_2 + 0.05 = 0.2\\\\d_2 + 0.15 = 0.2\\\\d_2 = 0.2 - 0.15\\\\d_2 = 0.05 \ m[/tex]

[tex]V_2 = \frac{V_1d_2}{d_1} \\\\V_2 = \frac{12 \times 0.05}{0.2} \\\\V_2 = 3.0 \ V[/tex]

Thus, the potential difference between the initial and final point is 3.0 V.

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Answer:

Kinetic energy = (1/2) (mass) (speed²)

First object: (1/2) (2 kg) (2 m/s)² = 4 joules .

Second object: (1/2) (4 kg) (3 m/s)² = 18 joules .

The second object had more kinetic energy than the first one had.

Explanation:

Answer:

Kinetic energy = (1/2) (mass) (speed²)

First object: (1/2) (2 kg) (2 m/s)² = 4 joules .

Second object: (1/2) (4 kg) (3 m/s)² = 18 joules .

The second object had more kinetic energy than the first one had.

Answer:

non economic benefits to international trade means not being too much profit not selling too much things /items in international trade

The characteristics of the speed of the traveling waves allows to find the result for the tension in the string is:  

         T = 10 N

The speed of a wave on a string is given by the relationship.

      v =[tex]\sqrt{\frac{T}{\mu } }[/tex]

Where   v es the velocty, t is the tension ang μ is the lineal density.

They indicate that the length of the string is L = 2.28 m and the pulse makes 4 trips in a time of t = 0.849 s, since the speed of the pulse in the string is constant, we can use the uniform motion ratio, where the distance traveled e 4 L

           v = [tex]\frac{d}{t}[/tex]  

           v = [tex]\frac{4 L}{t}[/tex]  

           v = [tex]\frac{4 \ 2.28 }{0.849}[/tex]  

            v = 10.7  m / s

Let's find the linear density of the string, which is the length of the mass divided by its mass.

            μ = [tex]\frac{m}{L}[/tex]  

            [tex]\mu = \frac{0.2}{2.28}[/tex]  

            μ = 8.77 10⁻² kg / m

The tension is:

        T = v² μ

Let's calculate

        T = 10.7²  8.77 10⁻²

        T = 1 0 N

In conclusion using the characteristics of the velocity of the traveling waves we can find the result for the tension in the string is:

         T = 10 N

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Explanation:

1. Movement, or a tendency to move, toward a center of gravity, as in the falling of bodies to the earth.

2. Movement toward or attraction to something.

"a tentative gravitation toward the prices that we saw before the announcement"

Carbon-Based Fuels Dominate Global Energy Use

Crude oil, coal, and natural gas supply about 85% of the energy used in the world. Fossil fuels are valuable as sources of energy because they contain hydrocarbons and other carbon-based materials.

The magnitude of the force that must be applied to push the book across the desk is 3.97 N.

The given parameters;

The acceleration of the book across the desk is calculated as follows;

a = μg

where;

a = 0.3 x 9.8

a = 2.94 m/s²

The magnitude of the force that must be applied is calculated as follows;

F = ma

F = 1.35 x 2.94

F = 3.97 N

Thus, the magnitude of the force that must be applied to push the book across the desk is 3.97 N.

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The rate of heat energy exhausted to the river is 600.96 MW.

The ratio of usable output to total input can be used to objectively measure efficiency. The efficiency of the device is defined as the ratio of energy converted to a useable form to the original amount of energy supplied.

Given parameters:

Efficiency of the power plant; η = 31 %

Output  electric power; O = 270 MW.

We know that, Efficiency of the power plant;

η  = (Output  electric power/ input power)× 100%

⇒ input power = (Output  electric power × 100)/η

⇒ input power = (270 × 100)/31 MW

= 870.96 MW.

So, the rate of heat energy exhausted to the river that cools the plant =  Input power- output power

= (870.96 - 270) MW

= 600.96 MW.

Hence, heat energy exhausted to the river that cools the plant  is 600.96 MW.

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Answer:

A. For every action there is an equal and opposite reaction.

Answer:

Moses had told them to not keep the food till morning but some kept some anyways because they probably thought they were going to starve or not have food the next morning but what I think it means is that you have to trust in God that he will provide for you and so when the people kept the food cuz he thought they were probably going to start of the next day it got maggots

Answer:b

Explanation:

Answer:

The lobster let the claw go. so, B.

