In a data set with a normal distribution, the mean is 98 and the standard deviation is 12. About what percent of the data lie between 74 and 122?

Answer:

907.46

Step-by-step explanation:

diameter = 34

radius = 17 (half of diameter)

A=πr^2

HOPE THIS HELPS PLZ MARK BRAINLIEST! :)

Answer:

what is the question?

Step-by-step explanation:

i need the question to answer

The first step when multiplying fractions is to find the reciprocal of the second fraction.

The statement is False.

The first step when multiplying fractions is to find the reciprocal of the second fraction.

The given statement is FALSE.

Because, First step in multiplying fractions is multiply the numerator from each fraction. That is, multiply the top number first.

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[tex]\cos\theta=\frac{10}{14}\\ \\

\theta=\cos^{-1}\frac{10}{14}\\ \\

\theta=44^o [/tex]

Answer:

20

Step-by-step explanation:

Answer:

Hello! I hope you are having a great day~

Here is the answer:

Mean Absolute Deviation (MAD): 4.33

Step-by-step explanation:

Mean absolute deviation (MAD) of a data set is the average distance between each data value and the mean. Mean absolute deviation is a way to describe variation in a data set. So the average distance is 4.33! It has already been rounded to the hundredth place

Answer:

The answer would be 30.

Step-by-step explanation:

Calculating 9×100÷30 equals 30 and that would be your answer.

Answer:

30

Step-by-step explanation:

30% * x = 9

x = 9/30%

x = 9/0.3

x = 30.

So, 30 is the number

Answer:

Z = 1

Step-by-step explanation:

Simplify the equation using PEMDAS.

4 x 2 - z = 7

8 - x = 7

- x = 7 - 8

-x = - 1

x = 1

Answer:

09

Step-by-step explanation:

After plotting the above equation on the coordinate plane, we can see the graph of the function.

A parametric equation in mathematics specifies a set of numbers as functions of one or more independent variables known as parameters.

We have two parametric equations:

x = 1 – t² and

y = 2t

t = y/2  and

0 ≤ t² ≤ 5

1 ≤ 1 - t²≤ 4

1 ≤ x≤ 4

Plug the above value in x = 1 – t²

x = 1- (y/2)²

x = 1 - y²/4

4x = 4 - y²

y² = 4(1 - x)

Thus, after plotting the above equation on the coordinate plane, we can see the graph of the function.

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Answer:

First Blank: Traditional

Second Blank: (the other choice, besides exempt)

Third Blank: Roth

Fourth Blank: Taxes exempt

Step-by-step explanation:

I got 5/5 on the test by reading through the other guys answer.

In a traditional 401(k), it is tax deferred because the income earned isn't taxed until the money is withdrawn.

Income tax is a tax applied on individuals or entities concerning income or profit earned by them.

A 401 k is a qualified tax-advantaged saving retirement plan. Usually, The 401K  plans are employer-sponsored. Employee contributions to the 401 k plans are deducted from the payroll before the taxes can be calculated.

This means that the employee contribution is not taxed at the time it's withheld by the employer.

The amounts saved are invested in market securities such as shares and companies bonds. The tax due from the money from the investment is deferred to the time of withdrawal.

The employee are needed to pay taxes on contributions and investments earning every financial year.

In a traditional 401(k), it is tax deferred because the income earned isn't taxed until the money is withdrawn.

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9514 1404 393

Answer:

  f(g(n)) = 4n-3

Step-by-step explanation:

f(g(n)) = f(4n -1) = (4n -1) -2

f(g(n)) = 4n -3

Answer:

Option (D)

Step-by-step explanation:

Given expression is,

x³ × 3 ÷ [tex]\frac{2}{9}[/tex] + 9x - (7 - 6x)

By substituting x = [tex]\frac{2}{3}[/tex],

[tex](\frac{2}{3})^3\times 3 \div \frac{2}{9}+9(\frac{2}{3})-[7-6(\frac{2}{3})][/tex]

By using rule PEMDAS,

P - Parenthesis

E - Exponent

M - Multiplication

D - Division

A - Addition

S - Subtraction

[tex]=(\frac{2}{3})^3\times 3 \div \frac{2}{9}+9(\frac{2}{3})-[7-4][/tex]

= [tex](\frac{2}{3})^3\times 3 \div \frac{2}{9}+9(\frac{2}{3})-3[/tex]

= [tex]\frac{8}{27}\times 3 \div \frac{2}{9}+6-3[/tex]

= [tex]\frac{8}{9}\div \frac{2}{9}+6-3[/tex]

= [tex]\frac{8}{9}\times \frac{9}{2}+6-3[/tex]

= 4 + 6 - 3

= 7

Option (D) is the answer.

