In a circle with radius of 10 millimeters, find the area of a sector whose central angle is 102°. Use 3.14 for π a. 177.93 mm^2b. 88.97 mm^2 c. 314 mm^2 d. 355.87 mm^2

Quantum computing is a better fit than classical computing because it can access advanced simulations for vast quantities of weather.

What is Quantum computing?

Quantum computing can process large number of data sets of weather for all the properties of quantum states. Unlike classical computers which contains only standard bits 0 and 1 , quantum computing use Qubit or Quantum bit in which there are more than two standard sets of bits. These Qubits can measure the light at any degrees of polarisation between 1 and 0.This is the spin attribute that corresponds to superposition. This can create a lot more possibilities beacuse we can run multiple tasks at once with only one bit of data beacuse of the superpositioned qubit. This unlike classical computers where the bit can be only 1 and 0 is more effectively used in breaking encryption tasks.

So, the analysis of vast quantities of weather data can be done in seconds using Quantum computing.

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The average electric current in the lightning will be 8 × [tex]10^{-17}[/tex] A

The lightning conductors are long metal strips running from the spike end of a conductor on the top of a building to the earth. They are used to prevent buildings from destruction when struck by thunder or lightning.

Given that a lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms, to calculate the average electric current in the lightning, we will first consider the charge released.

one charge = 1.6 × [tex]10^{-19}[/tex] C

Average current I = Q/t

Where

Substitute all the parameters into the formula

I = 1.6 × [tex]10^{-19}[/tex] C ÷ 2 × [tex]10^{-3}[/tex]

I = 8 × [tex]10^{-17}[/tex] A

Therefore, the average electric current in the lightning will be 8 × [tex]10^{-17}[/tex] A

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     charge must be equal to 5.74 ×10⁻⁵

 In the question it is said that the particle remains stationary which means the the net force on the particle is zero. So, the counterbalancing forces must be equal which means weight is equal to upward electric force.

     →    Fnet =0

     →    mg =  qE

 substituting the values we get :

         0.00345 × 9.81 =  q × 590

   →       q = 5.74 ×10⁻⁵

    Hence the charge must be equal to   5.74 ×10⁻⁵.

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The angle between the two vectors is 0⁰, thus the two vectors are parallel to each other.

The angle between the vectors describes the direction of the vector and the value of the angle can be determined from the horizontal and vertical components of the vectors as shown below.

The sum of the horizontal components and vertical components of the vectors is calculated as follows;

Sum of the horizontal component of the vectors, x = 1 + 1 = 2

Sum of the vertical component of the vectors, y = -1 + 1 = 0

The angle between the vectors is calculated as follows;

θ = arc tan (y/x)

θ = arc tan (0/2)

θ = arc tan (0)

θ = 0⁰

The angle between the two vectors is 0⁰, thus the two vectors are parallel to each other.

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Answer: C. 90°

Explanation:

The image formed will be located between the focal point, f and double of the distance from focal point, 2f.

A convex lens is the name given to any converging lens.

A converging lens or convex lens is a lens that converges rays of light that are traveling parallel to its principal axis.

The focal length, f of a lens is  the distance between the center of a lens  and its focus.

For an object that is placed between infinity and double of the distance from focal point, along a line perpendicular to the center of the lens,

The image formed will be located between the focal point, f and double of the distance from focal point, 2f.

Thus, for an object placed between infinity and 2f from the lens along a line perpendicular to the center of the lens. The image formed will be located between the focal point, f and double of the distance from focal point, 2f.

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The hottest celebrity is this one.

The majority of stars fall under a select few spectral categories. The hottest to the coldest stars are listed in the spectral types of the Henry Draper and Bright Star Catalogues (see stellar classification). The letters O, B, A, F, G, K, and M are used to indicate these categories in decreasing order of temperature.

Using spectral types, we can categorise stars based on their colour or the spectral lines that are visible in their light. The spectral types are OBAFGKM, with the hottest stars being O and the coldest being M. To humans, cooler stars appear redder and hotter stars appear bluer.

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The  energy of photon in kJ/mol is 329kJ/mol.