Explanation:

i hope this helps.

The velocity of the boat moving at the given conditions is 5.97 km/h at 67⁰.

The given parameters;

The resultant vertical velocity of the boat is calculated as;

[tex]v_y = 8 \ - \ 5 sin(30)\\\\v_y = 8 - 2.5\\\\v_y = 5.5 \ km/h[/tex]

The resultant horizontal velocity of the boat is calculated as;

[tex]v_x = -2 \ + 5cos(30)\\\\v_x = 2.33 \ km/h[/tex]

The resultant boat velocity is calculated as follows;

[tex]v = \sqrt{v_x^2 + v_y^2} \\\\v = \sqrt{2.33^2 + 5.5^2} \\\\v = 5.97 \ km/h[/tex]

The direction of the velocity;

[tex]\theta = tan^{-1} (\frac{v_y}{v_x} )\\\\\theta = tan^{-1}(\frac{5.5}{2.33} )\\\\\theta = 67 \ ^0[/tex]

Thus, the velocity of the boat moving at the given conditions is 5.97 km/h at 67⁰.

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Answer:

100 w bulb has more current.

Explanation:

P=V^2/R.

when velocity is constant power is inversly proportional to resistence, so 25 W will have an hogher resistance tjan a 100 w bulb.

P=VI

when v is constant, power is directly proportional to I. hence, 100 w bulbs will carry more current.

When you connect one or the other, the bulb that's connected carries more current than the one that's not connected.

When you connect BOTH of them, the 100W bulb carries more current than the 25W one.

The right hand rule to find the direction of the magnetic field for a falling bar is:

The magnetic force is given by the vector product of the velocity and the magnetic field.

        F = q v x B

Where the bolds indicate vectors, F is the force, q the charge on the particle, v the velocity and B the magnetic field.

In the vector product, the vectors are perpendicular, which is why the right-hand rule has been established, see attached:

They indicate that the bar is dropped, therefore its speed is vertical and downwards, it moves to the left therefore this is the direction of the force, we use the right hand rule, the magnetic field must be horizontal, we have two possibilities:

In conclusion using the right hand rule we can find the direction of the magnetic field for a falling bar is:

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Answer: False

Explanation:

It's received in elliptical cavities.

False. The statement is not entirely accurate. Condyloid joints are a type of synovial joint that allow movement in two planes, similar to an ellipsoid joint.

These joints are characterized by an oval-shaped projection of one bone fitting into an elliptical cavity of another bone. The term "condyle" does refer to a rounded projection or bump on a bone, but not all condyle bone markings create condyloid joints.

Condyloid joints are found in various parts of the body, such as the wrist (between the radius and carpal bones) and the knuckles (between the metacarpal bones and phalanges). They allow for movements such as flexion, extension, abduction, adduction, and circumduction.

It's important to note that the formation of a condyloid joint involves not only the presence of condyle bone markings but also the specific structural arrangement of the bones and the presence of articular cartilage, joint capsule, and synovial fluid. Therefore, while the term "condyle" is related to these joints, it does not accurately capture the complexity of their formation and function.

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Answer:

In hydrogeology, groundwater flow is defined as the "part of streamflow that has infiltrated the ground, entered the phreatic zone, and has been (or is at a particular time) discharged into a stream channel or springs; and seepage water." It is governed by the groundwater flow equation.

Answer:

Climate Change

Ito ang pagbabago sa normal na panahon sa isang lugar. Maaaring abnormal na pagbabago sa ulan na nattanggap ng isang lugar sa isang taon o ang abnormal na pagbabago sa init ng panahon.

Paano masusulusyunan ito?

Tanggalin sa pagkakasaksak ang mga gadgets kapag puno na

Huwag pumutol ng mga puno

Iwasan ang pagsakay sa transportasyon kung malapit lang ang pupuntahan

Explanation:

pa brainliest

Answer:

Explanation:

95.0 km/hr = 26.39 m/s

65 km/hr = 18.06 m/s

Circumference of a tire is 0.9π m

77 revolutions is a distance of

77(0.9π) = 69.3π m

v² = u² + 2as

a = (v² - u²) / 2s

a = (18.06² - 26.39²) / (2(69.3π))

a = -0.85 m/s²

s = (v² - u²) / 2a

s = (0² - 26.39²) / 2(-0.85)

s = 409 m