9514 1404 393

Answer:

  1.0 N

Step-by-step explanation:

When the length increases by the factor 120/80 = 3/2, the force required is multiplied by the inverse of this: 2/3.

The required force is ...

  (2/3)(1.5 N) = 1.0 N

Answer:

The last one

Step-by-step explanation:

Answer:

{(0,2), (-9,7), (-6, -1), (-2,2)}

Step-by-step explanation:

You can see if points are a function by seeing if the first value in the parenthesis (X value) and if they are the same, the points are not a function. The only points where the first value in the parenthesis are not the same is in the fourth set of points.

Answer:

t=-p/5+20

Step-by-step explanation:

p=100−5t

Swap sides so that all variable terms are on the left hand side.

100−5t=p

Subtract 100 from both sides.

−5t=p−100

Divide both sides by −5.

−5t/5 = p - 100/-5

Dividing by −5 undoes the multiplication by −5.

t = p - 100/-5

Divide p−100 by −5.

t=-p/5+20

Answer:

Since P(male)xP(fail) = 0.0549 and and P(male and fail) = 0.0773, the two results are different, so the events are not independent.

Step-by-step explanation:

Independent events:

Two events, A and B are independent, if:

[tex]P(A \cap B) = P(A)P(B)[/tex]

Probability of male:

58 + 14 = 72 males out of 58 + 14 + 98 + 11 = 181

So

P(male) = 72/181 = 0.3978

Probability of failling:

14 + 11 = 25 students fail out of 181. So

P(fail) = 28/181 = 0.1381

Multiplitication of male and failling:

0.3978*0.1381 = 0.0549

Probability of being male and failing:

14 out of 181. So

14/181 = 0.0773

Different probabilities, so not independent.

Since P(male)xP(fail) = 0.0549 and and P(male and fail) = 0.0773, the two results are different, so the events are not independent.

9514 1404 393

Answer:

  conditions for similarity are not violated by the transformation

Step-by-step explanation:

Dilation changes linear measures proportionally, and has no effect on angles. Rotation changes neither lengths nor angles. Hence the dilated, rotated triangle has the same angles as the original, and has proportional side lengths. Those are the requirements for figures to be similar, so the triangles are similar.

Answer:

The corresponding angles of the triangles are congruent

The image is a reduction of the pre-image

Neither the dilation nor the rotation change the shape of the triangle

Explanation:

For shapes to be similar:

1- there should be a ratio between the sides

2- angles in first shape should be congruent to angles in second shape

Now, a scale factor of 0.2 means that the sides of the image are 0.2 of the length of the original shape. However, angles are not changes

Let's check the choices:

1- The corresponding sides of the triangles are congruent:

This option is incorrect as dilation changes the lengths of the sides

2- The corresponding angles of the triangles are congruent:

This option is correct as neither dilation nor rotation alters the measures of the angles

3- The corresponding sides of the image are 5 times as long as those of the pre-image:

This option is incorrect as the sides of the image are only 0.2 times as long as those of the pre-image

4- The image is a reduction of the pre-image:

This option is correct as the sides of the image are 0.2 times those of the pre-image which means that the shape is reduced

5- Neither the dilation nor the rotation change the shape of the triangle:

This option is correct as both dilation and rotation are rigid transformations that do not alter the shape of the triangle (a triangle remains a triangle only with different side lengths)

6- The rotation reduces the size of the triangle:

This option is incorrect as rotation does not alter the size of the shape. It only changes its position

Hope this helps :)

Answer:

ayooo i'll take it

Step-by-step explanation:

thanks

Answer:

Ooh a couple more for 100 points!!

Step-by-step explanation:

Answer:

[tex]P(X > 11) = 0.368[/tex]

[tex]P(X > 22) = 0.135[/tex]

[tex]P(X > 33) = 0.050[/tex]

[tex]x = 33[/tex]

Step-by-step explanation:

Given

[tex]E(x) = 11[/tex] --- Mean

Required (Missing from  the question)

[tex](a)\ P(X>11)[/tex]

[tex](b)\ P(X>22)[/tex]

[tex](c)\ P(X>33)[/tex]

(d) x such that [tex]P(X <x)=0.95[/tex]

In an exponential distribution:

[tex]f(x) = \lambda e^{-\lambda x}, x \ge 0[/tex] --- the pdf

[tex]F(x) = 1 - e^{-\lambda x}, x \ge 0[/tex] --- the cdf

[tex]P(X > x) = 1 - F(x)[/tex]

In the above equations:

[tex]\lambda = \frac{1}{E(x)}[/tex]

Substitute 11 for E(x)

[tex]\lambda = \frac{1}{11}[/tex]

Now, we solve (a) to (d) as follows:

Solving (a): P(X>11)

[tex]P(X > 11) = 1 - F(11)[/tex]