Wavelength of radiation is 370nm. The frequency of given wavelength is

            ν = c / λ

            ν = 3×10^8 / 370×10^-9

            ν = 8.11 × 10^14 s^-1

      Now the energy of photon is:

             E = hν

             E = 6.63×10^-34  J.s/photon × 8.11×10^14s^-1

             E = 5.41× 10^-19  J/photon

         To find in mole

              E = 5.41× 10^-19 × 6.022×10^23

               E = 3.29 ×10^ 5 J/mol

   So, the energy of mole of photon is equal to 329 kJ/mol.

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Answer:

4.8 Ω

Explanation:

Ohm's law

V = IR

 or    V/I = R

        12/2.5 = R = 4.8 Ω

The initial temperature of the water was [tex]41.6688^{0} C[/tex].

Given,

Weight of glass 36.5g

specific heat for glass is 840 J/kg⋅C∘.

Initial temperature of glass was  [tex]23.6^{0} C[/tex].

Weight of water is 145*1=145g (Density*Volume=145ml*1g/ml)

Temperature final was [tex]40.8^{0} C[/tex].

specific heat for water is 4186 J/kgâ‹…Câˆ

(m of glass)(Cp of glass)(Tf_glass-Ti_glass) = (m of water)(Cp of water)(Ti_water - Tf_water)

36.5*840*(40.8-23.6)=145*4186*(Ti_water - 40.8)

Ti_water=[tex]41.6688^{0} C[/tex]

In thermodynamics, a material's specific heat capacity, or massic heat capacity as it is sometimes known, is equal to the heat capacity of a sample of the substance divided by the mass of the sample (symbol cp). Informally, it is the quantity of heat needed to raise a substance's temperature by one degree for every unit of mass that is added to it. joule per kelvin per kilogram, or Jkg1K1, is the SI unit for specific heat capacity. For instance, the amount of energy needed to increase the temperature of 1 kilogram of water by 1 K is 4184 joules, making water's specific heat capacity 4184 J kg 1 K 1.

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The total distance the toy car traveled is D. 19cm

The total distance of the toy car traveled in cm would be calculated

We would add the sum:

D = 9 + 4 + 6 cm

D = 19 cm

Therefore, the total distance the toy car traveled in cm is 19 cm.

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It turns out that the star in question belongs to the K5V star class. Thus, the surface temperature of this must be between 5200 K and 3700 K. It has a surface temperature of 6200 K to 5200 K and is a G2V class star, commonly known as Bernard's star. In other words, the star in question has a colder surface than HIP 87937. This is further explained below.

Generally, The temperature at a surface is referred to as the surface temperature. In particular, it may refer to the surface air temperature, which is the temperature of the air that is relatively close to the earth's surface.

In conclusion, The star in question is of the K5V type. Therefore, the temperature of the surface of this must be somewhere between 5200 and 3700 kelvin. The star with the designation HIP 87937, often known as Bernard's star, is of the G2V type. Stars of this type have a surface temperature that falls anywhere between 6200 and 5200 degrees Celsius. Therefore, it should come as no surprise that the surface temperature of the given star is lower than that of HIP 87937.

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Answer: It is hotter because K is before M

Explanation:

The actual surface temperature of this star is 4600 KK compared to 3100 KK for the M4 star in Parts A and B.

Answer:

yes

Explanation:

The heater is placed near the floor because the air currents move upwards so the hot air fills up the whole room. Whereas, an air conditioner is placed near the ceiling because the cold breeze tends to settle down. If it is placed near the floor then it will fill just the bottom of the room with cool air.

After the rod is charged and then touched on the neutral metallic sphere and then separated from it, the rod  is repelled by the sphere. Option A

There are very ways in which a static charge could be built up in an object. The ways include;

Now, after the rod is charged and then touched on the neutral metallic sphere and then separated from it, the rod  is repelled by the sphere.

Missing parts;

A plastic rod is charged up by rubbing a wool cloth, and brought to an initially neutral metallic sphere that is insulated from the ground. It is allowed to touch the sphere for a few seconds, and then is separated from the sphere by a small distance. After the rod is separated, the rod

A. is attracted by the sphere

B. is repelled by the sphere

C. feels no force due to the sphere

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The focal length of eyepiece is 2.85.

It is given that astronomical telescope is designed with over magnification of 35.

The object has a focal length of 100 cm.

We need to determine the focal length of the eyepiece.