Substitute 11 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-\frac{1}{11}* 11})[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-\frac{11}{11}})[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-1})[/tex]

Remove bracket

[tex]P(X > 11) = 1 - 1 + e^{-1}[/tex]

[tex]P(X > 11) = e^{-1}[/tex]

[tex]P(X > 11) = 0.368[/tex]

Solving (b): P(X>22)

[tex]P(X > 22) = 1 - F(22)[/tex]

Substitute 22 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-\frac{1}{11}* 22})[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-\frac{22}{11}})[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-2})[/tex]

Remove bracket

[tex]P(X > 22) = 1 - 1 + e^{-2}[/tex]

[tex]P(X > 22) = e^{-2}[/tex]

[tex]P(X > 22) = 0.135[/tex]

Solving (c): P(X>33)

[tex]P(X > 33) = 1 - F(33)[/tex]

Substitute 33 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-\frac{1}{11}* 33})[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-\frac{33}{11}})[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-3})[/tex]

Remove bracket

[tex]P(X > 33) = 1 - 1 + e^{-3}[/tex]

[tex]P(X > 33) = e^{-3}[/tex]

[tex]P(X > 33) = 0.050[/tex]

Solving (d): x when [tex]P(X <x)=0.95[/tex]

Here, we make use of:

[tex]P(X<x) = F(x)[/tex]

Substitute [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X<x) = 1 - e^{-\lambda x}[/tex]

So, we have:

[tex]0.95 = 1 - e^{-\lambda x}[/tex]

Subtract 1 from both sides

[tex]0.95 -1= 1-1 - e^{-\lambda x}[/tex]

[tex]-0.05=- e^{-\lambda x}[/tex]

Reorder the equation

[tex]e^{-\lambda x} = 0.05[/tex]

Substitute 1/11 for [tex]\lambda[/tex]

[tex]e^{-\frac{1}{11} x} = 0.05[/tex]

Solve for x:

[tex]x = -\frac{1}{1/11}\ ln(0.05)[/tex]

[tex]x = -11\ ln(0.05)[/tex]

[tex]x = 32.9530550091[/tex]

[tex]x = 33[/tex] --- approximated

Answer:

Step-by-step explanation:

Let us begin with the AA Similarity definition. It states that if two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.

This means that we need:

For this problem, it is unclear that there are more than one angles that are congruent to each other. We see that angle <DEF and <ABC are congruent, but the problem does not give any other angles. In another case, we must find one more to prove similarity by the AA similarity theorem.

Answer:

B.  28/15

Step-by-step explanation:

7/3 x 4/5 = 28/15

Answer:What is m?

Step-by-step explanation:

Answer:

16 and 25

Step-by-step explanation:

list perfect square numbers from 1 to 10

1, 4,9,16,25,36,49,64,81,100

looking at the list, 2 numbers he could be thinking of are 16 and 25

Answer:

4

Step-by-step explanation: thast it

Answer: 40

Step-by-step explanation:

Answer:

[tex]x = - \frac{2}{3} \: \: \: y = \frac{14}{3} [/tex]

Step-by-step explanation:

Since we know -7x=y we use the substitution method and plug it in the top equation.

[tex]x + - 7x = 4[/tex]

[tex] - 6x = 4[/tex]

[tex]x = - \frac{4}{6} [/tex]

or x=-2/3

Then plug it back in the the bottom equation

[tex] - 7( \frac { - 2}{3} ) = y[/tex]

y=14/3

Answer:

Step-by-step explanation:

0, 3, 8, 15, 24, . . .

it is arithmetic

Answer:

[tex]T_n = -48* (-\frac{1}{2})^{n}[/tex]

Step-by-step explanation:

Given

[tex]24, -12, 6,...[/tex]

Required

Write a formula

The above sequence shows a geometric sequence because:

[tex]r = \frac{-12}{24} = \frac{6}{-12} = -\frac{1}{2}[/tex] -- common ratio

The equation is determined using:

[tex]T_n = ar^{n-1}[/tex]

Where

[tex]a = 24[/tex]

Substitute values for a and r

[tex]T_n = 24* (-\frac{1}{2})^{n-1}[/tex]

Apply law of indices:

[tex]T_n = 24* (-\frac{1}{2})^{n} * (-\frac{1}{2})^{-1}[/tex]

[tex]T_n = 24* (-\frac{1}{2})^{n} * 1/(-\frac{1}{2})[/tex]

[tex]T_n = 24* (-\frac{1}{2})^{n} * 1*-2[/tex]

[tex]T_n = 1*-2*24* (-\frac{1}{2})^{n}[/tex]

[tex]T_n = -48* (-\frac{1}{2})^{n}[/tex]

The above represents the explicit formula