The formula to be used here is for astronomical telescope is:

[tex]m=\frac{f_{0} }{f_{e} }[/tex]

Using values here, we get

[tex]35=\frac{100 }{f_{e} }[/tex]

[tex]f_{e}=100/35=2.85[/tex]

Hence, the focal length of eyepiece is 2.85

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Gravity follows an inverse square law. This means that if the distance between two masses is decreased by a factor of 4, the gravitational force between those two masses: C. increases by a factor of 16.

Gravitational force is an attractive force that exists between all objects with mass; an object with mass attracts another object with mass; the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects.

Force between two masses = G M1 M1 / [tex]R^{2}[/tex]

since , gravitation force d follows an inverse square law

F is directly proportional to 1/[tex]R^{2}[/tex]

If distance between two masses is decreased by a factor of 4

Let initial distance  : R

when distance between two masses is decreased by a factor of 4 = 4R

Force  = G M1 M1 / [tex](4R)^{2}[/tex]

Force =  G M1 M1 / [tex]16R^{2}[/tex]

16 Force = G M1 M1 / [tex]R^{2}[/tex]

since , there is an inverse relation , so if distance is decreased , gravitation force will increase .

hence, gravitational force will increase by factor of 16

correct option C. increases by a factor of 16.

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Answer:

f=110HZ

Explanation:

Calculate the frequency of a wave

Based on equation λ= VT but T= 1/f

=> λ=V/f

=> f= V/λ

by V=22m/s

λ= 0.20m

=> f= 22/0.20= 22/(2×10-¹) = 110Hz

So the frequency of a wave is f=110Hz

Answer:

110

Explanation:

velocity=wavelength×frequency

22=0.20f

divide both sides by 0.20

22/0.20=0.20f/0.20

f=22/0.20

f=110

The role of Gravity in the formation of the solar system is that gravity caused the the solar system to move closer to the Sun.

  This was possible because gravity attracted smaller particles together until they formed large particles and began to rotate around the sun.

Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.

Gravity can also be said to mean an attraction between objects  objects with mass.

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400 J power will be delivered by lifting a stone of mass 2 kg at the height of 20m in two minutes.

The quantity of energy transferred or transformed per unit of time is known as power. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as an activity in ancient writings. A scalar quantity is a power.

Work completed and time is linked in the power equation. Since forces may move objects and we know that forces perform work, we might anticipate that by understanding the power, we can gain insight into how a body moves through time. This outcome may be especially beneficial.

Given that, a stone ‘X’ of mass 2 kg is lifted to the height of 20m in two minutes, and g=10 m/s-2

Power Delivered = Work done in lifting the stone

Work Done = Potential energy = mgh

Work done = 2 × 10 × 20

Work done = 400 J

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Option A.  A force does work on an object if a component of the force is  is parallel to the displacement of the object.

The force applied to an object to displace it from a given point to another point is known as work done on the object.

W = Fd cosθ

where;

Thus, A force does work on an object if a component of the force is  is parallel to the displacement of the object.

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The mass at the other end of bar will be 50g .

what is mass

It is the fundamental property of matter , every single property which exist in this world has mass

Mass never can be 0 .

So , the system is in equilibrium

let mass of the body be m

55×5= m×5.5

m= 5 5 × 5 /. 5.5

m= 5 0g



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137.5 kg mass can be placed 2m away from the other end of the bar to keep the bar horizontally.

To keep the bar horizontal, the right and left side torques must be equal:

[tex]F_{1} d_{1} =F_{2} d_{2}[/tex]

[tex]F_{2} =F_{1} \frac{d_{1} }{d_{2} }[/tex]

    [tex]=(55.9.8)\frac{5}{2}[/tex]

    =1347.5 N.

Convert this force of gravity into mass:

[tex]F_{2} =m_{2} g,[/tex]

[tex]m_{2} =\frac{F_{2} }{g}[/tex]

     [tex]=\frac{1347.5}{9.8}[/tex]

     =137.5 kg.

The answer is 137.5 kg.

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frequency fapproach is heard by a passenger = 302.05 Hz

frequency frecede is heard by a passenger = 228.37433 Hz

Given :

speed of train to the ground = 30.0 m/s

frequency emitted by the train whistle = 262 Hz

speed of sound in air = 344 m/s

To Find :

(A) frequency fapproach (B) frequency frecede

Solution :

The frequency of approach is given by

f' = f v + v(relative)

v - v(air)

= 262x 344 + 18

344 - 30

f' = 302.05 Hz

The frequency of approach is 302.05 Hz

The frequency of recede is given by

f' = f v - v(relative)

v + v(air)

= 262 x 344 - 18

344 + 30

The frequency of recede is 228.37433 Hz

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Pelvic girdle

In human anatomy, the pelvis is a complex of bones that connects the trunk and the legs, supports and balances the trunk, and houses and supports the intestines, the urinary bladder, and the internal organ. It is sometimes referred to as the bony pelvis or the pelvic girdle.
One is located on the left side of the body and the other is located on the right. They come together to make the pelvic girdle, a portion of the pelvis. The hip bones are attached to the upper portion of the skeleton at the sacrum.
The pelvic girdle's main function is to support the upper body's weight while seated and transfer that weight to the lower limbs while standing. For the muscles in the trunk and lower limbs, it functions as attachment point.

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Answer:

2.72×10^-7

Explanation:

velocity = frequency × wavelength

2.05×10^8=7.55×10^14 wavelength

wavelength = 2.05×10^8/7.55×10^14

wavelength = 2.72×10^-7

Answer:

The fringes are 4.7*10^-7 m apart, such that they are adjacent.

Explanation:

Using the formula for adjacent fringes given a single slit:

Δ[tex]x=\frac{(Wavelength)(Distance between slit and screen)}{Width}[/tex]

Δ[tex]x=\frac{(590/10^{9})(1.90) }{(2.30)}[/tex]

Δ[tex]x=0.000000487 m[/tex]

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The distance between the first-order and second-order dark fringes on the screen will be 4.874 × 10⁻⁵ cm.

Given:

wavelength, λ = 590 nm = 590 × 10⁻⁹ m

Distance between the slit and screen, D = 1.90 m

Width of slit, d = 2.30 m

Calculation:

We know that the distance between two slits is given as:

Δx = λD / d

where  λ is the wavelength of light

           D is the distance between the slit and screen

           d is the width of the slit

Applying values in the above equation we get:

Δx = (590 × 10⁻⁹ m)(1.90 m) / (2.30 m)

    = 4.874 × 10⁻⁷ m

    = 4.874 × 10⁻⁵ cm

Therefore, the distance between the first- and second-order dark fringes on the screen will be 4.874 × 10⁻⁵ cm.

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The net electric field at point D is determined as 3.95 x 10⁷ N/C.

E = kq/r²

where;

E(AD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)

E(AD) = 2.16 x 10⁷ i N/C

E = kq/r²

where;

r² = 5²  + 5²

r² = 50

r = √50

r = 7.07 cm

E(BD) = (9 x 10⁹ x 5 x 10⁻⁶)/(0.0707²)

E(BD) = 9 x 10⁶ N/C

in x - direction = 9 x 10⁶ N/C x cos(45) = 6.36 x 10⁶ i  N/C

in y - direction = 9 x 10⁶ N/C x sin(45) = 6.36 x 10⁶j  N/C

E = kq/r²

where;

E(CD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)

E(CD) = 2.16 x 10⁷ j N/C

Ei = 2.16 x 10⁷ i N/C  + 6.36 x 10⁶ i  N/C

Ei = 2.796 x 10⁷ i N/C

Ej = 2.16 x 10⁷ j N/C  + 6.36 x 10⁶j  N/C

Ej = 2.796 x 10⁷ j N/C

E = √Ei² + Ej²

E = √[(2.796 x 10⁷)² + (2.796 x 10⁷)²]

E = 3.95 x 10⁷ N/C

Thus, the net electric field at point D is determined as 3.95 x 10⁷ N/C.

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What is Law of conservation of charge?

Law of conservation of charge states that, "the total electric charge in an isolated system is always constant".

It can also be stated as, "Charge can neither be created nor destroyed but can only be converted from one form of energy to another".

What are the properties of conductors?

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The optic chiasm is the point where the optic nerves cross the midline, allowing the opposite side of the brain to process sensory data from one side of the body.

Since the optic nerves cross in the optic chiasm, also known as the optic chiasma, it plays a crucial role in the visual pathway. Within the suprasellar cistern, it is situated 10 mm above the pituitary gland and 10 mm beneath the hypothalamus near the base of the brain.

The optic chiasm's function is to make sure that visual impulses reach both hemispheres of the brain. The thalamus receives and processes the majority of brain impulses, which are then transmitted to various parts of the occipital lobe. Half of each divided optic nerve's fibers travel to the opposing side. Due to the anatomical configuration, injury to the optic nerve system results in particular patterns of vision loss.

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A long narrow solenoid has length l and a total of N turns, each of which has cross-sectional area A. Its inductance is μ₀ ( [tex]\frac{N^2A}{l}[/tex] ).

To find the answer, we need to know about the magnetic field due to a solenoid.

                             [tex]B=[/tex] μ₀n [tex]I[/tex]

                               [tex]n=\frac{N}{l}[/tex]

                            Φ [tex]= BA[/tex] Where, A is the area.

                                       Ф [tex]= \frac{NIA}{l}[/tex] μ₀

                                        Ф [tex]= LI[/tex]

                                        μ₀ ( [tex]\frac{N^2A}{l}[/tex] ) [tex]I[/tex]  [tex]=LI[/tex]

                                         [tex]L=[/tex] μ₀ ( [tex]\frac{N^2A}{l}[/tex] ).

Thus, we can conclude that the expression for inductance is  μ₀ ( [tex]\frac{N^2A}{l}[/tex] ).

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The inductance of a solenoid having N number of turns, area A and a length l will be equal to μ₀ ( [tex]\frac{N^2A}{l}[/tex]).

We need to understand the magnetic field created by a solenoid in order to determine the solution.

                                    [tex]B=\frac{NI}{l}[/tex]×μ₀

                                   [tex]flux=BA[/tex]  , A is the area.

                                      [tex]flux=\frac{NIA}{l}[/tex] times the μ₀.

                                        [tex]flux=IL[/tex]

                                     μ₀ ( [tex]\frac{N^2AI}{l}[/tex])= [tex]LI[/tex]

                                     [tex]L=[/tex] μ₀ ( [tex]\frac{N^2A}{l}[/tex]).

As a result, we can say that the inductance expression is   [tex]L=[/tex] μ₀ ( [tex]\frac{N^2A}{l}[/tex]).

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To correct the error in the diagram, we need to change +2Q to +Q in order for the charges to become balanced. Option A

A capacitor is  device that is used for storing electric charge. We know that the capacitor is composed of two conductors separated by an insulator.

In order to correct the error in the diagram, we need to change +2Q to +Q in order for the charges to become balanced. Option A

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Answer:

A

Explanation:

Answer:

Approximately [tex]13\; {\rm N \cdot m^{-1}}[/tex] (assuming that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex].)

Explanation:

Let [tex]F_{\text{s}}[/tex] denote the force that this spring exerts on the object. Let [tex]x[/tex] denote the displacement of this spring from the equilibrium position.

By Hooke's Law, the spring constant [tex]k[/tex] of this spring would ensure that [tex]F_\text{s} = -k\, x[/tex].

Note that the mass of the object attached to this spring is [tex]m = 540\; {\rm g} = 0.540\; {\rm kg}[/tex]. Thus, the weight of this object would be [tex]m\, g = 0.540\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \approx 5.230\; {\rm N}[/tex].

Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus, [tex]F_{\text{s}} = 5.230\; {\rm N}[/tex].

The spring in this question was stretched downward from its equilibrium by:

[tex]\begin{aligned} x &= (70\; {\rm cm} - 110\; {\rm cm}) \\ &= (-40)\; {\rm cm} \\ &= (-0.40) \; {\rm m}\end{aligned}[/tex].

(Note that [tex]x[/tex] is negative since this displacement points downwards.)

Rearrange Hooke's Law to find [tex]k[/tex] in terms of [tex]F_{\text{s}}[/tex] and [tex]x[/tex]:

[tex]\begin{aligned} k &= \frac{F_{\text{s}}}{-x} \\ &\approx \frac{5.230\; {\rm N}}{-(-0.40)\; {\rm m}} \\ &\approx 13\; {\rm N \cdot m^{-1}}\end{aligned}[/tex].